On 8/24/2012 7:05 PM, Stephen P. King wrote:
"...due to the law of conjugate bisimulation identity:
A ~ A = A ~ B ~ C ~ B ~ A = A ~ B ~ A
this is "retractable path independence": path independence only over retractable paths.
I don't understand this. You write A~(B~A) which implies that B~A is a "system" (in this
case one being simulated by A). But then you write
A~B~A=A~A
and also
A~B~C~A =/= A~C~B~A =/= A~A
This seems inconsistent, since A~B~C~A = A~D~A where D=B~C, but then A~D~A=A~A. And
A~C~B~A = A~E~A where E=C~B, and then A~E~A=A~A. But then A~B~C~A = A~C~B~A.
You drop the parentheses, implying the relation is associative, but then you treat it as
though it isn't??
Brent
--
You received this message because you are subscribed to the Google Groups
"Everything List" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/everything-list?hl=en.