RE: [PHP-DB] Corn job anomaly
> -Original Message- > From: Karl DeSaulniers [mailto:k...@designdrumm.com] > Sent: 25 September 2016 09:59 > To: PHP List Database > Subject: Re: [PHP-DB] Corn job anomaly > > Now I am getting an error with mysql syntax. > > "SELECT otn.*, cf.* FROM ".ORDER_TABLE." otn LEFT JOIN ".FIELDS_TABLE." cf > ON cf.Order_ID = otn.Order_ID WHERE cf.Earliest_Pickup >= DATE(NOW()) AND > cf.Earliest_Pickup <= DATE(NOW() + INTERVAL ".($Num_Days_Away+1)." DAY) AND > otn.Order_Status != 'Shipping' AND otn.Order_Status != 'Completed'" > > is giving me this error: > You have an error in your SQL syntax; check the manual that > corresponds to your MySQL server version for the right syntax to use near > '\"Shipping\" AND otn.Order_Status != \"Completed\"' at line 1 I don't think INTERVAL works like that - you probably need something like: ... cf.Earliest_Pickup <= DATE_ADD(CURDATE(), INTERVAL ".($Num_Days_Away+1)." DAY) AND ... Incidentally, as I understand it CURDATE() does exactly the same as DATE(NOW()), and is probably more readable. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, 110 Queen Square House, 80 Woodhouse Lane, Leeds Beckett University, Leeds LS2 8NU, United Kingdom E & S4B: m.f...@leedsbeckett.ac.uk T: +44 113 812 4730 To view the terms under which this email is distributed, please go to:- http://disclaimer.leedsbeckett.ac.uk/disclaimer/disclaimer.html -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: Formatting
> -Original Message- > From: Karl DeSaulniers [mailto:k...@designdrumm.com] > Sent: 26 November 2012 08:48 > To: php-db@lists.php.net > Subject: Re: [PHP-DB] Re: Formatting > > Ethan, > is this valid PHP? What is the ampersand for? What is it doing? Just > curious. > > $args[] = &$_POST[$k]; // Note the addition of the ampersand here That's a perfectly valid reference assignment. Please see the Fine Manual at: http://php.net/manual/language.references.whatdo.php Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Portland PD507, City Campus, Leeds Metropolitan University, Portland Way, LEEDS, LS1 3HE, United Kingdom E: m.f...@leedsmet.ac.uk T: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] SELECT
> -Original Message- > From: tamouse mailing lists [mailto:tamouse.li...@gmail.com] > Sent: 20 October 2011 21:37 > > On Tue, Oct 18, 2011 at 5:36 AM, Ford, Mike > wrote: > >> -Original Message- > >> From: Ron Piggott [mailto:ron.pigg...@actsministries.org] > >> Sent: 17 October 2011 18:38 > >> > >> What I am storing in the table is the start month # (1 to 12) and > >> day # (1 to 31) and then the finishing month # (1 to 12) and the > >> finishing day # (1 to 31) > >> > > > > This is a little bit of a tricky one, as you have to consider both > > start_month and end_month as special cases - so you need a three- > part > > conditional, for the start month, the end month, and the months in > > between. Something like this: > > > > SELECT * FROM `introduction_messages` > > WHERE (month>`start_month` AND month<`end_month`) > > OR (month=`start_month AND day>=`start_day`) > > OR (month=`end_month` AND day<=`end_day`); > > This still suffers from the problem in Jim's offer -- wrap of year > and > wrap of month Look again. Month wrap *is* handled by the specific tests for start_month and end_month. As to year-wrap, Ron's original post said: > >> ... The reason I didn’t use ‘DATE’ is because the same message > >> will be displayed year after year, depending on the date range. so I didn't bother about year-wrap, assuming he would include a range with start_date of 1/1 and another with end_date of 31/12. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Portland PD507, City Campus, Leeds Metropolitan University, Portland Way, LEEDS, LS1 3HE, United Kingdom E: m.f...@leedsmet.ac.uk T: +44 113 812 4730 But in the case of years actually mattering then, yes, the above would not work To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm
RE: [PHP-DB] SELECT
> -Original Message- > From: Ron Piggott [mailto:ron.pigg...@actsministries.org] > Sent: 17 October 2011 18:38 > > I need help creating a mySQL query that will select the correct > introduction message for a website I am making. The way I have > designed the table I can’t wrap my mind around the SELECT query that > will deal with the day # of the month. > > The part of the SELECT syntax I am struggling with is when the > introduction message is to change mid month. The reason I am > struggling with this is because I haven’t used ‘DATE’ for the column > type. The reason I didn’t use ‘DATE’ is because the same message > will be displayed year after year, depending on the date range. > > What I am storing in the table is the start month # (1 to 12) and > day # (1 to 31) and then the finishing month # (1 to 12) and the > finishing day # (1 to 31) > This is a little bit of a tricky one, as you have to consider both start_month and end_month as special cases - so you need a three-part conditional, for the start month, the end month, and the months in between. Something like this: SELECT * FROM `introduction_messages` WHERE (month>`start_month` AND month<`end_month`) OR (month=`start_month AND day>=`start_day`) OR (month=`end_month` AND day<=`end_day`); Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Portland PD507, City Campus, Leeds Metropolitan University, Portland Way, LEEDS, LS1 3HE, United Kingdom E: m.f...@leedsmet.ac.uk T: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm
RE: [PHP-DB] Re: Stuck in apostrophe hell
> -Original Message-
> From: Simcha Younger [mailto:sim...@syounger.com]
> Sent: 04 August 2010 08:19
>
> > paul_s_john...@mnb.uscourts.gov wrote:
>
> > >
> > > THE INPUT:
> > >
> > > $sql_insert_registration = sprintf("INSERT INTO
> > > Registrations (
> > > Class_ID,
> > > prid,
> > > Registrant,
> > > Company,
> > > Phone,
> > > Email
> > > )
> > > VALUES (
> > > $_POST[Class_ID],
> > > $_POST[prid],
> > > '%s',".
>
> You need double-quotes here,
> \"%s\",
No, he doesn't. Single quotes are fine. Doubles would more than likely be a SQL
error.
> > > parseNull($_POST['Company']).",
> > > '$_POST[Phone]',
> > > '$_POST[Email]'
> > > )", mysql_real_escape_string($_POST['Registrant']));
> > >
>
>
> --
> Simcha Younger
Cheers!
Mike
--
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Electronic Information Developer, Libraries and Learning Innovation,
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Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom
Email: m.f...@leedsmet.ac.uk
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RE: [PHP-DB] losing MySQL resource
> -Original Message- > From: Nehemias Duarte [mailto:ndua...@aflac.com] > Sent: 11 November 2009 14:25 > To: Stan; php-db@lists.php.net > Subject: RE: [PHP-DB] losing MySQL resource > > I was under the impression that session_start() had to be the FIRST > thing ran in the script. Is this incorrect? Yes. It has to be before any actual *output*, but it would be perfectly valid to have umpteen thousand lines of PHP before session_start() so long as all the output came after it. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Leeds Metropolitan University, C507, Civic Quarter Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] newbie: how to return one iteration *per unique date (DAY!)* in a timestamp column?
> -Original Message- > From: Govinda [mailto:govinda.webdnat...@gmail.com] > Sent: 05 August 2009 01:41 > > > Taking this: > > SELECT count(*) AS > > `CountUniqueDatesInMyTbl`, date(solarAWDateTime) AS `uniqueDate`, > > 'aweber_7solar_aw' AS `tableAlias` FROM aweber_7solar_aw GROUP BY > > DATE(solarAWDateTime) Just one other tiny point of style here: having given the expression date(solarAWDateTime) the alias uniqueDate, you should probably use that alias to refer to the same thing elsewhere in your query, such as in the GROUP BY column. So: SELECT count(*) AS `CountUniqueDatesInMyTbl`, date(solarAWDateTime) AS `uniqueDate`, 'aweber_7solar_aw' AS `tableAlias` FROM aweber_7solar_aw GROUP BY `uniqueDate`; That's how I'd write it, anyway. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Leeds Metropolitan University, C507, Civic Quarter Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Postgres query failing, not enough info for debugging...
