I am working on a Call Log application for our SA group. I
currently have the database back-end configured and working OK. Right now I
am working with 3 pages, one is to post new entries, the second is a log
view of all entries, and the last is a page that updates an existing entry.
I
I am working on a Call Log application, and need to calculate time.
For example, if a page is received at 12:00, the page is returned at 12:10,
and the call is resolved at 14:30... I need to be able to calculate the
time to return the page, and also the time to resolve the call. I am
I am working on an application that has several different fields
that are populated dropdown lists. In every case, this data is simply data
from a MySQL table column and works great. I have run into a new difficulty
though... One field that I am wanting to populate in a dropdown list
Thanks to everyone who responded. I have found a function that
fills the role perfectly.
-Original Message-
From: Russ [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 26, 2002 7:47 PM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Populating a dropdown list
In need of some help. I have a PHP form page that is updating a
MySQL database that is not working. Here is the code for the three pages
that work together for this application. The oncall_new.php works fine to
insert new records into the database, and the oncall_log.php works fine to
Figured it out. Thanks to anyone who started looking at this. The
problem was not having my variables in the correct order in the $updateSQL.
Once I corrected this, the posting now works fine.
-Original Message-
From: NIPP, SCOTT V (SBCSI)
[mailto:[EMAIL PROTECTED]]
Sent
Hey guys... I know that this is not specifically on topic for this
group, but I promise this is an easy one.
I am developing a web app, and need to create a development copy of
the production database. I have created the new database, now I just need
to export and import the
, SCOTT V (SBCSI)
[mailto:[EMAIL PROTECTED]]
Sent: Friday, July 05, 2002 12:26 PM
To: '[EMAIL PROTECTED]'
Subject: [PHP-DB] MySQL test database creation...
Hey guys... I know that this is not specifically on topic for this
group, but I promise this is an easy one.
I am developing
This time I have a real question that I need help with. I am not
sure why something is not working the way I intend it. This is most likely
a mistake in my understanding, but here goes...
I have a section of code that populates a dropdown list with the
results of a query on a
Since you are using phpMyAdmin, I would suggest taking a look at the
user table in the mysql database. I would suspect that you do not have the
proper permissions in the user table. If this 'admin' user should have full
rights to the database, you will need to make sure that you have
Perfect. Why was I trying to make this more difficult??? Sometimes
the simple solution is definitely the best.
-Original Message-
From: Shrock, Court [mailto:[EMAIL PROTECTED]]
Sent: Friday, July 05, 2002 1:50 PM
To: NIPP, SCOTT V (SBCSI); '[EMAIL PROTECTED]'
Subject: RE: [PHP
I seem to have run into another problem with a query that I am doing
exactly like the example in the MySQL documentation, I think. The following
query is not working on my PHP page, and it is not working from a MySQL
command line either. This looks exactly the same as an example in the
This is actually more of a MySQL question, but here goes...
I have two servers, one production and one development. I would
like to use the development server as a backup for the production server.
Is there a way to synchronize the MySQL databases between these two servers?
I
I just upgraded to Apache 1.3.26, and everything it fine except PHP.
Whenever I try to load a PHP page in the browser, the browser attempts to
download the page. I know that I am missing something simple here.
Scott Nipp
Phone: (214) 858-1289
E-mail: [EMAIL PROTECTED]
Web:
that
is working fine. I know that it shows .htm, but it works fine on my other
server this way. Thanks again.
-Original Message-
From: Beau Lebens [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, July 16, 2002 8:04 PM
To: NIPP, SCOTT V (SBCSI)
Subject: RE: [PHP-DB] Keeps prompting to download php page
Hey guys. Thanks in advance for all the help that this group has
provided to me so far. I am still learning, so many of my questions have
been pretty simple. This may also be pretty simple, but I cannot for the
life of me figure out how to make this happen.
I have a Log
I am populating a dropdown list from a database. This is working
fine with one minor glitch... For some reason, the first entry in the
database does not seem to be getting populated into the list. I do not see
anything wrong, and was hoping that someone else might be able to spot a
Thanks for the answers. This has resolved my problem.
