Re: [PHP] Listing a few words from one sentence ??
At 23:29 07.11.2002, conbud said:
[snip]
Say I have a sentence that contains 8 words, how do I get PHP to list just 4
of those 8 words ?
[snip]
Let's assume your words are delimited by one or more blanks, so you could:
$arwords = split(' ',$sentence);// make an array
$arwords = array_slice($arwords, 0, 4); // return the first 4 entries
echo join(' ', $arwords); // and show them
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Help w/ 4.2.3 Problem
I have been running 4.1.2 fine, but decided to compile in the latest version 4.2.3. When I run some existing code that works perfect under 4.1.2, not only does the code not run properly, but there are no error messages in the error_log ( apache file ). also in php.ini I added log_errors = On, and error_log = php_log, but I never see any error messages. Running on RedHat 7.2 with apache_1.3.27, mod_ssl-2.8.12-1.3.27, openssl-0.9.6g, php-4.2.3. ( Again this all ran fine with php-4.1.2 ). Any ideas on where to start ? Thanks -- ___ Jack Sasportas Innovative Internet Solutions Phone 305.665.2500 Fax 305.665.2551 www.innovativeinternet.com www.web56.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: Re[6]: [PHP] Trouble with php-4.2.3, apache-1.3.27, sablotron 0.96
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 IT WORKS!!! Hahah yeah! It may have been a pain in the butt for _me_ to install, but it was worth it- this is really cool! Thanks Tom, I really owe you one. - -Evan On Thursday 07 November 2002 02:18 am, you wrote: Hi, Thursday, November 7, 2002, 6:30:17 PM, you wrote: EN -BEGIN PGP SIGNED MESSAGE- EN Hash: SHA1 EN Apache fails sanity check. Same with and without the LDFLAGS thing. EN Error Output for sanity check EN cd ..; gcc -DLINUX=22 -I/usr/src/php-4.2.3 -I/usr/src/php-4.2.3/main EN - -I/usr/src/php-4.2.3/main -I/usr/src/php-4.2.3/Zend -I/usr/src/php-4.2.3/Zend EN - -I/usr/src/php-4.2.3/TSRM -I/usr/src/php-4.2.3/TSRM -I/usr/src/php-4.2.3 EN - -DNO_DL_NEEDED `./apaci` -o helpers/dummy helpers/dummy.c EN - -Wl,-rpath,/usr/local/lib -rdynamic -L/usr/local/lib -Lmodules/php4 EN - -L../modules/php4 -L../../modules/php4 -lmodphp4 -lsablot -lexpat -lcrypt EN - -lresolv -lm -ldl -lnsl -lresolv -lcrypt -lm -lcrypt -lexpat EN /usr/local/lib/libsablot.so: undefined reference to `operator new[](unsigned)' EN /usr/local/lib/libsablot.so: undefined reference to `vtable for EN __cxxabiv1::__si_class_type_info' EN /usr/local/lib/libsablot.so: undefined reference to `operator delete(void*)' EN /usr/local/lib/libsablot.so: undefined reference to `__gxx_personality_v0' EN /usr/local/lib/libsablot.so: undefined reference to `__cxa_pure_virtual' EN /usr/local/lib/libsablot.so: undefined reference to `vtable for EN __cxxabiv1::__class_type_info' EN /usr/local/lib/libsablot.so: undefined reference to `operator delete[](void*)' EN /usr/local/lib/libsablot.so: undefined reference to `vtable for EN __cxxabiv1::__vmi_class_type_info' EN /usr/local/lib/libsablot.so: undefined reference to `operator new(unsigned)' EN collect2: ld returned 1 exit status EN make: *** [dummy] Error 1 EN = End of Error Report = EN On Wednesday 06 November 2002 09:49 pm, Tom Rogers wrote: Hi, Thursday, November 7, 2002, 1:11:43 PM, you wrote: EN Same error. As a test try compiling statically into apache...That is the way I have php at the moment. EN -BEGIN PGP SIGNATURE- EN Version: GnuPG v1.0.7 (GNU/Linux) EN iD8DBQE9yiSn/rncFku1MdIRAgzAAJ98rCLh9jWATOF96Liv3Lwo8SUq2gCbBci3 EN CngocpcfDF0Oo6+UP5B1Wcc= EN =qcnu EN -END PGP SIGNATURE- looks like you also have to do: LDFLAGS=' -lstdc++' ./configure for apache as well (although I did not have to do any of this stuff except for the patch) - -- Why be born again, when you can just grow up? - -Unknown -BEGIN PGP SIGNATURE- Version: GnuPG v1.0.7 (GNU/Linux) iD8DBQE9y3Gn/rncFku1MdIRAmUTAJ46Vg0ATagguXrJKS8jnskcQDRDkwCgleFY JxNowBqh+jvtNOLB4mS/HuM= =zCxO -END PGP SIGNATURE- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP fopen() bug + solution
At 00:51 08.11.2002, Charles Wiltgen said:
[snip]
Example: while(!file_exists(index.php) { clearstatcache(); }
while(filesize(index.php 10) { clearstatcache(); }
[snip]
To be more effective, and to allow the OS to do something else while you're
waiting at the file, your script should sleep for some microseconds... this
will release the time slice your script is occupying and allow other things
to happen, without having the cpu going up to 100%.
while(!file_exists(index.php) { usleep(100); clearstatcache(); }
while(filesize(index.php 10) { usleep(100); clearstatcache(); }
This will sleep for 0.1 seconds, not really notable. Note that I put the
call to clearstatcache() _after_ the sleep...
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Help w/ 4.2.3 Problem
Jack Sasportas wrote: I have been running 4.1.2 fine, but decided to compile in the latest version 4.2.3. When I run some existing code that works perfect under 4.1.2, not only does the code not run properly, but there are no error messages in the error_log ( apache file ). also in php.ini I added log_errors = On, and error_log = php_log, but I never see any error messages. Running on RedHat 7.2 with apache_1.3.27, mod_ssl-2.8.12-1.3.27, openssl-0.9.6g, php-4.2.3. ( Again this all ran fine with php-4.1.2 ). Any ideas on where to start ? Thanks Check the register_globals setting. As from php version 4.2.2, this setting defaults to Off, while older versions defaults to On. Grtz Erwin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] WAP resources for PHP
At 03:06 08.11.2002, Research and Development said:
[snip]
I need to make a site WAP ready in less than a month. What books or
internet resources do you recommend for development of WAP in PHP.
[snip]
Do a Google search for WML - it turns out a couple of very helpful links.
One of the best is http://www.w3schools.com/wap/default.asp, offering a
complete tutorial on WML.
To start with (and I didn't find that at w3schools) it is
_absolutely_necessary_ you tell PHP to transmit the correct content-type
header, by setting the header yourself:
header('Content-type: text/vnd.wap.wml');
Have fun (and post the URL when finished .-) )
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird behaviour with references to objects...
At 03:36 08.11.2002, Tim Molendijk said:
[snip]
begin first code snippet
?php
/* New Container object created. At the same time it sets a Child object in
its $child attribute. (This is indicated by passing TRUE.) */
$testContainer1 = new Container(TRUE);
Ahh - culprit 1:
You said the container is creating a child instance - I assume it's done in
the constructor...
What you're doing here is to create a clone when assigning new()'s result
to $testContainer1. You should rather
$testContainer1 = new Container(TRUE);
Note the ampersand here - if you don't you'll get a clone.
Rule for references:
If your object does something in its constructor, use a reference
assignment for
new class()
Below the code for the classes Container en Child.
begin third code snippet
?php
class Container
{
var $children;
var $property;
// stuff deleted
function load()
{
$newChild = new Child(1);
Again - make this
$newChild = new Child(1);
function add($child)
{
/* Here a reference of $this (the Container object) is assigned to $child's
$parent attribute. */
$child-parent = $this;
/* Here $child (the newly created Child object) is assigned to the
container's $child property. */
$this-child = $child;
}
But you don't pass $child by reference! Make this
function ($child)
If you don't pass $child as a reference, the line
$child-parent = $this;
will set the parent value of the clone that's passed as an argument, and
leave the original $child unmodified!
Crosscheck all of your class code (and the code utilizing it) it you're
always passing references. Ref's work like a charm until you mess up at a
single location. Well, having made my way from C/C++ to PHP I'd rather deal
with pointers, but unfortunately PHP doesn't have them. So keep an eye open .-)
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Graphics question
At 05:38 08.11.2002, Mike Mannakee said:
[snip]
Jeez, this is simple. The browser is caching the image. There's no real
way to fix that. There are some headers that may encourage the browser to
not cache, but there is no sure way to control whether the users will have
this setting overridden.
Or, as in a previous thread from yesterday, you could make the image url
look different by using random():
img src=http://your/imageurl.jpg??php echo random()?
You can also search for specifics of the headers that are meant to stop a
browser from caching.
No-cache MIME headers are:
header('Pragma: no-cache');
header('Cache: none');
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] publishing php mysql website on cd-rom
My organization has a need to publish some of our web content on a CD-ROM. I'm in search of suggestions on how to publish our dynamic content (php/mysql templates) in some sort of runtime configuration that would let users browse the site from cd. What's involved with this? Is there such a thing as runtime mySQL? What would it take to serve PHP from a CD? In my opinion the best is to use something like wget -r in Linux. -- Krzysztof Dziekiewicz -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Cookie error after 4.2.3 upgrade
I get the following error when using a previously working cookie function:
expects parameter 3 to be long
Code is below... I just don't see the difference then the way the doc uses:
time() - 3600
-vs- the way I did it below...
