At 18:44 02/12/2002 -0500, John W. Holmes wrote:
Can you help me for this ?
Yeah, I already did:
Perhaps you could throw a clue my way, in that case.
I have an actor database (mySQL again) which has actor dates of birth in
'-MM-DD' format. I want to be able to query against that
On Tuesday 03 December 2002 18:29, James Coates wrote:
Perhaps you could throw a clue my way, in that case.
I have an actor database (mySQL again) which has actor dates of birth in
'-MM-DD' format. I want to be able to query against that ignoring the
year:
* give me actors who have
Hi,
please could someone tell me how i can return a month in text from an int ie
getMonth(12)
returns Decmber. Is this possible?
Thanks for your help
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Hi Shaun,
please could someone tell me how i can return a month in text from an int
ie
getMonth(12)
returns Decmber. Is this possible?
No. If you want to stick with this, write your own function to look up a
text array.
If the 12 is part of more data coming in from a form or db (for
Take a look at mktime() and date() ...
echo date(M,mktime(0,0,0,12,1,2002))
The first param of date is the format, M means month in string format
not number of month, and mktime paramas are:
int hour, int minute, int second, int month, int day, int year
This should work
Hi,
please
On Tuesday 03 December 2002 13:57, Shaun wrote:
Hi,
please could someone tell me how i can return a month in text from an int
ie
getMonth(12)
returns Decmber. Is this possible?
Thanks for your help
have a look at the mktime() function. Use this along with the date() function
to get
Thanks for your reply,
i am doing a fitnerss site and i want to display the muscle of the month.
This works fine with the following code:
function get_muscle(){
$month = date(F);
$query = SELECT * FROM Table_Muscle WHERE Muscle_Month = '$month';
$result = mysql_query($query);
At 19:32 03/12/2002 +0800, Jason Wong wrote:
Assuming the column holding the the birthday is called 'birthday':
[snip]
Many thanks!
* give me actors whose birthdays fall between two dates (ie: Aries)
This one is easy, use the BETWEEN clause in your SELECT statement. Consult
manual for
Thanks for this,
I understand how to update in date in database, but I need when I get date
from database to increase or decrease before to save in database.
Can you help me for this ?
John W. Holmes [EMAIL PROTECTED] wrote in message
Thanks for this,
I understand how to update in date in database, but I need when I get
date
from database to increase or decrease before to save in database.
Can you help me for this ?
Yeah, I already did:
You can select out the date you have now, use strtotime() to make it
into a unix
Hi,
I have one problem:
Date field in MySql database with value as 2002-31-12.
I want to increment or decrement this date and to put it again in table.
Can someone help me to increment or decrement date with some days?
Thanks,
Rosen
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To
I have one problem:
Date field in MySql database with value as 2002-31-12.
I want to increment or decrement this date and to put it again in
table.
Can someone help me to increment or decrement date with some days?
UPDATE yourtable SET yourcolumn = yourcolumn + INTERVAL 1 DAY WHERE ...
Thanks,
But I need before to save date in database to do some checks with the
inc/dec date.
Cal you help me ?
Thanks,
Rosen
John W. Holmes [EMAIL PROTECTED] wrote in message
002301c29960$21d6a360$7c02a8c0@coconut">news:002301c29960$21d6a360$7c02a8c0@coconut...
I have one problem:
Date field
What exactly do you want to do? I'm not a mind reader...
---John Holmes...
-Original Message-
From: Rosen [mailto:[EMAIL PROTECTED]]
Sent: Sunday, December 01, 2002 12:54 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Date problem
Thanks,
But I need before to save date in database
01c29965$7862e950$7c02a8c0@coconut...
What exactly do you want to do? I'm not a mind reader...
---John Holmes...
-Original Message-
From: Rosen [mailto:[EMAIL PROTECTED]]
Sent: Sunday, December 01, 2002 12:54 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Date problem
Thanks,
on 02/12/02 9:59 AM, Rosen ([EMAIL PROTECTED]) wrote:
I want to get date from database, to increment ot decrement it with some
days, to show the date and after thath
if user confirm it to save it to database.
