[PHP] Invalid Argument ??? Not sure how to debug this
Hi all and Good Morning.
I have been struggling with this code: I was wondering if someone could
lend me a hand.
I am working with this code and can't get the error to disappear.
After running I get
|-|
| Warning: Supplied argument is not a valid MySQL result resource in C:\My
|Documents\My |
| Webs\php\TMPibtpit3zq0.php on line 12
| |
|-|
Line 12 happens to be the WHILE statement. I am not sure if it is the
while statement or the results its looking for.
TIA So far, i havent been able to sleep atleast until I get this.
html
?
if (isset($searchstring))
{
$db = mysql_connect(localhost,webuser,);
mysql_select_db(cd_collection,$db);
$sql= SELECT * FROM cd_list WHERE $searchstring LIKE '%searchstring%'
ORDER BY artist ASC;
$result = mysql_query($sql,$db);
echo TABLE BORDER=2;
echo trtdbArtist/btdbTitle/btdbOptions/b/tr;
while ($myrow = mysql_fetch_array($result))
{
echo trtd.$myrow[artist].td.$myrow[title];
echo tda href=\edit.php?id=.$myrow[cd_id].
\View/a;
}
echo /TABLE;
}
else
{
?
form method=POST action=? $PHP_SELF ?
table border=2 cellspacing=2
trtdInsert Your Search String Here./td
tdSearch Type/td/tr
tr
tdinput type=text name=searchstring size=28/td
tdselect size=1 name=searchtype
option selected value=artistArtist/option
option value=titleTitle/option
option value=categoryCategory/option
/select/td
/tr
/table
pinput type = submit value=Submit name=B1
input type=reset value=Reset/p
/form
?
}
?
/html
**DAN**
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Re: [PHP] Invalid Argument ??? Not sure how to debug this
On Sunday 17 March 2002 16:38, Daniel Negron/KBE wrote: Hi all and Good Morning. I have been struggling with this code: I was wondering if someone could lend me a hand. I am working with this code and can't get the error to disappear. After running I get |-- |---| Warning: Supplied argument is not a valid MySQL result | resource in C:\My Documents\My | Webs\php\TMPibtpit3zq0.php on line 12 | | | - || Line 12 happens to be the WHILE statement. I am not sure if it is the while statement or the results its looking for. Put in some error checking code when you use the mysql functions as per the manual examples and you'll soon find where the error is. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk /* I'm having an emotional outburst!! */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Invalid Argument ??? Not sure how to debug this
Daniel,
$myrow[artist] and $myrow[title]
might be a good place to start. It looks like all your ; are in place.
I don't think you can place inside [] like that:
echo trtd.$myrow[artist].td.$myrow[title];
I have been struggling with this code: I was wondering if someone could
lend me a hand.
Line 12 happens to be the WHILE statement. I am not sure if it is the
while statement or the results its looking for.
TIA So far, i havent been able to sleep atleast until I get this.
html
?
if (isset($searchstring))
{
$db = mysql_connect(localhost,webuser,);
mysql_select_db(cd_collection,$db);
$sql= SELECT * FROM cd_list WHERE $searchstring LIKE '%searchstring%'
ORDER BY artist ASC;
$result = mysql_query($sql,$db);
echo TABLE BORDER=2;
echo trtdbArtist/btdbTitle/btdbOptions/b/tr;
while ($myrow = mysql_fetch_array($result))
{
echo trtd.$myrow[artist].td.$myrow[title];
echo tda href=\edit.php?id=.$myrow[cd_id].
\View/a;
}
echo /TABLE;
}
else
{
?
form method=POST action=? $PHP_SELF ?
table border=2 cellspacing=2
trtdInsert Your Search String Here./td
tdSearch Type/td/tr
tr
tdinput type=text name=searchstring size=28/td
tdselect size=1 name=searchtype
option selected value=artistArtist/option
option value=titleTitle/option
option value=categoryCategory/option
/select/td
/tr
/table
pinput type = submit value=Submit name=B1
input type=reset value=Reset/p
/form
?
}
?
/html
**DAN**
--
John Taylor-Johnston
-
' ' ' Collège de Sherbrooke:
ô¿ô http://www.collegesherbrooke.qc.ca/languesmodernes/
- Université de Sherbrooke:
http://compcanlit.ca/
819-569-2064
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[PHP] mysql fetch field
I seem to be getting unexpected information from a mysql fetch field query.
My table has three fields- here is the schema-
CREATE TABLE template (
id smallint(6) NOT NULL auto_increment,
name mediumtext NOT NULL,
multiple tinyint(4) DEFAULT '0' NOT NULL,
PRIMARY KEY (id),
UNIQUE id (id)
);
Using the samplecode on php.net to output an object containing the
properties of eacj field I have been able to output the following
Blob - 0
MaxLength - 1
Multiple Key - 0
Name - id
Not Null - 1
Numeric - 1
Primary Key - 1
Table - template
Type - int
Unique Key - 1
Unsigned - 0
ZeroFill - 0
Blob - 1
MaxLength - 7
Multiple Key - 0
Name - name
Not Null - 1
Numeric - 0
Primary Key - 0
Table - template
Type - blob
Unique Key - 0
Unsigned - 0
ZeroFill - 0
Blob - 0
MaxLength - 1
Multiple Key - 0
Name - multiple
Not Null - 1
Numeric - 1
Primary Key - 0
Table - template
Type - unknown
Unique Key - 0
Unsigned - 0
ZeroFill - 0
Which strange as the first field is specified as having a max length of 1
yet it is a small int with a length of 6.
Likewise the second field is specified as a blob with a maximum length of 7-
yet in my schema it is a medium text.
And again my third field is listed as havingan unkniwn typeyet in the schema
it is a tinyint
Here is my code
$TableInfo = new DB;
$TableInfoArray = $TableInfo -MySqlGetTableInfo('SELECT * FROM
template');
$a =-1;
$b = -1;
while (++$a count($TableInfoArray)){
$Content[++$b] = Blob - .$TableInfoArray[$a][0].br;
$Content[++$b] = MaxLength - .$TableInfoArray[$a][1].br;
$Content[++$b] = Multiple Key - .$TableInfoArray[$a][2].br;
$Content[++$b] = Name - .$TableInfoArray[$a][3].br;
$Content[++$b] = Not Null - .$TableInfoArray[$a][4].br;
$Content[++$b] = Numeric - .$TableInfoArray[$a][5].br;
$Content[++$b] = Primary Key - .$TableInfoArray[$a][6].br;
$Content[++$b] = Table - .$TableInfoArray[$a][7].br;
$Content[++$b] = Type - .$TableInfoArray[$a][8].br;
$Content[++$b] = Unique Key - .$TableInfoArray[$a][9].br;
$Content[++$b] = Unsigned - .$TableInfoArray[$a][10].br;
$Content[++$b] = ZeroFill - .$TableInfoArray[$a][11].br;
$Content[++$b] = br;
}
$Content = join('', $Content);
return $Content;
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Re: [PHP] Problem with sessions.
On Sat, 16 Mar 2002, Edward van Bilderbeek - Bean IT wrote:
maybe you better use:
session_unregister(counter);
I've put that, but it doesn't run. As you can see in the URLs
below, my code is:
if ($id == logout) { // the user wants logout :(
session_unregister(counter);
}
else { // user is navigating through our links
session_register(counter); // why I recover the previous value here,
// even I've clicked logout?
$counter++;
print counter: $counterbr/\n;
}
}
http://casa.ccp.servidores.net/tutorials/php/sessions/sessions.php and
http://casa.ccp.servidores.net/tutorials/php/sessions/sessions.phps you
have the web page and the code, respectively.
Tom says that I must create a new session with a different name
(now I only start a new session implicitly via session_register()).
Perhaps I am confused with the 'session' term. I thought that if I do
session_destroy() the session forget all the info, but if I check
session_id() before and after session_destroy() I see that the value is
the same.
Thanks for your help,
Carlos.
___Carlos Costa Portela_
| e-mail: [EMAIL PROTECTED] | home page: http://casa.ccp.servidores.net |
|_Tódalas persoas maiores foron nenos antes, pero poucas se lembran__|
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RE: [PHP] mysql fetch field
Actually I've alreasdy worked it out- sorry
-Original Message-
From: caspar kennerdale [mailto:[EMAIL PROTECTED]]
Sent: 17 March 2002 10:31
To: [EMAIL PROTECTED]
Subject: [PHP] mysql fetch field
I seem to be getting unexpected information from a mysql fetch field query.
My table has three fields- here is the schema-
CREATE TABLE template (
id smallint(6) NOT NULL auto_increment,
name mediumtext NOT NULL,
multiple tinyint(4) DEFAULT '0' NOT NULL,
PRIMARY KEY (id),
UNIQUE id (id)
);
Using the samplecode on php.net to output an object containing the
properties of eacj field I have been able to output the following
Blob - 0
MaxLength - 1
Multiple Key - 0
Name - id
Not Null - 1
Numeric - 1
Primary Key - 1
Table - template
Type - int
Unique Key - 1
Unsigned - 0
ZeroFill - 0
Blob - 1
MaxLength - 7
Multiple Key - 0
Name - name
Not Null - 1
Numeric - 0
Primary Key - 0
Table - template
Type - blob
Unique Key - 0
Unsigned - 0
ZeroFill - 0
Blob - 0
MaxLength - 1
Multiple Key - 0
Name - multiple
Not Null - 1
Numeric - 1
Primary Key - 0
Table - template
Type - unknown
Unique Key - 0
Unsigned - 0
ZeroFill - 0
Which strange as the first field is specified as having a max length of 1
yet it is a small int with a length of 6.
Likewise the second field is specified as a blob with a maximum length of 7-
yet in my schema it is a medium text.
