Re: [Vo]:Isotope separation technology can be improved

2013-05-28 Thread Harry Veeder
On Mon, May 27, 2013 at 10:11 AM, Edmund Storms stor...@ix.netcom.comwrote:


 On May 27, 2013, at 12:17 AM, Harry Veeder wrote:



 On Sat, May 25, 2013 at 10:30 AM, Edmund Storms stor...@ix.netcom.comwrote:


 On May 24, 2013, at 10:38 PM, Harry Veeder wrote:




 The process you have described has the characteristics of
 a ratchet. Curiously, Jones used the ratchet metaphor in another post where
 he characterised the effect of modulating the input on the cell.


 Yes Harry, this can be called a ratchet. All kinds of ratchets exist in
 Nature. The challenge is to find the cause. In this case, the nuclei have
 to communicate before they have fused into a single nuclei.  The form of
 htat communication is unknown, but very important. Once discovered, this
 will get someone the Nobel prize.

 Imagine the following sequence. The nuclei are held apart by an electron
 bond, which is normally the case. Once formed, this structure starts to
 resonate so that the two nuclei get periodically closer together.  As they
 approach each other, information is exchanged between the nuclei that tells
 them they have too much mass -energy for being this close. After all, if
 they were in contact, the excess mass-energy would be 24 MeV if the nuclei
 were deuterons. But they are not in contact yet, so that the excess
 mass-energy is less than the maximum. Nevertheless, this excess must be
 dissipated, which each nuclei does by emitting a photon having 1/2 of the
 excess energy for the distance achieved. After the photons are emitted, the
 resonance moves the two nuclei apart, but this time not as far as
 previously the case. The next resonance cycle again brings the nuclei
 close, but this time they come closer than before, again with emission of
 two photons. This cycle repeats until all energy has been dissipated and
 the two nuclei are in contact. The intervening electron, that was necessary
 to the process, is sucked into the final nucleus. Because very little
 energy is released by entry of the electron, the neutrino, if it is emitted
 at all, has very little energy available to carry away.

 This process, I suggest, is the unique and previously unknown phenomenon
 that CF has revealed.




 Ed,
 Typically we associate quantization with attractive forces as is the case
 with an electron and a proton in a hydrogen atom, but your system involves
 quantization with repulsive forces.


 Like charges repel and unlike charges attract. Quantization is always a
 balance between attraction and repulsion. Consequently, I do not understand
 your point.



In a hydrogen atom quantisation is present but there is only the attraction
between unlike charges, i.e. a electron and a proton. So as a general rule
quantisation does not require a balance between attraction and repulsion.



 Resonance occurs when an object can alternate between between attraction
 and repulsion. This combination results in forces that can  move an object
 between these two extremes as long as energy is supplied.


Yes, but the attractive forces are the bonds between the Pd or Ni atoms and
the repulsive forces between the hydrogen nuclei and the Pd or Ni nuclei.
The bonds between the atoms allow the big nuclei to coral hydrogen nuclei
by mutual repulsion. The presence of an electron inside the coral acts
a site of least repulsion where hydrogen nuclei are most likely to
converge as they are gradually brought together through emission of a
photon and resonance with the surrounding web of big nuclei.






 If pushing an electron and proton apart can happen in steps through the
 absorption of photons, I guess it follows that pushing together of
 protons can happen in steps through the emission of photons.


 Your description is not correct. Photon emission only occurs when the
 electron RETURNS to its original energy level.


I said If pushing an electron and proton apart can happen in steps through
the *absorption* of photons, I guess it follows that pushing together of
protons can happen in steps through the emission of photons.



 I'm not suggesting the electron has an role in emitting a photon. I'm
 proposing that a photon is emitted FROM THE NUCLEUS when two nuclei get too
 close to each other. Nuclei can not normally get this close. Consequently,
 the process is not normally possible.  The conditions in the NAE make this
 possible.


I think the electron does play a role. It serves to discharge a build of a
quantum of electrostatic energy that exists between the nuclei. Since the
state of repulsion is quantized the nuclei stay at that distance until the
next vibration from the matrix pushes them closer together.




  However, in the former situation the pushing apart is the effect but
 the absorption of the photons is the cause, whereas in the latter situation
 the pushing together is the cause, and the emission of photons is
 effector is it? ;-)


 The protons try to get close, but this is not possible because of the
 Coulomb barrier. 

Re: [Vo]:Isotope separation technology can be improved

2013-05-27 Thread Harry Veeder
On Sat, May 25, 2013 at 10:30 AM, Edmund Storms stor...@ix.netcom.comwrote:


 On May 24, 2013, at 10:38 PM, Harry Veeder wrote:




 The process you have described has the characteristics of
 a ratchet. Curiously, Jones used the ratchet metaphor in another post where
 he characterised the effect of modulating the input on the cell.


 Yes Harry, this can be called a ratchet. All kinds of ratchets exist in
 Nature. The challenge is to find the cause. In this case, the nuclei have
 to communicate before they have fused into a single nuclei.  The form of
 htat communication is unknown, but very important. Once discovered, this
 will get someone the Nobel prize.

 Imagine the following sequence. The nuclei are held apart by an electron
 bond, which is normally the case. Once formed, this structure starts to
 resonate so that the two nuclei get periodically closer together.  As they
 approach each other, information is exchanged between the nuclei that tells
 them they have too much mass -energy for being this close. After all, if
 they were in contact, the excess mass-energy would be 24 MeV if the nuclei
 were deuterons. But they are not in contact yet, so that the excess
 mass-energy is less than the maximum. Nevertheless, this excess must be
 dissipated, which each nuclei does by emitting a photon having 1/2 of the
 excess energy for the distance achieved. After the photons are emitted, the
 resonance moves the two nuclei apart, but this time not as far as
 previously the case. The next resonance cycle again brings the nuclei
 close, but this time they come closer than before, again with emission of
 two photons. This cycle repeats until all energy has been dissipated and
 the two nuclei are in contact. The intervening electron, that was necessary
 to the process, is sucked into the final nucleus. Because very little
 energy is released by entry of the electron, the neutrino, if it is emitted
 at all, has very little energy available to carry away.

 This process, I suggest, is the unique and previously unknown phenomenon
 that CF has revealed.




Ed,
Typically we associate quantization with attractive forces as is the case
with an electron and a proton in a hydrogen atom, but your system involves
quantization with repulsive forces.

If pushing an electron and proton apart can happen in steps through the
absorption of photons, I guess it follows that pushing together of
protons can happen in steps through the emission of photons. However, in
the former situation the pushing apart is the effect but the absorption
of the photons is the cause, whereas in the latter situation the pushing
together is the cause, and the emission of photons is effector is it?
;-)

If it is the cause, then the emission of photons serves to pull the protons
together.

Harry
PS. Wikipedia says the fractional quantum hall effect  also involves
quantized states of repulsion although they are between electrons rather
than protons and deuterons.


Re: [Vo]:Isotope separation technology can be improved

2013-05-27 Thread Andrew
Quantum mechanics governs both attraction and repulsion between charges. Ax far 
as the maths is concerned, it's just a sign change. If you come at this as an 
interaction characterised by exchange of quanta, then (via a momentum model) 
only repulsion makes intuitive sense. But that's OK - QM is nothing if not 
unintuitive.

Andrew
  - Original Message - 
  From: Harry Veeder 
  To: vortex-l@eskimo.com 
  Sent: Sunday, May 26, 2013 11:17 PM
  Subject: Re: [Vo]:Isotope separation technology can be improved





  On Sat, May 25, 2013 at 10:30 AM, Edmund Storms stor...@ix.netcom.com wrote:



On May 24, 2013, at 10:38 PM, Harry Veeder wrote:





  The process you have described has the characteristics of a ratchet. 
Curiously, Jones used the ratchet metaphor in another post where he 
characterised the effect of modulating the input on the cell.



Yes Harry, this can be called a ratchet. All kinds of ratchets exist in 
Nature. The challenge is to find the cause. In this case, the nuclei have to 
communicate before they have fused into a single nuclei.  The form of htat 
communication is unknown, but very important. Once discovered, this will get 
someone the Nobel prize. 


Imagine the following sequence. The nuclei are held apart by an electron 
bond, which is normally the case. Once formed, this structure starts to 
resonate so that the two nuclei get periodically closer together.  As they 
approach each other, information is exchanged between the nuclei that tells 
them they have too much mass -energy for being this close. After all, if they 
were in contact, the excess mass-energy would be 24 MeV if the nuclei were 
deuterons. But they are not in contact yet, so that the excess mass-energy is 
less than the maximum. Nevertheless, this excess must be dissipated, which each 
nuclei does by emitting a photon having 1/2 of the excess energy for the 
distance achieved. After the photons are emitted, the resonance moves the two 
nuclei apart, but this time not as far as previously the case. The next 
resonance cycle again brings the nuclei close, but this time they come closer 
than before, again with emission of two photons. This cycle repeats until all 
energy has been dissipated and the two nuclei are in contact. The intervening 
electron, that was necessary to the process, is sucked into the final nucleus. 
Because very little energy is released by entry of the electron, the neutrino, 
if it is emitted at all, has very little energy available to carry away.


This process, I suggest, is the unique and previously unknown phenomenon 
that CF has revealed. 



  Ed, 
  Typically we associate quantization with attractive forces as is the case 
with an electron and a proton in a hydrogen atom, but your system involves 
quantization with repulsive forces. 

  If pushing an electron and proton apart can happen in steps through the 
absorption of photons, I guess it follows that pushing together of protons can 
happen in steps through the emission of photons. However, in the former 
situation the pushing apart is the effect but the absorption of the photons 
is the cause, whereas in the latter situation the pushing together is the 
cause, and the emission of photons is effector is it? ;-)

  If it is the cause, then the emission of photons serves to pull the protons 
together.

