RE: [Vo]:Solar cell lifetime in space

[Arnaud Kodeck]

After drying the colloidal silica like the Ludox  
<https://www.sigmaaldrich.com/BE/en/product/aldrich/420832> 
https://www.sigmaaldrich.com/BE/en/product/aldrich/420832 is also very highly 
transparent.

 

Your coating if like fused silica is a good candidate to make a diffusion 
barrier of H2. At high temperature(above 800°C)  SS and metals diffuse H2 like 
a sponge. A layer of your product might stop the diffusion (damper it at least) 
if it is well crystalized and resist multiple heatings and coolings without 
deterioration due to thermal expansion difference between metals (or SS) and 
the SiO2 layer.

 

Some powders at high temperature are showing more and more interesting results 
for LENR. The leakage of H2 trough the vessel walls in such experiments is 
still a problem without a satisfactory solution. This may worth a try. Could it 
be easily applied on an inner surface of a pipe to have a layer like 
100~1000µm? What will be the behaviour with heating/cooling cycles over time.

 

 

From: MSF  
Sent: 22 December 2022 02:23
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Solar cell lifetime in space

 

I'm not sure of the actual crystalline structure, but it's not like silica gel, 
which displays substantial optical diffusion. Given the fact that it's highly 
transparent to the point of invisibility,  I'm making the assumption that the 
structure is similar to fused quartz.

 

--- Original Message ---
On Wednesday, December 21st, 2022 at 8:32 AM, Arnaud Kodeck 
mailto:arnaud.kod...@lakoco.be> > wrote:




What is the crystal structure of the adhered layer ? Amorphous (sort of silica 
gel) or crystallized (crystalline quartz) ?

 

From: MSF mailto:foster...@protonmail.com> > 
Sent: 21 December 2022 00:00
To: vortex-l@eskimo.com <mailto:vortex-l@eskimo.com> 
Subject: Re: [Vo]:Solar cell lifetime in space

 

 

I was working with this method of surface treatment of glass more decades ago 
than I care to remember. You simply  immerse ordinary glass into a bath of 
molten potassium nitrate and the sodium Ions at the surface are replaced with 
potassium ions, resulting in a highly impact resistant glass. These days it's 
called gorilla glass, but I was using this technique long before Corning.

 

I see that  cerium doped sheet is just glass, not fused silica. So it may be 
that no cerium ions could be implanted into pure silica by the molten salt 
technique.

 

I recently discovered a method of depositing a layer of silica on any given 
surface using a ridiculously simple and inexpensive technique. This is 
something that should have been discovered 200 or so years ago, but wasn't. 
I've searched for months trying to find out if this was done before, but I find 
no reference to it. The silica layer deposited is only a few tens of microns 
thick, but the process can be repeated. Other compounds can be included; so far 
I've only tried copper. This is a solid transparent well adhered layer, not 
some powdered composite.  I really don't know what to do with this, probably 
nothing. Thought you might be interested anyway.

 

--- Original Message ---
On Tuesday, December 20th, 2022 at 10:00 PM, Andrew Meulenberg 
mailto:mules...@gmail.com> > wrote:



Foster,

You have raised an interesting possibility. I have been out of the loop for 25 
years, so my info may be dated. However, the cerium was included in the melt, 
with the quantity a djusted for the optimum UV absorption for the coverslide 
thickness. 

 

Use of a doped layer rather than the bulk could possibly provide some improved 
optical matching in the "STACK". It would have to be tested for stability 
during the thermal cycles. If the surface doping (by dipping or by ion 
implantation) is a reliable process, this might be worth mentioning it to the 
appropriate people (who I no longer know).

 

Andrew

 

-- Forwarded message -

 

I guess this is getting off into the weeds a bit, but is the quartz layer doped 
with cerium in the mass? Or is the cerium diffused into the surface by 
immersion in a molten cerium compound?

 

--

On Tuesday, December 20th, 2022 at 2:26 AM, Andrew Meulenberg 
mailto:mules...@gmail.com> > wrote:



 

> 

 

 

 

 

RE: [Vo]:Solar cell lifetime in space

[Arnaud Kodeck]

What is the crystal structure of the adhered layer ? Amorphous (sort of silica 
gel) or crystallized (crystalline quartz) ?

 

From: MSF  
Sent: 21 December 2022 00:00
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Solar cell lifetime in space

 

 

I was working with this method of surface treatment of glass more decades ago 
than I care to remember. You simply  immerse ordinary glass into a bath of 
molten potassium nitrate and the sodium Ions at the surface are replaced with 
potassium ions, resulting in a highly impact resistant glass. These days it's 
called gorilla glass, but I was using this technique long before Corning.

 

I see that  cerium doped sheet is just glass, not fused silica. So it may be 
that no cerium ions could be implanted into pure silica by the molten salt 
technique.

 

I recently discovered a method of depositing a layer of silica on any given 
surface using a ridiculously simple and inexpensive technique. This is 
something that should have been discovered 200 or so years ago, but wasn't. 
I've searched for months trying to find out if this was done before, but I find 
no reference to it. The silica layer deposited is only a few tens of microns 
thick, but the process can be repeated. Other compounds can be included; so far 
I've only tried copper. This is a solid transparent well adhered layer, not 
some powdered composite.  I really don't know what to do with this, probably 
nothing. Thought you might be interested anyway.

 

--- Original Message ---
On Tuesday, December 20th, 2022 at 10:00 PM, Andrew Meulenberg 
mailto:mules...@gmail.com> > wrote:




Foster,

You have raised an interesting possibility. I have been out of the loop for 25 
years, so my info may be dated. However, the cerium was included in the melt, 
with the quantity a djusted for the optimum UV absorption for the coverslide 
thickness. 

 

Use of a doped layer rather than the bulk could possibly provide some improved 
optical matching in the "STACK". It would have to be tested for stability 
during the thermal cycles. If the surface doping (by dipping or by ion 
implantation) is a reliable process, this might be worth mentioning it to the 
appropriate people (who I no longer know).

 

Andrew

 

-- Forwarded message -

 

I guess this is getting off into the weeds a bit, but is the quartz layer doped 
with cerium in the mass? Or is the cerium diffused into the surface by 
immersion in a molten cerium compound?

 

--

On Tuesday, December 20th, 2022 at 2:26 AM, Andrew Meulenberg 
mailto:mules...@gmail.com> > wrote:




 

> 

 

 

 

RE: [Vo]:A New Way to Achieve Nuclear Fusion

[Arnaud Kodeck]

It was described in the movie ‘Moon’ in 2009. 
https://en.wikipedia.org/wiki/Moon_(2009_film)

 

From: Terry Blanton  
Sent: 18 December 2022 14:33
To: vortex-l@eskimo.com
Subject: Re: [Vo]:A New Way to Achieve Nuclear Fusion

 

In that case, a robotic mining system would suffice.  Combine that with 
Heinlein's mass driver and we're all set.

 

Well, we need a hot Fusion device first.

 

On Sun, Dec 18, 2022, 2:40 AM Robin mailto:mixent...@aussiebroadband.com.au> > wrote:

In reply to  Terry Blanton's message of Sat, 17 Dec 2022 22:52:39 -0500:
Hi,

An alpha particle of about 5 MeV will penetrate into solid matter about 10 
microns.
Under the best of circumstances we may imagine a Solar flare generated He3 ion 
having an energy of about 1 GeV, with
most having considerably less energy.
So our 1 GeV ion may be able to penetrate about 2 mm into Lunar regolith 
(assuming that the penetration depth is a
linear function of energy).

Using the reaction:-

D + He3 -> He4 + p + 18.35 MeV

We can make a high order estimate of the potential fusion energy derivable from 
a square meter of Lunar regolith.

Assuming 15 ppb, and with a density of 2.4 gm/mL of regolith we get about 12 
kWh of fusion energy / squ. meter of
regolith, unless I stuffed up the arithmetic. However mining should be pretty 
simple since only the top few mm of dust
need be processed.
(Note that, despite the name, you can't use a "vacuum cleaner" in the vacuum of 
the Moon. ;) )
[snip]
Cloud storage:-

Unsafe, Slow, Expensive 

...pick any three.

RE: [Vo]:ni and ca

[Arnaud Kodeck]

Do you mean that you witnessed decays of (Cu64 or Cu66) AND (W185 or W187) in 
Russ experiment ?
Arnaud

-Original Message-
From: Jürg Wyttenbach  
Sent: Sunday, 4 August 2019 13:52
To: vortex-l@eskimo.com
Subject: Re: [Vo]:ni and ca

Unluckily there are some exceptions with Cu/W and there may be more.

J.W.


Am 04.08.19 um 00:45 schrieb mix...@bigpond.com:
> In reply to  Jürg Wyttenbach's message of Sat, 3 Aug 2019 19:00:53 +0200:
> Hi,
> [snip]
>> Adding H* to any useful isotope would result in a much better energy
>> gain in  the range of 1..8 MeV at best. Adding H* is neutron like and
>> not always harmless...
> I would have thought that adding H* would only be neutron like when addition 
> of
> a neutron would result in a more stable nucleus than addition of a proton. 
> IOW,
> I think nature prefers to create stable nuclei, when possible.
> In the case of H* it can either add both the proton & the electron in an
> enhanced electron capture reaction, or just add the proton, and eject the
> electron. IOW it has a choice, and I suspect it will usually choose the path
> that leads to a stable nucleus.
>
> [snip]
> Regards,
>
>
> Robin van Spaandonk
>
> local asymmetry = temporary success
>
>
>

-- 
Jürg Wyttenbach
Bifangstr.22
8910 Affoltern a.A.
044 760 14 18
079 246 36 06

RE: [Vo]:Calcium as a Mills catalyst

[Arnaud Kodeck]

Jones,

 

Keep in mind that CacO3 decomposes to CaO in a dynamic vacuum with a 
temperature as low as 200°C. In the backing process in dynamic vacuum, the 
crystal CaCO3 in the mesh is decomposed to CaO.

 

CaO has been recognized as a catalyst of LENR by another team in Japan 
(Permeation of D2 in a layered Pd/CaO sandwich)

 

Arnaud

From: JonesBeene  
Sent: Tuesday, 30 July 2019 04:44
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Calcium as a Mills catalyst

 

Thanks Jeff –

 

This could be important. Limelight – as old-fashioned as it may seem at first - 
has long been claimed to have a number of optical properties which look like 
they are related to hydrino creation.

 

On a related topic, and looking at Fig.3 in the first cited paper, which is the 
emission spectra of calcium sulfate, the peak is at 580 nm.

 

Coincidentally (or not) the palladium optical anomaly where the metal switches 
sharply from photon reflector to perfect absorber is at 590 nm. That would only 
be relevant if calcium carbonate has its peak at about the same value.

 

There are a number of reasons to think the Mizuno breakthrough relates more to 
Mills’ theory than to LENR.

 

Jones

 

 

From: Jeff Driscoll  

 

and calcium oxide is a candoluminescent material where limelight is given off 
when hydrogen is exposed to the material at high temperature:

 

http://zhydrogen.com/wp-content/uploads/2018/06/Candoluminescence-of-cave-gypsum.pdf
  

 

https://www.youtube.com/watch?v=EXl6H7G6BMU  

 

https://en.wikipedia.org/wiki/Limelight  

 

On Mon, Jul 29, 2019 at 9:26 PM Jones Beene mailto:jone...@pacbell.net> > wrote:

For those who have not carefully followed Mills' work on dense hydrogen 
(hydrino) - calcium is listed as a favored catalyst. This could be important 
(or not) in the context of the recent Mizuno breakthrough ... certainly it has 
not been mentioned before but perhaps it should be (at least listed as a 
possibility) due to a few other related details.

 

The Rydberg level for Ca is the fifth - 1/5 as it is inverted and notably 
calcium is the one of the few for this level of shrinkage. There is 
complementary catalysis with the other potential catalysts present, since there 
is palladium - first level, oxygen/carbonate ion - 2nd level, nickel 7th and 
11th and now calcium in the middle - so that there is a deepening progression 
which could set up a cascade of some kind.

 

If one is not tied down to any particular M.O. or theory - then this spread of 
catalysis values could be relevant in the context of Alan Goldwater's new 
report on his early stage effort at replication where he finds calcium:

 

https://docs.google.com/document/d/16dP_SmSP8SuQbZ7p9eGoCwf1vwJKh7KPL7NAYv7j13o/edit

 

Really nice insight by Alan.

 




 

-- 

Jeff Driscoll
617-290-1998

 

RE: [Vo]:If Mizuno is correct, this design is likely tobetheprecursor to all future devices

[Arnaud Kodeck]

Hello Jürg,

How do you witness the reaction 107Cd->107Ag ?

Arnaud

-Original Message-
From: Jürg Wyttenbach  
Sent: Saturday, 20 July 2019 18:10
To: vortex-l@eskimo.com
Subject: Re: [Vo]:If Mizuno is correct, this design is likely tobetheprecursor 
to all future devices

Two simple samples:

7-Li + H* --> 8Li --> 8-Be --> 2 4-He. (Lipinski reaction)

105Pd +D* -->107Cd --> 107Ag classic P

You can identify the decay paths by the typical gammas emitted.

To learn about this use. 
https://www-nds.iaea.org/relnsd/vcharthtml/VChartHTML.html

Most of the time the A+D* reaction is followed by a beta+ decay. But 
there are some exceptions

Jürg

Am 20.07.19 um 00:39 schrieb mix...@bigpond.com:
> In reply to  Jürg Wyttenbach's message of Fri, 19 Jul 2019 23:05:52 +0200:
> Hi,
> [snip]
>> In nuclear transformation (LENR) D* adds like a double proton and H*
>> adds like a neutron. That's what we see (exactly measure) from the gamma
>> radiation signature of complex reactions.
> Could you give a couple of example reactions? (I'm a little unsure of what you
> mean when you say "adds like".)
> Regards,
>
>
> Robin van Spaandonk
>
> local asymmetry = temporary success
>
>
>

-- 
Jürg Wyttenbach
Bifangstr.22
8910 Affoltern a.A.
044 760 14 18
079 246 36 06

RE: [Vo]:How to make money with cold fusion

[Arnaud Kodeck]

You are assuming that D + D gives He4. In the Mizuno reactor, we still don’t 
know exactly what is the reaction taking place there. It could be Ni + D -> Cu 
or Pd + D -> Ag. Let’s hope that that the Pd is not consumed in the Mizuno 
reactor otherwise all you plans in the cost for fuels felt apart.

 

From: Jed Rothwell  
Sent: Wednesday, 3 July 2019 15:22
To: Vortex 
Subject: Re: [Vo]:How to make money with cold fusion

 

JonesBeene mailto:jone...@pacbell.net> > wrote:

 

The first products will be the ones highest in commercial need for portable 
source of electricity, not heat. I doubt that mining cryptocurrency will be 
high enough in value as a niche market for any advanced energy generator. They 
only need cheap - nothing else overrides cheap for most markets. Deuterium and 
palladium will never be cheap.

 

Deuterium is far cheaper than any other fuel. High-purity heavy water costs 
about $1000 per kilogram, or $1/g. One gram produces as much energy as 523 
gallons of gasoline. At two dollars per gallon, that costs $1,046. See p. 33:

 

https://lenr-canr.org/acrobat/RothwellJcoldfusiona.pdf  

 

Most of the cost of heavy water is for the energy needed to extract it. It is 
also expensive because there is no demand for it and techniques for extracting 
it have not improved much since the 1950s. Extracting large amounts of heavy 
water with cold fusion energy will lower the cost by at least a factor of 10, 
so it will be roughly 10,000 times cheaper than gasoline.

 

 

As of now Pd is $1.40 per milligram but demand could push that up by a factor 
of 100 or more.

 

Palladium cost $50.27 per gram which is $0.05 per milligram. Roughly half of 
palladium is used in catalytic converters. These will not be needed with cold 
fusion, freeing up supplies. Mizuno's projections show that even a large 
generator will need only a few grams of palladium.

 

https://www.apmex.com/spotprices/palladium-price  

 

RE: [Vo]:Exponential and self-heating reactions are not necessarily unstable

[Arnaud Kodeck]

The huge size of the reactor is an advantage against runaway of the LENR 
reaction.

 

From: Jed Rothwell  
Sent: Friday, 28 June 2019 01:56
To: Vortex 
Subject: Re: [Vo]:Exponential and self-heating reactions are not necessarily 
unstable

 

Arnaud Kodeck mailto:arnaud.kod...@lakoco.be> > wrote:

 

The design of the reactor is huge to compare with the amount of heat.

 

Oh come now. Obviously it has not been optimized. It is 60 cm long and the 
meshes are only 30 cm long. It is half empty.

 

It also has not been driven to maximum temperature. Mizuno has projected that 
it could be far hotter with much higher power density.

 

RE: [Vo]:Exponential and self-heating reactions are not necessarily unstable

[Arnaud Kodeck]

The design of the reactor is huge to compare with the amount of heat. For 
comparison, we had a SS cylindrical reactor (heated by inside) of 25cm length 
and 10cm diameter. It needs roughly 1kW to  keep it at 1000°C. @1000°C it needs 
more than 2W to increase the temperature of 1K. The question is if there is 
enough LENR reactions that the exponential overcome what the reactor can emit 
as radiation(T^4) and convection (becoming ‘negligible’ at first calculation 
for this kind of temperature in air).

 

Moreover there shall be an excitation inside the R20 (yet to be discovered) 
otherwise there will be no improvement with R19 and before. 

 

From: Jed Rothwell  
Sent: Thursday, 27 June 2019 20:52
To: Vortex 
Subject: [Vo]:Exponential and self-heating reactions are not necessarily 
unstable

 

Two or three people have suggested to me that Mizuno's reaction must be 
unstable because it is exponential and self-heating. I do not think so.

I commented on this at LENR-forum. Let me copy a few paragraphs.



First, you can see this is anomalous heat. Look at the first 10 minutes of Fig. 
6, and the stray points in Fig. 8. Resistance heating does not act that way.

Now look at the increase in Fig. 6 from minute 10 to hour 1:40. It is sedate. 
When resistance heating is turned up, the reactor heats about as quickly as a 
toaster oven. It takes a while for that increase to reach the flow calorimetry, 
but it does not take an hour and 30 minutes. This gradual increase is from 
anomalous heat. The anomalous heat increases exponentially in response to 
temperature, but "exponential" does not mean rapid, or out of control, or 
unstable. It just means the heat goes to a proportionally higher level in 
response to higher temperatures.

The reaction must be self-heating to some extent. 50 W of resistance heating 
alone would never begin to reach these temperatures. In Fig. 6, around 1:40 the 
heat leaving the reactor balances the heat being produced in the reactor, so 
the reaction stops going to higher levels. It stabilizes. Again, self-heating 
does not mean going out of control. Burning wood must self heat or the reaction 
stops, but that does not mean a wood fire goes out of control, or that it never 
reaches a terminal temperature and a stable, terminal heat production level.

 

 

 

. . . Apart from this, I have a feeling the heater is boosting the reaction for 
some reason other than just higher temperatures, such as IR stimulation. I will 
let others with more knowledge of physics speculate about that.

 

Anyway, I do not think an exponential self-heating reaction necessarily means 
the reactor might go out of control.

 

RE: [Vo]:Fwd: Mizuno's Q and A to a person who wants to replicate

[Arnaud Kodeck]

Thank you for the answers.

 

I don’t agree about the heaters for 2 reasons. First, because if it is bent, EM 
generated is not equal to a straight inline heater. And secondly, the IR 
generated (and could be a stimulator of the reaction) depends on the type on 
heater it is. This cannot be ruled out so easily.

 

The reactor R20 is made of 2 standard conflat flanges and one pipe with 2 
conflats (on each side).  The flanges are available from the shelf of any 
vacuum supplier. On the other hand, the pipe is not not from the shelf. It 
needs to be built on demand. But maybe, this is from the shelf of the Mizuno’s 
supplier. In this case it would be nice to have the name of the supplier. So 
the replicator would have same SS tube (Size and composition).

 

Once the replication is successful, replicators can then change one variable at 
a time a confirm which variable is mandatory or not. In this perspective the 
idea to order the mesh (with Pd) directly is a good path for success. And also 
it can provide to Mizuno the necessary funding to repair other equipment broken 
by earthquake.

 

From: Jed Rothwell  
Sent: Tuesday, 25 June 2019 23:27
To: Vortex 
Subject: Re: [Vo]:Fwd: Mizuno's Q and A to a person who wants to replicate

 

Arnaud Kodeck mailto:arnaud.kod...@lakoco.be> > wrote:

 

Hi Jed,

 

Did you have by any chance some more information about the sheath heater? It is 
a 2m long, so how is the heater bent?  You said (I don’t remember if it is here 
or LENRForum) that you will ask the question to Mizuno.

 

I asked, but he has not had a chance to respond. When I asked him why he 
selected that heater, he said, "because it was the cheapest one."

 

It has to be 500 W and heat resistant at high temperatures. I expect any heater 
that meets those specifications will do. I doubt it matters. That is probably 
the first time I have said, "I doubt it matters" with regard to materials in a 
cold fusion experiment. Usually we have no idea what matters but we have to be 
fanatically careful about sourcing all materials.

 

 

Other thing, can Mizuno provide his supplier of SS316 tube ? The devil is in 
details.

 

I will ask. 


Mizuno has a local specialized company fabricate his reactors out of stainless 
steel. They are always bolted together not welded, as you see. They have thin 
metal gaskets. I do not recall what metal it is. The reactor has to be airtight 
enough to hold a vacuum for weeks, and it must not contaminate the gas at high 
temperatures. That is about all I know about it. I expect any stainless steel 
reactor that meets these specifications will do. I recommend you test it for a 
week, baking it out at low pressure and looking for contamination in the gas, 
using a mass spectrometer.

I do not know much about welding, but I do not think you should weld a reactor 
because I have heard the welds might leak, or contaminate the gas. I suggest 
you have a reactor fabricated by a specialized company. You might be able to 
find scientific supply houses that sell off-the-shelf reactors.  

 

I have a feeling this experiment is not fussy about the sources of the 
materials, or contamination. Mizuno is usually very careful about 
contamination, as are all electrochemists. He seems almost lackadaisical with 
this experiment. The method of making the reactant seems frightfully crude. I 
am amazed that it works at all. Yet it does seem to work. If it works, I'm 
happy, and I am not going to argue with Mother Nature about it.

- Jed

 

RE: [Vo]:Fwd: Mizuno's Q and A to a person who wants to replicate

[Arnaud Kodeck]

Hi Jed,

 

Did you have by any chance some more information about the sheath heater? It is 
a 2m long, so how is the heater bent?  You said (I don’t remember if it is here 
or LENRForum) that you will ask the question to Mizuno.

 

Other thing, can Mizuno provide his supplier of SS316 tube ? The devil is in 
details.

 

Thank you,

Arnaud

From: Jed Rothwell  
Sent: Tuesday, 25 June 2019 16:17
To: Vortex 
Subject: [Vo]:Fwd: Mizuno's Q and A to a person who wants to replicate

 

A person who is thinking of replicating Mizuno's experiment asked series of 
questions in English. I wrote some responses myself. Then I translated 
everything into Japanese. Mizuno confirmed my responses and wrote some 
additional comments. I translated his responses back into English.

 

I recommend this method of communicating to avoid confusion and make life 
easier for both parties. It is good to have everything in writing. Frankly, 
this is probably a more effective way to communicate and to nail down the 
details than travelling to Japan and asking questions. This is especially 
effective in the initial phases of a replication.


Here are some of the questions with Mizuno's answers, translated, condensed and 
rewritten by me.


Does the mass of reactant matter?

The more reactant you have, the better, so please put in as much as possible.

Is there an optimum number of layers?

Probably, the more layers the better, without an upper limit.

Is the choice of Pd important?

Probably not. But you should rub it hard. The hypothesis is that by strongly 
rubbing the Pd into the Ni, you break up the oxide layer and create complex 
phases of metal on metal. That’s what I think is happening, but I do not 
understand the mechanism yet.

What about the choice of detergent, or the choice of the scrubbing pad?

I do not suppose the choice of detergent has an effect on excess heat 
generation. It probably has nothing to do with it. Just use whatever type you 
like. However, be sure to rinse thoroughly. This is necessary. I also doubt the 
choice of scrub pad has anything to do with heat generation. However, be sure 
to scrub the mesh thoroughly and then wash with alcohol.

 

ADDITIONAL COMMENTS BY ME:

 

I doubt the source of meshes matters, as long as they are Nickel-200, 180 mesh.

 

My gut feeling is that any source of Ni or Pd will work, as long as they are of 
sufficient purity and you avoid contamination, or you clean off contamination. 
This method of applying Pd is so crude, there must be large variations in the 
resulting material. So it seems unlikely the details matter. I think that the 
source of material is probably less important than material preparation. You 
have to clean the mesh and roughen the surface as instructed. Probably the mass 
of reactants and the geometry are important.

 

RE: [Vo]:Yokose et al. report 3 kW peak power from Cu-Ni-Zn composite

[Arnaud Kodeck]

At ICCF21, JBP was also reporting such runaway event with PdNiZr powder. The 
quantity of PdNiZr was about 100g when the runaway occurred. The runaway 
phenomena stopped when temperature reached ~450°C which is the upper limit for 
this kind of powder. The difference is that the runaway started from room 
temperature. No heat had been feed to the reactor.

 

The colour of the powder(black) was exactly the same as JPB had after the 
runaway. Normally this powder is metallic grey after deoxidation not black.

 

Arnaud

 

From: Jed Rothwell  
Sent: Tuesday, 30 October 2018 16:13
To: Vortex 
Subject: [Vo]:Yokose et al. report 3 kW peak power from Cu-Ni-Zn composite

 

See:

https://www.researchgate.net/publication/328547673_Anomalous_Heat_Burst_by_CNZ7_Sample_and_H-Gas

My comment:

The sample is ~1 kg. That is much more material than you were using years ago. 
That's good! I am very pleased to see that people are increasing the mass of 
reactant. I believe that is why the level of heat increased. I believe more 
heat comes from a larger number of active sites.

Okay, that may seem like an odd thing to say. It may seem obvious that heat 
will increase as the mass of reactant increases. But I do not think that has 
been tested -- or demonstrated -- up until now. We just assumed that is how it 
works.

Even what we consider obvious aspects of the phenomenon should be tested. It is 
possible that a giant mass of reactant might have no active sites. Or it might 
sinter and stop working.

I am pleased to see larger samples being tested, but that does not mean small 
scale tests such as Beiting and Staker are useless. They do superb calorimetry 
and their signal to noise ratio is high, so there is much to be learned from 
their tests as well. I am glad to see high s/n small-scale tests AND glad to 
see scaled-up tests. Both are valuable.

Note that Staker also reported run-away heat events. I believe they are roughly 
similar in scale to this, when you adjust for the amount of reactant and 
surface area.

 

Beiting:

 

http://lenr-canr.org/acrobat/BeitingEinvestigat.pdf

 

Staker:

 

http://coldfusioncommunity.net/wp-content/uploads/2018/10/ICCF21_Staker_2_Oct_2018.pdf

 

- Jed

 

RE: [Vo]:Ferrous alloys and spin energy transfer - mostly overlooked in LENR

[Arnaud Kodeck]

Like Mizuno but Mu metal instead of Ni.

 

From: JonesBeene [mailto:jone...@pacbell.net] 
Sent: Friday, 12 January 2018 19:35
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Ferrous alloys and spin energy transfer - mostly overlooked 
in LENR

 

To clarify:

 

Variance of good catalysts from the ideal 2Ry = 27.2 eV in ionization potential 
(the catalytic “hole”)
 
1)  Molybdenum  .07
2)  Potassium   .09
3)  Rubidium.09
 
BTW - palladium has a fit at 27.77 eV (.57 variance) which is much further from 
an ideal catalytic value than moly. But moly is a poor proton conductor.
 
This may indicate that hydrogen absorption is more important than catalytic 
fit. 
 
AFAIK – no one has ever tried the tactic of alloying or electroplating Pd onto 
Mu metal to optimize both goals.

 

---

 

… which brings to mind Claytor’s statement that the best alloy he has found for 
LENR was a Mu metal alloy. 

 

The use of Mu Metal as the active matrix for LENR could turn out to be the most 
valuable detail relative to spin and LENR if Claytor is correct … using “ 
Co-Netic” as the matrix alloy. Mu-metal is a nickel-iron alloy, and the 
proprietary alloy  in question, Co-Netic - has high added molybdenum. 

