I wrote:
The following is a bit speculative, but perhaps someone can correct any
misstatements I make -- if there is a magnetic field being created by the
cables coiling around the tube [1], I believe the field would point along
the axis of the tube, creating a theta pinch, even if only
*http://scitation.aip.org/content/aip/journal/jcp/136/3/10.1063/1.3678015
http://scitation.aip.org/content/aip/journal/jcp/136/3/10.1063/1.3678015*
*Quote:*
Within the optical cavity, the photons acquire an effective mass as
determined by the cut-off frequency of the cavity that can be 6–7 orders
Some people suspect that the resistor wire can't be Inconel because they
are predicted to melt at the reactor's operating temperature. However,
since we know the resistor wire casts a shadow in the alumina, the
temperature of the wire remains below the operating temperature and
therefore can't
how do you know this? How do you know the the wire is not the brightest
area?
On 15 October 2014 15:06, H Veeder hveeder...@gmail.com wrote:
Some people suspect that the resistor wire can't be Inconel because they
are predicted to melt at the reactor's operating temperature. However,
since
Highly doubtful. Above curie temperture of Nickel so no ferromagnetism,
and powder too microscopic hot resistivity too high, and AC frequency,
current and number of windings too low for strong magnetic fields or
significant eddy currents to form and give push via lenzs law.
On 15 October 2014
If you zoom in very closely on the hot reactor photos you can see the the
dark lines are of uniform width, continuity and shade. I am 95% confident
that is the shadow of the coil. The light areas change in brightness,
width, etc.
On Wed, Oct 15, 2014 at 3:56 AM, Robert Lynn
I am looking at high zoom at the same photos and finding it easy to draw
the opposite conclusion. Confirmation bias on both our parts :)
I think it is equivocal at best.
On 15 October 2014 19:52, ChemE Stewart cheme...@gmail.com wrote:
If you zoom in very closely on the hot reactor photos you
Additionally, look at the darkened photo, the wire exterior to the reactor
sourrounded by cooler materials to radiate to are brighter than the bright
wires in the reactor. Hard to believe it would be colder inside the
reactor surrounded by relatively hotter materials that are harder to
radiate
On Tue, Oct 14, 2014 at 10:14 PM, ChemE Stewart cheme...@gmail.com wrote:
Or just ride your bike...
http://koin.com/2014/09/05/electric-bike-battery-may-have-caused-bend-house-fire/
I have been studying the 18650, the cell which powers the Tesla.
Proper charging of the cell is a far cry from
From: ChemE Stewart
If you zoom in very closely on the hot reactor photos you can see the the dark
lines are of uniform width, continuity and shade.
If this is 3-phase 50-cycle, then the photo should be showing the gap of the
odd phase at any instant, which gap moves in one
The photo is an average of radiation from 50 Hz cycles, not
instantaneous...temp does not swing that quickly...?...
On Wednesday, October 15, 2014, Jones Beene jone...@pacbell.net wrote:
*From:* ChemE Stewart
If you zoom in very closely on the hot reactor photos you can see the the
dark
They specifically say in the report the coils are the dark areas. I doubt
they're lying about that.
On Wed, Oct 15, 2014 at 6:07 AM, Jones Beene jone...@pacbell.net wrote:
*From:* ChemE Stewart
If you zoom in very closely on the hot reactor photos you can see the the
dark lines are of
Can you attach that photo? I am not sure which one
On Wednesday, October 15, 2014, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
Additionally, look at the darkened photo, the wire exterior to the reactor
sourrounded by cooler materials to radiate to are brighter than the bright
wires in
Depends on the camera exposure time… Probably a digital camera. What would the
exposure time be?
From: ChemE Stewart
The photo is an average of radiation from 50 Hz cycles, not
instantaneous...temp does not swing that quickly...?...
If you zoom in very closely on the hot reactor photos
I think it also depends on high quickly the wire temp oscillates, thermal
conductivity, etc
On Wednesday, October 15, 2014, Jones Beene jone...@pacbell.net wrote:
Depends on the camera exposure time… Probably a digital camera. What
would the exposure time be?
*From:* ChemE Stewart
The
Not lying, but perhaps again confirmation bias, based on wrong assumptions.
How can the inconel wire in Fig 12b be hotter/brighter in the cooler
external environment outside the end of the reactor than it is in the
hotter internal environment inside the reactor?
On 15 October 2014 21:12, Blaze
The wire is not in the reactor, it is embedded in the insulating alumina
shell
On Wednesday, October 15, 2014, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
Not lying, but perhaps again confirmation bias, based on wrong assumptions.
