A 270 watt panel is 64.88" × 38.98".
Your guesstimate of 10000 watts would require (10000 /270) 37.037 panels.
Doing the math (64.88 x 38.98 x 37), that is 93573 sq inches.
There are 144 sq inches in a sq ft, so that is (93573/144) 649 sq ft, or a
25ft x 25ft.
Now I'm not going to say it is impossible, but it is downright foolish....
> -----Original Message-----
> From: EV [mailto:ev-boun...@lists.evdl.org] On Behalf Of Lawrence Rhodes via
> Sent: Wednesday, December 27, 2017 3:48 PM
> To: firstname.lastname@example.org
> Cc: Lawrence Rhodes
> Subject: [EVDL] Solar trailer calculation
> Hi all,
> My math is good enough to figure out I get about my 30kw Leaf gets 4.5 miles
> kw at
> 55mph more or less depending on wind. What I'd like to know is what size
> panel would
> be needed to support that speed. Now don't tell me it can't be done. I just
> want to know the
> formula for figuring it out. My puny brain exploded when I thought of all
> variables. I do
> know that a 3000 watt system would charge my car in 10 hours. I would just
> to know the
> numbers of what would be needed for continuous power at speed. I
> it would be
> about 10000 watts. I'd just like the exact number. Thanks, Lawrence
> Rhodes...the point is to
> build a teardrop solar range extender/RV that could charge while driving.
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