Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Sun, 30 Nov 2014 02:48:09 -0500: Hi Dave, Robin, don't beat yourself up too badly about having a short term mental block since it happens to all of us. :) [snip] We started this discussion considering the operation of UFO type devices as an example. I have a difficult time accepting the fact that they might actually be controlled by something not human. That concept seems to be too fantastic to believe but I hope to realize the truth one day. ? The observation that these crafts appear to hover in the air silently and without emitting any form of exhaust leads some to consider reactionless drives as the source of the force that keeps them airborne. I do not feel that this is necessary since the earth could easily form the other side of the thrust equation. If the ship has some means of pushing against the earth, then it would be able to balance out the momentum and energy equations that have precipitated the recent discussion. I agree, it's not necessary, but may still be the case. One of the patents recently mentioned here was talking about the Meissner effect. That would probably work if you could create a sufficiently large superconducting bubble, though I still haven't figured out how to calculate the lifting capacity per unit volume (which I presume would also very depending on the local field strength of the Earth's magnetic field), or even if this is the right question. :( We know for instance that a loop of wire carrying a large AC current can be repelled by any nearby metal surface. The amount of radiation exiting that wire can be quite small if the drive is at a low AC frequency. The near field effects induce a current within the metal surface that generates a force that holds up the loop. A power source on board the loop driven ship could be used to supply the current that allows the device to float above the metal surface. AFAIK this works by inducing eddy current in the metal plate which automatically oppose the inducing field. However the Earth wouldn't appear to be a very good metal plate? Now, back to the UFO and Earth situation. An observer on the Earth might not see the complete picture and could well assume that the ship emits no exhaust or mass of any kind. Of course we know that the Earth is being repelled away from the ship and supplies that mass. Momentum is conserved and all of the energy can likely be accounted for. I say likely since I have not taken the time required to prove it although I would be surprised to find out otherwise. Indeed. I of course have serious doubts that a simple magnetic drive would actually generate the force required to keep one of those crafts afloat, but the concept of using the Earth as the other side of the thrust equation might work with another force. A method of manipulating gravity appears like the ideal solution. Dave ...and would also work for the Sun, if it works for the Earth, or even the galaxy as a whole, or in part (IOW there is some form of gravitational field everywhere). However I suspect that even such a drive would not be used for long distance interstellar travel, because the relativistic aging would cause a real problem. Can you imagine returning home only to discover that your entire mission has been lost in the sands of time? That why I think that travel over any truly large distances would need to use wormholes. (Of course a light speed trip to Alpha Centauri would be interesting) ;) I also think that shielding would be a problem at speeds approaching that of light. A small rock in interstellar space could destroy the entire craft at that speed. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Fri, 28 Nov 2014 23:24:51 -0500: Hi Dave, [snip] OK, I have read several of those physics books and my position is sound. The formula for kinetic energy as seen by an observer is E=1/2*M*V*V. That V is not a difference, but the final relative velocity. If you want to find out how much the kinetic energy changes you must calculate the value of kinetic energy both before and then after the drive is applied. At that point you can find the delta in energy and you obtain the correct value according to physics. How about looking at the problem from a different perspective. Let the velocity change in two steps of 1 meter per second each. According to your procedure the kinetic energy is 2 times the amount gained in a single step since the same delta in velocity is determined for each one. You are correct. My mistake was in thinking that the change in kinetic energy had to be the same for all observers. This is not so. I do spout nonsense sometimes. Thanks for keeping me on the straight and narrow. :) In the other case the kinetic energy is the same both before and after the drive is enabled. The value is 1/2*1*1*M before the drive is enabled and 1/2*-1*-1*M after it completes its task. This is because the magnitude of the relative velocity is the same both before and then after the drive finishes. The sign changes, but that does not enter into the equation for kinetic energy since energy is a scalar. ... but if momentum can be exchanged, then changing direction need not cost any energy. (e.g. a marble bouncing on a hard surface approaches this condition.) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Robin, don't beat yourself up too badly about having a short term mental block since it happens to all of us. Energy can be conserved in an elastic collision such as you mentioned. Of course the momentum is modified in that case because the velocity changes direction. We started this discussion considering the operation of UFO type devices as an example. I have a difficult time accepting the fact that they might actually be controlled by something not human. That concept seems to be too fantastic to believe but I hope to realize the truth one day. The observation that these crafts appear to hover in the air silently and without emitting any form of exhaust leads some to consider reactionless drives as the source of the force that keeps them airborne. I do not feel that this is necessary since the earth could easily form the other side of the thrust equation. If the ship has some means of pushing against the earth, then it would be able to balance out the momentum and energy equations that have precipitated the recent discussion. We know for instance that a loop of wire carrying a large AC current can be repelled by any nearby metal surface. The amount of radiation exiting that wire can be quite small if the drive is at a low AC frequency. The near field effects induce a current within the metal surface that generates a force that holds up the loop. A power source on board the loop driven ship could be used to supply the current that allows the device to float above the metal surface. Now, back to the UFO and Earth situation. An observer on the Earth might not see the complete picture and could well assume that the ship emits no exhaust or mass of any kind. Of course we know that the Earth is being repelled away from the ship and supplies that mass. Momentum is conserved and all of the energy can likely be accounted for. I say likely since I have not taken the time required to prove it although I would be surprised to find out otherwise. I of course have serious doubts that a simple magnetic drive would actually generate the force required to keep one of those crafts afloat, but the concept of using the Earth as the other side of the thrust equation might work with another force. A method of manipulating gravity appears like the ideal solution. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sat, Nov 29, 2014 7:10 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 28 Nov 2014 23:24:51 -0500: Hi Dave, [snip] OK, I have read several of those physics books and my position is sound. The formula for kinetic energy as seen by an observer is E=1/2*M*V*V. That V is not a difference, but the final relative velocity. If you want to find out how much the kinetic energy changes you must calculate the value of kinetic energy both before and then after the drive is applied. At that point you can find the delta in energy and you obtain the correct value according to physics. How about looking at the problem from a different perspective. Let the velocity change in two steps of 1 meter per second each. According to your procedure the kinetic energy is 2 times the amount gained in a single step since the same delta in velocity is determined for each one. You are correct. My mistake was in thinking that the change in kinetic energy had to be the same for all observers. This is not so. I do spout nonsense sometimes. Thanks for keeping me on the straight and narrow. :) In the other case the kinetic energy is the same both before and after the drive is enabled. The value is 1/2*1*1*M before the drive is enabled and 1/2*-1*-1*M after it completes its task. This is because the magnitude of the relative velocity is the same both before and then after the drive finishes. The sign changes, but that does not enter into the equation for kinetic energy since energy is a scalar. ... but if momentum can be exchanged, then changing direction need not cost any energy. (e.g. a marble bouncing on a hard surface approaches this condition.) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Thu, 27 Nov 2014 23:47:17 -0500: Hi Dave, [snip] The v in the formula Ek = 1/2 mv^2 actually applies to the change in velocity, not velocity in any absolute sense. For the sake of convenience, we normally choose a frame of reference in which the initial velocity is zero which makes the calculation simpler. For observer 1, the change is 1/2 * m * (2-0)^2 = 1/2 * m * (2)^2. For observer 2, the change is 1/2 * m * (1 - -1)^2 = 1/2 * m * (2)^2. I.e. they both see the same change in kinetic energy. Note 1: I have not included the dimensions here to keep the formula as simple as possible in ASCII text. Note 2: Depending on the initial direction of motion, you may choose to write the equation for observer 2 as 1/2 * m * (-1 - 1)^2 = 1/2 * m * (-2)^2, however this still gives the same result for the kinetic energy change. Robin, I just came up with a thought experiment that lends support to the idea that a reactionless drive is not likely to exist. Take 2 different observers, one that is moving beside the ship at the same velocity as it has prior to activating the drive. The second one is moving at a velocity that allows him to observe the ship decelerate first until it reaches a velocity of zero relative to him and then to accelerate in the reverse direction until it reaches the exact same original velocity in the opposite direction. The first observer sees the velocity of the ship go from for this example 0 meters per second to 2 meters per second. He determines that the ship now has 2*2*Mass/2 units of kinetic energy. The amount of internal mass that the ship burns up to achieve this acceleration is extremely small and can almost be neglected. The second observer sees the ship moving at the same speed before and then after the application of the drive. The only difference he measures is that the direction of the motion of the ship is reversed by the drive. So he sees the ship begin the motion moving 1 meter per second relative to him initially and then after the drive shuts down the ship is moving 1 meter per second in the opposite direction. This observer determines that the kinetic energy of the ship has not changed measurably due to the application of the drive. At this low velocity the second observer determines that the mass converted into drive power is essentially the same as that determined by the first observer. Both guys have a very hard time figuring out exactly how much mass is converted, and they agree that any difference is hidden in the noise. In this experiment we have two independent observers seeing the same ship being subject to the same drive. The amount of kinetic energy being deposited to the ship by essentially the same loss of internal mass varies remarkably according to each. This does not add up. As I have mentioned before, with a normal drive this case can be handled without a problem. The exhaust material supplies the kinetic energy and momentum needed to balance the equation. Apparently every observer moving at a different initial velocity relative to the driven ship arrives at a significantly different calculation regarding the ships energy balance after the application of the drive. How could something this radical be possible? Let me say it again, there is no problem of this sort to deal with when a standard drive is applied. Dave Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Thu, 27 Nov 2014 22:48:46 -0500: Hi Dave, [snip] Robin, you were fortunate enough to see something strange that day. My wife and I witnessed some type of UFO a few years ago as well. I was driving and she was in the passengers seat. All I saw was a red ball moving through the trees that appeared much like the way a laser does when shined onto a black screen. She saw something far more impressive but refused to tell me about it until we traveled far enough away to be unable to return for a better look. She was afraid that I would want to go back, and she was right. What she described is nothing short of amazing. She said it moved extremely quickly form above us to within perhaps 30 yards. She also told me it emitted a bright beam of white light. I saw none of that. Of course we did not mention the sighting at that time. Dave The fact that you saw no white beam of light makes this sound like you might actually have had an abduction experience with lost memory. BTW in my posting of my UFO experience, I said that the angle between the wall and the top was about 20º. I meant the angle from the horizontal. The angle between the wall and the top was probably about 100º (or 80º, depending on how you measure the angle). Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
That is not correct Robin. Kinetic energy is calculated directly by the magnitude of relative velocity of the ship to the observer and therefore the second guy sees essentially no net change in kinetic energy once the drive cycle is completed. Also notice that the energy is nonlinear with velocity. The fact that it is proportional to the second power of the velocity allows the direction to become unimportant. I am beginning to suspect that you are playing games at this point. All you need to do is to look up the definition of kinetic energy to see that what I am stating is correct. I have no idea why you think kinetic energy has anything to do with the change in velocity instead of the net relative velocity. Perhaps you can quote a source. ;) Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Fri, Nov 28, 2014 4:02 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Thu, 27 Nov 2014 23:47:17 -0500: Hi Dave, [snip] The v in the formula Ek = 1/2 mv^2 actually applies to the change in velocity, not velocity in any absolute sense. For the sake of convenience, we normally choose a frame of reference in which the initial velocity is zero which makes the calculation simpler. For observer 1, the change is 1/2 * m * (2-0)^2 = 1/2 * m * (2)^2. For observer 2, the change is 1/2 * m * (1 - -1)^2 = 1/2 * m * (2)^2. I.e. they both see the same change in kinetic energy. Note 1: I have not included the dimensions here to keep the formula as simple as possible in ASCII text. Note 2: Depending on the initial direction of motion, you may choose to write the equation for observer 2 as 1/2 * m * (-1 - 1)^2 = 1/2 * m * (-2)^2, however this still gives the same result for the kinetic energy change. Robin, I just came up with a thought experiment that lends support to the idea that a reactionless drive is not likely to exist. Take 2 different observers, one that is moving beside the ship at the same velocity as it has prior to activating the drive. The second one is moving at a velocity that allows him to observe the ship decelerate first until it reaches a velocity of zero relative to him and then to accelerate in the reverse direction until it reaches the exact same original velocity in the opposite direction. The first observer sees the velocity of the ship go from for this example 0 meters per second to 2 meters per second. He determines that the ship now has 2*2*Mass/2 units of kinetic energy. The amount of internal mass that the ship burns up to achieve this acceleration is extremely small and can almost be neglected. The second observer sees the ship moving at the same speed before and then after the application of the drive. The only difference he measures is that the direction of the motion of the ship is reversed by the drive. So he sees the ship begin the motion moving 1 meter per second relative to him initially and then after the drive shuts down the ship is moving 1 meter per second in the opposite direction. This observer determines that the kinetic energy of the ship has not changed measurably due to the application of the drive. At this low velocity the second observer determines that the mass converted into drive power is essentially the same as that determined by the first observer. Both guys have a very hard time figuring out exactly how much mass is converted, and they agree that any difference is hidden in the noise. In this experiment we have two independent observers seeing the same ship being subject to the same drive. The amount of kinetic energy being deposited to the ship by essentially the same loss of internal mass varies remarkably according to each. This does not add up. As I have mentioned before, with a normal drive this case can be handled without a problem. The exhaust material supplies the kinetic energy and momentum needed to balance the equation. Apparently every observer moving at a different initial velocity relative to the driven ship arrives at a significantly different calculation regarding the ships energy balance after the application of the drive. How could something this radical be possible? Let me say it again, there is no problem of this sort to deal with when a standard drive is applied. Dave Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Fri, 28 Nov 2014 16:23:23 -0500: Hi Dave, [snip] Kinetic energy is calculated directly by the magnitude of relative velocity of the ship to the observer and therefore the second guy sees essentially no net change in kinetic energy once the drive cycle is completed. Also notice that the energy is nonlinear with velocity. The fact that it is proportional to the second power of the velocity allows the direction to become unimportant. I am beginning to suspect that you are playing games at this point. All you need to do is to look up the definition of kinetic energy to see that what I am stating is correct. I have no idea why you think kinetic energy has anything to do with the change in velocity instead of the net relative velocity. Velocity is a vector quantity, which means that it has both direction and magnitude. Before you square the quantity, you need to do vector addition (or subtraction in this case). The fact that the direction has changed, makes a difference in the change in kinetic energy. If you prefer, consider the fact that in order to change direction, the craft has to first decelerate until its speed is zero, then accelerate again in the opposite direction. Both observers see the same acceleration of the craft, but for one of them this results in a velocity of 2 m/s in one direction, while for other it appears as a change in velocity from +1 m/s to -1 m/s (or if you prefer from -1 m/s to +1 m/s). Perhaps you can quote a source. ;) Any physics book. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Fri, Nov 28, 2014 4:02 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Thu, 27 Nov 2014 23:47:17 -0500: Hi Dave, [snip] The v in the formula Ek = 1/2 mv^2 actually applies to the change in velocity, not velocity in any absolute sense. For the sake of convenience, we normally choose a frame of reference in which the initial velocity is zero which makes the calculation simpler. For observer 1, the change is 1/2 * m * (2-0)^2 = 1/2 * m * (2)^2. For observer 2, the change is 1/2 * m * (1 - -1)^2 = 1/2 * m * (2)^2. I.e. they both see the same change in kinetic energy. Note 1: I have not included the dimensions here to keep the formula as simple as possible in ASCII text. Note 2: Depending on the initial direction of motion, you may choose to write the equation for observer 2 as 1/2 * m * (-1 - 1)^2 = 1/2 * m * (-2)^2, however this still gives the same result for the kinetic energy change. Robin, I just came up with a thought experiment that lends support to the idea that a reactionless drive is not likely to exist. Take 2 different observers, one that is moving beside the ship at the same velocity as it has prior to activating the drive. The second one is moving at a velocity that allows him to observe the ship decelerate first until it reaches a velocity of zero relative to him and then to accelerate in the reverse direction until it reaches the exact same original velocity in the opposite direction. The first observer sees the velocity of the ship go from for this example 0 meters per second to 2 meters per second. He determines that the ship now has 2*2*Mass/2 units of kinetic energy. The amount of internal mass that the ship burns up to achieve this acceleration is extremely small and can almost be neglected. The second observer sees the ship moving at the same speed before and then after the application of the drive. The only difference he measures is that the direction of the motion of the ship is reversed by the drive. So he sees the ship begin the motion moving 1 meter per second relative to him initially and then after the drive shuts down the ship is moving 1 meter per second in the opposite direction. This observer determines that the kinetic energy of the ship has not changed measurably due to the application of the drive. At this low velocity the second observer determines that the mass converted into drive power is essentially the same as that determined by the first observer. Both guys have a very hard time figuring out exactly how much mass is converted, and they agree that any difference is hidden in the noise. In this experiment we have two independent observers seeing the same ship being subject to the same drive. The amount of kinetic energy being deposited to the ship by essentially the same loss of internal mass varies remarkably according to each. This does not add up. As I have mentioned before, with a normal drive this case can be handled without a problem. The exhaust material supplies the kinetic energy and momentum needed to balance the equation. Apparently every observer moving at a different initial velocity relative to the driven ship arrives at a significantly different calculation regarding the ships energy balance after the application
Re: [Vo]:They call me a moron. A reply.