How can the inconel wire in Fig 12b be hotter/brighter
PIERS Proceedings, Moscow, Russia, August 19–23, 2012
*Self-consistent Electrodynamics
https://piers.org/piersproceedings/download.php?file=cGllcnMyMDEyTW9zY293fDFBN18wMTcyLnBkZnwxMjAzMTkwNTU5MTE=*
Konstantin Meyl
Faculty of Computer and Electrical Engineering, Furtwangen University,
Germany
From: Robert Lynn
How can the Inconel wire in Fig 12b be hotter/brighter in the cooler external
environment outside the end of the reactor than it is in the hotter internal
environment inside the reactor?
In FWIW department, here is the grade of Inconel often used for resistor wire
I keep thinking he has built some sort of alumina/ceramic
klystron/microwave tube with that reactor.
http://www.daenotes.com/electronics/microwave-radar/microwave-tube-devices
On Wednesday, October 15, 2014, Jones Beene jone...@pacbell.net wrote:
*From:* Robert Lynn
How can the Inconel
ChemE Stewart cheme...@gmail.com wrote:
I think it also depends on high quickly the wire temp oscillates, thermal
conductivity, etc
Macroscopic changes in temperature are very slow compared to the kinds of
pulses a camera might capture. Unless you are talking about temperature
changes in micro
From: ChemE Stewart
I keep thinking he has built some sort of alumina/ceramic klystron/microwave
tube with that reactor.
Maybe… but is it not fair to say that you are kinda’ obsessed with microwaves
:-)
BTW in response to James Bowery’s post on Meryl – the SPP is an intense
From: ChemE Stewart cheme...@gmail.com
Sent: Wednesday, October 15, 2014 6:28:37 AM
The wire is not in the reactor, it is embedded in the insulating alumina
shell.
That's a guess. But it might be true.
I drew (and scanned) some diagrams of a possible structure following the March
2013
But the wire cannot be tungsten outside of the reactor where it is exposed
to air! Only inconel will survive air exposure at such temperatures for a
month, and it maxes out at about 1300-1350°C (even that is pushing it).
And that wire (Fig 12b) is visibly brighter than the wire lines in the
You would think after 30 days of sitting around, staring at the reactor ,
drinking coffee, eating lunch, sleeping and thinking about it, the team of
scientists would have discussed all of this and verified. They would have
plenty of time to triple check readings, even some type of portable
fig 2 : http://lenr.qumbu.com/web_hotcat2_pics/141011_lugano_fig2.jpg No
banding, dummy run
fig10 : http://lenr.qumbu.com/web_hotcat2_pics/141011_lugano_fig10.png Possible
IR banding, dummy run
fig 12a : http://lenr.qumbu.com/web_hotcat2_pics/141011_lugano_fig12a.jpg
Strong visible banding
I've been thinking of tungsten for a while now. Do they make an alloy
with tungsten that operates at high temps in an oxygen atmosphere. I ask
because, although the tungsten that is embedded in the reactor would be
protected from oxygen by the aluminum oxide coating, you have to connect
it
Your conclusion that there is no gain is incorrect. If that were the
situation, the behavior that the testers witnessed with increasing temperature
could not have happened. I do not know how much gain was actually present due
to some of the questions that remain about the true temperature,
12A looks like a damn flame shooting out the end of the thing!
Thin/uniform bands spiraling one way and thinker bands going the other.
That alumina shell looks wrapped, sort of like a paper mache newspaper
wrap, like alumina felt soaked in glue and wrapped. It is not even
straight.
On Wed, Oct
I wrote:
Macroscopic changes in temperature are very slow compared to the kinds of
pulses a camera might capture.
I mean they all blur together. If there are moving pulses of heat under the
alumina, by the time the heat reaches the surface it blurs together and you
would not see light and
I agree
On Wed, Oct 15, 2014 at 11:03 AM, Jed Rothwell jedrothw...@gmail.com
wrote:
I wrote:
Macroscopic changes in temperature are very slow compared to the kinds of
pulses a camera might capture.
I mean they all blur together. If there are moving pulses of heat under
the alumina, by
One more followup on Bob Ellefson's analysis of the SEM/EDS ToF/SIMS where
the unexpected surprise was apparent gallium. (mass 69)
I am wondering if the explanation is not exactly nuclear ! but instead, the
lithium has been fully absorbed into the K or L shell of the Ni62, giving it
high
Robert Lynn wrote:
But the wire cannot be tungsten outside of the reactor where it is exposed to
air!