  Harry
  PS. Wikipedia says the fractional quantum hall effect  also involves 
quantized states of repulsion although they are between electrons rather than 
protons and deuterons.



   

Re: [Vo]:Isotope separation technology can be improved

2013-05-27 Thread Harry Veeder
I experience momentum exchange as a push, but also don't think the cause of
everything must be explained
in terms that are consistent with momentum exchange. However,  I am  well
aware that this has been a dogma of
physics for hundreds of years.

Harry



On Mon, May 27, 2013 at 2:24 AM, Andrew andrew...@att.net wrote:

 **
 Quantum mechanics governs both attraction and repulsion between charges.
 Ax far as the maths is concerned, it's just a sign change. If you come at
 this as an interaction characterised by exchange of quanta, then (via a
 momentum model) only repulsion makes intuitive sense. But that's OK - QM is
 nothing if not unintuitive.

 Andrew

 - Original Message -
 *From:* Harry Veeder hveeder...@gmail.com
 *To:* vortex-l@eskimo.com
 *Sent:* Sunday, May 26, 2013 11:17 PM
 *Subject:* Re: [Vo]:Isotope separation technology can be improved



 On Sat, May 25, 2013 at 10:30 AM, Edmund Storms stor...@ix.netcom.comwrote:


  On May 24, 2013, at 10:38 PM, Harry Veeder wrote:




 The process you have described has the characteristics of
 a ratchet. Curiously, Jones used the ratchet metaphor in another post where
 he characterised the effect of modulating the input on the cell.


 Yes Harry, this can be called a ratchet. All kinds of ratchets exist in
 Nature. The challenge is to find the cause. In this case, the nuclei have
 to communicate before they have fused into a single nuclei.  The form of
 htat communication is unknown, but very important. Once discovered, this
 will get someone the Nobel prize.

 Imagine the following sequence. The nuclei are held apart by an electron
 bond, which is normally the case. Once formed, this structure starts to
 resonate so that the two nuclei get periodically closer together.  As they
 approach each other, information is exchanged between the nuclei that tells
 them they have too much mass -energy for being this close. After all, if
 they were in contact, the excess mass-energy would be 24 MeV if the nuclei
 were deuterons. But they are not in contact yet, so that the excess
 mass-energy is less than the maximum. Nevertheless, this excess must be
 dissipated, which each nuclei does by emitting a photon having 1/2 of the
 excess energy for the distance achieved. After the photons are emitted, the
 resonance moves the two nuclei apart, but this time not as far as
 previously the case. The next resonance cycle again brings the nuclei
 close, but this time they come closer than before, again with emission of
 two photons. This cycle repeats until all energy has been dissipated and
 the two nuclei are in contact. The intervening electron, that was necessary
 to the process, is sucked into the final nucleus. Because very little
 energy is released by entry of the electron, the neutrino, if it is emitted
 at all, has very little energy available to carry away.

 This process, I suggest, is the unique and previously unknown phenomenon
 that CF has revealed.




 Ed,
 Typically we associate quantization with attractive forces as is the case
 with an electron and a proton in a hydrogen atom, but your system involves
 quantization with repulsive forces.

 If pushing an electron and proton apart can happen in steps through the
 absorption of photons, I guess it follows that pushing together of
 protons can happen in steps through the emission of photons. However, in
 the former situation the pushing apart is the effect but the absorption
 of the photons is the cause, whereas in the latter situation the pushing
 together is the cause, and the emission of photons is effector is it?
 ;-)

 If it is the cause, then the emission of photons serves to pull the
 protons together.

 Harry
 PS. Wikipedia says the fractional quantum hall effect  also involves
 quantized states of repulsion although they are between electrons rather
 than protons and deuterons.








Re: [Vo]:Isotope separation technology can be improved

2013-05-27 Thread Edmund Storms


On May 27, 2013, at 12:17 AM, Harry Veeder wrote:




On Sat, May 25, 2013 at 10:30 AM, Edmund Storms  
stor...@ix.netcom.com wrote:


On May 24, 2013, at 10:38 PM, Harry Veeder wrote:





The process you have described has the characteristics of a  
ratchet. Curiously, Jones used the ratchet metaphor in another post  
where he characterised the effect of modulating the input on the  
cell.


Yes Harry, this can be called a ratchet. All kinds of ratchets exist  
in Nature. The challenge is to find the cause. In this case, the  
nuclei have to communicate before they have fused into a single  
nuclei.  The form of htat communication is unknown, but very  
important. Once discovered, this will get someone the Nobel prize.


Imagine the following sequence. The nuclei are held apart by an  
electron bond, which is normally the case. Once formed, this  
structure starts to resonate so that the two nuclei get periodically  
closer together.  As they approach each other, information is  
exchanged between the nuclei that tells them they have too much mass  
-energy for being this close. After all, if they were in contact,  
the excess mass-energy would be 24 MeV if the nuclei were deuterons.  
But they are not in contact yet, so that the excess mass-energy is  
less than the maximum. Nevertheless, this excess must be dissipated,  
which each nuclei does by emitting a photon having 1/2 of the excess  
energy for the distance achieved. After the photons are emitted, the  
resonance moves the two nuclei apart, but this time not as far as  
previously the case. The next resonance cycle again brings the  
nuclei close, but this time they come closer than before, again with  
emission of two photons. This cycle repeats until all energy has  
been dissipated and the two nuclei are in contact. The intervening  
electron, that was necessary to the process, is sucked into the  
final nucleus. Because very little energy is released by entry of  
the electron, the neutrino, if it is emitted at all, has very little  
energy available to carry away.


This process, I suggest, is the unique and previously unknown  
phenomenon that CF has revealed.




Ed,
Typically we associate quantization with attractive forces as is the  
case with an electron and a proton in a hydrogen atom, but your  
system involves quantization with repulsive forces.


Like charges repel and unlike charges attract. Quantization is always  
a balance between attraction and repulsion. Consequently, I do not  
understand your point.


Resonance occurs when an object can alternate between between  
attraction and repulsion. This combination results in forces that can   
move an object between these two extremes as long as energy is supplied.


If pushing an electron and proton apart can happen in steps through  
the absorption of photons, I guess it follows that pushing together  
of protons can happen in steps through the emission of photons.


Your description is not correct. Photon emission only occurs when the  
electron RETURNS to its original energy level.


I'm not suggesting the electron has an role in emitting a photon. I'm  
proposing that a photon is emitted FROM THE NUCLEUS when two nuclei  
get too close to each other. Nuclei can not normally get this close.  
Consequently, the process is not normally possible.  The conditions in  
the NAE make this possible.


 However, in the former situation the pushing apart is the effect  
but the absorption of the photons is the cause, whereas in the  
latter situation the pushing together is the cause, and the emission  
of photons is effector is it? ;-)


The protons try to get close, but this is not possible because of the  
Coulomb barrier. Nevertheless, at a critical distance, they discover  
that if they gave off a little energy they could get closer.  This is  
like an explosive suddenly discovering that if it rearranged the  
atoms, it could give off energy.  In the case of the protons, the  
resonance process intervenes and stops the energy release before it  
can be complete. As a result, only a photon having low energy can be  
released. But then resonance again brings the two protons close and  
another photon is emitted from each proton. This process repeats until  
all energy is removed and the final nucleus is formed.


Ed Storms


If it is the cause, then the emission of photons serves to pull the  
protons together.


Harry
PS. Wikipedia says the fractional quantum hall effect  also involves  
quantized states of repulsion although they are between electrons  
rather than protons and deuterons.









Re: [Vo]:Isotope separation technology can be improved

2013-05-27 Thread David Roberson

Ed, do you consider the emission of photons as a result of interaction of the 
protons due to the coulomb force between them or the strong force?   It seems 
that the initial distances are much to far apart to involve interaction by 
strong force.

Dave


-Original Message-
From: Edmund Storms stor...@ix.netcom.com
To: vortex-l vortex-l@eskimo.com
Cc: Edmund Storms stor...@ix.netcom.com
Sent: Mon, May 27, 2013 10:11 am
Subject: Re: [Vo]:Isotope separation technology can be improved




On May 27, 2013, at 12:17 AM, Harry Veeder wrote:






On Sat, May 25, 2013 at 10:30 AM, Edmund Storms stor...@ix.netcom.com wrote:
 


On May 24, 2013, at 10:38 PM, Harry Veeder wrote:
 




 
 
The process you have described has the characteristics of a ratchet. Curiously, 
Jones used the ratchet metaphor in another post where he characterised the 
effect of modulating the input on the cell.
 




Yes Harry, this can be called a ratchet. All kinds of ratchets exist in Nature. 
The challenge is to find the cause. In this case, the nuclei have to 
communicate before they have fused into a single nuclei.  The form of htat 
communication is unknown, but very important. Once discovered, this will get 
someone the Nobel prize. 
 


Imagine the following sequence. The nuclei are held apart by an electron bond, 
which is normally the case. Once formed, this structure starts to resonate so 
that the two nuclei get periodically closer together.  As they approach each 
other, information is exchanged between the nuclei that tells them they have 
too much mass -energy for being this close. After all, if they were in contact, 
the excess mass-energy would be 24 MeV if the nuclei were deuterons. But they 
are not in contact yet, so that the excess mass-energy is less than the 
maximum. Nevertheless, this excess must be dissipated, which each nuclei does 
by emitting a photon having 1/2 of the excess energy for the distance achieved. 
After the photons are emitted, the resonance moves the two nuclei apart, but 
this time not as far as previously the case. The next resonance cycle again 
brings the nuclei close, but this time they come closer than before, again with 
emission of two photons. This cycle repeats until all energy has been 
dissipated and the two nuclei are in contact. The intervening electron, that 
was necessary to the process, is sucked into the final nucleus. Because very 
little energy is released by entry of the electron, the neutrino, if it is 
emitted at all, has very little energy available to carry away.
 