Thanks !
function f_put_cookie($user_name,$user_email,$account_type,$company_name) {
global $HTTP_COOKIE_VARS;
global $s_c_url;
$l_url = ..$s_c_url;
$l_cookie_expireN = date('r', time() - 4000 );
$l_cookie_expire = date('r', time() + 400 );
$l_cookie_expire2 = date('r', time() + 400*30*12 );
setcookie(c_user_email,,$l_cookie_expireN);
setcookie(c_user_email,$user_email,$l_cookie_expire2,'/',$l_url,0);
setcookie(c_user_name,$user_name,$l_cookie_expire,'/',$l_url,0);
setcookie(c_account_type,$account_type,$l_cookie_expire,'/',$l_url,0);
setcookie(c_company_name,$company_name,$l_cookie_expire,'/',$l_url,0);
setcookie(c_uas_time,
GREEN,$l_cookie_expire,'/',$l_url,0);
}
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Help w/ 4.2.3 Problem
Most likely a register_globals settings problem. Try checking the manual in the php.ini settings page for more info. Marco - php|architect -- The Monthly Magazine For PHP Professionals Come visit us on the web at http://www.phparch.com! On Fri, 2002-11-08 at 03:11, Jack Sasportas wrote: I have been running 4.1.2 fine, but decided to compile in the latest version 4.2.3. When I run some existing code that works perfect under 4.1.2, not only does the code not run properly, but there are no error messages in the error_log ( apache file ). also in php.ini I added log_errors = On, and error_log = php_log, but I never see any error messages. Running on RedHat 7.2 with apache_1.3.27, mod_ssl-2.8.12-1.3.27, openssl-0.9.6g, php-4.2.3. ( Again this all ran fine with php-4.1.2 ). Any ideas on where to start ? Thanks -- ___ Jack Sasportas Innovative Internet Solutions Phone 305.665.2500 Fax 305.665.2551 www.innovativeinternet.com www.web56.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] File locking problem
I'm having file locking problems. I'm using fopen() to write a file via FTP. At the end, I'm doing... fflush($fp); fclose($fp); ...and then I include it immediately after. But many times I only get part of what I wrote to the file, which suggests that it wasn't really flushed and closed properly. Do you use include or require. In such situation you should not use include. -- Krzysztof Dziekiewicz -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Cookie error after 4.2.3 upgrade
Jack Sasportas wrote:
I get the following error when using a previously working cookie
function: expects parameter 3 to be long
Code is below... I just don't see the difference then the way the doc
uses: time() - 3600
-vs- the way I did it below...
Thanks !
function
f_put_cookie($user_name,$user_email,$account_type,$company_name) {
global $HTTP_COOKIE_VARS;
global $s_c_url;
$l_url = ..$s_c_url;
$l_cookie_expireN = date('r', time() - 4000 );
$l_cookie_expire = date('r', time() + 400 );
$l_cookie_expire2 = date('r', time() + 400*30*12 );
time() - 3600 returns an integer. The date function returns a string. The
function setcookie expects an integer (or long) as parameter 3. There's your
problem, change your code to:
$l_cookie_expireN = (int) date('r', time() - 4000 );
$l_cookie_expire = (int) date('r', time() + 400 );
$l_cookie_expire2 = (int) date('r', time() + 400*30*12 );
HTH
Erwin
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Convert GIF to JPG with or without GD
The GD library bundled with PHP 4.3 can read gif images (but not write them) And imagejpeg allows to create the jpeg file. -- Krzysztof Dziekiewicz -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] XML in PHP on Apache (RH 7.3)
Hello its urgent problem! I need apache server with php supporting XML, i have read the manual and some posts how-to compile it ( http://www.php.net/manual/en/ref.xml.php ) i have download sources of expat and doing step-by-step instructions given in one of the posts ( *pfreet at trusolutions dot com* /16-Aug-1999 05:13 ) i have made expat and configure php with xml and make it , and also Apache. well it still doesn't work. Could somebody sent me precise, step by step instruction how to configure it and make working? i'm not sure: 1.where i should place unziped expat files 2.how make file (parameters) please help! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Convert GIF to JPG with or without GD
Yes... I've tried Image Magic , it's good for my work :) Now, I can resize/resample/reformat any kind of picture... thanks for all! :) Krzysztof Dziekiewicz [EMAIL PROTECTED] a écrit dans le message de news: [EMAIL PROTECTED] The GD library bundled with PHP 4.3 can read gif images (but not write them) And imagejpeg allows to create the jpeg file. -- Krzysztof Dziekiewicz -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Cookies and Sessions
Allo, I seem to have run into a couple of problems with a project I am currently working on. First one is that the project has a login feature that tracks the user using cookies. The client alas has a desire to have multiple sites and have the login to other sites in his group seamless (in as much as he would like no additional logging in). Since the login feature uses cookies this requirement isn't quite fulfilled... ok, let me be honest, it ain't filled one little bit! The one thing I do have in my favour is that all the sites (at the moment anyway) have the same SERVER_ADDR. Is there anyway I can set a cookie using and IP Address rather than a URL. I have tried this with little success (setting the path to ). As a side note, I would like to be able to use sessions more but I am running into some (very) peculiarities. I have a library which starts the session and then I regester variables till my heart is content. Trouble comes when I want to view them in another page... nada! If I do a 'session_is_registered' on the variable it returns true so it seems to have the sessions set up just not updating the values.. not sure. Now I can set up small two file proof of practice examples but when I integrate into my existing project code I suffer from all manner of wierdness .. the most notable being the complete lack of persistence. I know it is a bit of a shot in the dark in as much as I have provided little in the way of diagnostic information, but would any of you bright bunnies be able to give me some pointers as to what I might want to look into to get more of a clue as to what is going on? Cheers for any assistance Kevin TheConfused -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Reading unknown number of form variables -? need a hint/help..
Its something like:
$res=mysql_query(select item_id, quantity from carts where
customer_id='$customer_id');
// you might want to join with another table to get item names and
others you need
while(list($item_id,$quantity)=mysql_fetch_row($res)) {
echo input name=\quantity[$item_id]\ value=\$quantity\
}
input type=submit
on the next page:
foreach($_POST['quantity'] as $item_id = $quantity) {
mysql_query(update carts set quantity='$quantity' where
item_id='$item_id' and customer_id='$customer_id');
}
hope you get the general idea, all information you need (for any item),
that is item_id and its quantity
will be stored in one input field, then you need to loop the array and
update rows. You only need to get the
customer_id, best done with sessions
Paul wrote:
Hi All:
I have the following setup:
The page contains multiple rows (something like a shoping cart) that
consist of item_id, item_name, and item_quantity. Item Quantity is a
text box that can be adjusted. I have a button to update all items..( I
am using query and based on item_id I can update database..) The number
of rows varies.
My question is - I really do not know how to get variables and update
multiple items in a database..I think I need to somehow grab them and
place in array perhaps? I am really not sure..I do not want to reinvent
the wheel..can some one give me hint? Is there a piece of code that I
can look at it and learn from?
Any help would be greatly appreciated
Paul
PS I also would like to place a checkbox (in every row) in the event the
item must be deleted..
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] sockets
This is how sockets work, if you close the process holding the socket, the conection is closed. There is no function reopen_the_old_conection. You are not clear about what you are trying to achive, but maybe you should rethink your design. Gareth Thomas wrote: Hi, I am running 4.3.0pre2 on RH 7.2 and on Windows2k I am trying to implement a socket based client/server communication program with the server being on the Linux side and the current test client on windows (although it will be on Linux eventually). A series of commands is sent by the client side which consists of 2 PHP pages, the first with some buttons and the second that sends the button commands to the server using sockets. The problem I am finding is that it appears PHP closes the socket connection once the second script has ended and it returns back to the first. Is there anyway of keeping the socket 'open' or can someone suggest a better way of doing this... Thanks in advance -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] For ... = max($myArray) vs For ... = $max
Is PHP smart enough to optimize loops?
That is, are these two 'for...loops' equivalent or is one slower than
the other?
$max = max($myArray);
for( $x = 1; $x = $length; $x++ ) {}
-- OR --
for( $x = 1; $x = max($myArray); $x++ ) {}
My gut instinct tells me since PHP is interpreted, that the top one is
the better way to go, but with the Zend Optimizer, I don't know if PHP
handles them the same way or not?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] problem with memory_limit and php 4.2.3
Hi all,
the httpd - Process on my linux-box exits (no segfault)
when executing the following simple script with php 4.2.3.
I don't get the expected error message ( something like
'Allowed memory size of 512000 bytes exhausted').
=[test Script]===
?
ini_set (memory_limit, 512000); // 500kB
$aArray = array();
for ($i=0;$i(1024);$i++) {
for ($j=0;$j1024;$j++) $aArray[$i] .= x;
echo . sizeof($aArray);
}
?
[end of Script]==
The same script works fine under php4.0.6. What ist going on
here? Is it a problem with my linux box or with php4.2.3?
My configuration: suse Linux 2.4.10-4GB i386
=[php.ini]==
engine = On
short_open_tag = On
asp_tags = Off
precision= 14
y2k_compliance = Off
output_buffering = Off
output_handler =
zlib.output_compression = Off
implicit_flush = Off
allow_call_time_pass_reference = On
safe_mode = Off
safe_mode_exec_dir =
safe_mode_allowed_env_vars = PHP_
safe_mode_protected_env_vars = LD_LIBRARY_PATH
disable_functions =
expose_php = On
max_execution_time = 600 ; Maximum execution time of each script, in
seconds
memory_limit = 92M ; Maximum amount of memory a script may consume
(8MB)
error_reporting = E_ALL ~E_NOTICE
display_errors = On
display_startup_errors = Off
log_errors = On
track_errors = Off
[...some more stuff]
=
=[php configure-line]===
./configure --with-apxs --enable-sockets --enable-memory-limit
--with-mysql --with-xslt-sablot --with-sablot=/usr/local/lib
--with-expat=/usr/local/lib --with-ldap --with-ftp --enable-track-vars
--enable-trans-sid --with-zlib-dir=/usr/lib --with-ming
--with-oci8=/opt/oracle/OraHome1 --enable-xslt
-with-config-file-path=/etc/httpd2
==[ldd output]==
ldd /usr/local/lib/php4/libphp4.so
/opt/oracle/OraHome1/lib/libclntsh.so.8.0 =
/opt/oracle/OraHome1/lib/libclntsh.so.8.0 (0x40175000)
libdl.so.2 = /lib/libdl.so.2 (0x406f9000)
libpam.so.0 = /lib/libpam.so.0 (0x406fd000)
libsablot.so.0 = /usr/local/lib/libsablot.so.0 (0x40706000)
libexpat.so.0 = /usr/local/lib/libexpat.so.0 (0x407e8000)
libming.so = /usr/local/lib/libming.so (0x4080b000)
libldap.so.1 = /usr/lib/libldap.so.1 (0x4084c000)
liblber.so.1 = /usr/lib/liblber.so.1 (0x40861000)
libz.so.1 = /lib/libz.so.1 (0x40866000)
libcrypt.so.1 = /lib/libcrypt.so.1 (0x40875000)
libresolv.so.2 = /lib/libresolv.so.2 (0x408a2000)
libm.so.6 = /lib/libm.so.6 (0x408b4000)
libnsl.so.1 = /lib/libnsl.so.1 (0x408d6000)
libc.so.6 = /lib/libc.so.6 (0x408ed000)
libwtc8.so = /opt/oracle/OraHome1/lib/libwtc8.so (0x40a13000)
libpthread.so.0 = /lib/libpthread.so.0 (0x40a15000)
libstdc++-libc6.2-2.so.3 = /usr/lib/libstdc++-libc6.2-2.so.3
(0x40a2b000)
/lib/ld-linux.so.2 = /lib/ld-linux.so.2 (0x8000)
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] What am I missing with this code?
for($i=1;$i13;$i++) {
?
lia
href=categoryresult.php?condition=?=urlencode(where
month(UserDOB)= . $i)??=jdmonthname($i,0)?nbsp;(?=$i?)/a/li
?php
}
?