-Original Message-
From: Andrey Hristov [mailto:[EMAIL PROTECTED]]
Sent: Monday, July 29, 2002 11:21 AM
To: NIPP, SCOTT V (SBCSI)
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Dropdown list question...
- Original
I am upgrading from PHP 4.1.2 to 4.2.2, and I cannot get the make
install to work. I am doing this on HP-UX 11.00, and I have tried the
suggestion of renaming the libphp4.sl files to libphp4.so, but I still get
failures. Below is the output of the make install before changing the
I have a Log Application that is fully functional, but I need to
change a behavior and can't quite figure out how. This app has three pages,
one for entering new entries, one to display all entries for the last 5
days, and the final page allows updating of existing entries. The problem
Give phpMyAdmin a try...
http://www.phpmyadmin.net/
-Original Message-
From: Brett Lathrope [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, October 02, 2002 8:55 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Noob questions...
Ok, here's my scenario...
My Web Host has all Root Admin
I am having trouble with a canned calendar application and I think
that maybe the problem is the crypt function. Does anyone know of a good
way to test the crypt function? I need to figure out somehow if this is the
source of the problem or not. Thanks.
Scott Nipp
Phone: (214)
I am trying to tweak an application that I have developed. The
application is our On-Call Log. This application consists of three pages;
one page to input new entries, one page to edit existing entries, and
finally a log view page. The log view page displays all entries for the
past 5
[mailto:phplist;gremlins.com.hk]
Sent: Friday, October 18, 2002 11:58 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Log Application Formatting Issue...
On Saturday 19 October 2002 00:09, NIPP, SCOTT V (SBCSI) wrote:
I am trying to tweak an application that I have developed. The
application is our On-Call
I am a little confused by a specific behavior of a session variable.
Here is an example of my confusion:
?php require_once('prod.lib.php');
session_start();
if (!isset($_SESSION['valid_user']))
{
echo You must be logged in to use this application. br;
echo Please a href=\login.php\
I am attempting to create a form of system names that is populated
from a database query. The database query is working fine, and the form
population is actually working fine also. The question I have is about
organizing the variables that result from the form. I want to use the
system
I know that this is not the forum for this question, I am only
looking for a pointer in the right direction here. I need to gain a better
understanding of HTML forms, specifically checkboxes. What I am looking for
is once I present a list of checkboxes and the user makes his selections,
is dependant on which method your form uses.
:-) If it is not checked then there is no entry. in PHP with
register_globals on the variable $checkbox1 will equal scoobydoo and not
be set if the box is not checked.
hope this helps...
Ryan
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto
: Tuesday, November 19, 2002 6:13 PM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: RE: [PHP-DB] HTML Forms question...
If you name the checkbox as name=system[] then PHP will automatically
create an array of the checkbox values which can be subsequently accessed
via $_POST['system'][n
-
From: 1LT John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, November 19, 2002 11:11 AM
To: NIPP, SCOTT V (SBCSI); 'Ryan Jameson (USA)'; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] HTML Forms question...
OK. If I am using the POST method and the checkbox 'name' for all
of the checkboxes
DUH!!! I'm an idiot. That was quite obvious. Thanks. Sorry for
the stupid question.
-Original Message-
From: Hutchins, Richard [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, November 19, 2002 2:40 PM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: RE: [PHP-DB] HTML Forms
I have an INSERT statement that I cannot quiet get working. The
table that this data is being put into has 7 columns, but I only care about
putting in the data from the first two columns at this time. The first
column is an array element, and the second column needs to be a timestamp.
. Holmes'; NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: RE: [PHP-DB] INSERT question...
Hmm
You learn something new everyday :)
Aaron
-Original Message-
From: 1LT John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: November 20, 2002 2:27 PM
To: Aaron Wolski; 'NIPP, SCOTT V (SBCSI
PROTECTED]]
Sent: Wednesday, November 20, 2002 2:21 PM
To: NIPP, SCOTT V (SBCSI); 'Aaron Wolski'; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] INSERT question...
OK. This sounds great, but now I am getting a completely different
error message.