On 16 June 2009 15:57, Carol Walter advised:
> Hello,
>
> I'm using PHP 5 and PostgreSQL 8.3.6. I have a query that is failing
> and I don't know how to troubleshoot the problem. The error message
> that it is giving is quite vague. The error message is as follows:
>
>
> Warning: pg_query_params() [function.pg-query-params]: Query failed:
> ERROR: syntax error at end of input at character 156 in /home/walterc/
> ssl/PHP/km_input_test2c.php on line 631
> ERROR: syntax error at end of input at character 156
>
> The query that is failing looks like this...
>
> $pg_pres_ins6 = pg_query_params("INSERT INTO \"brdgMediaCallsEvents
> \" (\"mediumId\", \"eventId\", rank) VALUES
> ((currval('\"tblMedia_mediumId_seq\"'),
> (currval('\"tblCallsEvents_eventId_seq\"'), $1)", array($ev_rank));
> echo pg_last_error($pg_connection);
You have 2 more opening parentheses than close parentheses in that SQL
-- in both cases, the parenthesis immediately preceding currval should
be omitted.
Also, to ameliorate your quote hell, you might consider using a heredoc
(http://php.net/manual/language.types.string.php#language.types.string.s
yntax.heredoc) for this:
$pg_pres_ins6 = pg_query_params(<
RE: [PHP-DB] Re: PHP and table/view names with '$'
On 23 April 2009 11:36, Mark Casson advised: > Hi Guys, > > Thanks to you both - you are spot on! > > Shame this is not better documented somewhere. I don't know how much better documented it can be than at http://php.net/language.types.string ... ;) Cheers! Mike -- Mike Ford, Electronic Information Developer, C507, Leeds Metropolitan University, Civic Quarter Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] variable with NULL value
On 03 May 2007 16:22, OKi98 wrote: > Hi, > > one more question. > > Why the variable, that contains NULL value appears to be not > set. U -- because that's how it's defined?? (http://php.net/isset) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, JG125, The Headingley Library, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 812 4730 Fax: +44 113 812 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm
RE: [PHP-DB] weird comparsion
On 03 May 2007 12:30, OKi98 wrote:
> I know about identity operator (===) but with == operator 0 is false
> and "foo" is true
No, that's not correct.
, try this:
>
> $foo=0;
> $bar="bar";
> if ($foo) echo("$foo is true, ");
> else echo("$foo is false, ");
> if ($bar) echo("$bar is true, ");
> else echo("$bar is false, ");
> if ($foo==$bar) echo("$foo==$bar");
>
> returns "0 is false, bar is true, 0==$bar"
That's because you've got loads of implicit type conversions going on there, so
you're not comparing like with like.
For if ($foo) ... and if ($bar) ...:
within the context of the if(), both $foo and $bar are implicitly converted to
Boolean:
- (bool)0 is FALSE
- (bool)"any non-empty() string" is TRUE
On the other hand, for if ($foo==$bar) ...:
in the context of the == comparison, $bar is converted to a number, and any
string not beginning with a numeric character converts to numeric zero -- so
you get a comparison of zero with zero, which is, of course, TRUE!
Or, in other words, (bool)$foo!==(bool)$bar, BUT (int)$foo===(int)$bar
It's exactly when you *don't* want this kind of automatic type-conversion
shenanigans going on that you should use the === operator to make your intent
entirely clear -- otherwise you have to be extremely aware of the context in
which you are evaluating your variables in order to avoid hidden surprises like
this.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
JG125, The Headingley Library,
James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] detecting negative numbers
On 17 July 2006 01:07, Dave W wrote: > No, I get it. I just thought that there might have been some built in > function like if(neg_num($quant - $amount)) > or something like that. I know how to do it, but I thought > that there might > have been an alternate method. Just because I asked a simple question > doesn't mean I'm stupid, I'm just curious if there is a > simpler way to do an > already simple task. The absolute simplest way to do this is what you originally had. I would not look further than if ($quant<$amount) // $quant-$amount is negative If I were reading your code, I would find both if(($quant-$amount)<0) and if(neg_num($quant-$amount)) more obfuscating than if($quant<$amount). Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHPSESSID how to append and access
On 25 May 2006 12:12, Girish Agarwal wrote:
> Hi All,
> I am using header("Location:
> http://dv-medical/phpscripts/test.php";) function to hop from
> one Page to
> Another in My Web Application
> My Problem is I have been unable to get the exact
> syntax to append
> the Session ID to the URL specified in the header so that it
> is available
header("Location: http://dv-medical/phpscripts/test.php?".SID)
That's what the SID constant is for. You can even use it with impunity when
cookies are in use, since it is set to the empty string in that case.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Displaying results from a query properly.
On 24 March 2006 16:40, Alex Major wrote:
> Thanks, works like a charm (had to make is -2 instead of -1
> as it added a
> space after each result). Hadn't thought of something so simple.
>
> On 24/3/06 16:22, "Bastien Koert" <[EMAIL PROTECTED]> wrote:
>
> > Build it up as a string and remove the trailing comma at the end of
> > the loop
> >
> > do { $sHTML .= ''.$administrators['username'].', ';}
> > while ($administrators = mysql_fetch_assoc($administrators_result))
> >
> > $sHTML = substr($sHTML, 0, strlen($sHTML)-1);
You don't need a strlen() call here, as substr understands "count from the
right" notation:
$sHTML = substr($sHTML, 0, -1);
... or, with Alex's correction:
$sHTML = substr($sHTML, 0, -2);
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Quick question
On 08 December 2005 20:53, Chris Payne wrote: > Hi there everyone, > > > > How do I set the following items with ini_set()? I looked at > the manual but > when I try nothing happens: > > > > * file_uploads > * upload_max_filesize > * max_input_time > * memory_limit > * max_execution_time > * post_max_size Apart from max_execution_time, the things affected by those settings all take place before your script even gains control -- so changing them in the script can never have any useful effect. To do any good, they must be set in an appropriate config file (php.ini, httpd.conf, .htaccess, etc.) as permitted. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] problem of transmiting variabl into another page?
On 02 December 2005 13:06, Bastien Koert wrote:
> echo "| href='alpha.php?artist=".chr($j)."'>".chr($j)." ";
>
> } ?>
>
> You need to use the ORD function to get the numerical ascii
> equivalent of the letter and the CHR function to go back the other
> way.
Gak! That's almost worse than the original!!
>
> Bastien
>
>
> > From: Mohamed Yusuf <[EMAIL PROTECTED]>
> > To: php-db@lists.php.net
> > Subject: [PHP-DB] problem of transmiting variabl into another page?
> > Date: Fri, 2 Dec 2005 12:30:12 +0200
> >
> > I am transmitting variable from one of my pages and I would like to
> > match that variable into mysql data. it won't return data.
> > my code is this.
> >
> > >echo "| $j |";
> >if ($j == Z) {
> > break;
> > }
> > } ?>
1. You have unquoted strings -- should be 'A' and 'Z'.
2. The test condition in your for is wrong (and either that or the break is
redundant).
Here's how I'd write it:
for ($j='A'; $j!='AA'; $j++):
echo "| $j |";
endfor;
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] timestamp
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm > -Original Message- > From: Balwant Singh [mailto:[EMAIL PROTECTED] > Sent: 01 February 2005 08:08 > > on echoing $timestamp i m getting "Fri Jan 28 19:53:09 2005" > but on echoing $date i m getting 1970-01-01. > also i m getting full info. by phpinfo() > > i m using php 4.2.2 , apache 2.0 and rad hat 9. The Change Log includes this line for version 4.3.3: "Fixed bug #13142 (strtotime not handling "M d H:i:s Y" format). (Ilia)" So I guess you need at least PHP 4.3.3 for this to work correctly for you. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] mysql - image storing
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 18 January 2005 17:11, Joseph Crawford wrote: > Jason, can you explain why stripslashes should not be used on data > taken from the db? when you store data in the db i thought it was good > practice to addslashes, when you retrieve from the db, you will need > to use stripslashes to remove the extra \ It's simple. Suppose you have a script that looks a bit like this (but hopefully with more input validation and error checking!): $value = addslashes($_POST['text']); // magic_quotes_gpc off $sql = "INSERT INTO tbl SET fld = '$value'"; database_execute($sql); Now suppose the user types this into the 'text' form field: Here's an apostrophe Here's what happens: PHP does this: $value is set to: Here\'s an apostrophe $sql becomes: INSERT INTO tbl SET fld = 'Here\'s an apostrophe' Which is sent to the database via database_execute() The DATABASE now does this: Receives the SQL statement: INSERT INTO tbl SET fld = 'Here\'s an apostrophe' (Note how the \ escape is required here to stop the field value from terminating prematurely -- but this escape is aimed at the *database*, and is not a PHP escape. A lot of confusion seems to arise here for databases which use the same \ escape character as PHP.) Extracts the value: Here\'s an apostrophe and de-escapes it to give:Here's an apostrophe Which gets inserted into the database. So the value inserted into the database is the unescaped original, and on retrieval there are no \ characters in the retrieved value to be stripslashes()ed. Hope that's clearer than mud, and helps you understand what's going on better. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] php latest release!
