[PHP] MySQL
In MySQL, I have a date field that is formatted 000-00-00 Is there a function in PHP I did not find yet that does this? John -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: MySQL
$date = date (Y-m-d); #works? :) Jtjohnston wrote: In MySQL, I have a date field that is formatted 000-00-00 Is there a function in PHP I did not find yet that does this? John -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] PHP script for command line
I am now trying to use php script from command line. Everything is Ok except only one thing: it will always send out header msg. How can stop it from sending header? Alex Shi -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] date( ) - function
i have one question linux system's time is right but php's date () function time is wrong... different system time and php's date( ) time is date () function call to the system time ? thansk /soma -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] 72dpi with gdlibrary2?
Hi there, I would like to create images with 72 dpi with gdlibrary2.01 Is this possible? Thanx Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Limit 15 where Newest
If (!$start) $start=0; $sql=select author, title, chapter from table order by date DESC limit $start, 15; ... and a link on the same page: echo(a href='samepage?start= . ($start + 15) . 'next/a); or something like that Tim www.chessish.com http://www.chessish.com -- From: Tyler Longren [SMTP:[EMAIL PROTECTED]] Sent: 05 February 2002 04:49 To: WIll; [EMAIL PROTECTED] Subject: Re: [PHP] Limit 15 where Newest $sql=select author, title, chapter from table order by date DESC limit 15; That's how you'd go about getting the 15 most recent table entries. The next 15 thing will require a bit more though. Tyler - Original Message - From: WIll [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, February 04, 2002 9:37 PM Subject: [PHP] Limit 15 where Newest I am trying to write a limit statement for my database. I want to say something like $sql=select author, title, chapter from database where last_update = Newest order by date limit 15; My question is how do you say Newest in php MySQL? And how do you put t link on the bottom of the page that will select the next 15 items in the database? Thank you. --WIll -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP script for command line
On Tue, 2002-02-05 at 00:36, Alex Shi wrote: I am now trying to use php script from command line. Everything is Ok except only one thing: it will always send out header msg. How can stop it from sending header? Alex Shi There are full instructions in the manual. Essentially, you are looking for the -q command line option. http://www.php.net/manual/en/commandline.php Hope this helps, Torben -- Torben Wilson [EMAIL PROTECTED] http://www.thebuttlesschaps.com http://www.hybrid17.com http://www.inflatableeye.com +1.604.709.0506 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] date( ) - function
try date(H:i:s,time()). Mike - Original Message - From: soma [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 12:32 AM Subject: [PHP] date( ) - function i have one question linux system's time is right but php's date () function time is wrong... different system time and php's date( ) time is date () function call to the system time ? thansk /soma -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] cURL
Hi, Can anyone point me out to some good resources on cURL?? Have to send 3 fields, Action,Username and Password for authentification to a Servlet and receive its response.. TIA, sands -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Compare values in an array
Can anybody tell me how I easily compare values in an associative array? I have for instance an array like: $foo['key1'] = 'abc'; $foo['key2'] = 'def'; $foo['key3'] = 'abc'; $foo['key4'] = 'ghi'; and I want to get the value 'abc' ... Please send me an email ([EMAIL PROTECTED]) because my newsgroups doesn't always work properly! Thanx, Rainer. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: HTTP Error 405 using POST method
In your example I see that you forgot /head after your /title ... maybe that's the problem! Scott Adams [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi. I'm learning PHP3 on an IIS 4.0 box and I started by trying out this simple HTML form. The form lets the user input his/her name, email address, and select whether he/she likes oranges or apples and sends the data to a .php file that displays what the user input on the HTML form. The form method is POST. When I submit the data I type, I receive an HTTP Error 405 message with the following text: start of error message HTTP Error 405 405 Method Not Allowed The method specified in the Request Line is not allowed for the resource identified by the request. Please ensure that you have the proper MIME type set up for the resource you are requesting. Please contact the server's administrator if this problem persists. end of error message Here is the HTML page with the form I am using: HTML HEAD TITLERequest for more information/TITLE BODY CENTERWould you like more information about our company? P FORM ACTION=email.php3 METHOD=POST Your name:BR INPUT TYPE=text NAME=name SIZE=20 MAXLENGTH=30 P Your email address:BR INPUT TYPE=text NAME=email SIZE=20 MAXLENGTH=30 P I prefer: SELECT NAME=preference OPTION value = ApplesApples OPTION value = OrangesOranges /SELECT P INPUT TYPE=submit VALUE=Send it! /FORM /CENTER /BODY /HTML What am I doing wrong? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Tricky array question
Hi there, I have a tricky array question. My app is passing via post a array variable called glacier. Now I am checking for the content of this array. Because there are more of those arrays, I am getting all the names out of a db. How is it possible to get the value and keep the name of the array dynamic? e.g: Array name passed by post is: $glacier // contains e.g. $glacier[0] = testname Array with category names coming out of db is: $category // contains e.g. $category[0] = glacier echo $categories[0]; // returns glacier echo $glacier[0]; // returns testname I tryed $categories[0][0] but it returns only the first letter of glacier (g) Any ideas?? Thanx, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Tricky array question
try using something like this:
$varname = $categories[0];
echo ${$varname}[0];
Greets,
Edward
Andy [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]...
Hi there,
I have a tricky array question.
My app is passing via post a array variable called glacier. Now I am
checking for the content
of this array. Because there are more of those arrays, I am getting all
the
names out of a db.
How is it possible to get the value and keep the name of the array
dynamic?
e.g:
Array name passed by post is: $glacier //
contains e.g. $glacier[0] = testname
Array with category names coming out of db is: $category // contains e.g.
$category[0] = glacier
echo $categories[0]; // returns glacier
echo $glacier[0]; // returns testname
I tryed $categories[0][0] but it returns only the first letter of glacier
(g)
Any ideas??
Thanx, Andy
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RE: [PHP] Tricky array question
It should be $category[0] = $glacier; ^--- ERROR in you code Niklas -Original Message- From: Andy [mailto:[EMAIL PROTECTED]] Sent: 5. helmikuuta 2002 11:59 To: [EMAIL PROTECTED] Subject: [PHP] Tricky array question Hi there, I have a tricky array question. My app is passing via post a array variable called glacier. Now I am checking for the content of this array. Because there are more of those arrays, I am getting all the names out of a db. How is it possible to get the value and keep the name of the array dynamic? e.g: Array name passed by post is: $glacier // contains e.g. $glacier[0] = testname Array with category names coming out of db is: $category // contains e.g. $category[0] = glacier echo $categories[0]; // returns glacier echo $glacier[0]; // returns testname I tryed $categories[0][0] but it returns only the first letter of glacier (g) Any ideas?? Thanx, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Tricky array question
Hi Andy, I was just reading your message, do I see that you send an array with a form? Like input name=glacier[x] ? I just wanted you to know that using brackets [] is not allowed in the html-name attribute! Your html-page will not validate :( The sollution is sending al your vars as simple vars (no array) and collect them with HTTP_GET_VARS[] or HTTP_POST_VARS[], php-variables. Maybe this will also be a sollution for your problem... just take a look from another point of view :) Cheers, Rainer. Andy [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi there, I have a tricky array question. My app is passing via post a array variable called glacier. Now I am checking for the content of this array. Because there are more of those arrays, I am getting all the names out of a db. How is it possible to get the value and keep the name of the array dynamic? e.g: Array name passed by post is: $glacier // contains e.g. $glacier[0] = testname Array with category names coming out of db is: $category // contains e.g. $category[0] = glacier echo $categories[0]; // returns glacier echo $glacier[0]; // returns testname I tryed $categories[0][0] but it returns only the first letter of glacier (g) Any ideas?? Thanx, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Find the nearest dealer in Germany on a given ZIP (PLZ)
Hi List ! I have a question on a topic that's been dealt with here before (but only for the US). I am looking for a soultion to find - via php /database - a way to search for the shortest distance between a given ZIP Code and available dealers nearby. So, let's assume I am living in German ZIP Code 7. I want to look for my nearest dealer. php and the database should be able to tell me where it is. Does anybody know how to achieve this ? Like in www.mediamarkt.de or at www.hp.com ? So it should be possible somehow. Do I have to link German ZIPs (=PLZs) to geographical data ? Where Can I get them from ? You cannot work on ZIPs alone, right ? how can you calculate the distance ? Thanks for any help Markus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Changes in Sessions (PHP Versions)
If you really need to use 4.0.6, try to use different
session save handler and/or serializer. Try WDDX
serializer at first, then try verious combinations.
If you use other save handler/serializer, it may work.
I suggest you to upgrade, though...
--
Yasuo Ohgaki
Travis Simpson wrote:
Sorry, I probably worded my question wrong.
I am creating a 10 step (or so) form that is non-linear... The user
enters all of their information and is able to go back and change
information that they have filled in. So I have the form (POST)
information set into session variables as soon as they click Next in
the form. Well, with 4.1.1 there were no problems... It ALL worked
perfectly. But unfortunately, in 4.0.6 it doesn't act the same.
I just have a foreach loop go through all the POST variables and make
them into SESSION variables,
--- Snippet ---
start_session();
foreach ($HTTP_POST_VARS as $key = $value) {
$HTTP_SESSION_VARS[$key] = $value;
}
--- End Snippet ---
Easy enough... Now, I have all the 10 steps linked to on the side bar.
a href=step1.php?PHPSESSID=$PHPSESSIDStep 1/a
But for some weird reason, those links BLANK all the session variables.
I tested this by doing a count() on the HTTP_SESSION_VARS array. And as
soon as I click one of the Step links on the side, it clears all of
them. I am not sure if I am doing this wrong, but it works fine (as I
said) in 4.1.1.
Another problem that I seem to be having... Is that 4.0.6 almost seems
like it is maxing out with a certain number of SESSION variables. Once
it has so many, it just starts over.
I will just post the link here tomorrow, unfortunately I don't have the
files on this computer.
I hope this is a little more clear.
Thanks,
-Travis
-Original Message-
From: Yasuo Ohgaki [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 04, 2002 6:11 PM
To: [EMAIL PROTECTED]; Travis Simpson
Subject: [PHP] Re: Changes in Sessions (PHP Versions)
Travis Simpson wrote:
Hey,
I am just wondering if there were any changes done to the session
engine or settings between PHP 4.0.6 and 4.1.1.
I have been getting nothing but grief from 4.0.6 and 4.1.1 seems to
work fine.
What did work with 4.0.6 and what didn't with 4.1.1?
If you are trying to use mm/msession save handler, it's broken somewhat.