All it's printing out is November and December, even though the month is
incrementing.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Most current non-beta version, and bcc
-Original Message- From: Rick Widmer [mailto:php3;developersdesk.com] Sent: 08 November 2002 04:16 To: Jill S; [EMAIL PROTECTED] Subject: Re: [PHP] Most current non-beta version, and bcc At 02:38 PM 11/7/02 -0600, Jill S wrote: so again I'll ask - Are the 4.2.3 downloads at the top of the page at: http://www.php.net/downloads/ beta versions or non-beta versions? 4.2.3 is currently the latest stable released version of PHP. Yes, that means NOT BETA. Anything that makes it to the downloads page is stable code. 4.3.0 should be out soon, but is not yet considered stable. It has also passed the BETA state and is in its second pre-release final testing. Nope, I'd still class that as BETA-testing. Actually, I might even call it pre-BETA! When they actually get around to making Release Candidates available (as in 4.3.0RC1), I'd call that real BETA testing. I wonder how the members of the PHP development group themselves would class these? Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Quick question
-Original Message- From: Martin Towell [mailto:martin.towell;world.net] Sent: 08 November 2002 06:23 what is the technical difference between using else if Well, technically this starts a new block structure level... and elseif ... and this doesn't. But to all intents and purposes it probably doesn't make any real difference. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: fgetcsv and end of line in values
i solved my prob with the latest stable snap. php 4.2.4. [EMAIL PROTECTED] wrote in news:20021107092154.13278.qmail;pb1.pair.com: greetings, i have problems using fgetcsv to explode a .csv file. some values consist of line-breaks. although these values are enclosed by quotes, php recognizes the line-break and starts a new dataset. the script workes fine in my old environment (win2k, apache 1.3.23, php 4.1.1), the problem occures in my new environment (win2k, apache 2.0.43, php 4.3.0). maybe config-params? i mentioned a new enclusure-attribute in fgetcsv since php 4.3.0. but experimenting with this didn't succeed. i also tried some different syntaxes in the delimiter-attrib of fgetcsv, no success. does anybody have any suggestion? thx. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: Cookie error after 4.2.3 upgrade
-Original Message-
From: Erwin [mailto:erwin;isiz.com]
Sent: 08 November 2002 08:55
Jack Sasportas wrote:
I get the following error when using a previously working cookie
function: expects parameter 3 to be long
Code is below... I just don't see the difference then the
way the doc
uses: time() - 3600
-vs- the way I did it below...
Thanks !
function
f_put_cookie($user_name,$user_email,$account_type,$company_name) {
global $HTTP_COOKIE_VARS;
global $s_c_url;
$l_url = ..$s_c_url;
$l_cookie_expireN = date('r', time() - 4000 );
$l_cookie_expire = date('r', time() + 400 );
$l_cookie_expire2 = date('r', time() + 400*30*12 );
time() - 3600 returns an integer. The date function returns a
string. The
function setcookie expects an integer (or long) as parameter
3. There's your
problem, change your code to:
$l_cookie_expireN = (int) date('r', time() - 4000 );
$l_cookie_expire = (int) date('r', time() + 400 );
$l_cookie_expire2 = (int) date('r', time() + 400*30*12 );
No, that's even worse!! Try this:
$l_cookie_expireN = time() - 4000;
$l_cookie_expire = time() + 400;
$l_cookie_expire2 = time() + 400*30*12;
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] For ... = max($myArray) vs For ... = $max
-Original Message-
From: Daevid Vincent [mailto:daevid;daevid.com]
Sent: 08 November 2002 11:13
Is PHP smart enough to optimize loops?
That is, are these two 'for...loops' equivalent or is one slower than
the other?
$max = max($myArray);
for( $x = 1; $x = $length; $x++ ) {}
-- OR --
for( $x = 1; $x = max($myArray); $x++ ) {}
My gut instinct tells me since PHP is interpreted, that the top one is
the better way to go, but with the Zend Optimizer, I don't know if PHP
handles them the same way or not?
With bare PHP, yes the first one is quicker. Don't know if the Zend Optimiser changes
that.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] HTTP POST FILE UPLOAD HELP
Ok, I have a problem with my file upload. When I upload a file, say $img, only $img is available and when I echo $img to the screen it gives the full path of the temporary image supposedly created by PHP. Echoing $_FILE['img']['tmp_name'], or any of the other $_FILE array elements, doesn't give anything. There is no array of information for the uploaded file, possibly because of the following problem I'm having: Another weird thing is that no temporary file is even created on the server (I did a system search on the C: drive of the windows box I'm using). Here is the info from my php.ini file: --- ; File Uploads ; ; Whether to allow HTTP file uploads. file_uploads = On ; Temporary directory for HTTP uploaded files (will use system default if not ; specified). upload_tmp_dir = C:\PHP\tmp_uploads ; Maximum allowed size for uploaded files. upload_max_filesize = 6M I even changed the upload_tmp_dir setting to the default and it still didn't create a temporary file of the image on the server. GD is definately installed and enabled according to phpinfo() -- although GD has nothing to do with this. I'm uploading *.jpg/*.jpeg files only. register_globals is on (I am aware of the risks). So what could be wrong? Is there another setting in the php.ini file that I need to worry about that is not set by default? I've pondered and tested this long enough and I'm beyond frustration, someone please help me with some suggestions to get me through this... Thanks, - Darwin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] HTTP POST FILE UPLOAD HELP
Hi, Simple question first: There is a perfect working example of file uploads available on the PHP website in the manual. Can you get that example to work? Justin on 08/11/02 10:05 PM, @ Darwin ([EMAIL PROTECTED]) wrote: Ok, I have a problem with my file upload. When I upload a file, say $img, only $img is available and when I echo $img to the screen it gives the full path of the temporary image supposedly created by PHP. Echoing $_FILE['img']['tmp_name'], or any of the other $_FILE array elements, doesn't give anything. There is no array of information for the uploaded file, possibly because of the following problem I'm having: Another weird thing is that no temporary file is even created on the server (I did a system search on the C: drive of the windows box I'm using). Here is the info from my php.ini file: --- ; File Uploads ; ; Whether to allow HTTP file uploads. file_uploads = On ; Temporary directory for HTTP uploaded files (will use system default if not ; specified). upload_tmp_dir = C:\PHP\tmp_uploads ; Maximum allowed size for uploaded files. upload_max_filesize = 6M I even changed the upload_tmp_dir setting to the default and it still didn't create a temporary file of the image on the server. GD is definately installed and enabled according to phpinfo() -- although GD has nothing to do with this. I'm uploading *.jpg/*.jpeg files only. register_globals is on (I am aware of the risks). So what could be wrong? Is there another setting in the php.ini file that I need to worry about that is not set by default? I've pondered and tested this long enough and I'm beyond frustration, someone please help me with some suggestions to get me through this... Thanks, - Darwin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] For ... = max($myArray) vs For ... = $max
As max($myArray) may potentionaly change, it is evalueted everytime (you
may do
$myArray[]=$big_number in your loop). So if you know it is not going to
change, use the first way.
Daevid Vincent wrote:
Is PHP smart enough to optimize loops?
That is, are these two 'for...loops' equivalent or is one slower than
the other?
$max = max($myArray);
for( $x = 1; $x = $length; $x++ ) {}
-- OR --
for( $x = 1; $x = max($myArray); $x++ ) {}
My gut instinct tells me since PHP is interpreted, that the top one is
the better way to go, but with the Zend Optimizer, I don't know if PHP
handles them the same way or not?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] What am I missing with this code?
-Original Message-
From: John Meyer [mailto:johnmeyer_1978;yahoo.com]
Sent: 08 November 2002 11:45
for($i=1;$i13;$i++) {
?
lia
href=categoryresult.php?condition=?=urlencode(where
month(UserDOB)= .
$i)??=jdmonthname($i,0)?nbsp;(?=$i?)/a/li
?php
}
?
All it's printing out is November and December, even
though the month is
incrementing.
You don't seem to have grasped what a Julian day number is -- what you're producing
here is the monthname of 12 consecutive days in IIRC about 4000BC which presumably
just happen to fall in what would have been November and December had such months
existed in that year!
This is a case where I really must suggest you RTFM, as there is a perfecxt example of
what you want to do in the only user note at
http://www.php.net/manual/en/function.jdmonthname.php
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Cookie error after 4.2.3 upgrade
change your code to:
$l_cookie_expireN = (int) date('r', time() - 4000 );
$l_cookie_expire = (int) date('r', time() + 400 );
$l_cookie_expire2 = (int) date('r', time() + 400*30*12 );
No, that's even worse!! Try this:
$l_cookie_expireN = time() - 4000;
$l_cookie_expire = time() + 400;
$l_cookie_expire2 = time() + 400*30*12;
You're right of course, let's say that it was very early when I wrote that
answer ;-))
Grtz Erwin
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] HTTP POST FILE UPLOAD HELP
At 13:05 08.11.2002, Darwin spoke out and said: [snip] is the info from my php.ini file: ; Temporary directory for HTTP uploaded files (will use system default if not ; specified). upload_tmp_dir = C:\PHP\tmp_uploads [snip] I believe you must escape backslashes in php.ini as well... or simply use forward slashes. Try this setting: upload_tmp_dir = C:/PHP/tmp_uploads Also, if this is Win2K Server, make sure the ACL's are set correctly. Usually Apache runs as system, so make sure you're giving the system user full rights (or at least r/w/d) to this directory. -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/
Re: [PHP] For ... = max($myArray) vs For ... = $max
The first one is better, and, besides that - it is the most correct way
- there might be something making the array change while inside the loop
- thus you have to do some extremely high calculations to understand the
array does not change runtime, which makes it useless.
Simply do the elegant programming and you will never have these issues.
--
Maxim Maletsky
[EMAIL PROTECTED]
Ford, Mike [LSS] [EMAIL PROTECTED] wrote... :
-Original Message-
From: Daevid Vincent [mailto:daevid;daevid.com]
Sent: 08 November 2002 11:13
Is PHP smart enough to optimize loops?
That is, are these two 'for...loops' equivalent or is one slower than
the other?
$max = max($myArray);
for( $x = 1; $x = $length; $x++ ) {}
-- OR --
for( $x = 1; $x = max($myArray); $x++ ) {}
My gut instinct tells me since PHP is interpreted, that the top one is
the better way to go, but with the Zend Optimizer, I don't know if PHP
handles them the same way or not?