And in what format is the date currently stored? -MM-DD? MySQL
timestamp? Unix
It's in -MM-YY
Justin French [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
on 02/12/02 9:59 AM, Rosen ([EMAIL PROTECTED]) wrote:
I want to get date from database, to increment ot decrement it with some
days, to show the date and after thath
if user
I want to get date from database, to increment ot decrement it with
some
days, to show the date and after thath
if user confirm it to save it to database.
There are a ton of ways you can do it. You can select the date and it's
inc/dec value in the same statement:
SELECT datecol, datecol +
Hi to all,
Sorry for this post I know this is a mysql related question, i just wanna
have other comments.suggestions from this list.
I have a problem regarding date queries in mysql. Im creating inventory
reports in PHP. I want to query from the date field a weekly report for a
specific month,
Sorry for this post I know this is a mysql related question, i just
wanna
have other comments.suggestions from this list.
I have a problem regarding date queries in mysql. Im creating
inventory
reports in PHP. I want to query from the date field a weekly report
for a
specific month, year,
;
}
Le Mardi 19 Novembre 2002 15:10, Edward Peloke a ¨¦crit :
I am pulling from a datetime field in mysql. The actual data looks like
this: 2002-11-30 00:00:00 When I output the data to the page, I want it to
appear as 11/30/2002. I want to use a php date format. I do not want it
formatted
I am pulling from a datetime field in mysql. The actual data looks like
this: 2002-11-30 00:00:00 When I output the data to the page, I want it to
appear as 11/30/2002. I want to use a php date format. I do not want it
formatted as it comes out of the db. But date(m/d/y, $myrow[departdate
to use a php date format. I do not want it
formatted as it comes out of the db. But date(m/d/y, $myrow[departdate])
returns 12/31/69. How can I do this?
THanks,
Eddie
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I am pulling from a datetime field in mysql. The actual data looks like
this: 2002-11-30 00:00:00 When I output the data to the page, I want it
to
appear as 11/30/2002. I want to use a php date format. I do not want it
formatted as it comes out of the db. But date(m/d/y, $myrow[departdate
hi to all again,
I have a problem here again regarding the date comparison. I need to check the most
recent date that was entered in mysql database in date format (Y-m-d), if the
datetoday is a day or two days in advanced compared to the queried date.
I need to make sure that the next
I have a problem here again regarding the date comparison. I need to
check the most recent date that was entered in mysql database in date
format (Y-m-d), if the datetoday is a day or two days in advanced
compared to the queried date.
I need to make sure that the next inserted date in the
Is it too late to change the way you insert dates into the DB? I really
think the unix timestamp is the easiest way to store dates... comparisons
are easy, because everything is in seconds, and using date() gives you the
ability to re-format your dates over and over again for presentation
to all;
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say it again?
--
Maxim Maletsky
[EMAIL PROTECTED]
On Sun, 10 Nov 2002 12:37:48 +0800 Michael P. Carel [EMAIL PROTECTED] wrote:
to all;
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Hi all:
I am having some problem with date validation
I am trying to validate the date in a form Field
I had provided a text field for date, so have to
expect all the different possible entry,
When i tried with checkdate() method it needs the
parametes in (int month,int date, int year). It make
Hi,
I had provided a text field for date, so have to
expect all the different possible entry,
This is generally a *very* bad idea. If a visitor to your site enters
4/3/01, do they mean the 4th March or the 3rd April?
I find the best thing to do is provide three drop-downs: one contains
I am having some problem with date validation
I am trying to validate the date in a form Field
I had provided a text field for date, so have to
expect all the different possible entry,
When i tried with checkdate() method it needs the
parametes in (int month,int date, int year). It make
the
Hi,
I have the following query :
for($i = 0; $i =$num_results; $i++)
{
$row = mysql_fetch_object($result);
echo table width =\100%\ border =\0\ cellpadding = \3\\n
.tr\n
.td bgcolor = \#ee\ align = \left\$row-id/td\n
.td bgcolor = \#ee\ align = \left\$row-Nombre/td\n
timestamps are in a MMDDHHMMSS format. If you've used a
TIMESTAMP, DATE, or DATETIME column in MySQL, then you have a MySQL
timestamp. The MySQL timestamp is not compatible with the PHP date()
function, it is expecting a Unix timestamp.
So...the solution is one of two things. You can use an INT
Using the date function, what's the easiest way to find the date of the next
Friday?
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Using the date function, what's the easiest way to find the date of the
next
Friday?