This process, I suggest, is the unique and previously unknown phenomenon that 
CF has revealed. 
 

 
 
Ed, 
Typically we associate quantization with attractive forces as is the case with 
an electron and a proton in a hydrogen atom, but your system involves 
quantization with repulsive forces. 




Like charges repel and unlike charges attract. Quantization is always a balance 
between attraction and repulsion. Consequently, I do not understand your point. 


Resonance occurs when an object can alternate between between attraction and 
repulsion. This combination results in forces that can  move an object between 
these two extremes as long as energy is supplied. 


 
 
If pushing an electron and proton apart can happen in steps through the 
absorption of photons, I guess it follows that pushing together of protons can 
happen in steps through the emission of photons.




Your description is not correct. Photon emission only occurs when the electron 
RETURNS to its original energy level.  


I'm not suggesting the electron has an role in emitting a photon. I'm proposing 
that a photon is emitted FROM THE NUCLEUS when two nuclei get too close to each 
other. Nuclei can not normally get this close. Consequently, the process is not 
normally possible.  The conditions in the NAE make this possible. 




 However, in the former situation the pushing apart is the effect but the 
absorption of the photons is the cause, whereas in the latter situation the 
pushing together is the cause, and the emission of photons is effector is 
it? ;-)




The protons try to get close, but this is not possible because of the Coulomb 
barrier. Nevertheless, at a critical distance, they discover that if they gave 
off a little energy they could get closer.  This is like an explosive suddenly 
discovering that if it rearranged the atoms, it could give off energy.  In the 
case of the protons, the resonance process intervenes and stops the energy 
release before it can be complete. As a result, only a photon having low energy 
can be released. But then resonance again brings the two protons close and 
another photon is emitted from each proton. This process repeats until all 
energy is removed and the final nucleus is formed. 


Ed Storms


 
 
If it is the cause, then the emission of photons serves to pull the protons 
together.
 
Harry
PS. Wikipedia says the fractional quantum hall effect  also involves quantized 
states

Re: [Vo]:Isotope separation technology can be improved

2013-05-27 Thread Edmund Storms
 Dave, the interaction is unique and not related to the strong force  
as normally defined. Some additional kind of interaction is revealed  
by the phenomenon.  Or perhaps the strong force is poorly  
understood. In any case, the two protons know that they have too  
much mass-energy for the distance. If the distance is reduced too  
quickly, as during hot fusion, all the energy either comes out as a  
single intense gamma or the resulting nucleus fragments.  CF allows  
the process to occur slowly enough for the details to be seen.


The structure creates a condition in which the proton can oscillate  
along the chain created by the linear molecule. This oscillation is  
fueled by the temperature in the NAE region, which is much greater  
than the bulk temperature, and by attraction when the protons are far  
apart and repulsion when they get too close. The only thing making  
this structure unique is the ability of the protons to get closer than  
any other way, but for only a brief time. In contrast, the muon allows  
this close distance, but once the distance is reduced, the loss of  
energy is immediately total, causing hot fusion. In this case, the  
process is not stopped and goes to completion as expected.  In the  
case of the Hydroton, the resonance moves the proton close only for a  
brief time, which allows only a short burst of energy release.  The  
resonance cycle then moves the proton too far away to cause energy  
release. The next cycle brings the two protons close again. I would  
attach a picture but Vortex does not like attachments.


This process allows only a short time for the energy to be released as  
a proton (gamma), with a repeated release created by the resonance,  
thereby creating the observed behavior.


Ed Storms


On May 27, 2013, at 9:07 AM, David Roberson wrote:

Ed, do you consider the emission of photons as a result of  
interaction of the protons due to the coulomb force between them or  
the strong force?   It seems that the initial distances are much to  
far apart to involve interaction by strong force.


Dave
-Original Message-
From: Edmund Storms stor...@ix.netcom.com
To: vortex-l vortex-l@eskimo.com
Cc: Edmund Storms stor...@ix.netcom.com
Sent: Mon, May 27, 2013 10:11 am
Subject: Re: [Vo]:Isotope separation technology can be improved


On May 27, 2013, at 12:17 AM, Harry Veeder wrote:




On Sat, May 25, 2013 at 10:30 AM, Edmund Storms stor...@ix.netcom.com 
 wrote:


On May 24, 2013, at 10:38 PM, Harry Veeder wrote:





The process you have described has the characteristics of a  
ratchet. Curiously, Jones used the ratchet metaphor in another  
post where he characterised the effect of modulating the input on  
the cell.


Yes Harry, this can be called a ratchet. All kinds of ratchets  
exist in Nature. The challenge is to find the cause. In this case,  
the nuclei have to communicate before they have fused into a single  
nuclei.  The form of htat communication is unknown, but very  
important. Once discovered, this will get someone the Nobel prize.


Imagine the following sequence. The nuclei are held apart by an  
electron bond, which is normally the case. Once formed, this  
structure starts to resonate so that the two nuclei get  
periodically closer together.  As they approach each other,  
information is exchanged between the nuclei that tells them they  
have too much mass -energy for being this close. After all, if they  
were in contact, the excess mass-energy would be 24 MeV if the  
nuclei were deuterons. But they are not in contact yet, so that the  
excess mass-energy is less than the maximum. Nevertheless, this  
excess must be dissipated, which each nuclei does by emitting a  
photon having 1/2 of the excess energy for the distance achieved.  
After the photons are emitted, the resonance moves the two nuclei  
apart, but this time not as far as previously the case. The next  
resonance cycle again brings the nuclei close, but this time they  
come closer than before, again with emission of two photons. This  
cycle repeats until all energy has been dissipated and the two  
nuclei are in contact. The intervening electron, that was necessary  
to the process, is sucked into the final nucleus. Because very  
little energy is released by entry of the electron, the neutrino,  
if it is emitted at all, has very little energy available to carry  
away.


This process, I suggest, is the unique and previously unknown  
phenomenon that CF has revealed.




Ed,
Typically we associate quantization with attractive forces as is  
the case with an electron and a proton in a hydrogen atom, but your  
system involves quantization with repulsive forces.


Like charges repel and unlike charges attract. Quantization is  
always a balance between attraction and repulsion. Consequently, I  
do not understand your point.


Resonance occurs when an object can alternate between between  
attraction and repulsion. This combination results in forces that  
can

Re: [Vo]:Isotope separation technology can be improved

2013-05-25 Thread Edmund Storms


On May 24, 2013, at 10:38 PM, Harry Veeder wrote:




On Thu, May 23, 2013 at 10:16 AM, Edmund Storms  
stor...@ix.netcom.com wrote:


On May 22, 2013, at 11:21 PM, Harry Veeder wrote:


Ed,

I think the structure of the coulomb barrier is open to intrinsic  
modification, but the variables governing this possibility cannot  
be uncovered by the tools and concepts of high energy physics.


I agree. In fact, the insistence that high energy physics be used is  
the flaw in the skeptical arguments.


In most situations the coulomb barrier behaves in a textbook  
fashion, but when bathed in the right vibrations the barrier can be  
tuned to soften.


I think a different description is more useful. The two nuclei have  
first to get critically close together by intervention of an  
electron. This process is conventional.  Once this happens and the  
bond can resonate, the periodic reduction in distance causes the  
nuclei to emit a photon (gamma).  Each emitted photon allows hte  
distance to be reduced because the energy of the system has now been  
reduced, which reduces the Coulomb barrier. After enough photons  
have been emitted, the two nuclei collapse into one, which is the  
nuclear product. Of course, the intervening electron that is  
required to reduce the barrier is sucked into the final nucleus.




The process you have described has the characteristics of a ratchet.  
Curiously, Jones used the ratchet metaphor in another post where he  
characterised the effect of modulating the input on the cell.


Yes Harry, this can be called a ratchet. All kinds of ratchets exist  
in Nature. The challenge is to find the cause. In this case, the  
nuclei have to communicate before they have fused into a single  
nuclei.  The form of htat communication is unknown, but very  
important. Once discovered, this will get someone the Nobel prize.


Imagine the following sequence. The nuclei are held apart by an  
electron bond, which is normally the case. Once formed, this structure  
starts to resonate so that the two nuclei get periodically closer  
together.  As they approach each other, information is exchanged  
between the nuclei that tells them they have too much mass -energy for  
being this close. After all, if they were in contact, the excess mass- 
energy would be 24 MeV if the nuclei were deuterons. But they are not  
in contact yet, so that the excess mass-energy is less than the  
maximum. Nevertheless, this excess must be dissipated, which each  
nuclei does by emitting a photon having 1/2 of the excess energy for  
the distance achieved. After the photons are emitted, the resonance  
moves the two nuclei apart, but this time not as far as previously the  
case. The next resonance cycle again brings the nuclei close, but this  
time they come closer than before, again with emission of two photons.  
This cycle repeats until all energy has been dissipated and the two  
nuclei are in contact. The intervening electron, that was necessary to  
the process, is sucked into the final nucleus. Because very little  
energy is released by entry of the electron, the neutrino, if it is  
emitted at all, has very little energy available to carry away.


This process, I suggest, is the unique and previously unknown  
phenomenon that CF has revealed.


Ed Storms



This model requires the nuclei to know that they must emit energy  
when they get close and that magnitude of the Coulomb barrier is  
sensitive to the excess mass-energy of the two nuclei.


Ed Storms




Is this another way of saying it is related to the nuclear force? If  
so then the ratchet is the nuclear force.


harry




Re: [Vo]:Isotope separation technology can be improved

2013-05-24 Thread Harry Veeder
On Thu, May 23, 2013 at 10:16 AM, Edmund Storms stor...@ix.netcom.comwrote:


 On May 22, 2013, at 11:21 PM, Harry Veeder wrote:

 Ed,

 I think the structure of the coulomb barrier is open to intrinsic
 modification, but the variables governing this possibility cannot be
 uncovered by the tools and concepts of high energy physics.