With bare PHP, yes the first one is quicker. Don't know if the Zend Optimiser
changes that.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Cookies and Sessions
kevin [EMAIL PROTECTED] wrote... : Allo, I seem to have run into a couple of problems with a project I am currently working on. First one is that the project has a login feature that tracks the user using cookies. The client alas has a desire to have multiple sites and have the login to other sites in his group seamless (in as much as he would like no additional logging in). You have very few things to do for solve it. One would be passing session id within the URL when jumping between the sites to then evaluate some session data. It is also the reasons large portal sites, when merging, add subdomains and lose their precious domains because subdomains can still share the cookies. Since the login feature uses cookies this requirement isn't quite fulfilled... ok, let me be honest, it ain't filled one little bit! And, even if you'd succeed it would be the greatest security risk. The one thing I do have in my favour is that all the sites (at the moment anyway) have the same SERVER_ADDR. Is there anyway I can set a cookie using and IP Address rather than a URL. I have tried this with little success (setting the path to ). Not sure, but I don't think you can - there are loads of sites sharing the same IPs. As a side note, I would like to be able to use sessions more but I am running into some (very) peculiarities. I have a library which starts the session and then I regester variables till my heart is content. Trouble comes when I want to view them in another page... nada! If I do a 'session_is_registered' on the variable it returns true so it seems to have the sessions set up just not updating the values.. not sure. Now I can set up small two file proof of practice examples but when I integrate into my existing project code I suffer from all manner of wierdness .. the most notable being the complete lack of persistence. You're probably missing something silly. Sessions do work ok. I know it is a bit of a shot in the dark in as much as I have provided little in the way of diagnostic information, but would any of you bright bunnies be able to give me some pointers as to what I might want to look into to get more of a clue as to what is going on? there are some articles on PHP Beginner regarding sessions and security - www.phpbeginner.com -- Maxim Maletsky [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to echo the end marker '?'
I'm just curious. Why do you want to echo within an echo? echo 'form action='.$PHP_SELF.''; will do the trick won't it? Unless I miss the point, I cannot see why you need to open new php tags for this? On Fri, 2002-11-08 at 14:25, Ernest E Vogelsinger wrote: At 12:15 08.11.2002, Philipp Bolliger spoke out and said: [snip] subject's allready my question ! I want to echo something like : form action = \,?php echo $PHP_SELF ? \ so that the action becomes ? echo $PHP_SELF ? !! But I can't figure out how to escape ? so that the interpreter doesn't take it as the end of the script ! Any idea ? [snip] Try echo 'form action=', '', '?', 'php echo $PHP_SELF', '?', '', ''; This should work (untested) -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] string to array
Hi all,
has anyone an elegant (and faster) way of converting 'string' to
array('s','t','r','i','n','g'), other then
for($i=0; $istrlen($string); $i++) $array[$i]=$string[$i];
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
Quick and Dirty:
?php
$string = 'hello how are you today';
$new_string = preg_split(/[\s]?/, $string);
print_r($new_string);
?
Timothy Hitchens (HiTCHO)
[EMAIL PROTECTED]
If you need PHP hosting with an experienced
support team 24/7 then email me today.
On Fri, 8 Nov 2002, Marek Kilimajer wrote:
Hi all,
has anyone an elegant (and faster) way of converting 'string' to
array('s','t','r','i','n','g'), other then
for($i=0; $istrlen($string); $i++) $array[$i]=$string[$i];
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
Hi,
Friday, November 8, 2002, 10:43:10 PM, you wrote:
MK Hi all,
MK has anyone an elegant (and faster) way of converting 'string' to
MK array('s','t','r','i','n','g'), other then
MK for($i=0; $istrlen($string); $i++) $array[$i]=$string[$i];
A string is already an array of chars
$string = 'string';
echo $string[0]; // will echo 's'
--
regards,
Tom
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
Tom Rogers wrote:
Hi,
Friday, November 8, 2002, 10:43:10 PM, you wrote:
Hi all,
has anyone an elegant (and faster) way of converting 'string' to
array('s','t','r','i','n','g'), other then
for($i=0; $istrlen($string); $i++) $array[$i]=$string[$i];
A string is already an array of chars
$string = 'string';
echo $string[0]; // will echo 's'
True, but that's different than the array type. Sometimes you'll just need
an array instead of a string.
Try using
$string = explode( '', 'string' );
Grtz Erwin
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
That won't work.. empty delimiter errors always.. you will have to use
my preg one from earlier...
Timothy Hitchens (HiTCHO)
[EMAIL PROTECTED]
If you need PHP hosting with an experienced
support team 24/7 then email me today.
On Fri, 8 Nov 2002, Erwin wrote:
Tom Rogers wrote:
Hi,
Friday, November 8, 2002, 10:43:10 PM, you wrote:
Hi all,
has anyone an elegant (and faster) way of converting 'string' to
array('s','t','r','i','n','g'), other then
for($i=0; $istrlen($string); $i++) $array[$i]=$string[$i];
A string is already an array of chars
$string = 'string';
echo $string[0]; // will echo 's'
True, but that's different than the array type. Sometimes you'll just need
an array instead of a string.
Try using
$string = explode( '', 'string' );
Grtz Erwin
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
String IS an array.
Basically, you could do this:
$str = 'The Dummy String';
for($i=0; $istrlen($str); $i++) {
echo $str[$i] . ':';
}
and you sould get the output:
T:h:e: :D:u:m:m:y: :S:t:r:i:n:g:
As of actually converting it you could do that very loop and have an:
$atr_arr[] = $str[$i] in it, or, even more elegantly by using split()
function or ...chunk.. something function(), don't remember right now.
--
Maxim Maletsky
[EMAIL PROTECTED]
Marek Kilimajer [EMAIL PROTECTED] wrote... :
Hi all,
has anyone an elegant (and faster) way of converting 'string' to
array('s','t','r','i','n','g'), other then
for($i=0; $istrlen($string); $i++) $array[$i]=$string[$i];
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird behaviour with references to objects...
with the reference you simply are re-refering the old internal values of the class. No, it is not reccomened to do so, unless, of course, you have a very good reason to. -- Maxim Maletsky [EMAIL PROTECTED] Martin Towell [EMAIL PROTECTED] wrote... : I remember reading somewhere (can't remember where though, maybe the php.net web site??) that if you use $this in a constructor (or any methods the constuctor calls), then you should instantiate the object using new otherwise you get a copy of the object that's just been created and not the actual new object (if that's not too confusing...) It's to do with the way the assignment operator works.. -Original Message- From: Tim Molendijk [mailto:tawm;wanadoo.nl] Sent: Friday, November 08, 2002 4:14 PM To: [EMAIL PROTECTED] Subject: Re: [PHP] Weird behaviour with references to objects... Hi all, First of all, thank you for the suggestions. Actually I accidently found a solution to the problem... Not that I understand it now, I just found a way to cope with it. By changing the first line of the first code snippet: $testContainer1 = new Container(TRUE); into: $testContainer1 = new Container(TRUE); the problem is gone! Don't ask me WHY this is the solution. In my Container-add() method I assign A REFERENCE of the Container object ($this) to $child-parent so I don't see why creating the Container object by reference is useful... If anyone has additional information on this subject feel free to post! Thanks everyone! Tim. Mike Mannakee [EMAIL PROTECTED] wrote in message news:20021108044622.68446.qmail;pb1.pair.com... This sounds like a matter that ought to make it to the programmers who code PHP itself. In the meantime can you code around it now that you know the bug is there? Mike Marco Tabini [EMAIL PROTECTED] wrote in message news:1036725595.21741.868.camel;localhost.localdomain... I'm not sure if my answer is going to be of much help, but I think this has to do with the way PHP handles references and copies of objects--it uses what I understand is a lazy copy mechanism, and thus the results on object manipulations can yield odd results. There was a discussion on a similar problem on PHP-DEV a while back--if you search the forums you should be able to find it. Hope this helps... Marco - php|architect -- The Monthly Magazine For PHP Professionals Come visit us on the web at http://www.phparch.com! On Thu, 2002-11-07 at 21:36, Tim Molendijk wrote: First of all I would like to say that I know this is a lot of text but I would be very pleased if you take a little time to read it nevertheless. The situation described below is not complicated at all... = Hello all, I'm dealing with this really weird problem which occurs when dealing with references within objects pointing to other objects. I'm trying to find out what it is now for a few days and I still don't get it. I minimised the code around the problem and it's weirder than ever. I would really appreciate it when you could take a look... I'm pretty experienced at PHP but perhaps you know something that I don't know. We have two different classes: Container and Child. Container objects contain a Child object in its $child property. A Child object has a $parent property, which contains a *reference* to the Container object by which it is held. So $containerObject should be the *same* as $containerObject-child-parent. To test this Container objects have a $property property. When changing this property the difference between one object and identical/cloned objects becomes visible. Now take a look at the following code. The indented text is code, the rest are comments. The code for the class Container and class Child are also included. Please scroll down or take a look at the attached file. begin first code snippet ?php /* New Container object created. At the same time it sets a Child object in its $child attribute. (This is indicated by passing TRUE.) */ $testContainer1 = new Container(TRUE); /* The Container object is created, the Child object is set and its reference to the Container object is set. Now it prints $testContainer1-property and $testContainer-child-parent-property. These should have an identical value because they should be from the same object (not cloned/identical, but the same). This is the result: property = 'state 1' child-parent-property = 'state 1' So this is as expected, no problem... yet. */ $testContainer1-printState(); /* Now $testContainer1's $property property is changed into another value. /*
Re: [PHP] string to array
Erwin [EMAIL PROTECTED] wrote... : A string is already an array of chars $string = 'string'; echo $string[0]; // will echo 's' True, but that's different than the array type. Sometimes you'll just need an array instead of a string. Try using $string = explode( '', 'string' ); I think this will fail. There is a function just for that, don't remember right now what it was. -- Maxim Maletsky [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
Hello,
Maxim Maletsky [EMAIL PROTECTED] wrote:
[snip]
As of actually converting it you could do that very loop and have an:
$atr_arr[] = $str[$i] in it, or, even more elegantly by using split()
function or ...chunk.. something function(), don't remember right now.
[/snip]
Perhaps, this would remind you... :)
?php
$str = 'string';
$chars = preg_split('//', $str, -1, PREG_SPLIT_NO_EMPTY);
print_r($chars);
?
That was from the manual:
http://www.php.net/manual/en/function.preg-split.php
- E
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
$string = explode( '', 'string' );
Timothy Hitchens wrote:
That won't work.. empty delimiter errors always..
Your right, I didn't know.
you will have to use
my preg one from earlier...
But your preg thingy will only split at spaces, so that'll have to change to
?
$string = 'test';
preg_split('//', $string, -1, PREG_SPLIT_NO_EMPTY);
?
in this case, right?