Why use the date() function?
$next_friday = strtotime(next friday);
---John Holmes...
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Responding to my own message. This is making me a little ticked. I can't
think it through. Here's exactly what I need:
There are a bunch of series of files (A series, B series, and so on) that
are to be released on the first, second, third, fourth, or (if it exists for
that month) fifth Friday
Ummm, I've read this twice, and don't get it!!!
You want to make:
- an 'A' file available on the first friday of the month
- an 'B' file available on the second friday of the month
- an 'C' file available on the third friday of the month
- an 'D' file available on the fourth friday of the month
I have a small but hard to solve problem to solve.
Wrote a Select Query for my webpage.
The query should select all values which where
written into the DB the last seven Days.
I thought everything was working fine, but now
the month has changed and everything went
wrong.
My Select Query is
Sascha Braun wrote:
I have a small but hard to solve problem to solve.
Wrote a Select Query for my webpage.
The query should select all values which where
written into the DB the last seven Days.
I thought everything was working fine, but now
the month has changed and everything
:26 PM
Subject: [PHP] Date Arithmetic
I have a small but hard to solve problem to solve.
Wrote a Select Query for my webpage.
The query should select all values which where
written into the DB the last seven Days.
I thought everything was working fine, but now
the month has changed
I have a small but hard to solve problem to solve.
Wrote a Select Query for my webpage.
The query should select all values which where
written into the DB the last seven Days.
I thought everything was working fine, but now
the month has changed and everything went
wrong.
My Select Query
Hello,
I have a table with timestamps in mysql. The timestamps of course are in
the format of 20020930014535 but I would like to format the output as
this:
date(l F jS H:i:s, $last_modified)
What is the simplest way to do this? I see there are a few ways to convert
it, but I was hoping for
In my pages, I just format the date from the SQL query:
SELECT DATE_FORMAT(last_modified, '%m/%d/%Y %h:%i:%s %p') AS
last_modified (...)
Look up the DATE_FORMAT on mysql.com to get a list of the arguments.
Hope this helps!
-Jason
Bryan Koschmann - Gkt wrote:
Hello,
I have a table with
Hi Jason,
I had come across this earlier, and while I can get it to return
perfectly, I was more looking for something that I could do without having
to pull 2 queries. Err, well wait, I wouldn't have to would I? I have 4
columns:
idnum, title, date, news
I was just doing a select * from
No problem!
Refresh MY memory here.. I noticed you didn't return the DATE_FORMAT
column AS var .. is that working okay? I seemed to think that it
returned a long unwieldy column name.. maybe things are good.. let me
know :-D
--Jason
Bryan Koschmann - Gkt wrote:
Hi Jason,
I had come
This is what I am using here:
$db = DB::connect(mysql://$username:$password@$hostName/$databaseName);
if (DB::iserror($db))
die($db-getMessage());
$sql = SELECT idnum, title, DATE_FORMAT(date, '%W, %M %D \ %l:%i%p'),
news FROM newslist ORDER BY idnum DESC;
$query = $db-query($sql);
if
I have a date ex 24/08/02
and I need to see if that date is the same date as it is today (only one
month later) but 5day's in advanced = that would be 24/09/02
so if(date == date now - 5)
{true}
else{false}
how can I do this right ?
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PHP General
Not sure why you need the 5 days in advance bit, but this might give you the
tools to work it all out.
I prefer to work with dates in unix timestamp format (seconds).
To get now, use time()
To get next month, there's a kewl function called strtotime(), which
converts english phrases into
Hi,
I'm using ImpAkt2 (PHP4, MySql, Apache on W2K)
I have update form (which has date-field). So now I have to enter date on
format yy.mm.dd (ex. today 02.09.27), and in the database has then correct
format -mm-dd.
Ok! I have also listing-page, which has date-field (it format is
i got 2 dates and i want to know how many minutes between em,, like:
$date1 = date(Y-m-j H:i);
$date2 = date(Y-m-j H:i, strtotime(now) + 1800);
$minutes = date_something($date1, $date2);
echo there are $minutes between, $date1 and $date2;
regards
patrick
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Patrick
Off the top of my head... Convert both date1 and date2 to unix timestamps,
and subtract one from the other. That will give you the number of seconds
between them. Then, convert to hours, minutes, etc as required.