 

http://custommagneticshielding.magneticshield.com/category/co-netic-sheet-and-foil

 

The high permeability makes mu-metal useful not only for shielding against 
static and low-frequency magnetic fields but also in converting most of the 
energy of an anomalous self-generated field into heat. This is a "soft" 
magnetic material that saturates at low magnetic fields and that is the key to 
the coupling magnons into heat. The high number of inherent Rydberg levels in 
the ionization potential of this alloy could be the key. BTW – it should be 
noted that  Molybdenum is the closest Rydberg ionization fit to Mills theory of 
all metals. That could be another key to understanding. No other metal is as 
close to the precise value.

 

RE: [Vo]: English translation of Parkhomov's latest presentation

[Arnaud Kodeck]

Thank you Bob for this nice translation. Shame there is no pressure 
measurements reported hence there was a transducer. Did they have problem with 
it? From Me356, pressure is a key ppint to control for the road to success in 
Ni/H LENR experiment.

 

COP 1.1~1.3 is below what Parkhomov had shown us with his boiler 2 years ago. 2 
years ago Parkhomov was using a chopped/dirty AC to control the power. This not 
the case this mass flow calorimetry. Is this the reason for the low cop ? Or 
pressure ?

 

Arnaud

 

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: vendredi 24 juin 2016 16:19
To: vortex-l@eskimo.com
Subject: [Vo]: English translation of Parkhomov's latest presentation

 

Good morning Vorts,


Here is a link to my Google drive folder having the English translation of A. 
Parkhomov's latest (6/23) presentation.  The link is to the folder containing 
the translation, and if updates are needed, I will put them in this same folder.

 

https://drive.google.com/open?id=0B5Pc25a4cOM2YnpFakRobUE1clE

 

Bob Higgins

RE: [Vo]:How Current Loops and Solenoids Curve Space-time

[Arnaud Kodeck]

Here is an interview of André Füzfa is the local newsweek:
http://www.levif.be/actualite/sciences/maitriser-la-gravitation-le-belge-qui
-bouscule-la-theorie-d-einstein/article-normal-447671.html

 

It is written in French.

Arnaud

  _  

From: Rich Murray [mailto:rmfor...@gmail.com] 
Sent: mardi 12 janvier 2016 05:49
To: vortex-l@eskimo.com; Rich Murray
Subject: Re: [Vo]:How Current Loops and Solenoids Curve Space-time

 

http://www.unamur.be/services/sevrex/sevrexp/librecourriel/2013/lcl-79/fuzfa
-andre/view

 

nice friendly happy bright confident open face

 

ah, what will be emerging by 2116... ??

 

!! Rich

 

On Mon, Jan 11, 2016 at 6:42 PM, Axil Axil  wrote:

The Rodin coil is raped in a vortex. It produces a monopole magnetic field.

 

https://www.youtube.com/watch?v=ZefDwDzHKLA

 

 

 

On Mon, Jan 11, 2016 at 8:48 AM, Jack Cole  wrote:

Saw this posted to the Google+ LENR group.  Seems interesting and has at
least been accepted for publication in Physical Review D
 .  The full paper is available on Arxiv
 .

 

They do propose a method of producing gravity through electromagnetism and
detecting the effects.  There does not seem to be any new physics proposed.
Although the effect would be minuscule and likely of no practical value in
the immediate future, they note:

 

"Such a detection of the space-time curvature generated by a magnetic field
in laboratory would constitute a major step in physics: the ability to
produce, detect, and ultimately control artificial gravitational fields. And
would this technology be developed, it could lead to amazing applications
like the controlled emission of gravitational waves with large alternative
electric currents. Gravity would then cease to be the last of the four
fundamental forces not under control by human beings."

 

Jack

 

 

RE: [Vo]:Jiang slides Fig. 6

[Arnaud Kodeck]

 

 

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: mercredi 3 juin 2015 21:15
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Jiang slides Fig. 6

 

Arnaud Kodeck arnaud.kod...@lakoco.be wrote:

 

BUT,

 

At point A, the power is lesser than at B, but temperature is higher! We
should have the opposite.

 

I do not think the difference in input electric power is significant. Just
before hour 06:00 the power was turned down. I think the red temperature T1
is still falling at the point you marked A.

 

You are right here. T1 is still falling but at a very slow pace. It will
never go down below point B at that point of falling rate.

 

Moreover, if there is excess heat occurring at point B, the delta of T1 (@ B
- @ A) should even higher! So I doubt here that there is excess heat at
point B.

 

Yes, I agree this is a problem. As you say, the T1 temperature at B is a
little lower, but it should be much higher. If there is anomalous heat
coming from the core of the reactor, that should push T1 up, well above
where it goes with heat from the electric heater only.

 

From hour 12:00 up to about 15:00 (when T3 breaks) input electric power is
fairly stable. It goes up only a little. Yet the T1, T2 and T3 temperatures
all rise. That looks to me like real excess heat coming from somewhere in
the reactor. At 15:00 T2 and T3 are still below T1, which I suppose
indicates the excess heat is lower than the input electric power heat.

 

Yes something has happened for sure. That is undoubtedly.

I cannot tell whether this excess heat is anomalous (from cold fusion) or
whether it is a chemical reaction.

 

I think at point B the T1 temperature should be much higher than it was at
point A if there is still excess heat being produced. It should stay up at
the peak it reached at around 16:00, an hour after T3 broke.

 

My assumption, the event between 12:00 and 15:00 has been above a threshold
that destroyed the NAE. That's just an hypothesis .

- Jed

 

RE: [Vo]:Jiang slides Fig. 6

[Arnaud Kodeck]

Look at the speed of rise when it reached 1300°C. It is just not like as it
will stop at 1301°C … The event was very strong. Chromel (Ni80%, Cr20%)
melts at 1420°C.

 

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: mercredi 3 juin 2015 21:36
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Jiang slides Fig. 6

 

Arnaud Kodeck arnaud.kod...@lakoco.be wrote:

 

Another point, the T2 thermocouple has been to a temperature far above what
chromel or alumel can survive to. The temperature of T2 increased far above
1400°C.

 

How do you know that? The line is cut off at 1300°C. There is no telling how
much higher it went. I do not think the thermocouple would be destroyed if
it went only a little above the maximum temperature for K-type thermocouples
(1372°C).

- Jed

 

RE: [Vo]:Jiang slides Fig. 6

[Arnaud Kodeck]

Thank you Jed for the improved quality for the pictures.

 

Look at my picture http://imgur.com/oAMdOfT

 

I’ve drawn 2 vertical lines: One before the T3 failure called A, and one
after the T3 failure called B.

 

It is supposed than at A, the excess heat didn’t started. At point B, it is
supposed that excess heat is occurring because T2 is above T1.

 

BUT,

 

At point A, the power is lesser than at B, but temperature is higher! We
should have the opposite.

 

Moreover, if there is excess heat occurring at point B, the delta of T1 (@ B
- @ A) should even higher! So I doubt here that there is excess heat at
point B.

 

Another point, the T2 thermocouple has been to a temperature far above what
chromel or alumel can survive to. The temperature of T2 increased far above
1400°C. Most probably, the T2 has been destroyed at that moment. The
measurements that the T2 gives after the breakdown can not be trusted
anymore. A new experiment with type B thermocouples (T2 and T3) should be
redone before stating any conclusions of excess heat.

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: mercredi 3 juin 2015 16:58
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Jiang slides Fig. 6

 

Jiang sent me a cleaner version of his Fig. 6 data. I will translate the
headings and annotate this later. See:

http://lenr-canr.org/Collections/Jiang%20DATA%202015-May-04%20to%20May-07.pd
f

Below the x-axis it just says Channel 01, Channel 02 . . . I am not sure
what channel is what. I think it is:

01 T1 (thermocouple 1, placed at heater)
02 T2
03 T3

04 Pressure?

05 ??

06 Power supply

07 T4? Temperature at outside surface (outside MgO insulation) Pretty sure.

08 (white line) not used, except that it shows a pulse at around 09:00 on
May 6.

- Jed

 

RE: [Vo]:Jiang slides Fig. 6

[Arnaud Kodeck]

Thank you Jed for the info you share with us.

 

What concern me here in this test is that T1(red) has not the same behaviour 
before and after that T3(blue) has broken. For the same voltage (cyan), the 
maximum temperature reported by T1 aren’t correlated with an excess heat 
occurring. If an excess heat was present, and for the same voltage, T1 after T3 
broken should be above T1 before the T3 broken. It is not the case, worst it is 
even below. T1 doesn’t show any excess heat, even if it is the farther of the 
TCs.

 

How can you believe a TC after he has reached is maximum allowed temperature? 
T2 has moved far above the limit, how the chromel or alumel will behave after 
the cooldown, if we can still call them chromel and alumel … I’m pretty sure 
this is not a Type K TC anymore.

 

Anyway, for sure, something happened when T3 has broken: Chemistry or LENR 
excess heat?

 

Arnaud

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: mardi 2 juin 2015 23:39
To: vortex-l@eskimo.com
Subject: [Vo]:Jiang slides Fig. 6

 

To reiterate, Jiang's slides are here:

https://www.scribd.com/doc/267085905/New-Result-on-Anomalous-Heat-Production-in-Hydrogen-loaded

Here are his additional comments:

http://www.e-catworld.com/2015/06/01/songsheng-jiang-answers-questions-on-lenr-replication-report/

Here is a comment he sent to me.

The experiment curves on the screen of the computer (Fig. 6) were measured in 
4-7 May, 2015. The curves of T1 (red), T2 (green), T3 (blue), power voltage 
(cyan) and pressure (yellow) display on the screen. The T3 (blue) was broken 
down,  when  temperature  rose to  about 1100 0C on 5 May, 2015. Since then, T3 
worked abnormally, it was not tracking T1 completely (also showing in Figure 
7a).

I annotated the graph shown in Fig. 6 to show what I think he means:


​​
The annotations are:

T1 higher than T2, T3
T3 (blue) malfunction
T3 erratic [malfunction continues]
T2 exceeds 1372°C [It exceeded that temperature earlier, briefly]

It does look like T3 malfunctioned suddenly. It stayed low, well below T1 (the 
red line).

I asked him how many hours Fig. 6 shows. Maybe it is the entire 96 hours?

- Jed

 

RE: [Vo]:Re: Parkhomov Ash Analysis Discussion - Preliminary

[Arnaud Kodeck]

Hello Mark,

 

If we consider that  Sample1  is fuel and Sample2 is ash, then there is
a clue that 64Ni could be converted to 65Cu in the Parkhomov reactor!

 

Let me show the maths:

If other Ni isotopes don't react then the quantities of Ni for each isotope
stay the same except for 64Ni:

58Ni: 64.03   60Ni: 26.34   61Ni: 1.22 62Ni: 3.99
64Ni: 2.85 Total = 98.43 (1.57 is assumed to be converted into 65Cu)

And in percentage, it gives then: 58Ni: 65.05 60Ni: 26.76   61Ni:
1.24 62Ni: 4.05

 

Those values are in the range of the sample2 data for the Ni, except a
slight deviation for 60Ni . more 60Ni found in the ash than calculated.

 

In the Lugano analysis, the 64Ni has disappeared. All converted in 65Cu?

 

Arnaud

  _  

From: Mark Jurich [mailto:jur...@hotmail.com] 
Sent: jeudi 23 avril 2015 11:51
To: vortex-l@eskimo.com
Subject: [Vo]:Re: Parkhomov Ash Analysis Discussion - Preliminary

 

FYI: Typo Fixed (30.1 - 30.9 in Natural State 65Cu Cell)

 

From: Mark Jurich mailto:jur...@hotmail.com  

Sent: Thursday, April 23, 2015 1:28 AM

To: vortex-l@eskimo.com 

Subject: Re: [Vo]:Parkhomov Ash Analysis Discussion - Preliminary

 

FYI:

 

Here is a link to the latest updated Elemental  Isotope Analysis in

Excel XLSX SpreadSheet (Sheets 1  2) Format:

 

http://tinyurl.com/lcnudcv

 

Mark Jurich

 

From: Mark Jurich mailto:jur...@hotmail.com  

Sent: Wednesday, April 22, 2015 12:02 AM

To: vortex-l@eskimo.com 

Subject: [Vo]:Parkhomov Ash Analysis Discussion - Preliminary

 

As many of you know, some preliminary Elemental Analysis (SIMS?)

and ICP-MS of Parkhomov Ash/Fuel were released during ICCF-19 in

Padua, Italy. At the FaceBook MFMP Site, some pictures of the analysis

were taken and posted:

 

http://www.e-catworld.com/2015/04/21/mfmp-publishes-parkhomovs-fuel-analysis
-video-of-parkhomov-discussion/

 

From the Elemental Analysis, it roughly looks like Ni is lost with a 

gain in Cu, but we all know how careful one has to be analyzing this.

Some of the Nickel might have coated something other than the ash.

Due to some issue, the Li Analysis is incomplete and will most likely be

resolved soon.  I believe Parkhomov has 2 more Fuel/Ash Analysis being

undertaken at this time, also (EDX and ?).

 

An incomplete picture of the ICP-MS Analysis roughly shows the following

(amongst other things  if we assume Rows 1  2 are Ash Analysis and

Row 3 is the Fuel Analysis):

 

https://www.facebook.com/MartinFleischmannMemorialProject/photos/p.959743037
389729/959743037389729

 

  6Li -  7Li

58Ni -  64Ni

 

Obviously, it's not as simple as this, but I wanted throw a bone out

there for us to chew on.

 

My guess is that Row 1 is a Best Run, Row 2 is a Pretty Good Run and

Row 3 is the Starting Fuel (since Li, Ni  Cu are at almost Natural
Abundances).

Tomorrow morning I will talk to a Russian American and try to decipher the
Cyrillic,

since no one at the MFMP Site has done it yet...

 

6Li is depleted by half, with the difference showing up as 7Li.

64Ni shows a gain of about 5 with the loss roughly showing up in 58Ni.

65Cu Values  ? seem to be cut off in the picture, and hopefully we will get

this data soon.

 

What do YOU think is happening?

 

As soon as I get a chance, I will post further links from the MFMP and E-Cat

World Sites for the Internet-Challenged amongst us.

 

Mark Jurich

 

RE: [Vo]:Yevgen Barsukov propose Parkhomov/MFMP reaction is chemistry

[Arnaud Kodeck]

Alain,

 

The excess heat generated by Parkhomov’s experiment (if real) is far above
any chemical reaction. 3 Li + 2 Al2O3 - 3 LiO2 + 4 Al doesn’t produce much
energy. The Li inside the reactor is very small 100 mg?

 

But Li could corrode the wall of AL203 making it less strong to resist to
the high pressure inside the reactor.

 

It could be an explanation of the BANG of MFMP. It can’t rule out excess
heat.

 

Arnaud

  _  

From: alain.coetm...@gmail.com [mailto:alain.coetm...@gmail.com] On Behalf
Of Alain Sepeda
Sent: mercredi 11 février 2015 14:48
To: Vortex List
Subject: [Vo]:Yevgen Barsukov propose Parkhomov/MFMP reaction is chemistry

 

Hi,

about recent Ni+LiAlH4 experiments done by Parkhomov and MFMP

on facebook group, Yevgen Barsukov propose that it is a chemical reaction:

 

 
https://www.facebook.com/MartinFleischmannMemorialProject/posts/92012771135
1262
https://www.facebook.com/MartinFleischmannMemorialProject/posts/920127711351
262

 

After decomposition of LiAlH4, pure lithium is left. Lithium is reacting
with the walls of the tube made of Al2O3, being a stronger metal than
aluminium it takes away its oxygen with release of heat.

 

is it an interesting hypothesis to check ?

 

I think we should also integrate in the reasoning the phase of LiAlH4
decomposition which is probably endothermic...

 

What is the total sum ? maybe this mean the reactor swallow heat at the
beginning, and restore more , or less, later...

 

what is the quantity of heat expected compared to the one AG Parkhomov
measured?

RE: [Vo]:Jack Cole improvement in LiOH design

[Arnaud Kodeck]

From the Lugano report. At page 44, the particle called number 3 has mainly
Fe and O in its composition.

 

  _  

From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: mercredi 28 janvier 2015 23:08
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Jack Cole improvement in LiOH design

 

From: Arnaud Kodeck 

 

*  It is known that Rossi uses Fe2O3 to increase the splitting of H2
molecules into H atom. 

 

How is this known, Arnaud ? 

 

I have heard it before, but there are many rumors floating around the
internet concerning Rossi's catalysts, most of which are guesses or based on
ppm found in ash. Many elements can turn up in the ash of experiments due to
migration - and iron and copper are very mobile at high temperatures.

 

In general, a catalyst which splits H2 molecules is called a spillover
catalyst. There is a great deal of information out there on this subject.
Nickel is a good spillover catalyst as is palladium, so there is no need for
another one - unless that catalyst provides something else. 

 

OTOH, iron and oxygen are both Mills' catalysts and anyone who has followed
Mills over the years will understand that in his experiments, good results
often depend on having 3 or 4 catalysts with different values operating
simultaneously, so Fe2O3 does fit that way as a matter of logic - at least
for those who favor a Millsean approach.

 

Jones

 

 

RE: [Vo]:Jack Cole improvement in LiOH design

[Arnaud Kodeck]

Hello Jones,

 

Do you want to keep your lime sauce secret?

 

Arnaud

  _  

From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: mardi 27 janvier 2015 18:28
To: vortex-l@eskimo.com
Subject: [Vo]:Jack Cole improvement in LiOH design

 

Jack Cole continues to improve his prior results, based on a simplified
Rossi/Parkhomov alumina tube reactor - with the aim of finding a safe and
reliable baseline experiment which almost anyone can pull off, even a
physics professor, in order to see thermal gain greater than chemical. 

 
http://www.lenr-coldfusion.com/2015/01/27/replication-nilioh-excess-heat-re
sults/
http://www.lenr-coldfusion.com/2015/01/27/replication-nilioh-excess-heat-res
ults/

Please note:

1)  Yes, Jack's experiment is low gain (COP~ 1.1) for now, and has no
frills, but it is simple and SAFE and does not require large power input
(although larger input is being considered)

2)  LAH is a dangerous reactant and only skilled experimenters with a
glove box should even think about it

3)  This experiment is now looking repeatable, and given that it is
safer, since there is no LAH, hopefully it will be replicated by many, or
else someone will discover where the experimental error lies and why
control-run calibrated thermometry (as in Lugano) can't be trusted. (note:
everyone agrees that this should move to precision calorimetry eventually,
once the gain is improved).

4)  Please do not be overly critical of low budget efforts where the
gain is based on calibration against a dummy reactor. Not everyone can
afford foolproof calorimetry, but anyone can make small cumulative advances
to a common theme, if the underlying experiment is safe enough and
inexpensive. 

5)  In fact, Cole's technique is similar but better performed than the
Lugano report, since he did use calibrated thermocouples which Levi failed
to do.

6)  Since the resistance wire is internal the experiment cannot reach
temperatures in excess of say 1000C but lower temperature will show thermal
gain. But this makes the experiment much simpler.

7)  In principle, COP of 1.1 is no less AMAZING than COP 2.5, if the
gain is above chemical, since both are arguably outside the laws of normal
thermodynamics.

Jones

RE: [Vo]:Jack Cole improvement in LiOH design

[Arnaud Kodeck]

Thank you Jones for the details. Rossi Hot cat starts to have a COP1 at
lower temperature than Parkhomov. It is known that Rossi uses Fe2O3 to
increase the splitting of H2 molecules into H atom. Rossi might also use CaO
for its luminescent property. CaO luminescence is in the NIR range, not the
FIR range as we spoken here at Vortex a few months ago.

 

 

  _  

From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: mercredi 28 janvier 2015 16:49
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Jack Cole improvement in LiOH design

 

Arnaud,

No there is no secret sauce, in the sense of a catalyst, if that is what
you mean, as this is basically a luminescent cement binder and there could
be better ones out there. 

In general, since experiments are ongoing - it is preferable to optimize the
blend first so as not to add confusion when something better turns up. This
blend does seem to seal tighter than the previous cement, yet it is not
clear that this cement adds anything other than extra photons. Jack made
other changes to the fuel which I am certain he will announce when he gets
the gain higher. 

The working hypothesis is that SPP formation is at the heart of the
Parkhomov reaction, and that SPP can be increased at a given temperature by
using a luminescent cement which is also a dielectric and can be in direct
contact with the conductor. That is the premise.

Lime is luminescent but probably would not work alone as it is corrosive.
The hope is that a fuel mix containing some CaO will emit photons at the
same intensity as Parkhomov but at much lower temperature - hopefully
200-300 degree lower - allowing an internal heater - instead of an external
heater. 

SPP form at the interface of a conductor and a dielectric - get it? There
are therefore large advantages to using a nickel based INTERNAL heater at
lower temperature and no LAH. That is, if you buy into SPP.

OK- so as to make this more transparent to anyone who wants to jump in now -
the fuel binder mix is about 32% CaO and 65% alumina. If you want to try
something similar from a vendor, look for a cement like Secar 71. I do not
know the proportions of the other ingredients Jack used, but I think he
dropped the iron oxide and wished he have used more nickel. He is using
Vale255 nickel. Jack is switching the heating wire from Kanthal to
nichrome-80 which should be a big improvement and will add nickel at the
interface (iron is also a catalyst for f/H, but corrodes easier). Kanthal is
mostly iron.

It is very possible that greater gain will be had from only adding more
nickel, both in the wire and/or as nickel powder in the mix. 

But go for it now - if you are ready, since any COP greater than one is
worth the effort.

From: Arnaud Kodeck 

Hello Jones,

Do you want to keep your lime sauce secret?

Arnaud

RE: [Vo]:the Parkhomov paper translated

[Arnaud Kodeck]

We don’t know when the picture has been taken. It could be that the picture
is taken just after the electrical power switch off. (After ~21:05 see
figure 6)

 

  _  

From: Finlay MacNab [mailto:finlaymac...@hotmail.com] 
Sent: lundi 29 décembre 2014 23:01
To: vortex-l@eskimo.com
Subject: RE: [Vo]:the Parkhomov paper translated

 

 

It is interesting that in figure 4 of the report the heating coils wrapped
around the Al2O3 cylinder appear dark.  

 

This suggests that the inside of the cylinder is hotter than the coils.  

 

http://www.e-catworld.com/wp-content/uploads/2014/12/Lugano-Confirmed.pdf

RE: [Vo]:Who could it be???

[Arnaud Kodeck]

There is one missing in the list below: Brian Ahern who has released some
patents and has joined the MFMP team.

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: dimanche 23 novembre 2014 03:23
To: vortex-l
Subject: Re: [Vo]:Who could it be???

 

Since Rossi says that the system in question is based on E-Cat technology,
then the system must be from Piantelli. 

 

On Sat, Nov 22, 2014 at 8:29 PM, Jed Rothwell jedrothw...@gmail.com wrote:

Rossi does not believe Defkalion has anything, so you can take that off your
list.

 

Michael C. H. McKubre lists the following LENR players:

Those embarked on practical demonstration include:

Black Light Power (US) - raised ~80M, know little about them. Not CF?*

Piantelli (Italy) - visited 2012, confirmed results, still working on
science.*

Rossi (Italy and US) - sold, bought*X  verified? Report reviewed in
October.

Defkalion (Greece, Italy and Canada) - Rossi spin-off, real product?*X

Brillouin (US) - working with SRI.*

That leaves only 3.

 

- Jed

 

 

RE: [Vo]: New Rossi lab photo has much information

[Arnaud Kodeck]

Bob,

 

Nice analysis. The eCats are configured in star or triangle. I think from
what analysed is that it is a star with a free neutral.

 

This could be also disinformation. This configuration might have never
worked at all and be published one year later to lead the replicator in the
wrong direction.

 

Arnaud

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: lundi 3 novembre 2014 15:49
To: vortex-l@eskimo.com
Subject: [Vo]: New Rossi lab photo has much information

 

Bob Greenyer of MFMP just posted this image of Rossi's lab with 3 hotCats
being tested and I put it on my Google drive:

 

 
https://drive.google.com/file/d/0B5Pc25a4cOM2U3FIWmpCMnlZaFE/view?usp=sharin
g

 

A wealth of information can be gleaned from this:

* Rossi is testing 3 hotCats simultaneously.

* Each hotCat is connected with 2-wires only - Each IS CONNECTED
SINGLE PHASE! This probably means that the hotCat only relies on heat-up,
not magnetic field interaction - certainly not rotating field interaction.

* The gray box has 3 thermocouple connections with one going to each
hotCat

* The gray box controller is controlling the energy to all 3 hotCats
via the red 3-phase SCR controller in such a way as to control the
temperature of each hotCat independently.

* This gray box controller is designed to control each hotCat solely
based on 1 temperature measurement per hotCat.  The temperature controllers
mounted on the gray box are probably each controlling the setpoint of each
hotCat (I.E. they are not being used just as temperature meters).  A
microcontroller in the gray box may read each meter (RS232) and then sets
the SCR angle for that phase to control the power to each hotCat.  

* The red SCR box may be configured for delta SCR configuration for
easy control of the individual hotCats, in which case a microprocessor would
not be needed.  Each of the little PID temperature controller panel meters
could directly control the corresponding SCR in the delta phase
configuration.  Even if the red box had y-configured SCRs, they probably
could be controlled with the panel temperature controllers with simple
logic.

* Replication need not use a 3-phase heater coil inside the hotCat
because there is no need to simulate an industrial environment.  Replication
just got easier.  Basically each hotCat is just a small temperature
regulated mini-tube furnace.  It would be possible to design the replica to
operate on ordinary US 120VAC, even with a 15A outlet using a triac dimmer
with an inexpensive PID temperature controller from eBay.

Bob Higgins

 

RE: [Vo]:temperature of the resistor wire.

[Arnaud Kodeck]

There are a lot of assumptions, but you are probably right. It would be
surprising that the team didn't have a look from the 4 mm hole. What is
inside of the eCat is the most important to witness (even more important
that the COP1). A 4 mm hole is enough for an eye to see the inside of the
tube. Even a camera of a smartphone can do this. That is a question we need
to ask to the test team. They should answer us and remove any doubts.

 

If the test team was not allowed to examine the inside of the eCat, it means
then that the test wasn't independent, but well under the Rossi's tricks. It
would be nice to have an answer from the tester about this as well.

 

In the case of the ash, most probably, the results aren't presentative at
all of the real reactant. The ash has hardened and glued to the inside of
the tube and taken back by Rossi. We shouldn't concentrate too much on the
ash except that we see transmutation ongoing inside of the eCat with
isotopic change without gamma.

 

Arnaud

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: samedi 18 octobre 2014 16:29
To: vortex-l@eskimo.com
Subject: Re: [Vo]:temperature of the resistor wire.

 

The reaction tube was only a 4mm diameter hole and as much a 28 cm deep.  In
addition, there was the plug for this end in the center of which the
thermocouple was glued.  The thermocouple must be present as part of the
CCI/MicroFusion 3-phase control system.  So, even while it was not clear
from the report, the dummy runs would have been operated with the plug in
the hole (probably not glued), obscuring the view into the hole.

 

Rossi himself added the powder to this hole in the presence of others and
glued in the plug.  Rossi removed the plug and then the ash in the presence
of others, probably not allowing them the difficult view down the reaction
tube.  Brian Ahern says, The Rossi test had the unknown condition that he
be present at the test and nobody was to gain unfettered access to the
ingredients.  So, it is highly likely that no one had the opportunity to
inspect the inside of this 4 mm hole well enough to know if it was virgin
ceramic or powder was inside.

 

The upshot is that we don't know that the added powder was really the whole
fuel; and it is highly likely, as I said, that it was just the consumable
portion plus maybe some obfuscation Ni powder.  In the case of the ash, the
only thing that came out was debris that had loosened from the inside.  The
quartz was likely from a grain in the alumina or part of the coating on the
inside of the tube.  Where did the 62Ni come from?  With the temperature
excursions of this tube, it is likely some portions flaked off from its
attachment to the inside of the tube, and it was there was random junk slag
from the reactions.  So the ash cannot be said to have evolved from the
input powder, which itself was not the active fuel.

 

Bob Higgins

 

On Sat, Oct 18, 2014 at 2:52 AM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Bob,

 

How do you know that the tube was first coated with enriched 62Ni as you
claim here below?

 

The observers could notice the presence of Ni on the inside wall by just
looking inside the eCat before the dummy run.