_
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Get your free @yahoo.com address at http://mail.yahoo.com
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[PHP] Re: Tricky array question
Hello Rainer, what kind of disadvantages do I take with me, if my form does not validate? Is this a problem because of the spiders, or the functionality? It works fine so far on all browsers I know. Can you please give more details? Thanx Andy Rainer [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi Andy, I was just reading your message, do I see that you send an array with a form? Like input name=glacier[x] ? I just wanted you to know that using brackets [] is not allowed in the html-name attribute! Your html-page will not validate :( The sollution is sending al your vars as simple vars (no array) and collect them with HTTP_GET_VARS[] or HTTP_POST_VARS[], php-variables. Maybe this will also be a sollution for your problem... just take a look from another point of view :) Cheers, Rainer. Andy [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi there, I have a tricky array question. My app is passing via post a array variable called glacier. Now I am checking for the content of this array. Because there are more of those arrays, I am getting all the names out of a db. How is it possible to get the value and keep the name of the array dynamic? e.g: Array name passed by post is: $glacier // contains e.g. $glacier[0] = testname Array with category names coming out of db is: $category // contains e.g. $category[0] = glacier echo $categories[0]; // returns glacier echo $glacier[0]; // returns testname I tryed $categories[0][0] but it returns only the first letter of glacier (g) Any ideas?? Thanx, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: Tricky array question
I think you should ignore that. I use it all the times, and it works fine. Niklas -Original Message- From: Andy [mailto:[EMAIL PROTECTED]] Sent: 5. helmikuuta 2002 12:37 To: [EMAIL PROTECTED] Subject: [PHP] Re: Tricky array question Hello Rainer, what kind of disadvantages do I take with me, if my form does not validate? Is this a problem because of the spiders, or the functionality? It works fine so far on all browsers I know. Can you please give more details? Thanx Andy Rainer [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi Andy, I was just reading your message, do I see that you send an array with a form? Like input name=glacier[x] ? I just wanted you to know that using brackets [] is not allowed in the html-name attribute! Your html-page will not validate :( The sollution is sending al your vars as simple vars (no array) and collect them with HTTP_GET_VARS[] or HTTP_POST_VARS[], php-variables. Maybe this will also be a sollution for your problem... just take a look from another point of view :) Cheers, Rainer. Andy [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi there, I have a tricky array question. My app is passing via post a array variable called glacier. Now I am checking for the content of this array. Because there are more of those arrays, I am getting all the names out of a db. How is it possible to get the value and keep the name of the array dynamic? e.g: Array name passed by post is: $glacier // contains e.g. $glacier[0] = testname Array with category names coming out of db is: $category // contains e.g. $category[0] = glacier echo $categories[0]; // returns glacier echo $glacier[0]; // returns testname I tryed $categories[0][0] but it returns only the first letter of glacier (g) Any ideas?? Thanx, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Tricky array question
Hello!
a have following mysql problem:
i need to execute several inserts at one query like this-
$sql-action(insert into words(word) values ('php');
insert into words(word) values ('general');
insert into words(word) values ('list'););
The word fild is unique
My problem is: when certain word (e.g. 'php') already exists in table words
all the query fails
I do not want to check every word on existance and then insert only new
words.
I want mysql to ignore fails. How can i do it?
Thanx
Valentin Petruchek (aki Zliy Pes)
http://zliypes.com.ua
mailto:[EMAIL PROTECTED]
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Re: [PHP] Tricky array question
This was just an error in my explenation I ment categories. Meanwhile I tryed var vars, but it does not work for any reason?!?!? My code looks like: $field = $categories[0].[0]; echo $field;// returns glacier[0] echo 'var '.$$field.'br'; // returns bluddy nothing echo $categories[0]; // returns glacier echo $glacier[0];// returns 110 Does anybody know how to get the 110 out of the array? Thanx for any help, Andy Niklas lampén [EMAIL PROTECTED] schrieb im Newsbeitrag 008101c1ae2d$a9df7580$ba93c5c3@Niklas">news:008101c1ae2d$a9df7580$ba93c5c3@Niklas... It should be $category[0] = $glacier; ^--- ERROR in you code Niklas -Original Message- From: Andy [mailto:[EMAIL PROTECTED]] Sent: 5. helmikuuta 2002 11:59 To: [EMAIL PROTECTED] Subject: [PHP] Tricky array question Hi there, I have a tricky array question. My app is passing via post a array variable called glacier. Now I am checking for the content of this array. Because there are more of those arrays, I am getting all the names out of a db. How is it possible to get the value and keep the name of the array dynamic? e.g: Array name passed by post is: $glacier // contains e.g. $glacier[0] = testname Array with category names coming out of db is: $category // contains e.g. $category[0] = glacier echo $categories[0]; // returns glacier echo $glacier[0]; // returns testname I tryed $categories[0][0] but it returns only the first letter of glacier (g) Any ideas?? Thanx, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Tricky array question
Put an @ infront of your comand
Andy
Val Petruchek [EMAIL PROTECTED] schrieb im Newsbeitrag
000801c1ae32$6fc1e360$[EMAIL PROTECTED]">news:000801c1ae32$6fc1e360$[EMAIL PROTECTED]...
Hello!
a have following mysql problem:
i need to execute several inserts at one query like this-
$sql-action(insert into words(word) values ('php');
insert into words(word) values ('general');
insert into words(word) values ('list'););
The word fild is unique
My problem is: when certain word (e.g. 'php') already exists in table
words
all the query fails
I do not want to check every word on existance and then insert only new
words.
I want mysql to ignore fails. How can i do it?
Thanx
Valentin Petruchek (aki Zliy Pes)
http://zliypes.com.ua
mailto:[EMAIL PROTECTED]
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[PHP] Seams not to be possible
This was just an error in my explenation I ment categories. Meanwhile I tryed var vars, but it does not work for any reason?!?!? My code looks like: $field = $categories[0].[0]; echo $field;// returns glacier[0] echo 'var '.$$field.'br'; // returns bluddy nothing echo $categories[0]; // returns glacier echo $glacier[0];// returns 110 Does anybody know how to get the 110 out of the array? Thanx for any help, Andy Andy [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi there, I have a tricky array question. My app is passing via post a array variable called glacier. Now I am checking for the content of this array. Because there are more of those arrays, I am getting all the names out of a db. How is it possible to get the value and keep the name of the array dynamic? e.g: Array name passed by post is: $glacier // contains e.g. $glacier[0] = testname Array with category names coming out of db is: $category // contains e.g. $category[0] = glacier echo $categories[0]; // returns glacier echo $glacier[0]; // returns testname I tryed $categories[0][0] but it returns only the first letter of glacier (g) Any ideas?? Thanx, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mysql fails
Sorry, incorrect subj!
Hello!
a have following mysql problem:
i need to execute several inserts at one query like this-
$sql-action(insert into words(word) values ('php');
insert into words(word) values ('general');
insert into words(word) values ('list'););
The word fild is unique
My problem is: when certain word (e.g. 'php') already exists in table words
all the query fails
I do not want to check every word on existance and then insert only new
words.
I want mysql to ignore fails. How can i do it?
Thanx
Valentin Petruchek (aki Zliy Pes)
http://zliypes.com.ua
mailto:[EMAIL PROTECTED]
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RE: [PHP] Tricky array question
Ahem... So you want to have a two dimensional variable? ? $Array = array(110, 220); // You array to add to $TwoDimensional array $TwoDimensional = array(); // Define $TwoDimensional to be an array $TwoDimensional[0] = $Array; // Insert values from $Array to $TwoDimensional print Var: .$TwoDimensional[0][0].brbr; ? Is this what you are looking for? Niklas -Original Message- From: Andy [mailto:[EMAIL PROTECTED]] Sent: 5. helmikuuta 2002 12:54 To: [EMAIL PROTECTED] Subject: Re: [PHP] Tricky array question This was just an error in my explenation I ment categories. Meanwhile I tryed var vars, but it does not work for any reason?!?!? My code looks like: $field = $categories[0].[0]; echo $field;// returns glacier[0] echo 'var '.$$field.'br'; // returns bluddy nothing echo $categories[0]; // returns glacier echo $glacier[0];// returns 110 Does anybody know how to get the 110 out of the array? Thanx for any help, Andy Niklas lampén [EMAIL PROTECTED] schrieb im Newsbeitrag 008101c1ae2d$a9df7580$ba93c5c3@Niklas">news:008101c1ae2d$a9df7580$ba93c5c3@Niklas... It should be $category[0] = $glacier; ^--- ERROR in you code Niklas -Original Message- From: Andy [mailto:[EMAIL PROTECTED]] Sent: 5. helmikuuta 2002 11:59 To: [EMAIL PROTECTED] Subject: [PHP] Tricky array question Hi there, I have a tricky array question. My app is passing via post a array variable called glacier. Now I am checking for the content of this array. Because there are more of those arrays, I am getting all the names out of a db. How is it possible to get the value and keep the name of the array dynamic? e.g: Array name passed by post is: $glacier // contains e.g. $glacier[0] = testname Array with category names coming out of db is: $category // contains e.g. $category[0] = glacier echo $categories[0]; // returns glacier echo $glacier[0]; // returns testname I tryed $categories[0][0] but it returns only the first letter of glacier (g) Any ideas?? Thanx, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Tricky array question
Hi Andy,
What Niklas wrote is true, at this moment it works fine, but.
when I write code, I always ask myself which factors are constant and still
will work in, let's say, about 3 years from now.
The fact is that you cannot know which kind of useragents (read
browsertypes) there will be in future. What you DO know is that w3c is
setting up rules on which future useragents will rely on. If you follow
these rules you won't be surprised in future! Look at www.w3c.org - XHTML.
My suggestion:
in your html-doc -
form action=mycode.php method=post name=form1
input name=form1_var1
input name=form1_var2
input name=form1_var3
etc..
/form
form action=mycode.php method=post name=form2
input name=form2_var1
input name=form2_var2
input name=form2_var3
etc..
/form
in mycode.php -
?php
while ($myvar = each($HTTP_POST_VARS)) {
$myarray[$myvar['key']] = $myvar['value'] ;
}
?
Rainer.
Andy [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hello Rainer,
what kind of disadvantages do I take with me, if my form does not
validate?
Is this a problem because of the spiders,
or the functionality?
It works fine so far on all browsers I know.
Can you please give more details?
Thanx Andy
Rainer [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi Andy,
I was just reading your message, do I see that you send an array with a
form?
Like input name=glacier[x] ?
I just wanted you to know that using brackets [] is not allowed in the
html-name attribute! Your html-page will not validate :(
The sollution is sending al your vars as simple vars (no array) and
collect
them with HTTP_GET_VARS[] or HTTP_POST_VARS[], php-variables.
Maybe this will also be a sollution for your problem... just take a look
from another point of view :)
Cheers,
Rainer.
Andy [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi there,
I have a tricky array question.
My app is passing via post a array variable called glacier. Now I am
checking for the content
of this array. Because there are more of those arrays, I am getting
all
the
names out of a db.
How is it possible to get the value and keep the name of the array
dynamic?
e.g:
Array name passed by post is: $glacier
//
contains e.g. $glacier[0] = testname
Array with category names coming out of db is: $category // contains
e.g.
$category[0] = glacier
echo $categories[0]; // returns glacier
echo $glacier[0]; // returns testname
I tryed $categories[0][0] but it returns only the first letter of
glacier
(g)
Any ideas??
Thanx, Andy
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[PHP] add value to serialized array?
Hi,
At start test.txt contains a serialized array with value one and two.
a:2:{i:0;s:3:one;i:1;s:3:two;}
after one run this is:
a:3:{i:0;s:3:one;i:1;s:3:two;i:2;s:4:tree;}
But the last row prints nothing. Why?
Tnx,
Bas
?
$array=array();
$fp=fopen(test.txt,r);
flock($fp,1);
$array=unserialize(fread($fp,filesize(test.txt)));
flock($fp,3);
fclose($fp);
array_push($array,tree);
$fp=fopen(test.txt,w+);
flock($fp,2);
fwrite($fp,serialize($array));
flock($fp,3);
fclose($fp);
$fp=fopen(test.txt,r);
flock($fp,1);
$array=unserialize(fread($fp,filesize(test.txt)));
flock($fp,3);
fclose($fp);
echo $array[0].$array[1].$array[2];
?
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Re: [PHP] mysql fails
Hello val,
a have following mysql problem:
i need to execute several inserts at one query like this-
$sql-action(insert into words(word) values ('php');
insert into words(word) values ('general');
insert into words(word) values ('list'););
The word fild is unique
My problem is: when certain word (e.g. 'php') already exists in table words
all the query fails
I do not want to check every word on existance and then insert only new
words.
I want mysql to ignore fails. How can i do it?