OK, I have read several of those physics books and my position is sound. The formula for kinetic energy as seen by an observer is E=1/2*M*V*V. That V is not a difference, but the final relative velocity. If you want to find out how much the kinetic energy changes you must calculate the value of kinetic energy both before and then after the drive is applied. At that point you can find the delta in energy and you obtain the correct value according to physics. How about looking at the problem from a different perspective. Let the velocity change in two steps of 1 meter per second each. According to your procedure the kinetic energy is 2 times the amount gained in a single step since the same delta in velocity is determined for each one. But the real change would be 2 times greater than the expected value according to your method. This is because the energy is proportional to the square of the velocity. So you would calculate 1/2*1*1*M for each delta of 1 meter per second for a total of M units of energy. The true value for the kinetic energy is 1/2*2*2*M units which is a net of 2*M total. In the other case the kinetic energy is the same both before and after the drive is enabled. The value is 1/2*1*1*M before the drive is enabled and 1/2*-1*-1*M after it completes its task. This is because the magnitude of the relative velocity is the same both before and then after the drive finishes. The sign changes, but that does not enter into the equation for kinetic energy since energy is a scalar. I know that there are many vorts out there that can help to explain this concept in a manner that is more convincing than I have. Now would be an excellent time for one or more of them to step in. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Fri, Nov 28, 2014 6:16 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 28 Nov 2014 16:23:23 -0500: Hi Dave, [snip] Kinetic energy is calculated directly by the magnitude of relative velocity of the ship to the observer and therefore the second guy sees essentially no net change in kinetic energy once the drive cycle is completed. Also notice that the energy is nonlinear with velocity. The fact that it is proportional to the second power of the velocity allows the direction to become unimportant. I am beginning to suspect that you are playing games at this point. All you need to do is to look up the definition of kinetic energy to see that what I am stating is correct. I have no idea why you think kinetic energy has anything to do with the change in velocity instead of the net relative velocity. Velocity is a vector quantity, which means that it has both direction and magnitude. Before you square the quantity, you need to do vector addition (or subtraction in this case). The fact that the direction has changed, makes a difference in the change in kinetic energy. If you prefer, consider the fact that in order to change direction, the craft has to first decelerate until its speed is zero, then accelerate again in the opposite direction. Both observers see the same acceleration of the craft, but for one of them this results in a velocity of 2 m/s in one direction, while for other it appears as a change in velocity from +1 m/s to -1 m/s (or if you prefer from -1 m/s to +1 m/s). Perhaps you can quote a source. ;) Any physics book. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Fri, Nov 28, 2014 4:02 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Thu, 27 Nov 2014 23:47:17 -0500: Hi Dave, [snip] The v in the formula Ek = 1/2 mv^2 actually applies to the change in velocity, not velocity in any absolute sense. For the sake of convenience, we normally choose a frame of reference in which the initial velocity is zero which makes the calculation simpler. For observer 1, the change is 1/2 * m * (2-0)^2 = 1/2 * m * (2)^2. For observer 2, the change is 1/2 * m * (1 - -1)^2 = 1/2 * m * (2)^2. I.e. they both see the same change in kinetic energy. Note 1: I have not included the dimensions here to keep the formula as simple as possible in ASCII text. Note 2: Depending on the initial direction of motion, you may choose to write the equation for observer 2 as 1/2 * m * (-1 - 1)^2 = 1/2 * m * (-2)^2, however this still gives the same result for the kinetic energy change. Robin, I just came up with a thought experiment that lends support to the idea that a reactionless drive is not likely to exist. Take 2 different observers, one that is moving beside the ship at the same velocity as it has prior to activating the drive. The second one is moving at a velocity that allows him to observe the ship decelerate first until it reaches a velocity of zero relative to him and then to accelerate in the reverse
Re: [Vo]:They call me a moron. A reply.
Professor Alfieo Di Bella at the University of Genoa, Italy. Invented a mobius reactionless drive US 3404854Device for Imparting Motion to a Body. USPTO indicated tests to overcome a US35-101 rejection..involved a lifting balloon experiment. Ad astra, Ron Kita, Chiralex On Thu, Nov 27, 2014 at 1:15 AM, David Roberson dlrober...@aol.com wrote: It would be refreshing to find that the energy is returned, but I harbor no expectation of that occurring. Consider that what we consider acceleration is exactly the same as deceleration as far as a ship is concerned. In either situation the ship is changing velocity as a function of time due to operation of the drive. I visualize the ship as being at rest just before each acceleration takes place. A force is applied by the reactionless drive at that time which leads to an acceleration along the line of the applied force. It does not make any difference what direction that force takes when you consider that the drive begins to burn up our mass at the time it causes the acceleration. There is no mechanism available to capture the kinetic energy that is assumed to exist. If it so happens that microwave radiation or any other form of radiation is emitted from the vacuum as a result of the drive then there may be no need to consider it reactionless. In that case the spaceman can determine the location of his missing mass. Please understand that I am skeptical that a reactionless drive is actually possible. The only reason for this line of speculation is to consider the consequences in case an actual force is proven to exist when one of these devices is operated. That has not been firmly established. Do you believe that a reactionless drive is possible? I suspect that you are kidding. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Wed, Nov 26, 2014 8:23 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Wed, 26 Nov 2014 17:43:00 -0500: Hi, [snip] Here I have to disagree. It makes more sense to assume that he looses energy during both accelerations. If that energy goes into the zpe field then it will just vanish as far as any observer can determine. The guy on the ship is satisfied that he used up some of the mass of his vehicle to accelerate regardless of the direction of that movement. This strange state of affairs is what makes me suspect of the entire concept. The mass just seems to vanish from the universe. If that were the case, then I would be suspicious of it too. That's why I think that if such a drive works at all, then the energy ends up as kinetic energy of the craft. As for the regenerative braking, consider this. It works with electric cars, because they can exchange momentum with the Earth through contact with the road. It is impossible for a normal rocket because they have no road with which to exchange momentum. However if this drive provides the capability of exchanging momentum with the ZPF, then the vehicle effectively has a road available to it while traveling through space, so regenerative breaking becomes a possibility. In the case of Sawyer's drive, it might manifest as virtual microwave photons becoming real photons in the drive, as it slows down. If these microwaves are then damped (i.e. rectified into DC and the energy stored), then they might constantly be replenished as the vehicle slows, thus converting the kinetic energy of the vehicle back into stored energy. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Thu, 27 Nov 2014 01:15:27 -0500: Hi, [snip] It would be refreshing to find that the energy is returned, but I harbor no expectation of that occurring. Consider that what we consider acceleration is exactly the same as deceleration as far as a ship is concerned. In either situation the ship is changing velocity as a function of time due to operation of the drive. I visualize the ship as being at rest just before each acceleration takes place. This implies a change of frame of reference, which explains why the kinetic energy vanishes. A force is applied by the reactionless drive at that time which leads to an acceleration along the line of the applied force. It does not make any difference what direction that force takes when you consider that the drive begins to burn up our mass at the time it causes the acceleration. There is no mechanism available to capture the kinetic energy that is assumed to exist. This is an assumption. If it so happens that microwave radiation or any other form of radiation is emitted from the vacuum as a result of the drive then there may be no need to consider it reactionless. In that case the spaceman can determine the location of his missing mass. The term reactionless is actually a misnomer. Nothing is reactionless. A better term would be exhaust free, or field drive (as has been used in the past). BTW the location of the missing mass is simply the kinetic energy of his vehicle, nothing is actually missing. You might consider an electric car to have a reactionless drive, as it has no exhaust. Perhaps virtual particles are the rough surface of space time, that provide the friction which allows us to get a grip on it. Please understand that I am skeptical that a reactionless drive is actually possible. The only reason for this line of speculation is to consider the consequences in case an actual force is proven to exist when one of these devices is operated. That has not been firmly established. I agree. Do you believe that a reactionless drive is possible? I suspect that you are kidding. I have seen an operating UFO. I know that some form of drive exists, though I don't know how it works, that part is just speculation and a bit of common sense. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
On Thu, Nov 27, 2014 at 1:37 PM, mix...@bigpond.com wrote: I have seen an operating UFO. Can you elaborate on this detail? Eric
Re: [Vo]:They call me a moron. A reply.
In reply to Eric Walker's message of Thu, 27 Nov 2014 14:09:42 -0800: Hi, [snip] On Thu, Nov 27, 2014 at 1:37 PM, mix...@bigpond.com wrote: I have seen an operating UFO. Can you elaborate on this detail? Eric I have previously on this list, but will again, as it was before your time. It was a sunny day with a clear blue sky. I stood in my back yard with a pair of binoculars in the shade of the house, looking generally in the direction of the sun. I looked for some time but saw nothing. Then I started searching the sky a bit more generally. Eventually I saw it. A grey/silver more or less cylindrical object with the cylinder axis vertical. The bottom was a little wider than the top, and had a sort of somewhat flared skirt. The top appeared to be somewhat pointed (about a 20 º angle with the sides). I guess this is the type of thing that is referred to as a top hat UFO. It must have been tilted slightly toward me, because I couldn't see under it, but could see the top somewhat. It bobbed gently sideways until it disappeared from view behind the neighbor's house. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Robin, you were fortunate enough to see something strange that day. My wife and I witnessed some type of UFO a few years ago as well. I was driving and she was in the passengers seat. All I saw was a red ball moving through the trees that appeared much like the way a laser does when shined onto a black screen. She saw something far more impressive but refused to tell me about it until we traveled far enough away to be unable to return for a better look. She was afraid that I would want to go back, and she was right. What she described is nothing short of amazing. She said it moved extremely quickly form above us to within perhaps 30 yards. She also told me it emitted a bright beam of white light. I saw none of that. Of course we did not mention the sighting at that time. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Thu, Nov 27, 2014 7:45 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to Eric Walker's message of Thu, 27 Nov 2014 14:09:42 -0800: Hi, [snip] On Thu, Nov 27, 2014 at 1:37 PM, mix...@bigpond.com wrote: I have seen an operating UFO. Can you elaborate on this detail? Eric I have previously on this list, but will again, as it was before your time. It was a sunny day with a clear blue sky. I stood in my back yard with a pair of binoculars in the shade of the house, looking generally in the direction of the sun. I looked for some time but saw nothing. Then I started searching the sky a bit more generally. Eventually I saw it. A grey/silver more or less cylindrical object with the cylinder axis vertical. The bottom was a little wider than the top, and had a sort of somewhat flared skirt. The top appeared to be somewhat pointed (about a 20 º angle with the sides). I guess this is the type of thing that is referred to as a top hat UFO. It must have been tilted slightly toward me, because I couldn't see under it, but could see the top somewhat. It bobbed gently sideways until it disappeared from view behind the neighbor's house. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Robin, I just came up with a thought experiment that lends support to the idea that a reactionless drive is not likely to exist. Take 2 different observers, one that is moving beside the ship at the same velocity as it has prior to activating the drive. The second one is moving at a velocity that allows him to observe the ship decelerate first until it reaches a velocity of zero relative to him and then to accelerate in the reverse direction until it reaches the exact same original velocity in the opposite direction. The first observer sees the velocity of the ship go from for this example 0 meters per second to 2 meters per second. He determines that the ship now has 2*2*Mass/2 units of kinetic energy. The amount of internal mass that the ship burns up to achieve this acceleration is extremely small and can almost be neglected. The second observer sees the ship moving at the same speed before and then after the application of the drive. The only difference he measures is that the direction of the motion of the ship is reversed by the drive. So he sees the ship begin the motion moving 1 meter per second relative to him initially and then after the drive shuts down the ship is moving 1 meter per second in the opposite direction. This observer determines that the kinetic energy of the ship has not changed measurably due to the application of the drive. At this low velocity the second observer determines that the mass converted into drive power is essentially the same as that determined by the first observer. Both guys have a very hard time figuring out exactly how much mass is converted, and they agree that any difference is hidden in the noise. In this experiment we have two independent observers seeing the same ship being subject to the same drive. The amount of kinetic energy being deposited to the ship by essentially the same loss of internal mass varies remarkably according to each. This does not add up. As I have mentioned before, with a normal drive this case can be handled without a problem. The exhaust material supplies the kinetic energy and momentum needed to balance the equation. Apparently every observer moving at a different initial velocity relative to the driven ship arrives at a significantly different calculation regarding the ships energy balance after the application of the drive. How could something this radical be possible? Let me say it again, there is no problem of this sort to deal with when a standard drive is applied. Dave
Re: [Vo]:They call me a moron. A reply.
Eric-- You have indicated that the space where pair production occurs is not empty. You indicate the space must have an electromagnetic field which interacts with an incoming photon. We have assumed different conditions necessary for pair production. You may be correct that empty space does not support pair production. I always understood it does. Bob - Original Message - From: Eric Walker To: vortex-l@eskimo.com Sent: Tuesday, November 25, 2014 10:47 PM Subject: Re: [Vo]:They call me a moron. A reply. On Mon, Nov 24, 2014 at 7:44 PM, Bob Cook frobertc...@hotmail.com wrote: Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? In the case of an incoming high-energy photon, the pair is produced as a result of the interaction of the photon with an electromagnetic field. The momentum of the incoming photon is conserved in the momentum of the outgoing electron and positron. Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? I assume it does. Do you have a reference (other than Hotson) that says that the rest mass does not include the energy of the intrinsic angular momentum? Since the spin of the electron and positron is presumably intrinsic, I gather they would not be an electron and a positron without it. Their spin is +/- 1/2, which gives them fermi statistics. If they had a different spin, e.g. integer spin, they would have different characteristics and be other than an electron and a positron. (Note there's also the analogous case of the muon and antimuon, etc.) Eric
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Sun, 23 Nov 2014 22:44:46 -0500: Hi, [snip] If the particles appear and then annihilate each other so that nothing is left then they would not carry away any momentum or energy. Normal drives require that an amount of momentum that equals that which is imparted into the ship be ejected in an opposite direction. If the particles are given kinetic energy, then annihilate, the annihilation energy will be larger than the energy required to create them (the excess being the kinetic energy they received). So what happens to the excess? Does it appear as EM radiation, or does it modify the zero point field (ZPF) locally? This may result in momentum being transferred to the ZPF i.e. the substratum of the universe, which being vastly more massive than the craft itself means that the craft itself effectively ends up with all of the energy. This is basically what I was trying to get at. The converted energy may end up as kinetic energy of the craft itself. As to a traveler not being able to tell that he is going faster, that is clearly not so. He can measure the change in red/blue shift of the stars. That will even tell him what direction he is traveling in. In simple terms he uses the same method we do when traveling in a car, he looks out of the window. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Mon, 24 Nov 2014 00:06:09 -0500: Hi, [snip] I agree Axil. And those particles that are produced are then given the momentum required to balance out that obtained by the ship. Also, they must remain in existence as real particles and not disappear after a brief time interval. The folks who speak of reactionless drives claim that their are no measurable particles remaining to locate after the momentum is imparted into the ship. That is where I can not agree. Dave Perhaps, because they are only virtual particles, they are still connected to the ZPF, and hence are effectively infinitely massive. That would mean that the energy imparted to the particles would approach zero, while still allowing transfer of momentum. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
One issue that tends to support the thought that the internal energy can vanish without a visible trace is that the man onboard the ship can detect that he is undergoing acceleration while the drive is active. If it is eventually confirmed that a force arises from the activation of the drive then energy will be imparted onto the ship according to his measurements. Even though all velocities are considered relative, a change in velocity can usually be determined. That is reason to sustain hope for reactionless drives becoming a reality. It remains to be proven that the force obtained will be practical. So far there is reason to suspect that it does not exit at all. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Wed, Nov 26, 2014 5:19 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Mon, 24 Nov 2014 00:06:09 -0500: Hi, [snip] I agree Axil. And those particles that are produced are then given the momentum required to balance out that obtained by the ship. Also, they must remain in existence as real particles and not disappear after a brief time interval. The folks who speak of reactionless drives claim that their are no measurable particles remaining to locate after the momentum is imparted into the ship. That is where I can not agree. Dave Perhaps, because they are only virtual particles, they are still connected to the ZPF, and hence are effectively infinitely massive. That would mean that the energy imparted to the particles would approach zero, while still allowing transfer of momentum. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Mon, 24 Nov 2014 11:08:27 -0500: Hi, [snip] Bob, consider the following sequence of maneuvers taken by the spaceship and the guy within. First, he decided to move in one direction for an extended length of time. Then he decides to return to his starting point by reversing the drive. After all of his mechanizations the final result is that he comes to rest at the original location and at the original velocity in space. If such a drive exists, then the answer is obvious. Returning to his original velocity does not cost extra energy. Quite the reverse, the energy originally expended to create kinetic energy of the vehicle is now returned, as the vehicles kinetic energy is converted back into potential energy, IOW he uses the vehicles kinetic energy to recharge his batteries, so that once back at his original position and velocity, he also has the same mass that he started out with. (The concept is analogous to regenerative braking). Of course in practice, recharging the batteries will not be 100% efficient. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Here I have to disagree. It makes more sense to assume that he looses energy during both accelerations. If that energy goes into the zpe field then it will just vanish as far as any observer can determine. The guy on the ship is satisfied that he used up some of the mass of his vehicle to accelerate regardless of the direction of that movement. This strange state of affairs is what makes me suspect of the entire concept. The mass just seems to vanish from the universe. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Wed, Nov 26, 2014 5:35 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Mon, 24 Nov 2014 11:08:27 -0500: Hi, [snip] Bob, consider the following sequence of maneuvers taken by the spaceship and the guy within. First, he decided to move in one direction for an extended length of time. Then he decides to return to his starting point by reversing the drive. After all of his mechanizations the final result is that he comes to rest at the original location and at the original velocity in space. If such a drive exists, then the answer is obvious. Returning to his original velocity does not cost extra energy. Quite the reverse, the energy originally expended to create kinetic energy of the vehicle is now returned, as the vehicles kinetic energy is converted back into potential energy, IOW he uses the vehicles kinetic energy to recharge his batteries, so that once back at his original position and velocity, he also has the same mass that he started out with. (The concept is analogous to regenerative braking). Of course in practice, recharging the batteries will not be 100% efficient. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Wed, 26 Nov 2014 17:43:00 -0500: Hi, [snip] Here I have to disagree. It makes more sense to assume that he looses energy during both accelerations. If that energy goes into the zpe field then it will just vanish as far as any observer can determine. The guy on the ship is satisfied that he used up some of the mass of his vehicle to accelerate regardless of the direction of that movement. This strange state of affairs is what makes me suspect of the entire concept. The mass just seems to vanish from the universe. If that were the case, then I would be suspicious of it too. That's why I think that if such a drive works at all, then the energy ends up as kinetic energy of the craft. As for the regenerative braking, consider this. It works with electric cars, because they can exchange momentum with the Earth through contact with the road. It is impossible for a normal rocket because they have no road with which to exchange momentum. However if this drive provides the capability of exchanging momentum with the ZPF, then the vehicle effectively has a road available to it while traveling through space, so regenerative breaking becomes a possibility. In the case of Sawyer's drive, it might manifest as virtual microwave photons becoming real photons in the drive, as it slows down. If these microwaves are then damped (i.e. rectified into DC and the energy stored), then they might constantly be replenished as the vehicle slows, thus converting the kinetic energy of the vehicle back into stored energy. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
It would be refreshing to find that the energy is returned, but I harbor no expectation of that occurring. Consider that what we consider acceleration is exactly the same as deceleration as far as a ship is concerned. In either situation the ship is changing velocity as a function of time due to operation of the drive. I visualize the ship as being at rest just before each acceleration takes place. A force is applied by the reactionless drive at that time which leads to an acceleration along the line of the applied force. It does not make any difference what direction that force takes when you consider that the drive begins to burn up our mass at the time it causes the acceleration. There is no mechanism available to capture the kinetic energy that is assumed to exist. If it so happens that microwave radiation or any other form of radiation is emitted from the vacuum as a result of the drive then there may be no need to consider it reactionless. In that case the spaceman can determine the location of his missing mass. Please understand that I am skeptical that a reactionless drive is actually possible. The only reason for this line of speculation is to consider the consequences in case an actual force is proven to exist when one of these devices is operated. That has not been firmly established. Do you believe that a reactionless drive is possible? I suspect that you are kidding. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Wed, Nov 26, 2014 8:23 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Wed, 26 Nov 2014 17:43:00 -0500: Hi, [snip] Here I have to disagree. It makes more sense to assume that he looses energy during both accelerations. If that energy goes into the zpe field then it will just vanish as far as any observer can determine. The guy on the ship is satisfied that he used up some of the mass of his vehicle to accelerate regardless of the direction of that movement. This strange state of affairs is what makes me suspect of the entire concept. The mass just seems to vanish from the universe. If that were the case, then I would be suspicious of it too. That's why I think that if such a drive works at all, then the energy ends up as kinetic energy of the craft. As for the regenerative braking, consider this. It works with electric cars, because they can exchange momentum with the Earth through contact with the road. It is impossible for a normal rocket because they have no road with which to exchange momentum. However if this drive provides the capability of exchanging momentum with the ZPF, then the vehicle effectively has a road available to it while traveling through space, so regenerative breaking becomes a possibility. In the case of Sawyer's drive, it might manifest as virtual microwave photons becoming real photons in the drive, as it slows down. If these microwaves are then damped (i.e. rectified into DC and the energy stored), then they might constantly be replenished as the vehicle slows, thus converting the kinetic energy of the vehicle back into stored energy. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
On Mon, Nov 24, 2014 at 7:44 PM, Bob Cook frobertc...@hotmail.com wrote: Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? In the case of an incoming high-energy photon, the pair is produced as a result of the interaction of the photon with an electromagnetic field. The momentum of the incoming photon is conserved in the momentum of the outgoing electron and positron. Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? I assume it does. Do you have a reference (other than Hotson) that says that the rest mass does not include the energy of the intrinsic angular momentum? Since the spin of the electron and positron is presumably intrinsic, I gather they would not be an electron and a positron without it. Their spin is +/- 1/2, which gives them fermi statistics. If they had a different spin, e.g. integer spin, they would have different characteristics and be other than an electron and a positron. (Note there's also the analogous case of the muon and antimuon, etc.) Eric
Re: [Vo]:They call me a moron. A reply.