 

Arnaud

  _  

For all we know, the inside of the reaction tube was first coated with an
isotopically enriched 62Ni powder which was bonded or sintered to the inside
wall.  Then when the reactor was open, a few of the wall particles became
dislodged and became part of the ash.  These were not necessarily transmuted
from the fuel, because I believe we only saw some consumable powder
(probably the hydride) and maybe some obfuscation Ni powder.  The point is
that what was put in was not representative of the active fuel - it is a
clue, but not statistically representative of the active portion of the
fuel.  Obviously this is an opinion.  Given the high temperature, none of
what Rossi originally put in would have come back out, except perhaps some
small amount of the Ni that had collected in a colder spot in the reaction
tube.  What more likely came out were small pieces that had flaked off of
the sides of the reactor tube due to thermal expansion mismatch as it was
heated and cooled, that were in the tube before he put in the ~1g of
consumables taken to be the fuel.

 

 

RE: [Vo]:temperature of the resistor wire.

[Arnaud Kodeck]

Bob,

 

How do you know that the tube was first coated with enriched 62Ni as you
claim here below?

 

The observers could notice the presence of Ni on the inside wall by just
looking inside the eCat before the dummy run.

 

Arnaud

  _  

For all we know, the inside of the reaction tube was first coated with an
isotopically enriched 62Ni powder which was bonded or sintered to the inside
wall.  Then when the reactor was open, a few of the wall particles became
dislodged and became part of the ash.  These were not necessarily transmuted
from the fuel, because I believe we only saw some consumable powder
(probably the hydride) and maybe some obfuscation Ni powder.  The point is
that what was put in was not representative of the active fuel - it is a
clue, but not statistically representative of the active portion of the
fuel.  Obviously this is an opinion.  Given the high temperature, none of
what Rossi originally put in would have come back out, except perhaps some
small amount of the Ni that had collected in a colder spot in the reaction
tube.  What more likely came out were small pieces that had flaked off of
the sides of the reactor tube due to thermal expansion mismatch as it was
heated and cooled, that were in the tube before he put in the ~1g of
consumables taken to be the fuel.

 

RE: [Vo]:temperature of the resistor wire.

[Arnaud Kodeck]

The reason Rossi is using a 3 phases power supply might be the rotating
field created by a 3 phases AC power supply.

 

  _  

From: Robert Lynn [mailto:robert.gulliver.l...@gmail.com] 
Sent: jeudi 16 octobre 2014 11:09
To: vortex-l@eskimo.com
Subject: Re: [Vo]:temperature of the resistor wire.

 

All fair points of view Dave.  Though with regard to 3 phase, at 900W input
there is obviously no need, adds a lot of mechanical complexity (3 heater
wires rather than 1) and a little more electrical complexity and would still
get impulsive waveform using rectified DC + half H bridge to provide an ac
pwm output - really simple linear power control that is dead simple to
measure and control power output of, with much greater scope for variation
of pulse frequency and duration.  I doubt you or any other engineer or
electrician would choose to do it the crude and restrictive way he has.

 

Haven't tackled the electrical side of things much; but as an EE would you
agree that conceptually it would be possible to hide a 10kHz AC signal
superimposed on the grid supplied 3phase with amplitude a little less than
the AC so as not to trigger the Triac turn off?  (Hardware pretty simple,
just 50% duty cycle driven half-H bridge of phase added to the 50Hz signal
by means of a series transformer).  My rough calculation suggest that could
allow 3x the power to be delivered to the reactor without showing up on the
PCE meter or having any DC component.  Not that I think it likely (far too
much potential for getting caught by someone with a multimeter or
oscilloscope), but if the power meters were known to have a max frequency
threshold then could this allow you to deliver more power without it being
easily spotted?

 

On 16 October 2014 16:12, David Roberson dlrober...@aol.com wrote:

Sorry Robert, I will make every attempt to use your correct name in the
future.  Thanks for clarifying your reasons for exhibiting the strong
critical position against the report.

I admit that I harbor questions about the accuracy of the temperature
measurements for many of the reasons that you point out.  To me the slope in
COP with temperature and the particle analysis are strong indicators that
the device is generating some type of nuclear power within its core.  I can
not honestly believe that Rossi would be attempting a scam as you seem to
think...he risks far too much.  One tiny slip and he is toast.

I recall reading in his blog that Ni62 was the active element from a couple
of years back.  At that time he was talking of developing a process that
enriched the raw material in order to achieve that goal.  Could that have
been what he thought was happening within his reactor at the time?  That
would explain why he bought some of that isotope for research.  I give him
the benefit of the doubt.

The 3 phase power concern just does not hold water to me.  Remember the
device tested is not normally used in isolation, but instead is a part of a
much larger system.  Phase balancing is quite common when a large amount of
power is required and I would likely have done exactly the same thing as
Rossi.

There are other reasons that I believe the test proves that power is
generated within the core that I have covered previously and will not repeat
at this time since it is late here.

Dave

 

 

 

-Original Message-
From: Robert Lynn robert.gulliver.l...@gmail.com
To: vortex-l vortex-l@eskimo.com

Sent: Thu, Oct 16, 2014 2:20 am
Subject: Re: [Vo]:temperature of the resistor wire.

(Dave, my granddad is Bob, I'm Robert :) ), I would be over the moon if we
had incontrovertible evidence of COP, but with a strong grounding in and
respect for the scientific method you cannot and should not ever give bold
assertions a free ride without vigorous critical review the skeptics of the
world won't go any easier on him than I will.  Which is what I am trying to
provide, and unfortunately the harder I have looked at it and the more
issues I have analysed the more likely it seems that the gain = 1 hypothesis
is as strong as gain 1. 

 

Occams razor would then favour gain=1 rather than a collection of
miraculously fortuitous LENR characteristics that include numerous
transmutation pathways (fission and fusion of Ni and Li) without ionising
radiation, or change in reaction rate as it goes from natural isotope ratios
to essentially all Li6+Ni2,  But my suspicions really shot through the roof
after reading that Rossi bought 99% Ni62 from a commercial supplier at one
point - and that is why I decided to look so hard at the physical attributes
of the device (thermodynamics/hightemp materials are my forte) - to see
whether it was thermodynamically unabiguous that there was gain 1.

 

The needless ambiguity of the test raises my ire, that the power input is so
clumsily measured when it would be so easy to use series resistors, triac
switched single phase AC, PWM DC power supply or etc with the same
electromagnetic effects within the reactor.  Rossi with his 

RE: [Vo]:Engineering and materials issues with high temperature hot-cat Lugano demo

[Arnaud Kodeck]

Bob, 

 

Just a thought. I'm not an expert of magnetic confinement of plasma. But,
the  encaps  might contain a proper wires configuration to close the
rotating magnetic field formed by the 3 phases current.

 

Arnaud

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 17:05
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

I am pretty sure these endcaps are just mechanical supports for the hot
tube in the middle.  They are large alumina outer rings that have been
filled with a cast-able refractory insulation such as a Vitcast 1200 INS or
Vitcast 1400 INS-H.  They insulate the mounting apparatus from the hot
radiating tube.  They serve no other function.  The wires don't go through
these and they do not seal the ends.  They are just supports.

 

On Wed, Oct 15, 2014 at 11:32 PM, Eric Walker eric.wal...@gmail.com wrote:

On Wed, Oct 15, 2014 at 9:24 AM, Bob Higgins rj.bob.higg...@gmail.com
wrote:

 

I believe the large tubes on the end to be thermally insulating supports for
the hot central 2 cm tube.

 

A question that came to me was whether the alumina endcaps could be replaced
with metal endcaps of a suitable alloy in the context of a larger array of
devices, in order to provide a suitable path out for the heat to be used to
generate steam.  Another question I have is how much thermal load one of
these devices can handle.

 

Eric

 

 

RE: [Vo]:Engineering and materials issues with high temperature hot-cat Lugano demo

[Arnaud Kodeck]

So why then does Rossi use a 3phases electrical power source? For such kind
of power this not needed. 1000W uses less than 5A.

 

So my guess is that Rossi uses the Rotating magnetic field in its Ecat
(http://en.wikipedia.org/wiki/Rotating_magnetic_field ). In this schema, the
end caps could be a magnetic mirror
(http://en.wikipedia.org/wiki/Magnetic_mirror ). In this configuration the
Ni and Li plasma can't get out of the confinement and the 3 phases give also
a rotation to this field. But I'm not an expert in magnetic confinement and
how to achieve it.

 

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 19:00
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

Seems to me that at the temperatures we are talking about (1000C) that bulk
magnetic effects are probably out of the question.  A plasma of Li would be
a conductor and a conductor could be conveyed in a moving magnetic field.  I
don't think any motion will occur because of any bulk magnetic affects -
these are all gone at this temperature.

 

This temperature also makes it difficult to consider magnetically confined
condensates as Yeong Kim has described.

 

On Thu, Oct 16, 2014 at 10:50 AM, Bob Cook frobertc...@hotmail.com wrote:

Bob. Amaud, etal--

 

I had the same thought as Amaud.  The wiring arrangement may be deigned to
create a magnetic field inside the reactor to align magnetic moments of the
various entities and facilitate resonant interactions at varying
probabilities to control the rate of reaction.  

 

Bob Cook

- Original Message - 

From: Arnaud Kodeck mailto:arnaud.kod...@lakoco.be  

To: vortex-l@eskimo.com 

Sent: Thursday, October 16, 2014 8:10 AM

Subject: RE: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

Bob, 

 

Just a thought. I'm not an expert of magnetic confinement of plasma. But,
the  encaps  might contain a proper wires configuration to close the
rotating magnetic field formed by the 3 phases current.

 

Arnaud


  _  


From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 17:05
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

I am pretty sure these endcaps are just mechanical supports for the hot
tube in the middle.  They are large alumina outer rings that have been
filled with a cast-able refractory insulation such as a Vitcast 1200 INS or
Vitcast 1400 INS-H.  They insulate the mounting apparatus from the hot
radiating tube.  They serve no other function.  The wires don't go through
these and they do not seal the ends.  They are just supports.

 

On Wed, Oct 15, 2014 at 11:32 PM, Eric Walker eric.wal...@gmail.com wrote:

On Wed, Oct 15, 2014 at 9:24 AM, Bob Higgins rj.bob.higg...@gmail.com
wrote:

 

I believe the large tubes on the end to be thermally insulating supports for
the hot central 2 cm tube.

 

A question that came to me was whether the alumina endcaps could be replaced
with metal endcaps of a suitable alloy in the context of a larger array of
devices, in order to provide a suitable path out for the heat to be used to
generate steam.  Another question I have is how much thermal load one of
these devices can handle.

 

Eric

 

 

 

RE: [Vo]:temperature of the resistor wire.

[Arnaud Kodeck]

Bob,

 

I like your idea on the mixing plasma with the rotating field of a 3phases
AC power supply. The heat is more homogeneous spread inside the reactor and
create a flux. Moreover it may have an action on the reaction occurring in
the eCat.

 

Arnaud

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 18:41
To: vortex-l@eskimo.com
Subject: Re: [Vo]:temperature of the resistor wire.

 

Dave, that was my first thought too, but in going over the construction of
the heater coils, it turned out to be a pain to deal with the heater wire
cross-overs.  You would not do this just because you were planning to
connect the array to a 3-phase supply.  You could simply have an array of
3N, have single phase coils, and balance each phase with the single phase
coils in the array device.  To go to the trouble of making each unit 3-phase
demands a better reason.  I posted earlier that I believe that the 3-phase
is specifically used to create a linear moving field (like a linear motor)
to circulate the lithium plasma that likely forms at high temperature.  This
would make the device much more uniformly heated in the face of chaotic LENR
occurring inside the reactor and would help avoid hot spots.

 

Bob

 

On Thu, Oct 16, 2014 at 10:13 AM, David Roberson dlrober...@aol.com wrote:

The three phase connection is not too surprising if we assume that many more
of these units are to be mounted in a complete system.  It would be extra
work for Rossi to construct a new device using only one phase for the
scientists to measure.  I give him a pass on this point.

RE: [Vo]:Engineering and materials issues with high temperature hot-cat Lugano demo

[Arnaud Kodeck]

The next question is a 3phases AC supply needed to reproduce the eCat
effect? The cold eCat don't use a 3phases power supply but Rossi could have
used magnet inside the cold eCat (Samarium cobalt magnet).

 

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 22:31
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

I think we are describing pretty much the same thing.  Only I don't believe
there is anything but refractory castable insulation in the large diameter
support cylinders at the end of the convection tube.  I think the heater
coils are axial and the 3-phase drive produces a linear conveyer, which when
it gets to the physical end of the tube will fold in on itself coaxially.
Moving field is the reason for the 3-phase drive.

 

On Thu, Oct 16, 2014 at 2:19 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

So why then does Rossi use a 3phases electrical power source? For such kind
of power this not needed. 1000W uses less than 5A.

 

So my guess is that Rossi uses the Rotating magnetic field in its Ecat
(http://en.wikipedia.org/wiki/Rotating_magnetic_field ). In this schema, the
end caps could be a magnetic mirror
(http://en.wikipedia.org/wiki/Magnetic_mirror ). In this configuration the
Ni and Li plasma can't get out of the confinement and the 3 phases give also
a rotation to this field. But I'm not an expert in magnetic confinement and
how to achieve it.

 

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 19:00
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

Seems to me that at the temperatures we are talking about (1000C) that bulk
magnetic effects are probably out of the question.  A plasma of Li would be
a conductor and a conductor could be conveyed in a moving magnetic field.  I
don't think any motion will occur because of any bulk magnetic affects -
these are all gone at this temperature.

 

This temperature also makes it difficult to consider magnetically confined
condensates as Yeong Kim has described.

 

On Thu, Oct 16, 2014 at 10:50 AM, Bob Cook frobertc...@hotmail.com wrote:

Bob. Amaud, etal--

 

I had the same thought as Amaud.  The wiring arrangement may be deigned to
create a magnetic field inside the reactor to align magnetic moments of the
various entities and facilitate resonant interactions at varying
probabilities to control the rate of reaction.  

 

 

RE: [Vo]:Engineering and materials issues with high temperature hot-cat Lugano demo

[Arnaud Kodeck]

What happens inside the eCat isn’t known. A magnetic field can be required
(And most probably it is the case). For the cold eCat, Rossi may have used a
magnet for the sake of simplicity. The wiggly filament let me think of a 2
magnetic fields that can occur inside the eCat: One global field made from
AC current (cm range) and one local field made with the Rossi Italian secret
sauce (µm range). Could the the wiggly secret powder sauce hit the liquefied
nickel and force it for the stripping neutron with nickel? The local force
might be huge enough.

 

I remember Rossi (2~3 years back) telling that it was an oscillating
phenomenon inside the eCat.

 

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 22:51
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

I don't think there was anything this fancy in Rossi's original eCats.  He
had an internal cartridge heater which would have had little magnetic field
escaping and it was single phase.  He also had an auxiliary heater wrapped
around the outside that would have had more magnetic field and it was also
single phase.  Who knows about a magnet?  Are you thinking of the single
phase light bulbs having the magnet causing the filament to wiggle back and
forth for flicker effect?

 

On Thu, Oct 16, 2014 at 2:44 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

The next question is a 3phases AC supply needed to reproduce the eCat
effect? The cold eCat don’t use a 3phases power supply but Rossi could have
used magnet inside the cold eCat (Samarium cobalt magnet).

 

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 22:31
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

I think we are describing pretty much the same thing.  Only I don't believe
there is anything but refractory castable insulation in the large diameter
support cylinders at the end of the convection tube.  I think the heater
coils are axial and the 3-phase drive produces a linear conveyer, which when
it gets to the physical end of the tube will fold in on itself coaxially.
Moving field is the reason for the 3-phase drive.

 

On Thu, Oct 16, 2014 at 2:19 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

So why then does Rossi use a 3phases electrical power source? For such kind
of power this not needed. 1000W uses less than 5A.

 

So my guess is that Rossi uses the Rotating magnetic field in its Ecat
(http://en.wikipedia.org/wiki/Rotating_magnetic_field ). In this schema, the
end caps could be a magnetic mirror
(http://en.wikipedia.org/wiki/Magnetic_mirror ). In this configuration the
Ni and Li plasma can’t get out of the confinement and the 3 phases give also
a rotation to this field. But I’m not an expert in magnetic confinement and
how to achieve it.

 

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 16 octobre 2014 19:00
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Engineering and materials issues with high temperature
hot-cat Lugano demo

 

Seems to me that at the temperatures we are talking about (1000C) that bulk
magnetic effects are probably out of the question.  A plasma of Li would be
a conductor and a conductor could be conveyed in a moving magnetic field.  I
don't think any motion will occur because of any bulk magnetic affects -
these are all gone at this temperature.

 

This temperature also makes it difficult to consider magnetically confined
condensates as Yeong Kim has described.

 

On Thu, Oct 16, 2014 at 10:50 AM, Bob Cook frobertc...@hotmail.com wrote:

Bob. Amaud, etal--

 

I had the same thought as Amaud.  The wiring arrangement may be deigned to
create a magnetic field inside the reactor to align magnetic moments of the
various entities and facilitate resonant interactions at varying
probabilities to control the rate of reaction.  

 

 

 

RE: [Vo]:Mizuno, Rossi copper transmutation

[Arnaud Kodeck]

Jones,

Why not consider also the Ni58 + 2p - Zn60 - Cu60 - Ni60? Zn60 has a spin
0.

_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: lundi 22 septembre 2014 17:34
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Mizuno, Rossi  copper transmutation

Typo- the suggested reaction is Ni58 + D - Cu60 - Ni60

_

I've looked through the isotope charts again -
searching for reactions that rapidly decay back to the starting element or
to any stable isotope which has already been reported to be there, and have
not found any other possibility...

...other than Ni58 (d,Cu59) - Ni60  which
happens by EC or positron emission, with a half-life of 20 minutes or so,
and which fits the facts as reported in the most robust experiments (Rossi,
DGT, Thermacore, Mills).

1)  No or few gamma
2)  No or little radioactive ash
3)  No tritium, helium or positron annihilation
4)  No or little bremsstrahlung 
5)  Excess energy which is at least 1000 times more than chemical

Since nickel absorbs a deuteron and decays back to
nickel in minutes, with low energy release, this reaction fits the bill. You
may be thinking - what about the positron (beta positive) decay? No problem
there, since nuclei which decay by positron emission also decay by electron
capture in a known branching ratio which is dependant on the net energy of
reaction.

According to wiki-the-wonderful, in low-energy
decays, electron capture is energetically favored by reactions below 1.022
MeV. The final state will have an electron added or a positron removed - and
so the energy released is determinative of what can happen in the branching.
As the energy of the decay goes up, so does the branching ratio towards
positron emission. However, if the energy difference is low, then positron
emission cannot occur, and electron capture is the sole decay mode. This
would seem to be ready-made for the DDDL or deuteron-deep-Dirac-level
species, which uses its tight electron for more than one purpose and
probably reduces the net energy of the reaction as well.

This still leaves spin conservation as the major
problem. The end products of this reaction would be Ni60, and the starting
nickel would be Ni58, so that is no problem. Both are spin 0.

But the intermediary isotope, with short half-life
would be Cu60 which is spin 2+ and the deuterium can only add is 1+ spin,
and the EC electron another ½ spin. This over-simplification of spin issues
- probably means that the reaction can only happen if a neutrino is
captured, or else the inherent spin deficit decreases the half-life even
more than its short nature. Probably the neutrino.

Best of all - as a general working hypothesis which
would make this relevant to LENR but is not expected to be seen anywhere
else (which explains why it is not documented in the physics literature, as
of now) there is NO other isotope in the periodic table (other than Ni58) -
which is both a proton conductor and demonstrably neutron-deficient ! (the
proof of that being that Ni-58 is lower amu than the preceding lower Z
element (cobalt-59). That's right it is a perfect storm scenario. If this
evolving explanation is correct, it will be seen nowhere else in the
periodic table, since it demands conditions which do not exist anywhere
else.

This means, anthropomorphically speaking - that
Ni58 desperately wants two more neutrons, and to get them, it essentially
steals from its surroundings, whenever a deuteron comes too close...
especially a DDDL.

Falsifiability? Yes, this is falsifiable in three
different way, which is a big advantage. Give me a working Rossi reactor :-)
and a few months: if the [Ni-Ni] explanation is true, if will be proved
beyond all reasonable doubt. 

P.S. do I get to keep the reactor?

_

One more thing to add ... wrt the overdue
suggestion (Doh, slaps forehead) that Rossi's secret sauce is looking like
it is deuterium. Thank you, Clean Planet.

The reaction would probably work best if it
is started with regular hydrogen, and then deuterium is added later. This is
because the exchange reaction between hydrogen and deuterium itself is so
robust. In fact, many of the early critics of LENR thought that the entire
phenomenon could be related to deuterium exchange. It is that energetic.

As we know, Rossi has this mysterious system
- which he calls cat-and-mouse. He has been intentionally vague on 

RE: [Vo]:Mizuno, Rossi copper transmutation

[Arnaud Kodeck]

Yes, in my view, the DDL state diatomic hydrogen (shrunken hydrogen) reacts
with Ni58. Should both atoms be in shrunken state? Is the DDL atoms small
enough to go in the lattice?

We can consider as well with pD or DD DDL state if natural hydrogen is used.

_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: lundi 22 septembre 2014 18:28
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Mizuno, Rossi  copper transmutation


From: Arnaud Kodeck 

Jones,

Why not consider also the Ni58 + 2p - Zn60 - Cu60
- Ni60? Zn60 has a spin 0.


_
the suggested reaction is Ni58 + D - Cu60
- Ni60

Arnaud, This would be a three body reaction, no? 

You may be suggesting this reaction - in the event that Rossi does
not use deuterium. That is wise to consider - since he professes not to,
despite a tank of it being seen in his lab, early on. 

There is an even better possibility when two protons densified as a
DDL molecule, and would act like the two needed neutrons, to make this
reaction work. 

If my understanding is correct, nickel-58 is active ONLY because it
is neutron-deficient, and the two protons do not help the immediate
situation, at least not on the surface - even if both protons decay to
neutrons, eventually. However, all bets are off with the DDL, since it
allows the protons to look like virtual neutrons.

There is nothing out there, which fits all of the parameters
seamlessly, so in the end - we need reliable data. But it looks like we are
framing a workable situation with enough variable to accommodate either D, H
or H+D as the active gases. 

In short, your suggestion may work well - an especially if Rossi
uses hydrogen only, and even more so - if the signature of the DDL formation
(soft x-ray) is documented.

Jones


attachment: winmail.dat

RE: EXTERNAL: Re: [Vo]:Review of Ed Storms book: \The Explanation of Low Energy Nuclear Reaction\

[Arnaud Kodeck]

Hello Bob,

 

I agree with you that Rossi does NOT use nano sized Ni particles. He has
always said that he use micro sized Ni particles. But can you point
explicitly a sentence from Rossi saying he use the carbonyl process or is it
an assumption? I never haerd such claim by Rossi.

 

It is clear that the Ni particles has a treatment to enhance the loading of
H inside the lattice (with Cu or/and La?). There are also nano sized builds
that create the SPP that trigger the reaction. The nano sized builds need to
survive high temperature.

 

Arnaud

  _  

From: Bob Higgins [mailto:rj.bob.higg...@gmail.com] 
Sent: jeudi 24 juillet 2014 00:33
To: vortex-l@eskimo.com
Subject: Re: EXTERNAL: Re: [Vo]:Review of Ed Storms book: \The Explanation
of Low Energy Nuclear Reaction\

 

Bob,

 

This is a common misconception.  Rossi does NOT use nano-Ni.  Rossi uses Ni
particles (from the carbonyl process) that have a high external area and
particle diameter of 4-8 microns.  Rossi adds a catalyst, that is believed
to be a nanopowder, to the carbonyl Ni particles and then grows features
on the Ni.

 

Bob Higgins

 

On Wed, Jul 23, 2014 at 2:54 PM, Bob Cook frobertc...@hotmail.com wrote:

Rossi claims that he uses nano-nickel particles.  I have no idea what the
sintering and melting temperatures of those structures.  We know that carbon
nano structures have very good high temperature properties.  A Ni-H nano
structure may even be better at high temperatures.  

 

I would not give up on Ni even in the hot cat performance.  Something Rossi
introduced say white hot conditions.  Of course it may be a fake.  I think
he has been honest with what he has said.  He may withhold information also,
however.  

 

I learned much in reactor design due to early failures.  The new designs
after failure generally allowed for higher temperature operations and
greater power output.   I would bet Rossi is not beyond learning from his
failures.

 

Bob

 

 

 

Sent from Windows Mail

 

From: Roarty, Francis X mailto:francis.x.roa...@lmco.com 
Sent: ‎Wednesday‎, ‎July‎ ‎23‎, ‎2014 ‎7‎:‎51‎ ‎AM
To: vortex-l@eskimo.com

 

Axil, nice insight which also gives support to dynamic formation of plasma
in the Papp engine. I was also one of those who felt self destruction would
bring the reaction to a halt but the Rossi melt down does  point to the
continued run away reaction even after the geometry has melted. Like they
say it gets worse before it gets better :_)

Fran

 

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: Wednesday, July 23, 2014 11:44 AM
To: vortex-l
Subject: EXTERNAL: Re: [Vo]:Review of Ed Storms book: \The Explanation of
Low Energy Nuclear Reaction\

 

One of the possibilities is that there are many types of nano-antennas
formed in the NiH system. When starting up the major carrier of the reaction
are the nanowires. But as the reactor heats up and its energy output is
increased, then the reaction sites may form in the spaces between
nano-particles.

 

The lesson thought to use by the meltdown of Rossi's reactor when the
temperature of the reactor passes 2000C is that the permanent reaction sites
will melt and be destroyed by the high heat.

 

However, the reaction still continues at an accelerated pace. In 10 seconds,
when control of the reactor is lost, the reactor goes from 1000C to 2000C
and produces a power output of a megawatt.

 

During this meltdown process the reaction carrier must have shifted from
primarily the nanowire to completely nanoparticles. When the hydrogen
containment fails, the reaction carrier must be completely nanoparticles. 

 

The take away, there are many ways in which the LENR reaction can be
carried. At any given time, the situation will govern which mechanism will
denominate.

 

By the way, Ed Storms theory cannot support this dynamic variation is
reaction mechanisms. Ed never wanted to add NiH reactor meltdown to his
collection of experimental results.

 

 

 

On Wed, Jul 23, 2014 at 5:10 AM, Peter Gluck peter.gl...@gmail.com wrote:

The simplest answer to these question is YES.

A bit longer one;

- as you know, DGT works by making hydrogen more reactive

and Ni more receptive, if you read their ICCF-17 paper you will see they

are increasing the mobility of the surfaces of Ni crystals- we still have to
see

what exactly can play the role of a nano-antenna, is there unity in
diversity

or even greater diversity in diversity- details have to be discovered, what
i am convinced is- it is not about simple cracks, however the very surace of
cracks can be ACTIVE

 

- yes, I think at LENR+ active sites are created very dynamically, we ahve
to learn the Know Why and how to accelearte in a controlled way the process

(let me repeat I am using NAE in other sense- the NAEnvironment is the 

complete cell- F P, or Piantelli etc , the entire E-cat or Hyperion)

 

- i still don't know the details regarding the death, birth and activity

of the active sites- it is a captivating story

 

RE: [Vo]:Rossi's isotopic ratios in his ash assay

[Arnaud Kodeck]

Maybe the copper found in the ash is one of the secret ingredients of the
Rossi reactor. Rossi just put natural copper in the reactor.

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: vendredi 18 juillet 2014 22:14
To: vortex-l
Subject: [Vo]:Rossi's isotopic ratios in his ash assay

 

Why does Rossi's isotopic ratios in his ash assay show the same natural
abundance as seen throughout the universe?

 

Because cosmological LENR has  already produced these isotopes and seeded
them throughout the universe as an ongoing dynamic process.

 

The take away, all LENR reactions produce the same isotopic ratios based on
the intrinsic nature of quark element condensation. .

RE: [Vo]:Mizuno slides coming

[Arnaud Kodeck]

Jones,

Before going more into the conclusions, there are some key information
missing in the slides. When the samples are taken out of the reactor, the
pressure inside the reactor is a key indicator of each quantity (Absolute
value instead of relative). If in absolute value, the quantity ’M/e=4’
decreases and ‘M/e=3 or 2’ increases then we can think about your theory.