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 10 January 2005 09:28, JeRRy wrote: > With PHP latest release from http://php.net/ do we > require to update Zend Optimizer? Yes. > People are claiming some scripts previously that > worked in a previous version of PHP works and not with the new > version. There are several bug reports on bugs.php.net about this. Also see the red warning text on http://php.net/downloads.php > Why is it required to update Zend? Earlier versions are incompatible with PHP 4.3.10, and exhibit various incorrect behaviours -- in particular, foreach produces the wrong results. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHP query to mysql database returns emtpy data, but Query Browser shows records
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On 07 January 2005 03:25, Jason Walker wrote:
> Graeme - you were moving in the right direction. Since the
> data in the field
> is varchar(250), the only thing that changes is the fact that the last
> number is 3 digits. Other page queries were also affected
> with 4 x 2 digit
> numbers in the category field (eg. '37 48 49 52').
>
> By adding '%' between each number and using 'LIKE' as opposed
> to '=', the
> queries through PHP return the correct value.
>
> I think is very strange as 3x numbers work fine when using
> spaces (' ')
> between each criteria (as in '37 48 53').
>
> The change would look something like:
>
> SELECT description from cpProducts where category like '39%47%48%172'
That's not a good idea, as it would also match entries like:
391 247 48 172
39 147 148 172
395 347 1486 1172
etc.
I think you really need to find out exactly what's in those failing records,
and why it's not matching your query.
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RE: [PHP-DB] Trying to connext to MySQL with PEAR
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 06 January 2005 21:10, Norland, Martin wrote: > > -Original Message- > > From: Ford, Mike [mailto:[EMAIL PROTECTED] > > Sent: Thursday, January 06, 2005 1:13 PM > > Subject: RE: [PHP-DB] Trying to connext to MySQL with PEAR [snip] > > Oh dear, as a fully-paid-up pedant, I'm afriad I can't resist this > > one: > > > > Doesn't affect the answer, but this occurrence of 'effect' should > > be 'affect'. ;) > > > > Cheers! > > > > Mike > > * Joining in on the fun * > > I'm afraid you spelled afraid incorrectly. I'll be sending you the > bill for my services related to this matter. Please send it to Mr Murphy, who obviously insinuated one of his pet gremlins into my keyboard for those few moments...! ;) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Trying to connext to MySQL with PEAR
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 06 January 2005 16:39, Jochem Maas wrote: > Hutchins, Richard wrote: > > echo $dsn; $isPersistant = TRUE; > > doesn't effect the code but 'Persistant' is spelled 'Persistent' Oh dear, as a fully-paid-up pedant, I'm afriad I can't resist this one: Doesn't affect the answer, but this occurrence of 'effect' should be 'affect'. ;) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] still Parse errors ,,, can you. impart me about it.
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 23 December 2004 18:04, amol patil wrote: > hallo Mike, > > thanks for reply, but i want a bit more help, again Please keep this on-list -- someone else may have time to reply before I can (especially as I am about to go home for my tea and a well-earned sleep!). > > i know these parse errors are generally typing mistakes , > > but i have checked for it , but still i am getting errors. > > i have attached files with their codes , can you go through > it to find what is going wrong > > > Parse error: parse error, unexpected '<' in > /home/dollar1/public_html/signup.php on line 263 > > > parse error, unexpected '<' in > /home/dollar1/public_html/login.php on line 94 > > > Parse error: parse error, unexpected T_STRING in > /home/dollar1/public_html/addfunds.php on line 91 then on 102 > > > > thank you. > > > "Ford, Mike" <[EMAIL PROTECTED]> wrote: > To view the terms under which this email is distributed, > please go to http://disclaimer.leedsmet.ac.uk/email.htm > > > > On 21 December 2004 07:58, amol patil wrote: > > > hallo friend, > > > > i have developed simple and small database website using php ,html > > and java script. > > > > but i am getting these three parse errors on clicking , > > > > i have checked 3-4 imes on these line numbers, but there wasn't any > > $ variable. php script is also correctly written. > > what is this T_STRING error. > > > > can you help me regarding this. > > > > thank you. > > > > errors: > > > > Parse error: parse error, unexpected $ in > > /home/dollar1/public_html/signup.php3 on line 379 > > $ in PHP's error messages represents the end of the file, so PHP has > reached the end of signup.php3 when it's still expecting more > program. This means you have an error somewhere in the preceding 378 > lines -- most likely a missing }. (If PHP was complaining about a > variable reference, the message would refer to "unexpected > T_VARIABLE".) > > > Cheers! > > Mike > > - > Mike Ford, Electronic Information Services Adviser, > Learning Support Services, Learning & Information Services, > JG125, James Graham Building, Leeds Metropolitan University, > Headingley Campus, LEEDS, LS6 3QS, United Kingdom > Email: [EMAIL PROTECTED] > Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 > > > > Do you Yahoo!? > Jazz up your holiday email with celebrity designs. Learn more. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] _POST, _GET, _REQUEST not working
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On 23 December 2004 01:12, Keane, Warren A FIN:EX wrote:
> I did try
>
> if (empty($_GET)) { parse_str($_SERVER['QUERY_STRING'],$_GET); }
>
> which worked so I guess I should be able to come up with an
> equivalent for _POST using argv, argc.
>
> > I am guessing but I also think the problem is to do with the fact
> > that the CGI sapi is being used.
>
> I am using the CLI SAPI, I checked using php_sapi_name(). Is this
> causing the problem?
Absolutely -- this is the Command-Line Interface. As this is intended for
command-line scripting, it has no notion of being used in a Web context and
does not even attempt to fill the $_POST or $_GET (or most of the other $_)
arrays. You need to use either the CGI SAPI, or the Apache module.
Cheers!
Mike
-
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JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] _POST, _GET, _REQUEST not working
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On 20 December 2004 21:50, Warren wrote:
> Hello,
>
> I am running PHP 4.39 as a CGI under Tomcat 5.025, Linux 2.4.20-31.9.
> Configure = './configure' '--with-java=/usr/java/j2sdk1.4.2_04'
> '--with-servlet=/home/www/jakarta-tomcat-5.0.25' '--with-mysql'
>
> I cannot get the _GET function or _REQUEST functions to pick
> up values from
> a form generating even though I can see the query string
> values in the URL
> as in:
> http://localhost:8080/ip7/httptest.php?var1=212122&var2=343434
>
> My HTML is very simple:
>
> http://localhost:8080/ip7/httptest.php"; method="get">
>
>
>
>
>
> The PHP program httptest.php is also very simple:
>
> global $_SERVER, $_GET, $_POST, $_REQUEST, $_SESSION, $_COOKIE;
>
> if(!empty($_REQUEST['var1'])) { $var1 = $_REQUEST['var1']; }
> else { $var1 ='undefined'; }
>
> if(!empty($_GET['var2'])) { $var2 = $_GET['var2']; }
> else $var2 ='undefined';
>
> // Various HMTL tags removed for simplicity
> echo $var1
> echo $var1
Is this a direct paste from your original? If so, there's an obvious error
here -- one of those should be $var2,'cos as it is you're never even echoing
the value of the $_GET parameter.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] Parse errors ,,, can you. impart me about it.
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 21 December 2004 07:58, amol patil wrote: > hallo friend, > > i have developed simple and small database website using php ,html > and java script. > > but i am getting these three parse errors on clicking , > > i have checked 3-4 imes on these line numbers, but there wasn't any $ > variable. php script is also correctly written. > what is this T_STRING error. > > can you help me regarding this. > > thank you. > > errors: > > Parse error: parse error, unexpected $ in > /home/dollar1/public_html/signup.php3 on line 379 $ in PHP's error messages represents the end of the file, so PHP has reached the end of signup.php3 when it's still expecting more program. This means you have an error somewhere in the preceding 378 lines -- most likely a missing }. (If PHP was complaining about a variable reference, the message would refer to "unexpected T_VARIABLE".) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHP 4.3.10RC2 - Any change in the way rows are fetch ed ?