Peter
At 10:38 PM 9/23/2002 +0200, Patrick wrote:
i got 2 dates and
You should be working with UNIX timestamps here. Convert the dates to human
readble only after you've done the calcuations.
-Kevin
- Original Message -
From: Patrick [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, September 23, 2002 2:38 PM
Subject: [PHP] date functions
i got
On 21-Sep-2002 Patrick wrote:
Hi,,
my server is located in the US and i live in Sweden, so when i try to run
the following command i get a 8hour diffrence,, anyone got any idea of how
to solve this?
date(Y-m-j)
putenv('TZ=Europe/Stockholm');
mktime(0,0,0,1,1,1970);
echo
I have two fields of type date in a MySQL table called training:
start_date
end_date
I can format the date using a select, for example
SELECT
DATE_FORMAT(start_date, '%M %d, %Y') as start_date,
DATE_FORMAT(end_date, '%M %d, %Y') as end_date
FROM training
I have two fields of type date in a MySQL table called training:
start_date
end_date
I can format the date using a select, for example
SELECT
DATE_FORMAT(start_date, '%M %d, %Y') as start_date,
DATE_FORMAT(end_date, '%M %d, %Y') as end_date
FROM training
Hi,,
my server is located in the US and i live in Sweden, so when i try to run
the following command i get a 8hour diffrence,, anyone got any idea of how
to solve this?
date(Y-m-j)
regards
Patrick
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Hi,
Saturday, September 21, 2002, 12:30:48 PM, you wrote:
P Hi,,
P my server is located in the US and i live in Sweden, so when i try to run
P the following command i get a 8hour diffrence,, anyone got any idea of how
P to solve this?
P date(Y-m-j)
P regards
P Patrick
A quick fix that
You have to add (or subtract) 28800 seconds to/from current time and use this
as the 2nd input to date.
echo date(Y-m-j, strtotime(now) + 28800);
Sascha
Hi,,
my server is located in the US and i live in Sweden, so when i try to run
the following command i get a 8hour diffrence,, anyone
Hi guys,
What is the easiest way to get the date of one year from today?
Accommodating for leap years is not essential (but would be a nice bonus).
Thanks,
Peter
- - - - - - - - - - - - - - - - - - - - -
Fourth Realm Solutions
[EMAIL PROTECTED]
http://www.fourthrealm.com
Tel: 519-739-1652
- -
Support @ Fourthrealm.com wrote:
Hi guys,
What is the easiest way to get the date of one year from today?
Accommodating for leap years is not essential (but would be a nice bonus).
Without leap year adjustment...
date( your format string here, time() + 60 * 60 * 24 * 365 );
HTH,
Rob.
--
With leap year adjustment...
strtotime(+1 year, timestamp);
will return a unix timestamp.
- Jacob
At 01:49 09/19/2002, Robert Cummings wrote:
Support @ Fourthrealm.com wrote:
Hi guys,
What is the easiest way to get the date of one year from today?
Accommodating for leap years is not
Jacob Miller wrote:
With leap year adjustment...
strtotime(+1 year, timestamp);
will return a unix timestamp.
Nice, don't think I've ever used that function :)
Cheers,
Rob.
--
.-.
| Robert Cummings |
:-`.
| Webdeployer -
Reformatting before an inserting/updating is one option, but how would we
change the mySQL database to accept the other format?
Peter
At 04:18 PM 9/12/2002 +0800, Jacob Miller wrote:
Why can't you just reformat it before inserting it into the db?
$date = 31.12.2002;
$parts
From http://www.mysql.com/doc/en/Using_DATE.html
quote
The format of a DATE value is '-MM-DD'. According to ANSI SQL, no other
format is allowed. You should use this format in UPDATE expressions and in
the WHERE clause of SELECT statements. For example:
mysql SELECT * FROM tbl_name WHERE
I know everyone love to quote read the manual and forget that we[newbies]
are only asking here because we need help...so here you go...
You can do the following...
DATE_FORMAT IS THE MySQL Command
And let say you want to format your date as the following mm-dd-yy(US) or
dd-mm-yy(the rest of
Thanks everyone for the helpful answers.
I agree that manuals are useful, but there are times when an example works
better.
I took all of this information, and some details from earlier posts about
dates, and produced the following function to make it easy to format dates
without have to go
Hi!