You have an error in your SQL syntax near '-sys) VALUES
, November 20, 2002 2:47 PM
To: NIPP, SCOTT V (SBCSI); 'Aaron Wolski'; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] INSERT question...
$query = INSERT INTO accounts (`id-sys`, rtime) VALUES('.$accnts[0].',
'NOW()');
Remove the quotes around NOW(). It's a function, not a string.
---John Holmes
Once again I am posting a bit off topic, so tell me to go away if
this is bugging people...
Thanks for all of the assistance so far in creating what will be a
completely automated user account request system. I am now trying to figure
out the mechanics of the account approval
I am trying to implement an approval system that sends an e-mail to
a user for approval linking them back to a special URL that matches database
entries for a verification string. The verification string sent via the
e-mail does not match that in the database and I am looking for help in
-
From: Peter Lovatt [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, December 04, 2002 4:45 PM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Special URL Verification String... PS
Hi
PS
I would use
$verify_string = md5(uniqid(rand()));
to generate a random identifier
I must be stupid, because I cannot for the life of me figure out why
I am not getting newlines from some very simply 'echo' statements. Here is
the portion of the code below, and I am getting everything run together on a
single line:
?php do {
echo $list['id-sys'] . \n;
$sys =
]]
Sent: Thursday, December 05, 2002 10:34 AM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Newline help...
HTML doesn't render newlines, only BR. Look at your HTML source code and
the newlines are there.
or,
if you're on windows, use \r\n for newlines.
---John Holmes
I am trying to convert something that I have working in a PHP script
to be a function in a library type of file. The code contained in the
function works fine in another script, but I am currently getting no output
from the function. I have a question about the nature of functions that
, December 06, 2002 1:58 PM
To: '[EMAIL PROTECTED]'
Subject: Re: [PHP-DB] Function questions...
$sys is an array, so echoing $sys will cause problems.
Are you trying to get a 4xN table of values and checkboxes? There's
got to be an easier way...
--- NIPP, SCOTT V (SBCSI) [EMAIL PROTECTED] wrote
, December 06, 2002 1:58 PM
To: '[EMAIL PROTECTED]'
Subject: Re: [PHP-DB] Function questions...
$sys is an array, so echoing $sys will cause problems.
Are you trying to get a 4xN table of values and checkboxes? There's
got to be an easier way...
--- NIPP, SCOTT V (SBCSI) [EMAIL PROTECTED] wrote
07 December 2002 04:12, NIPP, SCOTT V (SBCSI) wrote:
OK. Stumped once again. This function is now properly generating
and displaying the form as I intend it to. The only problem is that the
optional text and button at the end of the function is actually displaying
above the choices provided
Yes, and yes.
-Original Message-
From: John [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 06, 2002 2:41 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Data not entering DB
Questions:
Is this the right email addy to post help questions, and may I post the php
code within the
I am working on an application and I am not having a lot of luck
getting a form to behave the way I want. I am trying to keep the form self
referencing, not sure if that is the correct terminology. The form is an
approval form that queries a database to create a list of checkboxes.
I am attempting to UPDATE a table and I have having absolutely ZERO
success. Here is the query:
$tmp = $_POST['sbcuid'].-.$_POST['system'][$a];
$update = UPDATE accounts SET atime='NOW()' WHERE
\id-sys\='.$tmp.';
echo $update;
$result1 =
changed and take this as a lesson never to use '-' in a column name again.
Thanks again for the help. Maybe we all learned something from
this.
-Original Message-
From: DL Neil [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, December 10, 2002 2:00 PM
To: NIPP, SCOTT V (SBCSI); '1LT John W
I have now been granted access to a remote Oracle database that I
need to query. All of the work that I have done with databases and PHP has
been focused on MySQL, does anyone know of a good tutorial for PHP with
Oracle? My immediate question is how do I get logged into the remote
used
Oracle since 8i came out... but I'm pretty sure this is accurate. Except the
guess about how PHP does it.