MySQL manual 6.4.3 INSERT Syntax
Check out INSERT [IGNORE]
Regards,
=dn
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[PHP] Sending files to the user...?
The problem:
How to I send a file to the user? Sounds simple but, assume I have a 'daily
report' option from my main web page. When the user clicks on it, they are
taken to the file 'generate_report.php' (sample included).
Now, this code should generate the report, compress it if required and send
it ot the user - i.e. a dialog box opens asking the user to open/save/run
the incoming file.
Question is, how? - I've toyed with Content-Disposition but I'm not sure of
any reference materials for this. (Perhaps someone knows the RFC)
The code:
?php
/* file: generate_report.php */
// build the report
$report = xml...; /* basically an xml document
// compress if possible
if (extension_loaded(zlib) (strlen($report) 1024))
{
$report = gzcompress($report);
$compress = true;
}
else
{
$compressed = false;
}
$length = strlen($report);// I presume this can handle binary data
//header( something );
?
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[PHP] Re: Sending files to the user...?
Oh, and BTW, after sending the file, I will be redirecting the user to a
different page...
Alan McFarlane [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
The problem:
How to I send a file to the user? Sounds simple but, assume I have a
'daily
report' option from my main web page. When the user clicks on it, they are
taken to the file 'generate_report.php' (sample included).
Now, this code should generate the report, compress it if required and
send
it ot the user - i.e. a dialog box opens asking the user to open/save/run
the incoming file.
Question is, how? - I've toyed with Content-Disposition but I'm not sure
of
any reference materials for this. (Perhaps someone knows the RFC)
The code:
?php
/* file: generate_report.php */
// build the report
$report = xml...; /* basically an xml document
// compress if possible
if (extension_loaded(zlib) (strlen($report) 1024))
{
$report = gzcompress($report);
$compress = true;
}
else
{
$compressed = false;
}
$length = strlen($report);// I presume this can handle binary data
//header( something );
?
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RE: [PHP] Re: Sending files to the user...?
Your are on the right track.
Using the Header function is the way to do it.
But I guess you forget to take a look at the manual page. There are all
questions that you ask answered :)
So take a look http://www.php.net/manual/en/function.header.php .
in short:
RFC: http://www.w3.org/Protocols/rfc2616/rfc2616
Force download:
header(Content-type: application/pdf);
header(Content-Disposition: attachment; filename=downloaded.pdf);
/* ... output pdf file ... */
Kind Regards,
Jerry
-Original Message-
From: Alan McFarlane [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 05, 2002 1:36 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Sending files to the user...?
Oh, and BTW, after sending the file, I will be redirecting
the user to a
different page...
Alan McFarlane [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
The problem:
How to I send a file to the user? Sounds simple but, assume I have a
'daily
report' option from my main web page. When the user clicks
on it, they are
taken to the file 'generate_report.php' (sample included).
Now, this code should generate the report, compress it if
required and
send
it ot the user - i.e. a dialog box opens asking the user to
open/save/run
the incoming file.
Question is, how? - I've toyed with Content-Disposition but
I'm not sure
of
any reference materials for this. (Perhaps someone knows the RFC)
The code:
?php
/* file: generate_report.php */
// build the report
$report = xml...; /* basically an xml document
// compress if possible
if (extension_loaded(zlib) (strlen($report) 1024))
{
$report = gzcompress($report);
$compress = true;
}
else
{
$compressed = false;
}
$length = strlen($report);// I presume this can handle
binary data
//header( something );
?
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[PHP] Name of file included
I need to access the name of a file included. ie: in index.php I've included various files, among them navigation.inc. Instead of manually typing !--navigation.inc-- at the top of everyfile, I'd like to use something like: !--$included_file-- === Ron Dyck WebbTech www.WebbTech.net [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] How do I find double values in an associative array
Hello group, Can anybody tell me how I easily compare values in an associative array? I would like to find double values I have for instance an array like: $foo['key1'] = 'abc'; $foo['key2'] = 'def'; $foo['key3'] = 'abc'; $foo['key4'] = 'ghi'; and I want to get the value 'abc' ... Please send me an email ([EMAIL PROTECTED]) because my newsgroups doesn't always work properly! Thanx, Rainer. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] How do I find double values in an associative array
http://www.php.net/manual/en/function.array-count-values.php Jerry I feel like a manual... -Original Message- From: Rainer [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 05, 2002 2:51 PM To: [EMAIL PROTECTED] Subject: [PHP] How do I find double values in an associative array Hello group, Can anybody tell me how I easily compare values in an associative array? I would like to find double values I have for instance an array like: $foo['key1'] = 'abc'; $foo['key2'] = 'def'; $foo['key3'] = 'abc'; $foo['key4'] = 'ghi'; and I want to get the value 'abc' ... Please send me an email ([EMAIL PROTECTED]) because my newsgroups doesn't always work properly! Thanx, Rainer. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php The information contained in this email is confidential and may be legally privileged. It is intended solely for the addressee. Access to this email by anyone else is unauthorized. If you are not the intended recipient, any form of disclosure, production, distribution or any action taken or refrained from in reliance on it, is prohibited and may be unlawful. Please notify the sender immediately. The content of the email is not legally binding unless confirmed by letter bearing two authorized signatures. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to get the URL into a var?
hi,
I don't know whether this will solve your problem, but the
following prints the full path of the file that is being used.
script language=php
$uri = getenv('REQUEST_URI');
$path = $HTTP_SERVER_VARS[PATH_TRANSLATED];
// This prints /~user/subapp/test.php
echo br$uribr;
// This prints /home/servername/username/public_html/subapp/test.php
echo brpath : $pathbr;
/script
regards
- JFK
kishor
Nilgiri Networks
On Sat, 2 Mar 2002, Andy wrote:
Hi there,
I am trying to find out which dir the user is browsing. How can I get the
URL into a var? I tryed path_info, but it only returns the filename.
Here is an example:
URL: http://www.server.com/subapp/test.php
Should return :
subapp
Is this possible??
Thanx for any help
Cheers Andy
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[PHP] Getting variables from a text file
I have this text file I have to retreve infromation from, in the fallowing format: date1=1/1/2002title1=some titleheadline1=some headlinefull1=full articledate2=2/1/2002title2=some title and so on what would be the best thing for me to do to if I was to get the values of all the variables of the text file into a php document as variables. Regards, David Davíð Örn Jóhannssson Vefforritari Atómstöðin hf. Garðastræti 37 101 Reykjavík sími: 595-3643 fax: 595-3649 [EMAIL PROTECTED] http://www.atom.is
[PHP] Unable to get ImageTTFText output
Hi there, I am trying to use the ImageTTFText function to output some text onto an existing image. Problem being though that the text does not get outputted. I have placed the ttf file 'arial.ttf' within the same directory as my script. Here is a snippet of my code: Header(Content-Type: image/png); $im = ImageCreateFromPNG(original_image.png); $text_colour = ImageColorAllocate($im, 255, 255, 255); ImageTTFText($im, 20, 0, 3, 3, $text_colour, /arial.ttf, My text); ImagePNG($im); All this outputs is my original PNG image (with no text). I have used the following line instead of ImageTTFText and all works well. ImageString($im, 4, 3, 3, My text, $text_colour); Using phpinfo() I have checked the GD section and the following is outputted: GD Support - enabled GD Version - 2.0 or higher FreeType Support - enabled FreeType Linkage - with freetype JPG Support - enabled PNG Support - enabled WBMP Support - enabled Does anyone have any suggestions as to why this does not work? Has anyone else used the ImageTTFText function successfully? Neil Email: [EMAIL PROTECTED] [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Change of Language
How can in change the language in my site? (spanish) for example using the function date. (LANG?) Thanks Nicolás Llamosas _ MSN Photos es la manera más sencilla de compartir, editar e imprimir sus fotos favoritas. http://photos.latam.msn.com/Support/WorldWide.aspx -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Change of Language
check out: setlocale() Greets, Edward - Original Message - From: Nicolas Llamosas [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 4:13 PM Subject: [PHP] Change of Language How can in change the language in my site? (spanish) for example using the function date. (LANG?) Thanks Nicolás Llamosas _ MSN Photos es la manera más sencilla de compartir, editar e imprimir sus fotos favoritas. http://photos.latam.msn.com/Support/WorldWide.aspx -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Mysql
Pleae help me ! I need delete record from table user.mysql in mysql database, i log on in mysql like root and I log on on linux server like root. But when I write command : delete from user where user=''; mysql send me error message : ERROR 1036 Table 'user; is read only ! Thans for you helps... roman -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] PHP module build problem
I am trying to build PHP3 into apache 1.3. I have vanilla PHP and Apache sources. When I do the final Apache 'make', I get an error message complaining about not able to find target for alloc.h. The 'alloc.h' file is declared as a dependency for 'mod_php3.o' in the Makefile in folder 'src/modules/php3'. Any advice would be greatly helpful. = Anas Mughal [EMAIL PROTECTED] [EMAIL PROTECTED] Tel: 973-249-6665 __ Do You Yahoo!? Send FREE Valentine eCards with Yahoo! Greetings! http://greetings.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Unable to get ImageTTFText output
Hi I had similar problems when just specifying the font file in the same directory eg ./arial.ttf but got it to work okay when i used the full path eg : $fontfile = /apache/htdocs/arial.ttf; ImageTTFText($im, 20, 0, 3, 3, $text_colour, $fontfile, My text); Regards Girish -- www.girishnath.co.uk - Original Message - From: Neil Freeman [EMAIL PROTECTED] To: PHP General [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 2:59 PM Subject: [PHP] Unable to get ImageTTFText output Hi there, I am trying to use the ImageTTFText function to output some text onto an existing image. Problem being though that the text does not get outputted. I have placed the ttf file 'arial.ttf' within the same directory as my script. Here is a snippet of my code: Header(Content-Type: image/png); $im = ImageCreateFromPNG(original_image.png); $text_colour = ImageColorAllocate($im, 255, 255, 255); ImageTTFText($im, 20, 0, 3, 3, $text_colour, /arial.ttf, My text); ImagePNG($im); All this outputs is my original PNG image (with no text). I have used the following line instead of ImageTTFText and all works well. ImageString($im, 4, 3, 3, My text, $text_colour); Using phpinfo() I have checked the GD section and the following is outputted: GD Support - enabled GD Version - 2.0 or higher FreeType Support - enabled FreeType Linkage - with freetype JPG Support - enabled PNG Support - enabled WBMP Support - enabled Does anyone have any suggestions as to why this does not work? Has anyone else used the ImageTTFText function successfully? Neil Email: [EMAIL PROTECTED] [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] testing for cookies on the server side (again, still can't get my head around it)
So what's the flow of code to test for cookies on the server
side? I'm
pretty sure that the only way is to set a cookie, then test for it.
That is pretty much it. On the first page request to your application, if
PHP encounters a session_start() in your code, it will return a cookie named
PHPSESSID in the response headers. So you need to look for that cookie in
the request for the *second* page. If cookies are enabled in the browser,
the browser will return the cookie in the next request. Here's some code to
put at the top of the 2nd page:
?php
function check_cookies() {
global $HTTP_COOKIE_VARS;
if(!$HTTP_COOKIE_VARS[PHPSESSID]) {
header(Location: ./cookie_error.php);
exit();
}
}
?
I usually make my index.php page just set up the session, etc., then do an
automatic redirect to my second page, which is the first visible page. I put
the cookie check on this second page.