It could be exposed to air in the reactor too.
One could imagine the leads into the end-caps are Inconel - and the wire coils
are tungsten coated with alumina, or else body is two
Lockheed says makes breakthrough on fusion energy project - Yahoo News
WHOA !
http://news.yahoo.com/lockheed-says-makes-breakthrough-fusion-energy-project-123840986--finance.html
Get this:
“Ultra-dense deuterium, an isotope of hydrogen, is found in the earth's oceans….
I am
Makes you wonder if this is LENR related. 100 megawatts from a reactor
that fits on a truck, and no radioactive waste!!! Hmmm
Robert Dorr
On 10/15/2014 8:19 AM, Jones Beene wrote:
Lockheed says makes breakthrough on fusion energy project - Yahoo News
WHOA !
Martin Fleiishchmann Memorial Project Facebook page brought up the G69
and said it can be safely ignored as an artifact of the SIMS probe.
https://www.facebook.com/MartinFleischmannMemorialProject
SIMS stands for Secondary Ion Mass Spectrometry and Gallium 69 is
used as the primary ionisation
On Wed, Oct 15, 2014 at 1:04 AM, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
Highly doubtful. Above curie temperture of Nickel so no ferromagnetism,
and powder too microscopic hot resistivity too high
I assume, then, that magnetic domains and the curie temperature are not
relevant.
The video is pretty
http://www.youtube.com/watch?feature=player_embedded
http://www.youtube.com/watch?feature=player_embeddedv=UlYClniDFkM
v=UlYClniDFkM
but sparse technical details. Looks a lot like they added magnetic coils to the
Farnsworth Fusor.
I want to know about the
I wrote up my analysis of the banding : (Draft -- I'll rename it later).
http://lenr.qumbu.com/rossi_hotcat_oct2014_141014a.php
Short answer : we don't even know whether the bright bands line up with the
wires, or the gaps between them.
There are multiple explanations, which depend on the
Thanks Brad
AFAIK the SIMS which use gallium use elemental gallium, so there should be a
71Ga signal as well, which is apparently not seen. 40% of elemental gallium is
mass-71.
Do they have a reference for a device which only uses 69Ga?
If so, case closed.
-Original Message-
From:
I just suggested the following as the construction of the latest hotCat to
MFMP:
Here is a section drawing of the end of the new hotCat as I see it (
https://drive.google.com/file/d/0B5Pc25a4cOM2WXBNRjE2bDVVT1U/view?usp=sharing
). I believe IH would have used as many off-the-shelf components as
Watching the video makes me a bit suspicious of the no radiation claim.
High temperature fusion, magnetically bottled in a small container.
Seems to me the container will eventually become radioactive.
Robert Dorr
On 10/15/2014 9:17 AM, Jones Beene wrote:
The video is pretty
If there are neutrons emitted, then everything becomes activated, and this
reactor cannot be used on an airplane, as suggested. In the Wiki entry
http://en.wikipedia.org/wiki/Aneutronic_fusion
…there are two deuterium possibilities. But even those have secondary neutrons.
This does
They state that the device operates at many millions of degrees so it does not
make sense to discuss deuterium atoms. Ions are all that exist at that
temperature.
Dave
-Original Message-
From: Jones Beene jone...@pacbell.net
To: vortex-l vortex-l@eskimo.com
Sent: Wed, Oct 15,
A calibration curve will bend down. It never bends up.
this mean that temperature grow less than the power ?
this mean that when you increase the power, and if temperature grows much
more that before, something anomalous is happening ?
Either excess heat, or some external blanket effect
You have a good understanding in my opinion. There is no doubt that energy is
being generated within the core.
Dave
-Original Message-
From: Alain Sepeda alain.sep...@gmail.com
To: Vortex List vortex-l@eskimo.com
Sent: Wed, Oct 15, 2014 12:59 pm
Subject: Re: [Vo]:E-cat :
New version with embedded wires.
http://lenr.qumbu.com/rossi_hotcat_oct2014_141014b.php
Here I've also assumed that the wires are a simple single strand, rather than
the spiral form used in the earlier tests, and are in good thermal contact with
the Alumina.
One detail is how does the e-cat work when in after-death mode (SSM).
One mystery for me is the powder not to melt, hotter and the around...
I feel E-cat are very well engineered... we can be surpised like physicists
were by felischmanpons calorimeter...