And again my third field is listed as havingan unkniwn typeyet in the schema
it is a tinyint
Here is my code
$TableInfo = new DB;
$TableInfoArray = $TableInfo -MySqlGetTableInfo('SELECT * FROM
template');
$a =-1;
$b = -1;
while (++$a count($TableInfoArray)){
$Content[++$b] = Blob - .$TableInfoArray[$a][0].br;
$Content[++$b] = MaxLength - .$TableInfoArray[$a][1].br;
$Content[++$b] = Multiple Key - .$TableInfoArray[$a][2].br;
$Content[++$b] = Name - .$TableInfoArray[$a][3].br;
$Content[++$b] = Not Null - .$TableInfoArray[$a][4].br;
$Content[++$b] = Numeric - .$TableInfoArray[$a][5].br;
$Content[++$b] = Primary Key - .$TableInfoArray[$a][6].br;
$Content[++$b] = Table - .$TableInfoArray[$a][7].br;
$Content[++$b] = Type - .$TableInfoArray[$a][8].br;
$Content[++$b] = Unique Key - .$TableInfoArray[$a][9].br;
$Content[++$b] = Unsigned - .$TableInfoArray[$a][10].br;
$Content[++$b] = ZeroFill - .$TableInfoArray[$a][11].br;
$Content[++$b] = br;
}
$Content = join('', $Content);
return $Content;
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Re: [PHP] send fax
At 17.03.2002 07:35, you wrote: Hi, is it possible to send automated faxes via PHP? Thanks in advance, Senih If your ISP or your server is able to, yes. something like exec(sendfax options,$foo); should do this. check out your system and ISP for more infos on it. Some ISP´s offer the sending of faxes via an special e-mail adress, it´s forwarding a message to a fax. HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] retrieving remote web page
At 17.03.2002 00:45, you wrote: Hi, I'm wanting to retrieve a remote page and extract information from it to insert into my own page. I know that this can be done with fopen, however the page I am wishing to retrieve is generated with a POSTed form. Is there any way that I can retrieve a page that has been created by the filling in of a form (using the POST method)? Thanks for any help... -Andy there are several ways, you can use the snoopy class, look at sourceforge (easiest way) you can use header, to post the vars, and curl to retireve the vars, for me curl works better than fopen. Look at the manual or even at the archive for more infromations. HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] securing the website with htaccess creates problems with getimagesize
Hi there, I did put a password via htaccess on my website to hide my testing environment from other users. Now I discovered, that PHP can't read imagefile information via getimagesize because it does not get access to this dir anymore. How could I add php as a user with propper password ? Thanx for any help, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: No Sense: [PHP] Update: [PHP] Weird?
At 17.03.2002 17:09, you wrote: Hey folks, I read this with half of mind, but as I know, the function date needs something to convert from. $date = date (MD); for my opinion it should be called $date=date(MD,time()); or $date=date(MD,mktime(..)); then everything should work $to_path = c:\\ccl_www\\.$date.\\ccl_www\\; or $to_path = c:\\ccl_www\\$date\\ccl_www\\; HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Copy *.*
At 17.03.2002 03:10, you wrote: Does anyone know of another snippet any place where I can copy *.* (files and all sub-directories) from one drive to another? In other words, a backing-up function. The snippet I got from http://www.php.net/manual/en/function.copy.php has been a disaster. John Which OS are you using ? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OBJECT£ºWHAT'S THE RALATION BETWEEN A,B AND C?
At 17.03.2002 10:01, you wrote:
?php
class A
{
function A($i)
{
$this-value = $i;
// try to figure out why we do not need a reference here
$this-b = new B($this);
}
function createRef()
{
$this-c = new B($this);
}
function echoValue()
{
echo br,class ,get_class($this),': ',$this-value;
}
}
class B
{
function B($a)
{
$this-a = $a;
}
function echoValue()
{
echo br,class ,get_class($this),': ',$this-a-value;
}
}
// try to undestand why using a simple copy here would yield
// in an undesired result in the *-marked line
$a =new A(10);
$a-createRef();
$a-echoValue();
$a-b-echoValue();
$a-c-echoValue();
$a-value = 11;
$a-echoValue();
$a-b-echoValue(); // *
$a-c-echoValue();
?
Even if I don´t understand what your code does, shouldn´t you
give any variable a place to be stored so it schould look like
class foo
{
var $a;
var $b;
function fooplus()
{
$this - a = foofoo;
and so on ??
}
}
HTH Oliver
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Re: [PHP] Problem with sessions.
hi
If you put:
?
session_start();
as the first line on your page it will behave as you want I think.
Tom
At 08:41 PM 17/03/2002, Carlos Costa Portela wrote:
On Sat, 16 Mar 2002, Edward van Bilderbeek - Bean IT wrote:
maybe you better use:
session_unregister(counter);
I've put that, but it doesn't run. As you can see in the URLs
below, my code is:
if ($id == logout) { // the user wants logout :(
session_unregister(counter);
}
else { // user is navigating through our links
session_register(counter); // why I recover the previous value here,
// even I've clicked logout?
$counter++;
print counter: $counterbr/\n;
}
}
http://casa.ccp.servidores.net/tutorials/php/sessions/sessions.php and
http://casa.ccp.servidores.net/tutorials/php/sessions/sessions.phps you
have the web page and the code, respectively.
Tom says that I must create a new session with a different name
(now I only start a new session implicitly via session_register()).
Perhaps I am confused with the 'session' term. I thought that if I do
session_destroy() the session forget all the info, but if I check
session_id() before and after session_destroy() I see that the value is
the same.
Thanks for your help,
Carlos.
___Carlos Costa Portela_
| e-mail: [EMAIL PROTECTED] | home page: http://casa.ccp.servidores.net |
|_Tódalas persoas maiores foron nenos antes, pero poucas se lembran__|
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Re: [PHP] Class Function Issue
At 16.03.2002 22:24, you wrote:
Hi! I'm building a class, and am trying to include an authorization
function the code works when used outside of the class, but when I put
it inside the class, for some reason my session variables won't get
set. Am I attempting the impossible, or am I missing something that I
need to make this work? Below is the code for the Auth function.
function Auth($username,$password) {
$query = SELECT id,username,sl FROM KAOPA_users where
username='$username' AND password=PASSWORD('$password');
$Auth = $this-Query($query);
if ($this-number_returned($Auth) == '1') {
$id = mysql_result($Auth,0,id);
$uname = mysql_result($Auth,0,username);
$sl = mysql_result($Auth,0,sl);
global $HTTP_SESSION_VARS;
$HTTP_SESSION_VARS[id] = $id;
$HTTP_SESSION_VARS[user] = $uname;
$HTTP_SESSION_VARS[sl] = $sl;
}
}
some vars make trouble, using inside a class or function inside a class. Even
making them global doesn´t work. Try to set the vars via an explicit function,
so that they´re available inside your class, or just make them parameters
so your authorisation could look like
$MyClass - Auth($username,$password,$session_vars);
HTH Oliver
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[PHP] replacing all non [a-z] chars possible?
Hi there, I am wondering if it would be possible to replace all chars which are not inbetween [a-z] with a valid asccii coresponding to it. I have a db with a bunch of citynames and I would like to create valid filenames out of those. The prob is, that I do not know all special chars. For example there was one: ï which I did not know. So maybe there are a lot others similar like that. The point is, how could I create a valid filename out of those citynames which contains only the chars from a - z? I tryed erregrplc, but I do have to know the char for that. Thanx for any help, andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with sessions.
On Sun, 17 Mar 2002, Tom Rogers wrote: hi If you put: ? session_start(); as the first line on your page it will behave as you want I think. Thank you very much. It runs now ok :-). But I don't understand why, if I call session_destroy(), the system remember the value of the variable. The system running at... http://casa.ccp.servidores.net/tutorials/php/sessions/sessions.php and http://casa.ccp.servidores.net/tutorials/php/sessions/sessions.phps you have the web page and the code, respectively. Thank you very much, Carlos. ___Carlos Costa Portela_ | e-mail: [EMAIL PROTECTED] | home page: http://casa.ccp.servidores.net | |_Tódalas persoas maiores foron nenos antes, pero poucas se lembran__| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] replacing all non [a-z] chars possible?
A good solution is to store the file under a random generated filename and store that name, together with the real name, to the database. bvr. andy wrote: Hi there, I am wondering if it would be possible to replace all chars which are not inbetween [a-z] with a valid asccii coresponding to it. I have a db with a bunch of citynames and I would like to create valid filenames out of those. The prob is, that I do not know all special chars. For example there was one: ï which I did not know. So maybe there are a lot others similar like that. The point is, how could I create a valid filename out of those citynames which contains only the chars from a - z? I tryed erregrplc, but I do have to know the char for that. Thanx for any help, andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] replacing all non [a-z] chars possible?
I don't agree. Under this circumstances no picture search engine is gonna find this file. Thats why I am rewriting this module. Thanx anyway. Andy Bvr [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... A good solution is to store the file under a random generated filename and store that name, together with the real name, to the database. bvr. andy wrote: Hi there, I am wondering if it would be possible to replace all chars which are not inbetween [a-z] with a valid asccii coresponding to it. I have a db with a bunch of citynames and I would like to create valid filenames out of those. The prob is, that I do not know all special chars. For example there was one: ï which I did not know. So maybe there are a lot others similar like that. The point is, how could I create a valid filename out of those citynames which contains only the chars from a - z? I tryed erregrplc, but I do have to know the char for that. Thanx for any help, andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with sessions.
Hi As you had not started a session at that point there was none to destroy or unregister :) Tom At 11:53 PM 17/03/2002, Carlos Costa Portela wrote: On Sun, 17 Mar 2002, Tom Rogers wrote: hi If you put: ? session_start(); as the first line on your page it will behave as you want I think. Thank you very much. It runs now ok :-). But I don't understand why, if I call session_destroy(), the system remember the value of the variable. The system running at... http://casa.ccp.servidores.net/tutorials/php/sessions/sessions.php and http://casa.ccp.servidores.net/tutorials/php/sessions/sessions.phps you have the web page and the code, respectively. Thank you very much, Carlos. ___Carlos Costa Portela_ | e-mail: [EMAIL PROTECTED] | home page: http://casa.ccp.servidores.net | |_Tódalas persoas maiores foron nenos antes, pero poucas se lembran__| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with sessions.
On Mon, 18 Mar 2002, Tom Rogers wrote: Hi As you had not started a session at that point there was none to destroy or unregister :) Ok!!!. Thank you very much, Carlos. http://www.tertulandia.com : sea cual sea tu tema... allí está tu sitio! ___Carlos Costa Portela_ | e-mail: [EMAIL PROTECTED] | home page: http://casa.ccp.servidores.net | |_Tódalas persoas maiores foron nenos antes, pero poucas se lembran__| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] replacing all non [a-z] chars possible?
At 02:31 PM 3/17/2002 +0100, andy wrote:
Hi there,
I am wondering if it would be possible to replace all chars which are not
inbetween [a-z] with a valid asccii coresponding to it. I have a db with a
bunch of citynames and I would like to create valid filenames out of those.