Kirk
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Re: [PHP] Getting variables from a text file
Hi It looks like a querystring, so read the contents of the file into a variable, then use the parse_str() function on that variable, you can specify if you want them to be stored in an array too. http://www.php.net/manual/en/function.parse-str.php Regards Girish -- www.girishnath.co.uk - Original Message - From: David Orn Johannsson To: [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 2:50 PM Subject: [PHP] Getting variables from a text file I have this text file I have to retreve infromation from, in the fallowing format: date1=1/1/2002title1=some titleheadline1=some headlinefull1=full articledate2=2/1/2002title2=some title and so on what would be the best thing for me to do to if I was to get the values of all the variables of the text file into a php document as variables. Regards, David Davíð Örn Jóhannssson Vefforritari Atómstöðin hf. Garðastræti 37 101 Reykjavík sími: 595-3643 fax: 595-3649 [EMAIL PROTECTED] http://www.atom.is
[PHP] Easy Question -- Show/ Hide text based on output of query
Hi,
I am working on a page the displays the output of a query in a table and
I only want to show the field labels that have corresponding output from
the database. I am only really concerned with the last label in the
table.
The label is called Notes and the corresponding field in the database
is memberNotes
So I wrote the following script where I think I am saying if memberNotes
returns any value then print the output of $notes in the table cell
where it is called, but nothing happens and the output of $notes is not
displayed regardless whether memberNotes has any output.
?php If ($memberNotes =='1') {
$notes = div align=\/left\/font
size=\/-1\/bNotes:/b/font/div;
}else {
$notes = div align=\/left\/font
size=\/-1\/b/b/font/div;
}
?
In the table cell I placed the following
?php print $notes; ?
Can anyone see what I am doing wrong??
Thanks for the help
Ed
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[PHP] PHP / MYSQL security bug
Maybe I missed the thread but I was wondering if anyone has seen this report or done any testing on it. We tested it and it seems a pretty valid problem. Can anyone comment on a fix that may be in the works? Gerard - Security Advisory DW020203-PHP Release: 3rd February 2002 PHP Safe Mode Filesystem Circumvention Problem Severity: Medium to high. Affects: PHP, all versions which include safe_mode feature. Platform: UNIX, Microsoft Windows, any platforms on which PHP is available. Vendor: http://php.net. Discovered: 12th January 2002, Dave Wilson [EMAIL PROTECTED], using PHP 4.1.0 Apache 2 on Linux. -- VULNERABILITY IN BRIEF PHP (since version 3?) includes a commonly used feature known as Safe Mode. When enabled, scripts are highly limited in their ability to access or execute local files, among other things. PHP relies on a wrapper function around all filesystem calls to perform access checks, but unforunately the bundled MySQL client library has not been modified to perform such checks on LOAD DATA INFILE LOCAL statements. If an attacker has access to a MySQL server (either provided by you or himself), he can use it as a proxy by which to download files residing on the safe_mode-enabled web server. For large ISPs relying on this feature for individual customer privacy, it could mean clients accessing each other's files, or viewing of files on an improperly secured server. FIX Currently, no fix exists. You may use other PHP safe_mode functions to disable the use of the MySQL client library, or secure your servers in a proper fashion.. A suggested fix for the PHP developers might be to scan mysql_query()s for strings similar to LOAD DATA LOCAL INFILE. Happy hackers out there might like to look at libmysql.c:1764 if interested in fixing this problem, although that may only be possible from within PHP. EXAMPLE The attached script will (once configured correctly) attempt to read /var/log/lastlog via the SQL daemon and return it to the client. $ cp safe_mode.php /www $ wget -qO lastlog_via_mysql localhost/safe_mode.php $ diff /var/log/lastlog lastlog_via_mysql; echo $? 0 COMMENTS Due to the nature of the PHP project, development is very rapid and hence many sites do not keep up with latest PHP versions. If a fix was available, it would take quite a while to propagate. It is likely that this is not an isolated problem in PHP, my bets are on PostgreSQL and other PHP database extensions missing this one too. The MySQL support has been enabled in PHP by default for as long as I can remember. DAVE WILSON Currently residing in Belfast, Northern Ireland, he is available for work relating to network security auditing, post-attack recovery and forensics, and penetration testing. He may be contacted at [EMAIL PROTECTED]. If you have any comments regarding this advisory, please contact him directly. Sun Feb 3 21:23:03 GMT 2002 -dw --- Outgoing mail is certified Virus Free By AVG Anti-Virus. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.319 / Virus Database: 178 - Release Date: 1/28/2002 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: PHP module build problem
I just saw a posting on PHPBuilder that states that Apache 1.3.14 has changed alloc.h to ap_alloc.h. So, file renaming is suggested. Maybe that could fix the problem. (I will give it a try...) I would be open to any other suggestions... Thanks. --- Anas Mughal [EMAIL PROTECTED] wrote: I am trying to build PHP3 into apache 1.3. I have vanilla PHP and Apache sources. When I do the final Apache 'make', I get an error message complaining about not able to find target for alloc.h. The 'alloc.h' file is declared as a dependency for 'mod_php3.o' in the Makefile in folder 'src/modules/php3'. Any advice would be greatly helpful. = Anas Mughal [EMAIL PROTECTED] [EMAIL PROTECTED] Tel: 973-249-6665 __ Do You Yahoo!? Send FREE Valentine eCards with Yahoo! Greetings! http://greetings.yahoo.com = Anas Mughal [EMAIL PROTECTED] [EMAIL PROTECTED] Tel: 973-249-6665 __ Do You Yahoo!? Send FREE Valentine eCards with Yahoo! Greetings! http://greetings.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Check if var is a domain name
Hello, Does anyone know a function or how I could make a function to check a variable for being a valid domain name without the www. http://www./ In fron of it? Ex. $var = mynewdomain.com that would be TRUE Ex2. $var = www.mynewdomain.com that would be FALSE Ex3. $var = My Great Domain that would be FALSE And so on. Does anyone have a function that makes sure there are no illegal characters and there is a period in the middle of the text? Brandon Orther WebIntellects Design/Development Manager [EMAIL PROTECTED] 800-994-6364 www.webintellects.com
[PHP] What can I ask here?
Just want to make sure I am in the right forum... I am new to PHP and will be doing alot of coding with it in the near future. So I will be asking alot of newb questions... Thanks, Batch -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] What can I ask here?
Hi You'll find the mailing list archive an excellent source of info : http://marc.theaimsgroup.com/?l=php-generalr=1w=2 Regards :) Girish -- www.girishnath.co.uk - Original Message - From: Scott [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 4:07 PM Subject: [PHP] What can I ask here? Just want to make sure I am in the right forum... I am new to PHP and will be doing alot of coding with it in the near future. So I will be asking alot of newb questions... Thanks, Batch -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] What can I ask here?
You can also find good information for PHP here: www.phpdeveloper.org www.phpbuilder.com www.newbienetwork.net www.phpbeginner.com www.php.net // of course =) www.devshed.com Jason Lotito Programmer Developer Clockmedia Inc. Designing Tomorrow's Games, Today! 1-877-625-6256 514-908-2800 Fax: 514-908-2803 - Original Message - From: Girish Nath [EMAIL PROTECTED] To: Scott [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 11:18 AM Subject: Re: [PHP] What can I ask here? Hi You'll find the mailing list archive an excellent source of info : http://marc.theaimsgroup.com/?l=php-generalr=1w=2 Regards :) Girish -- www.girishnath.co.uk - Original Message - From: Scott [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 4:07 PM Subject: [PHP] What can I ask here? Just want to make sure I am in the right forum... I am new to PHP and will be doing alot of coding with it in the near future. So I will be asking alot of newb questions... Thanks, Batch -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] PHP / MYSQL security bug
The PHP developers are aware of this, and are working with MySQL to make it safer. it should be noted that PHP safe mode, whilst making the environment generally safer, is not an easy-answer to webserver security. The only real solution is to learn about better security and configuration. --james -- James Cox :: [EMAIL PROTECTED] Was I helpful? http://www.amazon.co.uk/exec/obidos/wishlist/23IVGHQ61RJGO/ -Original Message- From: Gerard Onorato [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 05, 2002 4:00 PM To: [EMAIL PROTECTED] Subject: [PHP] PHP / MYSQL security bug Maybe I missed the thread but I was wondering if anyone has seen this report or done any testing on it. We tested it and it seems a pretty valid problem. Can anyone comment on a fix that may be in the works? Gerard -- --- Security Advisory DW020203-PHP Release: 3rd February 2002 PHP Safe Mode Filesystem Circumvention Problem Severity: Medium to high. Affects: PHP, all versions which include safe_mode feature. Platform: UNIX, Microsoft Windows, any platforms on which PHP is available. Vendor: http://php.net. Discovered: 12th January 2002, Dave Wilson [EMAIL PROTECTED], using PHP 4.1.0 Apache 2 on Linux. -- VULNERABILITY IN BRIEF PHP (since version 3?) includes a commonly used feature known as Safe Mode. When enabled, scripts are highly limited in their ability to access or execute local files, among other things. PHP relies on a wrapper function around all filesystem calls to perform access checks, but unforunately the bundled MySQL client library has not been modified to perform such checks on LOAD DATA INFILE LOCAL statements. If an attacker has access to a MySQL server (either provided by you or himself), he can use it as a proxy by which to download files residing on the safe_mode-enabled web server. For large ISPs relying on this feature for individual customer privacy, it could mean clients accessing each other's files, or viewing of files on an improperly secured server. FIX Currently, no fix exists. You may use other PHP safe_mode functions to disable the use of the MySQL client library, or secure your servers in a proper fashion.. A suggested fix for the PHP developers might be to scan mysql_query()s for strings similar to LOAD DATA LOCAL INFILE. Happy hackers out there might like to look at libmysql.c:1764 if interested in fixing this problem, although that may only be possible from within PHP. EXAMPLE The attached script will (once configured correctly) attempt to read /var/log/lastlog via the SQL daemon and return it to the client. $ cp safe_mode.php /www $ wget -qO lastlog_via_mysql localhost/safe_mode.php $ diff /var/log/lastlog lastlog_via_mysql; echo $? 0 COMMENTS Due to the nature of the PHP project, development is very rapid and hence many sites do not keep up with latest PHP versions. If a fix was available, it would take quite a while to propagate. It is likely that this is not an isolated problem in PHP, my bets are on PostgreSQL and other PHP database extensions missing this one too. The MySQL support has been enabled in PHP by default for as long as I can remember. DAVE WILSON Currently residing in Belfast, Northern Ireland, he is available for work relating to network security auditing, post-attack recovery and forensics, and penetration testing. He may be contacted at [EMAIL PROTECTED]. If you have any comments regarding this advisory, please contact him directly. Sun Feb 3 21:23:03 GMT 2002 -dw -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP / MYSQL security bug
Hi Folks: Gerard Onorato wrote on the PHP-GENERAL mailing list: Security Advisory DW020203-PHP Release: 3rd February 2002 PHP Safe Mode Filesystem Circumvention Problem ... snip ... FIX Currently, no fix exists. ... snip ... A suggested fix for the PHP developers might be to scan mysql_query()s for strings similar to LOAD DATA LOCAL INFILE. But they're forgetting about MySQL's permission handling. The LOAD DATA command can be controlled by the File_priv permission at the User level. Also, the Insert_priv can be regulated at many levels, including the User, Database, table and column level. Naturally, if one can't insert, there's no way for them to run a LOAD DATA statement. Enjoy, --Dan -- PHP scripts that make your job easier http://www.analysisandsolutions.com/code/ SQL Solution | Layout Solution | Form Solution T H E A N A L Y S I S A N D S O L U T I O N S C O M P A N Y 4015 7 Ave, Brooklyn NY 11232v: 718-854-0335f: 718-854-0409 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Check if var is a domain name
Hi, I would use a regular expression to check it. This is a pretty general
one, but I think it should do the trick. It searches for 1 or more upper
or lowercase letters, followed by a literal dot, followed by 2 or 3
lowercase letters. Of course there are valid domains that would not match
this (foobar.co.uk) for example, but it should work with the values you
specified.
if (ereg(^[a-zA-Z]+\\.[a-z]{2,3}$, $var)) {
// valid domain
}
else{
// not valid
}
Jeff
At 07:59 AM 2/5/2002 -0800, Brandon Orther wrote:
Hello,
Does anyone know a function or how I could make a function to check a
variable for being a valid domain name without the www. http://www./
In fron of it?