It is a shame we don’t have the ‘M/e=1’ in this experiment results. We
are blind on this part.

‘M/e=2’ could be D+ or H2+:
If it’s D+, then it proves that the reactor splits D2 into 2 D and a key
for excess heat to happen. Rossi, DGT, and others all have claim that split
of diatomic hydrogen to atomic is a first step for the LENR to occur.
If it’s H2+, then we need a new theory. The check for ‘M/e=1’ aka H+
would have been a master clue into research for another theory like the one
you presented “Oppenheimer-Philips” which I don’t know anything about.

Arnaud

_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: vendredi 28 mars 2014 05:15
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Mizuno slides coming

Guys,

You may have missed one huge detail. Did not the gas quantity in the
reactor actually increase significantly after 30 days compared to initial
conditions ? 

Maybe I am the one to have misinterpreted that detail, which would
be extremely important and would seem to negate the possibility of from D+Ni
reactions. See Slide 46. It indicates to me that there was approximately
twice the number of gas molecules at the end of the run compared to the
start and to the null run.

If D2 gas reacts with nickel, not only do you get radioactive ash,
which is not mentioned but surely would have been mentioned if it was there,
but also a drop in pressure and in the quantity of gas - as hot protons are
captured in the metal and neutrons are absorbed.

Instead, the number of gas molecules approximately doubles during
the run. That is the main reason to look for a reaction where atoms of D2
shift isotopcially to nearly twice the number of atoms of H2 while producing
only moderate levels of gamma radiation. 

That kind of radiation would stand out like a sore
thumb.

With 150 watts of power from average 7 MeV protons
for 30 days, the Mizuno lab would be a small Fukushima…


From: torulf.gr...@bredband.net 
I see you was quicker with neutron capture.
But the should look for He4 in the Ni metal.
Eric Walker wrote:
H Veeder wrote:

Going from D to H should be endothermic.
Exciting slides.  I do not have the
wherewithal to assess their calorimetry, so I will assume it is accurate.
Here are some exothermic reactions involving
generation of H from D:
*   d + 60Ni → 61Ni + p + Q (6.1 MeV)
*   d + 61Ni → 62Ni + p + Q (8.9 MeV)
*   d + 62Ni → 63Ni + p + Q (5.1 MeV)
*   d + 64Ni → 65Ni + p + Q (7.9 MeV)
Note that in the authors'
back-of-the-envelope calculations using two d+d branches, yielding 4.03 MeV
and 3.27 MeV respectively, they came to an expected energy output that was
lower than the one they think they observed.  So the higher Qs of the above
reactions fit that picture nicely.  Their slides on the neutron capture
cross sections of nickel suggest that they are also looking at thinking
about the d+Ni reactions.  Regarding the radiation measurements they have
not yet reported on -- I will call out a guess that they will report
evidence of beta+ and beta- decay.
The treated nickel is interesting looking.
I assume this is what the nickel looks like prior to a reaction.  Note that
there is greater occasion for electrically insulated grains after the
treatment than before the treatment.
Note that the NiD system is quite different
than the oft-studied PdD system.  I vaguely recall sometime back that proton
and deuteron capture are not favorable in palladium, whereas proton capture
is favorable in nickel.  What is interesting in the above scenario is that
we are looking at the possibility not of proton capture but of neutron
capture.
Eric
attachment: winmail.dat

RE: [Vo]:Is there an echo in here?

[Arnaud Kodeck]

This has been refuted by the real Satoshi Nakamoto himself. We didn't hear
anything from him since ages and comes back to say that the Newsweek article
isn't the truth. The message from the real Satoshi Nakamoto has been
authenticated to be his real signature by the Bitcoin foundation.

-Original Message-
From: Terry Blanton [mailto:hohlr...@gmail.com] 
Sent: vendredi 7 mars 2014 01:16
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Is there an echo in here?

On Wed, Feb 26, 2014 at 9:20 AM, Jones Beene jone...@pacbell.net wrote:

 Bitcoin's pseudonymous creator Satoshi Nakamoto willed that currency
into
 existence in 2009,

Not a pseudonym:

http://mag.newsweek.com/2014/03/14/bitcoin-satoshi-nakamoto.html

RE: [Vo]:Re: The Rossi effect as an Inverted Mossbauer Effect

[Arnaud Kodeck]

From DGT, we know that the nickel needs to be above the debye temperature
for the Rossi effect to take place. Vibration in the lattice is a key
element. The Mossbauer effect could be the excitation needed for the
vibration in the lattice to take place.

Jones, can you explain what do you mean by Mossbauer isotope?
_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: lundi 17 février 2014 16:45
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Re: The Rossi effect as an Inverted Mossbauer
Effect

-Original Message-
From: Bob Cook 

 Jones-- You sound like you must be Dan Brown in real life.

Well, Bob - if I was getting royalties from Di Vinci code, they
would go to solving the Rossi code...

BTW - Blaze wants to know: what is real life? :-)

Jones


Worth repeating for those who do not appreciate the significance (of
what could be the unholy grail of new energy).

The 7 physical anomalies of nickel which could be related to LENR.
 
1) It is ferromagnetic - one of three elements

2) Has a Mossbauer isotope

3) Has the heaviest ratio stable isotope in the P.T. for nuclei
containing neutrons (as a % of the amu of the most common isotope of that
element - Ni-58 vs Ni-64) - a singularity

4) The main isotope is lower amu than a lower z element (Ni-58 is
lower amu than Cobalt) which is extremely rare in the P.T.

5) Has the highest innate stability isotope (Ni-62 has highest
binding energy per nucleon in the PT 8.8 MeV) - a singularity

6) Has an unstable isotope with gammaless EC decay- very rare
 
7) Has adjoining Rydberg levels in electron orbital ionization
potentials - one of three elements ... and curiously the other two are also
ferromagnetic.

Could this combination be coincidental to the Rossi effect? 

Is there a common denominator in the this range of properties...
such as spin?

BTW - an associate has told me that nickel is one of two elements in
the PT with two isotopes which are double magic Ni-56 and Ni-48, but
because neither of these are stable, it was deemed to be not important to
LENR - only further proof of nickel's oddities.


attachment: winmail.dat

RE: [Vo]:Re: The Rossi effect as an Inverted Mossbauer Effect

[Arnaud Kodeck]

Ni61 is the only odd isotope of Ni and count only for 1% of the natural 
Nickel. It will be huge cost to enrich the Ni61.


Ni61 + p = Cu62 which is beta+ emitter which would be easy detected in 
positron/electron annihilation. I don't think this is the reaction which 
happends inside Rossi's reactor.


The debye temperature is around 180°C for the nickel. Above this 
temperature, phonon can move freely in the lattice at the speed of 
sound. Axil always keeps speaking of coupling phonon/photon (polariton) 
at same resonant frequency could make the lattice to oscillate. If 
excitation frequency (photon) matches the resonant frequency of the 
lattice (phonon), wouldn't be like an invertedmossbauer effect?


Just thoughts ...



On 2014-02-18 15:53, Jones Beene wrote:

From: Arnaud Kodeck

From DGT, we know that the nickel needs to be above the debye
temperature for the Rossi effect to take place. Vibration in the 
lattice is
a key element. The Mossbauer effect could be the excitation needed for 
the

vibration in the lattice to take place.

Jones, can you explain what do you mean by Mossbauer isotope?

Arnaud,

First, off - I am not an expert in NMR and that is why I have been 
quizzing
Bob Cook about a subject that came up as far back as 1990 - in an 
effort to
explain the excess energy of LENR - and the lack of detectability of 
gamma

radiation.

Generally speaking, an isotope - usually with odd numbered amu such as
iron-57 or nickel-61, can permit a limited kind of photon chain 
reaction

of moderate energy photons due to a loss-free (recoilless)
absorption/emission nuclear property, and this would be especially true
within an exciton of the host metal.

I'm guessing that since the role of 57Fe is well-known in spectroscopy, 
you
are really asking how a corresponding nickel isotope nickel 
participates in
a similar reaction, where we are interested in bulk energy effects and 
not

subtle physical effects which are illuminated by the coherence.

That bulk effect, if it exists - would be the inverted reaction. Of
course, the reaction must involve photons below the detection limit - 
since

no gamma is detected. It would also probably need to involve infrared
coherence, and the idea is that in an inverted reaction there can be
frequency upshifting so two widely separated spectra are locked in 
phase.


In nickel at 350 degrees C, the nuclei will be moving chaotically due 
to

thermal motion, but not as chaotically if there is IR coherence
(superradiance) at near 10 THz. This part has actually been detected by 
NASA

but not the rest of the hypothesis. A moderate energy photon, of the
Mossbauer type - but below the detection limit of about 4 keV interacts
with, or is emitted by a nucleus which has a spread of vibrational 
values,
and there is a the Doppler effect. This photon can be called a gamma 
ray,
since it is of nuclear origin, but because the energy level must be low 
to

avoid detection - the terminology is x-ray. This is all hypothetical of
course.

Problem is: and may you realize this - the known value for nickel-61 of 
a

resonant photon is 67.4 keV which would have been detected in the Rossi
experiment. Therefore either there is either a second active Mossbauer
isotope, or a lower level resonance, below the detectability level. Of 
more

likely - the inverted Mossbauer effect is a fiction.

Anyway, to produce a resonant third signal, the two energies - the main
x-ray photon and Doppler shifted photon need to overlap at the IR 
resonance
(this signal will be in the range of FIR - far infrared at about 5-30 
THz).
Thus a putative inverted system would be in limited photon/phonon 
coherence
and possess a limited photon/phonon chain reaction capability at some 
level

which is not detectable by normal Geiger/radiation meters.

To backtrack, what Mössbauer discovered is that when the atoms are 
within a
solid matrix the effective mass of the nucleus is very much greater. 
The
recoiling mass is now effectively the mass of the whole system and if 
the
photon energy is small enough the recoil of the nucleus is too low to 
be

transmitted as a phonon and so the whole system recoils as if it were
coherent and it can be actually coherent in the IR range if the 
blackbody

peak is narrowed.

In the inverted version, presumably the resonance will allow FIR energy 
to
resonate as if the whole system were coherent and this will be 
upshifted to
a level felt by the nucleus (low keV). However, to my thinking this 
does not

work at 67.4 keV so the whole theory falls apart.

As you will notice, this suggestion has not been well-vetted - even 
after 24

years, so take it for what it's worth.

Jones


--
Arnaud Kodeck
LAKOCO Sprl

RE: [Vo]:Re: The Rossi effect as an Inverted Mossbauer Effect

[Arnaud Kodeck]

Bob,

As far as I know, there is no external magnetic field applied to the reactor
by means of coils. Anyway, the H field might become from the lattice itself?
Rossi and DGT have said to measure huge magnetic field near the reactor.
Always difficult to know what is the cause and what is the result of an
unknown black box.

Arnaud
-Original Message-
From: Bob Cook [mailto:frobertc...@hotmail.com] 
Sent: mardi 18 février 2014 22:04
To: vortex-l@eskimo.com
Subject: [Vo]:Re: The Rossi effect as an Inverted Mossbauer Effect
Importance: High

Amaud and Jones--

Keep in mind that at least for magnetic coupling--spin/angular momentum and 
its associated energy-- it is possible to modify resonant energy levels of 
the QM system by changing the magnitude of the static H field.  Transitions 
between J spin states can be created to match the necessary energy to make a

nuclear transition probable.

Bob Cook

-Original Message- 
From: Arnaud Kodeck
Sent: Tuesday, February 18, 2014 7:56 AM
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Re: The Rossi effect as an Inverted Mossbauer Effect

Ni61 is the only odd isotope of Ni and count only for 1% of the natural
Nickel. It will be huge cost to enrich the Ni61.

Ni61 + p = Cu62 which is beta+ emitter which would be easy detected in
positron/electron annihilation. I don't think this is the reaction which
happends inside Rossi's reactor.

The debye temperature is around 180°C for the nickel. Above this
temperature, phonon can move freely in the lattice at the speed of
sound. Axil always keeps speaking of coupling phonon/photon (polariton)
at same resonant frequency could make the lattice to oscillate. If
excitation frequency (photon) matches the resonant frequency of the
lattice (phonon), wouldn't be like an invertedmossbauer effect?

Just thoughts ...



On 2014-02-18 15:53, Jones Beene wrote:
 From: Arnaud Kodeck

 From DGT, we know that the nickel needs to be above the debye
 temperature for the Rossi effect to take place. Vibration in the lattice 
 is
 a key element. The Mossbauer effect could be the excitation needed for the
 vibration in the lattice to take place.

 Jones, can you explain what do you mean by Mossbauer isotope?

 Arnaud,

 First, off - I am not an expert in NMR and that is why I have been 
 quizzing
 Bob Cook about a subject that came up as far back as 1990 - in an effort 
 to
 explain the excess energy of LENR - and the lack of detectability of gamma
 radiation.

 Generally speaking, an isotope - usually with odd numbered amu such as
 iron-57 or nickel-61, can permit a limited kind of photon chain reaction
 of moderate energy photons due to a loss-free (recoilless)
 absorption/emission nuclear property, and this would be especially true
 within an exciton of the host metal.

 I'm guessing that since the role of 57Fe is well-known in spectroscopy, 
 you
 are really asking how a corresponding nickel isotope nickel participates 
 in
 a similar reaction, where we are interested in bulk energy effects and not
 subtle physical effects which are illuminated by the coherence.

 That bulk effect, if it exists - would be the inverted reaction. Of
 course, the reaction must involve photons below the detection limit - 
 since
 no gamma is detected. It would also probably need to involve infrared
 coherence, and the idea is that in an inverted reaction there can be
 frequency upshifting so two widely separated spectra are locked in phase.

 In nickel at 350 degrees C, the nuclei will be moving chaotically due to
 thermal motion, but not as chaotically if there is IR coherence
 (superradiance) at near 10 THz. This part has actually been detected by 
 NASA
 but not the rest of the hypothesis. A moderate energy photon, of the
 Mossbauer type - but below the detection limit of about 4 keV interacts
 with, or is emitted by a nucleus which has a spread of vibrational values,
 and there is a the Doppler effect. This photon can be called a gamma ray,
 since it is of nuclear origin, but because the energy level must be low to
 avoid detection - the terminology is x-ray. This is all hypothetical of
 course.

 Problem is: and may you realize this - the known value for nickel-61 of a
 resonant photon is 67.4 keV which would have been detected in the Rossi
 experiment. Therefore either there is either a second active Mossbauer
 isotope, or a lower level resonance, below the detectability level. Of 
 more
 likely - the inverted Mossbauer effect is a fiction.

 Anyway, to produce a resonant third signal, the two energies - the main
 x-ray photon and Doppler shifted photon need to overlap at the IR 
 resonance
 (this signal will be in the range of FIR - far infrared at about 5-30 
 THz).
 Thus a putative inverted system would be in limited photon/phonon 
 coherence
 and possess a limited photon/phonon chain reaction capability at some 
 level
 which is not detectable by normal Geiger/radiation meters.

 To backtrack, what Mössbauer discovered is that when the atoms

RE: [Vo]:Another new Kalman-Keszthelyi paper

[Arnaud Kodeck]

It's a very interesting paper.
Shame it didn't take also the reaction e + d + d - e' + He4 (+ Q). Is there a 
reason why it is not possible to do it? It would be nice also to do it with 
reaction e + p + p - e' +... and e + p + d - e' +...

Arnaud
-Original Message-
From: pagnu...@htdconnect.com [mailto:pagnu...@htdconnect.com] 
Sent: lundi 23 décembre 2013 03:13
To: vortex-l@eskimo.com
Subject: [Vo]:Another new Kalman-Keszthelyi paper

Electron assisted dd reactions in metals

- Peter Kalman, Tamas Keszthelyi  (Submitted on 20 Dec 2013)

ABSTRACT:
The electron assisted low energy dd reactions in deuterized metals are
investigated. It is shown that if a metal is irradiated with slow, free
deuterons then the e+d+d¨eŒ+p+t and e+d+d ¨ eŒ+n+3He electron assisted
dd processes have measurable probabilities even in the case of slow
deuterons. The cross sections and the yields in an irradiated sample are
determined. The results are connected with the so called anomalous
screening effect. It is concluded that the electron dd processes have to
be taken into account when evaluating the experimental data of low energy
fusion reactions in metals.

http://arxiv.org/abs/1312.5835

RE: [Vo]:Cravens report on NI Week demo

[Arnaud Kodeck]

Aren’t the temperatures below in K instead °C? I’m pretty sure the water
bath wasn’t at 397°C … neither 292°C

 

  _  

From: DJ Cravens [mailto:djcrav...@hotmail.com] 
Sent: vendredi 20 septembre 2013 23:14
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Cravens report on NI Week demo

 

E vs. temp was not done at the demo.
However below are some typical (average) values from some old lab runs.
I did not calibrate at the demo.  I only showed that the sample was warmer
than the control. That was the only point that was attempted there so there
was no claim of amount of energy but it was around 4 watts.   I did not want
to confuse things and there was no time to calibrate.  Just one sphere was
hotter than its environment- that was it.
 
The important point is that excess increases with temperature. 
You may want wait till the next issue of IE comes out to see some empirical
models (Letts, in #112) for better data.  Letts has fitted hundreds of data
sets.  
 


temp C

 excess W


292

0.2


312

0.6


332

1.2


352

3.9


372

6.2


397

7.1


 

  _  

To: vortex-l@eskimo.com
Subject: Re: [Vo]:Cravens report on NI Week demo
From: dlrober...@aol.com
Date: Fri, 20 Sep 2013 16:00:27 -0400

It is not clear how any form of energy gain is associated with this
experiment.  The demonstration appears to generate LENR energy, but the
input function is not present.  It would be educational to have a plot of
energy generation versus temperature.

 

Dave

-Original Message-
From: Jones Beene jone...@pacbell.net
To: vortex-l vortex-l@eskimo.com
Sent: Fri, Sep 20, 2013 3:53 pm
Subject: RE: [Vo]:Cravens report on NI Week demo

 
-Original Message-
From: Terry Blanton 
 
Jed Rothwell wrote:
 http://www.infinite-energy.com/images/pdfs/NIWeekCravens.pdf
 
 Such a simple, magnificent demonstration.  Can you make me a charger
for my Tesla car?  Charming.
 
Indeed it is - and understated since the hot sphere transfers heat to the
bed and to the control - so the actual gain is more than it appears.
 
... hey, Terry - are you the proud owner of a Tesla (or just wishing you
were)?
 
 

RE: [Vo]:Does this go to p. 31?

[Arnaud Kodeck]

Hello Jed,

 

I’m using the apps Docs PDF/PowerPoint Viewer (by Google) 3.10 inside google
chrome.

 

It works nicely. I go directly to the right page!

 

Arnaud

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: jeudi 22 août 2013 16:07
To: vortex-l@eskimo.com
Subject: [Vo]:Does this go to p. 31?

 

Here is a document from Adobe that is actually readable:

 

http://www.adobe.com/content/dam/Adobe/en/devnet/acrobat/pdfs/pdf_open_param
eters.pdf

 

It explains that you can jump to a page when you open an Acrobat document by
appending #page=nn 

 

I just tested this. With the Acrobat reader built into the Chrome browser,
this works. Sort of. It seems be going to the page number plus 1.

 

Try this link:

 

http://lenr-canr.org/acrobat/BiberianJPjcondensedf.pdf#page=30

 

This goes to page 31 which is the start of the Bockris paper. This link goes
to page 3 as far as I can tell:

 

http://lenr-canr.org/acrobat/BiberianJPjcondensedf.pdf#page=2

 

I guess the first page is number zero. A typical programmer mentality.

 

Please let me know if this does not work for you. Let me know what browser
you are using.

 

Anyway I will now begin inserting all of the individual papers within books
and within John Paul's Journal, with links directly to the pages. I think I
will change the button to say INCLUDED instead of DOWNLOAD. If it does
not jump to the right page the reader will have a clue that the paper is
included in the document.

 

- Jed

 

RE: [Vo]:Re: CMNS: about the Nuclear Active Environment

[Arnaud Kodeck]

How a heat shock can produce plasma?

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mardi 20 août 2013 20:49
To: vortex-l
Subject: Re: [Vo]:Re: CMNS: about the Nuclear Active Environment

 

Rossi uses heat shock to produce plasma.

 

On Tue, Aug 20, 2013 at 12:18 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Axil,
There is no plasma pulse in the rossi reactor !
Quoting Axil Axil janap...@gmail.com:

Testing.

What both builders of the Ni/H reactor have done is to find the proper
pulse rate for the plasma creation reaction through trial and error testing.


On Tue, Aug 20, 2013 at 11:29 AM, David Roberson dlrober...@aol.com wrote:

Axil,

 You discuss the destruction and reformation of NAE over a finite period
of time.  Do you think that there is some negative feedback mechanism in
effect which forces the new formations to match the old ones that have been
destroyed?  It seems logical that a process that does not have a direct
connection between production and destruction of NAE would proceed to
either thermal run away or ultimate cool down.

 I suppose that a process might originate where elevated temperature
results in that destruction being enhanced, particularly in the hot spots.
 The question is: What keeps the process in balance according to your
hypothesis?

 Dave


-Original Message-
From: Axil Axil janap...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Tue, Aug 20, 2013 10:23 am
Subject: Re: [Vo]:Re: CMNS: about the Nuclear Active Environment

  LENR is driven by a specific topology that directs electrons into the
special motions and concentrations which result in the LENR reaction.


  Cracks are a good example of this topology in that through the
discontinuity of the lattice that a crack provides, dipole motion meets a
boundary condition that forces electrons to follow a circular path as a
vortex electron currents forms.

 This dislocation of dipole motion must occur at the surface of a metal
at the boundary between the metal a dielectric isolator.


 The downside of a permanent lattice structure like a crack is that it
will deteriorate over time due to the stresses placed on its topology as
nuclear reactions occur in and around this boundary location.


 The crack will erode over time and the special conditions that cause the
electrons to behave in this special way will no longer be preserved over
extended time.


 But discontinuities in dipole movement will also occur between
nano-particles and micro particles.


 These discontinuities will be continually reformed and dispersed in a
dynamic process as the particles float and bump around in the turbulent
motion of a hot hydrogen atmosphere.


 These nanoparticles will also be destroyed by nuclear activity, but that
can be occasionally rebuilt out of the condensation process after the
plasma stage produced by a hot heater element or a spark discharge.


 In this way, the NAE, is continually rebuilt at a fixed rate that
exactly counters the rate of destruction caused in these particles by
nuclear activity.


 The effective LENR reaction is a fluid process of continual destruction
and renewal that any solid structure cannot duplicate.





On Tue, Aug 20, 2013 at 10:20 AM, Edmund Storms
stor...@ix.netcom.comwrote:

Terry, the problem is psychological, not scientific. Understanding CF
requires a change in perspective, which is hard for many people to do. You
need to look at the system in which the nuclear reaction occurs from the
perspective of the assembly of atoms, i.e. like a chemist does.  The
chemical system os constructed by interaction of the electrons and this
interaction has very clear rules. Any change required to initiate a nuclear
reaction will be communicated to this assembly and cause changes before the
change will be experienced by the nucleus. That process provides the basic
limitation to any mechanism proposed to occur in the lattice itself. In
other words, to cause a nuclear effect, the chemical structure will also be
affected in ways that will stop the nuclear process. This is how a chemical
system is known to behave based on centuries of experience by chemists and
by examining material over geological time. A change in perspective is
REQUIRED before a person can fully appreciate the role of the chemical
system.  That is why a condition must be created outside of the rules that
apply to the chemical system. The region INSIDE a crack provides this
environment. Events occurring in this region would not affect or be
affected by the chemical structure, hence could form a condition able to
initiate a nuclear reaction. This is a very basic insight that cannot be
falsified in the usual way. It requires a change in perspective to be
evaluated.

This situation is similar to how the relationship between the Sun and
Earth was once explained,  A change in perspective was required before the
correct analysis could be done. Before this change in perspective occurred,
very convincing mathematical analysis

Re: [Vo]:Re: CMNS: about the Nuclear Active Environment

[Arnaud Kodeck]

Axil,
There is no plasma pulse in the rossi reactor !
Quoting Axil Axil janap...@gmail.com:


Testing.

What both builders of the Ni/H reactor have done is to find the proper
pulse rate for the plasma creation reaction through trial and error testing.


On Tue, Aug 20, 2013 at 11:29 AM, David Roberson dlrober...@aol.com wrote:


Axil,

 You discuss the destruction and reformation of NAE over a finite period
of time.  Do you think that there is some negative feedback mechanism in
effect which forces the new formations to match the old ones that have been
destroyed?  It seems logical that a process that does not have a direct
connection between production and destruction of NAE would proceed to
either thermal run away or ultimate cool down.

 I suppose that a process might originate where elevated temperature
results in that destruction being enhanced, particularly in the hot spots.
 The question is: What keeps the process in balance according to your
hypothesis?

 Dave


-Original Message-
From: Axil Axil janap...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Tue, Aug 20, 2013 10:23 am
Subject: Re: [Vo]:Re: CMNS: about the Nuclear Active Environment

  LENR is driven by a specific topology that directs electrons into the
special motions and concentrations which result in the LENR reaction.


  Cracks are a good example of this topology in that through the
discontinuity of the lattice that a crack provides, dipole motion meets a
boundary condition that forces electrons to follow a circular path as a
vortex electron currents forms.

 This dislocation of dipole motion must occur at the surface of a metal
at the boundary between the metal a dielectric isolator.


 The downside of a permanent lattice structure like a crack is that it
will deteriorate over time due to the stresses placed on its topology as
nuclear reactions occur in and around this boundary location.


 The crack will erode over time and the special conditions that cause the
electrons to behave in this special way will no longer be preserved over
extended time.


 But discontinuities in dipole movement will also occur between
nano-particles and micro particles.


 These discontinuities will be continually reformed and dispersed in a
dynamic process as the particles float and bump around in the turbulent
motion of a hot hydrogen atmosphere.


 These nanoparticles will also be destroyed by nuclear activity, but that
can be occasionally rebuilt out of the condensation process after the
plasma stage produced by a hot heater element or a spark discharge.


 In this way, the NAE, is continually rebuilt at a fixed rate that
exactly counters the rate of destruction caused in these particles by
nuclear activity.


 The effective LENR reaction is a fluid process of continual destruction
and renewal that any solid structure cannot duplicate.





On Tue, Aug 20, 2013 at 10:20 AM, Edmund Storms  
stor...@ix.netcom.comwrote:



Terry, the problem is psychological, not scientific. Understanding CF
requires a change in perspective, which is hard for many people to do. You
need to look at the system in which the nuclear reaction occurs from the
perspective of the assembly of atoms, i.e. like a chemist does.  The
chemical system os constructed by interaction of the electrons and this
interaction has very clear rules. Any change required to initiate a nuclear
reaction will be communicated to this assembly and cause changes before the
change will be experienced by the nucleus. That process provides the basic
limitation to any mechanism proposed to occur in the lattice itself. In
other words, to cause a nuclear effect, the chemical structure will also be
affected in ways that will stop the nuclear process. This is how a chemical
system is known to behave based on centuries of experience by chemists and
by examining material over geological time. A change in perspective is
REQUIRED before a person can fully appreciate the role of the chemical
system.  That is why a condition must be created outside of the rules that
apply to the chemical system. The region INSIDE a crack provides this
environment. Events occurring in this region would not affect or be
affected by the chemical structure, hence could form a condition able to
initiate a nuclear reaction. This is a very basic insight that cannot be
falsified in the usual way. It requires a change in perspective to be
evaluated.

This situation is similar to how the relationship between the Sun and
Earth was once explained,  A change in perspective was required before the
correct analysis could be done. Before this change in perspective occurred,
very convincing mathematical analysis showed that the Sun circled the
Earth, as was obvious to any casual observer. The tools available at the
time could not falsify this concept.

Ed




On Aug 20, 2013, at 7:02 AM, Terry Blanton wrote:

 On Tue, Aug 20, 2013 at 7:49 AM, Sunil Shah s.u.n@hotmail.com

wrote:


Ed,

A long time ago, in Solid State Physics, I read 

RE: [Vo]:Norman D. Cook @ ICCF18: Isotope shifts in LENR

[Arnaud Kodeck]

I’ve read the slides. I don’t understand how the depletion mechanism works.
In other words, what makes this theory valuable? Everyone could give the
depletion rate for each isotope that matches the experimental values. There
is no discovery here. So there is something I’ve not understood.