2014-10-15 18:24 GMT+02:00 Bob Higgins
I now think the general structure is more like this :
http://lenr.qumbu.com/web_hotcat_pics/hotcat_141014_1_010.png
See http://lenr.qumbu.com/rossi_hotcat_oct2014_141014b.php in my other thread
for details
- Original Message -
From: Bob Higgins rj.bob.higg...@gmail.com
To:
Alan, Alumina fires at an extremely hot temperature, 1600-1700C for 96%,
and for high purity aluminas, the firing temperature may be over 1800C.
Firing must also occur in an oxygen (air) environment or the alumina will
lose some of it oxygen during firing. Embedding any metals in this and
having
You Alan have done an amazing job sleuthing out the details of this
thing. I suppose you are right, although I cannot tell. If you are right it
is a great job and if you are wrong you have a vivid imagination!
- Jed
Me too, good job. Tube in a tube reminds of the model rockets I used to
build. Fin supports between tubes might explain the wider dark band seen
as a spiral?. Do you think a lot of the heat might be discharged in a
space between tubes and out the ends? Or are the ends completely sealed?
On
I believe the ends, between the central tube and the outer 2 cm hot tube,
are filled in with a refractory cement. In fact, that whole space, and
maybe not the ends could be filled in to help improve the thermal
conductivity. Most importantly it should keep out the air that could
oxidize the
From: ChemE Stewart cheme...@gmail.com
Sent: Wednesday, October 15, 2014 11:08:42 AM
Me too, good job. Tube in a tube reminds of the model rockets I used to
build. Fin supports between tubes might explain the wider dark band seen as a
spiral?. Do you think a lot of the heat might be
Dear Friends,
The second issue of this Confront journal:
starts with a really bad shock
http://egooutpeters.blogspot.ro/2014/10/lenr-confront-journal-october-15-2014.html
but ends in a realistic- optimistic note.
Peter
--
Dr. Peter Gluck
Cluj, Romania
http://egooutpeters.blogspot.com
This is not Mark Gibbs' site but an aluminum mineral which may be relevant
to this discussion.
http://en.wikipedia.org/wiki/Gibbsite
Gibbsite is Al(OH)3 is one of the minerals found in bauxite. Unlike other
hydroxides, it is stable at high temperature.
We are told that in the Rossi reactor
I agree David. You can verify this by looking at the data for both the
caps and the E-Cat body. The caps are not incandescent, so there does not
appear to be any transparency issue there. The Delta T/Watt is nearly the
same despite an increase in input power of ~100W. You would expect it to
be
Alain Sepeda alain.sep...@gmail.com wrote:
A calibration curve will bend down. It never bends up.
this mean that temperature grow less than the power ?
Right.
this mean that when you increase the power, and if temperature grows much
more that before, something anomalous is happening ?
If the nickel particles are the ultimate source of 3.5X over-unity heat in
the Rossi reactor, it is paradoxical and against common sense that 900
constantly applied watts of heat energy is required to keep the nickel
particles active.
Furthermore, this COP value is far under what the Hot-cat
According to Albert, adding 25 MWhrs (90 gigajoules) of any form of energy
to an object increases its mass by 1 milligram, even though no matter has
been added... and vice-versa.
In the case of the AR glow-tube, where 1.5 MWhr has been reported, the
equivalent mass loss would only be about 60
Yeah might be pulling protons out of the Dirac sea to combine with
electrons, or something like that
On Wednesday, October 15, 2014, Jones Beene jone...@pacbell.net wrote:
According to Albert, adding 25 MWhrs (90 gigajoules) of any form of energy
to an object increases its mass by 1 milligram,
Good point Jack. One item of interest is that my simulation shows that one can
refer to two different COPs when the core generates heating power that are not
so evident with an inactive core. The first is an incremental COP that is
calculated by taking the derivative of the output power at a
From: Axil Axil janap...@gmail.com
Sent: Wednesday, October 15, 2014 12:47:05 PM
The conclusion that logic forces us to arrive at must be that there is
another place where all that over unity heat is coming from. These particles
cannot be producing (900 watts) (3.5) = 3150 watts of
Perhaps these are the sources. If you look at the literature (I don't
remember where, but I think it's a paper o presentation from Kim), it's
pointed out that 24MeV particles from within old experiments with Pd look
like conic craters with 4um in diameter and similar depth, if my memory is
We may eventually come to the conclusion that the nickel can produce power even
in the molten form. That seems to be what is implied. Is there reason to
assume that molten nickel can not work? A higher temperature might enhance the
process that is not well understood at the moment.