Ex. $var = mynewdomain.com that would be TRUE
Ex2. $var = www.mynewdomain.com that would be FALSE
Ex3. $var = My Great Domain that would be FALSE
And so on.
Does anyone have a function that makes sure there are no illegal
characters and there is a period in the middle of the text?
Brandon Orther
WebIntellects Design/Development Manager
[EMAIL PROTECTED]
800-994-6364
www.webintellects.com
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Re: [PHP] Unable to get ImageTTFText output
Girish, After a bit of searching around it appears that this is a bug of early versions of PHP, re-introduced in PHP v4.0.6 (the version I was using). I have upgraded to 4.10 and ImageTTFText now works fine. Neil Girish Nath wrote: Hi I had similar problems when just specifying the font file in the same directory eg ./arial.ttf but got it to work okay when i used the full path eg : $fontfile = /apache/htdocs/arial.ttf; ImageTTFText($im, 20, 0, 3, 3, $text_colour, $fontfile, My text); Regards Girish -- www.girishnath.co.uk - Original Message - From: Neil Freeman [EMAIL PROTECTED] To: PHP General [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 2:59 PM Subject: [PHP] Unable to get ImageTTFText output Hi there, I am trying to use the ImageTTFText function to output some text onto an existing image. Problem being though that the text does not get outputted. I have placed the ttf file 'arial.ttf' within the same directory as my script. Here is a snippet of my code: Header(Content-Type: image/png); $im = ImageCreateFromPNG(original_image.png); $text_colour = ImageColorAllocate($im, 255, 255, 255); ImageTTFText($im, 20, 0, 3, 3, $text_colour, /arial.ttf, My text); ImagePNG($im); All this outputs is my original PNG image (with no text). I have used the following line instead of ImageTTFText and all works well. ImageString($im, 4, 3, 3, My text, $text_colour); Using phpinfo() I have checked the GD section and the following is outputted: GD Support - enabled GD Version - 2.0 or higher FreeType Support - enabled FreeType Linkage - with freetype JPG Support - enabled PNG Support - enabled WBMP Support - enabled Does anyone have any suggestions as to why this does not work? Has anyone else used the ImageTTFText function successfully? Neil Email: [EMAIL PROTECTED] [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php *** This message was virus checked with: SAVI 3.53 Jan 2002 last updated 30th January 2002 *** -- Email: [EMAIL PROTECTED] [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] What can I ask here?
Don't forget about www.phpguru.org www.hotscripts.com Two other great sites for information and sample scripts. Dave Jason Lotito [EMAIL PROTECTED] wrote in message 037201c1ae61$b7e25a10$3b0a@JASON">news:037201c1ae61$b7e25a10$3b0a@JASON... You can also find good information for PHP here: www.phpdeveloper.org www.phpbuilder.com www.newbienetwork.net www.phpbeginner.com www.php.net // of course =) www.devshed.com Jason Lotito Programmer Developer Clockmedia Inc. Designing Tomorrow's Games, Today! 1-877-625-6256 514-908-2800 Fax: 514-908-2803 - Original Message - From: Girish Nath [EMAIL PROTECTED] To: Scott [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 11:18 AM Subject: Re: [PHP] What can I ask here? Hi You'll find the mailing list archive an excellent source of info : http://marc.theaimsgroup.com/?l=php-generalr=1w=2 Regards :) Girish -- www.girishnath.co.uk - Original Message - From: Scott [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, February 05, 2002 4:07 PM Subject: [PHP] What can I ask here? Just want to make sure I am in the right forum... I am new to PHP and will be doing alot of coding with it in the near future. So I will be asking alot of newb questions... Thanks, Batch -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] add value to serialized array?
Hello,
OKay, when i replace the last rows with:
$fp=fopen(test.txt,r);
flock($fp,1);
$array=array_merge($array,unserialize(fread($fp,filesize(test.txt;
flock($fp,3);
fclose($fp);
it works.
But now i want to place this in a class, and it goes wrong again.
Hope you can help, thanks,
Bas
--
?
class test
{
function test(){;}
function read()
{
$array=array();
$fp=fopen(test.txt,r);
flock($fp,1);
$array=unserialize(fread($fp,filesize(test.txt)));
flock($fp,3);
fclose($fp);
return $array;
}
function save($array)
{
$fp=fopen(test.txt,w+);
flock($fp,2);
fwrite($fp,serialize($array));
flock($fp,3);
fclose($fp);
}
function push($array,$value)
{
array_push($array,$value);
$this-save($array);
}
}
$test= new test;
$array=$test-read();
echo $array[0].$array[1].$array[2];
$test-push($array,three);
//$test-save($array);
$array=$test-read();
echo $array[0].$array[1].$array[2];
?
--
Op dinsdag 05 februari 2002 12:24, schreef u:
Hi,
At start test.txt contains a serialized array with value one and two.
a:2:{i:0;s:3:one;i:1;s:3:two;}
after one run this is:
a:3:{i:0;s:3:one;i:1;s:3:two;i:2;s:4:tree;}
But the last row prints nothing. Why?
Tnx,
Bas
?
$array=array();
$fp=fopen(test.txt,r);
flock($fp,1);
$array=unserialize(fread($fp,filesize(test.txt)));
flock($fp,3);
fclose($fp);
array_push($array,tree);
$fp=fopen(test.txt,w+);
flock($fp,2);
fwrite($fp,serialize($array));
flock($fp,3);
fclose($fp);
$fp=fopen(test.txt,r);
flock($fp,1);
$array=unserialize(fread($fp,filesize(test.txt)));
flock($fp,3);
fclose($fp);
echo $array[0].$array[1].$array[2];
?
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Re: [PHP] Problem...header already sent by
Hi Jason, Yeap, I ran 'phpinfo()' Server API=CGI. I look at the manual and you are right, I must run it as Apache module. Can someone tell me how do I change the setting to run as an APACHE module instead? Thanks, -Peter Jason Wong [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED]... On Tuesday 05 February 2002 15:20, Peter wrote: Hi Ryan, Thanks for the examples. Okay, I deleted the other stuff and just put this code and I get this from my interpreter? Is this a setting problem? Are you running PHP as a CGI? If so, what you want to do cannot be done. See chapter HTTP authentication with PHP. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk /* You will triumph over your enemy. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Easy Question -- Show/ Hide text based on output of query
On Wednesday 06 February 2002 00:03, Edward R. Bailey wrote:
Hi,
I am working on a page the displays the output of a query in a table and
I only want to show the field labels that have corresponding output from
the database. I am only really concerned with the last label in the
table.
The label is called Notes and the corresponding field in the database
is memberNotes
So I wrote the following script where I think I am saying if memberNotes
returns any value then print the output of $notes in the table cell
where it is called, but nothing happens and the output of $notes is not
displayed regardless whether memberNotes has any output.
?php If ($memberNotes =='1') {
What is $memberNotes supposed to contain? If it is supposed to contain notes
on members then surely it can't be '1' all the time?
I think you probably want:
if ($memberNotes) { ...
hth
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
Where is John Carson now that we need him?
-- RLG
*/
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Re: [PHP] Problem...header already sent by
On Wednesday 06 February 2002 01:52, Peter Ruan wrote: Hi Jason, Yeap, I ran 'phpinfo()' Server API=CGI. I look at the manual and you are right, I must run it as Apache module. Can someone tell me how do I change the setting to run as an APACHE module instead? Well, you don't change the setting as such. On a Linux system you would've have to recompile PHP and possibly Apache as well. On a Windows system you would probably just download the relevant files and install. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk /* linux: because a PC is a terrible thing to waste ([EMAIL PROTECTED] put this on Tshirts in '93) */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Easy Question -- Show/ Hide text based on output of query
On Wednesday 06 February 2002 02:14, Edward R. Bailey wrote:
Please keep the discussion on the list!
Thanks for responding! Yes the memberNotes database field only
contains information in about a third of the records so I wanted to hide
the entire field and label when their was no relevent data.
I made the change you suggested, but the field label does not show up
when memberNotes contains data. As follows is the current script. Is
what what you suggested?
?php If ($memberNotes) {
$notes = div align=\/left\/font
size=\/-1\/bNotes:/b/font/div;
} else {
$notes = div align=\/left\/font
size=\/-1\/b/b/font/div;
}
?
What are those forward slashes (/) doing in $notes? Try getting rid of them,
they don't look very HTML to me :)
Also try echo($notes) OUTSIDE of a table construct to see what it contains.
hth
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
Q: What do Winnie the Pooh and John the Baptist have in common?
A: The same middle name.
*/
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RE: [PHP] Easy Question -- Show/ Hide text based on output of query
I used echo($notes) at the bottom of the page and the output of $notes
prints reardless of whether or not the db field $memberNotes contains
any data. It seems to me that $notes is always acting as if $memberNotes
always contains data. Is their some way to invoke $notes only if
$memberNotes returns any data?
Thanks for your help,
ED
-Original Message-
From: Jason Wong [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 05, 2002 1:22 PM
To: PHP General Mailing List
Subject: Re: [PHP] Easy Question -- Show/ Hide text based on
output of query
On Wednesday 06 February 2002 02:14, Edward R. Bailey wrote:
Please keep the discussion on the list!
Thanks for responding! Yes the memberNotes database field only
contains information in about a third of the records so I wanted to
hide the entire field and label when their was no relevent data.
I made the change you suggested, but the field label does
not show up
when memberNotes contains data. As follows is the current
script. Is
what what you suggested?
?php If ($memberNotes) {
$notes = div align=\/left\/font
size=\/-1\/bNotes:/b/font/div;
} else {
$notes = div align=\/left\/font
size=\/-1\/b/b/font/div;
}
?
What are those forward slashes (/) doing in $notes? Try
getting rid of them,
they don't look very HTML to me :)
Also try echo($notes) OUTSIDE of a table construct to see
what it contains.
hth
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
Q:What do Winnie the Pooh and John the Baptist have in common?
A:The same middle name.
*/
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Re: [PHP] Easy Question -- Show/ Hide text based on output of query
On Wednesday 06 February 2002 02:38, Edward R. Bailey wrote: I used echo($notes) at the bottom of the page and the output of $notes prints reardless of whether or not the db field $memberNotes contains any data. It seems to me that $notes is always acting as if $memberNotes always contains data. Is their some way to invoke $notes only if $memberNotes returns any data? Please post your full code. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk /* I go on working for the same reason a hen goes on laying eggs. - H. L. Mencken */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Easy Question -- Show/ Hide text based on output of query
Sorry -- Here it is
?php If ($memberNotes) {
$notes = div align=leftfont
size=-1bNotes:/b/font/div;
} else {
$notes = ;
}
?
Then I call $notes using --
echo ($notes)
-Original Message-
From: Jason Wong [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 05, 2002 1:39 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Easy Question -- Show/ Hide text based on
output of query
On Wednesday 06 February 2002 02:38, Edward R. Bailey wrote:
I used echo($notes) at the bottom of the page and the
output of $notes
prints reardless of whether or not the db field
$memberNotes contains
any data. It seems to me that $notes is always acting as if
$memberNotes always contains data. Is their some way to
invoke $notes
only if $memberNotes returns any data?
Please post your full code.