 

  _  

From: Teslaalset [mailto:robbiehobbiesh...@gmail.com] 
Sent: samedi 10 août 2013 18:37
To: vortex-l@eskimo.com
Subject: [Vo]:Norman D. Cook @ ICCF18: Isotope shifts in LENR

 

IInteresting analysis of LENR experiments by Norman D. Cook and Valerio
Dallacasa, presented at ICCF 18. Shifts in isotopic percentages in LENR
'fuels'. 

It has some interesting hooks with Rossi's claim on Ni62 being essencial and
Defkalion menitioning that Ni61 does not participate in Ni-H LENR reactions.


 
http://www.linkedin.com/redirect?url=https%3A%2F%2Fmospace%2Eumsystem%2Eedu
%2Fxmlui%2Fbitstream%2Fhandle%2F10355%2F36817%2FSimulationNuclearTransmutati
onPresentation%2Epdf%3Fsequence%3D2urlhash=D4f0_t=tracking_anet
https://mospace.umsystem.edu/xmlui/bitstream/handle/10355/36817/SimulationNu
clearTransmutationPresentation.pdf?sequence=2 

 

Norman D. Cook is author of the book Models of the Atomic Nucleus,
published by Springer

RE: [Vo]:Norman D. Cook @ ICCF18: Isotope shifts in LENR

[Arnaud Kodeck]

Thanks Axil,

 

I do understand what you explained well. But what makes the theory valuable?
How do they explain the difference between isotopes? What does make the
value 86.13% in page 30 special? They play with Depletion Rates per Isotope,
as they want, to fit the arbitrary 86.13%. Or is it something that is not
well explained that enlighten the whole thing?

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: samedi 10 août 2013 23:17
To: vortex-l
Subject: Re: [Vo]:Norman D. Cook @ ICCF18: Isotope shifts in LENR

 

I don’t understand how the depletion mechanism works.

Fission preferentially occurs in one isotope over the others. This isotope
is depleted in relation to the others.

For example, Ni58 undergoes fission more often than do NI60, Ni61, Ni62, and
Ni64.

In slide titled Nickel Transmutation SUS304 alloy: 8% Nickel, 18% Chromium,
74% Iron …used in a high-temperature alloy+H20 Hydrogen-generating system,
this slide shows as follows:  


Ni58 drops as a percentage from 68% to 42% in nickel isotope abundance. This
means that Ni58 fissions into lighter elements more than the other nickel
isotopes.

 

On Sat, Aug 10, 2013 at 1:39 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

I’ve read the slides. I don’t understand how the depletion mechanism works.
In other words, what makes this theory valuable? Everyone could give the
depletion rate for each isotope that matches the experimental values. There
is no discovery here. So there is something I’ve not understood.

 

  _  

From: Teslaalset [mailto:robbiehobbiesh...@gmail.com] 
Sent: samedi 10 août 2013 18:37
To: vortex-l@eskimo.com
Subject: [Vo]:Norman D. Cook @ ICCF18: Isotope shifts in LENR

 

IInteresting analysis of LENR experiments by Norman D. Cook and Valerio
Dallacasa, presented at ICCF 18. Shifts in isotopic percentages in LENR
'fuels'. 

It has some interesting hooks with Rossi's claim on Ni62 being essencial and
Defkalion menitioning that Ni61 does not participate in Ni-H LENR reactions.


 
http://www.linkedin.com/redirect?url=https%3A%2F%2Fmospace%2Eumsystem%2Eedu
%2Fxmlui%2Fbitstream%2Fhandle%2F10355%2F36817%2FSimulationNuclearTransmutati
onPresentation%2Epdf%3Fsequence%3D2urlhash=D4f0_t=tracking_anet
https://mospace.umsystem.edu/xmlui/bitstream/handle/10355/36817/SimulationNu
clearTransmutationPresentation.pdf?sequence=2 

 

Norman D. Cook is author of the book Models of the Atomic Nucleus,
published by Springer

 

RE: [Vo]:Rossi and LENR to Electric conversion

[Arnaud Kodeck]

Hello Ron,

 

I had a look on the frenglish video. I can't see what is special in this
video. If the guy replaces the electrolysis cell with a film resistor
(without deep inductance), the magnet will be bouncing as well inside the
coil. In other words, it is the current from the grid which makes the magnet
bouncing, not a pseudo current from the cell.

 

Arnaud

  _  

From: Ron Kita [mailto:chiralex.k...@gmail.com] 
Sent: mercredi 31 juillet 2013 19:44
To: vortex-l
Subject: [Vo]:Rossi and LENR to Electric conversion

 

Greetings Vortex-L,

 

I just saw this, and  is this the

route that Rossi will use to generate electricity from the 

LENR plasma  reactions..website:

lenrnews.eu

http://www.enr.eu

 

I merely am an old friend of Gene M and follow

Rossi et al.

 

Respectfully,

Ron Kita, Chiralex

Clueless of LENR...my  disclaimer.

 

 

RE: [Vo]:The recent ICCF18 (Defkcalion Demo)

[Arnaud Kodeck]

Axil,

 

Where can I find the presentation of Kim at ICCF18?

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mardi 30 juillet 2013 16:38
To: vortex-l
Subject: Re: [Vo]:The recent ICCF18 (Defkcalion Demo)

 

Defkelion has mentioned nanoplasmonics in their ICCF-18 via Kim this year.
You best begin your study of this area of scienceto understand LENR.

RE: [Vo]:The recent ICCF18 (Defkcalion Demo)

[Arnaud Kodeck]

Defkalion is making a lot of claims without proof of what they say.

 

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mardi 30 juillet 2013 18:46
To: vortex-l
Subject: Re: [Vo]:The recent ICCF18 (Defkcalion Demo)

 

http://coldfusionnow.org/iccf-18-day-5-presentations-and-awards/

 

 http://coldfusionnow.org/iccf-18-day-5-presentations-and-awards/ ICCF-18
Day 5: Presentations and Awards

 

An excerpt from the reference.

 

 

Theoretical Analysis and Reaction Mechanisms for Experimental Results of
Hydrogen-Nickel Systems presented by Yeong Kim was anticipated because of
his recent collaboration with Defkalion Green Technologies, who beamed in a
video of their demonstration of the R-5 reactor in Milan on Tuesday.

 

The Hyperion reactor contains a core of nickel metal foam. Heating the
system to 180 C - 849 C, the Hyperion is then triggered, after which the
magnetic field rose 0.6 to 1.6 Tesla.

 

Kim says, This indicates that LENRs are producing very strong electric
fields E, currents I, and magnetic fields B.

 

ICCF-18fKim reported Defkalion tests produced excess heat only with the even
isotopes of Ni (58, 60, 62, and 64), whereas odd isotopes do not produce
excess heat (61).

 

No gammas outside of 50 keV to 300 keV were detected from the Hyperion. 

 

Graphs were shown of an excess heat run, and a control run, where the data
showed the power can be cut-off at will, revealing the ability to control
the reaction.

 

Kim then began to describe his theoretical explanation of the data. He
speculated that in the Fleischmann-Pons Effect (FPE), two deuterons making a
Helium-4 require a symmetric release of energy, to conserve total momentum.

 

For two-particles exiting the reaction, his model shows lower probability.

 

The problem is solved, says Kim, and he is willing to talk to other
theorists to help convince them.

 

He then described Boson Cluster-State Nuclear Fusion (BCSNF) generalized to
include Hydrogen-Metal Systems. While there are still some unknowns, namely
the S-factor representing the nuclear force strength, and the probability of
the Boson Cluster State (BCS), the predicted reaction rates can be compared
with the experimental reaction rates.

 

Kim speculated that the magnetic fields generated by the triggering could
provide magnetic alignments of Nickel atoms, and these could provide
localized magnetic trap (LMT) potentials for Boson clusters on the surface
of Ni powders, though these traps have short lifetimes.

 

It is Rydberg atoms that then form the BEC cluster state.

 

H and Ni powders triggered by glow discharge created a magnetic field
causing Rydberg states allowing nano-scale localized magnetic traps,
allowing Hydrogen Boson Cluster States in the LMT on the Ni surfaces. Fusion
between these elements create excess heat and locally produced glow
discharges.

 

Kim writes, Transmutation reactions involving Ni isotopes may not be
dominant reaction mechanism but could be part of much weaker secondary
reaction.

 

Kim believes that self-sustaining reactions could be improved by increasing
the deuterium density, and this will be tested with Hyperion R-6 reactor
with the on-line real-time mass spectrometer at Defkalion Lab. 

 

1% of Defkalion revenue will be spent on basic scientific research. Moving
forward, Defkalion will be cooperating with National Instruments, as well.

 


--

 

IMHO, Boson Cluster-State Nuclear Fusion (BCSNF) is a Nanoplasmonic process.

 

I do not agree with Kim that BEC is the primary LENR mechanism. It is
instead a epiphenomenon (plural - epiphenomena) or a secondary phenomenon
that occurs alongside or in parallel to a primary phenomenon.

 

An epiphenomenon can be an effect of primary phenomena, but cannot affect a
primary phenomenon.

 

In the field of complex systems, the term epiphenomenon tends to be used
interchangeably with emergent effect.

 



 

In the E-cat, the polariton formation process allows for the formation of
EMF solitons as separate unconnected units at low temperatures. 

 

As the temperature rises, polariton formation of global polariton
Bose-Einstein condensation appears as an epiphenomenon. This BEC will
thermalize the gamma radiation via a superatom mechanism.

 

See

 

Spasers explained

 

http://www.phy-astr.gsu.edu/stockman/data/Spaser_Chapter.pdf

 

 

 

On Tue, Jul 30, 2013 at 12:12 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Axil,

 

Where can I find the presentation of Kim at ICCF18?

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mardi 30 juillet 2013 16:38
To: vortex-l


Subject: Re: [Vo]:The recent ICCF18 (Defkcalion Demo)

 

Defkelion has mentioned nanoplasmonics in their ICCF-18 via Kim this year.
You best begin your study of this area of scienceto understand LENR.

 

RE: [Vo]:The recent ICCF18 (Defkcalion Demo)

[Arnaud Kodeck]

As said before by Jed, this is a full list of theoretical speculations put
one after another one. There no experiments that confirm their speculations.

Did they make any measurements about Rydberg hydrogen? The EM field that
they are claiming should have been measured with precision. Or are they
hiding the proof?

 

The Defkalion theory might be right to explain the excess heat of the
hyperion. But it might be as well something else that produces the extra
energy.

 

I hope the realtime spectrometer they are building with R6 reactor will open
our eyes to what's going on inside.

 

I don't blame Defkalion. They have made tremendous steps in the right
direction, and given a lot of hints to the public.

 

They have the device. If they make theory about how it is working, they
should then also provide the clues of their claimed theory. They did not. No
one else could. Everybody can make theory. Only Defkalion can make the final
proof or rejection.

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mardi 30 juillet 2013 22:41
To: vortex-l
Subject: Re: [Vo]:The recent ICCF18 (Defkcalion Demo)

 

What does proof buy you.

 

When someone tells you something, you can either ignore it or try it out. If
they supply you proof, that just motivates you more to try to replicate it.
If they supply no proof, you may not feel as confident that the thing will
work but you can still try to verify it via experimentation.

 

The function of proof is to just make you feel better that you are not
wasting your time..

 

 

On Tue, Jul 30, 2013 at 4:12 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Defkalion is making a lot of claims without proof of what they say.

 

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mardi 30 juillet 2013 18:46


To: vortex-l
Subject: Re: [Vo]:The recent ICCF18 (Defkcalion Demo)

 

http://coldfusionnow.org/iccf-18-day-5-presentations-and-awards/

 

 http://coldfusionnow.org/iccf-18-day-5-presentations-and-awards/ ICCF-18
Day 5: Presentations and Awards

 

An excerpt from the reference.

 

 

Theoretical Analysis and Reaction Mechanisms for Experimental Results of
Hydrogen-Nickel Systems presented by Yeong Kim was anticipated because of
his recent collaboration with Defkalion Green Technologies, who beamed in a
video of their demonstration of the R-5 reactor in Milan on Tuesday.

 

The Hyperion reactor contains a core of nickel metal foam. Heating the
system to 180 C - 849 C, the Hyperion is then triggered, after which the
magnetic field rose 0.6 to 1.6 Tesla.

 

Kim says, This indicates that LENRs are producing very strong electric
fields E, currents I, and magnetic fields B.

 

ICCF-18fKim reported Defkalion tests produced excess heat only with the even
isotopes of Ni (58, 60, 62, and 64), whereas odd isotopes do not produce
excess heat (61).

 

No gammas outside of 50 keV to 300 keV were detected from the Hyperion. 

 

Graphs were shown of an excess heat run, and a control run, where the data
showed the power can be cut-off at will, revealing the ability to control
the reaction.

 

Kim then began to describe his theoretical explanation of the data. He
speculated that in the Fleischmann-Pons Effect (FPE), two deuterons making a
Helium-4 require a symmetric release of energy, to conserve total momentum.

 

For two-particles exiting the reaction, his model shows lower probability.

 

The problem is solved, says Kim, and he is willing to talk to other
theorists to help convince them.

 

He then described Boson Cluster-State Nuclear Fusion (BCSNF) generalized to
include Hydrogen-Metal Systems. While there are still some unknowns, namely
the S-factor representing the nuclear force strength, and the probability of
the Boson Cluster State (BCS), the predicted reaction rates can be compared
with the experimental reaction rates.

 

Kim speculated that the magnetic fields generated by the triggering could
provide magnetic alignments of Nickel atoms, and these could provide
localized magnetic trap (LMT) potentials for Boson clusters on the surface
of Ni powders, though these traps have short lifetimes.

 

It is Rydberg atoms that then form the BEC cluster state.

 

H and Ni powders triggered by glow discharge created a magnetic field
causing Rydberg states allowing nano-scale localized magnetic traps,
allowing Hydrogen Boson Cluster States in the LMT on the Ni surfaces. Fusion
between these elements create excess heat and locally produced glow
discharges.

 

Kim writes, Transmutation reactions involving Ni isotopes may not be
dominant reaction mechanism but could be part of much weaker secondary
reaction.

 

Kim believes that self-sustaining reactions could be improved by increasing
the deuterium density, and this will be tested with Hyperion R-6 reactor
with the on-line real-time mass spectrometer at Defkalion Lab. 

 

1% of Defkalion revenue will be spent on basic scientific research. Moving
forward, Defkalion will be cooperating with National

RE: [Vo]:DGT Temperature Output Appears to Have a Problem

[Arnaud Kodeck]

Dave,

 

I'm fully agreed with you, but maybe to keep the reactor running, they need
that temp out .

 

Arnaud

  _  

From: David Roberson [mailto:dlrober...@aol.com] 
Sent: mardi 23 juillet 2013 21:23
To: vortex-l@eskimo.com
Subject: [Vo]:DGT Temperature Output Appears to Have a Problem

 

I have been watching the DGT demo with enthusiasm.  The technique that they
use to measure the output power gives me pause because of the elevated
output reading that they use to calculate the power. 

 

I noticed that the output temperature is in the ballpark of 150 C, which I
have a strong suspicion is not what the output water is actually exhibiting.
This may be a metallic structure reading instead of water since the internal
temperature readings are so large.  I am not capable of interacting with the
on line demo so perhaps someone else might ask them about this issue for me.

 

They should increase the water flow enough to keep the water from boiling in
order to prove that the power is as measured by their experiment.
Otherwise, I would just assume that the water is boiling and at 100 C
provided it is proven dry.

 

Does anyone else share this concern?

 

Dave

RE: [Vo]:DGT Temperature Output Appears to Have a Problem

[Arnaud Kodeck]

To do that, they will need to insulate the reactor from the coolant. So they
can increase the flow rate of cold water and keep same temp in the reactor.
Then another the problem might occur about stability of the reaction.

 

I've asked on the chat box to show the steam out the pipe. No answer :-( Bad
sign.

  _  

From: David Roberson [mailto:dlrober...@aol.com] 
Sent: mardi 23 juillet 2013 21:32
To: vortex-l@eskimo.com
Subject: Re: [Vo]:DGT Temperature Output Appears to Have a Problem

 

Arnaud, 

 

The internal temperature is most likely what must be maintained to keep it
running.  If they could conduct a bit less heat outward then the internal
heat could be maintained high at the same time.  This would be a balancing
act though.  Someone would have to play with the cooling coils to adjust
their position and contact.

 

Mats should find a way to expose the output water stream to the air and see
if it is violently ejected due to the pressure that should be associated
with the elevated output temperature of the steam.  My suspicion is that
they are not getting an accurate reading of the steam itself.  This is
unfortunate.

 

Dave



-Original Message-
From: Arnaud Kodeck arnaud.kod...@lakoco.be
To: vortex-l vortex-l@eskimo.com
Sent: Tue, Jul 23, 2013 3:28 pm
Subject: RE: [Vo]:DGT Temperature Output Appears to Have a Problem

Dave,

 

I'm fully agreed with you, but maybe to keep the reactor running, they need
that temp out .

 

Arnaud

  _  

From: David Roberson [mailto:dlrober...@aol.com mailto:dlrober...@aol.com?
] 
Sent: mardi 23 juillet 2013 21:23
To: vortex-l@eskimo.com
Subject: [Vo]:DGT Temperature Output Appears to Have a Problem

 

I have been watching the DGT demo with enthusiasm.  The technique that they
use to measure the output power gives me pause because of the elevated
output reading that they use to calculate the power. 

 

I noticed that the output temperature is in the ballpark of 150 C, which I
have a strong suspicion is not what the output water is actually exhibiting.
This may be a metallic structure reading instead of water since the internal
temperature readings are so large.  I am not capable of interacting with the
on line demo so perhaps someone else might ask them about this issue for me.

 

They should increase the water flow enough to keep the water from boiling in
order to prove that the power is as measured by their experiment.
Otherwise, I would just assume that the water is boiling and at 100 C
provided it is proven dry.

 

Does anyone else share this concern?

 

Dave

RE: [Vo]:DGT Temperature Output Appears to Have a Problem

[Arnaud Kodeck]

You need to be registered to livestream.

-Original Message-
From: Alan Fletcher [mailto:a...@well.com] 

There seem to be TWO chat streams .. the comments (where I've posted) and
the bar on the right (which has the most action). I haven't figured out how
to use the one on the right.

RE: [Vo]:Secrets

[Arnaud Kodeck]

 

 

  _  

From: Terry Blanton [mailto:hohlr...@gmail.com] 
Sent: mardi 23 juillet 2013 21:47
To: vortex-l@eskimo.com
Subject: [Vo]:Secrets

 

No dependence on isotopes!

= Ni61 doesn't react according Defkalion

Heat gradient in reactor cell!

= To have H flow inside the reactor? If yes then the reaction is in fact a
multi stages reaction.

WOW, this has been an exciting day.

RE: [Vo]:DGT Temperature Output Appears to Have a Problem

[Arnaud Kodeck]

Scroll to top ?

-Original Message-
From: Alan Fletcher [mailto:a...@well.com] 
Sent: mardi 23 juillet 2013 22:02
To: vortex-l@eskimo.com
Subject: Re: [Vo]:DGT Temperature Output Appears to Have a Problem

 From: Arnaud Kodeck arnaud.kod...@lakoco.be
 Sent: Tuesday, July 23, 2013 12:47:07 PM

 You need to be registered to livestream.

I registered, but that only lets me comment at the bottom of the screen, not
on the right.

RE: [Vo]:DGT Temperature Output Appears to Have a Problem

[Arnaud Kodeck]

The tap water is above 1 bar (Around 5 bars, depending the water tower
position). Could the pressure from the tap still be above 4 bars until pipe
exhaust?

-Original Message-
From: Alan Fletcher [mailto:a...@well.com] 
Sent: mardi 23 juillet 2013 22:25
To: vortex-l@eskimo.com
Subject: Re: [Vo]:DGT Temperature Output Appears to Have a Problem

Water-only at 143C would need a pressure of 4 bars.  Unlikely.

RE: EXTERNAL: Re: [Vo]:Speculation about hotCat CB radio RF generation

[Arnaud Kodeck]

If CB signal controls the eCat (which I doubt) then the problems of
overheating, positive feedback will be solved easily. This is not the case.
Otherwise a CB radio amateur could solve the eCat control issue if it was so
easy and COP infinite.

 

If EM enhances the reaction rate, then it should at a low frequency
regarding the material used by Rossi to make its eCat.

  _  

From: David L Babcock [mailto:ol...@rochester.rr.com] 
Sent: jeudi 30 mai 2013 02:57
To: vortex-l@eskimo.com
Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat CB radio RF
generation

 

If plenty of power is available, and stringent RF interference specs don't
need to be met, the simple wires will work fine.

But I must admit an engineer would always use a coax for such a task.
But maybe not an engineer who is trying to obsfucate


On 5/29/2013 4:47 PM, Arnaud Kodeck wrote:

To bring CB signal, the wires have to be shielded. The impedance must match
in all system. Attenuation of CB signal must be kept as low as possible .
The simple wires from the black box to the eCat doesn't meet those
requirements. It's common sense for an EE.

 


  _  


From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mercredi 29 mai 2013 22:43
To: vortex-l
Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Why else would Rossi say that the output of his control box was a trade
secret? 

 

A DC feed of a internal heater is not a trade secret.

 

On Wed, May 29, 2013 at 4:34 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Axil,

I doubt that the actual design of the eCat is able to bring CB range signal
from electrical heating system. Or where else ?

 


  _  


From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mercredi 29 mai 2013 22:08
To: vortex-l


Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

EMF simulation in the CB range will form nanoparticles (aka clusters).
Potassium is the best candidate for the formation of dynamic NAE through
nanoparticle formation when stimulated by EMF. 

 

On Wed, May 29, 2013 at 4:02 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Ed,

 

I think you forget to add the EM stimulation controlled by the black box
between wall socket and the eCat.

 Arnaud

 

 

 

 

RE: EXTERNAL: Re: [Vo]:Speculation about hotCat

[Arnaud Kodeck]

Ed,

 

I think you forget to add the EM stimulation controlled by the black box
between wall socket and the eCat.

 

Arnaud

  _  

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: mercredi 29 mai 2013 21:53
To: vortex-l@eskimo.com
Cc: Edmund Storms
Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Fran, I would not guess how Rossi bonds the powder to the wall, only that
this must be done. A secret sauce is applied before the Ni is placed in the
e-Cat in order to create the NAE. You need to identify how many additional
secret sauces you think are involved. He also places a hydride in the tube
to supply hydrogen. This material also might have an effect.  I suggest
speculation about things we have no way of knowing is not productive. Let's
discuss what is real and required by nature for the observed effect to be
produced. 

 

We know Rossi activates the Ni before it is used, i.e. creates the NAE.

We know this powder must make good thermal contact with the wall.

We know that Ni powder sinters at the temperature being produced.

We know that the NAE is stable at these temperatures. 

We know that the generated power increases with increased temperature.
Therefore, a positive feedback is operating.

We know that Rossi attempts to control this feedback by controlling the
temperature.

We know that the power source responds rapidly to the external temperature.
Therefore, good thermal contact exists between the source and the thermal
sink. 

We can suspect that no additional source of energy or stimulation is applied
to the power source other than temperature.

 

These are the only facts I can identify. Did I miss anything?

 

Ed Storms

 

 

 

On May 29, 2013, at 1:28 PM, Roarty, Francis X wrote:





Ed,

you make a good case that something improves the thermal bond of the powder
to the inner walls.. perhaps the function of the secret sauce.. I don't
recall the volume of the powder used but am under the impression it fills
most of the reactor tube and therefore must also have good thermal bond
through it's own bulk to reach the reactor walls. I think the MAHG was a
weak easily compromised cousin to this device with only a thin sputtered
layer on the inner wall of the tube while Rossi has designed a way to stack
NAE out into a bulk form away from the reactor wall.  I gathered from the
thread that very little powder spilled out when they cut it open after
destruction. so would assume the bonding held the powder inside as a foam or
gelatinous solid? Can we assume the secret sauce must bind the powder into
some form of solid. I am leaning toward an open foam like malted milk balls
but a recent thread also suggested a gelatinous colloid.

Fran

 

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: Wednesday, May 29, 2013 11:43 AM
To: vortex-l@eskimo.com
Cc: Edmund Storms
Subject: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Bob, this is a good analysis of a possible design.  You are right, the
powder must make good thermal contact with the wall for the nuclear reaction
to be controlled by temperature. Just how Rossi makes this happen is
unknown.  Nevertheless, most of the active nickel must be attached to the
inner wall of the stainless tube. In addition, at the temperatures used, the
Ni powder would sinter and not be easily to remove. 

 

As for modifying the stainless using chemical etch, I doubt this would be
effective.  This texture would have to be active initially and remain
unchanged at high temperature. Such textures are not stable and would not
survive the high temperature. Rossi has done something to the Ni powder that
is very stable and not affected by high temperature.  This fact alone
greatly reduces the possibilities to anyone familiar with the materials
science of this material. Rossi is gradually letting the cat out of the bag,
whether he wants to or not.

 

Ed Storms

On May 29, 2013, at 8:29 AM, Bob Higgins wrote:






I  would like to submit my speculation about the latest Rossi hotCat for
discussion on Vortex-l.

* We are told that the central reactor core is a 310 stainless steel
cylinder ( 3cm by 33cm).  There is no port for introduction of H2.  The ends
are cold welded closed.

* When the test device was sawed open, only a miniscule amount of
powder came out.  This cannot be the active powder - it would have melted as
loose powder rather than conveying the heat out of the cylinder.

* It is highly desirable to have high thermal conductivity between
the NAEs and the outer metal cylinder.  You wouldn't get this with loose
powder on the inside.

* 310 stainless is ~25% chromium, ~21% Ni, and the balance mostly
iron

Consider what Celani has done - taken a Ni-Cu alloy wire and etched out the
Cu to realize the surface nanotexturing, thus creating NAEs on the wire
outer surface.  Suppose we took the 310 stainless cylinder and used a
chromium etch on the inner surface.  Chrome etches typically contain nitric
acid which will 

RE: EXTERNAL: Re: [Vo]:Speculation about hotCat

[Arnaud Kodeck]

The EM stimulation may not need to be at a high frequency level. That could
be superwave as discussed here
http://www.mail-archive.com/vortex-l@eskimo.com/msg80933.html
http://www.mail-archive.com/vortex-l@eskimo.com/msg80933.html.

 

You say that the Ni/H reaction has shown no need of EM stimulation but that
was always at a low rate reaction. The secret Rossi sauce could be somewhere
there. EM stimulation could enhance the rate of the reaction.

 

That's not a fact I know.

  _  

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: mercredi 29 mai 2013 22:14
To: vortex-l@eskimo.com
Cc: Edmund Storms
Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Amaud, we do not know this is as a fact. That conclusion is only proposed.
We only know the black box controls the temperature INSIDE, probably in a
complex way.  The Ni-H2 reaction has shown no need in the past for EM
stimulation. In any case, the design limits the frequency to a very narrow
and presumably unproductive range. If Rossi wanted to apply stimulation, he
chose a very poor design, which I doubt he would do if this stimulation were
important.

 

Ed Storms

On May 29, 2013, at 2:02 PM, Arnaud Kodeck wrote:





Ed,

 

I think you forget to add the EM stimulation controlled by the black box
between wall socket and the eCat.

 

Arnaud

  _  

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: mercredi 29 mai 2013 21:53
To: vortex-l@eskimo.com
Cc: Edmund Storms
Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Fran, I would not guess how Rossi bonds the powder to the wall, only that
this must be done. A secret sauce is applied before the Ni is placed in the
e-Cat in order to create the NAE. You need to identify how many additional
secret sauces you think are involved. He also places a hydride in the tube
to supply hydrogen. This material also might have an effect.  I suggest
speculation about things we have no way of knowing is not productive. Let's
discuss what is real and required by nature for the observed effect to be
produced. 

 

We know Rossi activates the Ni before it is used, i.e. creates the NAE.

We know this powder must make good thermal contact with the wall.

We know that Ni powder sinters at the temperature being produced.

We know that the NAE is stable at these temperatures. 

We know that the generated power increases with increased temperature.
Therefore, a positive feedback is operating.

We know that Rossi attempts to control this feedback by controlling the
temperature.

We know that the power source responds rapidly to the external temperature.
Therefore, good thermal contact exists between the source and the thermal
sink. 

We can suspect that no additional source of energy or stimulation is applied
to the power source other than temperature.