Ryan
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, December 11, 2002 9:24 AM
To: '[EMAIL PROTECTED]'
Subject: [PHP-DB] Remote Oracle
I am now trying to setup connectivity to a remote Oracle database
for my PHP/Apache web server. I am attempting to verify connectivity to the
database by:
?php
$connection = OCILogon(user, password) or die (Unable to logon to
database.);
?
I have installed the Oracle client on
webserver is win32 then you need to uncomment the line in php.ini
that says :
;extension=php_oci8.dll
if it is unix based I am not sure what you need to do.
Ryan
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]]
Sent: Monday, December 16, 2002 1:58 PM
jobs... PHP is much
more powerful then anything m$ offers.
Ryan
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]]
Sent: Monday, December 16, 2002 2:08 PM
To: Ryan Jameson (USA); [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Oracle/PHP question...
Thanks, but my
Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]]
Sent: Monday, December 16, 2002 1:58 PM
To: '[EMAIL PROTECTED]'
Subject: [PHP-DB] Oracle/PHP question...
I am now trying to setup connectivity to a remote Oracle database
for my PHP/Apache web server. I am
I am attempting to recompile PHP 4.2.3 on HP-UX 11.00 for
connectivity to both a MySQL and a remote Oracle server. I am not having
much luck with this right now. Currently I am getting a couple of different
errors that are of concern for me. First of all, in the Apache error log I
am
Message-
From: NIPP, SCOTT V (SBCSI)
Sent: Tuesday, December 17, 2002 9:56 AM
To: '[EMAIL PROTECTED]'
Subject: PHP/Oracle Install questions...
I am attempting to recompile PHP 4.2.3 on HP-UX 11.00 for
connectivity to both a MySQL and a remote Oracle server. I am
OK. I think I now have Oracle support built into PHP/Apache. The
biggest hiccup for HP-UX seems to be that once you add Oracle support to
PHP, you CANNOT built PHP as a DSO, PHP MUST be compiled into Apache. Once
again, I think this is the case, I am still not completely sure at this
I would say his problem is the IIS 5.0. Switch to some non-MS
operating system running Apache as a web server and that should clear up
your problems. :)
-Original Message-
From: Jason Wong [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 20, 2002 11:24 AM
To: [EMAIL PROTECTED]
My head is sore from banging my head on my desk, so I will now ask
the gurus...
I am trying to get a canned Calendar application working, and I am
running into problems. The application is phpCommunityCalendar by
AppIdeas.com. The calendar is currently semi-functional, but for
OK, this isn't really a DB question, but it is definitely a PHP
question. I am working on customizing a calendar application for my group's
use and noticed that there is a function that has to do with a mouseover
effect. The problem is that this mouseover does not appear to do anything.
.
-Original Message-
From: John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 08, 2003 11:56 AM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Mouseover question...
OK, this isn't really a DB question, but it is definitely a PHP
question. I am
I am getting an error that is proving very difficult to isolate and
was hoping for help. The error is: Column count doesn't match value count
at row 1. I would include the code, but it is about 350 lines, and I am not
sure where to narrow it down at. Any ideas? Thanks.
Scott Nipp
, SCOTT V (SBCSI); '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Stumped...
Post your SQL statement.
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]]
Sent: Thursday, January 09, 2003 1:37 PM
To: '[EMAIL PROTECTED]'
Subject: [PHP-DB] Stumped...
I am
I have a question about using DATE_ADD in MySQL. I am not sure if
this is the most effective way of dealing with this problem so I am asking
here. The situation is that I am working on modifying a calendar system for
our use. Our On-Call rotation is such that when someone is On-Call
Thanks. I was noticing that it was not working. Let me give this a
try and see how things go.
-Original Message-
From: 1LT John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 15, 2003 10:32 AM
To: 1LT John W. Holmes; NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED
W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 15, 2003 10:32 AM
To: 1LT John W. Holmes; NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Date math functions...