 I agree. In fact, the insistence that high energy physics be used is the
 flaw in the skeptical arguments.

 In most situations the coulomb barrier behaves in a textbook fashion,
 but when bathed in the right vibrations the barrier can be tuned to
 soften.


 I think a different description is more useful. The two nuclei have first
 to get critically close together by intervention of an electron. This
 process is conventional.  Once this happens and the bond can resonate, the
 periodic reduction in distance causes the nuclei to emit a photon (gamma).
  Each emitted photon allows hte distance to be reduced because the energy
 of the system has now been reduced, which reduces the Coulomb barrier.
 After enough photons have been emitted, the two nuclei collapse into one,
 which is the nuclear product. Of course, the intervening electron that is
 required to reduce the barrier is sucked into the final nucleus.



The process you have described has the characteristics of
a ratchet. Curiously, Jones used the ratchet metaphor in another post where
he characterised the effect of modulating the input on the cell.



 This model requires the nuclei to know that they must emit energy when
 they get close and that magnitude of the Coulomb barrier is sensitive to
 the excess mass-energy of the two nuclei.

 Ed Storms

 Is this another way of saying it is related to the nuclear force? If so
then the ratchet is the nuclear force.

harry


Re: [Vo]:Isotope separation technology can be improved

2013-05-23 Thread Edmund Storms


On May 22, 2013, at 11:21 PM, Harry Veeder wrote:


Ed,

I think the structure of the coulomb barrier is open to intrinsic  
modification, but the variables governing this possibility cannot be  
uncovered by the tools and concepts of high energy physics.


I agree. In fact, the insistence that high energy physics be used is  
the flaw in the skeptical arguments.


In most situations the coulomb barrier behaves in a textbook  
fashion, but when bathed in the right vibrations the barrier can be  
tuned to soften.


I think a different description is more useful. The two nuclei have  
first to get critically close together by intervention of an electron.  
This process is conventional.  Once this happens and the bond can  
resonate, the periodic reduction in distance causes the nuclei to emit  
a photon (gamma).  Each emitted photon allows hte distance to be  
reduced because the energy of the system has now been reduced, which  
reduces the Coulomb barrier. After enough photons have been emitted,  
the two nuclei collapse into one, which is the nuclear product. Of  
course, the intervening electron that is required to reduce the  
barrier is sucked into the final nucleus.


This model requires the nuclei to know that they must emit energy  
when they get close and that magnitude of the Coulomb barrier is  
sensitive to the excess mass-energy of the two nuclei.


Ed Storms

This softening reduces the height of the barrier so that much less  
energy is required for fusion, but it will also enable the gradual  
dissipation of fusion

energy you have postulated.

Harry

On Wed, May 22, 2013 at 3:58 PM, Edmund Storms  
stor...@ix.netcom.com wrote:
Harry, calculations are useless in this case because the mechanism  
is unknown to which the calculations can be applied. We know that  
the mechanism for fusion and transmutation must be the same, which  
means they both must occur in the same NAE. I can describe a process  
that fits this requirement, but not here.


As a basic fact, the barrier can be either lowered by intervention  
of negative charge or overcome by sufficient energy. Regardless of  
which method is used, the energy resulting from transmutation must  
be dissipated gradually before the final isotope is formed.  
Otherwise, a strong gamma must be emitted to conserve momentum. In  
addition, the method used to get over the barrier will be more  
difficult than required for fusion, as you pointed out. So,  
something very unique is required. I find that use of extra energy  
from fusion is a more logical method than assembly of the required  
large negative charge.  Do you agree?


Ed Storms


On May 22, 2013, at 1:41 PM, Harry Veeder wrote:


Ed,

I am intrigued by your idea that the lack of gammas could be  
explained by fusion process which happens gradually rather than  
suddenly as is the case with hot fusion.
However,   on the one hand you say the fusion of protons and  
deuterons supplies the energy necessary to over come coulomb  
repulsion between Ni nucleus and the fusion products, but on the  
other hand you do not say where the energy comes from to over come  
the coulomb repulsion that exists among protons and deuterons.
While it is possible to reduce the energy required by placing an  
electron between protons and deuterons I doubt this will generate  
enough fusion reactions and energy if coulomb's law is correct. Or  
have you done calculations which show that it will?


Harry

On Wed, May 22, 2013 at 10:14 AM, Edmund Storms stor...@ix.netcom.com 
 wrote:
No Harry, the Coulomb barrier is the same in Hot and Cold fusion.  
The difference is that it is overcome very rapidly during hot  
fusion and very slowly during cold fusion. That is the only  
difference between the two methods. This difference results in a  
different behavior.


Yes, a theory should explain transmutation and mine does. However,  
transmutation can only occur as a minor consequence of fusion.  
Fusion must be taking place first, which provides the conditions  
and energy to get over the huge Coulomb barrier associated with  
transmutation. As a result, the heat results from the fusion  
reaction, while a little transmutation occurs and contributes a  
very small amount of energy.  The two reactions must work together  
because they both have to follow the same rules, according to my  
approach


Ed Storms
On May 22, 2013, at 2:59 AM, Harry Veeder wrote:

You propose that the coulomb barrier is structured differently  
from how it is normally portrayed in textbooks, and it is this  
difference that permits the low temperature fusion of protons and  
deuterons and energy production. Wouldn't the same difference help  
to explain how transmutations can happen as well? It seems to me a  
good theory should be able to explain both transmutations and  
energy production even if the nuclei involved differ in each case.


Harry
.
On Tue, May 21, 2013 at 5:55 PM, Edmund Storms stor...@ix.netcom.com 
 wrote:
Yes, Harry 

Re: [Vo]:Isotope separation technology can be improved

2013-05-22 Thread Harry Veeder
You propose that the coulomb barrier is structured differently from how it
is normally portrayed in textbooks, and it is this difference that permits
the low temperature fusion of protons and deuterons and energy
production. Wouldn't the same difference help to explain how transmutations
can happen as well? It seems to me a good theory should be able
to explain both transmutations and energy production even if the nuclei
involved differ in each case.

Harry
.
On Tue, May 21, 2013 at 5:55 PM, Edmund Storms stor...@ix.netcom.comwrote:

 Yes, Harry this is one of the several reasons why transmutation cannot be
 the source  of energy. Four more remain.

 Ed Storms
 On May 21, 2013, at 3:45 PM, Harry Veeder wrote:

 In an environment populated with Ni nuclei and H nuclei, the spontaneous
 fusion of a H nucleus with another H nucleus is favoured over spontaneous
 fusion with a Ni nucleus because the electrostatic force of repulsion is
 smaller between two H nucleus than it is between an H nucleus and an Ni
 nucleus.

 Harry







Re: [Vo]:Isotope separation technology can be improved

2013-05-22 Thread Edmund Storms
No Harry, the Coulomb barrier is the same in Hot and Cold fusion. The  
difference is that it is overcome very rapidly during hot fusion and  
very slowly during cold fusion. That is the only difference between  
the two methods. This difference results in a different behavior.


Yes, a theory should explain transmutation and mine does. However,  
transmutation can only occur as a minor consequence of fusion. Fusion  
must be taking place first, which provides the conditions and energy  
to get over the huge Coulomb barrier associated with transmutation. As  
a result, the heat results from the fusion reaction, while a little  
transmutation occurs and contributes a very small amount of energy.   
The two reactions must work together because they both have to follow  
the same rules, according to my approach


Ed Storms
On May 22, 2013, at 2:59 AM, Harry Veeder wrote:





You propose that the coulomb barrier is structured differently from  
how it is normally portrayed in textbooks, and it is this difference  
that permits the low temperature fusion of protons and deuterons and  
energy production. Wouldn't the same difference help to explain how  
transmutations can happen as well? It seems to me a good theory  
should be able to explain both transmutations and energy production  
even if the nuclei involved differ in each case.


Harry
.
On Tue, May 21, 2013 at 5:55 PM, Edmund Storms  
stor...@ix.netcom.com wrote:
Yes, Harry this is one of the several reasons why transmutation  
cannot be the source  of energy. Four more remain.


Ed Storms
On May 21, 2013, at 3:45 PM, Harry Veeder wrote:

In an environment populated with Ni nuclei and H nuclei, the  
spontaneous fusion of a H nucleus with another H nucleus is  
favoured over spontaneous fusion with a Ni nucleus because the  
electrostatic force of repulsion is smaller between two H nucleus  
than it is between an H nucleus and an Ni nucleus.


Harry









Re: [Vo]:Isotope separation technology can be improved

2013-05-22 Thread Harry Veeder
Ed,

I am intrigued by your idea that the lack of gammas could be explained
by fusion process which happens gradually rather than suddenly as is the
case with hot fusion.
However,   on the one hand you say the fusion of protons and deuterons
supplies the energy necessary to over come coulomb repulsion between Ni
nucleus and the fusion products, but on the other hand you do not say where
the energy comes from to over come the coulomb repulsion that exists among
protons and deuterons.
While it is possible to reduce the energy required by placing an electron
between protons and deuterons I doubt this will generate enough fusion
reactions and energy if coulomb's law is correct. Or have you done
calculations which show that it will?

Harry

On Wed, May 22, 2013 at 10:14 AM, Edmund Storms stor...@ix.netcom.comwrote:

 No Harry, the Coulomb barrier is the same in Hot and Cold fusion. The
 difference is that it is overcome very rapidly during hot fusion and very
 slowly during cold fusion. That is the only difference between the two
 methods. This difference results in a different behavior.