 

These are the only facts I can identify. Did I miss anything?

 

Ed Storms

 

 

 

On May 29, 2013, at 1:28 PM, Roarty, Francis X wrote:






Ed,

you make a good case that something improves the thermal bond of the powder
to the inner walls.. perhaps the function of the secret sauce.. I don't
recall the volume of the powder used but am under the impression it fills
most of the reactor tube and therefore must also have good thermal bond
through it's own bulk to reach the reactor walls. I think the MAHG was a
weak easily compromised cousin to this device with only a thin sputtered
layer on the inner wall of the tube while Rossi has designed a way to stack
NAE out into a bulk form away from the reactor wall.  I gathered from the
thread that very little powder spilled out when they cut it open after
destruction. so would assume the bonding held the powder inside as a foam or
gelatinous solid? Can we assume the secret sauce must bind the powder into
some form of solid. I am leaning toward an open foam like malted milk balls
but a recent thread also suggested a gelatinous colloid.

Fran

 

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: Wednesday, May 29, 2013 11:43 AM
To: vortex-l@eskimo.com
Cc: Edmund Storms
Subject: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Bob, this is a good analysis of a possible design.  You are right, the
powder must make good thermal contact with the wall for the nuclear reaction
to be controlled by temperature. Just how Rossi makes this happen is
unknown.  Nevertheless, most of the active nickel must be attached to the
inner wall of the stainless tube. In addition, at the temperatures used, the
Ni powder would sinter and not be easily to remove. 

 

As for modifying the stainless using chemical etch, I doubt this would be
effective.  This texture would have to be active initially and remain
unchanged at high temperature. Such textures are not stable and would not
survive the high temperature. Rossi has done something to the Ni powder that
is very stable and not affected by high temperature.  This fact alone
greatly reduces the possibilities to anyone familiar with the materials
science

RE: EXTERNAL: Re: [Vo]:Speculation about hotCat

[Arnaud Kodeck]

Axil,

I doubt that the actual design of the eCat is able to bring CB range signal
from electrical heating system. Or where else ?

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mercredi 29 mai 2013 22:08
To: vortex-l
Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

EMF simulation in the CB range will form nanoparticles (aka clusters).
Potassium is the best candidate for the formation of dynamic NAE through
nanoparticle formation when stimulated by EMF. 

 

On Wed, May 29, 2013 at 4:02 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Ed,

 

I think you forget to add the EM stimulation controlled by the black box
between wall socket and the eCat.

 

Arnaud

  _  

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: mercredi 29 mai 2013 21:53


To: vortex-l@eskimo.com
Cc: Edmund Storms

Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Fran, I would not guess how Rossi bonds the powder to the wall, only that
this must be done. A secret sauce is applied before the Ni is placed in the
e-Cat in order to create the NAE. You need to identify how many additional
secret sauces you think are involved. He also places a hydride in the tube
to supply hydrogen. This material also might have an effect.  I suggest
speculation about things we have no way of knowing is not productive. Let's
discuss what is real and required by nature for the observed effect to be
produced. 

 

We know Rossi activates the Ni before it is used, i.e. creates the NAE.

We know this powder must make good thermal contact with the wall.

We know that Ni powder sinters at the temperature being produced.

We know that the NAE is stable at these temperatures. 

We know that the generated power increases with increased temperature.
Therefore, a positive feedback is operating.

We know that Rossi attempts to control this feedback by controlling the
temperature.

We know that the power source responds rapidly to the external temperature.
Therefore, good thermal contact exists between the source and the thermal
sink. 

We can suspect that no additional source of energy or stimulation is applied
to the power source other than temperature.

 

These are the only facts I can identify. Did I miss anything?

 

Ed Storms

 

 

 

On May 29, 2013, at 1:28 PM, Roarty, Francis X wrote:

 

Ed,

you make a good case that something improves the thermal bond of the powder
to the inner walls.. perhaps the function of the secret sauce.. I don't
recall the volume of the powder used but am under the impression it fills
most of the reactor tube and therefore must also have good thermal bond
through it's own bulk to reach the reactor walls. I think the MAHG was a
weak easily compromised cousin to this device with only a thin sputtered
layer on the inner wall of the tube while Rossi has designed a way to stack
NAE out into a bulk form away from the reactor wall.  I gathered from the
thread that very little powder spilled out when they cut it open after
destruction. so would assume the bonding held the powder inside as a foam or
gelatinous solid? Can we assume the secret sauce must bind the powder into
some form of solid. I am leaning toward an open foam like malted milk balls
but a recent thread also suggested a gelatinous colloid.

Fran

 

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: Wednesday, May 29, 2013 11:43 AM
To: vortex-l@eskimo.com
Cc: Edmund Storms
Subject: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Bob, this is a good analysis of a possible design.  You are right, the
powder must make good thermal contact with the wall for the nuclear reaction
to be controlled by temperature. Just how Rossi makes this happen is
unknown.  Nevertheless, most of the active nickel must be attached to the
inner wall of the stainless tube. In addition, at the temperatures used, the
Ni powder would sinter and not be easily to remove. 

 

As for modifying the stainless using chemical etch, I doubt this would be
effective.  This texture would have to be active initially and remain
unchanged at high temperature. Such textures are not stable and would not
survive the high temperature. Rossi has done something to the Ni powder that
is very stable and not affected by high temperature.  This fact alone
greatly reduces the possibilities to anyone familiar with the materials
science of this material. Rossi is gradually letting the cat out of the bag,
whether he wants to or not.

 

Ed Storms

On May 29, 2013, at 8:29 AM, Bob Higgins wrote:





I  would like to submit my speculation about the latest Rossi hotCat for
discussion on Vortex-l.

* We are told that the central reactor core is a 310 stainless steel
cylinder ( 3cm by 33cm).  There is no port for introduction of H2.  The ends
are cold welded closed.

* When the test device was sawed open, only a miniscule amount of
powder came out.  This cannot be the active powder - it would have melted as
loose powder rather than conveying the heat out

RE: EXTERNAL: Re: [Vo]:Speculation about hotCat

[Arnaud Kodeck]

To bring CB signal, the wires have to be shielded. The impedance must match
in all system. Attenuation of CB signal must be kept as low as possible .
The simple wires from the black box to the eCat doesn't meet those
requirements. It's common sense for an EE.

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mercredi 29 mai 2013 22:43
To: vortex-l
Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Why else would Rossi say that the output of his control box was a trade
secret? 

 

A DC feed of a internal heater is not a trade secret.

 

On Wed, May 29, 2013 at 4:34 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Axil,

I doubt that the actual design of the eCat is able to bring CB range signal
from electrical heating system. Or where else ?

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mercredi 29 mai 2013 22:08
To: vortex-l


Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

EMF simulation in the CB range will form nanoparticles (aka clusters).
Potassium is the best candidate for the formation of dynamic NAE through
nanoparticle formation when stimulated by EMF. 

 

On Wed, May 29, 2013 at 4:02 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Ed,

 

I think you forget to add the EM stimulation controlled by the black box
between wall socket and the eCat.

 

Arnaud

  _  

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: mercredi 29 mai 2013 21:53


To: vortex-l@eskimo.com
Cc: Edmund Storms

Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Fran, I would not guess how Rossi bonds the powder to the wall, only that
this must be done. A secret sauce is applied before the Ni is placed in the
e-Cat in order to create the NAE. You need to identify how many additional
secret sauces you think are involved. He also places a hydride in the tube
to supply hydrogen. This material also might have an effect.  I suggest
speculation about things we have no way of knowing is not productive. Let's
discuss what is real and required by nature for the observed effect to be
produced. 

 

We know Rossi activates the Ni before it is used, i.e. creates the NAE.

We know this powder must make good thermal contact with the wall.

We know that Ni powder sinters at the temperature being produced.

We know that the NAE is stable at these temperatures. 

We know that the generated power increases with increased temperature.
Therefore, a positive feedback is operating.

We know that Rossi attempts to control this feedback by controlling the
temperature.

We know that the power source responds rapidly to the external temperature.
Therefore, good thermal contact exists between the source and the thermal
sink. 

We can suspect that no additional source of energy or stimulation is applied
to the power source other than temperature.

 

These are the only facts I can identify. Did I miss anything?

 

Ed Storms

 

 

 

On May 29, 2013, at 1:28 PM, Roarty, Francis X wrote:

 

Ed,

you make a good case that something improves the thermal bond of the powder
to the inner walls.. perhaps the function of the secret sauce.. I don't
recall the volume of the powder used but am under the impression it fills
most of the reactor tube and therefore must also have good thermal bond
through it's own bulk to reach the reactor walls. I think the MAHG was a
weak easily compromised cousin to this device with only a thin sputtered
layer on the inner wall of the tube while Rossi has designed a way to stack
NAE out into a bulk form away from the reactor wall.  I gathered from the
thread that very little powder spilled out when they cut it open after
destruction. so would assume the bonding held the powder inside as a foam or
gelatinous solid? Can we assume the secret sauce must bind the powder into
some form of solid. I am leaning toward an open foam like malted milk balls
but a recent thread also suggested a gelatinous colloid.

Fran

 

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: Wednesday, May 29, 2013 11:43 AM
To: vortex-l@eskimo.com
Cc: Edmund Storms
Subject: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Bob, this is a good analysis of a possible design.  You are right, the
powder must make good thermal contact with the wall for the nuclear reaction
to be controlled by temperature. Just how Rossi makes this happen is
unknown.  Nevertheless, most of the active nickel must be attached to the
inner wall of the stainless tube. In addition, at the temperatures used, the
Ni powder would sinter and not be easily to remove. 

 

As for modifying the stainless using chemical etch, I doubt this would be
effective.  This texture would have to be active initially and remain
unchanged at high temperature. Such textures are not stable and would not
survive the high temperature. Rossi has done something to the Ni powder that
is very stable and not affected by high temperature.  This fact alone
greatly reduces the possibilities to anyone familiar with the materials

RE: EXTERNAL: Re: [Vo]:Speculation about hotCat

[Arnaud Kodeck]

K2CO3 ?

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mercredi 29 mai 2013 22:49
To: vortex-l
Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

They stated that the chemical was potassium carbide or some other carbon
potassium combo.

 

Carbon will also make nana-particles when the compound vaporizes.

 

On Wed, May 29, 2013 at 4:44 PM, Edmund Storms stor...@ix.netcom.com
wrote:

OK, can anyone from DGT verify that potassium is required to make Ni nuclear
active?   If so, what chemical form is used? 

 

Ed Storms

 

On May 29, 2013, at 2:37 PM, Axil Axil wrote:





DGT has already stated that they use potassium.

 

On Wed, May 29, 2013 at 4:33 PM, Edmund Storms stor...@ix.netcom.com
wrote:

 

On May 29, 2013, at 2:27 PM, Axil Axil wrote:





You did not use the potassium based secret sauce that Rossi uses.

 

How do you know his sauce is potassium based? 





 

Without the ability to create potassium clusters, the reaction is weak.
Using only hydrogen clusters will not support a vigorous reaction. 

 

Again you say this with great certainty. Have you actually tried this idea
and does it work? If so, please publish the results.

 

Ed Storms





 

On Wed, May 29, 2013 at 4:21 PM, Edmund Storms stor...@ix.netcom.com
wrote:

Axil, you make your statements with great certainty. Have you ever actually
studied Ni and successfully caused LENR? I have and I do not see the
behavior you claim must occur.

 

Ed Storms

 

On May 29, 2013, at 2:08 PM, Axil Axil wrote:





EMF simulation in the CB range will form nanoparticles (aka clusters).
Potassium is the best candidate for the formation of dynamic NAE through
nanoparticle formation when stimulated by EMF. 

 

On Wed, May 29, 2013 at 4:02 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

Ed,

 

I think you forget to add the EM stimulation controlled by the black box
between wall socket and the eCat.

 

Arnaud

  _  

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: mercredi 29 mai 2013 21:53


To: vortex-l@eskimo.com
Cc: Edmund Storms

Subject: Re: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

 

 

Fran, I would not guess how Rossi bonds the powder to the wall, only that
this must be done. A secret sauce is applied before the Ni is placed in the
e-Cat in order to create the NAE. You need to identify how many additional
secret sauces you think are involved. He also places a hydride in the tube
to supply hydrogen. This material also might have an effect.  I suggest
speculation about things we have no way of knowing is not productive. Let's
discuss what is real and required by nature for the observed effect to be
produced. 

 

We know Rossi activates the Ni before it is used, i.e. creates the NAE.

We know this powder must make good thermal contact with the wall.

We know that Ni powder sinters at the temperature being produced.

We know that the NAE is stable at these temperatures. 

We know that the generated power increases with increased temperature.
Therefore, a positive feedback is operating.

We know that Rossi attempts to control this feedback by controlling the
temperature.

We know that the power source responds rapidly to the external temperature.
Therefore, good thermal contact exists between the source and the thermal
sink. 

We can suspect that no additional source of energy or stimulation is applied
to the power source other than temperature.

 

These are the only facts I can identify. Did I miss anything?

 

Ed Storms

 

 

 

On May 29, 2013, at 1:28 PM, Roarty, Francis X wrote:

 

Ed,

you make a good case that something improves the thermal bond of the powder
to the inner walls.. perhaps the function of the secret sauce.. I don't
recall the volume of the powder used but am under the impression it fills
most of the reactor tube and therefore must also have good thermal bond
through it's own bulk to reach the reactor walls. I think the MAHG was a
weak easily compromised cousin to this device with only a thin sputtered
layer on the inner wall of the tube while Rossi has designed a way to stack
NAE out into a bulk form away from the reactor wall.  I gathered from the
thread that very little powder spilled out when they cut it open after
destruction. so would assume the bonding held the powder inside as a foam or
gelatinous solid? Can we assume the secret sauce must bind the powder into
some form of solid. I am leaning toward an open foam like malted milk balls
but a recent thread also suggested a gelatinous colloid.

Fran

 

From: Edmund Storms [mailto:stor...@ix.netcom.com] 
Sent: Wednesday, May 29, 2013 11:43 AM
To: vortex-l@eskimo.com
Cc: Edmund Storms
Subject: EXTERNAL: Re: [Vo]:Speculation about hotCat

 

Bob, this is a good analysis of a possible design.  You are right, the
powder must make good thermal contact with the wall for the nuclear reaction
to be controlled by temperature. Just how Rossi makes this happen is
unknown.  Nevertheless, most of the active nickel must

RE: [Vo]:possible error in power-in calculation in Levi et al paper

[Arnaud Kodeck]

Yes the control box is more than a simple low frequency (below 10 Hz) ON/OFF
system.

 

  _  

From: Claudio C Fiorini [mailto:claudio.c.fior...@gmail.com] 
Sent: dimanche 26 mai 2013 00:07
To: vortex-l@eskimo.com
Subject: Re: [Vo]:possible error in power-in calculation in Levi et al paper

 

By the way: the low pf has nothing to do with the heating resistors, they
are behind the control box.

RE: [Vo]:Levi Hot Cat paper is a gem

[Arnaud Kodeck]

I'm wondering if Levi and al checked the quality of the electrical power! On
the topic regarding electrical measurements the report says that the
measurements were done with a PCE-830. The PCE-830 monitored the 3 phases
only and computed the energy consumption with data collected on the 3
phases. The PCE-830 can be fooled if the setup isn't as expected. For
example, the ground might be not the ground but a hidden phase. That's why
they should have checked:
- The quality of the ground
- The quality of the 3 phases regarding the neutral or between
phases
- The quality of the neutral (if present and used)
- The quality of the 50 Hz of the power line

That check will remove every concern about electrical input. Maybe they did
the check but there is no mention about that in the report of Levi and al.

To whom may I address this concern at the Levi's team and how ?

Arnaud
 -Original Message-
 From: Alan Fletcher [mailto:a...@well.com]
 Sent: mercredi 22 mai 2013 09:00
 To: vortex-l@eskimo.com
 Subject: Re: [Vo]:Levi Hot Cat paper is a gem
 
   So in a sense the elimination of fakes is cumulative.
 
 Bear in  mind that when Rossi says he has something he tends to follow up
 on it.
 (Maybe not exactly as promised, but close to it).
 
 Let's accept for the moment the OUTPUT analysis : it DOES produce the
 documented COP.
 
 Electrical INPUT is a two-edged sword. It can be measured to 6 decimal
 places .. IF you do it correctly,
 but if you don't cover ALL bases you might miss something.
 (eg an AC-only meter might not notice DC, or HF AC beyond its spec).
 
 But Rossi says he has a GAS-POWERED eCat. I believe him: ANY source of
 temperature stimulus will do.
 
 It's rather hard to modulate/cheat a GAS meter, though the actual INPUT
 power delivered might only be known to ONE decimal place.

RE: [Vo]:Re: Levi Hot Cat paper is a gem

[Arnaud Kodeck]

The power measurements carried by the Levi's team is at least poorly
reported, or worst poorly done. As said before the power consumption they
computed in the report is not convincing at all. There was no check
(reported at least, or worst not done) of the quality of the electrical wall
plug! There are ways there to fool the electrical power seen by the
observer with the PCE-830.

 

I'm not saying that Rossi scammed. Just that there, we have a huge flaw. I
hope Levi's team will give us more details about this topic.

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: mercredi 22 mai 2013 20:40
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Re: Levi Hot Cat paper is a gem

 

Andrew andrew...@att.net wrote:

 

My sense is that Rossi forbade them using a scope on the power feed in order
to protect proprietary drive waveform information.

 

This makes no sense. They measured the power going into the power supply.
How could they see the waveform there?

 

- Jed

 

RE: [Vo]:Levi Hot Cat paper is a gem : power conditioner needed

[Arnaud Kodeck]

 -Original Message-
 From: Alan Fletcher [mailto:a...@well.com]
 Sent: mercredi 22 mai 2013 22:19
 To: vortex-l@eskimo.com
 Subject: Re: [Vo]:Levi Hot Cat paper is a gem : power conditioner needed
 
  Electrical INPUT is a two-edged sword. It can be measured to 6
  decimal places .. IF you do it correctly,
  but if you don't cover ALL bases you might miss something.
  (eg an AC-only meter might not notice DC, or HF AC beyond its spec).
 
 I've come to the conclusion that the only way to overcome the power-side
 fake is to put a power conditioner between Rossi's power plug (maybe
 miswired per Bryce etc, or with a DC component) and his control box.
 
 I'd recommend a motor-generator, as it gives a nice sine output. Then the
 meter will work correctly, between the conditioner and the control box.

A basic quality control check of the power-side will be at first a good
step. The idea to put conditioner between Rossi's plug and the wall power
socket will remove any doubt for a miswired error (Voluntary or not)

RE: [Vo]:Celani detects gamma emissions during the January 14, 2011 Rossi Test

[Arnaud Kodeck]

Thank you Jed to remind me this exchange you had with Celani. I was not
fully aware of every detail. When I was reading, an idea come to me mind.
Could it be possible that the secret sauce of Rossi is a gamma emitter? I
explain myself: Secretly, Rossi could have opened his reactor to adjust
something inside then closed the reactor back. In the meantime, Celani
detected an increase of gamma emission. A low frequency gamma (25~50 keV)
could be easily shielded. If Rossi opened his reactor, then vacuum should be
applied prior to reload with H2. The noise of a vacuum pump can not be
hidden easily. Celani and al should have heard it as well. Rossi isn’t fool
to put air and H2 inside a closed vessel …

 

Unfortunately, we don’t have the wavelength of the emission. I don’t want to
play the sceptic here. Can Celani say that he is sure that Rossi didn’t open
his reactor while they were waiting behind the door?

 

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: mardi 21 mai 2013 15:48
To: vortex-l@eskimo.com
Subject: [Vo]:Celani detects gamma emissions during the January 14, 2011
Rossi Test

 

[Here is a message I posted in 2011]

 

Celani detects gamma emissions during the January 14, 2011 Rossi Test

Villa reported no gamma emissions or other radiation significantly above
background from the Rossi device. Celani, however, said that he did detect
something. Here are the details he related to me at ICCF16, from my notes
and with corrections from Celani.

Celani attended the demonstration on Jan. 14. The device did not work at
first. He and others were waiting impatiently in a room next to the room
with the device. He estimates that he was around 6 m from the device. He had
two battery-powered detectors:

1.  A sodium iodide gamma detector (NaI), set for 1 s acquisition time.

2.  A Geiger counter (model GEM Radalert II, Perspective Scientific),
which was set to 10 s acquisition time.

Both were turned on as he waited. The sodium iodide detector was in count
mode rather than spectrum mode; that is, it just tells the number of counts
per second.

Both showed what Celani considers normal background for Italy at that
elevation.

As he was waiting, suddenly, during a 1-second interval both detectors were
saturated. That is to say, they both registered counts off the scale. The
following seconds the NaI detector returned to nomal. The Geiger counter had
to be switched off to “delete” the “overrange,” which was 7.5
microsievert/hour, and later switched on again.

About 1 to 2 minutes after this event, Rossi emerged from the other room and
said the machine just turned on and the demonstration was underway.

Celani commented that the only conventional source of gamma rays far from a
nuclear reactor would be a rare event: a cosmic ray impact on the atmosphere
producing proton storm shower of particles. He and I agreed it is extremely
unlikely this happened coincidentally the same moment the reactor started .
. . Although, come to think of it, perhaps the causality is reversed, and
the cosmic ray triggered the Rossi device.

Another scientist said perhaps both detectors malfunctioned because of an
electromagnetic source in the building or some other prosaic source. Celani
considers this unrealistic because he also had in operation battery-operated
radio frequency detectors: an ELF (Extremely Low Frequency) and RF (COM
environmental microwave monitor), both made by Perspective Scientific. No
radio frequency anomalies were detected. I remarked that it is also
unrealistic because the two gamma detectors are battery powered and they
work on different principles. The scientist pointed to neutron detectors in
an early cold fusion experiment that malfunctioned at a certain time of day
every day because some equipment in the laboratory building was turned on
every day. That sort of thing can happen with neutron detectors, which are
finicky, but this Geiger counter is used for safety monitoring. Such devices
have to be rugged and reliable or they will not keep you safe, so I doubt it
is easy to fool one of them.

Celani expresses some reservations about the reality of the Rossi device.
Given his detector results I think it would be more appropriate for him to
question the safety of it.

When Celani went in to see the experiment in action, he brought out the
sodium iodide detector and prepared to change it to spectrum mode, which
would give him more information about the ongoing reaction. Rossi objected
vociferously, saying the spectrum would give Celani (or anyone else who see
it), all they need to know to replicate the machine and steal Ross's
intellectual property.

Celani later groused that there is no point to inviting scientists to a demo
if you have no intentions of letter them use their own instruments. (Note,
however, that Levi et al. did use their own instruments.)

 

Jacques Dufour also attended the demonstration. He does not speak much
Italian, so he could not follow the discussion. He made 

RE: [Vo]:Celani detects gamma emissions during the January 14, 2011 Rossi Test

[Arnaud Kodeck]

Lovable : Is it an April fool ? (Look at the date of comment of Andrea
Rossi)

2. 
Andrea Rossi

 http://www.journal-of-nuclear-physics.com/?p=614cpage=1#comment-209521
April 1st, 2012 at 5:51 PM

Dear Steven N. Karels:
We use regular Ni, then we make series of treatment. The cost of treatment
is irrelevant compared to the energy produced.
Warm Regards,
A.R.

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: mardi 21 mai 2013 20:23
To: vortex-l
Subject: Re: [Vo]:Celani detects gamma emissions during the January 14, 2011
Rossi Test

 

http://shutdownrossi.com/e-cat-science/110-quotes-by-rossi-about-gamma-rays-
and-transmutations/

 

110+ Quotes by Rossi about Gamma Rays and Transmutations

 

On Tue, May 21, 2013 at 2:19 PM, Axil Axil janap...@gmail.com wrote:

http://cold-fusion.ca/floridagate-puts-rossi-under-scrutiny-299000

 

“Floridagate” puts Rossi under scrutiny

 

The matter was investigated by Mr James Stokes who reported “Dr Rossi stated
the active ingredients are powdered nickel and a tablet containing a
compound which releases hydrogen gas during the process. The output thermal
energy is six times the electrical energy input. He acknowledged that no
nuclear reactions occur during the process and that only low energy photons
in the energy range 50-100 keV occur within the device. There are no
radiation readings above background when the device is in operation. Since
the device is not a reactor, the NRC does not have jurisdiction. Since there
is no radioactive materials used in the construction and no radioactive
waste is generated by it, the State of Florida, Bureau of Radiation Control
has no jurisdiction. Currently, all production, distribution and use of
these devices is overseas. Dr Rossi has arranged to meet with Underwriter
Laboratories (UL) to seek approval for manufacturing in the United States.”

 

On Tue, May 21, 2013 at 1:52 PM, DJ Cravens djcrav...@hotmail.com wrote:


Perhaps Rossi was adding some catalyst.   

For example, perhaps his source of Ni 62 is slightly radioactive  (say it
was prepared via neutron activation of other Ni isotopes say there was some
Ni   63m in it).

Then it might register when the catalyst was accessed.

 

Dennis

 

  _  

From: arnaud.kod...@lakoco.be
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Celani detects gamma emissions during the January 14, 2011
Rossi Test
Date: Tue, 21 May 2013 19:26:01 +0200

 

Thank you Jed to remind me this exchange you had with Celani. I was not
fully aware of every detail. When I was reading, an idea come to me mind.
Could it be possible that the secret sauce of Rossi is a gamma emitter? I
explain myself: Secretly, Rossi could have opened his reactor to adjust
something inside then closed the reactor back. In the meantime, Celani
detected an increase of gamma emission. A low frequency gamma (25~50 keV)
could be easily shielded. If Rossi opened his reactor, then vacuum should be
applied prior to reload with H2. The noise of a vacuum pump can not be
hidden easily. Celani and al should have heard it as well. Rossi isn’t fool
to put air and H2 inside a closed vessel …

 

Unfortunately, we don’t have the wavelength of the emission. I don’t want to
play the sceptic here. Can Celani say that he is sure that Rossi didn’t open
his reactor while they were waiting behind the door?

 

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: mardi 21 mai 2013 15:48
To: vortex-l@eskimo.com
Subject: [Vo]:Celani detects gamma emissions during the January 14, 2011
Rossi Test

 

[Here is a message I posted in 2011]

 

Celani detects gamma emissions during the January 14, 2011 Rossi Test

Villa reported no gamma emissions or other radiation significantly above
background from the Rossi device. Celani, however, said that he did detect
something. Here are the details he related to me at ICCF16, from my notes
and with corrections from Celani.

Celani attended the demonstration on Jan. 14. The device did not work at
first. He and others were waiting impatiently in a room next to the room
with the device. He estimates that he was around 6 m from the device. He had
two battery-powered detectors:

1.  A sodium iodide gamma detector (NaI), set for 1 s acquisition time.

2.  A Geiger counter (model GEM Radalert II, Perspective Scientific),
which was set to 10 s acquisition time.

Both were turned on as he waited. The sodium iodide detector was in count
mode rather than spectrum mode; that is, it just tells the number of counts
per second.

Both showed what Celani considers normal background for Italy at that
elevation.

As he was waiting, suddenly, during a 1-second interval both detectors were
saturated. That is to say, they both registered counts off the scale. The
following seconds the NaI detector returned to nomal. The Geiger counter had
to be switched off to “delete” the “overrange,” which was 7.5
microsievert/hour, and later switched on again.

About 1 to 2 minutes after this event, Rossi 

RE: [Vo]:E-Cat general observations

[Arnaud Kodeck]

From pictures in the Levi's report, the wires are not galvanic shielded
between the eCat and the controller. Thus frequency of the waveform (if any)
is low. And the waveform should be easily determined by a simple
oscilloscope.


 2. I don't have a problem with this verification being done at Rossi's 
 facility, because he doesn't want people carting off the device and 
 reverse-engineering the catalyst (I'm guessing palladium :) and the drive 
 waveform. Nevertheless, this wasn't a pure third party verification.
 

RE: [Vo]:E-Cat general observations

[Arnaud Kodeck]

The temperature limitation of fission nuclear plant is due to temperature of
vaporization of water. The reactor must always be filled with liquid water.
At the pressure inside a fission reactor, the limiting temperature is just a
little above 300°C. The water is slowing the neutron. Without water, a
reactor has a meltdown.

 

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: mardi 21 mai 2013 21:15
To: vortex-l@eskimo.com
Subject: Re: [Vo]:E-Cat general observations

 

Alan Fletcher a...@well.com wrote:

 

That was the motivation behind the hot-cat : the current operating
temperature of around 300C is likely a good fit with the Siemens turbine
they are purportedly experimenting with.