The prob is, that I do not know all special chars. For example there was
one: ï which I did not know. So maybe there are a lot others similar like
that.
The point is, how could I create a valid filename out of those citynames
which contains only the chars from a - z? I tryed erregrplc, but I do have
to know the char for that.
I found this in the user contributed notes for the function strtr(). It looks
like what you need:
function removeaccents($string) {
return strtr($string,
¥µÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖØÙÚÛÜÝßàáâãäåæçèéêëìíîïðñòóôõöøùúûüýÿ,
SOZsozYYuAAACDNOOYsaaaconooyy);
}
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[PHP] Session --trans-id
I have complied PHP with the enable trans id option However, when I start a session and go to a relivtive link , (./page.php) I do not get a session id in my URI. Any Ideas? Michael -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Writing files a problem
When writing to a file several problems occur with this code: ?php $stuff = include (news.txt); $file = fopen (news.txt, w); $newnews = include (template.txt) . $stuff; fwrite ($file, $newnews); ? However, this code works: ?php $file = fopen(template.txt, w); fwrite ($file, $temp); fclose ($file); ? The problem with the first set of code is that it opens template.txt1, and some letters that were in template.txt become a 1. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Including an external php file existing on another server..
Hi! On my Server i can`t use the date(W) function, and on another it works. How can i first run the script on the other server and then include it in a script on my server so i can use the date(W) variable? thanks, Martin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Writing files a problem
On Monday 18 March 2002 00:46, Ben Waldher wrote: When writing to a file several problems occur with this code: ?php $stuff = include (news.txt); $file = fopen (news.txt, w); $newnews = include (template.txt) . $stuff; fwrite ($file, $newnews); ? However, this code works: ?php $file = fopen(template.txt, w); fwrite ($file, $temp); fclose ($file); ? The problem with the first set of code is that it opens template.txt1, and some letters that were in template.txt become a 1. I've already replied to this before. The include() statement is NOT what you want. Have a look at the functions in the chapter Filesystem functions. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk /* Please ignore previous fortune. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Class Function Issue
oops... meant to send this to the list
- Original Message -
From: Jason Bell [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 10:27 AM
Subject: Re: [PHP] Class Function Issue
Thanks for the tip. I tried that... I passed $HTTP_SESSION_VARS as a
parameter, and it didn't work. :/
I also built another function inside the class to set session variables:
function SetSVAR($var,$value) {
global $HTTP_SESSION_VARS;
$HTTP_SESSION_VARS[$var] = $value;
}
If I call $MyClass-SetSVAR($var,$Value); it works
but if I put $this-SetSVAR($var,$Value); inside a class function it
doesn't
work
is it because these are in the same class? should they be seperated into 2
seperate classes?
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 4:38 AM
Subject: Re: [PHP] Class Function Issue
At 16.03.2002 22:24, you wrote:
Hi! I'm building a class, and am trying to include an authorization
function the code works when used outside of the class, but when I
put
it inside the class, for some reason my session variables won't get
set. Am I attempting the impossible, or am I missing something that I
need to make this work? Below is the code for the Auth function.
function Auth($username,$password) {
$query = SELECT id,username,sl FROM KAOPA_users where
username='$username' AND password=PASSWORD('$password');
$Auth = $this-Query($query);
if ($this-number_returned($Auth) == '1') {
$id = mysql_result($Auth,0,id);
$uname = mysql_result($Auth,0,username);
$sl = mysql_result($Auth,0,sl);
global $HTTP_SESSION_VARS;
$HTTP_SESSION_VARS[id] = $id;
$HTTP_SESSION_VARS[user] = $uname;
$HTTP_SESSION_VARS[sl] = $sl;
}
}
some vars make trouble, using inside a class or function inside a class.
Even
making them global doesn´t work. Try to set the vars via an explicit
function,
so that they´re available inside your class, or just make them parameters
so your authorisation could look like
$MyClass - Auth($username,$password,$session_vars);
HTH Oliver
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php-general Digest 17 Mar 2002 18:49:42 -0000 Issue 1232
php-general Digest 17 Mar 2002 18:49:42 - Issue 1232
Topics (messages 88804 through 88837):
Re: Again, and Again, and AGAIN!
88804 by: Jason Wong
Re: check on pictures
88805 by: Martin Kampherbeek
send fax
88806 by: Senih
88818 by: heinisch.creaction.de
Class Function Issue
88807 by: Jason Bell
88825 by: heinisch.creaction.de
88837 by: Jason Bell
problem with file writing
88808 by: Ben Waldher
88809 by: Jason Wong
Re: Weird?
88810 by: jtjohnston
Copy *.*
88811 by: jtjohnston
88822 by: heinisch.creaction.de
Invalid Argument ??? Not sure how to debug this
88812 by: Daniel Negron/KBE
88813 by: Jason Wong
88814 by: jtjohnston
mysql fetch field
88815 by: caspar kennerdale
88817 by: caspar kennerdale
Re: Problem with sessions.
88816 by: Carlos Costa Portela
88824 by: Tom Rogers
88827 by: Carlos Costa Portela
88830 by: Tom Rogers
88831 by: Carlos Costa Portela
Re: retrieving remote web page
88819 by: heinisch.creaction.de
securing the website with htaccess creates problems with getimagesize
88820 by: andy
Re: No Sense: [PHP] Update: [PHP] Weird?
88821 by: heinisch.creaction.de
Re: OBJECT£ºWHAT'S THE RALATION BETWEEN A,B AND C?
88823 by: Oliver Heinisch
replacing all non [a-z] chars possible?
88826 by: andy
88828 by: bvr
88829 by: andy
88832 by: Michael Sims
Session --trans-id
88833 by: lists.mhess.qn.net
Writing files a problem
88834 by: Ben Waldher
88836 by: Jason Wong
Including an external php file existing on another server..
88835 by: Martin Stix
Administrivia:
To subscribe to the digest, e-mail:
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To unsubscribe from the digest, e-mail:
[EMAIL PROTECTED]
To post to the list, e-mail:
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--
---BeginMessage---
On Sunday 17 March 2002 13:14, Jason Wong wrote:
You're using 4.1.1, $HTTP_POST_VARS{} has been replaced by $_POST[] (see
changelog/history/php.ini for details).
Sorry a typo:
$HTTP_POST_VARS[] has been replaced by $_POST[]
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
What's done to children, they will do to society.
*/
---End Message---
---BeginMessage---
Thanks for repying. Yes, the page has pictures. But all jpg pictures must
link to another jpg pictures. A gif is alowed to link to a html file. The
minium numers of jpg pictures must be 12.
Cheers,
Martin.
- Original Message -
From: Boaz Yahav [EMAIL PROTECTED]
To: Martin Kampherbeek [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Saturday, March 02, 2002 7:35 PM
Subject: RE: [PHP] check on pictures
This is pretty Trivial if the remote pages had a standard. But from your
words I understand that the remote gallery pages can look like anything
and contain links to other places than only images.
Not trivial at all...
Sincerely
berber
Visit http://www.weberdev.com Today!!!
To see where PHP might take you tomorrow.
-Original Message-
From: Martin Kampherbeek [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 28, 2002 10:51 PM
To: [EMAIL PROTECTED]
Subject: [PHP] check on pictures
Can someone help me with this problem?
Someone fills in my form. One field on the form is galleryurl. Here he
types a url with some pictures on it. On this page the are thumbnail
with links to bigger pictures.
Now I want to check if the pictures are realy on it. And I want to check
if there is a link to a picture on the thumbnail and not to a html page.
I hope someone can help me.
Cheers,
Martin.
---End Message---
---BeginMessage---
Hi,
is it possible to send automated faxes via PHP?
Thanks in advance,
Senih
---End Message---
---BeginMessage---
At 17.03.2002 07:35, you wrote:
Hi,
is it possible to send automated faxes via PHP?
Thanks in advance,
Senih
If your ISP or your server is able to, yes.
something like
exec(sendfax options,$foo);
should do this. check out your system and ISP for more infos on it.
Some ISP´s offer the sending of faxes via an special e-mail adress,
it´s forwarding a message to a fax.
HTH Oliver
---End Message---
---BeginMessage---
Hi! I'm building a class, and am trying to include an authorization function the
code works when used outside of the class, but when I put it inside the class, for
some reason my session variables won't get set. Am I attempting the impossible, or am
I missing something that I need to make this work? Below is the code for the Auth
function.
function Auth($username,$password) {
$query = SELECT id,username,sl FROM KAOPA_users where
username='$username' AND password=PASSWORD('$password');
$Auth = $this-Query($query);
if ($this-number_returned($Auth) == '1') {
[PHP] creating a dBase III file
Hi, I need to create a dBase III file however, my ISP does not have PHP compiled with --enable-debase. Does any one have or know of a class that could accomplish this? Thanks, Don
[PHP] substr_count() and regex
Hello there, I am trying to use substr_count() to count the number of Hebrew characters in a string, I tried substr_count($test, /[à-ú]/), but it returns 0 as if it can't match the regex I have inserted there, I hoped it will work the same as preg_match() that works great (preg_match(/[à-ú]/, $test)) for example works just fine, but I guess substr_count() is a bit different... Is there a way for me to do that? maybe with another similar function? (If not I will have to solve it in an ugly while loop that searches for Hebrew characters one by one...) Thank you. Regards Gil Disatnik UNIX system/security administrator. GibsonLP@EFnet _-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_ Windows NT has detected mouse movement, you MUST restart your computer before the new settings will take effect, [ OK ] Windows is a 32 bit patch to a 16 bit GUI based on a 8 bit operating system, written for a 4 bit processor by a 2 bit company which can not stand 1 bit of competition. -_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-
Re: [PHP] substr_count() and regex
?
function count_hebrew($string)
{
$i=0;
while(preg_match(/[à-ú]/,$string))
{
$string=preg_replace(/[à-ú]/,,$string,1);
$i++;
}
return $i;
}
$hebrew_characters=??? àhhjúkkk;
$number_of_hebrew_characters=count_hebrew($hebrew_characters);
echo $number_of_hebrew_characters;
?
Op zondag 17 maart 2002 20:15, schreef Gil Disatnik:
Hello there,
I am trying to use substr_count() to count the number of Hebrew characters
in a string,
I tried substr_count($test, /[à-ú]/), but it returns 0 as if it can't
match the regex I have inserted there, I hoped it will work the same as
preg_match() that works great (preg_match(/[à-ú]/, $test)) for example
works just fine, but I guess substr_count() is a bit different...