I have web-form, which has field (10 chars), there I enter date (format
dd.mm.). Then data saves to database (date-field type is date).
So everything works, but not fine. When I enter date in format ex.
31.12.2002 and save form, then I'll check what are in db (there are
2031-12-20).
It looks to me like the database is interpreting your date
incorrectly. Try changing the format you use to insert, -mm-dd
- jacob
At 15:11 09/12/2002, Tommi Virtanen wrote:
Hi!
I have web-form, which has field (10 chars), there I enter date (format
dd.mm.). Then data saves to
Well, insert format in wrong, but in Finland enter format is dd.mm.,
so I cannot use other insert format (it have to do other way).
gustavus
It looks to me like the database is interpreting your date
incorrectly. Try changing the format you use to insert, -mm-dd
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PHP General
Why can't you just reformat it before inserting it into the db?
$date = 31.12.2002;
$parts = split(\., $date);
echo $parts[2].-.$parts[1].-.$parts[0];
- jacob
At 16:13 09/12/2002, Tommi Virtanen wrote:
Well, insert format in wrong, but in Finland enter format is
Hi,
Is there any function which returns the day , month or year of a date ?
thanks
meltem
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Hi Meltem,
The PHP manual is at http://www.php.net/manual/en (mirror sites as well).
-Original Message-
From: Meltem Demirkus [mailto:[EMAIL PROTECTED]]
Sent: Monday, September 09, 2002 1:30 PM
To: [EMAIL PROTECTED]
Subject: [PHP] date question
Hi,
Is there any function which
i want Y (year format) printed on my php script (looping), i already tried
it but i got same Year format (ex 1978) in all row in my table
my loop script is:
$query = (select * from table);
$result = mysql_query($query);
while ($row = mysql_fetch_row($result))
$number =
mktime generally only works thru 2037. Why not create an array of the
months, and index in:
$months = array('Jan','Feb',);
$enddate = explode(-, $datereuslt[0]);
$finaldate = $months[$enddate-1] . -$enddate[1];
That's what I thought I might have to do. It's an alternative, but a
Having a little trouble with converting dates.
I have, in my database, a bunch of dates stored like this: -M. Month is
obviously the number of the month (5), not the name (May).
I want to convert the format to MMM, (ex: May, 2002), so I used the
mktime function. Basically I extract the
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, August 26, 2002 3:58 PM
Subject: [PHP] Date conversion problems
Having a little trouble with converting dates.
I have, in my database, a bunch of dates stored like this: -M. Month
is
obviously the number of the month (5
From: Matt [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Monday, August 26, 2002 5:42 PM
Subject: Re: [PHP] Date conversion problems
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, August 26, 2002 3:58 PM
Subject: [PHP] Date conversion problems
mktime
I have, in my database, a bunch of dates stored like this:
-M. Month is obviously the number of the month (5), not
the name (May).
I want to convert the format to MMM, (ex: May, 2002),
Do the conversion in MySQL - it'll save you grief in the long run...
SELECT
when I place date(h:i a) in a page on my server, and view it in a
browser, I am returned: 02:51 pm. According to the server itself,
though (logged in through ssh), using date, it is 3:51. gmdate(h:i
a) returns the same 2:51 time. They are both one hour off from the
server time.
Any ideas of
On Friday 16 August 2002 17:24, Kae Verens wrote:
when I place date(h:i a) in a page on my server, and view it in a
browser, I am returned: 02:51 pm. According to the server itself,
though (logged in through ssh), using date, it is 3:51. gmdate(h:i
a) returns the same 2:51 time. They are both
when I type date in a console on my server, it returns a different
time than that returned by date() or gmdate() - any idea why?
--
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http://www.contactjuggling.org/users/kverens/
http://www.contactjuggling.org/ (webmaster)
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To
('H:m:s \m \i\s\ \m\o\n\t\h'); // 17:03:17 m is month
$today = date(H:i:s); // 17:16:17
- Original Message -
From: Kae Verens [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, August 15, 2002 5:31 PM
Subject: [PHP] date() doesn't return system date
adi wrote:
incorect sintax
maybe I wasn't precise enough:
when I place date(h:i a) in a page on my server, and view it in a
browser, I am returned: 02:51 pm. According to the server itself,
though (logged in through ssh), using date, it is 3:51. gmdate(h:i
a) returns the same 2:51 time. They
Given a date how would you work out number of months elapsed between
DateInPast and DateNow?