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 16 December 2004 12:51, Vincent KONIECZEK wrote: > Hi there, > > > I was testing PHP 4.3.10RC2 with a well-tested web application when I > saw it failed badly. > > After a little debug, I have found that the problem comes > from this SQL > query: > SELECT CONCAT(num) AS k FROM user WHERE uid LIKE '%%' > where user is a table with num as the PK and uid as a VARCHAR(128). > > I expect a result like this one (var_export-like display) of > the fetched > row (with mysql_fetch_array()): > ([0] => 67,[k] => 67) > But mysql_fetch_array() gives me: > ([0] => ([0] => 67,[k] => 67)) > > For me, it is a really big problem. > I do not have it with PHP 4.3.8. > I did not take the time to test with PHP 4.3.9 nor 4.3.10 but > I took a > look at the documentation web sites, the latest Changelogs and made a > search on the mailing lists but found nothing about it. Similar problems have been reported to the bugs database, and have been traced to an old version of the Zend Optimiser -- if you are using this, try disabling it, and if your application then works ok upgrade to the latest version. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] date conversions
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On 16 December 2004 06:00, neil wrote:
> Hi
>
> I am needing to convert a d/m/y date such as 30/11/2004 into the
> format that mysql can use ie. 2004-11-20
>
> If I try the following:
>
> $testdate="30/11/2004";
> echo date("Y-m-d", strtotime($testdate));
>
> the result is - 2006-06-11
strtotime() is, unfortunately, a little American biased and only recognises
the mm/dd/ numeric format (using slashes). So the above is returning
the equivalent of the 11th day of the 30th month of 2004!
You can use other PHP functions, as has been suggested, but you might also
investigate the mySQL date formatting functions, as I believe they work
perfectly well on input dates as well as output ones.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 15:26, Stuart Felenstein wrote:
> --- "Ford, Mike" <[EMAIL PROTECTED]> wrote:
>
> > Well, your taste seems to be to use { }, so :-endif is irrelevant.
> >
> Alright it's Friday, I'm punchy but we're all in a
> good mood !
>
> Yes, I like the closing curlies
>
> So, then where do these lovely ladies go here ?
>
> if ($row_rsCS == false) {
>
> exit;
> }
And, by the way, why on earth are you using a print_r an a straight literal
string? Seems to me you could just put that text in as part of the HTML:
if ($row_rsCS == false) {
?>
No Matches Found
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 15:26, Stuart Felenstein wrote:
> --- "Ford, Mike" <[EMAIL PROTECTED]> wrote:
>
> > Well, your taste seems to be to use { }, so :-endif is irrelevant.
> >
> Alright it's Friday, I'm punchy but we're all in a
> good mood !
>
> Yes, I like the closing curlies
>
> So, then where do these lovely ladies go here ?
>
> if ($row_rsCS == false) {
?>
>
>
exit;
> }
Just put the PHP tags in as indicated and you'll be good to go.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 15:16, Stuart Felenstein wrote:
> --- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
>
> > The reason the close is there is because the next
> > line
> > of code is the print_r , and I put some html in
> > there.
> >
> So this works great:
>
> if ($row_rsCS == false) {
> print_r ("No Matches Found");
> exit;
> }
>
> But because I want to have some html formatting around
> the print_r, I closed the tags.
Yes, but you didn't include the { } to indicate the scope of the if -- so it
terminated at the ?>.
> I'm not sure how to use the endif.
Well, your taste seems to be to use { }, so :-endif is irrelevant.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 15:06, Stuart Felenstein wrote:
> > The closing ?> of a PHP segment also implies an
> > end-of-statement semicolon
> > -- so the above is equivalent to:
> >
> >if ($row_rsCS == false) ;
> > ?>
> >
> > Which, of course, means that the scope of the if
> > doesn't extend to anything
> > beyond this point.
> >
> > You need to mark the block controlled by the if,
> > using either {-} or
> > :-endif, according to your taste.
> >
> The reason the close is there is because the next line
> of code is the print_r , and I put some html in there.
Nothing wrong with having the closing ?> there -- please re-read my
response. If it's still unclear to you, please ask specific questions.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 14:39, Stuart Felenstein wrote:
> I want to send back a message when no matches are
> found on my search page. Basically "No matches
> found". I assumed that mysql_fetch_assoc would be the
> determining factor on whether any rows will come back.
> As you can see below I do a if ($row_rsCS == false).
> Apparently though (while the message is sharp and
> centered ;)), it is not to right place, since it sends
> the message and exits whether records / matches exist or not. Any
> suggestions ?
>
> Thank you
> Stuart
>
> $query_limit_rsCS = sprintf("%s LIMIT %d, %d",
> $query_rsCS, $startRow_rsCS, $maxRows_rsCS);
> //print_r($query_limit_rsCS);
> $rsCS = mysql_query($query_limit_rsCS, $Pmmodel) or
> die(mysql_error()); //print_r($rsCS);
> $row_rsCS = mysql_fetch_assoc($rsCS);
>
> if ($row_rsCS == false)
> ?>
The closing ?> of a PHP segment also implies an end-of-statement semicolon
-- so the above is equivalent to:
if ($row_rsCS == false) ;
?>
Which, of course, means that the scope of the if doesn't extend to anything
beyond this point.
You need to mark the block controlled by the if, using either {-} or
:-endif, according to your taste.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] mysql_array_array
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On 03 December 2004 13:15, Yemi Obembe wrote:
> $sql = "SELECT * FROM arcadia WHERE email=$v";
>$sql_in = "INSERT INTO arcadia ('email') VALUES ('$v')";
Spot the difference: you have quoted the email value $v in the INSERT
(correct) but not in the SELECT (wrong). This means that:
$res = mysql_query( $sql ) ;
is failing with a SQL error, so $res is not being set to a valid MySQL
result resource, so that when you execute:
if (list($row) = mysql_fetch_array($res)) {
The mysql_fetch_array() complains with the error you have seen.
After any database operation, you should check for failure and echo out any
error message -- see mysql_errno() (http://php.net/mysql_errno) and
mysql_error() (http://php.net/mysql_error).
Cheers!
Mike
-
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JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] Multi-User Update Problem
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 30 November 2004 14:45, SCALES, Andrew wrote: > Thanks very much for your help. The main difficulty I was > having really was > unlocking the record again if the user crashed out or just > closed down their > browser/computer (something they have a bad habit of doing) > but storing the > time the record was locked and ignoring the lock if it's over > that time > sounds interesting. > I may try storing the data in a session variable and then > comparing that to > the database before the updated data is inserted into the > record as Bastien > suggested. We wanted to keep hits on the db to a minimum, but > seen as some > extra traffic will be necessary anyway I may just try that. Another approach to this might be: Keep a column in your database table for time of last update of each record. When a user reads a record for update, don't lock it at this point, but save the time at which it was read into the user's session (or somewhere in the database). On receiving a potential update, check the time the record was read (as recorded above) and the last update time of the record (lock the record as part of this query) -- if the update time is later then the read time, someone else has updated in the interim and you should abandon ship; otherwise, update the record including a new last-updated value; in either case, unlock the record. This methodology keeps both the lock and unlock in the same script (and potentially within a single database transaction), so no need for any external checks for locked records, and minimizes the amount of time for which any one record is locked. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Transaction suddenly not working
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 29 November 2004 13:19, Stuart Felenstein wrote: > Now the printout of the query is this: > > 0: INSERT INTO Table1 (LurkID, ProfileName, Edu, > WorkAuth, WorkExp, CarLev, Secu, Confi, Relo, > Telecomu, City1, State1, City2, State2, TravelPref, > SalaryAnnual, SalaryHourly, Available) VALUES (47, > '', 7, 2, 1015, 5, , '', '', '', 'fds', 5, '', You have 2 successive commas in this last line, with no value in between -- this is your syntax error. > , 4, 26, , 2004-02-02)01062 : Duplicate entry '0-f' for key 1 And again on this line -- twice, in fact, since the previous line ends with a comma, too. Track down whatever is outputting these null values, fix it, and you should be good to go (well, at least less bad!). Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: Subject: Javascript Question (Was PHP / Javascri pt question)
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On 16 November 2004 15:12, Neil Smith wrote:
> That
>
> if (df[i].checked=true) {
>
> should of course read
>
> if (df[i].checked==true) {
No it shouldn't -- it should read
if (df[i].checked) {
More efficient, more readable, and, more important, The Right Way (TM)! ;)
Cheers!