Is there a way for me to do that? maybe with another similar function? (If
not I will have to solve it in an ugly while loop that searches for Hebrew
characters one by one...)
Thank you.
Regards
Gil Disatnik
UNIX system/security administrator.
GibsonLP@EFnet
_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Windows NT has detected mouse movement, you MUST restart
your computer before the new settings will take effect, [ OK ]
Windows is a 32 bit patch to a 16 bit GUI based on a 8 bit operating
system, written for a 4 bit processor by a 2 bit company which can
not stand 1 bit of competition.
-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-
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Re: [PHP] Class Function Issue
At 17.03.2002 10:49, you wrote:
Thanks for the tip. I tried that... I passed $HTTP_SESSION_VARS as a
parameter, and it didn't work. :/
I also built another function inside the class to set session variables:
function SetSVAR($var,$value) {
global $HTTP_SESSION_VARS;
$HTTP_SESSION_VARS[$var] = $value;
}
If I call $MyClass-SetSVAR($var,$Value); it works
but if I put $this-SetSVAR($var,$Value); inside a class function it
doesn't
work
I meant :
Main code
--
$FOO = new Yourclass
$sesvar = $HTTP_SESSION_VARS;
$FOO - SetSVars($sesvar);
--
CLASS
yourlass
var insidesesvars;
{
function SetSVAR($sesvar)
{
$this - insidesesvars = $sesvars;
}
} // end Yourclass
There are often problems with so called globalvars like $HTTP_REFERER,
$HTTP_SESSION_VARS ...
using inside Objects, don´t ask me why.
HTH Oliver
At 16.03.2002 22:24, you wrote:
Hi! I'm building a class, and am trying to include an authorization
function the code works when used outside of the class, but when I
put
it inside the class, for some reason my session variables won't get
set. Am I attempting the impossible, or am I missing something that I
need to make this work? Below is the code for the Auth function.
function Auth($username,$password) {
$query = SELECT id,username,sl FROM KAOPA_users where
username='$username' AND password=PASSWORD('$password');
$Auth = $this-Query($query);
if ($this-number_returned($Auth) == '1') {
$id = mysql_result($Auth,0,id);
$uname = mysql_result($Auth,0,username);
$sl = mysql_result($Auth,0,sl);
global $HTTP_SESSION_VARS;
$HTTP_SESSION_VARS[id] = $id;
$HTTP_SESSION_VARS[user] = $uname;
$HTTP_SESSION_VARS[sl] = $sl;
}
}
some vars make trouble, using inside a class or function inside a class.
Even
making them global doesn´t work. Try to set the vars via an explicit
function,
so that they´re available inside your class, or just make them parameters
so your authorisation could look like
$MyClass - Auth($username,$password,$session_vars);
HTH Oliver
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[PHP] Re: index.php question
Try adding a slash to the end of the URL i.e. www.whatever.com/~jondoe/ and see if that helps. Maybe Apache tries to parse your PHP file as if it is an HTML file. Omland Christopher M [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi all, I'm new to the mailing list, I hope I'm in the right spot. I have installed php, and .php files work fine, unless they are my index file. For example http://whatever.com/~jondoe/info.php will work. But if I make a index.php file and go to http://whatever.com/~jondoe it wont work. I can view the source and see my php code, which I know means the server isn't translating it. I'm running RH LINUX, and running apache webserver. I have checked the httpd.conf file and the load modules lines are in there, and they are correct??(I THINK) Any help would be appreciated. Thank You. -Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] pdflib
I have a html report and am looking into using phplib to generate a pdf instead. I have got it installed and started experimenting with it but ether it is extremely convoluted or I am missing something. How would I create a simple list report (the type you would do in a table). It seems all I can to is specify X/Y coordinates and print text. Don't know how many pages the report will be for a start. Ben * Ben Edwards +44 (0)117 9400 636 * * Critical Site Builderhttp://www.criticaldistribution.com * * online collaborative web authoring content management system * * i-Contact Progressive Video http://www.videonetwork.org * * Smashing the Corporate image http://www.subvertise.org * * Bristol Indymedia http://bristol.indymedia.org * * Bristol's radical news http://www.bristle.org.uk * * PGP : F0CA 42B8 D56F 28AD 169B 49F3 3056 C6DB 8538 EEF8 * -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] replacing all non [a-z] chars possible?
I don't agree. First of all, picture search engines don't use filenames, they use ALT attributes and surrounding text. Secondly, you can still make the images available using both the database ID and a urlencoded version of the original filename: http://myserver.org/fetchimage.php/33445/guberstrasse.jpg Just use $PATH_INFO. fetchimage.php looks up 33445, finds the correct file, sends the appropriate headers, and pumps the correct file's data to the browser. The browser and search engines think the filename was guberstrasse.jpg. Everybody wins. miguel On Sun, 17 Mar 2002, andy wrote: I don't agree. Under this circumstances no picture search engine is gonna find this file. Thats why I am rewriting this module. Thanx anyway. Andy Bvr [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... A good solution is to store the file under a random generated filename and store that name, together with the real name, to the database. bvr. andy wrote: Hi there, I am wondering if it would be possible to replace all chars which are not inbetween [a-z] with a valid asccii coresponding to it. I have a db with a bunch of citynames and I would like to create valid filenames out of those. The prob is, that I do not know all special chars. For example there was one: ï which I did not know. So maybe there are a lot others similar like that. The point is, how could I create a valid filename out of those citynames which contains only the chars from a - z? I tryed erregrplc, but I do have to know the char for that. Thanx for any help, andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] pdflib
On Sun, 17 Mar 2002, Ben Edwards wrote: I have a html report and am looking into using phplib to generate a pdf instead. I have got it installed and started experimenting with it but ether it is extremely convoluted or I am missing something. How would I create a simple list report (the type you would do in a table). It seems all I can to is specify X/Y coordinates and print text. Don't know how many pages the report will be for a start. I haven't found it to be particularly easy. It works okay for simple things - our example being a web-based generator for simple office stationery like business cards and envelopes - but for serious text processing you should probably look into adding a few pieces to the process. You can easily generate, for instance, RTF from a database and then pipe it through any of several freely-available programs that will turn that into a PDF. This way you don't have to deal with painful details like page breaks, word wrapping and line lengths, etc. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] links
Hi, I got a table where I on the left has a link to page1. Another place in the table I have a button, which also links to page1. Is it possible to tell which of the two links has been pressed. I need to know so I only show a specific message when the button has been pressed. Regards, Morten -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] links
On Sun, 17 Mar 2002, Morten Nielsen wrote:
I got a table where I on the left has a link to page1. Another place in the
table I have a button, which also links to page1. Is it possible to tell
which of the two links has been pressed.
I need to know so I only show a specific message when the button has been
pressed.
The link:
a href=page1.html?which=1
The button:
a href=page1.html?which=2
page1.html:
? print they clicked link number {$HTTP_GET_VARS['which']}; ?
miguel
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[PHP] Web Tables and php forms
I am completely stuck, and I am preying that someone will be able to help me. I have set up a php web form that allows one of my users to write columns for my site. This works great, I do a search and replace to replace /n with br because they don't know much about html. I have managed to get them into the habit of using bold, italics and underline tags, but now a few of them want to add tables and I have no idea how I can make this easy for them. Has anyone got any idea how I could allow them to do this, or perhaps know of a system that could be of some benefit, keeping in mind their minimal html expertise? Any help would be GREATLY appreciated. Peace
Re: [PHP] Saving data with cookies
At 17.03.2002 18:21, you wrote: Hi list, I'm developing a system to store Resumes, since my form has a lot of fields, about 70, i'd like to have the ability to save the filled ones if my user wants to finish it later. Wha'ts the best way to implement this kind of feature. Maybe I could use cookies, right?!?!? If so, how can I store this, multiples cookies, one big cookie, like an array?? this is possible?? Thank's in advance Rodrigo Peres your form has (70?) inputs like input type=text name=name_of_var[] -- this is an arrayvaraible every field the same name ! the form will then submit an (one) array, which could be stored in your database (For I´m not shure how it will be saved, I would save this array as an something separated text.) you send an cookie with a long lifetime to the client, this cookie is also stored in your DB. So a user wants to continue his form, you can select the users form via the cookie, and send an pre prepared form to the client. I think that´s all. If this user sends it back, you update the textfield, for his next continuation. But take a look on sending cookies, I found out, that the major browsers want different style cookies. HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Invalid Argument ??? Not sure how to debug this
On Sun, 17 Mar 2002, Daniel Negron/KBE wrote:
$sql= SELECT * FROM cd_list WHERE $searchstring LIKE '%searchstring%'
ORDER BY artist ASC;
How about:
SELECT * FROM cd_list WHERE searchstring LIKE '%{$searchstring}%'
Then again, do you actually have a column called searchstring in your
table?
In any case, the way you had it didn't seem to make much sense unless you
wanted to search a user-supplied column for a string that literally
contained the string searchstring.
miguel
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[PHP] Errormessages
I run a script on my page that has worked fine before with 4.0.3 but now when my provider has upgraded to 4.1.2, a bunch of error messages appear. I get some messages about variables not being defined just as if I can't send variables via the adressbar (/ ../index.php?$kat=0 for example. ) How come they suddenly appear as not being defined? I also get a lot of messages saying PHP Warning: Undefined offset: 1 in /home/f/falk/public_html/index.php on line 148 What does it mean that I have an undefined offset? You can find all errormessages here http://www.acc.umu.se/~falk Please help. Markus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Errormessages
On Sun, 17 Mar 2002, Markus Falk wrote: I run a script on my page that has worked fine before with 4.0.3 but now when my provider has upgraded to 4.1.2, a bunch of error messages appear. I get some messages about variables not being defined just as if I can't send variables via the adressbar (/ ../index.php?$kat=0 for example. ) How come they suddenly appear as not being defined? I also get a lot of messages saying PHP Warning: Undefined offset: 1 in /home/f/falk/public_html/index.php on line 148 What does it mean that I have an undefined offset? If you try to, say, print $arr[1] and there is no element in $arr with index '1', then you've got an undefined offset situation. You might want to read http://www.php.net/manual/en/function.error-reporting.php to see how you can control at runtime which errors are displayed. Alternatively, perhaps a lot of fellow customers are having the same issue, and so it might be worth it for your provider to change this globally. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Web Tables and php forms
If you want to do this the hard way (for you) then you can create a form which asks for the number of rows/columns and pops up another form with a table and rows x columns input boxes - then you can build the table code and maybe even insert it in the original code via JavaScript (assuming that the whole tables module would be a popup from the main text editing page). You may want to take a look at nl2br() and htmlspecialchars() so they don't mess up your tables. htmlspecialchars() would obviously inhibit bold and italics rendering. Be warned though that this will never end - they'll need table editing next, then they'll want to be able to delete rows/columns, insert rows/columns, merge cells, split cells, set background colors, styles and whatnot... ;-) HTH Bogdan mikeyb wrote: I am completely stuck, and I am preying that someone will be able to help me. I have set up a php web form that allows one of my users to write columns for my site. This works great, I do a search and replace to replace /n with br because they don't know much about html. I have managed to get them into the habit of using bold, italics and underline tags, but now a few of them want to add tables and I have no idea how I can make this easy for them. Has anyone got any idea how I could allow them to do this, or perhaps know of a system that could be of some benefit, keeping in mind their minimal html expertise? Any help would be GREATLY appreciated. Peace -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Moving server clock?
