2013/10/22 John Clark <[email protected]> > > > > On Mon, Oct 21, 2013 at 6:03 PM, meekerdb <[email protected]> wrote: > > > On 10/21/2013 9:16 AM, John Clark wrote: >> >> >> Let me put it in this way: accepting that P(W) = P(M) =1/2, with W >>> and M describing the first person experiences of the respective copies, do >>> you accept that P(M) = P(W) = 1/2, >>> >> >> > No I don't accept that, not if P(W) is the probability that the >> Washington Man will see Washington; the probability of that would be 1 not >> 1/2. And if P(W) means the probability the Helsinki Man will see Washington >> that would be 0 not 1/2 because the Helsinki Man would have to be turned >> into something that is not the Helsinki Man before the Helsinki Man can see >> a different city. >> >> > Why? If he flew to Washington he would still be the Helsinki man. >> > > OK, then if he flew to Moscow he would be the Helsinki man too, and if he > used a Star Trek style transporter instead of a airplane he would still be > the Helsinki Man, and if the transporter sent him to both cities at the > same time he would still be "The Helsinki Man". So you tell me, using logic > and your definition how many cities did "The Helsinki Man" see? > > >> > He's the Helsinki man because of the continuity of his memories, just >> as you are still John Clark even though you've changed locations since >> yesterday. >> > > Fine. If that's what you mean by "The Helsinki Man" then in Bruno's > thought experiment with the duplication chamber and using the exact same > reasoning the probability The Helsinki Man will see Washington is 100% and > the probability The Helsinki Man will see Moscow is 100%. And yes yes I > know, each copy will see only one city, but if the definition of "The > Helsinki Man" is the one you give above, "the continuity of his memories", > then it is irrelevant how many cities each individual copy sees. >
Errare humanum est, perseverare diabolicum. > > John K Clark > > > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at http://groups.google.com/group/everything-list. > For more options, visit https://groups.google.com/groups/opt_out. > -- All those moments will be lost in time, like tears in rain. -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/groups/opt_out.