Mike
-
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Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] PHP / Javascript question
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 16 November 2004 03:03, Chris Payne wrote: This is OT, really, but because it's an easy answer: > if ( document.removeitems.del.value == "" ) > BUT because the tickboxes information is stored in a PHP > Array called del[] > I am having major problems getting it to work. You shouldn't be, since any good JavaScript text will tell you that, by definition, x.y is identical to x['y']; so: document.removeitems['del[]'] will get you started. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Persistent Connections to Oracle databases
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 11 November 2004 19:11, Patrick David wrote: > My understanding of persistent connections was that using the > ociplogon function a connection would be opened to the > database and all other connections to the same database (with > the same username and password) would use the first one > previously opened, which mean I would have only 1 connection > to the database. I know this is a late response, but I haven't seen anybody point this out yet: that's 1 connection *per Apache child process*, since each process still has to have its own connection. > But in fact it is not what is happening, > every time I submit the page to the same database a new > connection is opened. Which is a little bit annoying if I > submit this one 100 times (100 connections at the end). Potentially, if you have Apache configured to run 100 children or more. If you configure it to run only 50 children, that's the maximum number of Oracle connections you will get. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: [EMAIL PROTECTED] November 2, 2004
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 02 November 2004 08:04, GH wrote: > Therefore everyone in the world has an interest in what happens in the > american body politic just as Americans have an interest in what > happens to the British Prime Minister and in parts of the British > body politic. This may be true, and I will certainly be keeping an eye on the news to see what the result of the presidential election is. However, a substantial proportion of the people on this list do not have the right to vote in this election, and are extremely irritated to receive a reminder about voting on a list where such a reminder is wholly off-topic. We would be equally irritated about a reminder to vote in Canadian/Brazilian/Russian/South African elections (well, perhaps except for those resident in those countries!). I, personally, would be equally irritated about a reminder to vote in British elections, even though it would apply to me, since, again, it is wholly off-topic in this list. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Forms list from database
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On 01 November 2004 21:11, Jason T. Davidson wrote:
> Here is the code:
>
>
> cellspacing="0">
>
>
>
>
>while ($check=mysql_fetch_array($result)){
> print "$check[LNAME],$check[FNAME]($check[CID])";
> }
> >
>
>
>
>
I think you're missing some tags -- these should be
present around each value extracted from the database, so:
while ($check=mysql_fetch_array($result)){
print
"{$check['LNAME']},{$check['FNAME']}({$check['CID']})\n";
}
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] Problems with mysql_num-rows()
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 01 November 2004 05:01, Doug Thompson wrote: > The variables are not being expanded. As a minimum, you need to > escape the single quotes. $query = "SELECT * from user where > name=\'$userid\' and pass=password(\'$password\')" This is complete BS. The whole string is in double quotes -- the presence of single quotes within it has no effect whatsoever on the expansion of variables, nor is it necessary to escape them. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Convert plain text to HTML tagged text
On 28 September 2004 18:15, [EMAIL PROTECTED] wrote: > To the list: > > I've googled and searched the manual, but I'm still looking > for a simple solution to a simple problem. > > I have a MySQL database of text stories in longtext MySQL > fields. These stories have simple returns (\r) in them and no > other formatting. I need to use these stories both for web > and print production, so I need to be able to get the text > out of MySQL via PHP and have those returns change to > tags. But I also need to keep those extra tags out of the > database file so the text can be exported and poured into a > layout program. > > HTMLspecialchars and HTMLentities don't seem like the right > solution, but maybe I'm missing something. Do I have to use > regular expressions in PHP as the text is pulled from the database? http://www.php.net/str_replace should be all you need -- no need for regexps for such a simple replace. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] MultSelect ListBox hell!
On 23 September 2004 20:53, Stuart Felenstein wrote:
> So here is what I have:
>
> //Here is defines the field variable and uses
> //CodeCharge function to grab the variable
> $s_Industry = CCGetParam("s_Industry", "");
> $s_LocationState = CCGetParam("s_LocationState", "");
> $s_TaxTerm = CCGetParam("s_TaxTerm", "");
>
> //Here is the parsing of the array. I'm not sure
> what the $proj variable is for. I gather it's a
> holder for the array values
>
> if (count($s_Industry) > 0 AND is_array($s_Industry)) {
> foreach ($s_Industry as $key => $value) {
> if ($Proj1 != "") $Proj1 = $Proj1.",";
> $Proj1 = $Proj1."'".$value."'";
> }
> }
$Proj1 now contains a comma-separated list of the values passed to
$s_Industry, which was filled by the CCGetParam() above. The above code
block is equivalent to (and would be better coded as):
if (count($s_Industry) > 0 AND is_array($s_Industry)) {
$Proj1 = "'".implode("','", $s_Industry)."'";
}
which may look somewhat familiar to you!
> //Parsing next array
> if (count($s_LocationState) > 0 AND
> is_array($s_LocationState))
> {
> foreach ($s_LocationState as $key => $value) {
> if ($Proj2 != "") $Proj2 = $Proj2.",";
> $Proj2 = $Proj2."'".$value."'";
> }
> }
> //Parsing file array
> if (count($s_TaxTerm) > 0 AND is_array($s_TaxTerm)) {
> foreach ($s_TaxTerm as $key => $value) {
> if ($Proj3 != "") $Proj3 = $Proj3.",";
> $Proj3 = $Proj3."'".$value."'";
> }
> }
These two blocks are similar for the other two parameters, $s_LocationState
and $s_TaxTerm
> Here is what will be the death of me :)
> First the where condition below is being appended to
> anoher file in my main sql statement (don't ask:))
> CC keeps their code in various sections and files.
> Anyway , if you remember yesterday, it was determined
> that I needed the where condition to be dynamically
> created based on the user input.
> Obviously the code below does nothing of that sort.
Obviously it does, using the lists of values built above.
> So as a start, I'm trying to figure out what I can do
> with this section here (since this is really what
> needs to be changed, I think) to make it all right.
>
> if ($Proj1)
> $VendorJobs->ds->SQL.= " AND (`VendorJobs`.Industry IN (".$Proj1."))";
Plug the value for $Proj1 built above into this, and again you have
something that may look very familiar to you. It's the very same IN clause
I was urging you to use yesterday! ;)
> if ($Proj2)
> $VendorJobs->ds->SQL.= " AND
> (`VendorJobs`.LocationState IN (".$Proj2."))";
> if ($Proj3)
> $VendorJobs->ds->SQL.= " AND (VendorJobs.TaxTerm IN (".$Proj3."))";
> echo "SQL:". $VendorJobs->ds->SQL."";
So you now have a dynamically built portion of SQL, in $VendorJobs->ds->SQL,
that has a clause like "AND x IN ('a','b','c')" for each input field that
has any values set. According to your specs, this could be anywhere up to
six separate clauses. This seems to be exactly what you wanted, so your
code looks good to go.
To help you understand exactly what's going on here, or in any script or
program you're struggling to interpret, I would recommend two time-honoured
techniques:
(i) Dry running: get out your genuine old-fashioned pen and paper, pretend
you're the PHP interpreter processing this program, and write down the value
of each variable as you work through the code. Yes, it can be quite
long-winded and tedious, but you really get a tremendous feel for exactly
what's going on. The number of times I've done this and cursed myself as
I've watched a value going out of range, or not getting set at all, I
couldn't begin to count.
(ii) As a variation of the above, put *lots* of debugging echos in your
script: echo the value of every variable frequently and redundantly -- it
can help sometimes just to have the reassurance that a value really hasn't
changed, even though you know it absolutely shouldn't!! Again, if you're
struggling with how a script operates this can help you see how values are
built up, and can often show you exactly where a wrong value gets calculated
(and how, and maybe even why). It's especially important to echo your final
complete SQL statement just before it's executed, so that if it produces an
error message you've got the actual relevant SQL right in front of you.
Hope this helps.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] Using PHP to generate SQL statement
On 23 September 2004 07:47, Ed Lazor wrote:
> I keep looking at the following code and thinking there's
> gotta be a better
> way. I've been in front of the computer all day tho and I'm drawing
> a blank. Any ideas?
Seems to me we've just answered a very similar question to this (and I'd be
surprised it there weren't several relevant threads in the list archives).