[snip]
if ($dateDiff == 3) {
mysql($DBName,UPDATE Balances SET CompEarned=CompTaken+8 WHERE
said
OK, I cannot figure out why I keep getting errors about Duplicate
entry for key 1. Someone please come to my rescue here as this is truly
kicking my but.
if ($dateDiff == 2) {
mysql($DBName,INSERT INTO phpCalendar_Details VALUES (
'$said','Comp day for weekend
Under Unix I don't know that this is possible, but hopefully someone
else will know of a way. I would love to be able to e-mail some Excel files
that I generate with a Perl cron job, but there does not appear to be any
practical way to do this in Unix.
-Original Message-
From:
poorly
coded piece of software, and if I as a relative PHP newbie know this, it is
really bad.
-Original Message-
From: John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 15, 2003 10:07 PM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Duplicate keys
the difference of 2 or 3 days?
-Original Message-
From: 1LT John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 04, 2003 10:04 AM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Date Range Question...
I am working on an app that needs to post information to a website
I have a JOIN that is not working, and figured I would piggie-back on this
thread to see if someone could give me a quick answer... Here is the JOIN
syntax. This is my very first attempt at a JOIN statement, so I may be
doing something blatantly wrong here.
SELECT 'A.Title'
FROM
This is more of an SQL question, but I am not sure where else to
turn for help. I am trying a JOIN, for the first time ever, and it is NOT
working for me. The following is what I am attempting;
SELECT 'A.Title'
FROM `phpCalendar_Daily` AS 'B'
JOIN 'phpCalendar_Details' AS 'A' ON
AND A.StopDate
-Original Message-
From: 1LT John W. Holmes [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 04, 2003 1:36 PM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Subject: Re: [PHP-DB] A little JOIN help please...
SELECT 'A.Title'
FROM `phpCalendar_Daily` AS 'B'
JOIN
I developed some dynamic content for a larger web page, and once I
pasted the code into the appropriate area of the page I am seeing the
strangest error. Here is the error:
Warning: Failed opening '/www/DW/index1.htm' for inclusion
(include_path='.:/usr/local/lib/php') in Unknown on line
requests call the
Help
Desk/span/h4
...snip
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 06, 2003 11:09 AM
To: NIPP, SCOTT V (SBCSI)
Subject: RE: [PHP-DB] Weird PHP behavior...
well show the working code and then show just a portion
It turned out to be just a simple file permissions issue.
-Original Message-
From: Mohammad Saad [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 06, 2003 12:31 PM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED];
[EMAIL PROTECTED]
Subject: Re: [PHP-DB] Weird PHP behavior
I would most definitely recommend pulling them from a DB table
rather than hard coding these into a page. Here is a code snippet that I
use to do this on one of my pages:
mysql_select_db($Prod, $Prod);
$query_systems = SELECT Name FROM systems ORDER BY Name ASC;
$systems =
I am having a lot of trouble with a query that works fine from a
basic SQL command line, but fails in my web script. Here is the portion of
code including the query:
mysql_select_db($database, $Prod);
$query_groups = SELECT name FROM group;
$groups = mysql_query($query_groups, $Prod) or
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Query Help...
- Original Message -
From: NIPP, SCOTT V (SBCSI) [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 10, 2003 9:23 AM
Subject: [PHP-DB] Query Help...
I am having a lot of trouble with a query that works fine from a
basic SQL
OK... I have once again thought of something cool to do, and can't
quite figure out how to make it happen. I am developing a user account
request system for work. Things are coming along nicely. The user logs
into the system, kind of, selects the systems that he wants to have accounts
I don't really understand this suggestion. Could someone possibly
expound on this further? Maybe an example? Thanks.
-Original Message-
From: Ben Walling [mailto:[EMAIL PROTECTED]
Sent: Tuesday, March 11, 2003 12:19 PM
To: NIPP, SCOTT V (SBCSI)
Subject: Re: Stumped again
populated into the array in the first place.
-Original Message-
From: Ben Walling [mailto:[EMAIL PROTECTED]
Sent: Tuesday, March 11, 2003 1:48 PM
To: NIPP, SCOTT V (SBCSI)
Cc: [EMAIL PROTECTED]
Subject: RE: Stumped again...
Your code:
while($name = mysql_fetch_row($groups_tmp
I create an array on one page and then process it on the next page
as I have registered the array as a session variable. I need to basically
process one of these arrays twice, so I want to make a copy of the array.