Right now, I have a static server time clock on my page, produced by date(). I would like to make it move, and I was wondering if anyone has code that returns the server time to javascript to animate it or something? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Web Tables and php forms
I think you have to draw a line somewhere... you can't give them everything they want, becasue the costs involved in making these simple tools available is massive. And at every step where you give them more control, you lose a little more control. Do you REALLY want them creating tables? This could result in more bugs, more code problems, poor presentation, etc etc. That aside, if they just want simple columns, I guess you could have a process where the select how many columns, the widths, etc etc, then supply the content. Also, if they wanted tables to display spreadsheet style data, it's possible someone has created a small program which munch's up a CSV file (comma separated file, which can be exported from programs such as Excel), and spits it out into a table. It couldn't be *that* hard to make one from scratch either. It depends on what they want to achieve by using tables. Justin French mikeyb wrote: I am completely stuck, and I am preying that someone will be able to help me. I have set up a php web form that allows one of my users to write columns for my site. This works great, I do a search and replace to replace /n with br because they don't know much about html. I have managed to get them into the habit of using bold, italics and underline tags, but now a few of them want to add tables and I have no idea how I can make this easy for them. Has anyone got any idea how I could allow them to do this, or perhaps know of a system that could be of some benefit, keeping in mind their minimal html expertise? Any help would be GREATLY appreciated. Peace -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Copy *.*
Windows :) John [EMAIL PROTECTED] wrote: At 17.03.2002 03:10, you wrote: Does anyone know of another snippet any place where I can copy *.* (files and all sub-directories) from one drive to another? In other words, a backing-up function. The snippet I got from http://www.php.net/manual/en/function.copy.php has been a disaster. John Which OS are you using ? -- John Taylor-Johnston - ' ' ' Collège de Sherbrooke: ô¿ô http://www.collegesherbrooke.qc.ca/languesmodernes/ - Université de Sherbrooke: http://compcanlit.ca/ 819-569-2064 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] creating a dBase III file
Don, Since you are creating this file, you can wrap your character fields in quotes. (Surely you can amend it to look after plumbing issues?) They're automatically stripped off in the APPEND FROM .. DELIMITED WITH delimited. Alternately you can use tabs to separate fields, tildes, almost anything. Miles At 06:32 PM 3/17/2002 -0500, you wrote: Hi Miles, Thanks for your response. I was thinking of a way to create a comma delimited file but my problem is that the data might contain commas. Therefore, and CSV file I create from the data might be corrupted. Unfortunately, I cannot alter the data in any way prior. - Original Message - From: Miles Thompson [EMAIL PROTECTED] To: Don [EMAIL PROTECTED] Sent: Sunday, March 17, 2002 2:59 PM Subject: Re: [PHP] creating a dBase III file Don, Maybe you can get at it sideways: create a comma delimited file which the dBase app can import. Alternately, there are sites on the 'Net which give you file structures; dBase is pretty simple as all field are fixed length and you'd only have to make certain that you had the header properly adjusted. Miles Thompson At 02:13 PM 3/17/2002 -0500, you wrote: Hi, I need to create a dBase III file however, my ISP does not have PHP compiled with --enable-debase. Does any one have or know of a class that could accomplish this? Thanks, Don -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] T_CONSTANT_ENCAPSED_STRING error
I'm receiving Parse error: parse error, expecting
`T_CONSTANT_ENCAPSED_STRING' in /host/plugged/index.php on line 3 error
when trying to require_once a couple of files.
top of index.php looks like so (line 3 is where I use $homeDir .
/common/header.php)
?php
require_once(homedir.php);
require_once($homeDir . /common/header.php);
?
contents of homedir.php is
?php
if (getenv(SERVER_ADDR) == 127.0.0.1)
{
$homeDir = C:/home/plugged;
}else{
// $homeDir = dirname(__FILE__);
$homeDir = /home/plugged;
}
?
As you can see I've tried 2 different things in the else statement, I've
even commented out the whole if statement leaving only the else statement
it still bombs. This works perfectly well on my test server it seemed to
be working just fine a couple days ago. Only thing that I can think of is
the fact that I added a couple other variables to homedir.php, but none have
anywhere near the same variable name as $homeDir. I'm not even sure what
the T_CONSTANT_ENCAPSED_STRING error is I'm guessing it's an error or else
why would it stop my page from loading?
Patrick
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Re: [PHP] Moving server clock?
On Sun, 17 Mar 2002, Leif K-Brooks wrote: Right now, I have a static server time clock on my page, produced by date(). I would like to make it move, and I was wondering if anyone has code that returns the server time to javascript to animate it or something? Are you particularly concerned about super precision? If not, why not just output the JavaScript via PHP with the server time in a variable, then you can have your JavaScript calculate the delta against client PC time, and output the current time on an ongoing basis from there. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Targetted redirection?
is there any limitation with header function?im wondering why it not realy
working for me. it really gives me a headache.
i've done exactly what you've told us but it does'nt work. i remove the
comment from the left.php or right.php and retain the index.ph as-is, but
still it doesnt jump out the frames.
* index.php **
?php
# This has no effect.
# header('Window-target: _top');
?
html
headtitleindex page/title/head
frameset COLS=120,*
FRAME SRC=left.php name=menu scrolling=no
frame src=right.php name=content
/frameset
/html
* left.php **
?php
# Turning this on will jump this page out of the frames.
header('Window-target: _top');
?
htmlheadtitlethe menu/title/headbody
a href=right.php target=contentright/a
br /a href=right2.php target=contentright 2/a
/body/html
* right.php **
?php
# Turning this on will jump this page out of the frames.
header('Window-target: _top');
?
HTMLHEADTITLERight/TITLE/HEADBODY
Hi there. This is the main content page in the right frame.
/BODY/HTML
* right2.php **
?php
# This has no effect.
# header('Window-target: _top');
?
HTMLHEADTITLERight 2/TITLE/HEADBODY
Hi there. This is the secondary content page in the right frame.
/BODY/HTML
Now, put all those files on your machine. Hit index.php and you'll see
everything normally. Then, uncomment the header function in left.php or
right.php and you'll see that page jump out of the frames. But, turn
the header on in index.php or index2.php and you'll still be in the
frames.
Enjoy,
--Dan
--
PHP scripts that make your job easier
http://www.analysisandsolutions.com/code/
SQL Solution | Layout Solution | Form Solution
T H E A N A L Y S I S A N D S O L U T I O N S C O M P A N Y
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[PHP] Brain Dead...
I am trying to get a form to work with pull down menu. But I am so brain dead I forgot how to get the input from the pull down menu. Where do I put input to pass on to php? Chuck Payne -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Brain Dead...
Dropdownmenu is a select name=ddmenuoption/select So the php variable that will hold the user's choice is stored in variable $ddmenu. Thus, no input needed. cheers, --thalis On Sun, 17 Mar 2002, Chuck PUP Payne wrote: I am trying to get a form to work with pull down menu. But I am so brain dead I forgot how to get the input from the pull down menu. Where do I put input to pass on to php? Chuck Payne -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Brain Dead...
Ok, but I have this as an example
select name=abc size=1
option value=a selectedA/option
option value=bB/option
option value=cC/option
option value=dD/option
/select
Are you saying that abc should be $abc? I not clear.
I have for my sql as this...
db_name = xxxinks;
$table_name = ssslinks;
$connection = @mysql_connect(mybox.com,anyusers,!@#$%) or die (Couldn't
connect);
$db = @mysql_select_db($db_name, $connection) or die (Couldn't select
database.);
$sql = INSERT INTO $table_name
(abc, key_word, links, name)
VALUES
('$abc', '$keywords', '$links', '$name');
$result = @mysql_query($sql, $connection) or die(Couldn't execute query.);
but I get that it can't do the query. So I am think it not passing abc...
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck PUP Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:25 PM
Subject: Re: [PHP] Brain Dead...
Dropdownmenu is a select name=ddmenuoption/select
So the php variable that will hold the user's choice is stored in variable
$ddmenu.
Thus, no input needed.
cheers,
--thalis
On Sun, 17 Mar 2002, Chuck PUP Payne wrote:
I am trying to get a form to work with pull down menu. But I am so brain
dead I forgot how to get the input from the pull down menu. Where do I
put
input to pass on to php?
Chuck Payne
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Re: [PHP] Brain Dead...
What does I get that it can't do the query mean? What error are you getting?
On Sun, 17 Mar 2002, Chuck Payne wrote:
Ok, but I have this as an example
select name=abc size=1
option value=a selectedA/option
option value=bB/option
option value=cC/option
option value=dD/option
/select
Are you saying that abc should be $abc? I not clear.
I have for my sql as this...
db_name = xxxinks;
$table_name = ssslinks;
$connection = @mysql_connect(mybox.com,anyusers,!@#$%) or die (Couldn't
connect);
$db = @mysql_select_db($db_name, $connection) or die (Couldn't select
database.);
$sql = INSERT INTO $table_name
(abc, key_word, links, name)
VALUES
('$abc', '$keywords', '$links', '$name');
$result = @mysql_query($sql, $connection) or die(Couldn't execute query.);
but I get that it can't do the query. So I am think it not passing abc...
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck PUP Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:25 PM
Subject: Re: [PHP] Brain Dead...