If the spaceman can detect the microwave photons exiting the cavity with lots of momentum the drive would not be considered reactionless. A true reactionless drive does not exhaust any significant form of matter or energy that can be detected by the guy when it operates. Of course heat can be radiated from the ship provided it does not contain enough momentum to supply the forward directed force. That is the definition as I understand it. A normal type of propulsion system always emits some form of exhaust that carries plenty of momentum. The momentum gained by the ship is exactly balanced by the momentum of the exiting exhaust in a standard rocket engine. Newton's law about every reaction having an equal and opposite reaction is what we have observed for all rocket engines. Leave out the equal and opposite reaction and you have a reactionless design. Thus far I have seen no evidence that a reactionless engine is possible according to the above definition. Could it be that some of you guys do not define a reactionless drive in the same manner as I? From some of the responses I am receiving that appears to be the case. If true, then how would you describe the operation of one and how is that different than what we normally expect? Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:48 am Subject: Re: [Vo]:They call me a moron. A reply. On Sun, Nov 23, 2014 at 9:21 PM, David Roberson dlrober...@aol.com wrote: With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. If the guy with the spaceship with the EmDrive could bend the laws of physics for a moment and arrange for tracer photons, perhaps he could see microwave photons exiting the cavity of the drive in the opposite direction, accounting for the anomalous thrust. (Perhaps I'm missing your point.) Eric
Re: [Vo]:They call me a moron. A reply.
Another idea based on the same concept, some forms of energy do not seem to contribute to rest mass, I doubt a compressed spring would have a different rest mass due to it's energy storage than the same spring uncompressed. Actually the spring is supposed to have a greater amount of rest mass when compressed. E=MC*C can be used to calculate the tiny additional mass due to the added energy. The example you have chosen is too difficult to analyze without a great deal of time. Perhaps someone else wants to give it a try. If your example depends upon the spring not gaining mass with added energy then it does not function the way you suspect. I am not aware of any method of storing energy that does not result in an increase in the rest mass of the storage device. For example, heating a frying pan makes it more massive. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:57 am Subject: Re: [Vo]:They call me a moron. A reply. First off I believe that Newtons laws break down with regular engineering, there are multiple mechanical devices that do genuinely appear to create a net thrust. However these can not be proven from conjecture, they must be accurately replicated to maybe prove they work, and disproof may barely be possible due to subtle factors being potentially at work. Nevertheless, here is a reaction-less thruster that is capable of being mathematically proven or disproven. Take 2 identical flywheels spinning in opposite directions, these are rotating so far so as to have a useful increase in relativistic mass. Throw it from the front of your spaceship to the back, as it is moving to the rear of the ship they stop rotating, store the energy and now once they are not rotating they compress a spring at the other end of the ship. Because the relativistic mass is less when they are being stopped, you can gain net momentum, additionally you can move then back to the front of the ship and one there spin them up again and throw them aft repeatedly. So if the relativistic mass increase is not considered real, then what is stopping us from accelerating mass beyond light speed if the resistance to acceleration is unchanged? Another idea based on the same concept, some forms of energy do not seem to contribute to rest mass, I doubt a compressed spring would have a different rest mass due to it's energy storage than the same spring uncompressed. So if we can store energy in a way that has no mass, then we can also then turn that energy into mass, for instance the particle products of a proton-proton collision can be much greater than the mass of the 2 protons. So if we can make and destroy (increase and decrease) rest mass at will then we can again move a weight that is heavier when we push off then when it comes to a stop. Neither of these seem close to practical, but are they flawed? On Mon, Nov 24, 2014 at 6:21 PM, David Roberson dlrober...@aol.com wrote: The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The problem is that this energy can be depleted without having anything to show for its loss. If taken to the extreme most of the ship can be converted into energy by some nuclear process to supply power for the drive mechanism. After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. He will not have any kinetic energy relative to himself. He sees that his ships mass has depleted but has nothing to show where it went. With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:02 am Subject: Re: [Vo]:They call me a moron. A reply. On Sun, Nov 23, 2014 at 8:26 PM, David Roberson dlrober...@aol.com wrote: I encourage anyone out there with knowledge about how to overcome the obvious problems to offer their input. One thought here -- the reactionless drive that I am aware of being in the recent news is the EmDrive. That one involves the generation of microwaves and their reflection in a cavity. It's not clear whether anyone other than Nasa and the inventor believe that it works as advertised. But if it does, note that energy must be expended to generate the microwaves, e.g., by a battery, to which the usual E=mc^2 conversion will apply. Eric
Re: [Vo]:They call me a moron. A reply.
Ok, so a charged battery is more massive than a discharged battery... A bowling ball on a shelf is more massive than the same bowling ball on the ground (greater potential energy). A spring compressed or stretched is more massive than one under no tension. I was wondering as I typed the previous email if this would be the reply, it isn't an angle of e=mc2 I have heard of but it sounds plausible that energy has mass. This creates a problem though, the mass of everything in the universe is then logically effected by all other masses, electric and magnetic fields and other potential sources of energy! So a new galaxy is born and suddenly all mass in the universe has too. Not sure that makes sense, but it does make for some interesting scifi! John On Mon, Nov 24, 2014 at 9:20 PM, David Roberson dlrober...@aol.com wrote: Another idea based on the same concept, some forms of energy do not seem to contribute to rest mass, I doubt a compressed spring would have a different rest mass due to it's energy storage than the same spring uncompressed. Actually the spring is supposed to have a greater amount of rest mass when compressed. E=MC*C can be used to calculate the tiny additional mass due to the added energy. The example you have chosen is too difficult to analyze without a great deal of time. Perhaps someone else wants to give it a try. If your example depends upon the spring not gaining mass with added energy then it does not function the way you suspect. I am not aware of any method of storing energy that does not result in an increase in the rest mass of the storage device. For example, heating a frying pan makes it more massive. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:57 am Subject: Re: [Vo]:They call me a moron. A reply. First off I believe that Newtons laws break down with regular engineering, there are multiple mechanical devices that do genuinely appear to create a net thrust. However these can not be proven from conjecture, they must be accurately replicated to maybe prove they work, and disproof may barely be possible due to subtle factors being potentially at work. Nevertheless, here is a reaction-less thruster that is capable of being mathematically proven or disproven. Take 2 identical flywheels spinning in opposite directions, these are rotating so far so as to have a useful increase in relativistic mass. Throw it from the front of your spaceship to the back, as it is moving to the rear of the ship they stop rotating, store the energy and now once they are not rotating they compress a spring at the other end of the ship. Because the relativistic mass is less when they are being stopped, you can gain net momentum, additionally you can move then back to the front of the ship and one there spin them up again and throw them aft repeatedly. So if the relativistic mass increase is not considered real, then what is stopping us from accelerating mass beyond light speed if the resistance to acceleration is unchanged? Another idea based on the same concept, some forms of energy do not seem to contribute to rest mass, I doubt a compressed spring would have a different rest mass due to it's energy storage than the same spring uncompressed. So if we can store energy in a way that has no mass, then we can also then turn that energy into mass, for instance the particle products of a proton-proton collision can be much greater than the mass of the 2 protons. So if we can make and destroy (increase and decrease) rest mass at will then we can again move a weight that is heavier when we push off then when it comes to a stop. Neither of these seem close to practical, but are they flawed? On Mon, Nov 24, 2014 at 6:21 PM, David Roberson dlrober...@aol.com wrote: The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The problem is that this energy can be depleted without having anything to show for its loss. If taken to the extreme most of the ship can be converted into energy by some nuclear process to supply power for the drive mechanism. After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. He will not have any kinetic energy relative to himself. He sees that his ships mass has depleted but has nothing to show where it went. With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:02 am Subject: Re: [Vo]:They call me a moron. A reply. On
Re: [Vo]:They call me a moron. A reply.
Just to clarify that further, if the mass of something depended on it's energy, and if that includes potential energy then anything that provides potential energy to other objects increases the potential of every object that could fall into this potential field at any at any point. And since some potential fields can be established and later removed such as a magnetic field then the mass of energything in the universe that could be effected by a magnetic field would be increased the moment it is turned on, and not when turned off. And if you had a gravitational source that could be established and disestablished this should increase the potential energy and hence mass of everything that is effected by gravity, including light (in as much as light has mass of a sorts). Rather than magnetisms limited range of effects. John On Mon, Nov 24, 2014 at 11:12 PM, John Berry berry.joh...@gmail.com wrote: Ok, so a charged battery is more massive than a discharged battery... A bowling ball on a shelf is more massive than the same bowling ball on the ground (greater potential energy). A spring compressed or stretched is more massive than one under no tension. I was wondering as I typed the previous email if this would be the reply, it isn't an angle of e=mc2 I have heard of but it sounds plausible that energy has mass. This creates a problem though, the mass of everything in the universe is then logically effected by all other masses, electric and magnetic fields and other potential sources of energy! So a new galaxy is born and suddenly all mass in the universe has too. Not sure that makes sense, but it does make for some interesting scifi! John On Mon, Nov 24, 2014 at 9:20 PM, David Roberson dlrober...@aol.com wrote: Another idea based on the same concept, some forms of energy do not seem to contribute to rest mass, I doubt a compressed spring would have a different rest mass due to it's energy storage than the same spring uncompressed. Actually the spring is supposed to have a greater amount of rest mass when compressed. E=MC*C can be used to calculate the tiny additional mass due to the added energy. The example you have chosen is too difficult to analyze without a great deal of time. Perhaps someone else wants to give it a try. If your example depends upon the spring not gaining mass with added energy then it does not function the way you suspect. I am not aware of any method of storing energy that does not result in an increase in the rest mass of the storage device. For example, heating a frying pan makes it more massive. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:57 am Subject: Re: [Vo]:They call me a moron. A reply. First off I believe that Newtons laws break down with regular engineering, there are multiple mechanical devices that do genuinely appear to create a net thrust. However these can not be proven from conjecture, they must be accurately replicated to maybe prove they work, and disproof may barely be possible due to subtle factors being potentially at work. Nevertheless, here is a reaction-less thruster that is capable of being mathematically proven or disproven. Take 2 identical flywheels spinning in opposite directions, these are rotating so far so as to have a useful increase in relativistic mass. Throw it from the front of your spaceship to the back, as it is moving to the rear of the ship they stop rotating, store the energy and now once they are not rotating they compress a spring at the other end of the ship. Because the relativistic mass is less when they are being stopped, you can gain net momentum, additionally you can move then back to the front of the ship and one there spin them up again and throw them aft repeatedly. So if the relativistic mass increase is not considered real, then what is stopping us from accelerating mass beyond light speed if the resistance to acceleration is unchanged? Another idea based on the same concept, some forms of energy do not seem to contribute to rest mass, I doubt a compressed spring would have a different rest mass due to it's energy storage than the same spring uncompressed. So if we can store energy in a way that has no mass, then we can also then turn that energy into mass, for instance the particle products of a proton-proton collision can be much greater than the mass of the 2 protons. So if we can make and destroy (increase and decrease) rest mass at will then we can again move a weight that is heavier when we push off then when it comes to a stop. Neither of these seem close to practical, but are they flawed? On Mon, Nov 24, 2014 at 6:21 PM, David Roberson dlrober...@aol.com wrote: The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The
Re: [Vo]:They call me a moron. A reply.
Bob, well said, I would only add that this is also not a matter of ejecting mass but energy consumed to directionalize an existing media like an airplane or boat prop re-directionalize air or water - it is giving the spacecraft linkage to the ether against which it can simply push. Although this is easier to see with hydrogen particles I think Shawyer is somehow employing the same principle with just microwaves. IMHO the hydrogen when fractionalized or IRH is aging at a different rate than normal 3D hydrogen, many recent threads seem to indicate that SPP is the linkage to these regions where the isotropy is broken and virtual particle pressure is fractured into a tapestry described by the ( inverse spacing between lattice geometries) ^4 through which hydrogen still migrates according to the random motion of gas law, The SPP linkage is allowing us to push against a special type of relativistic hydrogen - a type that doesn't shoot past our stationary frame at high fractions of C but rather modifies the space between these plates into a gravitational hill/warp where virtual particles are compressed instead of stretched. Mass is not lost because nature will float physical matter back to our plane as the local frame for these hydrogen are still subject to random gas motion that migrates it back up thru the tapestry from the more robust areas against which the linkage finds purchase. Although the Rossi and Mills scheme utilize the random motion of gas to bootstrap their process I actually suspect it will be easier to demonstrate inertia modification by employing SPP as stims, I just don't think anyone has looked for it yet / Difiore et all were seeking an effect from passive arrangement of cavities and don't believe they ever tried to stimulate the effect. Fran From: Bob Cook [mailto:frobertc...@hotmail.com] Sent: Sunday, November 23, 2014 6:38 PM To: vortex-l@eskimo.com Subject: EXTERNAL: Re: [Vo]:They call me a moron. A reply. Dave-- If the mass is converted into mass of virtual particles in the Dirac space, it is obvious that the man in the space ship would never see the results. The standard conversion of energy normally happens in a measurable 3-D space the space man knows. The other situation involves the Dirac space in addition to the standard 3-D space, but still conserves energy/mass, its just not observable yet. You must think outside the 3-D box. Engineers do this better than scientists. Note Bob Higgins recent comment attributed to a mentor of his. Bob - Original Message - From: David Robersonmailto:dlrober...@aol.com To: vortex-l@eskimo.commailto:vortex-l@eskimo.com Sent: Sunday, November 23, 2014 1:23 PM Subject: Re: [Vo]:They call me a moron. A reply. That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.commailto:mix...@bigpond.com To: vortex-l vortex-l@eskimo.commailto:vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's
Re: [Vo]:They call me a moron. A reply.
David-- If Dirac was correct about his negative energy sea containing epos with its below energy electron-positron pairs (epos), then there might be negative energy momentum--my term--as well, which is where the momentum of virtual particles in the spaceman's 3-D space disappear to upon an--annihilation--a term invented in the 1930's to counter Dirac's concept of energy returning to the negative energy sea. (Keep in mind that the modern concepts of pair production from empty space and the opposite reaction of e-p annihilation do not conserve energy associated with angular momentum of the electron and positron nor the change of energy of the electric field creation or collapse associated with the creation or loss of charge respectively.) The spaceman in his 3-D space would think that momentum transfer did not occur because there would be no particles or other evidence of mass or energy moving away from his space ship, yet his ship would be accelerating in his 3-D space based on observation of objects he considered to be fixed relative to his initial position. This would be the reaction less drive device in his space ship. Bob Cook - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Sunday, November 23, 2014 9:06 PM Subject: Re: [Vo]:They call me a moron. A reply. I agree Axil. And those particles that are produced are then given the momentum required to balance out that obtained by the ship. Also, they must remain in existence as real particles and not disappear after a brief time interval. The folks who speak of reactionless drives claim that their are no measurable particles remaining to locate after the momentum is imparted into the ship. That is where I can not agree. Dave -Original Message- From: Axil Axil janap...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 11:39 pm Subject: Re: [Vo]:They call me a moron. A reply. There is no such think as a reactionless drive. Particles must be being produced in the vacuum by EMF. On Sun, Nov 23, 2014 at 10:40 PM, David Roberson dlrober...@aol.com wrote: Yes Axil. The drive would then qualify as a standard one and the problem dissolves. This does not appear to what the proponents of a reactionless drive believe is occurring from what I have determined. They suggest that there is nothing available to carry away the balancing momentum. Why call it a reactionless drive if exhaust can be measured? Dave -Original Message- From: Axil Axil janap...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:41 pm Subject: Re: [Vo]:They call me a moron. A reply. No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave
Re: [Vo]:They call me a moron. A reply.