Grtz Erwin
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to echo the end marker '?'
Hello, (B (B"Petre Agenbag" [EMAIL PROTECTED] wrote: (B I'm just curious. (B (BMe, too. :) (B (B Why do you want to echo within an echo? (B echo 'form action="'.$PHP_SELF.'"'; (B will do the trick won't it? (B (BTrue. (B (B Unless I miss the point, I cannot see why you need to open new php tags (B for this? (B (BBut, if there's a special reason... (B (B echo $PHP_SELF ? !! But I can't figure out how to escape ? so that (Bthe (Binterpreter doesn't take it as the end of the script ! Any idea ? (B (BWell, we can use lt; instead of and gt; instead of , etc... (B (B- E (B (B...[snip]... (B (B-- (BPHP General Mailing List (http://www.php.net/) (BTo unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
This is working great, thank you.
Timothy's expression output one empty element at the start and the end,
but otherwise worked ( and
I don't know why :-(
Erwin wrote:
$string = explode( '', 'string' );
Timothy Hitchens wrote:
That won't work.. empty delimiter errors always..
Your right, I didn't know.
you will have to use
my preg one from earlier...
But your preg thingy will only split at spaces, so that'll have to change to
?
$string = 'test';
preg_split('//', $string, -1, PREG_SPLIT_NO_EMPTY);
?
in this case, right?
Grtz Erwin
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] string to array
Guys, not to confuse you, but I think there is a more elegant way doing
it that. I had the same issue once long ago (2-3 years ago?) and had put
it up on the mailing lists too.
Gotta remember what it was and for what project then find the code in my
libraries. I really think i accomplished it without preg_split()...
--
Maxim Maletsky
[EMAIL PROTECTED]
@ Edwin [EMAIL PROTECTED] wrote... :
Hello,
Maxim Maletsky [EMAIL PROTECTED] wrote:
[snip]
As of actually converting it you could do that very loop and have an:
$atr_arr[] = $str[$i] in it, or, even more elegantly by using split()
function or ...chunk.. something function(), don't remember right now.
[/snip]
Perhaps, this would remind you... :)
?php
$str = 'string';
$chars = preg_split('//', $str, -1, PREG_SPLIT_NO_EMPTY);
print_r($chars);
?
That was from the manual:
http://www.php.net/manual/en/function.preg-split.php
- E
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Convince teh boss
Very interesting! Thanks! I'm sure the list will be very useful. ;) BTW, perhaps you can add apple.com to your list. (Apache, Linux--should be BSD...) - E -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Unable to execute c++ .exe file from php
I am unable to execute my c++ program from within PHP when it runs as a cgi in Apache. I am able to run: $cmd=dir c:\abc system ($cmd, $errCode); and see the content of the directory, but I don't seem to be able to run a simple hello.exe (c++) file. $cmd = c:\abc\hello.exe; system ($cmd, $errCode); The errCode always comes back with 128. What does 128 mean? Here is some info on my setup. OS: Windows XP Server: Apache 2.0.43 (win32) PHP 4.2.3 I am running PHP as a CGI I am able to execute my c++ program (hello.exe) from this .php file just fine if I use the PHP cli. I appreciate any help. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Wildcard search
I've tried doing a search for this problem on the web, but haven't found anything, nor have I found any solution on the php.net documentation. Does anyone know if it's possible to do a file search with a wildcard character? I need to find if there are any HTML files in a certain directory, but file_exists(htmls/*.html) doesn't seem to work when tested. Neither do similar applications of readdir(). Is there another way to do this, or do I have to do a readdir() and read the filename of every file until I find an HTML or until all files have been read. - Do you Yahoo!? U2 on LAUNCH - Exclusive medley videos from Greatest Hits CD
Re: [PHP] Wildcard search
How about:
$a = explode (' ', shell_exec (ls $foldername/*.html));
This should return an array that contains the name of all the *.html
files in the folder $foldername, if any.
Hope this helps.
Cheers,
Marco
-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!
On Fri, 2002-11-08 at 09:34, Mako Shark wrote:
I've tried doing a search for this problem on the web, but haven't found anything,
nor have I found any solution on the php.net documentation.
Does anyone know if it's possible to do a file search with a wildcard character? I
need to find if there are any HTML files in a certain directory, but
file_exists(htmls/*.html) doesn't seem to work when tested. Neither do similar
applications of readdir(). Is there another way to do this, or do I have to do a
readdir() and read the filename of every file until I find an HTML or until all files
have been read.
-
Do you Yahoo!?
U2 on LAUNCH - Exclusive medley videos from Greatest Hits CD
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ob_gzhandler
I get no output at all.
All DoCache does is write $buffer to a file then return $buffer since I use
this for some other serverside caching to save on database hits.
I have other areas that I call ob_start(ob_gzhandler) and that works fine
but when I call in via DoCache it breaks.
I much prefer your idea of mod_deflate. I will look into that since I
believe that belongs in apache rather than a PHP program also.
I am still curious why it doesn't work though.
Here is my True DoCache function:
function docache ($buffer) {
$fp=fopen(cachefilename(), w);
if($fp)
fputs($fp,$buffer);
return ob_gzhandler($buffer);
}
cachefilename() simply returns an MD5 of the requested URI.
This will return a blank webpage in IE and Mozilla. When I take out
ob_gzhandler it then works fine.
Thanks,
Serge.
- Original Message -
From: Ernest E Vogelsinger [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 08, 2002 4:00 AM
Subject: Re: [PHP] ob_gzhandler
At 07:45 08.11.2002, Serge Paquin said:
[snip]
Hello,
Is their anyway to use ob_gzhandler along with another callback?
I've
tried the following which does not work:
function DoCache($buffer) {
/* Do a bunch of stuff */
return ob_gzhandler($buffer);
}
ob_start(DoCache);
What do you mean by does not work? Does it output nothing, or can't
you
see any compressed data?
1) output is empty
Must be an error in your DoCache() function - check the buffer you're
passing to ob_gzhandler() by writing it to a file (you can't echo it
here...)
2) you don't see compressed output
2.a) That's how it is designed. ob_gzhandler checks the request headers to
see if the browser supports any of the compressed formats (gzip, deflate),
and if it doesn't find it then it simply does nothing.
2.b) PHP needs to be compiled using --with-zlib to provide ob_gzhandler
support. You don't get any error if you don't have zlib configured. Check
phpinfo() to see if zlib support is available.
Personal hint:
If you're using the url_rewriter.tags and have session cookies disabled,
ob_gzhandler will break this. The reason is that PHP parses the
_very_final_ output to mangle the session identifier to any (local) url;
in
case this _very_final_ output is compressed ir can't find any link and
can't merge the session identifier.
I personally believe it's better to have compression be done at the web
server (refer to http://httpd.apache.org/docs-2.0/mod/mod_deflate.html).
It's more general then, after all...
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Unable to execute c++ .exe file from php
escape your backslashes: $cmd = c:\\abc\\hello.exe; Ladan Pickering wrote: I am unable to execute my c++ program from within PHP when it runs as a cgi in Apache. I am able to run: $cmd=dir c:\abc system ($cmd, $errCode); and see the content of the directory, but I don't seem to be able to run a simple hello.exe (c++) file. $cmd = c:\abc\hello.exe; system ($cmd, $errCode); The errCode always comes back with 128. What does 128 mean? Here is some info on my setup. OS: Windows XP Server: Apache 2.0.43 (win32) PHP 4.2.3 I am running PHP as a CGI I am able to execute my c++ program (hello.exe) from this .php file just fine if I use the PHP cli. I appreciate any help. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Unable to execute c++ .exe file from php
At 15:30 08.11.2002, Ladan Pickering spoke out and said: [snip] I am unable to execute my c++ program from within PHP when it runs as a cgi in Apache. I am able to run: $cmd=dir c:\abc system ($cmd, $errCode); and see the content of the directory, but I don't seem to be able to run a simple hello.exe (c++) file. $cmd = c:\abc\hello.exe; system ($cmd, $errCode); [snip] I think you need to either escape the backslash (like c:\\abc\\hello.exe), or simply use forward slashes (as c:/abc/hello.exe). -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/
RE: [PHP] Wildcard search
-Original Message- From: Mako Shark [mailto:phpman2000;yahoo.com] do I have to do a readdir() and read the filename of every file until I find an HTML or until all files have been read. This is what the shell expression supplied by Marco Tabini actually does; doing it in PHP (readdir(), etc.) eliminates the exec of the shell process and is faster (readdir() is a thin veneer on the readdir system call) and the problem of portability if you want to use this on both Unix and Windows. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ob_gzhandler
I just realized that mod_deflate is for Apache 2. I am still on the
Apache 1.3 tree so I don't beleive I can take advantage.
- Original Message -
From: Ernest E Vogelsinger [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 08, 2002 4:00 AM
Subject: Re: [PHP] ob_gzhandler
At 07:45 08.11.2002, Serge Paquin said:
[snip]
Hello,
Is their anyway to use ob_gzhandler along with another callback?
I've
tried the following which does not work:
function DoCache($buffer) {
/* Do a bunch of stuff */
return ob_gzhandler($buffer);
}
ob_start(DoCache);
What do you mean by does not work? Does it output nothing, or can't
you
see any compressed data?
1) output is empty
Must be an error in your DoCache() function - check the buffer you're
passing to ob_gzhandler() by writing it to a file (you can't echo it
here...)
2) you don't see compressed output
2.a) That's how it is designed. ob_gzhandler checks the request headers to
see if the browser supports any of the compressed formats (gzip, deflate),
and if it doesn't find it then it simply does nothing.
2.b) PHP needs to be compiled using --with-zlib to provide ob_gzhandler
support. You don't get any error if you don't have zlib configured. Check
phpinfo() to see if zlib support is available.
Personal hint:
If you're using the url_rewriter.tags and have session cookies disabled,
ob_gzhandler will break this. The reason is that PHP parses the
_very_final_ output to mangle the session identifier to any (local) url;
in
case this _very_final_ output is compressed ir can't find any link and
can't merge the session identifier.
I personally believe it's better to have compression be done at the web
server (refer to http://httpd.apache.org/docs-2.0/mod/mod_deflate.html).
It's more general then, after all...
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ob_gzhandler
At 15:48 08.11.2002, Serge Paquin spoke out and said:
[snip]
I get no output at all.
All DoCache does is write $buffer to a file then return $buffer since I use
this for some other serverside caching to save on database hits.
I have other areas that I call ob_start(ob_gzhandler) and that works fine
but when I call in via DoCache it breaks.
I much prefer your idea of mod_deflate. I will look into that since I
believe that belongs in apache rather than a PHP program also.
I am still curious why it doesn't work though.