 

The pressurized water in a conventional fission reactor is about 320°C I
believe. The reactors could be designed to run at higher temperatures but
they deliberately made them low with poor Carnot efficiency because this
reduces wear and tear on the turbines, pipes and so on. In a system where
the heat costs you little or nothing, it makes sense to trade off Carnot
efficiency for lower equipment costs.

 

- Jed

 

RE: [Vo]:Levi Hot Cat paper is a gem

[Arnaud Kodeck]

Did the testing team check the electrical power provided by Rossi’s team?

Is ground the ground?

Are all 3 phases, the 3 phases at 120° each? (Are all that 3 phases
effectively measured by the PCE-830 ?)

Is the neutral the neutral?

What are the voltages? (Between phases, between phase and neutral, neutral
and ground)

Is the frequency at 50 Hz?

 

They don’t say anything about that in the report. A highly qualified team in
a full week should have had a look at that.

  _  

From: James Bowery [mailto:jabow...@gmail.com] 
Sent: mardi 21 mai 2013 23:19
To: vortex-l
Subject: Re: [Vo]:Levi Hot Cat paper is a gem

 

The strongest technical argument for the veracity of this report is that the
power measured going into the device is 360W and that the way it was
measured was from the wall socket through an industry standard power
analyzer (PCE-830 Power and Harmonics Analyzer by PCE Instruments).
Detractors assert that as the test was conducted on the premises of the
company licensing the technology EFA srl, therefore Rossi could have
defrauded the investigators by hidden camera, or other spy device, observing
when to apply a hidden AC power source of such high frequency, overlaid on
the normal power, that it would have been undetectable by the PCE-830. This
assertion about the PCE-830's limitations has not been validated as
plausible by PCE Instruments or any other authority.

 

On Mon, May 20, 2013 at 9:09 PM, Jed Rothwell jedrothw...@gmail.com wrote:

I just read this paper for the third time. This is a gem. These people think
and write like engineers rather than scientists. That is a complement coming
from me. They dot every i and cross every t. I can't think of a single thing
I wish they had checked but did not.

 

In ever instance, their assumptions are conservative. Where there is any
chance of mismeasuring something, they assume the lowest possible value for
output, and the highest value for input. They assume emissivity is 1 even
though it is obviously lower (and therefore output is higher). The add in
every possible source of input, whereas any factor that might increase
output but which cannot be measured exactly is ignored. For example, they
know that emissivity from the sides of the cylinder close to 90 degrees away
from the camera is undermeasured (because it is at an angle), but rather
than try to take that into account, they do the calculation as if all
surfaces are at 0 degrees, flat in front of the camera. In the first set of
tests they know that the support frame blocks the IR camera partly, casting
a shadow and reducing output, but they do not try to take than into account.

 

Furthermore, this is a pure black box test, exactly what the skeptics and
others have been crying out for. They make no assumptions about the nature
of the reaction or the content of the cylinder. They make no adjustments for
it; the heat is measured the same way you would measure an electrically
heated cylinder or a cylinder with a gas flame inside it. It is hands-off in
the literal sense, with only the thermocouples touching the cell, and the
rest at a distance, including the clamp on ammeter which placed below the
power supply. You do not have to know anything about the reaction to be sure
these measurements are right. There is nothing Rossi could possibly do to
fool these instruments, which the authors brought with them. They left a
video camera on the instruments at all times to ensure there was no
hanky-panky. They wrote:


The clamp ammeters were connected upstream from the control box to ensure
the trustworthiness of the measurements performed, and to produce a
nonfalsifiable document (the video recording) of the measurements
themselves.

 

They estimate the extent to which the heat exceeds the limits of chemistry
by both the mass of the cell and the volume of the cell. In the first test,
they use the entire weight of the inside cell as the starting point, rather
than just the powder, as if stainless steel might be the reactant. In the
second test they determine that the powder weighs ~0.3 g but they round that
up to 1 g.

 

They use Martin Fleischmann's favorite method of looking at the heat decay
curves when the power cycles off. Plot 5 clearly shows that the heat does
not decay according to Newton's law of cooling. There must be a heat
producing reaction in addition to the electric heater.

 

I like it!

 

- Jed

 

 

RE: [Vo]:Hot Cat report published

[Arnaud Kodeck]

I am surprised by the date of publication: Pentecost. Pentecost means the
descent of the Holy Spirit to the Apostles.

Coincidence?

 -Original Message-
 From: Alan Fletcher [mailto:a...@well.com]
 Sent: lundi 20 mai 2013 11:51
 To: vortex-l@eskimo.com
 Subject: Re: [Vo]:Hot Cat report published
 
 I found an svg file with sample Rogone plots ... and superimposed the Dec
 test on it
 
 Equations 34 and 35
 
 http://www.well.com/~af/ecat_dec_chart_130520A.png
 
 
 (Gee whiz : the COP came out the way we calculated it!)

RE: [Vo]: ECAT Time Domain Response

[Arnaud Kodeck]

Rossi has recently stated in JONP that local hot spots in its reactor were
the main issue. If a spot come to a certain upper threshold, the reactor
goes out of control. The keys are uniformity of heat production inside the
eCat and equal density of energy extraction along the entire surface. The
only way to control the eCat, as far as we know now, is through the inside
temperature of the reactor. If Rossi want to improve the COP, the way to do
it is to find another variable to control (as done by Defkalion with spark
plug). Nevertheless, your time domain work might help a lot.

 

  _  

From: David Roberson [mailto:dlrober...@aol.com] 
Sent: lundi 20 mai 2013 21:17
To: vortex-l@eskimo.com
Subject: [Vo]: ECAT Time Domain Response

I was very pleased at the appearance of the time domain temperature plots
that were shown plotted along with the drive waveform.  These plots strongly
resembled the ones that my model produced and I have long contended that his
limitation of 6 for COP is based upon stable operation of the system.  This
limit occurs as a result of the observation that a device such as his has
the ability to internally generate all of the heat required to run away
unless it can be carefully manipulated.   The SSM period and level are key
to getting the desired performance.

RE: [Vo]: ECAT Time Domain Response

[Arnaud Kodeck]

From Rossi statements, the powder melts and the reactor stops working.

 

  _  

From: mark.gi...@gmail.com [mailto:mark.gi...@gmail.com] On Behalf Of Mark
Gibbs
Sent: lundi 20 mai 2013 23:17
To: vortex-l@eskimo.com
Subject: Re: [Vo]: ECAT Time Domain Response

Does anyone know what happens when Rossi's reactor goes out of control? Does
it melt down or just stop working?

 

RE: [Vo]:Palladium vs Ni-62

[Arnaud Kodeck]

_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: lundi 13 mai 2013 04:34
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Palladium vs Ni-62

Well cost effective would be in the context of the value of the output
over time, no? 

Rossi says a few $ for each 10kW unit per 6 months

If Rossi could buy nickel powder enriched in the active isotope by a factor
of 8-10 times over natural enrichment  - and get it for $100 per gram (in
quantity) and he needs only 10 grams for a 10 kW reactor then it is cost
effective.

That's in the same order as Rossi claims

If DGT is correct, in that they do not need enrichment - then they are in
doubly good shape, given the wording of Rossi's patent application, but who
can be believed ? We have seen even less real results from DGT than from
Rossi.

Mills has shown that nickel and hydrogen alone can work, but apparently
reliability is the issue no one wants to talk about. 

Mills has also showed some clue for a catalyst.

If this isotope has made reliability a non-issue for Rossi, we should know
in the next few months. He seems more confident than ever, but it could be
part of a charade.

I don't believe in isotope enrichment of nickel. He knows that its
patent is weak due too a lot of missing knowledge on what's going on inside
it's reactor or don't want to show. And therefore the patent is easy to
bypass. I think the Isotope topic is just a cloud of smoke.
attachment: winmail.dat

RE: [Vo]:Palladium vs Ni-62

[Arnaud Kodeck]

Jones,

It's a very interesting analysis. I just to want to add 2 comments:

Rossi always claims to have very cost effective powder and catalyst. If
enriched nickel is needed, stop me if I'm wrong, but there is no intrinsic
reason to have a very high purity of Ni62. The last percents are always the
most expensive to have.

That contradicts also the claims from Defkalion. Defkalion says that all the
even isotope are suitable.

Arnaud
_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: dimanche 12 mai 2013 21:42
To: vortex-l@eskimo.com
Subject: [Vo]:Palladium vs Ni-62

If the commercialization of LENR were to resolve on the single issue of cost
of the active metal host, the winner would likely be counterintuitive, based
on present assumptions.

Palladium these days sells for $ 708/oz or about $25 gram.
Nickel-62 - request a quote the price is highly dependent on the quantity
to be ordered. 

The range of quotes for 10 gram orders is from $100,000 to $200,000. The
purity is 95-97%.

The info above, favoring palladium, seems to be unequivocal but in fact -
that conclusion is superficial. 

First, palladium is rare and the price is extremely sensitive to demand. It
could double overnight and has done so, historically. There is no chance of
it going down. Then there is deuterium, which is also costly.

Second, nickel as a bulk metal is pretty cheap - and will go up but there
are limits.  As of May 09, 2013: $6.95 per pound is the quote for nickel. In
terms of increased demand, it could go over $10/lb but probably not over $20
- since it is a high tonnage metal already.

The natural content of Ni-62 is between 3-4%. If half of this can be removed
from a gaseous feedstock, the remaining nickel is still worth the same as
bulk nickel. That is a major advantage over other isotopes used for
enrichment. The purity or conversely - the enrichment level can probably be
low. That is of highest importance for lower cost. It nickel sometimes works
in an un-enriched state, then the level needed for reliable operation could
be relatively low in the 15-20 percent range - and easier to manufacture.

There is only one gaseous form of nickel, but when gasified, nickel could be
enriched in the same kind of ultra-centrifuge cascade used for U. The cost
of enrichment from this process is well-known and probably applicable to
nickel. 

Therefore we are faced with this scenario: what is the fair price of
Nickel-62 in the event that LENR is proved and the demand skyrockets? 

This price -  in the end will be a matter of politics but highly influenced
by supply/demand economics and the desire of the military to have this kind
of power available, especially in aviation. There will be subsidies to
promote LENR - perhaps more than what was given to fission, solar energy and
oil - due to its presumed ecological advantages but they will be hard
fought.

There are many independent companies providing isotopes of all kinds now,
but in the end none of them own gas centrifuge plants for high volume. The
price charged by an mothballed plant could be relatively low - given the
sunk cost and need for jobs in states like Kentucky and Ohio where these
plants exist and which can be switched over to nickel.

Everything gets down to politics in the end, but that equation does not
favor LENR in the USA, due to big oil ... but it does favor LENR in Asia.
China is a wild-card in the rapid commercialization of LENR.

Jones




attachment: winmail.dat

RE: [Vo]:pictures of 1mw E-cat plant shipping

[Arnaud Kodeck]

We can see on the panorama picture ( http://postimg.org/image/6v14pk649/
http://postimg.org/image/6v14pk649/), the hot cat still in the metallic
shelf without electrical feedings.

 

The boxes of the cold cat are different from the October, 2011.

 

It looks like very amateur workshop behind the garage.

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: vendredi 3 mai 2013 22:14
To: vortex-l@eskimo.com
Subject: Re: [Vo]:pictures of 1mw E-cat plant shipping

 

Susanna Gipp susan.g...@gmail.com wrote:

 

I would better title this thread as pictures of 1MW E-cat towing. 

Who didn't recognize the same Oct 2011 demo big box at the Bologna's
facility? 

 

It is the same one, isn't it? This is the 1 MW reactor, not the hot cat.
That's smaller than 1 MW isn't it?

 

This is being taken somewhere to be tested, by someone name Fabiani. These
photos are prefaced with a letter:

 

Dear Doc.Rossi,

please, find the photos of 24H performace test of the MW1-Ecat made on april
30 - may 01 and the photos of when it has been transported from Bologna to
Ferrara to pepare it for the test.

Best regards
M.Eng. F.Fabiani

 

- Jed

 

RE: [Vo]:More on a KGS virtual neutron and Ni-62

[Arnaud Kodeck]

Jones,

It's very interesting theory. Nevertheless, in the web page you mention here
below, it says that Ni63 has a half life of around 100 years (a century).  I
don't think Rossi's device can stay on for that long time.

Arnaud
_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: dimanche 28 avril 2013 18:14
To: vortex-l@eskimo.com
Subject: [Vo]:More on a KGS virtual neutron and Ni-62

Let me add that Robin has been suggesting something akin to this for some
time, based on Mills instead of the KGS (Klein Gordon state) or DDL and it
could be that any deeply redundant state will suffice.

One detail that reinforces the notion that the Rossi reaction, if  it is
real and based on Ni-62 as the only active species (big if), as stated in
his patent application ... goes direct to Cu-63 via virtual-neutron (proton
addition) is this.

Focardi, who probably contributed heavily to the Rossi hypothesis, had no
doubt noticed that in the isotope tables Ni-63 is unstable, and has a short
half-life AND because it comes from the most stable isotope in the periodic
table - has a beta decay energy which is tiny - only 17.4 keV on average
with no gamma. See it near the bottom of this table:

http://homepages.cae.wisc.edu/~blanchar/purebeta.htm

First off, notice in the table above that there are not many pure beta
emitters, meaning that there is NEVER a gamma, and fewer yet with low
average energy below 20 keV and fewer yet from common electrode metals.
There are only 4-5 good candidates for LENR in this table.

NB This post is not suggesting that an actual beta decay takes place, only a
virtual neutron reaction which is instantaneous and looks like a betas decay
except that the half-life becomes moot. Thus, we only look at the
comparative beta decay energy to get a read on what can, or cannot, be
easily hidden in a reaction that has minimal shielding. IOW - we want to
find candidates with NO gamma and low bremsstrahlung. There are few.

The tiny beta decay energy would be necessary to explain how the reaction
could be robust, compared to chemical, and yet show little external photon
radiation. The Ni-62 - Cu-63 reaction via a VN virtual neutron instead of
a beta decay following a neutron absorption, would still have about 20,000
times more energy than chemical.

Notice also in this table that another good candidate electrode material for
a gamma-less hidden VN reaction based on known beta decay -  is
palladium-107 !

I would add also that a RPF reaction - reversible proton fusion, could
operate only to provide a KGS species - which is a proton bound by an
electron at ~5 keV which in this case makes it a virtual neutron

Yes - this makes things complicated. Very anti-Ockham. So be it.
_

Again - if it is a reality, a deep fractional state, even if
not deriving from Dirac (if you believe Kim) could be an interesting
candidate for the hypothetical virtual neutron ... which would be needed
to make some of these Ni-H hypotheses work. 

If you want to go from Ni-62 which is Rossi's pick of the
litter, directly to Cu-63 (and not Cu-62!) then the DDL or KGS virtual
neutron could do this elegantly, using the close electron for screening. 

If Rossi is correct that Ni-62 is indeed the active species,
then the virtual neutron makes the most sense of anything out there; even if
AR himself missed the critical detail of going direct to Cu-63 instead of
Cu-62.



attachment: winmail.dat

RE: [Vo]:More on a KGS virtual neutron and Ni-62

[Arnaud Kodeck]

Jones,

Ok, I understood. But then what makes the Ni62 special in this case?

Arnaud
_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: dimanche 28 avril 2013 20:56
To: vortex-l@eskimo.com
Subject: RE: [Vo]:More on a KGS virtual neutron and Ni-62

Arnaud,

Yes - that is why I tried to make it clear that a VN or virtual neutron
reaction is not the same as a beta decay (following a real neutron
absorption, which has a half-life). The analogy is being used to assess the
net energy available.

It is hard to make this kind of distinction crystal clear in a forum post,
since the VN reaction can mean different things to different observers and
formerly was tied to an interpretation of CQM theory.

Robin has promoted this particular mechanism for some time, based on the
Mills hydrino at deep redundancy - being a good VN candidate. There are
other candidates including KGS (as a replacement for DDL).

The mechanics of a VN exchange go something like this.

A proton with a very tightly bound electron looks like a neutron to a
Nickel-62 nucleus. It is effectively neutral but with a negative near-field
which is a bonus for the reaction.

When this VN nears the larger nucleus however, the bond to the electron is
broken, but since the electron has effectively shielded the charge of the
proton, for long enough for the strong force of the Ni to see it, we have a
different kind of reaction than if it were a real neutron. Thus the Ni-62
takes the proton only, and the electron is expelled as if it was an
instantaneous beta decay. 

There is no half life with a VN reaction. It is instantaneous and looks like
a proton absorption.

Never mind that there are not many believers in this reaction ... at least
not yet.

_
From: Arnaud Kodeck 

Jones,

It's very interesting theory. Nevertheless, in the web page you
mention here below, it says that Ni63 has a half life of around 100 years (a
century).  I don't think Rossi's device can stay on for that long time.

Arnaud
_
From: Jones Beene 

Let me add that Robin has been suggesting something akin to this for
some time, based on Mills instead of the KGS (Klein Gordon state) or DDL and
it could be that any deeply redundant state will suffice.

One detail that reinforces the notion that the Rossi reaction, if
it is real and based on Ni-62 as the only active species (big if), as
stated in his patent application ... goes direct to Cu-63 via
virtual-neutron (proton addition) is this.

Focardi, who probably contributed heavily to the Rossi hypothesis,
had no doubt noticed that in the isotope tables Ni-63 is unstable, and has a
short half-life AND because it comes from the most stable isotope in the
periodic table - has a beta decay energy which is tiny - only 17.4 keV on
average with no gamma. See it near the bottom of this table:

http://homepages.cae.wisc.edu/~blanchar/purebeta.htm

First off, notice in the table above that there are not many pure
beta emitters, meaning that there is NEVER a gamma, and fewer yet with low
average energy below 20 keV and fewer yet from common electrode metals.
There are only 4-5 good candidates for LENR in this table.

NB This post is not suggesting that an actual beta decay takes
place, only a virtual neutron reaction which is instantaneous and looks like
a betas decay except that the half-life becomes moot. Thus, we only look at
the comparative beta decay energy to get a read on what can, or cannot, be
easily hidden in a reaction that has minimal shielding. IOW - we want to
find candidates with NO gamma and low bremsstrahlung. There are few.

The tiny beta decay energy would be necessary to explain how the
reaction could be robust, compared to chemical, and yet show little external
photon radiation. The Ni-62 - Cu-63 reaction via a VN virtual neutron
instead of a beta decay following a neutron absorption, would still have
about 20,000 times more energy than chemical.

Notice also in this table that another good candidate electrode
material for a gamma-less hidden VN reaction based on known beta decay -  is
palladium-107 !

I would add also that a RPF reaction - reversible proton fusion,
could operate only to provide a KGS species - which is a proton bound by an
electron at ~5 keV which in this case makes it a virtual neutron

Yes - this makes things complicated. Very anti-Ockham. So be it.
_

Again - if it is a reality, a deep fractional state,
even if not deriving from Dirac (if you believe Kim) could be an interesting
candidate for the hypothetical virtual neutron ... which would be needed
to make some of these Ni-H hypotheses work

RE: [Vo]:April 2013 Defkalion GT Interview

[Arnaud Kodeck]

Jones,

Your theory below might explain also what Rossi has told a bit 2 years ago:
Some xRay are absorbed.
Some EM fields are escaping his eCat.

Moreover, in Pedrodragon, Rossi used Nickel, Hydrogen in the Bergius process
(http://en.wikipedia.org/wiki/Bergius_process). Sodium, potassium, and
magnesium were also compounds that were fetching the Bergius reactor.
Similarly Mills uses Sodium or potassium to create the hydrinos.

How the Celani's wire can be fitted into this theory ?

Arnaud
_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: samedi 6 avril 2013 21:29
To: vortex-l@eskimo.com
Subject: RE: [Vo]:April 2013 Defkalion GT Interview

Eric,
Defkalion's description of the reaction is still consistent with
there being copious soft x-rays that arebeing blocked by the housing
of the reactor

Yes - you have probably heard Robin and myself and a few others suggesting
that the EUV spectrum is the most likely source of energetic radiation that
will be seen in any Ni-H reaction which resembles Mills. And all of them do
resemble Mills/BLP - at least AFAIK.

Mills was seeing UV 20 years ago, so it is not new. Some few gammas can
probably be seen when redundancy becomes extreme, but he says that most of
the output is UV. Mills has never reported gammas, it should be noted... but
then again, he has turned a blind eye to anything which is suggestive of a
nuclear explanation.

This UV radiation spectrum is because of the Rydberg energy multiples of
27.2 eV, 54.4 eV, and 108.8 eV etc. which happen in ground state redundancy.
These are in the UV/EUV range, but the upper end of that range can be called
soft x-rays -even if that is misleading, in a way.

Mills claims the energy comes from the electron orbitals of the catalyst
holes. This does not mean that RM got everything right however, and Robin
has already made a few changes of note (on his site) that seem to work
better.

As to applying or integrating Mills to other theories, at least in the
context of the dynamics of redundant orbitals and UV emission, this has been
largely avoided except by Arie de Geus (deceased). There is always room for
compromise however, if one is not tied too closely to either camp. 

In an evolving theory of RPF, it dawns on me just now that it is possible to
merge with a partial Mills explanation... so here goes. First, the reaction
has chemical dynamics which proceed somewhat as Mills suggests, but instead
of the energy coming from loss of electron momentum (angular momentum) the
energy comes directly from mass-to-energy conversion in the proton nucleus
via magnons. In fact, it is the shrinkage of the orbital that provides the
asymmetry which is needed in RPF in order to extract net energy from a
neutral reaction - which can be either endothermic or exothermic in QCD. 

RPF can then be described as providing first the endotherm to allow for the
shrinkage, with then the exotherm is  coming immediately thereafter from
magnon coupling, instead of UV. There could be a bit of both. Hey, I could
almost convince myself that this is a good fit. 

The best evidence for this, and possibly a partial proof, would come from a
finding that there is not nearly enough UV to provide the excess heat which
is seen, and secondly that the heat seen is via inductive coupling
(requiring a ferromagnetic matrix).

Thanks for the segue.

Jones

From: Eric Walker 
Where did you get the idea that soft x-rays were not
harmful? In fact they are deadly, but not instantly deadly, if that makes
them slightly less problematic.
The thought did occur to me after I pressed send that
given a sufficient flux, you could end up cooking yourself before too long.

My remarks about soft x-rays were ambiguous -- I could have
meant that they do not pose safety concerns when shielded by the kind of
housing that a reactor will typically have, or I could have meant that they
are benign in general.  My actual meaning was to suggest that they might be
benign in general (without shielding).  As someone who knows nothing about
nuclear physics, I feel at liberty to make one or two embarrassing comments.
;)
Sterling Allan, whom you quote - is a tireless PR person and
promoter in the PT Barnum tradition - but not a scientist. Even
Hadjichristos, listed as CTO of Defkalion has given no indication of being
literate in several important scientific fields.
My apologies for the confusion -- I didn't intend to offer
Allan or Hadjichristos as authorities.  The quote was meant to provide
another data point and does not give anything to base any conclusions on.
But it is interesting to note that if the quote is half accurate,
Defkalion's description of the reaction is still consistent (?) with there
being copious soft x-rays that are being blocked by the housing of the
reactor.

Eric

RE: [Vo]:April 2013 Defkalion GT Interview

[Arnaud Kodeck]

Rossi could have seen some strange excess heat behavior of its Petrodragon
reactor. Then he decided to look at it a bit more in details (without
especially looking for a LENR reaction). The rubber (which contains a lot of
Sulfur) was a fetch of its Petrodragon reactor. I'm just speculating here.
Did Rossi need a lubricant in the petrodragon reactor? Were there moving
parts?

In a Defkalion presentation, I remember that there was a dashboard in the
background of a picture. In that board, a hexavalent look like molecule was
designed. Could it be H6S? I'm speculating as well here.
_
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: samedi 6 avril 2013 23:08
To: vortex-l@eskimo.com
Subject: RE: [Vo]:April 2013 Defkalion GT Interview

Most interesting. This is a provocative observation that the Petrodragon
reactor used the Bergius process, Arnaud. 

It would be even more interesting if we knew for sure what catalysts
specifically that Rossi was using there. All of the transition metals listed
in the Wiki entry on Bergius are Mills catalysts. 

Molybdenum, in fact, is the closest fit of all transition metals to 27.2
under Mills Theory - when it goes from Mo2+ - Mo3+ (27.13 eV) and the
sulfides would facilitate that ionic transition since they are so reactive
with hydrogen.

For instance, if we knew for sure that Rossi was adding MoS2 - which is a
commonly used catalyst in the petrochemical industry (but better known as a
dry lubricant), then that is strong indication that this particular catalyst
found its way into the E-Cat (along with scrap rubber ??) 

There is a fair chance that Andrea Rossi discovered the heat anomaly first
with the Petrodragon reactor before moving on to a smaller version. I have
never heard this particular suggestion voiced before now, but it makes
sense, no? 

The E-cat is simply a little Petrodragon reactor. LOL. 

That would explain its very crude construction in the first models, and the
large amount of exterior gunk seen on them. If you have ever used molybdenum
disulfide, you know what I am talking about. 

_
From: Arnaud Kodeck 

Jones,

Your theory below might explain also what Rossi has told a bit 2
years ago:
Some xRay are absorbed.
Some EM fields are escaping his eCat.

Moreover, in Pedrodragon, Rossi used Nickel, Hydrogen in the Bergius
process (http://en.wikipedia.org/wiki/Bergius_process). Sodium, potassium,
and magnesium were also compounds that were fetching the Bergius reactor.
Similarly Mills uses Sodium or potassium to create the hydrinos.

How the Celani's wire can be fitted into this theory ?

Arnaud
_
From: Jones Beene 

Eric,
Defkalion's description of the reaction is still consistent
with there being copious soft x-rays that are   being blocked by the housing
of the reactor

Yes - you have probably heard Robin and myself and a few others
suggesting that the EUV spectrum is the most likely source of energetic
radiation that will be seen in any Ni-H reaction which resembles Mills. And
all of them do resemble Mills/BLP - at least AFAIK.

Mills was seeing UV 20 years ago, so it is not new. Some few gammas
can probably be seen when redundancy becomes extreme, but he says that most
of the output is UV. Mills has never reported gammas, it should be noted...
but then again, he has turned a blind eye to anything which is suggestive of
a nuclear explanation.

This UV radiation spectrum is because of the Rydberg energy
multiples of 27.2 eV, 54.4 eV, and 108.8 eV etc. which happen in ground
state redundancy. These are in the UV/EUV range, but the upper end of that
range can be called soft x-rays -even if that is misleading, in a way.

Mills claims the energy comes from the electron orbitals of the
catalyst holes. This does not mean that RM got everything right however,
and Robin has already made a few changes of note (on his site) that seem to
work better.

As to applying or integrating Mills to other theories, at least in
the context of the dynamics of redundant orbitals and UV emission, this has
been largely avoided except by Arie de Geus (deceased). There is always room
for compromise however, if one is not tied too closely to either camp. 

In an evolving theory of RPF, it dawns on me just now that it is
possible to merge with a partial Mills explanation... so here goes. First,
the reaction has chemical dynamics which proceed somewhat as Mills suggests,
but instead of the energy coming from loss of electron momentum (angular
momentum) the energy comes directly from mass-to-energy conversion in the
proton nucleus via magnons. In fact, it is the shrinkage of the orbital
that provides the asymmetry which is needed in RPF in order to extract net
energy from a neutral

RE: [Vo]:thoughts on LENR energy

[Arnaud Kodeck]

Axil,

How can you say that Nickel-48 is stable?

Arnaud

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: jeudi 28 mars 2013 20:11
To: vortex-l@eskimo.com
Subject: Re: [Vo]:thoughts on LENR energy

 

Physics has seven magic numbers. An atom with a magic number of protons or 
neutrons is super stable. 

When both the protons and neutrons are magic, that's a double magic atom. There 
are only seven of them. 

The seven magic numbers are 2, 8, 20, 28, 50, 82, and 126. They are the number 
of nucleons - which can be either protons or neutrons - you need to fill up the 
shells found in the atomic nucleus. The completely filled shells cause the 
atomic nucleus to be more tightly bound together than simple calculations would 
predict, meaning the magic atoms are unusually stable.