David-- You stated: After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. Yes he can determine he is moving. All he needs to do is look out the window and see that he is moving relative to objects that were fixed before he started his travel and are assumed to have remained fixed. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Sunday, November 23, 2014 9:21 PM Subject: Re: [Vo]:They call me a moron. A reply. The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The problem is that this energy can be depleted without having anything to show for its loss. If taken to the extreme most of the ship can be converted into energy by some nuclear process to supply power for the drive mechanism. After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. He will not have any kinetic energy relative to himself. He sees that his ships mass has depleted but has nothing to show where it went. With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:02 am Subject: Re: [Vo]:They call me a moron. A reply. On Sun, Nov 23, 2014 at 8:26 PM, David Roberson dlrober...@aol.com wrote: I encourage anyone out there with knowledge about how to overcome the obvious problems to offer their input. One thought here -- the reactionless drive that I am aware of being in the recent news is the EmDrive. That one involves the generation of microwaves and their reflection in a cavity. It's not clear whether anyone other than Nasa and the inventor believe that it works as advertised. But if it does, note that energy must be expended to generate the microwaves, e.g., by a battery, to which the usual E=mc^2 conversion will apply. Eric
Re: [Vo]:They call me a moron. A reply.
There is ambiguity here based upon a 3D vs 4D perspective but maybe some of these patents regarding remediation of radioactive gas in a catalyst could shed some light. I would posit that this reaction is actually based upon relativistic effects on radioactive gas when local vacuum wavelengths are compressed by Casimir geometry. I think ZPE / HUP keeps physical/ persistent matter floating in our 3d ant farm like a canoe stuck in a water fall and matter pushed away is pushed back by the stream or like atmosphere being forever resupplied in front of an aircraft prop, my gut feeling is the more fractionalized/ condensed hydrogen becomes the harder you can push against the ether. I don't think the hydrogen is lost but will slowly be pushed back into the waterfall where persistent matter is trapped to make room for more hydrogen to gain entry [passive exploitation like Rossi/Mills] - forcing a circulation like Modell Haisch describe in their patent may be a better way to exploit this effect. Fran From: Bob Cook [mailto:frobertc...@hotmail.com] Sent: Monday, November 24, 2014 10:31 AM To: vortex-l@eskimo.com Subject: EXTERNAL: Re: [Vo]:They call me a moron. A reply. David-- If Dirac was correct about his negative energy sea containing epos with its below energy electron-positron pairs (epos), then there might be negative energy momentum--my term--as well, which is where the momentum of virtual particles in the spaceman's 3-D space disappear to upon an--annihilation--a term invented in the 1930's to counter Dirac's concept of energy returning to the negative energy sea. (Keep in mind that the modern concepts of pair production from empty space and the opposite reaction of e-p annihilation do not conserve energy associated with angular momentum of the electron and positron nor the change of energy of the electric field creation or collapse associated with the creation or loss of charge respectively.) The spaceman in his 3-D space would think that momentum transfer did not occur because there would be no particles or other evidence of mass or energy moving away from his space ship, yet his ship would be accelerating in his 3-D space based on observation of objects he considered to be fixed relative to his initial position. This would be the reaction less drive device in his space ship. Bob Cook - Original Message - From: David Robersonmailto:dlrober...@aol.com To: vortex-l@eskimo.commailto:vortex-l@eskimo.com Sent: Sunday, November 23, 2014 9:06 PM Subject: Re: [Vo]:They call me a moron. A reply. I agree Axil. And those particles that are produced are then given the momentum required to balance out that obtained by the ship. Also, they must remain in existence as real particles and not disappear after a brief time interval. The folks who speak of reactionless drives claim that their are no measurable particles remaining to locate after the momentum is imparted into the ship. That is where I can not agree. Dave -Original Message- From: Axil Axil janap...@gmail.commailto:janap...@gmail.com To: vortex-l vortex-l@eskimo.commailto:vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 11:39 pm Subject: Re: [Vo]:They call me a moron. A reply. There is no such think as a reactionless drive. Particles must be being produced in the vacuum by EMF. On Sun, Nov 23, 2014 at 10:40 PM, David Roberson dlrober...@aol.commailto:dlrober...@aol.com wrote: Yes Axil. The drive would then qualify as a standard one and the problem dissolves. This does not appear to what the proponents of a reactionless drive believe is occurring from what I have determined. They suggest that there is nothing available to carry away the balancing momentum. Why call it a reactionless drive if exhaust can be measured? Dave -Original Message- From: Axil Axil janap...@gmail.commailto:janap...@gmail.com To: vortex-l vortex-l@eskimo.commailto:vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:41 pm Subject: Re: [Vo]:They call me a moron. A reply. No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.commailto:dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the
Re: [Vo]:They call me a moron. A reply.
Bob, consider the following sequence of maneuvers taken by the spaceship and the guy within. First, he decided to move in one direction for an extended length of time. Then he decides to return to his starting point by reversing the drive. After all of his mechanizations the final result is that he comes to rest at the original location and at the original velocity in space. All of this can be done at low velocities so that relativistic effects have an insignificant contribution to the results. As a matter of fact, the magnitude of force so far generated according to reactionless drive proponents would clearly fall into this category. Under these conditions what would the guy on the ship observe? He has never been able to detect or measure any form of energy or mass actually being exhausted by his ship since it is invisible to him. He has effectively moved nowhere as compared to his original velocity and position. But, for some strange reason the energy required to power the drive has vanished and he can not find it onboard his ship nor in the exhaust which is by definition non existent. I can see no way to justify this result unless the mass of an object can vary over time. If you carry this process to the extreme the ship will simply loose most of its mass with nothing to indicate where it went. Keep in mind that a normal type of spaceship drive does not suffer this consequence. Even in the case where the motion is reversed, all of the mass of the spaceship can be accounted for. The original mass has been redistributed about the local region of space and contains kinetic energy due to its motion relative to the original ship. In one case the numbers add up, in the other case they do not. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 10:31 am Subject: Re: [Vo]:They call me a moron. A reply. David-- If Dirac was correct about his negative energy sea containing epos with its below energy electron-positron pairs (epos), then there might be negative energy momentum--my term--as well, which is where the momentum of virtual particles in the spaceman's 3-D space disappear to upon an--annihilation--a term invented in the 1930's to counter Dirac's concept of energy returning to the negative energy sea. (Keep in mind that the modern concepts of pair production from empty space and the opposite reaction of e-p annihilation do not conserve energy associated with angular momentum of the electron and positron nor the change of energy of the electric field creation or collapse associated with the creation or loss of charge respectively.) The spaceman in his 3-D space would think that momentum transfer did not occur because there would be no particles or other evidence of mass or energy moving away from his space ship, yet his ship would be accelerating in his 3-D space based on observation of objects he considered to be fixed relative to his initial position. This would be the reaction less drive device in his space ship. Bob Cook - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Sunday, November 23, 2014 9:06 PM Subject: Re: [Vo]:They call me a moron. A reply. I agree Axil. And those particles that are produced are then given the momentum required to balance out that obtained by the ship. Also, they must remain in existence as real particles and not disappear after a brief time interval. The folks who speak of reactionless drives claim that their are no measurable particles remaining to locate after the momentum is imparted into the ship. That is where I can not agree. Dave -Original Message- From: Axil Axil janap...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 11:39 pm Subject: Re: [Vo]:They call me a moron. A reply. There is no such think as a reactionless drive. Particles must be being produced in the vacuum by EMF. On Sun, Nov 23, 2014 at 10:40 PM, David Roberson dlrober...@aol.com wrote: Yes Axil. The drive would then qualify as a standard one and the problem dissolves. This does not appear to what the proponents of a reactionless drive believe is occurring from what I have determined. They suggest that there is nothing available to carry away the balancing momentum. Why call it a reactionless drive if exhaust can be measured? Dave -Original Message- From: Axil Axil janap...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:41 pm Subject: Re: [Vo]:They call me a moron. A reply. No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson
Re: [Vo]:They call me a moron. A reply.
Yes, he can determine that he has changed velocity by looking outside the ship at other objects. That is why I proposed the recent posting where he returns to the original location and velocity. That procedure counters the thought that a final velocity change can obscure any problems due to usage of the reactionless drive. Special Relativity is generally considered capable of countering the natural feeling that a particular velocity is important in space, but with zero velocity change there is no need to play that card. The guy must reconcile where the mass of his ship has gone after using the reactionless drive. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 10:38 am Subject: Re: [Vo]:They call me a moron. A reply. David-- You stated: After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. Yes he can determine he is moving. All he needs to do is look out the window and see that he is moving relative to objects that were fixed before he started his travel and are assumed to have remained fixed. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Sunday, November 23, 2014 9:21 PM Subject: Re: [Vo]:They call me a moron. A reply. The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The problem is that this energy can be depleted without having anything to show for its loss. If taken to the extreme most of the ship can be converted into energy by some nuclear process to supply power for the drive mechanism. After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. He will not have any kinetic energy relative to himself. He sees that his ships mass has depleted but has nothing to show where it went. With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:02 am Subject: Re: [Vo]:They call me a moron. A reply. On Sun, Nov 23, 2014 at 8:26 PM, David Roberson dlrober...@aol.com wrote: I encourage anyone out there with knowledge about how to overcome the obvious problems to offer their input. One thought here -- the reactionless drive that I am aware of being in the recent news is the EmDrive. That one involves the generation of microwaves and their reflection in a cavity. It's not clear whether anyone other than Nasa and the inventor believe that it works as advertised. But if it does, note that energy must be expended to generate the microwaves, e.g., by a battery, to which the usual E=mc^2 conversion will apply. Eric
Re: [Vo]:They call me a moron. A reply.
David-- The guy need only account for the loss of mass energy by adding the amount of energy transferred to the negative energy sea. Of course, if he does not consider a negative energy sea exists, he cannot properly account. He is stuck with an observation that makes no sense to him. His reaction less drive converted what was originally linear momentum of real particles to the intrinsic property of angular momentum energy, which he does not accounted for in measuring the the rest mass of real particles. The rest mass of his ship has decreased from his counting of particles, the angular momentum of the universe has been transferred to the negative sea--the Dirac sea. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 8:23 AM Subject: Re: [Vo]:They call me a moron. A reply. Yes, he can determine that he has changed velocity by looking outside the ship at other objects. That is why I proposed the recent posting where he returns to the original location and velocity. That procedure counters the thought that a final velocity change can obscure any problems due to usage of the reactionless drive. Special Relativity is generally considered capable of countering the natural feeling that a particular velocity is important in space, but with zero velocity change there is no need to play that card. The guy must reconcile where the mass of his ship has gone after using the reactionless drive. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 10:38 am Subject: Re: [Vo]:They call me a moron. A reply. David-- You stated: After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. Yes he can determine he is moving. All he needs to do is look out the window and see that he is moving relative to objects that were fixed before he started his travel and are assumed to have remained fixed. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Sunday, November 23, 2014 9:21 PM Subject: Re: [Vo]:They call me a moron. A reply. The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The problem is that this energy can be depleted without having anything to show for its loss. If taken to the extreme most of the ship can be converted into energy by some nuclear process to supply power for the drive mechanism. After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. He will not have any kinetic energy relative to himself. He sees that his ships mass has depleted but has nothing to show where it went. With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:02 am Subject: Re: [Vo]:They call me a moron. A reply. On Sun, Nov 23, 2014 at 8:26 PM, David Roberson dlrober...@aol.com wrote: I encourage anyone out there with knowledge about how to overcome the obvious problems to offer their input. One thought here -- the reactionless drive that I am aware of being in the recent news is the EmDrive. That one involves the generation of microwaves and their reflection in a cavity. It's not clear whether anyone other than Nasa and the inventor believe that it works as advertised. But if it does, note that energy must be expended to generate the microwaves, e.g., by a battery, to which the usual E=mc^2 conversion will apply. Eric
Re: [Vo]:They call me a moron. A reply.
When the ship was moving in one direction only we calculate that all of the missing mass ends up as kinetic energy of the ship. But now that two directions are used and we end up at the original starting point and velocity we decide that all of that energy is imparted to the negative energy sea. How do we reconcile these two very different sinks for the energy? I seldom like to use the term magic in a scientific argument, but that is the best way to explain this concept. We operate a device onboard our ship for a long period of time while our ship vanishes into thin space. We have absolutely nothing to show for the missing mass and no one can locate any of it. That is a long stretch. A second observer that was at rest next to the ship before the drive was active is also confused. He sees the ship gaining kinetic energy while violating the conservation of momentum by demonstrating no exhaust stream. But then, it returns to his side with no motion remaining and contains potentially much less mass than before. He must be totally baffled. This is especially difficult for him to understand when everything would add up correctly had the ship used a normal drive by ejecting exhaust. There are too many inconsistencies for me to accept the concept as possible so far. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:14 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- The guy need only account for the loss of mass energy by adding the amount of energy transferred to the negative energy sea. Of course, if he does not consider a negative energy sea exists, he cannot properly account. He is stuck with an observation that makes no sense to him. His reaction less drive converted what was originally linear momentum of real particles to the intrinsic property of angular momentum energy, which he does not accounted for in measuring the the rest mass of real particles. The rest mass of his ship has decreased from his counting of particles, the angular momentum of the universe has been transferred to the negative sea--the Dirac sea. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 8:23 AM Subject: Re: [Vo]:They call me a moron. A reply. Yes, he can determine that he has changed velocity by looking outside the ship at other objects. That is why I proposed the recent posting where he returns to the original location and velocity. That procedure counters the thought that a final velocity change can obscure any problems due to usage of the reactionless drive. Special Relativity is generally considered capable of countering the natural feeling that a particular velocity is important in space, but with zero velocity change there is no need to play that card. The guy must reconcile where the mass of his ship has gone after using the reactionless drive. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 10:38 am Subject: Re: [Vo]:They call me a moron. A reply. David-- You stated: After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. Yes he can determine he is moving. All he needs to do is look out the window and see that he is moving relative to objects that were fixed before he started his travel and are assumed to have remained fixed. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Sunday, November 23, 2014 9:21 PM Subject: Re: [Vo]:They call me a moron. A reply. The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The problem is that this energy can be depleted without having anything to show for its loss. If taken to the extreme most of the ship can be converted into energy by some nuclear process to supply power for the drive mechanism. After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. He will not have any kinetic energy relative to himself. He sees that his ships mass has depleted but has nothing to show where it went. With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. Dave -Original
Re: [Vo]:They call me a moron. A reply.
David, I take it you now accept that energy can be stored without increasing mass? I can see you have avoided tackling the subject so I assume this is an admission that you can't. This then means we can produce a reactionless drive by changing between forms of energy that do and do not contribute mass. As for the microwave cavity, if you put microwaves in a cavity, how long after you stop pumping in microwaves do they stop bouncing around inside? Real world, which means an imperfect cavity. So the production of thrust seems to occur as a bonus. We can't really observe that the energy loss is greater because thrust is produced. Additionally the argument energy could come to nothing it maybe in a sense correct, but only because a true reactionless drive by default will destroy the conservation of energy by allowing both the creation and destruction of energy. Creation because reaching double the speed with the same energy cost is a violation as it implies eventually gaining more from acceleration that the energy cost. And indeed because opposing kinetic energy results in a net loss of energy. But an assumption about the perfection of the CoE should not be assumed since that is just a theory and one that is based on the assumption that the fabric of space does not change. But if this device is pushing on the virtual particles of space or maybe the Higgs Boson or space time it's self then energy would not necessarily be conserved. Here is an article on the non-conservation of energy: http://www.preposterousuniverse.com/blog/2010/02/22/energy-is-not-conserved/ Please remember that the conservation of energy is just an idea based on symmetry. And I would personally argue that treating energy like a supernatural force makes no sense and that any example of energy being converted and conserved looks much more like creation and destruction of energy happening in perfect balance. And that giving energy some life, some existence besides the mechanics of the situation is mysticism. John On Tue, Nov 25, 2014 at 7:05 AM, David Roberson dlrober...@aol.com wrote: When the ship was moving in one direction only we calculate that all of the missing mass ends up as kinetic energy of the ship. But now that two directions are used and we end up at the original starting point and velocity we decide that all of that energy is imparted to the negative energy sea. How do we reconcile these two very different sinks for the energy? I seldom like to use the term magic in a scientific argument, but that is the best way to explain this concept. We operate a device onboard our ship for a long period of time while our ship vanishes into thin space. We have absolutely nothing to show for the missing mass and no one can locate any of it. That is a long stretch. A second observer that was at rest next to the ship before the drive was active is also confused. He sees the ship gaining kinetic energy while violating the conservation of momentum by demonstrating no exhaust stream. But then, it returns to his side with no motion remaining and contains potentially much less mass than before. He must be totally baffled. This is especially difficult for him to understand when everything would add up correctly had the ship used a normal drive by ejecting exhaust. There are too many inconsistencies for me to accept the concept as possible so far. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:14 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- The guy need only account for the loss of mass energy by adding the amount of energy transferred to the negative energy sea. Of course, if he does not consider a negative energy sea exists, he cannot properly account. He is stuck with an observation that makes no sense to him. His reaction less drive converted what was originally linear momentum of real particles to the intrinsic property of angular momentum energy, which he does not accounted for in measuring the the rest mass of real particles. The rest mass of his ship has decreased from his counting of particles, the angular momentum of the universe has been transferred to the negative sea--the Dirac sea. Bob - Original Message - *From:* David Roberson dlrober...@aol.com *To:* vortex-l@eskimo.com *Sent:* Monday, November 24, 2014 8:23 AM *Subject:* Re: [Vo]:They call me a moron. A reply. Yes, he can determine that he has changed velocity by looking outside the ship at other objects. That is why I proposed the recent posting where he returns to the original location and velocity. That procedure counters the thought that a final velocity change can obscure any problems due to usage of the reactionless drive. Special Relativity is generally considered capable of countering the natural feeling that a particular velocity is important in space, but with zero velocity
Re: [Vo]:They call me a moron. A reply.