Here is my True DoCache function:
function docache ($buffer) {
$fp=fopen(cachefilename(), w);
if($fp)
fputs($fp,$buffer);
return ob_gzhandler($buffer);
}
cachefilename() simply returns an MD5 of the requested URI.
This will return a blank webpage in IE and Mozilla. When I take out
ob_gzhandler it then works fine.
[snip]
It seems to me your ob_gzhandler is broken... anyway, since PHP 4.0.3 the
output callback function has a second parameter called mode, even if you
don't do anythiong with it you should pass it on:
function docache ($buffer, $mode) {
$fp=fopen(cachefilename(), w);
if($fp)
fputs($fp,$buffer);
return ob_gzhandler($buffer, $mode);
}
But I doubt this would change anything here... ob_gzhandler _should_ return
some value. You have some output in the file do you?
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
Re: [PHP] ob_gzhandler
Yes their is always output.
Also the way my system works if it finds a current cache file then it just does
readfile and no database connection.
On that output I use ob_start(ob_gzhandler) and it outputs compressed without an
error so it seems that ob_gzhandler is working fine that's the part that gets me.
Serge.
On Fri, 08 Nov 2002 15:58:12 +0100
Ernest E Vogelsinger [EMAIL PROTECTED] wrote:
At 15:48 08.11.2002, Serge Paquin spoke out and said:
[snip]
I get no output at all.
All DoCache does is write $buffer to a file then return $buffer since I use
this for some other serverside caching to save on database hits.
I have other areas that I call ob_start(ob_gzhandler) and that works fine
but when I call in via DoCache it breaks.
I much prefer your idea of mod_deflate. I will look into that since I
believe that belongs in apache rather than a PHP program also.
I am still curious why it doesn't work though.
Here is my True DoCache function:
function docache ($buffer) {
$fp=fopen(cachefilename(), w);
if($fp)
fputs($fp,$buffer);
return ob_gzhandler($buffer);
}
cachefilename() simply returns an MD5 of the requested URI.
This will return a blank webpage in IE and Mozilla. When I take out
ob_gzhandler it then works fine.
[snip]
It seems to me your ob_gzhandler is broken... anyway, since PHP 4.0.3 the
output callback function has a second parameter called mode, even if you
don't do anythiong with it you should pass it on:
function docache ($buffer, $mode) {
$fp=fopen(cachefilename(), w);
if($fp)
fputs($fp,$buffer);
return ob_gzhandler($buffer, $mode);
}
But I doubt this would change anything here... ob_gzhandler _should_ return
some value. You have some output in the file do you?
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ob_gzhandler
At 16:08 08.11.2002, Serge Paquin spoke out and said:
[snip]
Yes their is always output.
Also the way my system works if it finds a current cache file then it just
does readfile and no database connection.
On that output I use ob_start(ob_gzhandler) and it outputs compressed
without an error so it seems that ob_gzhandler is working fine that's the
part that gets me.
[snip]
Hmm - one glitch comes to my mind - maybe you need to close the buffer file
before passing the buffer to ob_gzhandler?
function docache ($buffer, $mode) {
$fp=fopen(cachefilename(), w);
if($fp) {
fputs($fp,$buffer);
fclose($fp);
}
return ob_gzhandler($buffer, $mode);
}
But I believe the problem must be somewhere in the outer logic - the
callback you showed doesn't do any discrimination if it has a cache file or
not. Check here, I'd suggest...
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
[PHP] How to echo the end marker '?'
Hi everyone, subject's allready my question ! I want to echo something like : form action = \,?php echo $PHP_SELF ? \ so that the action becomes ? echo $PHP_SELF ? !! But I can't figure out how to escape ? so that the interpreter doesn't take it as the end of the script ! Any idea ? cheers, phibo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to echo the end marker '?'
At 12:15 08.11.2002, Philipp Bolliger spoke out and said: [snip] subject's allready my question ! I want to echo something like : form action = \,?php echo $PHP_SELF ? \ so that the action becomes ? echo $PHP_SELF ? !! But I can't figure out how to escape ? so that the interpreter doesn't take it as the end of the script ! Any idea ? [snip] Try echo 'form action=', '', '?', 'php echo $PHP_SELF', '?', '', ''; This should work (untested) -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/
[PHP] Other Notice problem...
This is not the same question i asked yesterday. When i set error_reporting = E_ALL and display_errors = On in my php.ini, i get the next message: Notice: Undefined variable: varname in . How can i fix this problem without setting error_reporting = E_ALL ~E_NOTICE and/or display_errors = Off, or what way do you think is the best to resolve this problem? Thanks, RB _ Charla con tus amigos en línea mediante MSN Messenger: http://messenger.microsoft.com/es -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
This usually means that you're using a variable without having initialized it. For example $a = $b + 1; will give you that warning if no value is assigned to $b prior to this line. It's PHP's way of telling you that you might be doing something wrong. Perhaps if you post some of your code we can help better? Marco - php|architect -- The Monthly Magazine For PHP Professionals Come visit us on the web at http://www.phparch.com! On Fri, 2002-11-08 at 10:31, R B wrote: This is not the same question i asked yesterday. When i set error_reporting = E_ALL and display_errors = On in my php.ini, i get the next message: Notice: Undefined variable: varname in . How can i fix this problem without setting error_reporting = E_ALL ~E_NOTICE and/or display_errors = Off, or what way do you think is the best to resolve this problem? Thanks, RB _ Charla con tus amigos en línea mediante MSN Messenger: http://messenger.microsoft.com/es -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
At 16:31 08.11.2002, R B spoke out and said:
[snip]
This is not the same question i asked yesterday.
When i set error_reporting = E_ALL and display_errors = On in my php.ini,
i get the next message:
Notice: Undefined variable: varname in .
How can i fix this problem without setting error_reporting = E_ALL
~E_NOTICE and/or display_errors = Off, or what way do you think is the best
to resolve this problem?
[snip]
But it's the same answer ;-)
If you want to be completely warning-and-notice-free, you need to define
the variable before accessing it:
// this will give a notice
echo $undefined_var;
// and this won't
$define_var = 'some data, or simply put null here';
echo $defined_var;
The same holds true for array indices:
$test_array = array('One', 'Two', 'Three');
// this will give a notice
echo $test_array[3];
// and this won't
echo $test_array[2];
// and this won't as well
if (array_key_exists(3))
echo $test_array[3];
Get the idea? IMHO it's complete overkill with PHP to predefine variables
since they're auto-initialized with NULL when used first. These notices are
only for the development cycle, to aid us in spotting a problem where you
expect some data to be there, but it aint because the variable name has
been mistyped...
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
Re: [PHP] Weird behaviour with references to objects...
Ernest E Vogelsinger [EMAIL PROTECTED] wrote in message
news:5.1.1.6.2.20021108092657.02befe20;mail.vogelsinger.at...
At 03:36 08.11.2002, Tim Molendijk said:
[snip]
Ahh - culprit 1:
You said the container is creating a child instance - I assume it's done
in
the constructor...
What you're doing here is to create a clone when assigning new()'s result
to $testContainer1. You should rather
$testContainer1 = new Container(TRUE);
Note the ampersand here - if you don't you'll get a clone.
Rule for references:
If your object does something in its constructor, use a reference
assignment for
new class()
Ernest,
Before your post I accidently found out a solution:
$testContainer1 = new Container(TRUE) instead of $testContainer1 = new
Container(TRUE);
When I found this out I didn't understand WHY this was the solution...
Thanks to your comments I DO understand why... I suddenly see every jigsaw
piece fall in place :D
The difference between the first code snippet (that with $testContainer1)
and the second code snippet (that with $testContainer2) is that in code
snippet 2 the Container object is already constructed and assigned to
$testContainer2 when loading it. Then when it is loaded $this (in add())
refers to the object in $testContainer2 so no problem occurs.
But in code snippet 1 the Container object loads itself before it is
assigned to $testContainer1. During this process $this (in add()) refers to
the object that is being created. And now the core is: the object that is
being created is *not* the same object as the one that is assigned to
$testContainer1!! So the references to the created object will not refer to
$testContainer1!! That's it!!! I completely understand... Thanks a lot
Ernest!
Again - make this
$newChild = new Child(1);
But you don't pass $child by reference! Make this
function ($child)
If you don't pass $child as a reference, the line
$child-parent = $this;
will set the parent value of the clone that's passed as an argument, and
leave the original $child unmodified!
This is not true in my case, because instead of doing:
function add($child) { ... }
I do:
function add($child) { ... }
and then call it with:
$this-add($child);
This has the same result... As far as I know I doesn't matter whether you
put an ampersand before the variable in your function definition or your in
your function call.
Crosscheck all of your class code (and the code utilizing it) it you're
always passing references. Ref's work like a charm until you mess up at a
single location. Well, having made my way from C/C++ to PHP I'd rather
deal
with pointers, but unfortunately PHP doesn't have them. So keep an eye
open .-)
The problem is solved and I completely understand why now. This last thing
is thanks to you Ernest.
Regards,
Tim
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] File locking problem
Krzysztof Dziekiewicz wrote... Do you use include or require. In such situation you should not use include. I tried require() too, but it made no difference. I later learned that if you fopen(), write some stuff, fflush() and ffclose(), that doesn't mean the file is complete (or that it even exists). This has to be a PHP bug, which I'd be happy to file if someone more experienced could confirm that it isn't stupid user error. For a workaround, after I fflush() and fclose() I while() until the file exists, and then while() until it's larger than 10 bytes. I should while() until it's the size of the data I've written, but this method has been reliable so far. -- Charles Wiltgen Well, once again my friend, we find that science is a two-headed beast. One head is nice, it gives us aspirin and other modern conveniences... but the other head of science is bad! Oh beware the other head of science...it bites! -- The Tick -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird behaviour with references to objects...
At 16:48 08.11.2002, Tim Molendijk spoke out and said: [snip] The problem is solved and I completely understand why now. This last thing is thanks to you Ernest. [snip] Glad it works - you're very welcome :) -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/
Re: [PHP] Weird behaviour with references to objects...
One more:
At 16:48 08.11.2002, Tim Molendijk spoke out and said:
[snip]
This is not true in my case, because instead of doing:
function add($child) { ... }
I do:
function add($child) { ... }
and then call it with:
$this-add($child);
This has the same result... As far as I know I doesn't matter whether you
put an ampersand before the variable in your function definition or your in
your function call.
[snip]
True for now, but this is officially deprecated. Functions or methods
accepting a reference are required to be prototyped that way - this helps
you not to forget to pass by reference. You really should modify your
functions using reference parameters when declaring them, if you're using
references...