Nonetheless:
> $sql = "select ID from products where ";
>
> if ($webpage->parameter_isset("CategoryID")) {
Two possible approaches that spring to mind are:
$sql = "select ID from products where 1=1";
if ($webpage->parameter_isset("CategoryID")) {
$sql .= " AND CategoryID = '{$webpage->CategoryID}'";
}
if ($webpage->parameter_isset("CompanyID")) {
$sql .= " AND CompanyID = '{$webpage->CompanyID}'";
}
if ($webpage->parameter_isset("SettingID")) {
$sql .= " AND SettingID = '{$webpage->SettingID}'";
}
if ($webpage->parameter_isset("SystemID")) {
$sql .= "AND SystemID = '{$webpage->SystemID}'";
}
Or:
$where = ''
foreach (array('CategoryID', 'CompanyID', 'SettingID', 'SystemID')
as $field):
if ($webpage->parameter_isset($field)):
$where .= ($where?' AND':'')." $field = '{$webpage->$field}'";
endif;
endforeach;
if ($where):
$sql = "select ID from products where$where";
...
else:
// no where information -- major error
endif;
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] MultSelect ListBox hell!
On 22 September 2004 18:45, Stuart Felenstein wrote:
> Just to confirm,
> This is what I'm going to start with:
Yeah, I'd say you've pretty much got it, except...
> //base sql statement
> $sql = "select * from jobs where record_deleted = 'NO' ";
>
> if (isset($_POST['states'])){
Your SQL is going to need some sort of conjunction here, as your WHERE phrase already
has an initial condition in it. I'm guessing you'll want an AND, so:
$sql .= 'AND ';
> //check to see if the states is an array
> // multiple items or just one
> if (is_array($_POST['state']))
You've switched from $_POST['states'] to $_POST['state'] -- fix whichever is wrong ;)
> $sql .= "state='".implode("' OR state='",
> $_POST['state'])."'";
Given the conditions you want your WHERE phrase to test, you're going to need more
parentheses to force the ORs to be evaluated before the ANDs; this is where the IN
syntax, IMO, is more readable. So you want either:
$sql .= "(state='".implode("' OR state='",$_POST['state'])."')";
or:
$sql .= "state IN ('".implode("','",$_POST['state'])."')";
>
> }else{
> //$_POST['state'] is not an array
> $sql .= "state = '".$_POST['state']."' ";
> }//end if
>
> if (isset($_POST['job'])){
>if (isset($_POST['state'])){ $sql .= " AND "; }
And throughout this second block you've used a cut'n'paste of the first block without
altering ['state'] to ['job'] -- just the sort of oversight that can give you the
raving heebie-jeebies somewhere down the line if you fail to fix it! ;)
>
> //add in the AND if the state is set
> //check to see if the states is an array
> //multiple items or just one
>
> if (is_array($_POST['state']))
>$sql .= "state='".implode("' OR state='",
> $_POST['state'])."'";
> $sql .= ")";
> }else{
> $_POST['job'] is not an array
> $sql .= "job = '".$_POST['job']."' ";
> }
> //end if
Given the moderate complexity of this code, I'd strongly recommend echo-ing out $sql
immediately before it's used whilst you're in testing mode. When your query fails,
you'll already be one step ahead in working out what the problem is.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] MultSelect ListBox hell!
> -Original Message-
> From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
> Sent: 22 September 2004 16:45
>
> --- "Ford, Mike" <[EMAIL PROTECTED]> wrote:
>
> > >if (is_array($_POST['state'])){
> > > $sql .= "(";
> > > $x = 0;
> > > foreach ($_POST['state'] as $state)
> > >if ($x == 0){
> > >$sql.= "state = '$state' ";
> > >$x=1;
> > > }else{
> > > $sql .= " OR state = '$state' ";
> > > }
> > > $sql .= ")";
> >
> > PHP has the very nice implode function to make this
> > much easier:
> >
> > $sql = "state='".implode(' OR state=', $_POST['state'])."'";
> >
> > (If your database supports the IN operator, this is
> > probably even better:
> > $sql = "state IN ('".implode("','", $_POST['state'])."')"; )
>
> Sorry, cause I know this is probably a stupid
> question, but what block of code does the implode
> statement replace ?
Everything inside the if(is_array()). Ummm, that should probably still be a
.= operator, then. There's also some quotes missing in the original
version, so:
if (is_array($_POST['state']))
$sql .= "state='".implode("' OR state='", $_POST['state'])."'";
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services, JG125, James
Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS,
LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] MultSelect ListBox hell!
> -Original Message-
> From: John Holmes [mailto:[EMAIL PROTECTED]
> Sent: 22 September 2004 16:39
>
> From: "Ford, Mike" <[EMAIL PROTECTED]>
> >>if (is_array($_POST['state'])){
> >
> > This check isn't really necessary in PHP, since
> $_POST['state'] will
> > *always* be an array if the form field has NAME='state[]', even if
> > only 1 is selected.
>
> But remember that the form comes from the client. Just
> because you create
> the form with "state[]", that doesn't mean I'm going to send
> it that way. ;)
Yeah, true -- I have a very bad tendency to forget about security considerations like
that until someone reminds me (often a posting on this list does it ;). Just because
I have a well-defined set of well-behaved users...!!
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services, JG125, James Graham
Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United
Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] MultSelect ListBox hell!
> -Original Message-
> From: Bastien Koert [mailto:[EMAIL PROTECTED]
> Sent: 22 September 2004 15:27
[]
> //base sql statement
> $sql = "select * from jobs where record_deleted = 'NO' ";
>
> if (isset($_POST['states'])){
>//check to see if the states is an array (multiple items
> or just one
This check isn't really necessary in PHP, since $_POST['state'] will *always* be an
array if the form field has NAME='state[]', even if only 1 is selected.
>if (is_array($_POST['state'])){
> $sql .= "(";
> $x = 0;
> foreach ($_POST['state'] as $state)
>if ($x == 0){
>$sql.= "state = '$state' ";
>$x=1;
> }else{
> $sql .= " OR state = '$state' ";
> }
> $sql .= ")";
PHP has the very nice implode function to make this much easier:
$sql = "state='".implode(' OR state=', $_POST['state'])."'";
(If your database supports the IN operator, this is probably even better:
$sql = "state IN ('".implode("','", $_POST['state'])."')"; )
> }else{
> //$_POST['state'] is not an array
> $sql .= "state = '".$_POST['state']."' ";
> }//end if
>
> if (isset($_POST['job'])){
> if (isset($_POST['state'])){ $sql .= " AND "; } //add in
> the AND if the
> state is set
> //check to see if the states is an array (multiple items or just one
>if (is_array($_POST['job'])){
> $sql .= "(";
> $x = 0;
> foreach ($_POST['job'] as $job )
>if ($x == 0){
>$sql.= "job = '$job ";
>$x=1;
> }else{
> $sql .= " OR job = '$job ";
> }
> $sql .= ")";
> }else{
> //$_POST['job'] is not an array
> $sql .= "job = '".$_POST['job']."' ";
> }//end if
Ditto for the job field.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services, JG125, James Graham
Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United
Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Inserting a ' into mySQL
> -Original Message- > From: Ron Piggott > Sent: 21/08/04 01:53 [] > One of the problems I am now having is if the user types an ' into their > entry --- these ones do not get saved into the mySQL database. [] > I can look at this and understand that if an ' is keyed why it wouldn't save > and that line would create an error --- How do you work around this? That's what mysql_real_escape_string() is for -- http://www.php.net/mysql_real_escape_string. Cheers! Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: Checkboxes in a table
> -Original Message- > From: Ford, Mike [LSS] > Sent: 21/08/04 01:57 > foreach ($_POST['checkbox'] as $key=>$irrelevant): > // checkbox[$key] was checked > endif; OK, it's 2a.m. here and I'm about asleep, whioch is why that last line didn't read endforeach; !!! Cheers! Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: Checkboxes in a table
> -Original Message- > From: Jasper Howard > Sent: 21/08/04 00:49 > > just set the checked value of the check boxes to something like, > "true", and when you are going through the check boxes in the second > script do something like this: Urrr -- you script will only ever see checkboxes which are checked -- unchecked ones won't be trnsmitted. So just foreach() over the received array, and the indexes you see are for the checked boxes: foreach ($_POST['checkbox'] as $key=>$irrelevant): // checkbox[$key] was checked endif; Cheers! Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] I have a CR-LF problem when pulling stuff out of my DB
On 19 August 2004 17:02, Michael Cortes wrote: > ctrl-m is a carriage return. Does anyone know what ctrl seqence is > line feed? ctrl-j (CR and LF are ASCII codes 13 and 10, so ctrl+ the 13th and 10th letters of the alphabet respectively!) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Check Boxes
On 18 August 2004 15:53, John Holmes wrote:
> Ford, Mike [LSS] wrote:
>
> > > $chkboxes = $_POST['ch'];
> > > $sql = 'SELECT ';
> > > foreach($chkboxes as $k => $v)
> > > {
> > > $sql .= $v;
> > > if($k < (sizeof($chkboxes) - 1))
> > > {
> > > $sql .= ', ';
> > > }
> > > }
> > > $sql .= ' FROM form';
> >
> >
> > $sql = 'SELECT ' . implode(', ', $chkboxes) . 'FROM form';
>
> Just note that with either solution, someone can post a value of "*
> FROM table WHERE 1#" and see everything in any table in your database.