The question is how do I do this? I have tried the following:
$array2 =
]
Sent: Wednesday, March 12, 2003 10:40 AM
To: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Easy array question...
Are you using:
$array2 = $_SESSION[array1];
Not sure that will do the trick, but it was my first inclination.
Rich
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto
.
-Original Message-
From: Jonathan Villa [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 10:58 AM
To: [EMAIL PROTECTED]; NIPP, SCOTT V (SBCSI); 'Hutchins, Richard';
[EMAIL PROTECTED]
Subject: RE: [PHP-DB] Easy array question...
Sorry, I just reread your post
$array_copy = array
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 11:10 AM
To: '[EMAIL PROTECTED]'; 'Hutchins, Richard'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Easy array question...
Here is basically what I have and what I am getting
I am curious about what you guys may have along the lines of best
practices for forwarding from a URL to a login, and then jumping back to the
original URL automatically. I have several separate applications that all
need to utilize the same login mechanism. I want the user to be able to
In response to your bullet points...
1. Built in mysql_ functions in php (does perl have this?)
Perl does not have built in functions for MySQL or any
other database. The Perl functions are all added through modules. This is
somewhat annoying as compared to PHP
I am working on a page that displays a line of information with a
checkbox at the end. I began by getting all of the information I wanted
displayed working properly and now I am adding the checkbox. Everything is
going find with the exception that all of a sudden with the checkbox code
Anyone have an links to websites that offer good tutorials on web
design? I am most interested in learning about templates and how to design
these for use with PHP pages. I am using DreamWeaver MX as a development
environment and would really like some help with DreamWeaver templates if
OK... I moved the form tag up before the table tag and added a tr
tag to the beginning of the first line of display in the loop. No
difference in the output. The first line of the output loop is still a
completely empty line.
-Original Message-
From: [EMAIL PROTECTED]
from
the original query than perform another database query to populate this
value yet again. Thanks yet again for the help.
-Original Message-
From: CPT John W. Holmes [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 2:14 PM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Cc: [EMAIL
, 2003 9:06 AM
To: NIPP, SCOTT V (SBCSI); [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Datetime help in an INSERT...
I have actually discovered that the $td value is blank. The reason
appears to be that the page is reloading when a button is pushed, and that
is when the $td
: Thursday, June 05, 2003 9:01 AM
To: NIPP, SCOTT V (SBCSI)
Subject: RE: [PHP-DB] Datetime help in an INSERT...
You could alway place it as a GET
echo a href=\yourscript.com/yourpage.php?td=$td\;
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto
]
Sent: Thursday, June 05, 2003 9:48 AM
To: NIPP, SCOTT V (SBCSI)
Subject: RE: [PHP-DB] Datetime help in an INSERT...
a button is being pressed?
so it is processing a form?
if its in a form just pass along the value of $td via hidden input data...
input type=hidden name=td value=? echo $td; ?
jay
. I am guessing that you guys will need more info to help out
with this now. Just let me know what you want. Thanks again.
-Original Message-
From: CPT John W. Holmes [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 05, 2003 10:07 AM
To: NIPP, SCOTT V (SBCSI)
Subject: Re: [PHP-DB] Datetime
I know there is another mailing list for installation questions, but
I am hoping for some help here. I get enough mail from this list alone
without having to join another. Anyway, while attempting to compile version
4.3.2 I am running into the following error during the configure...
I am stumbling across something that I thought I have done before,
and I am not having any luck finding an example of this. Basically, I am
wanting to timestamp the date and time into new entries in a simple database
table. The following section is the actual code for this, and I cannot
The error I am receiving is:
You have an error in your SQL syntax near ' NOW())' at line 1
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:45 PM
To: NIPP, SCOTT V (SBCSI)
Subject: Re: [PHP-DB] Datetime help in an INSERT
. It will update automatically when
the record is inserted and/or updated.
ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td );
Randy
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:47 PM
To: '[EMAIL PROTECTED]'
Cc: '[EMAIL
1 - 100 of 129 matches
Mail list logo