 Yes, a theory should explain transmutation and mine does. However,
 transmutation can only occur as a minor consequence of fusion. Fusion must
 be taking place first, which provides the conditions and energy to get over
 the huge Coulomb barrier associated with transmutation. As a result, the
 heat results from the fusion reaction, while a little transmutation occurs
 and contributes a very small amount of energy.  The two reactions must work
 together because they both have to follow the same rules, according to my
 approach

 Ed Storms
 On May 22, 2013, at 2:59 AM, Harry Veeder wrote:

 You propose that the coulomb barrier is structured differently from how it
 is normally portrayed in textbooks, and it is this difference that permits
 the low temperature fusion of protons and deuterons and energy
 production. Wouldn't the same difference help to explain how transmutations
 can happen as well? It seems to me a good theory should be able
 to explain both transmutations and energy production even if the nuclei
 involved differ in each case.

 Harry
 .
 On Tue, May 21, 2013 at 5:55 PM, Edmund Storms stor...@ix.netcom.comwrote:

 Yes, Harry this is one of the several reasons why transmutation cannot be
 the source  of energy. Four more remain.

 Ed Storms
 On May 21, 2013, at 3:45 PM, Harry Veeder wrote:

 In an environment populated with Ni nuclei and H nuclei, the spontaneous
 fusion of a H nucleus with another H nucleus is favoured over spontaneous
 fusion with a Ni nucleus because the electrostatic force of repulsion is
 smaller between two H nucleus than it is between an H nucleus and an Ni
 nucleus.

 Harry









Re: [Vo]:Isotope separation technology can be improved

2013-05-22 Thread Edmund Storms
Harry, calculations are useless in this case because the mechanism is  
unknown to which the calculations can be applied. We know that the  
mechanism for fusion and transmutation must be the same, which means  
they both must occur in the same NAE. I can describe a process that  
fits this requirement, but not here.


As a basic fact, the barrier can be either lowered by intervention of  
negative charge or overcome by sufficient energy. Regardless of which  
method is used, the energy resulting from transmutation must be  
dissipated gradually before the final isotope is formed. Otherwise, a  
strong gamma must be emitted to conserve momentum. In addition, the  
method used to get over the barrier will be more difficult than  
required for fusion, as you pointed out. So, something very unique is  
required. I find that use of extra energy from fusion is a more  
logical method than assembly of the required large negative charge.   
Do you agree?


Ed Storms


On May 22, 2013, at 1:41 PM, Harry Veeder wrote:


Ed,

I am intrigued by your idea that the lack of gammas could be  
explained by fusion process which happens gradually rather than  
suddenly as is the case with hot fusion.
However,   on the one hand you say the fusion of protons and  
deuterons supplies the energy necessary to over come coulomb  
repulsion between Ni nucleus and the fusion products, but on the  
other hand you do not say where the energy comes from to over come  
the coulomb repulsion that exists among protons and deuterons.
While it is possible to reduce the energy required by placing an  
electron between protons and deuterons I doubt this will generate  
enough fusion reactions and energy if coulomb's law is correct. Or  
have you done calculations which show that it will?


Harry

On Wed, May 22, 2013 at 10:14 AM, Edmund Storms  
stor...@ix.netcom.com wrote:
No Harry, the Coulomb barrier is the same in Hot and Cold fusion.  
The difference is that it is overcome very rapidly during hot fusion  
and very slowly during cold fusion. That is the only difference  
between the two methods. This difference results in a different  
behavior.


Yes, a theory should explain transmutation and mine does. However,  
transmutation can only occur as a minor consequence of fusion.  
Fusion must be taking place first, which provides the conditions and  
energy to get over the huge Coulomb barrier associated with  
transmutation. As a result, the heat results from the fusion  
reaction, while a little transmutation occurs and contributes a very  
small amount of energy.  The two reactions must work together  
because they both have to follow the same rules, according to my  
approach


Ed Storms
On May 22, 2013, at 2:59 AM, Harry Veeder wrote:

You propose that the coulomb barrier is structured differently from  
how it is normally portrayed in textbooks, and it is this  
difference that permits the low temperature fusion of protons and  
deuterons and energy production. Wouldn't the same difference help  
to explain how transmutations can happen as well? It seems to me a  
good theory should be able to explain both transmutations and  
energy production even if the nuclei involved differ in each case.


Harry
.
On Tue, May 21, 2013 at 5:55 PM, Edmund Storms  
stor...@ix.netcom.com wrote:
Yes, Harry this is one of the several reasons why transmutation  
cannot be the source  of energy. Four more remain.


Ed Storms
On May 21, 2013, at 3:45 PM, Harry Veeder wrote:

In an environment populated with Ni nuclei and H nuclei, the  
spontaneous fusion of a H nucleus with another H nucleus is  
favoured over spontaneous fusion with a Ni nucleus because the  
electrostatic force of repulsion is smaller between two H nucleus  
than it is between an H nucleus and an Ni nucleus.


Harry












Re: [Vo]:Isotope separation technology can be improved

2013-05-22 Thread Axil Axil
The transfer of energy in a nuclear reaction must be sudden because of
requirements of quantum mechanics.

The first law of QM is that whenever energy is transferred, the
superposition of a QM states is resolved.


The transfer of energy is equivalent to an outside observer making a
measurement of a QM system in superposition.


This means that the thermalization of the energy quanta must be distributed
and intrinsic to  the energy release QM process.


Of course, the energy release process could be a series of nuclear decay
processes, but then it would not be fusion.





On Wed, May 22, 2013 at 3:58 PM, Edmund Storms stor...@ix.netcom.comwrote:

 Harry, calculations are useless in this case because the mechanism is
 unknown to which the calculations can be applied. We know that the
 mechanism for fusion and transmutation must be the same, which means they
 both must occur in the same NAE. I can describe a process that fits this
 requirement, but not here.

 As a basic fact, the barrier can be either lowered by intervention of
 negative charge or overcome by sufficient energy. Regardless of which
 method is used, the energy resulting from transmutation must be dissipated
 gradually before the final isotope is formed. Otherwise, a strong gamma
 must be emitted to conserve momentum. In addition, the method used to get
 over the barrier will be more difficult than required for fusion, as you
 pointed out. So, something very unique is required. I find that use of
 extra energy from fusion is a more logical method than assembly of the
 required large negative charge.  Do you agree?

 Ed Storms



 On May 22, 2013, at 1:41 PM, Harry Veeder wrote:

 Ed,

 I am intrigued by your idea that the lack of gammas could be explained
 by fusion process which happens gradually rather than suddenly as is the
 case with hot fusion.
 However,   on the one hand you say the fusion of protons and deuterons
 supplies the energy necessary to over come coulomb repulsion between Ni
 nucleus and the fusion products, but on the other hand you do not say where
 the energy comes from to over come the coulomb repulsion that exists among
 protons and deuterons.
 While it is possible to reduce the energy required by placing an electron
 between protons and deuterons I doubt this will generate enough fusion
 reactions and energy if coulomb's law is correct. Or have you done
 calculations which show that it will?

 Harry

 On Wed, May 22, 2013 at 10:14 AM, Edmund Storms stor...@ix.netcom.comwrote:

 No Harry, the Coulomb barrier is the same in Hot and Cold fusion. The
 difference is that it is overcome very rapidly during hot fusion and very
 slowly during cold fusion. That is the only difference between the two
 methods. This difference results in a different behavior.

 Yes, a theory should explain transmutation and mine does. However,
 transmutation can only occur as a minor consequence of fusion. Fusion must
 be taking place first, which provides the conditions and energy to get over
 the huge Coulomb barrier associated with transmutation. As a result, the
 heat results from the fusion reaction, while a little transmutation occurs
 and contributes a very small amount of energy.  The two reactions must work
 together because they both have to follow the same rules, according to my
 approach

 Ed Storms
 On May 22, 2013, at 2:59 AM, Harry Veeder wrote:

 You propose that the coulomb barrier is structured differently from how
 it is normally portrayed in textbooks, and it is this difference that
 permits the low temperature fusion of protons and deuterons and energy
 production. Wouldn't the same difference help to explain how transmutations
 can happen as well? It seems to me a good theory should be able
 to explain both transmutations and energy production even if the nuclei
 involved differ in each case.

 Harry
 .
 On Tue, May 21, 2013 at 5:55 PM, Edmund Storms stor...@ix.netcom.comwrote:

 Yes, Harry this is one of the several reasons why transmutation cannot
 be the source  of energy. Four more remain.

 Ed Storms
 On May 21, 2013, at 3:45 PM, Harry Veeder wrote:

 In an environment populated with Ni nuclei and H nuclei, the spontaneous
 fusion of a H nucleus with another H nucleus is favoured over spontaneous
 fusion with a Ni nucleus because the electrostatic force of repulsion is
 smaller between two H nucleus than it is between an H nucleus and an Ni
 nucleus.

 Harry











Re: [Vo]:Isotope separation technology can be improved

2013-05-22 Thread mixent
In reply to  Edmund Storms's message of Tue, 21 May 2013 20:51:20 -0600:
Hi Ed,
[snip]

You may be right. Time will tell.

Robin, you are making an assumption here. You are assuming that no  
energy has been lost before the neutrino is emitted and the electron  
is absorbed. Suppose, as I have proposed, the energy  is lost as a  
series of photons before the electron is added so that no energy  
remains to be carried by the neutrino. Cold fusion is unique because  
it requires this kind of process, i.e. the energy must be lost before  
the fusion process is complete. In contrast, hot fission occurs when  
all energy is lost at the time fusion is complete.  That is the  
essential difference between the two phenomenon.  You need to read my  
papers to see how CF must work to be consistent with what has  been  
observed.  The process can only be properly understood by considering  
all aspects of the process, not just this one event.