I was waiting for someone to come in with a security warning, but knew that whoever it
was would express it much better than I could ;) -- so, a gold medal to John!!
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] Check Boxes
On 18 August 2004 11:24, randy wrote:
> $chkboxes = $_POST['ch'];
> $sql = 'SELECT ';
> foreach($chkboxes as $k => $v)
> {
> $sql .= $v;
> if($k < (sizeof($chkboxes) - 1))
> {
> $sql .= ', ';
> }
> }
> $sql .= ' FROM form';
$sql = 'SELECT ' . implode(', ', $chkboxes) . 'FROM form';
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] OCI8
On 13 August 2004 13:29, yannick wrote:
> I have some trouble with Oracle Database and php...
>
> see this code:
> while (1) {
> $conn=OCILogon($username,$password,$database);
Try OCIPLogon() rather than OCILogon().
> $stmt=OCIParse($conn,"select 50 as toto from dual");
> OCIDefineByName($stmt,"TOTO",&$total);
Not related to your problem, but you don't need that & -- in fact, it's deprecated and
may, one day, cause a parse error.
> OCIExecute($stmt);
> OCIFetch($stmt);
> echo ":::$total:::\n";
> OCILogoff($conn);
> $err=OCIError($conn);
> OCILogoff($conn);
> sleep(10);
> }
> >
>
> when i execute it, the number of fd on ocius.msg is growing. but
> there is only 1 connection at database.
>
> Can someone help me ?
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] Date problem: data is current as of yesterday
-Original Message-
From: Karen Resplendo
To: [EMAIL PROTECTED]
Sent: 02/07/04 19:36
Subject: [PHP-DB] Date problem: data is current as of yesterday
The database queries all the sources at night after everyone has gone
home. That means the data was current as of yesterday. This little
snippet below returns yesterday's date, except that the first day of the
month returns "0" for the day. Now, I know why this is happening, but I
can't find out how to fix it (in VBA or SQL Server I would just say,
"date()-1":
$today = getdate();
$month = $today['month'] ;
$mday = $today['mday'] -1;
$year = $today['year'];
echo "Data is current as of $month $mday, $year";
--
The mktime() function is your friend for this kind of date arithmetic. For
example, this is one possible way to do what you want:
$yesterday = mktime(12, 0, 0, $today['mon'], $today['mday']-1,
$today['year']);
echo "Data is current as of ".date("F j, Y", $yesterday);
(Note the use of time 12:00:00 to avoid daylight savings oddities!)
The examples on the date() and mktime() manual pages may suggest other
possibilities to you.
Cheers!
Mike
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RE: [PHP-DB] More problems with searching
On 01 July 2004 20:02, Shiloh Madsen wrote:
> What technique would you suggest to accomplish the same thing?
Well, personally I'd tend to use the flag-the-first-pass method, which suppresses the
addition of the AND or OR the first time through the build loop (I think someone else
posted an example of this to the list). But both ways can be considered valid
approaches -- it just depends on what seems better (or more elegant, if you like!) to
you.
> - Original Message -
> From: "Ford, Mike [LSS]" <[EMAIL PROTECTED]>
>
> > On 01 July 2004 18:36, Justin Patrin wrote:
> >
> > > On Thu, 1 Jul 2004 12:28:46 -0500, Shiloh Madsen
> > > <[EMAIL PROTECTED]> wrote:
> > > >
> > > >
> > > > this was Mr Holmes's solution (in part):
> > > > $query = "SELECT * FROM keyword WHERE 1 "
> > > > $words = explode(' ',$_GET['search_text']);
> > > > foreach($words as $word)
> > > > { $query .= " AND keyword = '$word' "; }
> > >
> > > Shouldn't that be OR?
> >
> > ... and, if it should, that should be a 0 instead of a 1
> (although I'm not
> a huge fan of this technique!).
Cheers!
Mike
-
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RE: [PHP-DB] More problems with searching
On 01 July 2004 18:36, Justin Patrin wrote:
> On Thu, 1 Jul 2004 12:28:46 -0500, Shiloh Madsen
> <[EMAIL PROTECTED]> wrote:
> >
> > After the very kind help i was given last night I have the query
> > being built right, however the query does not work. Just to
> > refresh, the gentlemen who had helped me suggested creation of a
> > query that looks like:
> >
> > SELECT * FROM table1 where 1 or cat or dog...and so forth. Now,
> > this query is building fine, but the where 1 is causing it to
> > return rows even if it has none of the search terms. When i run it
> > in sql without the where 1 it works as it should, but with that, i
> > get all rows returned. Is there a way i can reword this query or am
> > I doing something wrong?
> >
> > this was Mr Holmes's solution (in part):
> > $query = "SELECT * FROM keyword WHERE 1 "
> > $words = explode(' ',$_GET['search_text']);
> > foreach($words as $word)
> > { $query .= " AND keyword = '$word' "; }
>
> Shouldn't that be OR?
... and, if it should, that should be a 0 instead of a 1 (although I'm not a huge fan
of this technique!).
Cheers!
Mike
-
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Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] [PHP]: session problem
On 24 June 2004 16:44, H. J. Wils wrote:
> this is the code, but this code works on my hosting provider but not
> on my own server. I think i have to change settings in php.ini but
> dont know which...
> first page:
>
> session_start();
>
> include "connect.php";
> include "functions.php";
>
> $user= $_GET["email"];
> $ww = $_GET["ww"];
>
> $check_user_query = "select id,email, password from user where
> email='$user' and password='$ww'";
> $check_user_res = mysql_query($check_user_query) or
> die(mysql_error().": $check_user_query");
>
> if (mysql_num_rows($check_user_res) == 1){
> //user is ingelogd
>
>$userdata =
> mysql_fetch_array($check_user_res);
>$sid=session_id();
>$uid=$userdata["id"];
>$_SESSION['logged_in'] = true;
>$_SESSION['sid'] = $sid;
>$_SESSION['user'] = $uid;
>
>$dt = date("Y-m-d H:i:s");
>
> header("location: user.php?action=0");
> }else{
> header("location: user.php?action=9");
> }
Redirecting like this will not pass the session id in the URL if that is
necessary, which it would be if cookies are not being used. Since you say
it works for you from your provider's system but not your local one, this
suggests that your provider has session.use_cookies turned on, but you have
it turned off.
If this is so, you can solve your immediate problem by turning that option
on in your php.ini, but the redirects will still not work correctly for
anyone who has cookies turned off in their browser. If you are bothered
about this, you need to make use of the handy-dandy SID constant that PHP
helpfully provides, thusly:
header("Location: user.php?action=0&".SID);
or, if you're a tidy-URL geek, something like:
header("Location: user.php?action=0".(SID?"&".SID:""));
(BTW, notice the correct spelling of the "Location" header, with a capital
L; and, yes, others are right when they say it should be a full absolute
URL. These things have been known to matter to some browsers, so it's best
to make a habit of getting them right!)
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] Image / file uploader
On 30 April 2004 01:10, Craig Hoffman wrote:
> When I put single quotes in the PHP_SELF and I get this error:
> Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE,
> expecting T_STRING or T_VARIABLE or T_NUM_STRING
>
> and I can't use double quotes because its in an echo statement. What
> am I missing?