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
Re: [PHP] PHP fopen() bug + solution
Ernest, To be more effective, and to allow the OS to do something else while you're waiting at the file, your script should sleep for some microseconds... An excellent suggestion, thanks very much! :^) -- Charles Wiltgen -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] File locking problem
At 16:50 08.11.2002, Charles Wiltgen spoke out and said: [snip] I tried require() too, but it made no difference. I later learned that if you fopen(), write some stuff, fflush() and ffclose(), that doesn't mean the file is complete (or that it even exists). This has to be a PHP bug, which I'd be happy to file if someone more experienced could confirm that it isn't stupid user error. [snip] I don't believe it has something to do with PHP, much more with the FTP server you're accessing... This might delay the actual flushing for what reason ever. I don't believe PHP buffers files differently if they are accessed using an fopen url wrapper. -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/
Re: [PHP] For ... = max($myArray) vs For ... = $max
Friday, November 8, 2002, 12:13:01 PM, Daevid Vincent wrote:
$max = max($myArray);
for( $x = 1; $x = $length; $x++ ) {}
-- OR --
for( $x = 1; $x = max($myArray); $x++ ) {}
My gut instinct tells me since PHP is interpreted, that the top one is
the better way to go, but with the Zend Optimizer, I don't know if PHP
handles them the same way or not?
The first one is faster, but it depends on the site of the array and how
often you call the loop. I prefer doing it like this though:
for($x = 1, $max = count($myArray); $x = $max; $x++ ) {}
For some good optimization (and other) tips check out:
http://phplens.com/lens/php-book/optimizing-debugging-php.php
http://www.lerdorf.com/tips.pdf
--
Kjartan [EMAIL PROTECTED] (http://natrak.net/)
:: Silence is one great art of conversation.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird behaviour with references to objects...
Ernest E Vogelsinger [EMAIL PROTECTED] wrote in message
news:5.1.1.6.2.20021108165218.03238948;mail.vogelsinger.at...
One more:
True for now, but this is officially deprecated. Functions or methods
accepting a reference are required to be prototyped that way - this
helps
you not to forget to pass by reference. You really should modify your
functions using reference parameters when declaring them, if you're using
references...
Yes I know it is poor programming habits to do like I did... But I have a
reason for it. I have quite a lot methods that accept objects *optional*. So
f.e.:
---
class Product
{
var $language;
function Product($language = FALSE)
{
$this-language = $language;
}
}
---
Now to make this possible it becomes impossible to do what you suggest:
function Product($language = FALSE)
is not allowed. And in my application this optional arguments functionality
is very important. So I have preferred this over the decent habit.
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
My code is:
?php
some code.
if ($status == ADD) {
some code ...
...
...
}
?
The message is: Notice: Undefined variable: status in
I'm going to explain how my script work.
I have an php page (addProduct.php) with an input form. I have 2 buttons
(add and cancel) and a hidden control with name=status. If i press the add
button, the page submit the form data to the same page (form
action=addProduct.php) with status hidden control name set to ADD, so the
if statement its true only if i press the add button.
I see the message when i call the page to add the data not when i submit the
data.
How can i fix the problem? or there is another best way to do this?
From: Marco Tabini [EMAIL PROTECTED]
To: R B [EMAIL PROTECTED]
CC: [EMAIL PROTECTED]
Subject: Re: [PHP] Other Notice problem...
Date: 08 Nov 2002 10:25:46 -0500
This usually means that you're using a variable without having
initialized it. For example
$a = $b + 1;
will give you that warning if no value is assigned to $b prior to this
line. It's PHP's way of telling you that you might be doing something
wrong.
Perhaps if you post some of your code we can help better?
Marco
-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!
On Fri, 2002-11-08 at 10:31, R B wrote:
This is not the same question i asked yesterday.
When i set error_reporting = E_ALL and display_errors = On in my
php.ini,
i get the next message:
Notice: Undefined variable: varname in .
How can i fix this problem without setting error_reporting = E_ALL
~E_NOTICE and/or display_errors = Off, or what way do you think is the
best
to resolve this problem?
Thanks,
RB
_
Charla con tus amigos en línea mediante MSN Messenger:
http://messenger.microsoft.com/es
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
_
MSN. Más Útil Cada Día http://www.msn.es/intmap/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird behaviour with references to objects...
At 17:04 08.11.2002, Tim Molendijk spoke out and said:
[snip]
Yes I know it is poor programming habits to do like I did... But I have a
reason for it. I have quite a lot methods that accept objects *optional*. So
f.e.:
---
class Product
{
var $language;
function Product($language = FALSE)
{
$this-language = $language;
}
}
---
Now to make this possible it becomes impossible to do what you suggest:
function Product($language = FALSE)
is not allowed. And in my application this optional arguments functionality
is very important. So I have preferred this over the decent habit.
[snip]
You might always simply omit the parameter when calling the function
(you'll get a notice about that if enabled). You just cannot pass constants:
function Product($language)
{
...
}
// ok, but gives a notice
Product();
// will fail
Product('ger');
If you keep your code like it is be warned that it may break with a future
version of PHP.
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
Re: [PHP] Other Notice problem...
Try
if (isset ($status) $status == 'ADD')
instead... this should take care of the error--IF you're sure that the
fact that the $status variable is not set at that point is ok.
Marco
-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!
On Fri, 2002-11-08 at 11:04, R B wrote:
My code is:
?php
some code.
if ($status == ADD) {
some code ...
...
...
}
?
The message is: Notice: Undefined variable: status in
I'm going to explain how my script work.
I have an php page (addProduct.php) with an input form. I have 2 buttons
(add and cancel) and a hidden control with name=status. If i press the add
button, the page submit the form data to the same page (form
action=addProduct.php) with status hidden control name set to ADD, so the
if statement its true only if i press the add button.
I see the message when i call the page to add the data not when i submit the
data.
How can i fix the problem? or there is another best way to do this?
From: Marco Tabini [EMAIL PROTECTED]
To: R B [EMAIL PROTECTED]
CC: [EMAIL PROTECTED]
Subject: Re: [PHP] Other Notice problem...
Date: 08 Nov 2002 10:25:46 -0500
This usually means that you're using a variable without having
initialized it. For example
$a = $b + 1;
will give you that warning if no value is assigned to $b prior to this
line. It's PHP's way of telling you that you might be doing something
wrong.
Perhaps if you post some of your code we can help better?
Marco
-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!
On Fri, 2002-11-08 at 10:31, R B wrote:
This is not the same question i asked yesterday.
When i set error_reporting = E_ALL and display_errors = On in my
php.ini,
i get the next message:
Notice: Undefined variable: varname in .
How can i fix this problem without setting error_reporting = E_ALL
~E_NOTICE and/or display_errors = Off, or what way do you think is the
best
to resolve this problem?
Thanks,
RB
_
Charla con tus amigos en línea mediante MSN Messenger:
http://messenger.microsoft.com/es
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
_
MSN. Más Útil Cada Día http://www.msn.es/intmap/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
At 17:04 08.11.2002, R B spoke out and said:
[snip]
I'm going to explain how my script work.
I have an php page (addProduct.php) with an input form. I have 2 buttons
(add and cancel) and a hidden control with name=status. If i press the add
button, the page submit the form data to the same page (form
action=addProduct.php) with status hidden control name set to ADD, so the
if statement its true only if i press the add button.
I see the message when i call the page to add the data not when i submit the
data.
[snip]
Ahhh your $status variable should be a form variable? Well, as pointed
out many times the last days, register_globals is OFF by default since PHP
v.4.something. Either turn register_globals on in your PHP.ini (bad and
deprecated, read the security bulletins), or you refer to the _POST array:
if ($_POST['status'] == ADD)
if the data is not set (the status control empty), you'll still get a
notice about an undefined array index, so you might
if (array_key_exists('status', $_POST)) {
switch ($_POST['status']) {
case 'ADD':
break;
default:
echo 'Unsupported status!';
}
}
else echo 'No status sent!';
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
Re: [PHP] Wildcard search
$a = explode (' ', shell_exec (ls $foldername/*.html));
Didn't know of shell_exec() until now. It works, though. Thanks!
Is there any reason why it wouldn't work? If I changed servers, say, and there were
some ports blocked and etc. etc., is there a risk that I should know?
-
Do you Yahoo!?
U2 on LAUNCH - Exclusive medley videos from Greatest Hits CD
Re: [PHP] Wildcard search
Well, as a general rule, it won't work if you're not using a UNIX o/s or
if PHP has been set up with safe mode on, or if you don't have the right
permission to see that folder. That's probably a non-inclusive list, but
there should be ways around each of these problems (depending on the
degree of control you have over the server).
Marco
-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!
On Fri, 2002-11-08 at 11:14, Mako Shark wrote:
$a = explode (' ', shell_exec (ls $foldername/*.html));
Didn't know of shell_exec() until now. It works, though. Thanks!
Is there any reason why it wouldn't work? If I changed servers, say, and there were
some ports blocked and etc. etc., is there a risk that I should know?
-
Do you Yahoo!?
U2 on LAUNCH - Exclusive medley videos from Greatest Hits CD
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] registering object in session - Object to string notice error?
I have a simple object/class:
Class MainData {
Var items =array();
...some other functions but nothing to initialize it
}
in a code when I do :
$somevar= new MainData();
session_register($somevar);
I get notice type of error:
Notice: Object to string conversion in C...\page_vip.php on line 27
How can I avoid this? It does not stop code and it is not a fatal error
but perhaps I am missing something
Paul
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
The array_key_exists or isset is a good solution.
About your comment, i have the register_globals=on.
I have 2 questions:
1.- What's the relation to have register_globals=off with this notice
message?
2.- I read the security comment about register_globals=on in the php.ini,
but i set to on because if i set to off, i can't pass GET variables to other
page. how can you pass GET variables to other page without setting
register_globals=on?
From: Ernest E Vogelsinger [EMAIL PROTECTED]
To: R B [EMAIL PROTECTED]
CC: [EMAIL PROTECTED],[EMAIL PROTECTED]
Subject: Re: [PHP] Other Notice problem...
Date: Fri, 08 Nov 2002 17:14:30 +0100
At 17:04 08.11.2002, R B spoke out and said:
[snip]
I'm going to explain how my script work.
I have an php page (addProduct.php) with an input form. I have 2 buttons
(add and cancel) and a hidden control with name=status. If i press the
add
button, the page submit the form data to the same page (form
action=addProduct.php) with status hidden control name set to ADD, so
the
if statement its true only if i press the add button.
I see the message when i call the page to add the data not when i submit
the
data.