Dropdownmenu is a select name=ddmenuoption/select
So the php variable that will hold the user's choice is stored in variable
$ddmenu.
Thus, no input needed.
cheers,
--thalis
On Sun, 17 Mar 2002, Chuck PUP Payne wrote:
I am trying to get a form to work with pull down menu. But I am so brain
dead I forgot how to get the input from the pull down menu. Where do I
put
input to pass on to php?
Chuck Payne
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RE: [PHP] Brain Dead...
do other variables you pass to the script get set?
if not, do you have register_globals (or whatever it is) turned on?
maybe use $_GET or $_POST instead?
-Original Message-
From: Chuck Payne [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 18, 2002 1:36 PM
To: Thalis A. Kalfigopoulos
Cc: PHP General
Subject: Re: [PHP] Brain Dead...
Ok, but I have this as an example
select name=abc size=1
option value=a selectedA/option
option value=bB/option
option value=cC/option
option value=dD/option
/select
Are you saying that abc should be $abc? I not clear.
I have for my sql as this...
db_name = xxxinks;
$table_name = ssslinks;
$connection = @mysql_connect(mybox.com,anyusers,!@#$%) or die (Couldn't
connect);
$db = @mysql_select_db($db_name, $connection) or die (Couldn't select
database.);
$sql = INSERT INTO $table_name
(abc, key_word, links, name)
VALUES
('$abc', '$keywords', '$links', '$name');
$result = @mysql_query($sql, $connection) or die(Couldn't execute query.);
but I get that it can't do the query. So I am think it not passing abc...
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck PUP Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:25 PM
Subject: Re: [PHP] Brain Dead...
Dropdownmenu is a select name=ddmenuoption/select
So the php variable that will hold the user's choice is stored in variable
$ddmenu.
Thus, no input needed.
cheers,
--thalis
On Sun, 17 Mar 2002, Chuck PUP Payne wrote:
I am trying to get a form to work with pull down menu. But I am so brain
dead I forgot how to get the input from the pull down menu. Where do I
put
input to pass on to php?
Chuck Payne
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Re: [PHP] Brain Dead...
When I go to post, I get the following alertCouldn't execute query so
I know I can connect, so it must be my SQL statement. That why I wondering
how to pass the menu information to php so that it can do the SQL statement.
I don't have $abc in the menu but I do have abc. So I am trying to find out
how to do that. Maybe I am going about it the wrong way.
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:40 PM
Subject: Re: [PHP] Brain Dead...
What does I get that it can't do the query mean? What error are you
getting?
On Sun, 17 Mar 2002, Chuck Payne wrote:
Ok, but I have this as an example
select name=abc size=1
option value=a selectedA/option
option value=bB/option
option value=cC/option
option value=dD/option
/select
Are you saying that abc should be $abc? I not clear.
I have for my sql as this...
db_name = xxxinks;
$table_name = ssslinks;
$connection = @mysql_connect(mybox.com,anyusers,!@#$%) or die
(Couldn't
connect);
$db = @mysql_select_db($db_name, $connection) or die (Couldn't select
database.);
$sql = INSERT INTO $table_name
(abc, key_word, links, name)
VALUES
('$abc', '$keywords', '$links', '$name');
$result = @mysql_query($sql, $connection) or die(Couldn't execute
query.);
but I get that it can't do the query. So I am think it not passing
abc...
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck PUP Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:25 PM
Subject: Re: [PHP] Brain Dead...
Dropdownmenu is a select name=ddmenuoption/select
So the php variable that will hold the user's choice is stored in
variable
$ddmenu.
Thus, no input needed.
cheers,
--thalis
On Sun, 17 Mar 2002, Chuck PUP Payne wrote:
I am trying to get a form to work with pull down menu. But I am so
brain
dead I forgot how to get the input from the pull down menu. Where do
I
put
input to pass on to php?
Chuck Payne
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RE: [PHP] Brain Dead...
Another thing you might want to try doing is throwing in phpinfo() somewhere
to see what variables you are actually getting
-Original Message-
From: Chuck Payne [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 18, 2002 1:44 PM
To: Thalis A. Kalfigopoulos
Cc: PHP General
Subject: Re: [PHP] Brain Dead...
When I go to post, I get the following alertCouldn't execute query so
I know I can connect, so it must be my SQL statement. That why I wondering
how to pass the menu information to php so that it can do the SQL statement.
I don't have $abc in the menu but I do have abc. So I am trying to find out
how to do that. Maybe I am going about it the wrong way.
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:40 PM
Subject: Re: [PHP] Brain Dead...
What does I get that it can't do the query mean? What error are you
getting?
On Sun, 17 Mar 2002, Chuck Payne wrote:
Ok, but I have this as an example
select name=abc size=1
option value=a selectedA/option
option value=bB/option
option value=cC/option
option value=dD/option
/select
Are you saying that abc should be $abc? I not clear.
I have for my sql as this...
db_name = xxxinks;
$table_name = ssslinks;
$connection = @mysql_connect(mybox.com,anyusers,!@#$%) or die
(Couldn't
connect);
$db = @mysql_select_db($db_name, $connection) or die (Couldn't select
database.);
$sql = INSERT INTO $table_name
(abc, key_word, links, name)
VALUES
('$abc', '$keywords', '$links', '$name');
$result = @mysql_query($sql, $connection) or die(Couldn't execute
query.);
but I get that it can't do the query. So I am think it not passing
abc...
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck PUP Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:25 PM
Subject: Re: [PHP] Brain Dead...
Dropdownmenu is a select name=ddmenuoption/select
So the php variable that will hold the user's choice is stored in
variable
$ddmenu.
Thus, no input needed.
cheers,
--thalis
On Sun, 17 Mar 2002, Chuck PUP Payne wrote:
I am trying to get a form to work with pull down menu. But I am so
brain
dead I forgot how to get the input from the pull down menu. Where do
I
put
input to pass on to php?
Chuck Payne
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[PHP] Re: Invalid Argument ??? Not sure how to debug this (RESOLVED)
I guess I should have walked away then come back to it. I was just trying
to get this code to work with little effort as possible. I guess, I should
have done it right in the first place. What I didn't realize is that I
mistakenly made
$sql= SELECT * FROM cd_list WHERE $searchstring LIKE '%searchstring%'
I should have made $searchstring to $searchtype that resolved the initial
problem with the code.
Thank you Nathan. I guess from now on I wont be trying to shortcut coding
Also thank you all for you assistance in this matter.
Thank You
Daniel Negrón
Lotus Notes Administrator / Developer
KB Electronics, Inc.
954.346.4900x122
http://www.kbelectronics.com
Nathan
etherwolf@sop To: Daniel Negron/KBE
[EMAIL PROTECTED]
ris.net cc:
Subject: Re: Invalid Argument ??? Not
sure how to debug this
03/17/2002
04:54 PM
The simplest thing to do to narrow down the source of the problem is change
line 9 to read:
$result = mysql_query($sql,$db) or exit(mysql_error().BR.$sql);
This will halt the script before it even gets to line 12 and give you the
error MySQL had as well as
the query that was sent to the database. This is a very good practice for
the rest of your php code.
Your ...LIKE %searchstring%... bit with no $ will give you all rows
matching:
searchstring*
I take it that is not your intention... You probably need to change that
to:
...LIKE %.$searchstring.%...
Also, why are both your column name and desired value the same? Should you
be selecting WHERE
columnname LIKE %$searchstring%?
If you are still unsuccessful in resolving this, I'll help out however I
can.
Cheers,
# Nathan
- Original Message -
From: Daniel Negron/KBE [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 1:38 AM
Subject: Invalid Argument ??? Not sure how to debug this
Hi all and Good Morning.
I have been struggling with this code: I was wondering if someone could
lend me a hand.
I am working with this code and can't get the error to disappear.
After running I get
|-|
| Warning: Supplied argument is not a valid MySQL result resource in C:\My
Documents\My |
| Webs\php\TMPibtpit3zq0.php on line 12
|
|-|
Line 12 happens to be the WHILE statement. I am not sure if it is the
while statement or the results its looking for.
TIA So far, i havent been able to sleep atleast until I get this.
html
?
if (isset($searchstring))
{
$db = mysql_connect(localhost,webuser,);
mysql_select_db(cd_collection,$db);
$sql= SELECT * FROM cd_list WHERE $searchstring LIKE '%searchstring%'
ORDER BY artist ASC;
$result = mysql_query($sql,$db);
echo TABLE BORDER=2;
echo trtdbArtist/btdbTitle/btdbOptions/b/tr;
while ($myrow = mysql_fetch_array($result))
{
echo trtd.$myrow[artist].td.$myrow[title];
echo tda href=\edit.php?id=.$myrow[cd_id].
\View/a;
}
echo /TABLE;
}
else
{
?
form method=POST action=? $PHP_SELF ?
table border=2 cellspacing=2
trtdInsert Your Search String Here./td
tdSearch Type/td/tr
tr
tdinput type=text name=searchstring size=28/td
tdselect size=1 name=searchtype
option selected value=artistArtist/option
option value=titleTitle/option
option value=categoryCategory/option
/select/td
/tr
/table
pinput type = submit value=Submit name=B1
input type=reset value=Reset/p
/form
?
}
?
/html
**DAN**
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Re: [PHP] Brain Dead...
Is it possible to check the Mysql log and tell us its point of view?
On Sun, 17 Mar 2002, Chuck Payne wrote:
When I go to post, I get the following alertCouldn't execute query so
I know I can connect, so it must be my SQL statement. That why I wondering
how to pass the menu information to php so that it can do the SQL statement.
I don't have $abc in the menu but I do have abc. So I am trying to find out
how to do that. Maybe I am going about it the wrong way.
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:40 PM
Subject: Re: [PHP] Brain Dead...
What does I get that it can't do the query mean? What error are you
getting?
On Sun, 17 Mar 2002, Chuck Payne wrote:
Ok, but I have this as an example
select name=abc size=1
option value=a selectedA/option
option value=bB/option
option value=cC/option
option value=dD/option
/select
Are you saying that abc should be $abc? I not clear.
I have for my sql as this...
db_name = xxxinks;
$table_name = ssslinks;
$connection = @mysql_connect(mybox.com,anyusers,!@#$%) or die
(Couldn't
connect);
$db = @mysql_select_db($db_name, $connection) or die (Couldn't select
database.);
$sql = INSERT INTO $table_name
(abc, key_word, links, name)
VALUES
('$abc', '$keywords', '$links', '$name');
$result = @mysql_query($sql, $connection) or die(Couldn't execute
query.);
but I get that it can't do the query. So I am think it not passing
abc...