So, if both the neutrons and protons happen to be magic numbers, the atom is 
not only extra stable, but its nucleus is also rigidly spherical, which is very 
unusual and helps observers confirm the doubly magic properties of the atom. 

These isotopes - which include helium-4 (2 protons and 2 neutrons, and one of 
the most abundant isotopes in the universe), lead-208 (82 protons and 126 
neutrons, and the heaviest stable atom), and the pair of calcium-48 and 
nickel-48 (the former has 20 protons and 28 neutrons, while the latter is vice 
versa). The latest to be discovered is tin-132, which has 50 protons and 82 
neutrons.

These protons and neutrons form shells as follows

The magic numbers are then
•   2
•   8=2+6
•  20=2+6+12
•  28=2+6+12+8
•  50=2+6+12+8+22
•  82=2+6+12+8+22+32
• 126=2+6+12+8+22+32+44
• 184=2+6+12+8+22+32+44+58


Miley and Hora identified that nuclei undergoing a LENR reaction want to 
stabilize at the highly stable double magic number configuration.

This is because neutrons want to be paired with protons to form a spherical 
nucleus with perfectly shaped shells.
.

Elements with lots of unpaired neutrons like Th232 and U238 would make for 
great LENR metals. These metals would stabilize at lead 208.

Some nuclides are double-magic, in that the number of protons and neutrons are 
both magic, such as helium-4, oxygen-16, calcium-40, calcium-48, nickel-48, and 
lead-208. These isotopes are particularly stable and this is where LENR wants 
to go. 

Hora who is Miley’s collaborator, makes a convincing case that the nucleus 
conforms to a R (n) (n = 1, 2, 3…) of the Boltzmann probabilities, namely R (n) 
= 3n. This suggests a threefold property of stable configurations at magic 
numbers in Nuclei, consistent with a quark property.

Now, we can use this nuclear engineering background to predict what the LENR 
ash content will look like.


In LENR two concurrent processes are occurring simultaneously: fusion and 
fission.

The strength of these two reactions will reflect the amount of screening that 
the reactor can produce.

Elements built up by the fusion process will be subsequently disassembled by a 
fission process.

But you can expect to see proton magic number elements like helium, calcium, 
oxygen, nickel, tin and lead appear in the LENR ash because they are proton 
magic number elements.

Also, you can expect to see Neutron magic number isotopes favored in LENR.

It is a well-known fact that screening can increase the radiation levels of 
alpha emitters.


When screening intensity is increased, it is reasonable to expect that other 
light elements besides Helium(Z=2) will be expelled(aka fission) from the 
nucleus. 

These are Lithium(Z=3) , Beryllium(Z=4), and Boron(Z=5).

Also intermediate elements will form that result from the emissions of these 
light elements like iron, chromium vanadium, titanium, and scandium.

Sulfur(Z=16) will form from the beryllium(Z=4) emission from calcium(Z=20). 



On Thu, Mar 28, 2013 at 9:52 AM, DJ Cravens djcrav...@hotmail.com wrote:


 

  _  

Date: Wed, 27 Mar 2013 22:21:44 -0400
From: janap...@gmail.com
To: vortex-l@eskimo.com
Subject: [Vo]:thoughts on LENR energy


 
In LENR, the delicate balance within the nucleus between nuclear attraction and 
the electrical repulsion between protons is disturbed in the opposite fashion.

In the light of LENR fusion, a nucleus with many unbalanced neutrons like Ni64 
will be elongated and energetic due to asymmetry neutron energy.


 

 

cheers:   axil
 
---
 
You may want to check George Miley's analysis in: Miley, G.H., Name, G., 
Williams, M.J., Patterson, J.A., Nix, J., Cravens, D., and Hora, H. 1996,. 
“Quantitative Observation of Transmutation Products Occurring in Thin-Film 
Coated Microscopheres During. Electrolysis,” Progress in New hydrogen, pp. 
629-644, ( 1997). 36.   
you can find a good clear graph of products here:
http://www.alienscientist.com/forum/showthread.php?699-Ni-H2-ECat-Project/page33
 
The thing that you said that I notice is the elongated nuclei.I remember 
looking at George's graph upside down - not to see products but to see what 
could be fuel and noticed 

RE: [Vo]:thoughts on LENR energy

[Arnaud Kodeck]

Look at the url :  http://www.highbeam.com/doc/1G1-57799535.html 
http://www.highbeam.com/doc/1G1-57799535.html

 

Not sure you can find it at the corner of the street.

 

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: jeudi 28 mars 2013 21:57
To: vortex-l@eskimo.com
Subject: Re: [Vo]:thoughts on LENR energy

 

I saw it on the internet, but maybe it is not true.

Maybe you need to have the number of neutrons equal or exceed the number of 
protons for the element to be stable.

In Ni48 there are only 20 neutrons. That might not be so good.



On Thu, Mar 28, 2013 at 4:36 PM, Arnaud Kodeck arnaud.kod...@lakoco.be wrote:

Axil,

How can you say that Nickel-48 is stable?

Arnaud

  _  

From: Axil Axil [mailto:janap...@gmail.com] 
Sent: jeudi 28 mars 2013 20:11
To: vortex-l@eskimo.com
Subject: Re: [Vo]:thoughts on LENR energy

 

Physics has seven magic numbers. An atom with a magic number of protons or 
neutrons is super stable. 

When both the protons and neutrons are magic, that's a double magic atom. There 
are only seven of them. 

The seven magic numbers are 2, 8, 20, 28, 50, 82, and 126. They are the number 
of nucleons - which can be either protons or neutrons - you need to fill up the 
shells found in the atomic nucleus. The completely filled shells cause the 
atomic nucleus to be more tightly bound together than simple calculations would 
predict, meaning the magic atoms are unusually stable.

So, if both the neutrons and protons happen to be magic numbers, the atom is 
not only extra stable, but its nucleus is also rigidly spherical, which is very 
unusual and helps observers confirm the doubly magic properties of the atom. 

These isotopes - which include helium-4 (2 protons and 2 neutrons, and one of 
the most abundant isotopes in the universe), lead-208 (82 protons and 126 
neutrons, and the heaviest stable atom), and the pair of calcium-48 and 
nickel-48 (the former has 20 protons and 28 neutrons, while the latter is vice 
versa). The latest to be discovered is tin-132, which has 50 protons and 82 
neutrons.

These protons and neutrons form shells as follows

The magic numbers are then
•   2
•   8=2+6
•  20=2+6+12
•  28=2+6+12+8
•  50=2+6+12+8+22
•  82=2+6+12+8+22+32
• 126=2+6+12+8+22+32+44
• 184=2+6+12+8+22+32+44+58


Miley and Hora identified that nuclei undergoing a LENR reaction want to 
stabilize at the highly stable double magic number configuration.

This is because neutrons want to be paired with protons to form a spherical 
nucleus with perfectly shaped shells.
.

Elements with lots of unpaired neutrons like Th232 and U238 would make for 
great LENR metals. These metals would stabilize at lead 208.

Some nuclides are double-magic, in that the number of protons and neutrons are 
both magic, such as helium-4, oxygen-16, calcium-40, calcium-48, nickel-48, and 
lead-208. These isotopes are particularly stable and this is where LENR wants 
to go. 

Hora who is Miley’s collaborator, makes a convincing case that the nucleus 
conforms to a R (n) (n = 1, 2, 3…) of the Boltzmann probabilities, namely R (n) 
= 3n. This suggests a threefold property of stable configurations at magic 
numbers in Nuclei, consistent with a quark property.

Now, we can use this nuclear engineering background to predict what the LENR 
ash content will look like.


In LENR two concurrent processes are occurring simultaneously: fusion and 
fission.

The strength of these two reactions will reflect the amount of screening that 
the reactor can produce.

Elements built up by the fusion process will be subsequently disassembled by a 
fission process.

But you can expect to see proton magic number elements like helium, calcium, 
oxygen, nickel, tin and lead appear in the LENR ash because they are proton 
magic number elements.

Also, you can expect to see Neutron magic number isotopes favored in LENR.

It is a well-known fact that screening can increase the radiation levels of 
alpha emitters.


When screening intensity is increased, it is reasonable to expect that other 
light elements besides Helium(Z=2) will be expelled(aka fission) from the 
nucleus. 

These are Lithium(Z=3) , Beryllium(Z=4), and Boron(Z=5).

Also intermediate elements will form that result from the emissions of these 
light elements like iron, chromium vanadium, titanium, and scandium.

Sulfur(Z=16) will form from the beryllium(Z=4) emission from calcium(Z=20). 

On Thu, Mar 28, 2013 at 9:52 AM, DJ Cravens djcrav...@hotmail.com wrote:


 

  _  

Date: Wed, 27 Mar 2013 22:21:44 -0400
From: janap...@gmail.com
To: vortex-l@eskimo.com
Subject: [Vo]:thoughts on LENR energy


 
In LENR, the delicate balance within the nucleus between nuclear attraction and 
the electrical repulsion between protons is disturbed in the opposite fashion.

In the light of LENR fusion, a nucleus with many unbalanced neutrons like Ni64 
will be elongated and energetic due to asymmetry neutron energy.


 

 

cheers:   axil

RE: [Vo]:Android Controlled Spark Plug Driver: Universal LENR Reactor

[Arnaud Kodeck]

There is nothing special here. Every gasoline car engine has it. Or am I
missing something?

 

In 5 min googling, I find this
http://christian.liljedahl.dk/guides/arduino-spark-plug

 

This circuit is far more reliable.

  _  

From: Jack Cole [mailto:jcol...@gmail.com] 
Sent: mardi 26 mars 2013 11:18
To: vortex-l@eskimo.com
Subject: [Vo]:Android Controlled Spark Plug Driver: Universal LENR Reactor

 

The following may be of interest to some interested in LENR and hobbyist
science.

 

http://www.lenr-coldfusion.com/2013/03/26/android-controlled-spark-plug-driv
er-universal-lenr-reactor/

Re: [Vo]:Android Controlled Spark Plug Driver: Universal LENR Reactor

[arnaud . kodeck]

If you are afraid of back surges from coil. Use a fast diode (This  
free wheel diode should be present anyway). If it is still not enough,  
you might consider also to have 2 distinct power supplies: One for the  
control and one for the high voltage galvanic protected. Mosfet  
intrinsically gives a very good protection from its gate. Normally a  
driver of the gate should be used to insure fast loading/deloading of  
the mosfet's gate.

Arnaud

Quoting Jack Cole jcol...@gmail.com:


Arnaud,

Thanks for your feedback.  I have seen the page you are referring to
before.  I would be hesitant to use the circuit outlined in that as it
would seem likely to allow back surges that would damage the controller.

I'm certainly not claiming anything groundbreaking here.  It is just a
piece of the puzzle for a control system.

Best regards,
Jack



On Tue, Mar 26, 2013 at 5:49 AM, Arnaud Kodeck  
arnaud.kod...@lakoco.bewrote:



**

There is nothing special here. Every gasoline car engine has it. Or am I
missing something?

** **

In 5 min googling, I find this
http://christian.liljedahl.dk/guides/arduino-spark-plug

** **

This circuit is far more reliable.
  --

*From:* Jack Cole [mailto:jcol...@gmail.com]
*Sent:* mardi 26 mars 2013 11:18
*To:* **vortex-l@eskimo.com**
*Subject:* [Vo]:Android Controlled Spark Plug Driver: Universal LENR
Reactor

** **

The following may be of interest to some interested in LENR and hobbyist
science.

** **


http://www.lenr-coldfusion.com/2013/03/26/android-controlled-spark-plug-driver-universal-lenr-reactor/

Re: [Vo]:Rossi says third party tests concluded

[Arnaud Kodeck]

What could mean a 2 stages eCat ?

Is Rossi able to make different flavors of its magical powder ?
   One powder with low temp start but with slow kinetic (Low kW),  
called by Rossi the mouse
   One powder with high temp start but with fast kinetic (High kW),  
called by Rossi the cat


This will allow better COP without loosing too much of control.

Quoting Jed Rothwell jedrothw...@gmail.com:


Rossi wrote:




   1.  Andrea Rossi
March 25th, 2013 at 8:13  
PMhttp://www.journal-of-nuclear-physics.com/?p=791cpage=4#comment-664056


   Dear Robert Tanhaus:
   1- no, we revolutioned the technology separating the activation from
   the E-Cat, making 2 separated apparatuses in the same house: * mouse (
   activator) and Cat. *This has enhanced the efficiency of the E-Cat. *Has
   been an idea I got during a night of fever and asma attack… I couldn’t
   sleep, it worked.
   2- He is helping manufacturing the plants
   Warm Regards,
   A.R.

* House here means chamber, or reaction vessel.


Here is the question from Tanhaus:

Dear Andrea Rossi,

Wonderful!!

I have two questions.
1. Was the Hot Cat in Pordenone of the same model as the Hot Cats in the
3rd party test now?
2. Did your “new” partner helped you a lot designing these two stage
reactors?

Thank you,
Robert Tanhaus



- Jed

RE: EXTERNAL: Re: [Vo]:Rossi says third party tests concluded

[Arnaud Kodeck]

Rossi uses electrical heating inside its eCats for controlling purpose. He
needs to be sure that the energy produced by LENR reaction inside the eCat
is below the maximum output possible (The coolant). Otherwise, the control
of the reaction will be lost and powder will overheat. If it's happen, the
powder looses its magic and the powder becomes LENR inert. Rossi stayed that
a lot of times.

The way of Rossi has presented the mouse/cat configuration let me think that
there are 2 distinguished parts inside the vessel. I'm not convinced that
Rossi controls subtlety each NAE.
Arnaud
 -Original Message-
 From: Roarty, Francis X [mailto:francis.x.roa...@lmco.com]
 Sent: mardi 26 mars 2013 15:47
 To: vortex-l@eskimo.com
 Subject: RE: EXTERNAL: Re: [Vo]:Rossi says third party tests concluded
 
 Arnaud,
 He might be zeroing in on a method to prevent the self destruction but
 still get the larger COP..perhaps a thin layer of activated NAE needs to
 be surrounded by a lesser or non activated region that can still continue
 to process the plasma ignited by the mouse ... I suspect many of the
 repeatability issues are due to a self destructive geometry that wears
 faster with output levels.
 Fran
 
 -Original Message-
 From: Arnaud Kodeck [mailto:arnaud.kod...@lakoco.be]
 Sent: Tuesday, March 26, 2013 9:41 AM
 To: vortex-l@eskimo.com
 Subject: EXTERNAL: Re: [Vo]:Rossi says third party tests concluded
 
 What could mean a 2 stages eCat ?
 
 Is Rossi able to make different flavors of its magical powder ?
 One powder with low temp start but with slow kinetic (Low kW),
 called by Rossi the mouse
 One powder with high temp start but with fast kinetic (High kW),
 called by Rossi the cat
 
 This will allow better COP without loosing too much of control.
 
 Quoting Jed Rothwell jedrothw...@gmail.com:
 
  Rossi wrote:
 
 
 
 1.  Andrea Rossi
  March 25th, 2013 at 8:13
  PMhttp://www.journal-of-nuclear-physics.com/?p=791cpage=4#comment-
 664056
 
 Dear Robert Tanhaus:
 1- no, we revolutioned the technology separating the activation from
 the E-Cat, making 2 separated apparatuses in the same house: * mouse
 (
 activator) and Cat. *This has enhanced the efficiency of the E-Cat.
 *Has
 been an idea I got during a night of fever and asma attack. I
 couldn't
 sleep, it worked.
 2- He is helping manufacturing the plants
 Warm Regards,
 A.R.
 
  * House here means chamber, or reaction vessel.
 
  Here is the question from Tanhaus:
 
  Dear Andrea Rossi,
 
  Wonderful!!
 
  I have two questions.
  1. Was the Hot Cat in Pordenone of the same model as the Hot Cats in the
  3rd party test now?
  2. Did your new partner helped you a lot designing these two stage
  reactors?
 
  Thank you,
  Robert Tanhaus
 
 
 
  - Jed
 
 

RE: [Vo]:Nokia developing phone that recharges itself without mains electricity

[Arnaud Kodeck]

50Hz antenna will make the phone very huge ...

 
 If they extended the range to below 50Hz, they could pick up the stray
 field
 from the grid, which is much larger than the RF transmissions they are
 harvesting now. Since most of this would be harvested indoors, it would
 automatically be charged to the users account anyway. (Although it would
 only be
 worth a fraction of a cent.)
 
 Regards,
 
 Robin van Spaandonk
 
 http://rvanspaa.freehostia.com/project.html

RE: [Vo]:Re: CMNS: only a perfect LENR theory should attack other theories

[Arnaud Kodeck]

Eric,

 

Says that slow neutron is produced and absorbed by atoms in a LENR device.
In the order of 6.24E11 neutron captures per second for 1W, as you said,
some atoms which have received an absorbed neutron will become radioactive,
emitting gamma. Example: 58Ni + n - 59Ni - 59Co + e+. We should easily
detect e- + e+ = 2 gammas 511KeV with a 100$ Geiger counter. Anyway, it is
not good to play around such a reactor in those conditions.

 

Arnaud

  _  

From: Eric Walker [mailto:eric.wal...@gmail.com] 
Sent: vendredi 22 mars 2013 09:35
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Re: CMNS: only a perfect LENR theory should attack other
theories

 

Lou,

 

If LENR neutrons are indeed generated as proposed by W-L, almost all will
be in the thermal range - quite a low momentum by fusion standards.

 

They speak about ultra low momentum neutrons, which I think is
significantly lower than thermal energies.  These would then collide with
nickel substrate atoms in inelastic and elastic collisions as well as be
absorbed.  The highest absorption cross sections in the graphs you point to
for nickel are ~1000 for 63Ni and ~1 for 59Ni.  63Ni is only synthetic,
and 59Ni exists only in trace quantities, so in general the absorption cross
section for unenriched nickel will be lower than these.  According to the
charts, the cross section for 58Ni, the most common isotope (68 percent), is
~100 barns, and that for 60Ni (26 percent) is ~50 barns.  So I think you
would take the weighted average of these to get an upper bound on the
absorption cross section of a block of normal nickel; e.g., 100 * .68 + 50 *
.26 = 81 barns. That would be the upper bound, I think, neglecting other
isotopes that exist in small amounts.

 

I looked, and it is difficult to pin down exactly how to calculate the half
value layer (the amount of material needed to decrease the intensity of an
incident neutron beam by half) starting from the microscopic total cross
section. Here we have the absorption cross section rather than the total
cross section.  The other two relevant cross sections -- elastic and
inelastic -- are going to bounce our neutrons around and then out of the
system, so I wonder if they can be neglected.  It seems that shielding
thickness is something that is experimentally determined and not calculated
analytically so much, although perhaps Robin or someone else can help us out
with a calculation.

 

An absorption cross section of 81 is not perfect.  It is not hard to imagine
that some neutrons would get through.  To get a sense of how many neutrons
we're talking about, consider the number needed to produce by 1 W of power
production through absorption into nickel.  The upper bound on the amount of
energy that will be provided by a single Ni(n,*) reaction will be around 10
MeV, if I've done my calculation right.  For 1W power, 1J of energy is
produced during one 1s.  To get 1J energy, at you need

 

  6.24150974E12 MeV / 10 MeV = 6.24E11 neutron captures per second.

 

The trick is to figure out how efficient 81 barns is at stopping that kind
of flux.  If even 0.1 percent of the neutrons escape, that's 624 million
neutrons escaping from the system per second.  I assume that is a lot, and
that that would set off a GM counter.  If this is correct, the question
becomes whether 81 barns is going to stop a lot more than 99.9 percent of
the neutrons being generated and captured.

 

Also bear in mind that there is a saturation that occurs, where the nickel
cannot be further activated, after which it starts to transmit neutrons.  At
that point I think they would need to be absorbed by other isotopes that
have evolved lest they escape in large numbers.

 

Eric

 

RE: [Vo]:Re: CMNS: only a perfect LENR theory should attack other theories

[Arnaud Kodeck]

Jed,

 

For cell phone the maximum power from the mobile is given by the equilibrium
between Uplink (Handset - base station) and Downlink (Base station -
Handset). Hopefully, base stations have a better maximum power and also a
better sensitivity for the receive path (around -110 dBm). The mobile
sensitivity for the best one is -102 dBm.

 

At the beginning of a call, the mobile is emitting at full power. Then the
power is decreased over time if reception conditions are good at base
station. The goal is to reduce interferences with other mobiles and safe the
batteries. At the norm establishment (end 80s, early 90s) there was no
health consideration.

 

For GSM 2G 900Mhz Band, the maximum power is 2W (33 dBm)

For GSM 2G 1800Mhz Band, the maximum power is 1W (30 dBm)

For 3G, the maximum limit is 1W (not sure but around 1W)

For CDMA and PCS (used in USA), the powers are in the same value range.

 

For LENR point of view, if we want to make cell phone powered by LENR, there
is no need to have a 2W LENR power device because:

In call, the power is decreased over time.

In standby mode (no call), consumption is very low.

 

The best should have a battery charged by small LENR device of tenth of mW
electric. Battery would be charged when the mobile is in standby mode (no
call). Even with an efficiency of 5% to convert heat to electricity, only a
0.5W heat LENR device is far enough. 0.5W can be dissipated easily out of
the cell phone.

 

More generally, all nomad devices have a low power profile. They do not need
for the generation of supercondensateurs for example, but LENR well.

 

Arnaud

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: jeudi 21 mars 2013 19:57
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Re: CMNS: only a perfect LENR theory should attack other
theories

 

I wrote:

 

A 10 mW heat source may well be commercial in 20 years. It would be enough
to drive a cell phone.

 

Oops. No, it would take more like 12 W, I think. 3 W is the most a cell
phone is allowed to produce, for health safety reasons. I suppose you could
trickle charge the thing with a fraction of 1 W, but then it might run out
of power in the middle of a long conversation.

 

A 12 W thermoelectric heat source in a cell phone would make the phone too
hot to hold. I guess some sort of trickle charging would be needed.

 

I am having trouble finding the power consumption of a modern cell phone. It
has fallen considerably in recent years.

 

Here is a table of commonly used machines:

 

http://www.wholesalesolar.com/StartHere/HowtoSaveEnergy/PowerTable.html

 

Most are below the 1.5 kW limit.

 

- Jed

 

RE: [Vo]:Re: CMNS: only a perfect LENR theory should attack other theories

[Arnaud Kodeck]

If the LENR mobile is coupled with a battery, then the battery will act as
the main power supply when mobile is in call state. LENR power station
should be seen here only has an embedded charger. In this condition, for the
majority of the users, continuous tenth of mW is enough.

 

In current available mobiles, it is not possible to have continuous call at
2W for a long period of time before batteries get empty. Nothing new for
LENR here, because the majority of people are not ready to pay more to be
able to call at 2W power 24h/24h.

 

I'm not sure we want to have 10W heat power in our pockets. Fire hazards due
to high temperature are here a main issue. This is against a mobile without
battery.

 

  _  

From: Jed Rothwell [mailto:jedrothw...@gmail.com] 
Sent: jeudi 21 mars 2013 23:00
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Re: CMNS: only a perfect LENR theory should attack other
theories

 

Arnaud Kodeck arnaud.kod...@lakoco.be wrote:

 

At the beginning of a call, the mobile is emitting at full power. Then the
power is decreased over time if reception conditions are good at base
station.

. . .

 For GSM 2G 900Mhz Band, the maximum power is 2W (33 dBm)

For GSM 2G 1800Mhz Band, the maximum power is 1W (30 dBm)

 

Very interesting! Thanks for the info.

 

Still, I think that means that if you are in a bad location you will need
continuous power of 2 W. Therefore with a thermoelectric device if you want
to stay connected indefinitely, you would need enough heat to keep producing
2 W continuously. I can imagine a situation like this when someone is caught
in the wilderness or trapped in a building in an earthquake.

 

I do not think thermoelectric power conversion efficiency will remain at
only 5%. I presume it will be something more like 20% by the time this
technology matures. So, to get 2 W electricity you will need ~10 Watts
thermal.

 

Perhaps the cell phone cold fusion device could produce 10 W only in an
emergency and normally it would produce much less, to keep the handset from
getting hot.

 

You might also want a burst of high power when the cell phone is used as a
flashlight, with the screen continually at the brightest setting. Again,
this might be useful in an emergency. As I said, for someone lost in the
woods or trapped in a collapsed building in an earthquake.

 

- Jed

 

RE: [Vo]:Speculation on Rossi from OILPRICE.com

[Arnaud Kodeck]

This article from Oilprice.com is a really good bullshit. It will take ages
before LENR will have an impact on oil prices, and therefore on energy
prices. Big banks, and big oil companies will have (or already have) a
strong fight against LENR. But surely it will not be like it's explained in
the article.

With 10 GW or even 100 GW of LENR energy available, the energy prices might
start to be slightly affected. For comparison, 100 GW is a little more than
what France has of electrical power installed. Suppose Rossi and others
start to produce LENR reactors, how long will it take to have 10 GW of LENR
energy available? 3~4 years at least, guess from my thumb.

We can keep our oil company share ;-)

RE: [Vo]:Speculation on Rossi from OILPRICE.com

[Arnaud Kodeck]

I don't understand what you exactly mean here? I'm aware of the new
robotization revolution (Baxter robot, and the same arm multi purposes
robots ...), but anyway, you can't change the all economy in a few winks.

Moreover, in the beginning, there will have a huge fight against LENR by
lobbyists before it could be mass market. Let just hope than we will be
fester than the east Asian in this run.

From: James Bowery [mailto:jabow...@gmail.com] 
Sent: vendredi 8 mars 2013 22:29
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Speculation on Rossi from OILPRICE.com

You're one minor and one major industrial revolution behind in this
analysis:

Minor:  The emergence of the east Asian giants has already fundamentally
changed the political economics of technology deployment.  They are much
less encumbered  than is the West and much more motivated to apply their
manufacturing flexibility.  This is like a combination of the Nazi economic
miracle and the post-war German economic miracle.

Major:  Click on The Makers Revolution
On Fri, Mar 8, 2013 at 3:19 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:
This article from Oilprice.com is a really good bullshit. It will take ages
before LENR will have an impact on oil prices, and therefore on energy
prices

RE: [Vo]:Speculation on Rossi from OILPRICE.com

[Arnaud Kodeck]

I did! Thank you for it. Nothing special I'm aware of.

 

Do you belief than LENR will change the energy market in less than 3 years?

 

  _  

From: James Bowery [mailto:jabow...@gmail.com] 
Sent: samedi 9 mars 2013 01:01
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Speculation on Rossi from OILPRICE.com

 

You didn't click through the link and watch the presentation by Anderson.

 

Do so.

On Fri, Mar 8, 2013 at 5:11 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:

I don't understand what you exactly mean here? I'm aware of the new
robotization revolution (Baxter robot, and the same arm multi purposes
robots ...), but anyway, you can't change the all economy in a few winks.

Moreover, in the beginning, there will have a huge fight against LENR by
lobbyists before it could be mass market. Let just hope than we will be
fester than the east Asian in this run.

From: James Bowery [mailto:jabow...@gmail.com]
Sent: vendredi 8 mars 2013 22:29
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Speculation on Rossi from OILPRICE.com


You're one minor and one major industrial revolution behind in this
analysis:

Minor:  The emergence of the east Asian giants has already fundamentally
changed the political economics of technology deployment.  They are much
less encumbered  than is the West and much more motivated to apply their
manufacturing flexibility.  This is like a combination of the Nazi economic
miracle and the post-war German economic miracle.

Major:  Click on The Makers Revolution
On Fri, Mar 8, 2013 at 3:19 PM, Arnaud Kodeck arnaud.kod...@lakoco.be
wrote:
This article from Oilprice.com is a really good bullshit. It will take ages
before LENR will have an impact on oil prices, and therefore on energy
prices

 

RE: [Vo]:Interesting graph of daily power generation in Germany, May 2012

[Arnaud Kodeck]

German decided to shutdown nuclear power plant well before Fukushima
disaster. Siemens has sold its nuclear department to the French. Fukushima
just convinced finally without doubt about nuclear fission energy.

 

With all those PV cells all around Germany and Benelux houses just make
sunny Sunday the nightmare of electricity grid managers. In those hot and
sunny Sunday, there is a lot of electricity available, but no one to buy it.

 

To compensate the PV cells (and also for the wind) when the weather is
cloudy or not windy, they are burning tons of lignite which is worst than
coal regarding pollution.

 

The picture isn't as nice in Germany as we could see at a first glance.

 

Arnaud