[snip]
Ahhh your $status variable should be a form variable? Well, as pointed
out many times the last days, register_globals is OFF by default since PHP
v.4.something. Either turn register_globals on in your PHP.ini (bad and
deprecated, read the security bulletins), or you refer to the _POST array:
if ($_POST['status'] == ADD)
if the data is not set (the status control empty), you'll still get a
notice about an undefined array index, so you might
if (array_key_exists('status', $_POST)) {
switch ($_POST['status']) {
case 'ADD':
break;
default:
echo 'Unsupported status!';
}
}
else echo 'No status sent!';
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
_
MSN. Más Útil Cada Día http://www.msn.es/intmap/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
At 17:27 08.11.2002, R B spoke out and said: [snip] The array_key_exists or isset is a good solution. About your comment, i have the register_globals=on. I have 2 questions: 1.- What's the relation to have register_globals=off with this notice message? If register_globals is OFF, $status will simply not be set by PHP. You can always access it as $_POST['status'] or $_REQUEST['status']. 2.- I read the security comment about register_globals=on in the php.ini, but i set to on because if i set to off, i can't pass GET variables to other page. how can you pass GET variables to other page without setting register_globals=on? What do you mean by pass it on to other page? I'm afraid I don't get you. What are you trying to accomplish? -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/
[PHP] php/html debug
Hi, is there any software on the market with I can test my html/php based web portal? I mean for example the data flow between html forms and php files/scripts. For Example a login form on html site and a check with an other php site and I want begin the test on the html site and check weather the right values goes to the php script. Thanks! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird behaviour with references to objects...
Ernest E Vogelsinger [EMAIL PROTECTED] wrote in message
news:5.1.1.6.2.20021108170633.00b8cb60;mail.vogelsinger.at...
You might always simply omit the parameter when calling the function
(you'll get a notice about that if enabled). You just cannot pass
constants:
function Product($language)
{
...
}
// ok, but gives a notice
Product();
// will fail
Product('ger');
ok well that's an idea indeed... i'll think about it.
If you keep your code like it is be warned that it may break with a future
version of PHP.
why do you think it won't be supported by future versions? all i do is
passing an object by reference. because in this case this function always
should accept its argument as a reference and therefore is bad programming
habit does not mean the php construction is bad or weird!?!
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
About your comment 1: if i have register_globals=on, why $status is not be set by PHP? About your comment 2: if i have 2 pages: p01.php and p02.php, with p01.php code: ... ... a href=p02.php?pp=2link/a ... ... and p02.php code: ... ... echo $pp; ... ... If i have register_globals=off, then when i click the link, in p02.php page, the echo command display nothing. If i have register_globals=on, then the echo command displays the value buy this way is deprecated. How can i run the script without problems having register_globals=off? Thanks, RB From: Ernest E Vogelsinger [EMAIL PROTECTED] To: R B [EMAIL PROTECTED] CC: [EMAIL PROTECTED],[EMAIL PROTECTED] Subject: Re: [PHP] Other Notice problem... Date: Fri, 08 Nov 2002 17:31:25 +0100 At 17:27 08.11.2002, R B spoke out and said: [snip] The array_key_exists or isset is a good solution. About your comment, i have the register_globals=on. I have 2 questions: 1.- What's the relation to have register_globals=off with this notice message? If register_globals is OFF, $status will simply not be set by PHP. You can always access it as $_POST['status'] or $_REQUEST['status']. 2.- I read the security comment about register_globals=on in the php.ini, but i set to on because if i set to off, i can't pass GET variables to other page. how can you pass GET variables to other page without setting register_globals=on? What do you mean by pass it on to other page? I'm afraid I don't get you. What are you trying to accomplish? -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/ _ Charla con tus amigos en línea mediante MSN Messenger: http://messenger.microsoft.com/es -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] problem compiling php
hi there again, here's the problem: I compiled apache using --enable-modules=so What do i need to do now in order to compile and install php on my machine? Furthermore, how do i add mysql support to apache? Is there a --with-mysql switch? Kind regards, dimitris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
On Friday, Nov 8, 2002, at 16:44 Europe/London, R B wrote: if i have 2 pages: p01.php and p02.php, with p01.php code: ... ... a href=p02.php?pp=2link/a ... ... and p02.php code: ... ... echo $pp; ... ... If i have register_globals=off, then when i click the link, in p02.php page, the echo command display nothing. If i have register_globals=on, then the echo command displays the value buy this way is deprecated. How can i run the script without problems having register_globals=off? p02.php code: ... ... echo $_GET['pp']; ... ... -- Stuart -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
And without using the $_GET[] array. From: Stuart [EMAIL PROTECTED] To: R B [EMAIL PROTECTED] CC: [EMAIL PROTECTED], [EMAIL PROTECTED], [EMAIL PROTECTED] Subject: Re: [PHP] Other Notice problem... Date: Fri, 8 Nov 2002 16:52:50 + On Friday, Nov 8, 2002, at 16:44 Europe/London, R B wrote: if i have 2 pages: p01.php and p02.php, with p01.php code: ... ... a href=p02.php?pp=2link/a ... ... and p02.php code: ... ... echo $pp; ... ... If i have register_globals=off, then when i click the link, in p02.php page, the echo command display nothing. If i have register_globals=on, then the echo command displays the value buy this way is deprecated. How can i run the script without problems having register_globals=off? p02.php code: ... ... echo $_GET['pp']; ... ... -- Stuart _ Charla con tus amigos en línea mediante MSN Messenger: http://messenger.microsoft.com/es -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird behaviour with references to objects...
At 17:32 08.11.2002, Tim Molendijk spoke out and said: [snip] why do you think it won't be supported by future versions? all i do is passing an object by reference. because in this case this function always should accept its argument as a reference and therefore is bad programming habit does not mean the php construction is bad or weird!?! [snip] This is clearly said in your PHP.ini file: ; Whether to enable the ability to force arguments to be passed by reference ; at function call time. This method is deprecated and is likely to be ; unsupported in future versions of PHP/Zend. The encouraged method of ; specifying which arguments should be passed by reference is in the function ; declaration. You're encouraged to try and turn this option Off and make ; sure your scripts work properly with it in order to ensure they will work ; with future versions of the language (you will receive a warning each time ; you use this feature, and the argument will be passed by value instead of by ; reference). allow_call_time_pass_reference = On ...god has spoken :) I'd rather have the abilty to pass A reference like foo($a) and have the opportunity to choose at runtime if I want to use a reference here or not, but it's how they say... -- O Ernest E. Vogelsinger (\) ICQ #13394035 ^ http://www.vogelsinger.at/
Re: [PHP] Other Notice problem...
On Friday, Nov 8, 2002, at 16:56 Europe/London, R B wrote: And without using the $_GET[] array. Why don't you want to use the $_GET array? If you really don't want to use it you can use the extract function but if you're going to do that you might as well have register_globals on. -- Stuart p02.php code: ... ... echo $_GET['pp']; ... ... -- Stuart -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] ftp file exists
How do you check if a file exists a remote ftp site.
Re: [PHP] problem compiling php
On Saturday 09 November 2002 00:52, dk1eng wrote: hi there again, here's the problem: I compiled apache using --enable-modules=so What do i need to do now in order to compile and install php on my machine? The manual says it all. Basically: ./configure --with-apxs=/usr/local/apache/bin/apxs \ --with-config-file-path=/usr/local/apache/conf ... If you want a more comprehensive set of installation instructions have a look at the LAMP guide, google for lamp install php apache mysql, it's a bit old but the stuff there should still be relevant. Furthermore, how do i add mysql support to apache? Is there a --with-mysql switch? You probably want to add mysql support to PHP rather than apache. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Our policy is, when in doubt, do the right thing. -- Roy L. Ash, ex-president, Litton Industries */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] problem compiling php
i would always make sure you check the manuals for the information first... http://www.php.net/manual/en/install.apache.php On Fri, 2002-11-08 at 16:52, dk1eng wrote: hi there again, here's the problem: I compiled apache using --enable-modules=so What do i need to do now in order to compile and install php on my machine? Furthermore, how do i add mysql support to apache? Is there a --with-mysql switch? Kind regards, dimitris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- .: B i g D o g :. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ftp file exists
Try
$f = fopen ('ftp://server/filename', 'r');
if $f is null, the file doesn't exist. Otherwise, it exists and you have
to fclose ($f). FTP support has to be compiled into your version of PHP
for this to work.
Marco
-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!
On Fri, 2002-11-08 at 12:01, Fifield, Mike wrote:
How do you check if a file exists a remote ftp site.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
At 17:44 08.11.2002, R B spoke out and said:
[snip]
About your comment 1:
if i have register_globals=on, why $status is not be set by PHP?
well _then_ we have 2 possibilities:
1) your form input field isn't named status but rather Status or
STATUS - take care of the case here, PHP is case sensitive with variables
and associative indices.
2) Your form simply submits _nothing_ in this field - check your JavaScript
(perhaps it is disabled?)
About your comment 2:
if i have 2 pages: p01.php and p02.php,
with p01.php code:
...
a href=p02.php?pp=2link/a
...
and p02.php code:
...
echo $pp;
If i have register_globals=off, then when i click the link, in p02.php page,
the echo command display nothing.
If i have register_globals=on, then the echo command displays the value buy
this way is deprecated.
How can i run the script without problems having register_globals=off?
?php
$parms = null;
foreach ($_GET as $p=$v) {
if ($parms) $parms .= '';
$parms .= $p=.urlencode($v);
}
?
...
a href=p02.php??php=$parms?
This will do what you want (untested, but should work)
--
O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
Re: [PHP] php/html debug
I have used nusphere PHPEd and it works okay...but i do not know what you are really trying to do here... On Fri, 2002-11-08 at 16:31, Anna Gyor wrote: Hi, is there any software on the market with I can test my html/php based web portal? I mean for example the data flow between html forms and php files/scripts. For Example a login form on html site and a check with an other php site and I want begin the test on the html site and check weather the right values goes to the php script. Thanks! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- .: B i g D o g :. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
On Saturday 09 November 2002 00:52, Stuart wrote: How can i run the script without problems having register_globals=off? p02.php code: ... ... echo $_GET['pp']; ... ... Yes. And try reading the manual, or the archives. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* While money can't buy happiness, it certainly lets you choose your own form of misery. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Other Notice problem...
On Saturday 09 November 2002 00:56, R B wrote: And without using the $_GET[] array. Probably by using black magic instead -- or maybe use $_REQUEST, but I don't think you want to use that either :) -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Auribus teneo lupum. [I hold a wolf by the ears.] [Boy, it *sounds* good. But what does it *mean*?] */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ftp file exists
if there's no function to check (which i can;t find real quick) do
soething like this:
if (!ftp_mdtm($conn_id, $file) {
echo File doesn't exist;
} else {
echo File exist;
}
On Friday, Nov 8, 2002, at 12:01 US/Eastern, Fifield, Mike wrote:
How do you check if a file exists a remote ftp site.
Jule Slootbeek
[EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