Ed Storms



On May 21, 2013, at 8:30 PM, mix...@bigpond.com wrote:

 In reply to  Edmund Storms's message of Tue, 21 May 2013 18:28:19  
 -0600:
 Hi,
 [snip]
 However, if protium was fusing into deuterium, which is an
 extremely rare reaction to begin with, there should be gamma
 radiation.

 There is no gamma radiation from the p-e-p reaction (as distinct  
 from the p-p
 reaction). The energy disappears with the neutrino. Therefore  
 *effectively* this
 reaction produces no energy.
 However useful energy would be released from subsequent fusion  
 reactions
 involving the D formed in the p-e-p reaction.

 Regards,

 Robin van Spaandonk

 http://rvanspaa.freehostia.com/project.html

Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/project.html



Re: [Vo]:Isotope separation technology can be improved

2013-05-22 Thread Harry Veeder
Ed,

I think the structure of the coulomb barrier is open to intrinsic
modification, but the variables governing this possibility cannot be
uncovered by the tools and concepts of high energy physics. In most
situations the coulomb barrier behaves in a textbook fashion, but when
bathed in the right vibrations the barrier can be tuned to soften. This
softening reduces the height of the barrier so that much less energy is
required for fusion, but it will also enable the gradual dissipation
of fusion
energy you have postulated.

Harry

On Wed, May 22, 2013 at 3:58 PM, Edmund Storms stor...@ix.netcom.comwrote:

 Harry, calculations are useless in this case because the mechanism is
 unknown to which the calculations can be applied. We know that the
 mechanism for fusion and transmutation must be the same, which means they
 both must occur in the same NAE. I can describe a process that fits this
 requirement, but not here.

 As a basic fact, the barrier can be either lowered by intervention of
 negative charge or overcome by sufficient energy. Regardless of which
 method is used, the energy resulting from transmutation must be dissipated
 gradually before the final isotope is formed. Otherwise, a strong gamma
 must be emitted to conserve momentum. In addition, the method used to get
 over the barrier will be more difficult than required for fusion, as you
 pointed out. So, something very unique is required. I find that use of
 extra energy from fusion is a more logical method than assembly of the
 required large negative charge.  Do you agree?

 Ed Storms


 On May 22, 2013, at 1:41 PM, Harry Veeder wrote:

 Ed,

 I am intrigued by your idea that the lack of gammas could be explained
 by fusion process which happens gradually rather than suddenly as is the
 case with hot fusion.
 However,   on the one hand you say the fusion of protons and deuterons
 supplies the energy necessary to over come coulomb repulsion between Ni
 nucleus and the fusion products, but on the other hand you do not say where
 the energy comes from to over come the coulomb repulsion that exists among
 protons and deuterons.
 While it is possible to reduce the energy required by placing an electron
 between protons and deuterons I doubt this will generate enough fusion
 reactions and energy if coulomb's law is correct. Or have you done
 calculations which show that it will?

 Harry

 On Wed, May 22, 2013 at 10:14 AM, Edmund Storms stor...@ix.netcom.comwrote:

 No Harry, the Coulomb barrier is the same in Hot and Cold fusion. The
 difference is that it is overcome very rapidly during hot fusion and very
 slowly during cold fusion. That is the only difference between the two
 methods. This difference results in a different behavior.

 Yes, a theory should explain transmutation and mine does. However,
 transmutation can only occur as a minor consequence of fusion. Fusion must
 be taking place first, which provides the conditions and energy to get over
 the huge Coulomb barrier associated with transmutation. As a result, the
 heat results from the fusion reaction, while a little transmutation occurs
 and contributes a very small amount of energy.  The two reactions must work
 together because they both have to follow the same rules, according to my
 approach

 Ed Storms
 On May 22, 2013, at 2:59 AM, Harry Veeder wrote:

 You propose that the coulomb barrier is structured differently from how
 it is normally portrayed in textbooks, and it is this difference that
 permits the low temperature fusion of protons and deuterons and energy
 production. Wouldn't the same difference help to explain how transmutations
 can happen as well? It seems to me a good theory should be able
 to explain both transmutations and energy production even if the nuclei
 involved differ in each case.

 Harry
 .
 On Tue, May 21, 2013 at 5:55 PM, Edmund Storms stor...@ix.netcom.comwrote:

 Yes, Harry this is one of the several reasons why transmutation cannot
 be the source  of energy. Four more remain.

 Ed Storms
 On May 21, 2013, at 3:45 PM, Harry Veeder wrote:

 In an environment populated with Ni nuclei and H nuclei, the spontaneous
 fusion of a H nucleus with another H nucleus is favoured over spontaneous
 fusion with a Ni nucleus because the electrostatic force of repulsion is
 smaller between two H nucleus than it is between an H nucleus and an Ni
 nucleus.

 Harry











RE: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread DJ Cravens
Ni 62 has zero spin but the others have a nuclear spin component.  So I should 
be relatively easy to come up with a way to separate them.
 
D2

 
Date: Tue, 21 May 2013 16:15:20 -0400
From: jedrothw...@gmail.com
To: vortex-l@eskimo.com
Subject: [Vo]:Isotope separation technology can be improved

Somewhere in all these recent comments, Jones Beene made interesting 
observations about the cost of nickel isotopes. I cannot find the comments. The 
gist of it was that if Rossi device requires an unusual metal isotope the cost 
may not be much cheaper than conventional energy.


I believe that is incorrect. When I was researching the book I read some books 
and online resources about isotope separation, especially heavy water but also 
zinc and other elements. Perhaps my information is out of date, but what I 
learned then was that isotope separation technology has not been pursued much 
since World War II, when it was first developed for nuclear weapons.


There has not been much practical use for isotopes. If a mass-market for a 
particular nickel isotope emerged, I believe that rapid progress would be made 
and the cost would soon fall.

I also learned that much of the cost of isotope separation is for energy. Most 
of the techniques are energy intensive. Therefore, a cold fusion economy that 
called for isotope separation would bootstrap itself to lower costs. I 
illustrated this with the projected cost of heavy water, but that would apply 
to nickel as well, I think.


I believe the quoted costs for isotopes are for highly pure monoisotopic 
samples. I do not think that Rossi would need a pure sample. If he only 
increased the concentration of one rare isotope, without eliminating the 
others, I assume that would work.


- Jed 

Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Bob Higgins
I don't understand why 62Ni would make a difference in the reaction.  Are
we now seriously considering that the Ni nucleus participates in the
nuclear reaction that causes the heat?  Dr. Storms proposes that physical
cracks in the lattice are the NAE and the money crop of the reaction does
not have any Ni nuclei being consumed except as a possible side reaction.
 If the NAE are cracks (plausible but far from certain), then would the
62Ni create a more desirable crack than a 60Ni or a 64Ni?  How would the
isotope affect the crack as an NAE?  Wouldn't only valence/conduction band
electron effects show up in the crack?  If so, how could an isotope in the
lattice have any effect on what happens in the crack?

At William and Mary's ILENR-12, Dr. Peter Hagelstein told me that
transmutation of Ni is endothermic.


On Tue, May 21, 2013 at 4:18 PM, DJ Cravens djcrav...@hotmail.com wrote:

 Ni 62 has zero spin but the others have a nuclear spin component.  So
 I should be relatively easy to come up with a way to separate them.

 D2



Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Jed Rothwell
I wrote:


 If he only increased the concentration of one rare isotope, without
 eliminating the others, I assume that would work.


The point being that present day isotope separation techniques work by
processing the same material over and over again, gradually increasing the
concentration of the desired isotope at each stage. That is what Bockris
told me. That is what various other sources say. So if you only want a
semi-pure concentration with one isotope at greater concentration than the
natural distribution, you do not need to process the sample over and over
again. This would greatly lower costs I believe.

I doubt that Rossi's reactor would need monoisotopic metal. His reactors
are not known for having pure material or clean-room grade construction.

- Jed


RE: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Jones Beene
Guys,

 

Without getting too philosophical Cost is almost  a relative thing. When
the demand is there, the cost will come down to some reasonable level. When
the politicians favor it, the cost will be even lower.

 

Aluminum was more expensive than gold when it was first put into production.
Zirconium was like platinum until a certain Admiral Rickover demanded that
he get it for a thousand times cheaper - and he did within a year.

 

I have checked with half a dozen suppliers and the present cost of Ni-62 is
at least $10,000 per gram - which is much higher than palladium, but that is
not the end of story.

 

We can look at U235 for an example of a rare isotope - which Government
has decided ought to be available cheaply. This is as the model for Ni-62
future pricing. 

 

However, that on that decision about nickel - it could be years away, and
involves political interference from Big Oil. But it is safe to hazard a
guess.

 

Based upon the cost of natural nickel being around $10 per pound, and the
sunk cost of large gas centrifuges owned by Sam, the cost of this isotope
could be as low as a dollar a gram, if they wanted it to be. That is a
factor of 10,000 less than now. That is about what Rossi is paying.

 

The big problem is how do inventors and developers get hold of some for
experiments?

 

I have been told recently (very recently) that Rossi may be getting his -
not from ENEA but from DoE - remember the Amp-Enerco connection? 

 

Yup - that DoE and those former high officials now with Amp-Enerco - who
have the right to the ECat in the USA - and that is essentially why Rossi
builds them in Florida and ships them to Italy. And it is why he says cost
is no problem.

 

Indeed Cost is no problem when the rare Ni-62 comes free from the NRC/DoE
via Amp-Enerco. What a deal.

 

Jones

 

 

 

From: DJ Cravens 

 

Ni 62 has zero spin but the others have a nuclear spin component.  So I
should be relatively easy to come up with a way to separate them.
 
D2

 

  _  

Date: Tue, 21 May 2013 16:15:20 -0400
From: jedrothw...@gmail.com
To: vortex-l@eskimo.com
Subject: [Vo]:Isotope separation technology can be improved

Somewhere in all these recent comments, Jones Beene made interesting
observations about the cost of nickel isotopes. I cannot find the comments.
The gist of it was that if Rossi device requires an unusual metal isotope
the cost may not be much cheaper than conventional energy.