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
I go on working for the same reason a hen goes on laying eggs.
- H. L. Mencken
*/
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Re: [PHP] Easy Question -- Show/ Hide text based on output of query
On Wednesday 06 February 2002 02:53, Edward R. Bailey wrote:
Sorry -- Here it is
?php If ($memberNotes) {
$notes = div align=leftfont
size=-1bNotes:/b/font/div;
} else {
$notes = ;
}
?
Then I call $notes using --
echo ($notes)
I meant your *whole* script -- never mind, have you tried echo($memberNotes)
to see what that contains? Are you sure it doesn't contain spaces or other
non-visible characters?
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
All language designers are arrogant. Goes with the territory...
(By Larry Wall)
*/
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[PHP] Links to other pages
Hi, I have a link on my page that looks like this: $CFG-dirroot= f:/Inetpub/wwwroot/mymarket2; a href=?=$CFG-dirroot?/login.phpLogin/a The link is displayed right on my page, but when I press it a dialog box is saying that I am downloading the php file and wether I want to open or save it. Can anybody tell me what is wrong? Thanks, Morten -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Easy Question -- Show/ Hide text based on output of query
Thanks for all your help, but I figured out what I did wrong
I was calling the memberNotes field using
echo $get_detail-Fields(memberNotes)
so when I replaced $memberNotes in the script with
$get_detail-Fields(memberNotes) it worked like a charm
If ($get_detail-Fields(memberNotes)) {
$notes = div align=leftfont
size=-1bNotes:/b/font/div;
} else {
$notes = ;
}
Dumb error on my part.
Thank you very much for your patience,
Ed
-Original Message-
From: Jason Wong [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 05, 2002 1:53 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Easy Question -- Show/ Hide text based on
output of query
On Wednesday 06 February 2002 02:53, Edward R. Bailey wrote:
Sorry -- Here it is
?php If ($memberNotes) {
$notes = div align=leftfont
size=-1bNotes:/b/font/div;
} else {
$notes = ;
}
?
Then I call $notes using --
echo ($notes)
I meant your *whole* script -- never mind, have you tried
echo($memberNotes)
to see what that contains? Are you sure it doesn't contain
spaces or other
non-visible characters?
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
All language designers are arrogant. Goes with the
territory... (By Larry Wall) */
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Re: [PHP] Problem...header already sent by
Ryan, I just tried it with my Linux box and I get the authentication box...which is good sign. So it looks like a PHP in MS Windows (the 'fabulous' windows) setting which from the error.log file indicates as well. /** error message listed in error.log **/ [Mon Feb 04 22:36:30 2002] [error] [client 127.0.0.1] malformed header from script. Bad header=HTTP/1.0 401 Unauthorized: /apache/php/php.exe In looks like a setting problem in some .ini file. Do you know how to correct this problem? Thanks for the help! -Peter Ryan F. Bayhonan wrote: It will work as expected Peter. ?php header (WWW-authenticate: Basic realm=\Private\); header (HTTP/1.0 401 Unauthorized); echo Unauthorized; exit; ? So where do we go from here?? Ryan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: Changes in Sessions (PHP Versions)
Hey,
I changed it from:
$HTTP_SESSION_VARS[$key] = $value;
To:
session_register($key);
$key = $value;
And now it works fine.
At first, when I wrote the $key = $value... It made no sense... I was
just doing it because I didn't know what else to try. And it actually
works ;) I figured it would set the variable $key to the value of
$value. But it didn't. It created a new variable. Naming it the value of
$key. And giving that new variable the value of $value.
Does this confuse anybody else?? ;)
Thanks for all your help,
-Travis
-Original Message-
From: Yasuo Ohgaki [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 05, 2002 2:33 AM
To: Travis Simpson
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Re: Changes in Sessions (PHP Versions)
If you really need to use 4.0.6, try to use different
session save handler and/or serializer. Try WDDX
serializer at first, then try verious combinations.
If you use other save handler/serializer, it may work.
I suggest you to upgrade, though...
--
Yasuo Ohgaki
Travis Simpson wrote:
Sorry, I probably worded my question wrong.
I am creating a 10 step (or so) form that is non-linear... The user
enters all of their information and is able to go back and change
information that they have filled in. So I have the form (POST)
information set into session variables as soon as they click Next in
the form. Well, with 4.1.1 there were no problems... It ALL worked
perfectly. But unfortunately, in 4.0.6 it doesn't act the same.
I just have a foreach loop go through all the POST variables and make
them into SESSION variables,
--- Snippet ---
start_session();
foreach ($HTTP_POST_VARS as $key = $value) {
$HTTP_SESSION_VARS[$key] = $value;
}
--- End Snippet ---
Easy enough... Now, I have all the 10 steps linked to on the side bar.
a href=step1.php?PHPSESSID=$PHPSESSIDStep 1/a
But for some weird reason, those links BLANK all the session
variables.
I tested this by doing a count() on the HTTP_SESSION_VARS array. And
as
soon as I click one of the Step links on the side, it clears all of
them. I am not sure if I am doing this wrong, but it works fine (as I
said) in 4.1.1.
Another problem that I seem to be having... Is that 4.0.6 almost seems
like it is maxing out with a certain number of SESSION variables. Once
it has so many, it just starts over.
I will just post the link here tomorrow, unfortunately I don't have
the
files on this computer.
I hope this is a little more clear.
Thanks,
-Travis
-Original Message-
From: Yasuo Ohgaki [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 04, 2002 6:11 PM
To: [EMAIL PROTECTED]; Travis Simpson
Subject: [PHP] Re: Changes in Sessions (PHP Versions)
Travis Simpson wrote:
Hey,
I am just wondering if there were any changes done to the session
engine or settings between PHP 4.0.6 and 4.1.1.
I have been getting nothing but grief from 4.0.6 and 4.1.1 seems to
work fine.
What did work with 4.0.6 and what didn't with 4.1.1?
If you are trying to use mm/msession save handler, it's broken
somewhat.
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[PHP] HowTo Send HTTP POST from Within Scrip
Hi eveyone. I'm trying to build an application to interface with UPS Online Tools server. I have to send it an XML formatted request via HTTP POST, and I'm not sure how. Normally, PHP receives such requests when a user clicks a button on a form I created, but how do I initiate a POST from with a script? Better yet, how do I get the response? Thanks for help! Gabe - Ender Technology Corp. Websites, Database Applications, Hosting (310) 516-7411 [EMAIL PROTECTED] http://www.endertechnology.com/ - Ender Technology Corp. Websites, Database Applications, Hosting (310) 516-7411 [EMAIL PROTECTED] http://www.endertechnology.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Links to other pages
You're server will only parse PHP files that come from your server's doot cirectory or one of the virtualhost root directories, and then only when called through the right protocol. If you call a file directly from a drive (in this case, F), you aren't accessing it through the server, and therefore are not parsing the file because the server never sees it. The reason standard HTML works that way is because HTML is browser parsed. The browser makes the decision. PHP is server-parsed, and then sends across the correct headers to force the browser into printing the output as HTML or XML or whatever is being sent. Try changing your $CFG-dirroot to a values based on your server root or a vhost root (for whichever site the script below is for). Mike Frazer Morten Nielsen [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi, I have a link on my page that looks like this: $CFG-dirroot= f:/Inetpub/wwwroot/mymarket2; a href=?=$CFG-dirroot?/login.phpLogin/a The link is displayed right on my page, but when I press it a dialog box is saying that I am downloading the php file and wether I want to open or save it. Can anybody tell me what is wrong? Thanks, Morten -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Check if var is a domain name
Your reg-ex wouldn't quite work. Remember, .info, .name, .coop and other
new TLDs are out or are coming out soon. A limit of {2,3} would rule them
all out as invalid.
It's only really possible if you have a list of all available TLDs and
compare in part to that. There are like 130 TLDs too, so it's not the most
practical thig in the world.
Mike Frazer
Jeff Sheltren [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi, I would use a regular expression to check it. This is a pretty
general
one, but I think it should do the trick. It searches for 1 or more upper
or lowercase letters, followed by a literal dot, followed by 2 or 3
lowercase letters. Of course there are valid domains that would not match
this (foobar.co.uk) for example, but it should work with the values you
specified.
if (ereg(^[a-zA-Z]+\\.[a-z]{2,3}$, $var)) {
// valid domain
}
else{
// not valid
}
Jeff
At 07:59 AM 2/5/2002 -0800, Brandon Orther wrote:
Hello,
Does anyone know a function or how I could make a function to check a
variable for being a valid domain name without the www. http://www./
In fron of it?
Ex. $var = mynewdomain.com that would be TRUE
Ex2. $var = www.mynewdomain.com that would be FALSE
Ex3. $var = My Great Domain that would be FALSE
And so on.
Does anyone have a function that makes sure there are no illegal
characters and there is a period in the middle of the text?
Brandon Orther
WebIntellects Design/Development Manager
[EMAIL PROTECTED]
800-994-6364
www.webintellects.com
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RE: [PHP] Re: Changes in Sessions (PHP Versions)
This suggests that register_globals was set to 'off' in the first case and 'on' in the second case. The lines below are perfect examples of how to change the code when changing the register_globals setting in php.ini. Kirk -Original Message- From: Travis Simpson [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 05, 2002 12:08 PM To: [EMAIL PROTECTED] Cc: 'Yasuo Ohgaki' Subject: RE: [PHP] Re: Changes in Sessions (PHP Versions) Hey, I changed it from: $HTTP_SESSION_VARS[$key] = $value; To: session_register($key); $key = $value; And now it works fine. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] HowTo Send HTTP POST from Within Scrip
Search the archives on PostToHost, or also go here: http://www.zend.com/zend/spotlight/mimocsumissions.php#Heading6 http://marc.theaimsgroup.com/?l=php-generalm=92353052714384w=2 I think if you also search on UPS you will find discussion of this exact problem. Good luck! Kirk -Original Message- From: Gabriel Richards [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 05, 2002 12:42 PM To: PHP General Subject: [PHP] HowTo Send HTTP POST from Within Scrip Hi eveyone. I'm trying to build an application to interface with UPS Online Tools server. I have to send it an XML formatted request via HTTP POST, and I'm not sure how. Normally, PHP receives such requests when a user clicks a button on a form I created, but how do I initiate a POST from with a script? Better yet, how do I get the response? Thanks for help! Gabe - Ender Technology Corp. Websites, Database Applications, Hosting (310) 516-7411 [EMAIL PROTECTED] http://www.endertechnology.com/ - Ender Technology Corp. Websites, Database Applications, Hosting (310) 516-7411 [EMAIL PROTECTED] http://www.endertechnology.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: HowTo Send HTTP POST from Within Scrip
It's usually done with fsockopen();, and curl module functions for SSL servers. There are a few classes for each method, on the most tradicional snippets and clasess websites. I enjoyed using one called Snoopy. Also the manual pages comments are very helpful (both on fsockopen(); related functions and curl module ones). -- Julio Nobrega. Um dia eu chego lá: http://sourceforge.net/projects/toca Gabriel Richards [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi eveyone. I'm trying to build an application to interface with UPS Online Tools server. I have to send it an XML formatted request via HTTP POST, and I'm not sure how. Normally, PHP receives such requests when a user clicks a button on a form I created, but how do I initiate a POST from with a script? Better yet, how do I get the response? Thanks for help! Gabe - Ender Technology Corp. Websites, Database Applications, Hosting (310) 516-7411 [EMAIL PROTECTED] http://www.endertechnology.com/ - Ender Technology Corp. Websites, Database Applications, Hosting (310) 516-7411 [EMAIL PROTECTED] http://www.endertechnology.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Duplicate e-mails
The following php script sends two (2) e-mails to each addressee. Why?