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck PUP Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:25 PM
Subject: Re: [PHP] Brain Dead...
Dropdownmenu is a select name=ddmenuoption/select
So the php variable that will hold the user's choice is stored in
variable
$ddmenu.
Thus, no input needed.
cheers,
--thalis
On Sun, 17 Mar 2002, Chuck PUP Payne wrote:
I am trying to get a form to work with pull down menu. But I am so
brain
dead I forgot how to get the input from the pull down menu. Where do
I
put
input to pass on to php?
Chuck Payne
--
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Re: [PHP] Brain Dead...
I think it I am the right path now, it has to do with $_GET or $_POST not
passing the information on to mysql.
But I will look at the log shortly.
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 10:00 PM
Subject: Re: [PHP] Brain Dead...
Is it possible to check the Mysql log and tell us its point of view?
On Sun, 17 Mar 2002, Chuck Payne wrote:
When I go to post, I get the following alertCouldn't execute query
so
I know I can connect, so it must be my SQL statement. That why I
wondering
how to pass the menu information to php so that it can do the SQL
statement.
I don't have $abc in the menu but I do have abc. So I am trying to find
out
how to do that. Maybe I am going about it the wrong way.
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:40 PM
Subject: Re: [PHP] Brain Dead...
What does I get that it can't do the query mean? What error are you
getting?
On Sun, 17 Mar 2002, Chuck Payne wrote:
Ok, but I have this as an example
select name=abc size=1
option value=a selectedA/option
option value=bB/option
option value=cC/option
option value=dD/option
/select
Are you saying that abc should be $abc? I not clear.
I have for my sql as this...
db_name = xxxinks;
$table_name = ssslinks;
$connection = @mysql_connect(mybox.com,anyusers,!@#$%) or die
(Couldn't
connect);
$db = @mysql_select_db($db_name, $connection) or die (Couldn't
select
database.);
$sql = INSERT INTO $table_name
(abc, key_word, links, name)
VALUES
('$abc', '$keywords', '$links', '$name');
$result = @mysql_query($sql, $connection) or die(Couldn't execute
query.);
but I get that it can't do the query. So I am think it not passing
abc...
Chuck
- Original Message -
From: Thalis A. Kalfigopoulos [EMAIL PROTECTED]
To: Chuck PUP Payne [EMAIL PROTECTED]
Cc: PHP General [EMAIL PROTECTED]
Sent: Sunday, March 17, 2002 9:25 PM
Subject: Re: [PHP] Brain Dead...
Dropdownmenu is a select name=ddmenuoption/select
So the php variable that will hold the user's choice is stored in
variable
$ddmenu.
Thus, no input needed.
cheers,
--thalis
On Sun, 17 Mar 2002, Chuck PUP Payne wrote:
I am trying to get a form to work with pull down menu. But I am
so
brain
dead I forgot how to get the input from the pull down menu.
Where do
I
put
input to pass on to php?
Chuck Payne
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RE: [PHP] PHP CGI
simple answer - yes and possibly I believe, anything that's run on a server to output stuff to a browser, can be considered a CGI program The second question is like asking - Will COBOL ever become obsolete? - maybe, possibly, but there'll, no doubt, be someone, somewhere still using it. -Original Message- From: David Duong [mailto:[EMAIL PROTECTED]] Sent: Monday, March 18, 2002 2:08 PM To: [EMAIL PROTECTED] Subject: [PHP] PHP CGI Can PHP be considered CGI? Would PHP replace Perl as the main language of CGI? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Having problems doing a binary upload. open_basedir problem?
I'm attempting to get file uploads via a HTML form to work. I've been
working on this for a couple of days, reading the PHP.net manual, and
searching the newsgroups and various web sites. Haven't come up with a
solution to my problem.
Basically I'm unable to upload any files to my web site. I don't have
control over the server since my site is hosted. Here is the error messages
I'm getting followed by the code.
** HTML output: **
User file: /tmp/phpEhNNmW
User filename: biglaugha.gif
User file size: 1370
User file type: image/gif
Testing short track var names.
$_FILES['userfile']['tmp_name']: /tmp/phpEhNNmW
$_FILES['userfile']['name']: biglaugha.gif
Warning: open_basedir restriction in effect. File is in wrong directory
in /usr/local/psa/home/vhosts/logicalsystem.com/httpdocs/up_load.php on
line 18
Warning: Unable to create '/httpdocs/biglaugha.gif': No such file or
directory in
/usr/local/psa/home/vhosts/logicalsystem.com/httpdocs/up_load.php on
line 23
Warning: Unable to move '/tmp/phpEhNNmW' to '/httpdocs/biglaugha.gif' in
/usr/local/psa/home/vhosts/logicalsystem.com/httpdocs/up_load.php on
line 23
** end of output **
** HTML/PHP file containing the form **
!DOCTYPE html public -//W3C//DTD HTML 4.01 Transitional//EN
HTML
HEAD
TITLETest Upload/TITLE
/HEAD
BODY
FORM action=up_load.php method=post enctype=multipart/form-
data
INPUT type=hidden name=MAX_FILE_SIZE value=10Send
this file:
INPUT name=userfile type=file
INPUT type=submit value=Send File
/FORM
/BODY
/HTML
** end of file **
** PHP files that processes the submitted form(up_load.php) **
?php
//Print some vars for debugging
print strongUser file:/strong $userfile;
print br;
print strongUser filename:/strong $userfile_name;
print br;
print strongUser file size/strong: $userfile_size;
print br;
print strongUser file type:/strong $userfile_type;
print br;
print brTesting short track var names.br;
print strong\$_FILES['userfile']['tmp_name']:/strong .$_FILES
['userfile']['tmp_name'];
print br;
print strong\$_FILES['userfile']['name']:/strong .$_FILES['userfile']
['name'];
print br;
// In PHP 4.1.0 or later, $_FILES should be used instead of
$HTTP_POST_FILES.
//This code is a direct lift from the PHP.net site.
if (is_uploaded_file($HTTP_POST_FILES['userfile']['tmp_name']))
{
//made some changes to this line to reflect target directory.
//I also have another directory /httpdocs/tmp that has rwx for world.
//Same results
copy($HTTP_POST_FILES['userfile']['tmp_name'], /httpdocs/);
} else {
echo Possible file upload attack. Filename: . $HTTP_POST_FILES
['userfile']['name'];
}
/* ...or... */
move_uploaded_file($HTTP_POST_FILES['userfile']['tmp_name'], /httpdocs/
$userfile_name);
?
** end of file **
** Some vars returned using phpinfo() **
safe_mode: On
open_basedir: /usr/local/psa/home/vhosts/logicalsystem.com/httpdocs
upload_tmp_dir: /tmp
PHP is version 4.1.0
The end goal is to put the data into a database. I've used the fopen and
fread functions with not success. I backed off and tried the example from
the PHP.net manual and that doesn't work either. This appears to be a
problem with safe mode and/or open_basedir being set. Is there a work
around or something?
Thanks!
Jack
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Re: [PHP] Errormessages
On Monday 18 March 2002 06:31, Markus Falk wrote: I run a script on my page that has worked fine before with 4.0.3 but now when my provider has upgraded to 4.1.2, a bunch of error messages appear. I get some messages about variables not being defined just as if I can't send variables via the adressbar (/ ../index.php?$kat=0 for example. ) How come they suddenly appear as not being defined? I also get a lot of messages saying PHP Warning: Undefined offset: 1 in /home/f/falk/public_html/index.php on line 148 What does it mean that I have an undefined offset? You can find all errormessages here http://www.acc.umu.se/~falk Because in PHP 4.1.1+ the setting register_globals has been turned off by 'default'. To access the variables passed through the URL you need to use $_GET[]. For your example above that would be $_GET['kat']. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk /* When the English language gets in my way, I walk over it. -- Billy Sunday */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] I need help building The CGI Open Source Foundry (COSF)
I need some experienced people to become managers of the CGI Open Source Foundry (COSF)? I am planning to make a CGI Open Source Foundry We will start in stages. Stage 1 getting initial members (Hard Part) - Once we gain 10-20 members we will start stage 2. Stage 2 Dividing them into groups (members can be in multiple groups) - Managers - Head(s) of the specific groups. - GUI - Members with strong webdesigner skills - Database - File Wizards - Good with file manipulation - Clean-up - Clean up the source - General Developers - Resource - Find servers to host this - Marketers - Those who will distribute the scripts. - Newbies/Learners - Webmasters - See Stage 5 Stage 3 Finding/Creating a Groupware script that will allow us to all to work on single or multiple scripts. Stage 4 Decide what would be the perfect first project. This project may be an existing one in the makes with high potential, or something from scratch. (Ten people on one script may sound crazy but I think it will work if we planned it out.) Stage 5 Making the main site. The site will include a place to Release and Plan all our scripts. I have my eye on SourceForge.net as host. After the first stages well start making other scripts that will be of use. If your interested or have comments than your input would be appreciated. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] password protect off site file
Hello, Is there any way to password protect a file for an include(); that is off site? Server A has a php script that has a call to a text file on server B, but to get access I need the A user to enter a password ID before they can take a look at the file on B. htaccess only works for images - not includes in php. Any suggestions? Thanks for any input, Sean -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP CGI
On Sun, 17 Mar 2002, David Duong wrote: Can PHP be considered CGI? Sometimes. CGI is a standardized interface between web servers and backend applications. PHP can communicate with web servers using that mechanism, but it doesn't have to (depends on the web server in use). I think the problem here is that you're not asking the question you think you're asking. Unfortunately, I'm not sure what you're really trying to figure out. Would PHP replace Perl as the main language of CGI? Who knows? It might. Its use is growing rapidly, and it's much easier to learn. A few years ago the prospect would have been unthinkable, due to the vastly greater supply of Perl CGI web apps and free libraries in circulation. These days the advantage is not so strong. And PHP is far better optimized for the specific task of web application development. On the other hand, Perl is in the abstract a more powerful language. So many programmers will continue to prefer it. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP CGI