John, I suspect that you are reading my lack of answer the wrong way. I have been quite busy writing a post about how to test an ECAT like device during a lot of that time. Pushing a mass against gravity is a way to store potential energy. Without going into details I suspect that energy must indeed be stored as mass in this case. Perhaps later it will become clear as to how that takes place and how it can be measured. Perhaps it would be better for you to come up with a practical method of storing energy that can be applied to a reactionless drive and then someone can show you how you are making a mistake. Actually I believe it would be better for you to research the concept and answer that question for yourself. Take the spring for example. Choose a closed system that includes the spring and a battery and motor. Energy stored within the battery can be used to drive the motor that can then have gears that compress the spring. If the spring did not store energy in the form of mass then that system would loose mass as the battery is discharged. A nuclear battery or reactor could perform the same function. So, that is an example of a stand alone system similar to those that you are considering which would loose mass as a result of internal operations. A reactionless drive is not required in this case to lead into a unrealistic situation. I imagine any of the ideas that you are proposing can be subjected to a similar thought process and proven wrong. You can determine that without my involvement. The Q of a microwave cavity determines how long it takes for the internal reflections to die down. This is a well understood process. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 2:30 pm Subject: Re: [Vo]:They call me a moron. A reply. David, I take it you now accept that energy can be stored without increasing mass? I can see you have avoided tackling the subject so I assume this is an admission that you can't. This then means we can produce a reactionless drive by changing between forms of energy that do and do not contribute mass. As for the microwave cavity, if you put microwaves in a cavity, how long after you stop pumping in microwaves do they stop bouncing around inside? Real world, which means an imperfect cavity. So the production of thrust seems to occur as a bonus. We can't really observe that the energy loss is greater because thrust is produced. Additionally the argument energy could come to nothing it maybe in a sense correct, but only because a true reactionless drive by default will destroy the conservation of energy by allowing both the creation and destruction of energy. Creation because reaching double the speed with the same energy cost is a violation as it implies eventually gaining more from acceleration that the energy cost. And indeed because opposing kinetic energy results in a net loss of energy. But an assumption about the perfection of the CoE should not be assumed since that is just a theory and one that is based on the assumption that the fabric of space does not change. But if this device is pushing on the virtual particles of space or maybe the Higgs Boson or space time it's self then energy would not necessarily be conserved. Here is an article on the non-conservation of energy: http://www.preposterousuniverse.com/blog/2010/02/22/energy-is-not-conserved/ Please remember that the conservation of energy is just an idea based on symmetry. And I would personally argue that treating energy like a supernatural force makes no sense and that any example of energy being converted and conserved looks much more like creation and destruction of energy happening in perfect balance. And that giving energy some life, some existence besides the mechanics of the situation is mysticism. John On Tue, Nov 25, 2014 at 7:05 AM, David Roberson dlrober...@aol.com wrote: When the ship was moving in one direction only we calculate that all of the missing mass ends up as kinetic energy of the ship. But now that two directions are used and we end up at the original starting point and velocity we decide that all of that energy is imparted to the negative energy sea. How do we reconcile these two very different sinks for the energy? I seldom like to use the term magic in a scientific argument, but that is the best way to explain this concept. We operate a device onboard our ship for a long period of time while our ship vanishes into thin space. We have absolutely nothing to show for the missing mass and no one can locate any of it. That is a long stretch. A second observer that was at rest next to the ship before the drive was active is also confused. He sees the ship gaining kinetic energy while violating the conservation of momentum by demonstrating no exhaust stream. But then, it returns to his side with no
Re: [Vo]:They call me a moron. A reply.
David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each direction--going out and coming back. He notices a loss of mass to somewhere, but not account for by any particles or mass he can measure that has left the space craft in going and coming back. The stationary observer sees a speeding up and slowing down going out and the same coming back. He also does not see any mass being expelled by the spaceship. However he weighs the ship when it has returned and notices a decrease in mass equivalent to the energy used to speed up and slow down that he observed. Both of the observers see the same loss of mass, but do not realize it has been transferred to outside of their 3-D space as negative energy and momentum to the Dirac sea. Total energy and momentum was conserved in the transfer. Seems magical, but conserves energy and momentum, potentially by conserving spin energy with a coupling between angular momentum and linear momentum and related energy states whether those states are negative or positive--I sound like Rossi-- Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 10:05 AM Subject: Re: [Vo]:They call me a moron. A reply. When the ship was moving in one direction only we calculate that all of the missing mass ends up as kinetic energy of the ship. But now that two directions are used and we end up at the original starting point and velocity we decide that all of that energy is imparted to the negative energy sea. How do we reconcile these two very different sinks for the energy? I seldom like to use the term magic in a scientific argument, but that is the best way to explain this concept. We operate a device onboard our ship for a long period of time while our ship vanishes into thin space. We have absolutely nothing to show for the missing mass and no one can locate any of it. That is a long stretch. A second observer that was at rest next to the ship before the drive was active is also confused. He sees the ship gaining kinetic energy while violating the conservation of momentum by demonstrating no exhaust stream. But then, it returns to his side with no motion remaining and contains potentially much less mass than before. He must be totally baffled. This is especially difficult for him to understand when everything would add up correctly had the ship used a normal drive by ejecting exhaust. There are too many inconsistencies for me to accept the concept as possible so far. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:14 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- The guy need only account for the loss of mass energy by adding the amount of energy transferred to the negative energy sea. Of course, if he does not consider a negative energy sea exists, he cannot properly account. He is stuck with an observation that makes no sense to him. His reaction less drive converted what was originally linear momentum of real particles to the intrinsic property of angular momentum energy, which he does not accounted for in measuring the the rest mass of real particles. The rest mass of his ship has decreased from his counting of particles, the angular momentum of the universe has been transferred to the negative sea--the Dirac sea. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 8:23 AM Subject: Re: [Vo]:They call me a moron. A reply. Yes, he can determine that he has changed velocity by looking outside the ship at other objects. That is why I proposed the recent posting where he returns to the original location and velocity. That procedure counters the thought that a final velocity change can obscure any problems due to usage of the reactionless drive. Special Relativity is generally considered capable of countering the natural feeling that a particular velocity is important in space, but with zero velocity change there is no need to play that card. The guy must reconcile where the mass of his ship has gone after using the reactionless drive. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 10:38 am Subject: Re: [Vo]:They call me a moron. A reply. David-- You stated: After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. Yes he can determine he is moving. All he needs to do is look out the window and see that he is moving relative to objects that were fixed before he
Re: [Vo]:They call me a moron. A reply.
I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each direction--going out and coming back. He notices a loss of mass to somewhere, but not account for by any particles or mass he can measure that has left the space craft in going and coming back. The stationary observer sees a speeding up and slowing down going out and the same coming back. He also does not see any mass being expelled by the spaceship. However he weighs the ship when it has returned and notices a decrease in mass equivalent to the energy used to speed up and slow down that he observed. Both of the observers see the same loss of mass, but do not realize it has been transferred to outside of their 3-D space as negative energy and momentum to the Dirac sea. Total energy and momentum was conserved in the transfer. Seems magical, but conserves energy and momentum, potentially by conserving spin energy with a coupling between angular momentum and linear momentum and related energy states whether those states are negative or positive--I sound like Rossi-- Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 10:05 AM Subject: Re: [Vo]:They call me a moron. A reply. When the ship was moving in one direction only we calculate that all of the missing mass ends up as kinetic energy of the ship. But now that two directions are used and we end up at the original starting point and velocity we decide that all of that energy is imparted to the negative energy sea. How do we reconcile these two very different sinks for the energy? I seldom like to use the term magic in a scientific argument, but that is the best way to explain this concept. We operate a device onboard our ship for a long period of time while our ship vanishes into thin space. We have absolutely nothing to show for the missing mass and no one can locate any of it. That is a long stretch. A second observer that was at rest next to the ship before the drive was active is also confused. He sees the ship gaining kinetic energy while violating the conservation of momentum by demonstrating no exhaust stream. But then, it returns to his side with no motion remaining and contains potentially much less mass than before. He must be totally baffled. This is especially difficult for him to understand when everything would add up correctly had the ship used a normal drive by ejecting exhaust. There are too many inconsistencies for me to accept the concept as possible so far. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:14 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- The guy need only account for the loss of mass energy by adding the amount of energy transferred to the negative energy sea. Of course, if he does not consider a negative energy sea exists, he cannot properly account. He is stuck with an observation that makes no sense to him. His reaction less drive converted what was originally linear momentum of real particles to the intrinsic property of angular momentum energy, which he does not accounted for in measuring the the rest mass of real particles. The rest mass of his ship has decreased from his counting of particles, the
Re: [Vo]:They call me a moron. A reply.
David-- Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? The parameter of spin associated with the electron and the positron that are produced in the pair production involves angular momentum of the electron that comes from some source--empty space or some other place. Where does the energy associated with that angular momentum of each of those new particles come from? Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? One possible answer is that the energy associated with angular momentum is not convertible to mass, at least in the 3-D space we know, but is coupled to epos and their mass energy in the Dirac sea of particles with negative energy. I do not have a good answer for the conversion of angular momentum to linear momentum involving the Dirac sea. I believe Dirac only assumed conservation of energy. D. L. Hotson provided some explaination of the Dirac sea and its realtion to the spin of the electron and positron in an interesting paper that can be obtained at the following link: http://www.google.com/url?sa=trct=jq=esrc=ssource=webcd=4ved=0CDUQFjADurl=http%3A%2F%2Fopenseti.org%2FDocs%2FHotsonPart1.pdfei=W_lzVIS_KoT3oATC_IGABAusg=AFQjCNEGpOAW06Y1ny75ZQHr58i_WIOasAbvm=bv.80185997,d.cGU Check page 12 of this paper for the a possible answer regarding the conversion of energy associated with angular momentur of the electron and positron. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 6:15 PM Subject: Re: [Vo]:They call me a moron. A reply. I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each direction--going out and coming back. He notices a loss of mass to somewhere, but not account for by any particles or mass he can measure that has left the space craft in going and coming back. The stationary observer sees a speeding up and slowing down going out and the same coming back. He also does not see any mass being expelled by the spaceship. However he weighs the ship when it has returned and notices a decrease in mass equivalent to the energy used to speed up and slow down that he observed. Both of the observers see the same loss of mass, but do not realize it has been transferred to outside of their 3-D space as negative energy and momentum to the Dirac sea. Total energy and momentum was conserved in the transfer. Seems magical, but conserves energy and momentum, potentially by conserving spin energy with a coupling between angular momentum and linear momentum and related energy states whether those states are negative or positive--I sound like Rossi-- Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 10:05 AM Subject: Re: [Vo]:They call me a moron. A reply. When the ship was moving in one direction only we calculate that all of the missing mass ends up as kinetic energy of the ship. But now that two directions are used and we end up at the original starting point and velocity we decide that all of that energy is imparted to the negative energy sea. How do we reconcile these two very different sinks for the
Re: [Vo]:They call me a moron. A reply.
Pair production is fairly well established from what I have read. In that case energy is converted into mass but I do not recall any mention of the real pair appearing without some type of input. In particle accelerators mass is created in the form of new particles from the energy contained within the original interacting particles. Both of these cases convert one form of energy into another but do not create anything out of the vacuum without that initial energy. Here I equate energy with mass when I use the term energy. You need to ask someone else about the angular momentum questions you have since I have never looked into that issue. By the way, if I do not respond to your posting or some part of the same it does not carry any implications of my acceptance to what you are stating. I just may not be inclined to comment. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 10:44 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? The parameter of spin associated with the electron and the positron that are produced in the pair production involves angular momentum of the electron that comes from some source--empty space or some other place. Where does the energy associated with that angular momentum of each of those new particles come from? Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? One possible answer is that the energy associated with angular momentum is not convertible to mass, at least in the 3-D space we know, but is coupled to epos and their mass energy in the Dirac sea of particles with negative energy. I do not have a good answer for the conversion of angular momentum to linear momentum involving the Dirac sea. I believe Dirac only assumed conservation of energy. D. L. Hotson provided some explaination of the Dirac sea and its realtion to the spin of the electron and positron in an interesting paper that can be obtained at the following link: http://www.google.com/url?sa=trct=jq=esrc=ssource=webcd=4ved=0CDUQFjADurl=http%3A%2F%2Fopenseti.org%2FDocs%2FHotsonPart1.pdfei=W_lzVIS_KoT3oATC_IGABAusg=AFQjCNEGpOAW06Y1ny75ZQHr58i_WIOasAbvm=bv.80185997,d.cGU Check page 12 of this paper for the a possible answer regarding the conversion of energy associated with angular momentur of the electron and positron. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 6:15 PM Subject: Re: [Vo]:They call me a moron. A reply. I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each direction--going out and coming back. He notices a loss of mass to somewhere, but not account for by any particles or mass he can measure that has left the space craft in going and coming back. The stationary observer sees a speeding up and slowing down going out and the same coming back. He also does not see any mass being expelled by the spaceship. However he weighs the ship when it has returned and
Re: [Vo]:They call me a moron. A reply.
please see http://www.phys.uconn.edu/~dunne/dunne_schwinger.html *The Schwinger effect: non-perturbative vacuum pair production* On Mon, Nov 24, 2014 at 10:44 PM, Bob Cook frobertc...@hotmail.com wrote: David-- Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? The parameter of spin associated with the electron and the positron that are produced in the pair production involves angular momentum of the electron that comes from some source--empty space or some other place. Where does the energy associated with that angular momentum of each of those new particles come from? Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? One possible answer is that the energy associated with angular momentum is not convertible to mass, at least in the 3-D space we know, but is coupled to epos and their mass energy in the Dirac sea of particles with negative energy. I do not have a good answer for the conversion of angular momentum to linear momentum involving the Dirac sea. I believe Dirac only assumed conservation of energy. D. L. Hotson provided some explaination of the Dirac sea and its realtion to the spin of the electron and positron in an interesting paper that can be obtained at the following link: http://www.google.com/url?sa=trct=jq=esrc=ssource=webcd=4ved=0CDUQFjADurl=http%3A%2F%2Fopenseti.org%2FDocs%2FHotsonPart1.pdfei=W_lzVIS_KoT3oATC_IGABAusg=AFQjCNEGpOAW06Y1ny75ZQHr58i_WIOasAbvm=bv.80185997,d.cGU Check page 12 of this paper for the a possible answer regarding the conversion of energy associated with angular momentur of the electron and positron. Bob - Original Message - *From:* David Roberson dlrober...@aol.com *To:* vortex-l@eskimo.com *Sent:* Monday, November 24, 2014 6:15 PM *Subject:* Re: [Vo]:They call me a moron. A reply. I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each direction--going out and coming back. He notices a loss of mass to somewhere, but not account for by any particles or mass he can measure that has left the space craft in going and coming back. The stationary observer sees a speeding up and slowing down going out and the same coming back. He also does not see any mass being expelled by the spaceship. However he weighs the ship when it has returned and notices a decrease in mass equivalent to the energy used to speed up and slow down that he observed. Both of the observers see the same loss of mass, but do not realize it has been transferred to outside of their 3-D space as negative energy and momentum to the Dirac sea. Total energy and momentum was conserved in the transfer. Seems magical, but conserves energy and momentum, potentially by conserving spin energy with a coupling between angular momentum and linear momentum and related energy states whether those states are negative or positive--I sound like Rossi-- Bob - Original Message - *From:* David Roberson dlrober...@aol.com *To:* vortex-l@eskimo.com *Sent:* Monday, November 24, 2014 10:05 AM *Subject:* Re: [Vo]:They call me a moron. A reply. When the ship was moving in one direction only we calculate that all of the missing mass ends up as kinetic energy of the ship. But now that
Re: [Vo]:They call me a moron. A reply.
more... http://arxiv.org/pdf/1106.5965.pdf On Mon, Nov 24, 2014 at 11:31 PM, Axil Axil janap...@gmail.com wrote: please see http://www.phys.uconn.edu/~dunne/dunne_schwinger.html *The Schwinger effect: non-perturbative vacuum pair production* On Mon, Nov 24, 2014 at 10:44 PM, Bob Cook frobertc...@hotmail.com wrote: David-- Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? The parameter of spin associated with the electron and the positron that are produced in the pair production involves angular momentum of the electron that comes from some source--empty space or some other place. Where does the energy associated with that angular momentum of each of those new particles come from? Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? One possible answer is that the energy associated with angular momentum is not convertible to mass, at least in the 3-D space we know, but is coupled to epos and their mass energy in the Dirac sea of particles with negative energy. I do not have a good answer for the conversion of angular momentum to linear momentum involving the Dirac sea. I believe Dirac only assumed conservation of energy. D. L. Hotson provided some explaination of the Dirac sea and its realtion to the spin of the electron and positron in an interesting paper that can be obtained at the following link: http://www.google.com/url?sa=trct=jq=esrc=ssource=webcd=4ved=0CDUQFjADurl=http%3A%2F%2Fopenseti.org%2FDocs%2FHotsonPart1.pdfei=W_lzVIS_KoT3oATC_IGABAusg=AFQjCNEGpOAW06Y1ny75ZQHr58i_WIOasAbvm=bv.80185997,d.cGU Check page 12 of this paper for the a possible answer regarding the conversion of energy associated with angular momentur of the electron and positron. Bob - Original Message - *From:* David Roberson dlrober...@aol.com *To:* vortex-l@eskimo.com *Sent:* Monday, November 24, 2014 6:15 PM *Subject:* Re: [Vo]:They call me a moron. A reply. I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each direction--going out and coming back. He notices a loss of mass to somewhere, but not account for by any particles or mass he can measure that has left the space craft in going and coming back. The stationary observer sees a speeding up and slowing down going out and the same coming back. He also does not see any mass being expelled by the spaceship. However he weighs the ship when it has returned and notices a decrease in mass equivalent to the energy used to speed up and slow down that he observed. Both of the observers see the same loss of mass, but do not realize it has been transferred to outside of their 3-D space as negative energy and momentum to the Dirac sea. Total energy and momentum was conserved in the transfer. Seems magical, but conserves energy and momentum, potentially by conserving spin energy with a coupling between angular momentum and linear momentum and related energy states whether those states are negative or positive--I sound like Rossi-- Bob - Original Message - *From:* David Roberson dlrober...@aol.com *To:* vortex-l@eskimo.com *Sent:* Monday, November 24, 2014 10:05 AM *Subject:* Re: [Vo]:They call me a moron. A reply. When the ship was moving
Re: [Vo]:They call me a moron. A reply.