?php
$connection=mysql_connect(localhost,wagner,XXX) or die (No
connection!);
$db=mysql_select_db(sbwresearch,$connection) or die (No database!);
$message= Dear consumer,\n
The following are the online surveys ... etc.\n;
$qry_1=select * from con_inf;
$result_1=mysql_query($qry_1,$connection) or die (No query # 1!);
while ($row_1=mysql_fetch_array($result_1, MYSQL_ASSOC))
{
$e_mail=$row_1[e_mail];
mail($e_mail,
News from SBW Research,
$message,
From:SBW Research [EMAIL PROTECTED]\n);
};
mysql_free_result($result_1);
mysql_close($connection);
header (location:done.htm);
exit;
?
Anthony Rodriguez
([EMAIL PROTECTED])
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[PHP] Books on PHP
Hello, I am new to PHP and was wondering if anyone can point me the right direction with PHP urls and books to learn how to develop web sites using PHP. I read some of the information on www.php.net web site and have the PHP Bible. Thanks, Ron -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Duplicate e-mails
Hi Anthony:
Anthony Rodriguez wrote:
The following php script sends two (2) e-mails to each addressee. Why?
I'll bet the email addresses in question are listed in the table twice. Open
up a MySQL command line prompt and enter select * from con_inf; to make
sure. To keep this from happening, you can delete the duplicates then add a
unique index on the e_mail field in the MySQL table definition.
$qry_1=select * from con_inf;
Side Issue 1: why are you selecting everything (via *) rather than just
e_mail, since that's all you're using in the script?
$result_1=mysql_query($qry_1,$connection) or die (No query # 1!);
while ($row_1=mysql_fetch_array($result_1, MYSQL_ASSOC))
{
$e_mail=$row_1[e_mail];
mail($e_mail,
Side Note 2: You can combiune those two lines into one:
mail($row_1['e_mail'],
mysql_free_result($result_1);
mysql_close($connection);
Side Note 3: You don't worry about these commands in scripts you're about to
exit anyway.
Enjoy,
--Dan
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RE: [PHP] Books on PHP
I got started with a book called, PHP and MySQL Web Development by Luke Welling and Laura Thomson, published by SAMS. This book is clearly written with the self-taught programmer in mind, tearing apart numerous real-world examples and explaining relevant concepts in depth. It does not go into theory or advanced topics making it a terrible book for the experienced programmer. It is also not a good function reference. But far as reference goes, I say forget the books. Nothing can beat the function search at www.php.net. -- Kevin Stone [EMAIL PROTECTED] www.helpelf.com -Original Message- From: Ronald D Wahlen [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 05, 2002 2:07 PM To: [EMAIL PROTECTED] Subject: [PHP] Books on PHP Hello, I am new to PHP and was wondering if anyone can point me the right direction with PHP urls and books to learn how to develop web sites using PHP. I read some of the information on www.php.net web site and have the PHP Bible. Thanks, Ron -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: whic OS is under?
There is something. Its one of the enironment vars I think. Look for UNAME or U something. I'm not sure if this gives the current OS or the OS on which PHP was compiled though. Ivo Stoykov [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi group: Is there a way to guess which OS the script is running? I couldn't find anything in the manual about this. Thank you Ivo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] File Upload -- File Trailer Partial
Please Cc: me -- I can't keep up with anything like the full volume of PHP-General any more and have only lurked for quite some time :-( I'm consistently seeing file uploads get only the trailing N bytes of the file if the file is over a certain size. This is on applications that worked flawlessly under previous versions on the old ISP, but I had to start using http://php.net/move_uploaded_file and working around/through safe mode on the new ISP. The limit does *NOT* seem to be a constant, but perhaps the ISP's attempt to alter the File Upload Limit has affected this over time... I guess I'm seeking reassurance that: A) File upload not known to be broken B) move_uploaded_file completely finishes and CLOSES a file before returning The variance in the amount of data succesfully acquired feels like move_uploaded_file is leaving the file open, and then I fopen() it, and get the latter half of the file due to file-pointer cross-wiring or something. Here is the top bit of phpinfo(): PHP Version 4.2.0-dev System OpenBSD o2 2.9 conf#0 i386 Build Date Jan 29 2002 15:56:06 Configure Command'./configure' '--with-apache=../apache_1.3.22' '--with-config-file-path=/var/www/conf' '--enable-trans-sid' '--enable-ftp' '--enable-sockets' '--with-openssl' '--with-gd' '--with-jpeg-dir=/usr/local/lib' '--with-png-dir=/usr/local/lib' '--with-tiff-dir=/usr/local/lib' '--with-zlib-dir=/usr/include' '--with-mysql' '--with-pdflib' '--with-mcrypt' '--with-pgsql=/usr/local' Server API Apache Virtual Directory Support disabled Configuration File (php.ini) Path /var/www/conf/php.ini ZEND_DEBUG disabled Thread Safety disabled This program makes use of the Zend Scripting Language Engine: Zend Engine v1.2.0, Copyright (c) 1998-2002 Zend Technologies -- Got Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] POST to SSL Server without CURL?
Thank you for your very helpful guidance to this point! My host doesn't have the CURL module installed and it is unlikely they will do it (PHP running on NT). Apparently I can't just fsockopen(www.ups.com, 443); ??? Is there another way? Gabe -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] whic OS is under?
On Mon, 2002-02-04 at 05:45, Ivo Stoykov wrote: Hi group: Is there a way to guess which OS the script is running? I couldn't find anything in the manual about this. Thank you Ivo The constant PHP_OS will tell you. For a list of all currently defined constants, try http://www.php.net/get_defined_constants. Hope this helps, Torben -- Torben Wilson [EMAIL PROTECTED] http://www.thebuttlesschaps.com http://www.hybrid17.com http://www.inflatableeye.com +1.604.709.0506 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mktime() problem
How can I make sure the user enters a date in format
mm/dd/ and the date must be between the year 1600
and 2038.
The script below meets the criterion above, except
mktime() or strtotime() does not validate year 1600
dates. Any suggestions? Thanks
$dateparts = explode('/', $Date);
$month = $dateparts[0];
$day = $dateparts[1];
$year = $dateparts[2];
$date1 = date (m/d/Y, mktime
(0,0,0,$month,$day,$year));
if (!$Date) {
$submit = 0;
$Date = BDate Required/B;
}
elseif (!checkdate($month,$day,$year)) {
$submit = 0;
$Date = BInvalid Date/B;
}
elseif ($Date != $date1) {
$submit = 0;
$Date = BInvalid Date/B;
}
elseif ($year 1600 || $year 2030) {
$submit = 0;
$Date = BInvalid Date/B;
}
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[PHP] How do I display variables in text boxes when the value of a drop down menu changes?
Hi, I have a PHP script that displays a form. On one section of the form, there is a drop down menu followed by a few text boxes. I'd like to alter the values of the text boxes when the user changes the selection in the dropdown menu. What I've done is create 10 arrays (the drop down menu has 10 items hence one array per item). Each time the user changes the selection in the drop down menu, I figure I'd: a) save the current variables to the array corfresponding to the old selection b) fill the text boxes with vales of the array corresponding to the new selection Is this possible using PHP? I figure that since PHP is server side, I will have to use JavaScript to provide some of the functionality I require but how do I set and access PHP variables from JavaScript? If the above is not workable, Is there another way I can accomplish this? Thanks in advance, Don
[PHP] Re: Books on PHP
Hello, Ronald D Wahlen wrote: Hello, I am new to PHP and was wondering if anyone can point me the right direction with PHP urls and books to learn how to develop web sites using PHP. I read some of the information on www.php.net web site and have the PHP Bible. Look here for a long list of books with some reviewed. http://phpclasses.UpperDesign.com/products.html Regards, Manuel Lemos -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] date(), time() different to system time
Hey guys,
I'm running a RH7.2 box with apache 1.3.20 installed and php-4.1.1
installed as a DSO.
Everything is working fine, except that the output from any date() or
time() references is 16 hours behind the system time (and hwtime) on the
machine.
The machine gets its time from an ntp server which is correct; this setup
is similar for other boxes on the network which have no problems with the
date or time in php being correct.
If I output date('T') then the correct timezone (EST...I'm in Aus) is
displayed, but any time or dates are 16 hours behind.
Where does php read the time/date values from? Is there something I can
tweak or something that I should look at to correct this? I know I could
kludge around it in users php code by tacking an extra 16 hours onto each
value but obviously that's not a good solution for a box which will be
used by others!
Any thoughts / headsup would be appreciated.
cheers,
Anth
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[EMAIL PROTECTED] - PLANET NETCOM - www.pnc.com.au
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RE: [PHP] How do I display variables in text boxes when the value of a drop down menu changes?
to access php var in javascript, you'll need to set up javascript vars with the values of the php vars you want to use. eg. ? $foobar = testing; ? script alert(foobar); // will display nothing - not set yet foobar = ?= $foobar; ?; alert(foobar); // now will display testing /script remember, to get the vars back to php, you'll need to make a request to the server using one of serveral methods hope that helps Martin -Original Message- From: Don [mailto:[EMAIL PROTECTED]] Sent: Wednesday, February 06, 2002 9:00 AM To: php list Subject: [PHP] How do I display variables in text boxes when the value of a drop down menu changes? Hi, I have a PHP script that displays a form. On one section of the form, there is a drop down menu followed by a few text boxes. I'd like to alter the values of the text boxes when the user changes the selection in the dropdown menu. What I've done is create 10 arrays (the drop down menu has 10 items hence one array per item). Each time the user changes the selection in the drop down menu, I figure I'd: a) save the current variables to the array corfresponding to the old selection b) fill the text boxes with vales of the array corresponding to the new selection Is this possible using PHP? I figure that since PHP is server side, I will have to use JavaScript to provide some of the functionality I require but how do I set and access PHP variables from JavaScript? If the above is not workable, Is there another way I can accomplish this? Thanks in advance, Don
[PHP] MySQL selecting the maximum value from a column
Thank you all you listeners out there. I'll try to be respectful of your time and patience, and apoligize in advance for my greeness - I am 2 weeks into PHP/MySQL. I am trying to select the higest value from the column Thought_Num below. But it returns nothing. ?PHP $db = mysql_connect(localhost, root); mysql_select_db(DynaSite,$db); $result = mysql_query(SELECT MAX(Thought_Num) FROM quotes,$db); $myrow = mysql_fetch_array($result); print the result is $myrow[Thought_Num]; ? If I change my select to something that without the MAX (e.g. Select from quotes where DocID=1), the code works fine. Thanks in advance for your help. Regards, Melanie Second Street Web Design http://www.second-street.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] MySQL selecting the maximum value from a column
what happens if you do this? $result = mysql_query(SELECT MAX(Thought_Num) as Thought_Num FROM quotes,$db); I'm thinking that the column name in your original query is being called MAX(Thought_Num) and not Thought_Num. Martin -Original Message- From: Melanie Gann [mailto:[EMAIL PROTECTED]] Sent: Wednesday, February 06, 2002 10:12 AM To: [EMAIL PROTECTED] Subject: [PHP] MySQL selecting the maximum value from a column Thank you all you listeners out there. I'll try to be respectful of your time and patience, and apoligize in advance for my greeness - I am 2 weeks into PHP/MySQL. I am trying to select the higest value from the column Thought_Num below. But it returns nothing. ?PHP $db = mysql_connect(localhost, root); mysql_select_db(DynaSite,$db); $result = mysql_query(SELECT MAX(Thought_Num) FROM quotes,$db); $myrow = mysql_fetch_array($result); print the result is $myrow[Thought_Num]; ? If I change my select to something that without the MAX (e.g. Select from quotes where DocID=1), the code works fine. Thanks in advance for your help. Regards, Melanie Second Street Web Design http://www.second-street.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Can anyone jog my memory on HTTP_REFERER Javascript location:replace?