I mean any time you hear the word CGI it is rarely referring to PHP, always Perl (My most comfortable Web language). You'd think that CGI only refers to Perl. If you goto a site and download scripts under category CGI you would be downloading Perl scripts, PHP has its own category. Should CGI still mainly Perl even though PHP is somewhat easier, quicker thus easier suited for CGI. I think the meaning of CGI is quite blured. Anyone else think so? [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... On Sun, 17 Mar 2002, David Duong wrote: Can PHP be considered CGI? Sometimes. CGI is a standardized interface between web servers and backend applications. PHP can communicate with web servers using that mechanism, but it doesn't have to (depends on the web server in use). I think the problem here is that you're not asking the question you think you're asking. Unfortunately, I'm not sure what you're really trying to figure out. Would PHP replace Perl as the main language of CGI? Who knows? It might. Its use is growing rapidly, and it's much easier to learn. A few years ago the prospect would have been unthinkable, due to the vastly greater supply of Perl CGI web apps and free libraries in circulation. These days the advantage is not so strong. And PHP is far better optimized for the specific task of web application development. On the other hand, Perl is in the abstract a more powerful language. So many programmers will continue to prefer it. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] PHP CGI
I think the meaning of CGI is quite blured. Anyone else think so? I think the the meaning of CGI (Common Gateway Interface) has lost it's meaning by a lot of people who just hear the acronym and not the full phrase. It's like the term PC - when people hear that, they almost straight away think IBM/IBM Compats, but, as all of you should know, there's MANY other types of PC around the place, not just IBM/IBM Compats. Same goes for CGI programs. -Original Message- From: David Duong [mailto:[EMAIL PROTECTED]] Sent: Monday, March 18, 2002 3:47 PM To: [EMAIL PROTECTED] Subject: Re: [PHP] PHP CGI I mean any time you hear the word CGI it is rarely referring to PHP, always Perl (My most comfortable Web language). You'd think that CGI only refers to Perl. If you goto a site and download scripts under category CGI you would be downloading Perl scripts, PHP has its own category. Should CGI still mainly Perl even though PHP is somewhat easier, quicker thus easier suited for CGI. I think the meaning of CGI is quite blured. Anyone else think so? [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... On Sun, 17 Mar 2002, David Duong wrote: Can PHP be considered CGI? Sometimes. CGI is a standardized interface between web servers and backend applications. PHP can communicate with web servers using that mechanism, but it doesn't have to (depends on the web server in use). I think the problem here is that you're not asking the question you think you're asking. Unfortunately, I'm not sure what you're really trying to figure out. Would PHP replace Perl as the main language of CGI? Who knows? It might. Its use is growing rapidly, and it's much easier to learn. A few years ago the prospect would have been unthinkable, due to the vastly greater supply of Perl CGI web apps and free libraries in circulation. These days the advantage is not so strong. And PHP is far better optimized for the specific task of web application development. On the other hand, Perl is in the abstract a more powerful language. So many programmers will continue to prefer it. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP CGI
On Sun, 17 Mar 2002, David Duong wrote: I mean any time you hear the word CGI it is rarely referring to PHP, always Perl (My most comfortable Web language). You'd think that CGI only refers to Perl. Back in the day, CGI repositories had a greater representation of programs written in C and other hardcore languages. As web servers became more available, the center of gravity of CGI development moved toward more accessible languages, such as Perl (along with shell scripts, Python, TCL, etc.). If you goto a site and download scripts under category CGI you would be downloading Perl scripts, PHP has its own category. One reason for this is that PHP is not necessarily CGI. The typical high-performance PHP installation is running as either a static or dynamic module linked into Apache through that web server's proprietary interface. For all these people, CGI has nothing to do with it. In point of fact, many people also run Perl in similar fashions (such as mod_perl), in which case CGI is also out of the equation. But by the time this became common, Perl web development had already developed a strong connection to the term CGI. Should CGI still mainly Perl even though PHP is somewhat easier, quicker thus easier suited for CGI. People should do their development any way they feel comfortable. Once again, though, you're confusing CGI, which is a specific interface, with server-side web application development in general. I think the meaning of CGI is quite blured. Anyone else think so? Yes, the term is very often misused and has come to be misconstrued as referring to things that have nothing to do with CGI. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] $_SESSION / Windows doesn't work!?
Hi,
I'm trying to use $_SESSION on Windows2000+PHP4.1.2 binary version.
But it seems that $_SESSION doesn't work, even in the simplest samples
like;
--
?php
session_start();
if (!isset($_SESSION['count'])) {
$_SESSION['count'] = 0;
}
else {
$_SESSION['count']++;
}
print session_name().=.session_id().br.$_SESSION['count'];
?
a href='?=$PHP_SELF ?'!/a
---
session_id is set properly in this case.
Moreover, the old way of using session works, i.e. session_register(...)
and so on.
Does anyone know about this trouble?
Regards,
Hiroshi Ayukawa
http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top
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[PHP] empty lines cause http headers?
I'm writing a page that will do a little snooping into a db (based on a previous form submit) and start a session based on the results. The problem is that PHP seems to be sending the HTTP headers when it encounters the first blank line in the code (which I do use to help separate the code a bit). Am I right in this assumption .. and then the big Q.. how do I do PHP calculations and then specify a session without sending premature headers by accident? ~ Mike -- Mike Zornek | Project Leader Apple Student Developers The Insanely Great Site with the Insanely Long URL http://www.applestudentdevelopers.org Personal Site: http://www.mikezornek.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] empty lines cause http headers?
On Mon, 18 Mar 2002, Michael Zornek wrote:
The problem is that PHP seems to be sending the HTTP headers when it
encounters the first blank line in the code (which I do use to help separate
the code a bit).
Am I right in this assumption .. and then the big Q.. how do I do PHP
calculations and then specify a session without sending premature headers by
accident?
Just make sure the blank lines are ? inside php tags ?
If they're out in the raw HTML area, the headers will get packaged up and
the content output buffer collection will begin.
- - - - - - bad - - - - - -
?
header('X-Site-Type: Fabulous');
print 'That blank line gave me just the breathing room I needed.';
?
- - - - - - good - - - - - -
?
header('X-Site-Type: Fabulous');
print 'So did this one, but it won't stop my header from working.';
?
- - - - - - - - - - - -
miguel
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[PHP] unscriber please
Roy Daniel , ST IT Developer System - PT BERCA COMPUTEL My E-mail : [EMAIL PROTECTED] and : [EMAIL PROTECTED] / [EMAIL PROTECTED] My ICQNumber : # 103507581 My Phone Cell : 0816-1192832 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] empty lines cause http headers? [FIXED]
Twas 3/18/02 12:21 AM, when [EMAIL PROTECTED] [EMAIL PROTECTED] said: Just make sure the blank lines are ? inside php tags ? If they're out in the raw HTML area, the headers will get packaged up and the content output buffer collection will begin. After some investigation I saw an extra space after the closing PHP ? tag after an include call. No more error :-) .. not to say my script is working as anticipated yet though .. hehe.. Thanks guys! ~ Mike -- Mike Zornek | Project Leader Apple Student Developers The Insanely Great Site with the Insanely Long URL http://www.applestudentdevelopers.org Personal Site: http://www.mikezornek.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] pathname
I need a function to traverse a pathname
to check if the path exists, if not start from scratch
and create (MkDir) the path.
Let's say:
$to_path = c:\\aaa\\bbb\\ccc\\ddd\\;
or
$to_path = c:/aaa/bbb/ccc/ddd/;
if(!is_dir($to_path))
{
#I need to explode by both \\ AND / to find out
mkdir($to_path, 0777);
}
How do I parse it and MkDir the path?
Thanks,
John
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Re: [PHP] pathname
On Mon, 18 Mar 2002, jtjohnston wrote:
I need a function to traverse a pathname
to check if the path exists, if not start from scratch
and create (MkDir) the path.
Let's say:
$to_path = c:\\aaa\\bbb\\ccc\\ddd\\;
or
$to_path = c:/aaa/bbb/ccc/ddd/;
if(!is_dir($to_path))
{
#I need to explode by both \\ AND / to find out
mkdir($to_path, 0777);
}
How do I parse it and MkDir the path?
1. Change all \\ to /
2. Explode the string on /
3. Loop $i from 1 to number of parts
3a. Implode $i elements from the exploded array on / to form a subpath
3b. Does that directory exist?
3c. If not, mk it
3d. Increment $i and go back to 3a
4. Presto, you're done
miguel
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[PHP] NNTP Services
Hello everyone I have a problem to post messages to newsgroups. How can i do it. thanks Muhammad Fawad -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] rec_copy
http://www.php.net/manual/en/function.copy.php
Thanks all! I needed to check if pathname exists:
if (!is_dir($to_path))
{
echo Creating destination pathbr;
create_path($to_path);
}
John Steele helped out with a few lines of code. I added a comment to
http://www.php.net/manual/en/function.copy.php
Here is the result:
?
###
$date = date (Ymd);
###
#$from_path = c:\\tmp\\cp\\from;
$from_path = c:/program files/easyphp/ccl_www;
$to_path = c:/tmp/cp/to/$date/ccl_www;
###
if (!is_dir($to_path))
{
echo Creating destination pathbr;
create_path($to_path);
}
###
if(!is_dir($from_path))
{
echo failed;
exit;
}
else
{
rec_copy($from_path, $to_path);
echo Files copied from $from_path and backed up to $to_path\n;
}
#
function rec_copy($from_path, $to_path)
{
if (!is_dir($to_path))
# create_path($to_path);
mkdir($to_path, 0777);
$this_path = getcwd();
if (is_dir($from_path))
{
chdir($from_path);
$handle = opendir('.');
while (($file = readdir($handle)) !== false)
{
if (($file != .) ($file != ..))
{
if (is_dir($file))
{
rec_copy ($from_path.\\.$file, $to_path.\\.$file);
chdir($from_path);
}
if (is_file($file))
{
copy($from_path.\\.$file, $to_path.\\.$file);
}
}
}
closedir($handle);
}
else
{
echo if (is_dir($from_path))br;
}
}
function create_path($to_path)
{
$path_array = explode('/', $to_path); // split the path by directories
/*
echo 'pre';// show everything in the $path_array variable
var_dump($path_array);
echo '/pre';
*/
$dir=''; // start with empty directory
foreach($path_array as $key = $val) {
// echo $key = $valbr;
if (!strpos($val, ':')) { // if it's not a drive letter
$dir .= '/'. $val;
if (!is_dir($dir)) {
// echo Not a dir: $dirbr;
if (!mkdir($dir, 0777))
echo Failed creating directory: $dirbr;
else
echo Created directory: $dirbr;
}
}
}
}
?
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