I believe that is incorrect. When I was researching the book I read some
books and online resources about isotope separation, especially heavy water
but also zinc and other elements. Perhaps my information is out of date, but
what I learned then was that isotope separation technology has not been
pursued much since World War II, when it was first developed for nuclear
weapons.

There has not been much practical use for isotopes. If a mass-market for a
particular nickel isotope emerged, I believe that rapid progress would be
made and the cost would soon fall.

I also learned that much of the cost of isotope separation is for energy.
Most of the techniques are energy intensive. Therefore, a cold fusion
economy that called for isotope separation would bootstrap itself to lower
costs. I illustrated this with the projected cost of heavy water, but that
would apply to nickel as well, I think.

I believe the quoted costs for isotopes are for highly pure monoisotopic
samples. I do not think that Rossi would need a pure sample. If he only
increased the concentration of one rare isotope, without eliminating the
others, I assume that would work.

- Jed



Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Edmund Storms
Good point, Bob.  Simple arguments can show that the amount of energy  
claimed by Rossi can not result from the Ni+p=Cu reaction regardless  
of the isotope. Ironically, people will accept Rossi's claim that  
transmutation is the source of energy while questioning whether he  
makes any energy at all. Amazing!


Ed Storms
On May 21, 2013, at 2:30 PM, Bob Higgins wrote:

I don't understand why 62Ni would make a difference in the  
reaction.  Are we now seriously considering that the Ni nucleus  
participates in the nuclear reaction that causes the heat?  Dr.  
Storms proposes that physical cracks in the lattice are the NAE and  
the money crop of the reaction does not have any Ni nuclei being  
consumed except as a possible side reaction.  If the NAE are cracks  
(plausible but far from certain), then would the 62Ni create a more  
desirable crack than a 60Ni or a 64Ni?  How would the isotope affect  
the crack as an NAE?  Wouldn't only valence/conduction band electron  
effects show up in the crack?  If so, how could an isotope in the  
lattice have any effect on what happens in the crack?


At William and Mary's ILENR-12, Dr. Peter Hagelstein told me that  
transmutation of Ni is endothermic.



On Tue, May 21, 2013 at 4:18 PM, DJ Cravens djcrav...@hotmail.com  
wrote:
Ni 62 has zero spin but the others have a nuclear spin component.   
So I should be relatively easy to come up with a way to separate them.


D2





RE: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread DJ Cravens
yes, I have doubts about Ni + p or Ni + 2p reactions.   most of these seem 
endothermic to me.
I would be more inclined to think there some kind of p+p   like event.  (OK 
Ed... p e p )
 
 
Dennis

 
CC: stor...@ix.netcom.com
From: stor...@ix.netcom.com
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Isotope separation technology can be improved
Date: Tue, 21 May 2013 14:48:13 -0600

Good point, Bob.  Simple arguments can show that the amount of energy claimed 
by Rossi can not result from the Ni+p=Cu reaction regardless of the isotope. 
Ironically, people will accept Rossi's claim that transmutation is the source 
of energy while questioning whether he makes any energy at all. Amazing!
Ed Storms
On May 21, 2013, at 2:30 PM, Bob Higgins wrote:I don't understand why 62Ni 
would make a difference in the reaction.  Are we now seriously considering that 
the Ni nucleus participates in the nuclear reaction that causes the heat?  Dr. 
Storms proposes that physical cracks in the lattice are the NAE and the money 
crop of the reaction does not have any Ni nuclei being consumed except as a 
possible side reaction.  If the NAE are cracks (plausible but far from 
certain), then would the 62Ni create a more desirable crack than a 60Ni or a 
64Ni?  How would the isotope affect the crack as an NAE?  Wouldn't only 
valence/conduction band electron effects show up in the crack?  If so, how 
could an isotope in the lattice have any effect on what happens in the crack? 
At William and Mary's ILENR-12, Dr. Peter Hagelstein told me that transmutation 
of Ni is endothermic.

On Tue, May 21, 2013 at 4:18 PM, DJ Cravens djcrav...@hotmail.com wrote:
  Ni 62 has zero spin but the others have a nuclear spin component.  So I 
should be relatively easy to come up with a way to separate them.
 
D2

 
  

Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Axil Axil
If you have studied the ash from the Ni/H reactors you must conclude that:

Any elements having an even number of nucleons with spin zero will react in
LENR.

LENR has a far greater energy density than U235 because cascades of LENR
reaction products will fission from a very high atomic weight to a low
weight.

LENR reclaims the energy that a supernova used to produce the heavy
reactive isotope and will reduce that isotope down to its original light
atomic number configuration.

Fusion is a secondary low probability reaction channel.





On Tue, May 21, 2013 at 4:30 PM, Bob Higgins rj.bob.higg...@gmail.comwrote:

 I don't understand why 62Ni would make a difference in the reaction.  Are
 we now seriously considering that the Ni nucleus participates in the
 nuclear reaction that causes the heat?  Dr. Storms proposes that physical
 cracks in the lattice are the NAE and the money crop of the reaction does
 not have any Ni nuclei being consumed except as a possible side reaction.
  If the NAE are cracks (plausible but far from certain), then would the
 62Ni create a more desirable crack than a 60Ni or a 64Ni?  How would the
 isotope affect the crack as an NAE?  Wouldn't only valence/conduction band
 electron effects show up in the crack?  If so, how could an isotope in the
 lattice have any effect on what happens in the crack?

 At William and Mary's ILENR-12, Dr. Peter Hagelstein told me that
 transmutation of Ni is endothermic.


 On Tue, May 21, 2013 at 4:18 PM, DJ Cravens djcrav...@hotmail.com wrote:

 Ni 62 has zero spin but the others have a nuclear spin component.  So
 I should be relatively easy to come up with a way to separate them.

 D2





RE: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Jones Beene
 

 

From: Bob Higgins 

 

I don't understand why 62Ni would make a difference in the reaction.  Are we
now seriously considering that the Ni nucleus participates in the nuclear
reaction that causes the heat

 

IMO this is a Mills type reaction (BLP), involving deep hydrogen
redundancy - and the Ni does not transmute into another element. 

 

This particular isotope is simply a much better catalyst for deep redundancy
at the 300 eV level. This mechanism goes beyond Randell Mills theory into QM
and wave function collapse, which Mills rejects.

 

Rossi and Focardi apparently believe that nickel transmutes to copper, but
the proof offered indicates otherwise. Others believe that protons fuse to
deuterium. There is no proof of that.

 

Many qualified observers, at this stage, have markedly different opinions. 

 

However, it is worth repeating that if it is a nuclear reaction - there
should be gamma radiation and/or radioactive ash. There is none.

 

Jones



Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Harry Veeder
In an environment populated with Ni nuclei and H nuclei, the spontaneous
fusion of a H nucleus with another H nucleus is favoured over spontaneous
fusion with a Ni nucleus because the electrostatic force of repulsion is
smaller between two H nucleus than it is between an H nucleus and an Ni
nucleus.

Harry


On Tue, May 21, 2013 at 4:54 PM, DJ Cravens djcrav...@hotmail.com wrote:

 yes, I have doubts about Ni + p or Ni + 2p reactions.   most of these seem
 endothermic to me.
 I would be more inclined to think there some kind of p+p   like event.
 (OK Ed... p e p )


 Dennis


 --
 CC: stor...@ix.netcom.com
 From: stor...@ix.netcom.com
 To: vortex-l@eskimo.com
 Subject: Re: [Vo]:Isotope separation technology can be improved
 Date: Tue, 21 May 2013 14:48:13 -0600

 Good point, Bob.  Simple arguments can show that the amount of energy
 claimed by Rossi can not result from the Ni+p=Cu reaction regardless of the
 isotope. Ironically, people will accept Rossi's claim that transmutation is
 the source of energy while questioning whether he makes any energy at all.
 Amazing!

 Ed Storms
 On May 21, 2013, at 2:30 PM, Bob Higgins wrote:

 I don't understand why 62Ni would make a difference in the reaction.  Are
 we now seriously considering that the Ni nucleus participates in the
 nuclear reaction that causes the heat?  Dr. Storms proposes that physical
 cracks in the lattice are the NAE and the money crop of the reaction does
 not have any Ni nuclei being consumed except as a possible side reaction.
  If the NAE are cracks (plausible but far from certain), then would the
 62Ni create a more desirable crack than a 60Ni or a 64Ni?  How would the
 isotope affect the crack as an NAE?  Wouldn't only valence/conduction band
 electron effects show up in the crack?  If so, how could an isotope in the
 lattice have any effect on what happens in the crack?

 At William and Mary's ILENR-12, Dr. Peter Hagelstein told me that
 transmutation of Ni is endothermic.


 On Tue, May 21, 2013 at 4:18 PM, DJ Cravens djcrav...@hotmail.com wrote:

 Ni 62 has zero spin but the others have a nuclear spin component.  So
 I should be relatively easy to come up with a way to separate them.

 D2






Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Edmund Storms
Jones, there is no ash because no one has looked for deuterium.  
Everyone who might find enough deuterium to detect is focused on  
transmutation. If they now find deuterium, their favorite explanation  
will go up in smoke and the patents that claim to need nickel will be  
useless.  I'm trying to get someone to look for deuterium and report  
the results. So far, no luck. Until this test is made, no conclusion  
is worth accepting.


Ed Storms
On May 21, 2013, at 3:33 PM, Jones Beene wrote:




From: Bob Higgins

I don't understand why 62Ni would make a difference in the  
reaction.  Are we now seriously considering that the Ni nucleus  
participates in the nuclear reaction that causes the heat


IMO this is a “Mills type” reaction (BLP), involving deep hydrogen  
redundancy - and the Ni does not transmute into another element.