That is a great link. Axil thanks. The voltage requirement may be reached in SPP's as they collapse and their intense magnetic field changes rapidly. Has the voltage between two pair electrons or protons been calculated. The electric field must be pretty great up close to a pair of electrons held together by their opposite spins. Many electrons in a SPP vortex may even cause greater electric fields. Bob - Original Message - From: Axil Axil To: vortex-l Sent: Monday, November 24, 2014 8:31 PM Subject: Re: [Vo]:They call me a moron. A reply. please see http://www.phys.uconn.edu/~dunne/dunne_schwinger.html The Schwinger effect: non-perturbative vacuum pair production On Mon, Nov 24, 2014 at 10:44 PM, Bob Cook frobertc...@hotmail.com wrote: David-- Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? The parameter of spin associated with the electron and the positron that are produced in the pair production involves angular momentum of the electron that comes from some source--empty space or some other place. Where does the energy associated with that angular momentum of each of those new particles come from? Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? One possible answer is that the energy associated with angular momentum is not convertible to mass, at least in the 3-D space we know, but is coupled to epos and their mass energy in the Dirac sea of particles with negative energy. I do not have a good answer for the conversion of angular momentum to linear momentum involving the Dirac sea. I believe Dirac only assumed conservation of energy. D. L. Hotson provided some explaination of the Dirac sea and its realtion to the spin of the electron and positron in an interesting paper that can be obtained at the following link: http://www.google.com/url?sa=trct=jq=esrc=ssource=webcd=4ved=0CDUQFjADurl=http%3A%2F%2Fopenseti.org%2FDocs%2FHotsonPart1.pdfei=W_lzVIS_KoT3oATC_IGABAusg=AFQjCNEGpOAW06Y1ny75ZQHr58i_WIOasAbvm=bv.80185997,d.cGU Check page 12 of this paper for the a possible answer regarding the conversion of energy associated with angular momentur of the electron and positron. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 6:15 PM Subject: Re: [Vo]:They call me a moron. A reply. I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each direction--going out and coming back. He notices a loss of mass to somewhere, but not account for by any particles or mass he can measure that has left the space craft in going and coming back. The stationary observer sees a speeding up and slowing down going out and the same coming back. He also does not see any mass being expelled by the spaceship. However he weighs the ship when it has returned and notices a decrease in mass equivalent to the energy used to speed up and slow down that he observed. Both of the observers see the same loss of mass, but do not realize it has been transferred to outside of their 3-D space as
Re: [Vo]:They call me a moron. A reply.
http://arxiv.org/pdf/1409.1032v1.pdf A EMF field that equals or exceeds the mass equivalent of a meson (140 MeV) will produce mesons from the vacuum. This is the cold fusion mechanism in a nutshell. On Mon, Nov 24, 2014 at 11:46 PM, Bob Cook frobertc...@hotmail.com wrote: That is a great link. Axil thanks. The voltage requirement may be reached in SPP's as they collapse and their intense magnetic field changes rapidly. Has the voltage between two pair electrons or protons been calculated. The electric field must be pretty great up close to a pair of electrons held together by their opposite spins. Many electrons in a SPP vortex may even cause greater electric fields. Bob - Original Message - *From:* Axil Axil janap...@gmail.com *To:* vortex-l vortex-l@eskimo.com *Sent:* Monday, November 24, 2014 8:31 PM *Subject:* Re: [Vo]:They call me a moron. A reply. please see http://www.phys.uconn.edu/~dunne/dunne_schwinger.html *The Schwinger effect: non-perturbative vacuum pair production* On Mon, Nov 24, 2014 at 10:44 PM, Bob Cook frobertc...@hotmail.com wrote: David-- Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? The parameter of spin associated with the electron and the positron that are produced in the pair production involves angular momentum of the electron that comes from some source--empty space or some other place. Where does the energy associated with that angular momentum of each of those new particles come from? Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? One possible answer is that the energy associated with angular momentum is not convertible to mass, at least in the 3-D space we know, but is coupled to epos and their mass energy in the Dirac sea of particles with negative energy. I do not have a good answer for the conversion of angular momentum to linear momentum involving the Dirac sea. I believe Dirac only assumed conservation of energy. D. L. Hotson provided some explaination of the Dirac sea and its realtion to the spin of the electron and positron in an interesting paper that can be obtained at the following link: http://www.google.com/url?sa=trct=jq=esrc=ssource=webcd=4ved=0CDUQFjADurl=http%3A%2F%2Fopenseti.org%2FDocs%2FHotsonPart1.pdfei=W_lzVIS_KoT3oATC_IGABAusg=AFQjCNEGpOAW06Y1ny75ZQHr58i_WIOasAbvm=bv.80185997,d.cGU Check page 12 of this paper for the a possible answer regarding the conversion of energy associated with angular momentur of the electron and positron. Bob - Original Message - *From:* David Roberson dlrober...@aol.com *To:* vortex-l@eskimo.com *Sent:* Monday, November 24, 2014 6:15 PM *Subject:* Re: [Vo]:They call me a moron. A reply. I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each direction--going out and coming back. He notices a loss of mass to somewhere, but not account for by any particles or mass he can measure that has left the space craft in going and coming back. The stationary observer sees a speeding up and slowing down going out and the same coming back. He also does not see any mass being expelled by the spaceship. However he weighs the ship when it has returned and notices a decrease in mass
Re: [Vo]:They call me a moron. A reply.
Axil-- You mean we just stumbled on it? Inside the nutshell that is? Bob - Original Message - From: Axil Axil To: vortex-l Sent: Monday, November 24, 2014 8:54 PM Subject: Re: [Vo]:They call me a moron. A reply. http://arxiv.org/pdf/1409.1032v1.pdf A EMF field that equals or exceeds the mass equivalent of a meson (140 MeV) will produce mesons from the vacuum. This is the cold fusion mechanism in a nutshell. On Mon, Nov 24, 2014 at 11:46 PM, Bob Cook frobertc...@hotmail.com wrote: That is a great link. Axil thanks. The voltage requirement may be reached in SPP's as they collapse and their intense magnetic field changes rapidly. Has the voltage between two pair electrons or protons been calculated. The electric field must be pretty great up close to a pair of electrons held together by their opposite spins. Many electrons in a SPP vortex may even cause greater electric fields. Bob - Original Message - From: Axil Axil To: vortex-l Sent: Monday, November 24, 2014 8:31 PM Subject: Re: [Vo]:They call me a moron. A reply. please see http://www.phys.uconn.edu/~dunne/dunne_schwinger.html The Schwinger effect: non-perturbative vacuum pair production On Mon, Nov 24, 2014 at 10:44 PM, Bob Cook frobertc...@hotmail.com wrote: David-- Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? The parameter of spin associated with the electron and the positron that are produced in the pair production involves angular momentum of the electron that comes from some source--empty space or some other place. Where does the energy associated with that angular momentum of each of those new particles come from? Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? One possible answer is that the energy associated with angular momentum is not convertible to mass, at least in the 3-D space we know, but is coupled to epos and their mass energy in the Dirac sea of particles with negative energy. I do not have a good answer for the conversion of angular momentum to linear momentum involving the Dirac sea. I believe Dirac only assumed conservation of energy. D. L. Hotson provided some explaination of the Dirac sea and its realtion to the spin of the electron and positron in an interesting paper that can be obtained at the following link: http://www.google.com/url?sa=trct=jq=esrc=ssource=webcd=4ved=0CDUQFjADurl=http%3A%2F%2Fopenseti.org%2FDocs%2FHotsonPart1.pdfei=W_lzVIS_KoT3oATC_IGABAusg=AFQjCNEGpOAW06Y1ny75ZQHr58i_WIOasAbvm=bv.80185997,d.cGU Check page 12 of this paper for the a possible answer regarding the conversion of energy associated with angular momentur of the electron and positron. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 6:15 PM Subject: Re: [Vo]:They call me a moron. A reply. I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding
Re: [Vo]:They call me a moron. A reply.
I've thought enough--I'm headed for bed--:) - Original Message - From: Axil Axil To: vortex-l Sent: Monday, November 24, 2014 8:54 PM Subject: Re: [Vo]:They call me a moron. A reply. http://arxiv.org/pdf/1409.1032v1.pdf A EMF field that equals or exceeds the mass equivalent of a meson (140 MeV) will produce mesons from the vacuum. This is the cold fusion mechanism in a nutshell. On Mon, Nov 24, 2014 at 11:46 PM, Bob Cook frobertc...@hotmail.com wrote: That is a great link. Axil thanks. The voltage requirement may be reached in SPP's as they collapse and their intense magnetic field changes rapidly. Has the voltage between two pair electrons or protons been calculated. The electric field must be pretty great up close to a pair of electrons held together by their opposite spins. Many electrons in a SPP vortex may even cause greater electric fields. Bob - Original Message - From: Axil Axil To: vortex-l Sent: Monday, November 24, 2014 8:31 PM Subject: Re: [Vo]:They call me a moron. A reply. please see http://www.phys.uconn.edu/~dunne/dunne_schwinger.html The Schwinger effect: non-perturbative vacuum pair production On Mon, Nov 24, 2014 at 10:44 PM, Bob Cook frobertc...@hotmail.com wrote: David-- Pair production, which I assume you agree is real, creates mass from empty space. What is the source of this mass, or the equivalent energy? What is the mechanism that makes this happen? The parameter of spin associated with the electron and the positron that are produced in the pair production involves angular momentum of the electron that comes from some source--empty space or some other place. Where does the energy associated with that angular momentum of each of those new particles come from? Why does not the rest mass of the electron or the positron include the energy associated with the angular momentum that is intrinsic to those particles? One possible answer is that the energy associated with angular momentum is not convertible to mass, at least in the 3-D space we know, but is coupled to epos and their mass energy in the Dirac sea of particles with negative energy. I do not have a good answer for the conversion of angular momentum to linear momentum involving the Dirac sea. I believe Dirac only assumed conservation of energy. D. L. Hotson provided some explaination of the Dirac sea and its realtion to the spin of the electron and positron in an interesting paper that can be obtained at the following link: http://www.google.com/url?sa=trct=jq=esrc=ssource=webcd=4ved=0CDUQFjADurl=http%3A%2F%2Fopenseti.org%2FDocs%2FHotsonPart1.pdfei=W_lzVIS_KoT3oATC_IGABAusg=AFQjCNEGpOAW06Y1ny75ZQHr58i_WIOasAbvm=bv.80185997,d.cGU Check page 12 of this paper for the a possible answer regarding the conversion of energy associated with angular momentur of the electron and positron. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Monday, November 24, 2014 6:15 PM Subject: Re: [Vo]:They call me a moron. A reply. I suppose that if one can assume that mass can just vanish into somewhere without leaving a trace that it may be possible for a drive of this sort to operate. It is easy for the guy on the ship to detect that he is accelerating which takes a force and therefore energy from somewhere. That source could be onboard the ship in the form of a cold fusion reactor or something similar. With this in mind I believe that it becomes necessary to prove that the sink for this energy is indeed something like the Dirac sea. So far evidence for some sort of invisible sink is found in the form of a force that some researchers claim to measure when experimenting with reactionless drives. It is quite unfortunate that the magnitude of the forces thus far measured is so tiny. If it can be shown that a vehicle in open space can accelerate without any form of exhaust then I think the concept may be valid. Of course all of the energy must be obtained from within the vehicle and not due to outside influence. It remains a question as to whether or not mass can vanish in the manner suggested. Locate a spaceship that accelerates without exhaust and you make a strong case for some energy sink that can be pushed against although the Dirac sea may not be that sink. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 7:57 pm Subject: Re: [Vo]:They call me a moron. A reply. David-- In your going and coming trip: The spaceman uses energy by speeding up and slowing down in each
Re: [Vo]:They call me a moron. A reply.
In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
In reply to H Veeder's message of Fri, 21 Nov 2014 11:30:46 -0500: Hi Harry, I think there might be some nuclear/chemical effects at very close range, but that's just a guess. The range would be determined by the lifetime of the virtual particles. [snip] What I was wondering is if the reaction of the quantum vacuum has other observable effects besides the thrust. For example, the thrust generated by a standard engine results in an exhaust which can be seen to disturb other bodies nearby. If one can push against the quantum vacuum will this disturb other bodies as well? Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Dave I do not understand what you are talking about. But if consider the following, it might? Generate the same conundrum while not violating the conservation of momentum or energy. Take a spring, compress it. As the spring is allowed to decompress generates light (by either friction, or electromagnetic induction to an efficient form of lighting. The light is projected in one direction, providing a small but real thrust. This would have propulsion with unchanging mass (other forms of energy storage could be used instead). Does this also generate the same 'problem' for you? On Mon, Nov 24, 2014 at 10:23 AM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Ok, just a thought... But if there are particles popping into (semi)existence for a moment... If it were full existence their annihilation would not be so eventless. Then could these particles be effected by magnetic and electric fields? Could they react as other materials do? Could they actually act as at least part of the electric and magnetic field carrying capacity of the vacuum? (the permittivity and permeability of free space). I am unsure what interesting implications come from this line of reasoning, but I bet there are some. John On Mon, Nov 24, 2014 at 11:34 AM, Axil Axil janap...@gmail.com wrote: No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
If the created particles were mesons, these particles would decay into electrons and neutrinos. I suspect that an experiment can be prepared to detect those electrons. Also the mesons would effect the rate of nuclear decay of radioactive isotopes. On Sun, Nov 23, 2014 at 5:56 PM, John Berry berry.joh...@gmail.com wrote: Ok, just a thought... But if there are particles popping into (semi)existence for a moment... If it were full existence their annihilation would not be so eventless. Then could these particles be effected by magnetic and electric fields? Could they react as other materials do? Could they actually act as at least part of the electric and magnetic field carrying capacity of the vacuum? (the permittivity and permeability of free space). I am unsure what interesting implications come from this line of reasoning, but I bet there are some. John On Mon, Nov 24, 2014 at 11:34 AM, Axil Axil janap...@gmail.com wrote: No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Dave-- If the mass is converted into mass of virtual particles in the Dirac space, it is obvious that the man in the space ship would never see the results. The standard conversion of energy normally happens in a measurable 3-D space the space man knows. The other situation involves the Dirac space in addition to the standard 3-D space, but still conserves energy/mass, its just not observable yet. You must think outside the 3-D box. Engineers do this better than scientists. Note Bob Higgins recent comment attributed to a mentor of his. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Sunday, November 23, 2014 1:23 PM Subject: Re: [Vo]:They call me a moron. A reply. That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Wait, virtual particle don't decay though, they annihilate don't they? (I am unsure what the significant difference might be) And annihilation of virtual particles don't create any energy since there was none... But this makes me wonder, what about particles that there isn't an antimatter version of? I am not well versed on particle physics, but I can only think of the photon. Is there an anti-higgs? But while there isn't an anti-photon, photons do kinda cancel in an EMF sense, this can be seen whe one looks at the EMF around a receiving antenna, it creates an opposing EMF. But this reminds me of a thought I have often had, we assume that light absorbed (to our senses) is light somehow stopped, but could not not be seen as the superimposition of an opposite photon, both of which then carry on to the ends of the universe unimpeded as they interact with nothing as they equal zero? But still existing, just as the net zero magnetic flux around a torrid transformer can induce a voltage. Sure, this might not be able to make it's presence felt in the same way, but logically it would still exist as I guess information. John On Mon, Nov 24, 2014 at 12:01 PM, Axil Axil janap...@gmail.com wrote: If the created particles were mesons, these particles would decay into electrons and neutrinos. I suspect that an experiment can be prepared to detect those electrons. Also the mesons would effect the rate of nuclear decay of radioactive isotopes. On Sun, Nov 23, 2014 at 5:56 PM, John Berry berry.joh...@gmail.com wrote: Ok, just a thought... But if there are particles popping into (semi)existence for a moment... If it were full existence their annihilation would not be so eventless. Then could these particles be effected by magnetic and electric fields? Could they react as other materials do? Could they actually act as at least part of the electric and magnetic field carrying capacity of the vacuum? (the permittivity and permeability of free space). I am unsure what interesting implications come from this line of reasoning, but I bet there are some. John On Mon, Nov 24, 2014 at 11:34 AM, Axil Axil janap...@gmail.com wrote: No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways.
Re: [Vo]:They call me a moron. A reply.