I have
In reply to David Roberson's message of Wed, 15 Oct 2014 16:16:29 -0400:
Hi,
[snip]
We may eventually come to the conclusion that the nickel can produce power
even in the molten form. That seems to be what is implied. Is there reason
to assume that molten nickel can not work? A higher
I believe that Ni particles will not work once melted - just intuition,
because I don't buy the neutron stripping yet. If we take a leap of faith
and say that the central reactor core alumina tube is coated with particles
sintered to its inside (like a catalytic converter for example), we don't
In reply to Jones Beene's message of Wed, 15 Oct 2014 12:13:20 -0700:
Hi,
[snip]
If 0.006 gm of H has to supply 1.5 MWh, then each atom needs to supply 9.3 MeV.
This is not out of the question, if the right reaction is found. However if it
only acts as a catalyst for neutron transfer reactions,
In reply to Jones Beene's message of Wed, 15 Oct 2014 08:05:31 -0700:
Hi,
[snip]
One more followup on Bob Ellefson's analysis of the SEM/EDS ToF/SIMS where
the unexpected surprise was apparent gallium. (mass 69)
I am wondering if the explanation is not exactly nuclear ! but instead, the
lithium
On Wed, Oct 15, 2014 at 4:03 PM, Jones Beene jone...@pacbell.net wrote:
What's the point? The point is that if there is a real paradigm shift here,
then it does not necessarily have to nuclear fusion as the source, not even
involve the nucleus. We should be thinking outside the box ... err...
Greetings vortex-L,
Went here after seeing it earlier..now gone.
Temporary???
http://www.lockheedmartin.com/us/news/press-releases/2014/october/141015ae_lockheed-martin-pursuing-compact-nucelar-fusion.html
Ad astra,
Ron Kita, Chiralex
Still Listed here: http://www.lockheedmartin.com/us/news/press-releases.html
On Thu, Oct 16, 2014 at 10:02 AM, Ron Kita chiralex.k...@gmail.com wrote:
Greetings vortex-L,
Went here after seeing it earlier..now gone.
Temporary???
You have a typo in your link. nuCELar ...
cheers
patrick
On Thu, Oct 16, 2014 at 10:17 AM, Patrick Ellul ellulpatr...@gmail.com
wrote:
Still Listed here:
http://www.lockheedmartin.com/us/news/press-releases.html
On Thu, Oct 16, 2014 at 10:02 AM, Ron Kita chiralex.k...@gmail.com
wrote:
Ok, after escalating from random-questions-embedded-in-a-long-posting to
open-conjecture-with-direct-questions and getting nowhere, I went with the
shakily-supported-but-loudly-declared-claim-of-fact route so popular on the
internet, and that elicited a couple of responses from kind and
the resistor wire expands with respect to the alumina as it heats up,
breaking any bonding contact, or lifting the wire of the inner alumina tube
in more and more places and leading to less and less conductive contact -
prompting the wire to heat up as more as more of the energy it transmits to
Since they are measuring the input energy to the wire that makes no sense
On Wednesday, October 15, 2014, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
the resistor wire expands with respect to the alumina as it heats up,
breaking any bonding contact, or lifting the wire of the inner
Do you have exceptional hearing?
It has nothing to do with measuring of the wire power, except that as the
wire heats up, increase the thermal resistance of the heat flow between
wire and reactor body (by reducing number of points of physical contact)
and of course the wire temperature will go up (given same input power) - I
These might be pretty similar to Rossi's setup. (Google Superthal smu)
Superthal heating modules
Prefabricated heating modules consisting of vacuum-formed ceramic fibre
with an integral Kanthal Super molybdenum-disilicide (MoSi2) heating
element for up to 1750°C (3180°F) element temperature.
such units are not made as 3 phase helically wound assemblies, MoSi2 is
non-ductile/brittle and very difficult to make and even worse to bond to,
and there is still the unanswered problem of how do you bond inconel wire
that can survive only to 1350°C to an insulated heating element that is
If the wire were the brightest area there would be no excess heat.
Harry
On Wed, Oct 15, 2014 at 3:56 AM, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
how do you know this? How do you know the the wire is not the brightest
area?
On 15 October 2014 15:06, H Veeder hveeder...@gmail.com
But the reactor heat should drop at the same time.