If I understand what I think you're asking, you're trying to access the
results in Javascript of something the PHP script processed... use your php
script to spit out some javascript. For example:
print script language='javascript'\n;
print $Result = .$Results.;\n;
print /script;
-Original Message-
From: Scott Fletcher [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 04, 2002 2:09 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Can anyone jog my memory on HTTP_REFERER Javascript
location:replace?
Hi!
I had found a way around the problem and it work, but when I enabled the
web security features, it messed up. So, with some debugging and I found
the problem and I'm not sure how to find a way around it. You see
I use page1.php to do certain features but the problem is that PHP
execution get done before the file (non-PHP programming) in passthru('...')
get done later. So, I can't get the result before PHP finish executing.
There, I came up with the Javascript where the non-PHP scripting can spit
out the Javascript code and the Javascript take care of it. It work so
well. To my dismay, the PHP pick up the HTTP_REFERER doesn't work because
HTTP_REFERER was all blank when Javascript use location.replace(''); code.
So, it messed up the webpage. Is there a way to get the HTTP_REFERER code?
Or a different Javascript code? I mean there's no way to get the PHP
execution to pause while the non-PHP programming get done first. Is there?
Thanks,
Scott
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Re: [PHP] MySQL selecting the maximum value from a column
On Tue, 2002-02-05 at 15:12, Melanie Gann wrote: Thank you all you listeners out there. I'll try to be respectful of your time and patience, and apoligize in advance for my greeness - I am 2 weeks into PHP/MySQL. I am trying to select the higest value from the column Thought_Num below. But it returns nothing. ?PHP $db = mysql_connect(localhost, root); mysql_select_db(DynaSite,$db); $result = mysql_query(SELECT MAX(Thought_Num) FROM quotes,$db); $myrow = mysql_fetch_array($result); print the result is $myrow[Thought_Num]; ? If I change my select to something that without the MAX (e.g. Select from quotes where DocID=1), the code works fine. Thanks in advance for your help. Essentially, your problem here is that your query 'SELECT MAX(Thought_Num) FROM quotes' will return a column named 'MAX(Though_Num)'--so you either need to do this: print the result is $myrow[MAX(Thought_Num)]; Or, much preferably, explicitly name the column in the query: SELECT max(Thought_Num) as Thought_Num FROM QUOTES ...and then access it as you had before. Regards, Melanie Hope this helps, Torben -- Torben Wilson [EMAIL PROTECTED] http://www.thebuttlesschaps.com http://www.hybrid17.com http://www.inflatableeye.com +1.604.709.0506 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] How do I keep form inputs from being cleared - Please Help!
I have a registration form and if a user enters bad information and the php script generates an error, I want the user to be able to hit back and have his inputs still there. Most websites I've ever used do this, but for some reason, my form loses all its data when the back button is pushed. This doesn't seem like something unique to PHP, but I thought maybe you guys could shed some light. Maybe a header which instructs the browser to cache it? Btw, I plan on having the script reprint the form with the old values anyway, but for reference I'd really like to know because I haven't been able to figure it out. Thanks for any help! =) -Me
Re: [PHP] Problem...header already sent by
Hello again Peter, I describe my reply below. I must run it as Apache module. Can someone tell me how do I change the setting to run as an APACHE module instead? I'll be replying to this question in a Windows Operating System setting. You have 2 option in installing PHP as in Win OS, either to use the executable installer less than 1MB file size or to use the zip file almost 4MB file size (I recommend to use the zip file installer since its more complete interms of modules and othre dlls). Unzipped the zip file into any directory you want then just read and follow the instruction found on the install.txt file. The install.txt file also indicated how to install PHP as a module on Apache, a minor changes on the httpd.conf must be made. The install.txt file will tell you how. Until then Regards, Ryan F. Bayhonan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] date(), time() different to system time
Hey Anth,
Hey guys,
=some of the better-looking amongst us are not guys (and then some of us are...)
I'm running a RH7.2 box with apache 1.3.20 installed and php-4.1.1
installed as a DSO.
Everything is working fine, except that the output from any date() or
time() references is 16 hours behind the system time (and hwtime) on the
machine.
The machine gets its time from an ntp server which is correct; this setup
is similar for other boxes on the network which have no problems with the
date or time in php being correct.
If I output date('T') then the correct timezone (EST...I'm in Aus) is
displayed, but any time or dates are 16 hours behind.
Where does php read the time/date values from? Is there something I can
tweak or something that I should look at to correct this? I know I could
kludge around it in users php code by tacking an extra 16 hours onto each
value but obviously that's not a good solution for a box which will be
used by others!
Any thoughts / headsup would be appreciated.
Check out the meaning of EST.
Sixteen hours behind NSW, Australian time would make it New York time wouldn't it?
Rather than the three-character codes, check out the +or- settings in the date
functions to check that you
and your server are in the same time zone.
=dn
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Re: [PHP] How do I keep form inputs from being cleared - Please Help!
http://www.thickbook.com choose the tutorial for a form with custom error messages. Miles Thompson At 06:40 PM 2/5/2002 -0500, SpamSucks86 wrote: I have a registration form and if a user enters bad information and the php script generates an error, I want the user to be able to hit back and have his inputs still there. Most websites I've ever used do this, but for some reason, my form loses all its data when the back button is pushed. This doesn't seem like something unique to PHP, but I thought maybe you guys could shed some light. Maybe a header which instructs the browser to cache it? Btw, I plan on having the script reprint the form with the old values anyway, but for reference I'd really like to know because I haven't been able to figure it out. Thanks for any help! =) -Me -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] safe mode/mkdir problem - HELP!
Hello!
I'm trying to create a directory, let's say: /some/dir. My script
(create_dir.cgi) is located at the cgi-bin directory and begins with
#!/usr/bin/php. So it's like any other script, isn't it?
The problem is: running php in safe mode with the script permissions:
rwxr-xr-x 8 rootroot1234 Nov 14 12:28 create_dir.cgi
I got:
Warning: MkDir failed (Permission denied) in
/var/www/cgi-bin/create_dir.cgi on line xxx
When executing the instruction: mkdir('/some/dir', 0755);
But /some permissions are:
drwxr-xr-x8 root root 4096 Nov 14 12:28 /some
Running in safe mode, I thought that I could use mkdir() to create it,
because the ownerships are the same! Am I wrong? Safe mode only give
access when the ownerships are the same.
When I change the ownership to /some
to the uid/gid apache is running (apache(48)/apache(48)), I get:
Warning: SAFE MODE Restriction in effect. The script whose uid is 0 is
not allowed to access /some/dir owned by uid 48 in
/var/www/cgi-bin/create_dir.cgi on line xxx
And another doubt is: running my script as a cgi, with the php binary
outside the webserver tree, it runs like any other script (as written in
the manual). I should be able to run it is setuid flags and get complete
access, but even in this case the uid/gid that my script runs is always
the webserver process uid/gid (apache/apache)
I'm running RedHat Linux 7.2 with apache 1.3.22 and php 4.0.6. The php
package includes the php apache module and the php binary.
Thanks in advance,
Roberto
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[PHP] Dynamic Dropdown menu question.
Hi.
I'm working on an edit page where the pull down menu is populated from a
database. I can't figure out how to print selected when that particular
record is the one associated with the current ID. Can anyone help?
Here's my current code:
!-- Dynamic Career Menu--
?php
include(common.inc);
$connection = @mysql_connect($db_host,$db_user,$db_pass) or
die(Couldn't Connect.);
$db = @mysql_select_db($db_name, $connection) or die(Couldn't select
database.);
$sql =SELECT job_id,category,description,job_id AS my_job_id FROM
$cat_table_name;
$result = @mysql_query($sql, $connection) or die(Error #. mysql_errno() .
: . mysql_error());
while ($row = mysql_fetch_array($result)) {
$job_id=$row['job_id'];
$category=$row['category'];
$description=$row['description'];
$my_job_id=$row['my_job_id'];
echo option value=\$job_id\ ;
if ($job_id == '$my_job_id') {
echo selected ;
}
echo $title/option;
}
$num = @mysql_num_rows($result);
?
!-- /Dynamic Career Menu--
This is about the 5th iteration of this menu I've been working on. If
anyone has any ideas, please email me at [EMAIL PROTECTED] as I am on the
digest.
Thanks,
mto
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M A N G O
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f- 303.938.8507
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Re: [PHP] Dynamic Dropdown menu question.
On Tue, 2002-02-05 at 16:23, Michael O'Neal wrote:
Hi.
I'm working on an edit page where the pull down menu is populated from a
database. I can't figure out how to print selected when that particular
record is the one associated with the current ID. Can anyone help?
Here's my current code:
!-- Dynamic Career Menu--
?php
include(common.inc);
$connection = @mysql_connect($db_host,$db_user,$db_pass) or
This isn't your problem, but you do not really need to quote the above
variables.
die(Couldn't Connect.);
$db = @mysql_select_db($db_name, $connection) or die(Couldn't select
database.);
$sql =SELECT job_id,category,description,job_id AS my_job_id FROM
$cat_table_name;
$result = @mysql_query($sql, $connection) or die(Error #. mysql_errno() .
: . mysql_error());
while ($row = mysql_fetch_array($result)) {
$job_id=$row['job_id'];
$category=$row['category'];
$description=$row['description'];
$my_job_id=$row['my_job_id'];
echo option value=\$job_id\ ;
if ($job_id == '$my_job_id') {
This is your problem: remove the quotes. PHP does not interpolate
single-quoted strings:
http://www.php.net/manual/en/language.types.string.php#language.types.string.syntax.single
[snip]
Hope this helps,
Torben
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http://www.thebuttlesschaps.com
http://www.hybrid17.com
http://www.inflatableeye.com
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Re: [PHP] Dynamic Dropdown menu question.
Hi, looking at your sql statement, it seems like you are always setting
my_job_id and job_id to the same value for each row in the table. select
job_id AS my_job_id is just putting the value of job_id in a variable
called my_job_id. Could you tell us the structure of your mysql table please?
Jeff
At 05:23 PM 2/5/2002 -0700, Michael O'Neal wrote:
Hi.
I'm working on an edit page where the pull down menu is populated from a
database. I can't figure out how to print selected when that particular
record is the one associated with the current ID. Can anyone help?
Here's my current code:
!-- Dynamic Career Menu--
?php
include(common.inc);
$connection = @mysql_connect($db_host,$db_user,$db_pass) or
die(Couldn't Connect.);
$db = @mysql_select_db($db_name, $connection) or die(Couldn't select
database.);
$sql =SELECT job_id,category,description,job_id AS my_job_id FROM
$cat_table_name;
$result = @mysql_query($sql, $connection) or die(Error #. mysql_errno() .
: . mysql_error());
while ($row = mysql_fetch_array($result)) {
$job_id=$row['job_id'];
$category=$row['category'];
$description=$row['description'];
$my_job_id=$row['my_job_id'];
echo option value=\$job_id\ ;
if ($job_id == '$my_job_id') {
echo selected ;
}
echo $title/option;
}
$num = @mysql_num_rows($result);
?
!-- /Dynamic Career Menu--
This is about the 5th iteration of this menu I've been working on. If
anyone has any ideas, please email me at [EMAIL PROTECTED] as I am on the
digest.
Thanks,
mto
--
Michael O'Neal
Web Producer
-
M A N G O
B O U L D E R
-
http://www.thinkmango.com
e- [EMAIL PROTECTED]
p- 303.442.1821
f- 303.938.8507
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