No problem with that concept John. Pressing the spring initially adds the energy that is latter released. Notice that the light energy carries mass which of course has momentum. The momentum that is imparted upon the ship is matched by that of the light. That is a normal propulsion system. A reactionless system would have the ship with the spring begin to move in some direction without any type of ejection mass. That is my objection. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:27 pm Subject: Re: [Vo]:They call me a moron. A reply. Dave I do not understand what you are talking about. But if consider the following, it might? Generate the same conundrum while not violating the conservation of momentum or energy. Take a spring, compress it. As the spring is allowed to decompress generates light (by either friction, or electromagnetic induction to an efficient form of lighting. The light is projected in one direction, providing a small but real thrust. This would have propulsion with unchanging mass (other forms of energy storage could be used instead). Does this also generate the same 'problem' for you? On Mon, Nov 24, 2014 at 10:23 AM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Yes, and the faster the ship moves the lower frequency an observer in the initial frame will see the exhaust. I have no problem as I said in understanding how this conserves momentum and energy. But I have no idea what you were talking about with relative mass changes etc... On Mon, Nov 24, 2014 at 4:25 PM, David Roberson dlrober...@aol.com wrote: No problem with that concept John. Pressing the spring initially adds the energy that is latter released. Notice that the light energy carries mass which of course has momentum. The momentum that is imparted upon the ship is matched by that of the light. That is a normal propulsion system. A reactionless system would have the ship with the spring begin to move in some direction without any type of ejection mass. That is my objection. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:27 pm Subject: Re: [Vo]:They call me a moron. A reply. Dave I do not understand what you are talking about. But if consider the following, it might? Generate the same conundrum while not violating the conservation of momentum or energy. Take a spring, compress it. As the spring is allowed to decompress generates light (by either friction, or electromagnetic induction to an efficient form of lighting. The light is projected in one direction, providing a small but real thrust. This would have propulsion with unchanging mass (other forms of energy storage could be used instead). Does this also generate the same 'problem' for you? On Mon, Nov 24, 2014 at 10:23 AM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
Yes Axil. The drive would then qualify as a standard one and the problem dissolves. This does not appear to what the proponents of a reactionless drive believe is occurring from what I have determined. They suggest that there is nothing available to carry away the balancing momentum. Why call it a reactionless drive if exhaust can be measured? Dave -Original Message- From: Axil Axil janap...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:41 pm Subject: Re: [Vo]:They call me a moron. A reply. No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
If the particles appear and then annihilate each other so that nothing is left then they would not carry away any momentum or energy. Normal drives require that an amount of momentum that equals that which is imparted into the ship be ejected in an opposite direction. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:56 pm Subject: Re: [Vo]:They call me a moron. A reply. Ok, just a thought... But if there are particles popping into (semi)existence for a moment... If it were full existence their annihilation would not be so eventless. Then could these particles be effected by magnetic and electric fields? Could they react as other materials do? Could they actually act as at least part of the electric and magnetic field carrying capacity of the vacuum? (the permittivity and permeability of free space). I am unsure what interesting implications come from this line of reasoning, but I bet there are some. John On Mon, Nov 24, 2014 at 11:34 AM, Axil Axil janap...@gmail.com wrote: No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
OK Bob, I tend to think outside of the box quite often, but sometimes that does not get me to where I would like to go. I would love to find that a reactionless drive is possible, but so far the evidence is strongly against that concept. You must become the spaceman inside his ship in order to see where the problem exists. If the mass and energy leaving the ship is not visible or measurable by the guy then he will become quite upset to see his ship vaporizing into nothing as the drive operates. As far as he can determine his ship is at rest in space once the drive is shut down. He can then take an inventory of the mass of his machine and wonders where most of it went, particularly if a large amount of it is converted into energy used to power the drive. With a normal drive every morsel of the original mass and energy can be located. Actually, I believe that the center of mass of the original ship remains in the same location and has the same magnitude after the normal drive is activated. The same is not true for a reactionless drive. Each external observer will determine that the center of mass of a normal ship remains at a constant location. This is true regardless of the final velocity of the ship relative to those guys. This is certainly true for very slow moving ships such as we would measure under non relativistic situations being presently discussed. The conservation of momentum ensures that this occurs. I encourage anyone out there with knowledge about how to overcome the obvious problems to offer their input. Start by explaining how the spaceman could accept the change in mass of his ship without any measurable emissions into space remembering that velocity is entirely relative. In this case I am playing the part of the skeptic but will make every effort to prove myself wrong. I honestly want to be wrong about this type of system. Dave -Original Message- From: Bob Cook frobertc...@hotmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 6:38 pm Subject: Re: [Vo]:They call me a moron. A reply. Dave-- If the mass is converted into mass of virtual particles in the Dirac space, it is obvious that the man in the space ship would never see the results. The standard conversion of energy normally happens in a measurable 3-D space the space man knows. The other situation involves the Dirac space in addition to the standard 3-D space, but still conserves energy/mass, its just not observable yet. You must think outside the 3-D box. Engineers do this better than scientists. Note Bob Higgins recent comment attributed to a mentor of his. Bob - Original Message - From: David Roberson To: vortex-l@eskimo.com Sent: Sunday, November 23, 2014 1:23 PM Subject: Re: [Vo]:They call me a moron. A reply. That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l
Re: [Vo]:They call me a moron. A reply.
There is no such think as a reactionless drive. Particles must be being produced in the vacuum by EMF. On Sun, Nov 23, 2014 at 10:40 PM, David Roberson dlrober...@aol.com wrote: Yes Axil. The drive would then qualify as a standard one and the problem dissolves. This does not appear to what the proponents of a reactionless drive believe is occurring from what I have determined. They suggest that there is nothing available to carry away the balancing momentum. Why call it a reactionless drive if exhaust can be measured? Dave -Original Message- From: Axil Axil janap...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:41 pm Subject: Re: [Vo]:They call me a moron. A reply. No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
I am sorry that my thoughts are not being clearly put into writing. Perhaps as the subject is further discussed you can determine exactly what I am thinking and accept or reject my ideas. My tendency is to choose an observation frame that simplifies the understanding of a problem. In this particular case that frame appears to be attached to the ship undergoing acceleration due to the drive. Measurements by the guy onboard strongly reject the consequences that result from the use of a reactionless drive. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 10:30 pm Subject: Re: [Vo]:They call me a moron. A reply. Yes, and the faster the ship moves the lower frequency an observer in the initial frame will see the exhaust. I have no problem as I said in understanding how this conserves momentum and energy. But I have no idea what you were talking about with relative mass changes etc... On Mon, Nov 24, 2014 at 4:25 PM, David Roberson dlrober...@aol.com wrote: No problem with that concept John. Pressing the spring initially adds the energy that is latter released. Notice that the light energy carries mass which of course has momentum. The momentum that is imparted upon the ship is matched by that of the light. That is a normal propulsion system. A reactionless system would have the ship with the spring begin to move in some direction without any type of ejection mass. That is my objection. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:27 pm Subject: Re: [Vo]:They call me a moron. A reply. Dave I do not understand what you are talking about. But if consider the following, it might? Generate the same conundrum while not violating the conservation of momentum or energy. Take a spring, compress it. As the spring is allowed to decompress generates light (by either friction, or electromagnetic induction to an efficient form of lighting. The light is projected in one direction, providing a small but real thrust. This would have propulsion with unchanging mass (other forms of energy storage could be used instead). Does this also generate the same 'problem' for you? On Mon, Nov 24, 2014 at 10:23 AM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every
Re: [Vo]:They call me a moron. A reply.
On Sun, Nov 23, 2014 at 8:26 PM, David Roberson dlrober...@aol.com wrote: I encourage anyone out there with knowledge about how to overcome the obvious problems to offer their input. One thought here -- the reactionless drive that I am aware of being in the recent news is the EmDrive. That one involves the generation of microwaves and their reflection in a cavity. It's not clear whether anyone other than Nasa and the inventor believe that it works as advertised. But if it does, note that energy must be expended to generate the microwaves, e.g., by a battery, to which the usual E=mc^2 conversion will apply. Eric
Re: [Vo]:They call me a moron. A reply.
I agree Axil. And those particles that are produced are then given the momentum required to balance out that obtained by the ship. Also, they must remain in existence as real particles and not disappear after a brief time interval. The folks who speak of reactionless drives claim that their are no measurable particles remaining to locate after the momentum is imparted into the ship. That is where I can not agree. Dave -Original Message- From: Axil Axil janap...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 11:39 pm Subject: Re: [Vo]:They call me a moron. A reply. There is no such think as a reactionless drive. Particles must be being produced in the vacuum by EMF. On Sun, Nov 23, 2014 at 10:40 PM, David Roberson dlrober...@aol.com wrote: Yes Axil. The drive would then qualify as a standard one and the problem dissolves. This does not appear to what the proponents of a reactionless drive believe is occurring from what I have determined. They suggest that there is nothing available to carry away the balancing momentum. Why call it a reactionless drive if exhaust can be measured? Dave -Original Message- From: Axil Axil janap...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 5:41 pm Subject: Re: [Vo]:They call me a moron. A reply. No one knows what is going on in the vacuum. If real particles are being produced by EMF in the vacuum, then the drive is not reactionless. On Sun, Nov 23, 2014 at 4:23 PM, David Roberson dlrober...@aol.com wrote: That is the point Robin. In the case of a car you can find where all of the original mass is located after the car accelerates to a new velocity. It might not be easy, but it can be done. The reactionless drive spaceship can not find the lost mass that is assumed to be converted into energy to generate thrust. A person onboard the ship will only see that the mass of his ship is depleted since his velocity is constant after the drive is cut off as far as he knows. Of course he will feel the acceleration as the drive is powered, but he has no way to determine his velocity relative to the universe before or after that occurs. Velocity is relative to the observer. If we take this process to the extreme, lets assume that 90% of the mass of the original ship is consumed by the energy required to operate the reactionless drive. Once the drive is shut down the spaceman begins to drift in space. As far as he can observe, he is sitting still in space and has no kinetic energy. But where did all that original mass end up? It just vanished, which makes no sense. With a normal ship that relies upon the conservation of momentum all of the mass that has been ejected can be located. Whether in the form of electromagnetic waves or raw mass that was ejected, the total will be the same as before the drive is activated. This makes complete sense and is what has been demonstrated so far in real life. In the first case mass has been lost without anything to show for its existence. In the second one, nothing is missing and everything adds up as expected. I find it very difficult to believe that both situations are possible. How would you explain to the spaceman on the ship powered by a reactionless drive where most of the mass of his ship is now located? Have atoms of fuel actually disappeared? Even if some form of nuclear reaction is used to power the drive he can not locate the energy generated by the nuclear process. Dave -Original Message- From: mixent mix...@bigpond.com To: vortex-l vortex-l@eskimo.com Sent: Sun, Nov 23, 2014 3:26 pm Subject: Re: [Vo]:They call me a moron. A reply. In reply to David Roberson's message of Fri, 21 Nov 2014 23:25:41 -0500: Hi, [snip] My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. It's just the same as a car on a road. You know that some of the energy in the fuel ends up as kinetic energy of the car, and this doesn't surprise you at all. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
Re: [Vo]:They call me a moron. A reply.
The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The problem is that this energy can be depleted without having anything to show for its loss. If taken to the extreme most of the ship can be converted into energy by some nuclear process to supply power for the drive mechanism. After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. He will not have any kinetic energy relative to himself. He sees that his ships mass has depleted but has nothing to show where it went. With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:02 am Subject: Re: [Vo]:They call me a moron. A reply. On Sun, Nov 23, 2014 at 8:26 PM, David Roberson dlrober...@aol.com wrote: I encourage anyone out there with knowledge about how to overcome the obvious problems to offer their input. One thought here -- the reactionless drive that I am aware of being in the recent news is the EmDrive. That one involves the generation of microwaves and their reflection in a cavity. It's not clear whether anyone other than Nasa and the inventor believe that it works as advertised. But if it does, note that energy must be expended to generate the microwaves, e.g., by a battery, to which the usual E=mc^2 conversion will apply. Eric
Re: [Vo]:They call me a moron. A reply.
On Sun, Nov 23, 2014 at 9:21 PM, David Roberson dlrober...@aol.com wrote: With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. If the guy with the spaceship with the EmDrive could bend the laws of physics for a moment and arrange for tracer photons, perhaps he could see microwave photons exiting the cavity of the drive in the opposite direction, accounting for the anomalous thrust. (Perhaps I'm missing your point.) Eric
Re: [Vo]:They call me a moron. A reply.
First off I believe that Newtons laws break down with regular engineering, there are multiple mechanical devices that do genuinely appear to create a net thrust. However these can not be proven from conjecture, they must be accurately replicated to maybe prove they work, and disproof may barely be possible due to subtle factors being potentially at work. Nevertheless, here is a reaction-less thruster that is capable of being mathematically proven or disproven. Take 2 identical flywheels spinning in opposite directions, these are rotating so far so as to have a useful increase in relativistic mass. Throw it from the front of your spaceship to the back, as it is moving to the rear of the ship they stop rotating, store the energy and now once they are not rotating they compress a spring at the other end of the ship. Because the relativistic mass is less when they are being stopped, you can gain net momentum, additionally you can move then back to the front of the ship and one there spin them up again and throw them aft repeatedly. So if the relativistic mass increase is not considered real, then what is stopping us from accelerating mass beyond light speed if the resistance to acceleration is unchanged? Another idea based on the same concept, some forms of energy do not seem to contribute to rest mass, I doubt a compressed spring would have a different rest mass due to it's energy storage than the same spring uncompressed. So if we can store energy in a way that has no mass, then we can also then turn that energy into mass, for instance the particle products of a proton-proton collision can be much greater than the mass of the 2 protons. So if we can make and destroy (increase and decrease) rest mass at will then we can again move a weight that is heavier when we push off then when it comes to a stop. Neither of these seem close to practical, but are they flawed? On Mon, Nov 24, 2014 at 6:21 PM, David Roberson dlrober...@aol.com wrote: The fact that energy can be extracted from the battery to drive the microwave source is certainly possible. No one will ague against that point. The problem is that this energy can be depleted without having anything to show for its loss. If taken to the extreme most of the ship can be converted into energy by some nuclear process to supply power for the drive mechanism. After the drive is shut down the ship stops accelerating and comes to rest in space. Even though the new velocity is different than the old one before the drive operates, a guy onboard the ship can not determine that he is moving. He will not have any kinetic energy relative to himself. He sees that his ships mass has depleted but has nothing to show where it went. With a normal drive the guy can see the exhaust that is moving relative to him which contains all of the converted energy. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Mon, Nov 24, 2014 12:02 am Subject: Re: [Vo]:They call me a moron. A reply. On Sun, Nov 23, 2014 at 8:26 PM, David Roberson dlrober...@aol.com wrote: I encourage anyone out there with knowledge about how to overcome the obvious problems to offer their input. One thought here -- the reactionless drive that I am aware of being in the recent news is the EmDrive. That one involves the generation of microwaves and their reflection in a cavity. It's not clear whether anyone other than Nasa and the inventor believe that it works as advertised. But if it does, note that energy must be expended to generate the microwaves, e.g., by a battery, to which the usual E=mc^2 conversion will apply. Eric
Re: [Vo]:They call me a moron. A reply.
On Thu, Nov 20, 2014 at 10:27 AM, H Veeder hveeder...@gmail.com wrote: At least the Church never questioned Galileo's intelligence. Heretic yes. Moron no. Harry ***Sure they did. From Wikipedia: In 1616, an Inquisitorial commission unanimously declared heliocentrism to be foolish and absurd in philosophy, http://en.wikipedia.org/wiki/Galileo_Galilei
Re: [Vo]:They call me a moron. A reply.
On Fri, Nov 21, 2014 at 3:55 AM, Kevin O'Malley kevmol...@gmail.com wrote: On Thu, Nov 20, 2014 at 10:27 AM, H Veeder hveeder...@gmail.com wrote: At least the Church never questioned Galileo's intelligence. Heretic yes. Moron no. Harry ***Sure they did. From Wikipedia: In 1616, an Inquisitorial commission unanimously declared heliocentrism to be foolish and absurd in philosophy, http://en.wikipedia.org/wiki/Galileo_Galilei I guess it depends on what one means by moron. Harry
Re: [Vo]:They call me a moron. A reply.
On Thu, Nov 20, 2014 at 4:18 PM, mix...@bigpond.com wrote: In reply to H Veeder's message of Thu, 20 Nov 2014 13:27:00 -0500: Hi, [snip] ?Newton's laws of motion are effectively violated unless the reaction of these virtual particles can be observed in another way. ...it just means you are pushing against the mass of the universe. Effectively, all the energy absorbed is returned as kinetic energy of the craft. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html What I was wondering is if the reaction of the quantum vacuum has other observable effects besides the thrust. For example, the thrust generated by a standard engine results in an exhaust which can be seen to disturb other bodies nearby. If one can push against the quantum vacuum will this disturb other bodies as well? Harry
Re: [Vo]:They call me a moron. A reply.
It seems to me that the reactionless type of drive does seem to violate common sense. By this statement I mean that if we assume that internal energy is converted into kinetic energy by using the drive then the mass of the spaceship would appear to be different according to different observers. For example, an observer at rest with the ship before it activates the drive will measure a certain value of mass. If we assume that this observer watches the ship speed up relative to him without emitting exhaust he comes to the conclusion that energy has appeared out of nowhere and is imparted to the ship. A second observer who is at rest with the ship after the drive is enacted will wonder why its mass has decreased. The energy associated with this mass loss seems to vanish into thin air. This system leads one to conclude that the conservation of momentum as well as conservation of energy and mass becomes violated. If you think of this behavior as effecting individual atoms, how and why would it be appropriate to obtain different values for this parameter? This problem appears to eliminate the real likelihood of reactionless drives. Dave -Original Message- From: H Veeder hveeder...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Fri, Nov 21, 2014 11:31 am Subject: Re: [Vo]:They call me a moron. A reply. On Thu, Nov 20, 2014 at 4:18 PM, mix...@bigpond.com wrote: In reply to H Veeder's message of Thu, 20 Nov 2014 13:27:00 -0500: Hi, [snip] ?Newton's laws of motion are effectively violated unless the reaction of these virtual particles can be observed in another way. ...it just means you are pushing against the mass of the universe. Effectively, all the energy absorbed is returned as kinetic energy of the craft. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html What I was wondering is if the reaction of the quantum vacuum has other observable effects besides the thrust. For example, the thrust generated by a standard engine results in an exhaust which can be seen to disturb other bodies nearby. If one can push against the quantum vacuum will this disturb other bodies as well? Harry
Re: [Vo]:They call me a moron. A reply.