This particular isotope is simply a much better catalyst for deep  
redundancy at the 300 eV level. This mechanism goes beyond Randell  
Mills theory into QM and wave function collapse, which Mills rejects.


Rossi and Focardi apparently believe that nickel transmutes to  
copper, but the proof offered indicates otherwise. Others believe  
that protons fuse to deuterium. There is no proof of that.


Many qualified observers, at this stage, have markedly different  
opinions.


However, it is worth repeating that if it is a nuclear reaction –  
there should be gamma radiation and/or radioactive ash. There is none.


Jones




Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Edmund Storms
Yes, Harry this is one of the several reasons why transmutation cannot  
be the source  of energy. Four more remain.


Ed Storms
On May 21, 2013, at 3:45 PM, Harry Veeder wrote:

In an environment populated with Ni nuclei and H nuclei, the  
spontaneous fusion of a H nucleus with another H nucleus is favoured  
over spontaneous fusion with a Ni nucleus because the electrostatic  
force of repulsion is smaller between two H nucleus than it is  
between an H nucleus and an Ni nucleus.


Harry


On Tue, May 21, 2013 at 4:54 PM, DJ Cravens djcrav...@hotmail.com  
wrote:
yes, I have doubts about Ni + p or Ni + 2p reactions.   most of  
these seem endothermic to me.
I would be more inclined to think there some kind of p+p   like  
event.  (OK Ed... p e p )



Dennis


CC: stor...@ix.netcom.com
From: stor...@ix.netcom.com
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Isotope separation technology can be improved
Date: Tue, 21 May 2013 14:48:13 -0600

Good point, Bob.  Simple arguments can show that the amount of  
energy claimed by Rossi can not result from the Ni+p=Cu reaction  
regardless of the isotope. Ironically, people will accept Rossi's  
claim that transmutation is the source of energy while questioning  
whether he makes any energy at all. Amazing!


Ed Storms
On May 21, 2013, at 2:30 PM, Bob Higgins wrote:

I don't understand why 62Ni would make a difference in the  
reaction.  Are we now seriously considering that the Ni nucleus  
participates in the nuclear reaction that causes the heat?  Dr.  
Storms proposes that physical cracks in the lattice are the NAE and  
the money crop of the reaction does not have any Ni nuclei being  
consumed except as a possible side reaction.  If the NAE are cracks  
(plausible but far from certain), then would the 62Ni create a more  
desirable crack than a 60Ni or a 64Ni?  How would the isotope affect  
the crack as an NAE?  Wouldn't only valence/conduction band electron  
effects show up in the crack?  If so, how could an isotope in the  
lattice have any effect on what happens in the crack?


At William and Mary's ILENR-12, Dr. Peter Hagelstein told me that  
transmutation of Ni is endothermic.



On Tue, May 21, 2013 at 4:18 PM, DJ Cravens djcrav...@hotmail.com  
wrote:
Ni 62 has zero spin but the others have a nuclear spin component.   
So I should be relatively easy to come up with a way to separate them.


D2







Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Axil Axil
Nickel nano-particles are superparamagnetic. They interact with dipole
vibration. This may be the reason why nickel nanostructures are important
in the nanoplasmonic causation of LENR.

 *

Magnetic relaxation of a system of superparamagnetic particles weakly
coupled by dipole-dipole interactions

http://arxiv.org/ftp/arxiv/papers/1109/1109.4294.pdf
*


On Tue, May 21, 2013 at 4:30 PM, Bob Higgins rj.bob.higg...@gmail.comwrote:

 I don't understand why 62Ni would make a difference in the reaction.  Are
 we now seriously considering that the Ni nucleus participates in the
 nuclear reaction that causes the heat?  Dr. Storms proposes that physical
 cracks in the lattice are the NAE and the money crop of the reaction does
 not have any Ni nuclei being consumed except as a possible side reaction.
  If the NAE are cracks (plausible but far from certain), then would the
 62Ni create a more desirable crack than a 60Ni or a 64Ni?  How would the
 isotope affect the crack as an NAE?  Wouldn't only valence/conduction band
 electron effects show up in the crack?  If so, how could an isotope in the
 lattice have any effect on what happens in the crack?

 At William and Mary's ILENR-12, Dr. Peter Hagelstein told me that
 transmutation of Ni is endothermic.


 On Tue, May 21, 2013 at 4:18 PM, DJ Cravens djcrav...@hotmail.com wrote:

 Ni 62 has zero spin but the others have a nuclear spin component.  So
 I should be relatively easy to come up with a way to separate them.

 D2





Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Terry Blanton
If Ni62 is not consumed, the cost is somewhat academic.



RE: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Jones Beene
 

From: Edmund Storms 

 

Jones, there is no ash because no one has looked for deuterium. Everyone who
might find enough deuterium to detect is focused on transmutation. If they
now find deuterium, their favorite explanation will go up in smoke and the
patents that claim to need nickel will be useless.  I'm trying to get
someone to look for deuterium and report the results. So far, no luck. Until
this test is made, no conclusion is worth accepting.

 

Hi Ed,

 

Almost everyone agrees that deuterium (and helium and tritium) should be
looked for in the ash of this device, but that this probably will not happen
soon. Your explanation of why Rossi doesn't want to know this could be
absolutely correct. He shoots himself in the foot. Someone else must do
this, if it is to be done.

 

If the ratio of H to D in the gas was 6,500:1 when it was filled - and after
a week of run-time the ratio was 5,000:1 then that finding would be
meaningful. Hydrogen is unlikely to leak preferentially, so the large change
in ratio would indicate fusion as the prima facie explanation.

 

However, if protium was fusing into deuterium, which is an extremely rare
reaction to begin with, there should be gamma radiation. If you say there is
no gamma radiation because this is a novel type of fusion reaction which
shows none, then there is still a huge problem (aside from the extra
miracle) - tritium. At a certain point, tritium is favored and its decay
radiation will be obvious - even after shutdown. yet none shows up, when any
decent monitor should see it.

 

You probably do not want to add a third miracle by suggesting that no
tritium happens. Thus, the lack of tritium makes the search for extra
deuterium of lower priority than it otherwise would be. In the end, if the
H/D ratio is substantially different - we will have found something that
indicates a novel form of hydrogen fusion, which Rossi's patent does not
cover. 

 

However, another smart thing to do- if someone besides AR really wants to
find out the modus operandi would be to first look for the lower energy
photons - EUV. Rossi does not want to do that because of the huge portfolio
of prior art from BLP. OTOH, Mills and company might want to do this kind of
testing in a replica AR cell, as a way to get royalties from Rossi, in the
event that he beats them to market.

 

Many theories suggest the gain could be coming from EUV photons - and it is
easier to document them than deuterium, but I doubt we will know form Rossi.
I hope that Mills looks at the Ni-62 possibility, in the context of his
theory. 

 

This could pay off handsomely, Randy .

 

 

From: Bob Higgins

 

I don't understand why 62Ni would make a difference in the reaction.  Are we
now seriously considering that the Ni nucleus participates in the nuclear
reaction that causes the heat

 

IMO this is a Mills type reaction (BLP), involving deep hydrogen
redundancy - and the Ni does not transmute into another element.

 

This particular isotope is simply a much better catalyst for deep redundancy
at the 300 eV level. This mechanism goes beyond Randell Mills theory into QM
and wave function collapse, which Mills rejects.

 

Rossi and Focardi apparently believe that nickel transmutes to copper, but
the proof offered indicates otherwise. Others believe that protons fuse to
deuterium. There is no proof of that.

 

Many qualified observers, at this stage, have markedly different opinions.

 

However, it is worth repeating that if it is a nuclear reaction - there
should be gamma radiation and/or radioactive ash. There is none.

 

Jones

 



Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Jed Rothwell
On Tue, May 21, 2013 at 8:28 PM, Edmund Storms stor...@ix.netcom.comwrote:

 Vortex will not accept an attachment so you will have to find the paper
 elsewhere.

 J. Condensed Matter Nucl. Sci. 11 (2013) 1-15
 Research Article
 Nature of Energetic Radiation Emitted from a Metal Exposed to H2
 Edmund Storms* and Brian Scanlan



http://lenr-canr.org/acrobat/StormsEnatureofen.pdf

or

http://lenr-canr.org/acrobat/BiberianJPjcondensedj.pdf

- Jed


Re: [Vo]:Isotope separation technology can be improved

2013-05-21 Thread Edmund Storms
Robin, you are making an assumption here. You are assuming that no  
energy has been lost before the neutrino is emitted and the electron  
is absorbed. Suppose, as I have proposed, the energy  is lost as a  
series of photons before the electron is added so that no energy  
remains to be carried by the neutrino. Cold fusion is unique because  
it requires this kind of process, i.e. the energy must be lost before  
the fusion process is complete. In contrast, hot fission occurs when  
all energy is lost at the time fusion is complete.  That is the  
essential difference between the two phenomenon.  You need to read my  
papers to see how CF must work to be consistent with what has  been  
observed.  The process can only be properly understood by considering  
all aspects of the process, not just this one event.


Ed Storms



On May 21, 2013, at 8:30 PM, mix...@bigpond.com wrote:

In reply to  Edmund Storms's message of Tue, 21 May 2013 18:28:19  
-0600:

Hi,
[snip]

However, if protium was fusing into deuterium, which is an
extremely rare reaction to begin with, there should be gamma
radiation.


There is no gamma radiation from the p-e-p reaction (as distinct  
from the p-p
reaction). The energy disappears with the neutrino. Therefore  
*effectively* this

reaction produces no energy.
However useful energy would be released from subsequent fusion  
reactions

involving the D formed in the p-e-p reaction.

Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/project.html