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(YearsDifference*12)+FullMonthsDifference :)
Regards, Stas.
- Original Message -
From: Brian McGarvie [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, August 02, 2002 1:50 PM
Subject: [PHP] Date Stuff...
Given a date how would you work out number of months elapsed between
Given a date how would you work out number of months elapsed
between DateInPast and DateNow?
( $monthTo - $monthFrom ) + (( $yearTo - $yearFrom ) * 12 )
I believe that's the correct equation for figuring out the number of months.
Chris
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Hi, im making a tab/lyric portal, and for viewing tabs i want to display the
time the lyric/tab was submitted. So I retrive it from a MySQL database (as
a timestamp) and format it using the date function. The problem is, that the
date: 19-01-2038 04:14:07 is allways returned, even though in the
I have a column in one of my mysql tables which holds the date time that
the record was inserted. When I run a query later on I want to display the
date, but if the date is today or yesterday I want to display today or
yesterday instead .. how do i compare to stored date with todays date?
Hello all,
I am very new to PHP and I have added some minor PHP to my website. I
would like to make a PHP calander to keep track of things going on. Could
someone tell me how I can get the first day of every month.
For Example:
01 Jul 2002 was a Monday.
01 Mar 2002 will be a Thursday
I
[EMAIL PROTECTED]
Date: Mon, 15 Jul 2002 16:44:39 -0600
To: [EMAIL PROTECTED]
Subject: [PHP] Date () Help please
Hello all,
I am very new to PHP and I have added some minor PHP to my website. I
would like to make a PHP calander to keep track of things going on. Could
someone tell me how I
bs 3:5-6
From: Attila [EMAIL PROTECTED]
Date: Mon, 15 Jul 2002 16:44:39 -0600
To: [EMAIL PROTECTED]
Subject: [PHP] Date () Help please
Hello all,
I am very new to PHP and I have added some minor PHP to my website. I
would like to make a PHP calander to keep track of things going o
rd with all your heart, And lean not on your own
understanding; In all your ways acknowledge Him, And he shall direct
your
paths. - Proverbs 3:5-6
From: Attila [EMAIL PROTECTED]
Date: Mon, 15 Jul 2002 16:44:39 -0600
To: [EMAIL PROTECTED]
Subject: [PHP] Date () Help please
H
: [PHP] Date () Help please
OK thought I should share in case any needs it but got it to work.
Here
is
what it looks like and thanks to Richard Baskett for the help.
$yr= date (Y);
$mnth = date (F);
$dy= 1;
$string = $dy $mnth $yr;
$today = date(w,strtotime($string));
Thanks for the help
Had trouble getting this posed at the newsgroup - will try on the maillist
here:
I have a date field passed in a form like this:
01-02-2003
Is there a handy function to convert that to other ways of expressing the
date such as:
01/02/03
OR
2003-01-02
I know the syntax of the date
:25 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Date formatting
Had trouble getting this posed at the newsgroup - will try on the maillist
here:
I have a date field passed in a form like this:
01-02-2003
Is there a handy function to convert that to other ways of expressing the
date such as:
01/02
On Wed, Jul 10, 2002 at 12:25:08PM -0500, Rw wrote:
01-02-2003
Is there a handy function to convert that to other ways of expressing the
date such as:
01/02/03
$temp = preg_replace('/^(\d{2})-(\d{2})-(\d{2})(\d{2})$/', '\\1/\\2/\\4',
$date);
2003-01-02
$temp =
Check out the date() and mktime() functions.
-Original Message-
Now i want to compare the leave_from and leave_to date to find out the
number of days between!
What should i do or any function in php can provide this operation?
];
[EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Thursday, June 20, 2002 12:53 PM
Subject: RE: [PHP] Date Comparsion
Check out the date() and mktime() functions.
-Original Message-
Now i want to compare the leave_from and leave_to date to find out the
number of days between!
What
Dear all
I had a form which let user to input the leave_from and leave_to date into,
the format of the date that user input is -mm-dd.
Now i want to compare the leave_from and leave_to date to find out the
number of days between!
What should i do or any function in php can provide this
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