Dave, I disagree but I like that you utilize the local observer becoming the remote observer because I think Shawyer's claim of a relativistic component is correct. Think SR, time dilation and Lorentzian contraction via vacuum engineering instead of near C velocity. Even if the modification is only slight this device is building a warp or well that allows us to exchange spatial and temporal coordinates such that we can unbalance the normal law of equal and opposite reaction. Accumulated over time in free space this would make a reactionless drive. Spontaneous emission is known to be modified by microwave cavities and I think this is may be the principle that he is optimizing via geometry and microwaves. Think about the Pythagorean relationship between time and space experienced by the Paradox twins, the near C twin is contracted in the direction of travel from the stationary twins perspective and is time dilated BUT everything appears normal to each twin in their own local frame.. each twin perceives normal time and space locally but the quadrants are shifted from each other. If Shawers is modifying inertial frames without spatial displacement [what Puthoff calls vacuum engineering] then you can have dilation, contraction and the opportunity to establish linkage between different frames because they can be stationary to each other spatially..something that IMHO is the reason for the odd spectrum of light for which Mills named his company as SPP translates wavelengths between scales. If shawyer can establish linkage between different inertial frames than he should be able to exchange time for motion. He is using microwaves but extending this theory to Rossi and Mills I am suggesting that the hydrogen that is most suppressed by Casimir geometry {DCE} is the most contracted and dialted and just like the twin Paradox is experiencing time and space in different quadrants from the hydrogen outside the cavity which exists at a very consistent vacuum pressure we refer to as the isotropy. If force can be exerted on these dilated hydrogen from a different inertial frame it will unbalance the spatial forces in both frames because of the Lorentzian translations. Fran From: David Roberson [mailto:dlrober...@aol.com] Sent: Friday, November 21, 2014 4:04 PM To: vortex-l@eskimo.com Subject: EXTERNAL: Re: [Vo]:They call me a moron. A reply. It seems to me that the reactionless type of drive does seem to violate common sense. By this statement I mean that if we assume that internal energy is converted into kinetic energy by using the drive then the mass of the spaceship would appear to be different according to different observers. For example, an observer at rest with the ship before it activates the drive will measure a certain value of mass. If we assume that this observer watches the ship speed up relative to him without emitting exhaust he comes to the conclusion that energy has appeared out of nowhere and is imparted to the ship. A second observer who is at rest with the ship after the drive is enacted will wonder why its mass has decreased. The energy associated with this mass loss seems to vanish into thin air. This system leads one to conclude that the conservation of momentum as well as conservation of energy and mass becomes violated. If you think of this behavior as effecting individual atoms, how and why would it be appropriate to obtain different values for this parameter? This problem appears to eliminate the real likelihood of reactionless drives. Dave -Original Message- From: H Veeder hveeder...@gmail.commailto:hveeder...@gmail.com To: vortex-l vortex-l@eskimo.commailto:vortex-l@eskimo.com Sent: Fri, Nov 21, 2014 11:31 am Subject: Re: [Vo]:They call me a moron. A reply. On Thu, Nov 20, 2014 at 4:18 PM, mix...@bigpond.commailto:mix...@bigpond.com wrote: In reply to H Veeder's message of Thu, 20 Nov 2014 13:27:00 -0500: Hi, [snip] ?Newton's laws of motion are effectively violated unless the reaction of these virtual particles can be observed in another way. ...it just means you are pushing against the mass of the universe. Effectively, all the energy absorbed is returned as kinetic energy of the craft. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html What I was wondering is if the reaction of the quantum vacuum has other observable effects besides the thrust. For example, the thrust generated by a standard engine results in an exhaust which can be seen to disturb other bodies nearby. If one can push against the quantum vacuum will this disturb other bodies as well? Harry
Re: [Vo]:They call me a moron. A reply.
Fran, it is OK to disagree with me and I have been wrong more than enough times to justify your feelings. There may well be some process such as you are considering and hopefully one day it will be brought into the light. My consideration of reactionless drives is based upon the observation that the mass of atoms, molecules, and all other forms of matter remain a constant to the local observer at least. I include the mass that can be attributed to energy which is either emitted by some action of the matter or absorbed in other ways. So far, every attempt that I have made to calculate or measure this combination yields the same result. As you know, the total mass-energy would have to change if the system were to be subject to a reactionless drive. If somehow it is found to be possible to make a drive of this nature without having to expend energy then at least the local observer might be satisfied. The remote observers, which would include everyone moving at a different speed relative to the spaceship would each determine a different answer for the net energy expended. If the system follows the conservation of momentum and conservation of mass-energy then all of the various observers would reach the same conclusion. This is a powerful suggestion that those two laws apply. Picture a spaceman onboard the ship that tallies the mass of his vehicle before and after activation of the reactionless drive. If net energy were required in order to change the velocity of the ship then he will find that his machine has lost mass. This would be sufficient reason to be concerned since eventually his ship can loose most of the mass and have nothing to show for the energy that it once contained. The guy in the normal ship readily calculates that his lost mass has been ejected mainly out the rear of the device and still exists in a manner that can be accounted for. Dave -Original Message- From: Roarty, Francis X francis.x.roa...@lmco.com To: vortex-l vortex-l@eskimo.com Sent: Fri, Nov 21, 2014 5:01 pm Subject: Re: [Vo]:They call me a moron. A reply. Dave, I disagree but I like that you utilize the local observer becoming the remote observer because I think Shawyer’s claim of a relativistic component is correct. Think SR, time dilation and Lorentzian contraction via vacuum engineering instead of near C velocity. Even if the modification is only slight this device is building a warp or well that allows us to exchange spatial and temporal coordinates such that we can unbalance the normal law of equal and opposite reaction. Accumulated over time in free space this would make a reactionless drive. Spontaneous emission is known to be modified by microwave cavities and I think this is may be the principle that he is optimizing via geometry and microwaves. Think about the Pythagorean relationship between time and space experienced by the Paradox twins, the near C twin is contracted in the direction of travel from the stationary twins perspective and is time dilated BUT everything appears normal to each twin in their own local frame.. each twin perceives normal time and space locally but the quadrants are shifted from each other. If Shawers is modifying inertial frames without spatial displacement [what Puthoff calls vacuum engineering] then you can have dilation, contraction and the opportunity to establish linkage between different frames because they can be stationary to each other spatially..something that IMHO is the reason for the odd spectrum of light for which Mills named his company as SPP translates wavelengths between scales. If shawyer can establish linkage between different inertial frames than he should be able to exchange time for motion. He is using microwaves but extending this theory to Rossi and Mills I am suggesting that the hydrogen that is most suppressed by Casimir geometry {DCE} is the most contracted and dialted and just like the twin Paradox is experiencing time and space in different quadrants from the hydrogen outside the cavity which exists at a very consistent vacuum pressure we refer to as the isotropy. If force can be exerted on these dilated hydrogen from a different inertial frame it will unbalance the spatial forces in both frames because of the Lorentzian translations. Fran From: David Roberson [mailto:dlrober...@aol.com] Sent: Friday, November 21, 2014 4:04 PM To: vortex-l@eskimo.com Subject: EXTERNAL: Re: [Vo]:They call me a moron. A reply. It seems to me that the reactionless type of drive does seem to violate common sense. By this statement I mean that if we assume that internal energy is converted into kinetic energy by using the drive then the mass of the spaceship would appear to be different according to different observers. For example, an observer at rest with the ship before it activates the drive will measure a certain value of mass. If we assume that this observer watches the ship
Re: [Vo]:They call me a moron. A reply.
Another example is the reactionless engine that NASA has just tested that supposedly violates Newton's Laws of Motion. Sorry for being picky, but they haven't tested a reactionless engine. They have measured anomalous thrust in a test pendulum setup. http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/20140009930.pdf .s Date: Wed, 19 Nov 2014 15:53:07 -0500 From: janap...@gmail.com To: vortex-l@eskimo.com Subject: [Vo]:They call me a moron. A reply. Many, if not most, of the LENR detractors/skeptics base their viewpoint on a position that LENR can’t work because it contradicts the laws of physics. The heart of the matter lies in engineering. A good engineer will use the optimum physical principle to get the job done. As a example, a Wakefield accelerator that is just a few feet in length uses a different set of physical laws to do what the CERN 17 mile diameter accelerator does. A scientist who specialized in nuclear physics may not understand what laws to apply to get his job done in a more optimized way. That does not make the physical principles applied in the optimized solution invalid. It just means that the engineers of the optimized solution have amazed the scientist to such a huge extent that the scientist is baffled into disbelief when he sees the results of the engineering. Another example is the reactionless engine that NASA has just tested that supposedly violates Newton's Laws of Motion. It turns out that the EMF field used in the engine pushes against the virtual particles in the vacuum. This does not make the test that NASA conducted of that engine a SCAM or the engineers who understand what is going on morons.
Re: [Vo]:They call me a moron. A reply.
I agree that it is just anomalous measurement letting fear/hope reactionless engine. the problem is that most skeptics don't simply ast for REPLICATE IT MORE TO PROVE IT BAD but DONT WASTE MONEY REPLICATING... they als claim it is a student error ignoring all de things that have been checked, and the intriguing sensibility to microwave resonance. what I see most of the time is the total absence of true skeptics. there are believers, confident in one paper, or wisshful. there are deniers afraid to have laws broken, who insut any success ful author there are cautious optimistics who are intrigued, hopeful, but ready to be decieved. No aggressive skeptic have considered the microwave resonance effect and proposed anything... this is what I camm cargo cult skepticism. It remind me the inverted clamp... there is a huge problem with lugano that McKubre have spotted, bad calibration, but that one have to consider numerically... what is the error of emissivity required, and what is the real temperature if COP=1 in lugano test... nobody answered. I tried but I suspect I'm wrong, because I don't know exactly how is computed the IR cam estimated temperature at a given emissivity claim. NB: if someone can give me the method I can revert the equation. 2014-11-20 10:20 GMT+01:00 Sunil Shah s.u.n@hotmail.com: Another example is the reactionless engine that NASA has just tested that supposedly violates Newton's Laws of Motion. Sorry for being picky, but they haven't tested a reactionless engine. They have measured anomalous thrust in a test pendulum setup. http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/20140009930.pdf .s -- Date: Wed, 19 Nov 2014 15:53:07 -0500 From: janap...@gmail.com To: vortex-l@eskimo.com Subject: [Vo]:They call me a moron. A reply. Many, if not most, of the LENR detractors/skeptics base their viewpoint on a position that LENR can’t work because it contradicts the laws of physics. The heart of the matter lies in engineering. A good engineer will use the optimum physical principle to get the job done. As a example, a Wakefield accelerator that is just a few feet in length uses a different set of physical laws to do what the CERN 17 mile diameter accelerator does. A scientist who specialized in nuclear physics may not understand what laws to apply to get his job done in a more optimized way. That does not make the physical principles applied in the optimized solution invalid. It just means that the engineers of the optimized solution have amazed the scientist to such a huge extent that the scientist is baffled into disbelief when he sees the results of the engineering. Another example is the reactionless engine that NASA has just tested that supposedly violates Newton's Laws of Motion. It turns out that the EMF field used in the engine pushes against the virtual particles in the vacuum. This does not make the test that NASA conducted of that engine a SCAM or the engineers who understand what is going on morons.
Re: [Vo]:They call me a moron. A reply.
From: Alain Sepeda alain.sep...@gmail.com Sent: Thursday, November 20, 2014 6:59:56 AM there is a huge problem with lugano that McKubre have spotted, bad calibration, but that one have to consider numerically... what is the error of emissivity required, and what is the real temperature if COP=1 in lugano test... nobody answered. I tried but I suspect I'm wrong, because I don't know exactly how is computed the IR cam estimated temperature at a given emissivity claim. NB: if someone can give me the method I can revert the equation. - - - - The basic equations are in my report http://lenr.qumbu.com/blackbody_141105A.php I started looking into the sensitivity to emissivity (and even wrote an IR camera simulator), but didn't finish it. The calculated power from Stefan-Boltzmann (equal to Planck if emmisivity is constant with wavelength) is P = c1 * em * T^4 ...(1) But the camera itself measures the power it's receiving, P_measured, and derives T from that, the emmissivity, and internal constants. I don't have my notes at hand, so lets just say that T = function(emmissivity,measured_power) ...(2) At worst the estimated T will be proportional to em -- if so, putting this into (1) gives P = c1 * em * em^4 * P_measured ...(3) --- ie proportional to em^5 (But it might be em^3 or even better ... so don't quote this ) I didn't run the error margins, but my impression was that it would still yield COP1 even in the worst plausible scenario. I probably won't have time to get back to this for a couple of weeks.
Re: [Vo]:They call me a moron. A reply.
When the thing being measured has been designed to be a reactionless thrust producing engine, then yes that is what they have been testing. I guess you could say a proposed experimental reactionless engine. But since that is the intention and goal of the device measured to have apparently produced an reationless thrust so as to be used as an engine in space flight, then that is what it is. On Thu, Nov 20, 2014 at 10:20 PM, Sunil Shah s.u.n@hotmail.com wrote: Another example is the reactionless engine that NASA has just tested that supposedly violates Newton's Laws of Motion. Sorry for being picky, but they haven't tested a reactionless engine. They have measured anomalous thrust in a test pendulum setup. http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/20140009930.pdf .s -- Date: Wed, 19 Nov 2014 15:53:07 -0500 From: janap...@gmail.com To: vortex-l@eskimo.com Subject: [Vo]:They call me a moron. A reply. Many, if not most, of the LENR detractors/skeptics base their viewpoint on a position that LENR can’t work because it contradicts the laws of physics. The heart of the matter lies in engineering. A good engineer will use the optimum physical principle to get the job done. As a example, a Wakefield accelerator that is just a few feet in length uses a different set of physical laws to do what the CERN 17 mile diameter accelerator does. A scientist who specialized in nuclear physics may not understand what laws to apply to get his job done in a more optimized way. That does not make the physical principles applied in the optimized solution invalid. It just means that the engineers of the optimized solution have amazed the scientist to such a huge extent that the scientist is baffled into disbelief when he sees the results of the engineering. Another example is the reactionless engine that NASA has just tested that supposedly violates Newton's Laws of Motion. It turns out that the EMF field used in the engine pushes against the virtual particles in the vacuum. This does not make the test that NASA conducted of that engine a SCAM or the engineers who understand what is going on morons.
Re: [Vo]:They call me a moron. A reply.
Has anyone seen data from a test of one of these devices that is generated within a system that is totally isolated from outside power sources and connections? I suppose that will require a battery of some type. Also, it will gain much credibility if operated within a vacuum chamber which would eliminate any force due to interaction of air particles. We need a drive that operates without requiring any form of exhaust if we are to reach the stars one day. Dave -Original Message- From: John Berry berry.joh...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Thu, Nov 20, 2014 12:58 pm Subject: Re: [Vo]:They call me a moron. A reply. When the thing being measured has been designed to be a reactionless thrust producing engine, then yes that is what they have been testing. I guess you could say a proposed experimental reactionless engine. But since that is the intention and goal of the device measured to have apparently produced an reationless thrust so as to be used as an engine in space flight, then that is what it is. On Thu, Nov 20, 2014 at 10:20 PM, Sunil Shah s.u.n@hotmail.com wrote: Another example is the reactionless engine that NASA has just tested that supposedly violates Newton'sLaws of Motion. Sorry for being picky, but they haven't tested a reactionless engine. They have measured anomalous thrust in a test pendulum setup. http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/20140009930.pdf .s Date: Wed, 19 Nov 2014 15:53:07 -0500 From: janap...@gmail.com To: vortex-l@eskimo.com Subject: [Vo]:They call me a moron. A reply. Many, if not most, of the LENRdetractors/skeptics base their viewpoint on a position that LENRcan’t work because it contradicts the laws of physics. The heart ofthe matter lies in engineering. A good engineer will use the optimumphysical principle to get the job done. As a example, a Wakefieldaccelerator that is just a few feet in length uses a different set ofphysical laws to do what the CERN 17 mile diameter accelerator does.A scientist who specialized in nuclear physics may not understandwhat laws to apply to get his job done in a more optimized way. Thatdoes not make the physical principles applied in the optimizedsolution invalid. It just means that the engineers of the optimizedsolution have amazed the scientist to such a huge extent that thescientist is baffled into disbelief when he sees the results of theengineering. Another example is the reactionless engine that NASA has just tested that supposedly violates Newton'sLaws of Motion. It turns out that the EMF field used in the enginepushes against the virtual particles in the vacuum. This does not make the test thatNASA conducted of that engine a SCAM or the engineers who understandwhat is going on morons.
Re: [Vo]:They call me a moron. A reply.
On Wed, Nov 19, 2014 at 3:53 PM, Axil Axil janap...@gmail.com wrote: Many, if not most, of the LENR detractors/skeptics base their viewpoint on a position that LENR can’t work because it contradicts the laws of physics. The heart of the matter lies in engineering. A good engineer will use the optimum physical principle to get the job done. As a example, a Wakefield accelerator that is just a few feet in length uses a different set of physical laws to do what the CERN 17 mile diameter accelerator does. A scientist who specialized in nuclear physics may not understand what laws to apply to get his job done in a more optimized way. That does not make the physical principles applied in the optimized solution invalid. It just means that the engineers of the optimized solution have amazed the scientist to such a huge extent that the scientist is baffled into disbelief when he sees the results of the engineering. Another example is the reactionless engine that NASA has just tested that supposedly violates Newton's Laws of Motion. It turns out that the EMF field used in the engine pushes against the virtual particles in the vacuum. Newton's laws of motion are effectively violated unless the reaction of these virtual particles can be observed in another way. This does not make the test that NASA conducted of that engine a SCAM or the engineers who understand what is going on morons. At least the Church never questioned Galileo's intelligence. Heretic yes. Moron no. Harry
Re: [Vo]:They call me a moron. A reply.
In reply to H Veeder's message of Thu, 20 Nov 2014 13:27:00 -0500: Hi, [snip] ?Newton's laws of motion are effectively violated unless the reaction of these virtual particles can be observed in another way. ...it just means you are pushing against the mass of the universe. Effectively, all the energy absorbed is returned as kinetic energy of the craft. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html