I guess it depends if they are measuring heat loss on all surfaces of the
device. The total dissipated heat should not change except for due to the
reaction and changes to input power. I have not read the report in detail
to see how many
Greeting Vortex-L,
A yawn for the Aviation Week Lockheed Fusion website:
http://aviationweek.com/technology/skunk-works-reveals-compact-fusion-reactor-details
Ad Astra,
Ron Kita, Chiralex
Doylestown PA
Does this not indicate that the wire must be producing inductive heating in
the powder?
On Wed, Oct 15, 2014 at 8:23 PM, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
the resistor wire expands with respect to the alumina as it heats up,
breaking any bonding contact, or lifting the wire of
I think it is, but irregardless a wire alone cannot create COP1
On Wednesday, October 15, 2014, Axil Axil janap...@gmail.com wrote:
Does this not indicate that the wire must be producing inductive heating
in the powder?
On Wed, Oct 15, 2014 at 8:23 PM, Robert Lynn
So how do you imagine it inductively heats the powder given low AC
frequency, weak solenoid magnetic field, tiny cross section area powder,
and high resistivity of nickel near its melting point?
The physics + mathematics to estimate the magnetic field strength and eddy
currents induced are
Why did Rossi say that a DC current applied to the wire would not work? Why
does the startup procedure need for a magnetic field to be applied?
On Wed, Oct 15, 2014 at 9:56 PM, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
So how do you imagine it inductively heats the powder given low AC
So how many turns are in the coil? And what are you calculating for a field
strength?
On Wednesday, October 15, 2014, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
So how do you imagine it inductively heats the powder given low AC
frequency, weak solenoid magnetic field, tiny cross section
If the wire inside the reactor was hot enough to glow it should produce a
more uniform spiral glow along the entire length of the tube.
Harry
On Wed, Oct 15, 2014 at 8:19 AM, Robert Lynn robert.gulliver.l...@gmail.com
wrote:
Additionally, look at the darkened photo, the wire exterior to the
If the thermography was done reasonably well, then it is proving to be more
than just a means of measuring excess heat, it is also a means of probing
the LENR phenomena.
Harry
Not if it is touching the walls of inner or outer alumina tube in places,
intermittent contact due to vagaries of original wire winding around inner
tube and subsequent large differential thermal expansion so that the wire
is quenched in some places but not in others. Would explain the variation
Thanks for posting your ideas.
I hadn't seen that picture of the march 2013 reactor sitting on the scale
with heating coils visible.
Why don't we just accept that the authors of the 2014 test also know enough
about the construction of the reactor to say that the dark bands align with
the wires?
This is the likely what makes it appear that there is a gain above 1.
So at least we have you now believing that a wire cannot create a gain
above 1 and that the wire is not inside the reactor core.
I wonder if we can estimate number of coil wraps from the photo(dark
bands), we might be
Nullis in verba. :) I believe my eyes more than others words. In finding
so many potential faults with so little published information (they had a
month to investigate!!) I can only say that I am unimpressed by the
critical observational skills of the testers. If they had approached this
demo
Nullis in verba. :) I believe my eyes more than others words. In finding
so many potential faults with so little published information (they had a
month to investigate!!) I can only say that I am unimpressed by the
critical observational skills or reporting of the testers. If they had
You might say I am splitting hairs but what Mckubre has written here is
technically incorrect.
The Stephan-Boltzman law is relationship between temperature and output
power.
It is not a relationship between input power and output power so you can't
use the law by itself
to infer any relationship
Bob, you appear to be too convinced that the gain is unity and are going to
great lengths to obtain that result. The testers are well respected scientists
and no one should assume that they are so easily misslead. Besides, there are
several measurements that support the fact that the COP is
On Wed, Oct 15, 2014 at 1:50 PM, mix...@bigpond.com wrote:
However if it [hydrogen] only acts as a catalyst for neutron transfer
reactions, then nowhere near that
amount would be needed.
My current theory is that the hydrogen plays no role in this particular
instance. Perhaps elsewhere, deep
To go a bit further, the law applies to black body radiation and not just any
emitter. I suspect it is a difficult task to prove that the actual power
being radiated is exactly what is expected unless a system is constructed to
capture all of the radiation over the entire spectrum. Then that
Look at this way the paper is getting peer reviewed in public. Hopefully
they will revise the paper to address the criticisms.
Harry
On Wed, Oct 15, 2014 at 11:58 PM, Robert Lynn
robert.gulliver.l...@gmail.com wrote:
Nullis in verba. :) I believe my eyes more than others words. In finding
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