Curly braces:
echo ("
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] quotations in value field
On 14 April 2004 15:21, Mikael Grön wrote: > On Apr 14, 2004, at 15:14, H-Mac Moderator wrote: > > > Mikael- > > > > I suspect you want htmlspecialchars, Not stripslashes. See: > > http://us4.php.net/manual/en/function.htmlspecialchars.php > Well, I guess a combination of htmlspecialchars and some > other function > to convert it back, before it gets sent of in the _plain text mails_. You don't need to convert it back -- that happens automatically when the form is resubmitted. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] How to redirect after a valid login
On 14 March 2004 02:14, Benjamin wrote: > What kind of error does it give you? Because in the snippet you gave > us you wrote > > > include "mainmenu.php"; // Which gives me an error ! > > And that should give you an error because it should be > > include( "mainmenu.php" ); //note parenthesies Nope. Perfectly valid without the parentheses -- do it all the time. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] win32 Timestamp problem
On 09 March 2004 20:36, J. Kevin C. Burton wrote: > Hey all, after reading documentation on the Win32 bug > regarding Timestamps > not being able to go prior than 1970.. > > I am in need of a way to calculate someone's age. > > Has anyone found a fix or workaround for this bug? Or a way > to calculate age > without using the timestamp? > > They say that v5 of PHP will fix this issue, but I've been using every > stable release of PHP5 and it's a no go. No, it won't. It's an operating system issue, and nothing PHP *can* fix. > Any help would be appreciated. Have you looked at the Calendar extension? http://www.php.net/calendar Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Two Column Sort
On 05 March 2004 14:49, Ken Colburn wrote: > Mike - > > I've tried your options and I get either an error message, no > sorting, or sorting that does not do both columns with B's at the > top. It's my understanding that I must still use sort_field and > sort_order (though I tried just ORDER BY). It does seem simple, but > nothing > works. It would > be a great help if you could plug something (anything) into > the url that > works at > http://congress.techpolitics.org/contributions22504.php/ > Hope this isn't > asking too much. Right, this is what I plugged in that I think gives the result you're asking for: http://congress.techpolitics.org/contributions22504.php?sort_field=cbc%20des c,%20net_receipts&sort_order=asc I've had to contrive the parameters a bit to work around the way you're processing them, but hopefully you get the idea. Just to over-egg the pudding a bit, I thought I'd extend the idea slightly and give you one more example: http://congress.techpolitics.org/contributions22504.php?sort_field=cbc%20des c,state%20asc,%20net_receipts&sort_order=desc Cheers! Mike P.S. please keep the discussion on the list so others can chip in if they want -- and any final resolution gets into the list archives for anyone reading the thread in the future. - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] ocistatement
On 05 March 2004 09:38, Torsten Lange wrote:
> Hello,
> I receive an array from an OCIFetchStatement() and want to
> address its
> elements by indices, which fails. The original select has two columns.
> How do I have to visualize that array? I want to load it into an
> list. I tried also some examples with
> while(list...), but it
> can not work until I don't know the structure.
If your column names are, say, ID and NAME, then the array looks like this:
Array ('ID' => Array ('id1', 'id2', 'id3', ...),
'NAME' => Array ('name1', 'name2', 'name3', ...)
)
So the rows of your query result are:
$arr['ID'][0], $arr['NAME'][0]
$arr['ID'][1], $arr['NAME'][1]
$arr['ID'][2], $arr['NAME'][2]
... etc. ...
HTH
Cheers!
Mike
-
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Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] Two Column Sort
On 04 March 2004 19:04, [EMAIL PROTECTED] wrote:
> On Thu, 4 Mar 2004 10:55:20 -0000, Ford, Mike [LSS]
> <[EMAIL PROTECTED]> wrote:
>
> > On 03 March 2004 17:07, [EMAIL PROTECTED] wrote:
> >
> > > Here's the php code for the sort command:
> > >
> > > echo "CBC > > href='contributions22504.php?sort_field=cbc,
> > > net_receipts&sort_order=desc'
> > > target='_self'>Sort\n";
> > >
> > > Here's the basic setup that begins the script:
> > >
> > > # get sort order (if any) passed to script
> > > $sort_field = $_REQUEST['sort_field'];
> > > if (! $sort_field) {$sort_field = "State";}
> > > $sort_order = $_REQUEST['sort_order'];
> > > if (! $sort_order) {$sort_order = "asc";}
> >
> > Well, you're going to need an order phrase that looks like this:
> >
> > ORDER BY CBC DESC, NET_RECEIPTS ASC
> >
> > so you may need a little rethink about how you're passing those
> > arguments.
> >
> > Cheers!
> >
> > Mike
> >
> Thanks, but you're past my level. Can you show me the exact coding I
> should use?
Well, not really, as there are several ways you could approach this and the one you
choose will depend on your exact application, personal preference, and whether there's
an "r" in the month ;)
> Apparently I can't just replace SORT_FIELD=CBC,
> NET_RECEIPTS&SORT_ORDER=DESC with ORDER BY CBC DESC, NET_RECEIPTS ASC
Well, you can, but the question is more whether that's what you want to do.
My original point was that if your URL has a query string that looks like
?sort_field=cbc, net_receipts&sort_order=asc
then you're going to get your variables set like this:
$sort_field = 'cbc, net_receipt';
$sort_order = 'asc';
but you need to interpolate an additional 'desc' into the sort order string to get the
CBC column to sort the way you want, so that the query ends up like:
SELECT ... ORDER BY cbc DESC, net_receipts asc
Whilst this is possible using PHP string functions (or regexes), it doesn't seem like
the easiest or most flexible method. A couple of alternatives off the top of my head
might be:
(i) just pass the full ORDER BY phrase (...?sort_order=cbc desc, net_receipts asc)
(ii) pass multiple parameters each with one column name and sort order (either
...?sort1=cbc desc&sort2=net_receipts asc, or ?sort[]=cbc desc&sort[]=net_receipts asc)
(iii) pass a parameter with a set of column names, and another with a matching set of
sort orders (...?sort_field=cbc,net_receipts&sort_order=desc,asc). This requires you
to break each set apart (by explode()ing on the comma, say), then reassemble them into
a suitable ORDER BY phrase. This option probably also requires you to do the most
validation, as you have to decide what happens when one set has more items in it than
the other, or is misformed in some other way, and so on.
Of course, you might decide that column CBC always wants to be sorted descending
regardless, in which case looking for it in the parameters and interpolating the
required DESC keyword is probably the way to go after all...!!
At the end of the day, only you can decide which of these is appropriate (or if some
other solution is), but I hope I've given you some pointers to help you make that
decision.
Cheers!
Mike
-
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Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] Two Column Sort
On 03 March 2004 17:07, [EMAIL PROTECTED] wrote:
> I'm re-raising an issue I never quite resolved which has become more
> critical. I want to sort a table on two columns. There are
> about 440
> rows of which about 400 are blank in the first sort column (CBC); the
> other rows show B in that column. When I use the coding
> below, the two
> column sort takes place but the rows designated B are at the
> bottom of the
> (long) table and I want them at the top. Neither asc nor desc
> accomplishes this (just reverses the second factor order,
> still at the
> bottom below the blanks).
>
> Here's the php code for the sort command:
>
> echo "CBC href='contributions22504.php?sort_field=cbc,
> net_receipts&sort_order=desc'
> target='_self'>Sort\n";
>
> Here's the basic setup that begins the script:
>
> # get sort order (if any) passed to script
> $sort_field = $_REQUEST['sort_field'];
> if (! $sort_field) {$sort_field = "State";}
> $sort_order = $_REQUEST['sort_order'];
> if (! $sort_order) {$sort_order = "asc";}
Well, your going to need an order phrase that looks like this:
ORDER BY CBC DESC, NET_RECEIPTS ASC
so you may need a little rethink about how you're passing those arguments.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] oracle: fetch a query result into an array
On 18 February 2004 18:22, Torsten Lange contributed these pearls of wisdom:
>
> while(OCIFetch($stmt))
> {
> $column_name = OCIResult($stmt,'COLUMN_NAME');
missing [] here -- should be:
$column_name[] = OCIResult($stmt,'COLUMN_NAME');
> $counter++; }
You might also want to look up ocifetchstatement
(http://www.php.net/ocifetchstatement).
Cheers!
Mike
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RE: [PHP-DB] Inserting querydata as default value in form
On 28 January 2004 18:05, Georg Herland wrote: > Hi! > > I hav made a simle page to insert update and delete data in MYSQL. > I try to put existing data into a standard form field to make editing > easyer: > Problem is when the text data contains a space ie "Look > here". Then only the > first word show. Oh dear, it's HTML 101 time again. Quote your attribute values! Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Quick Question: Line Breaks
On 09 January 2004 03:58, Jacob Hackamack wrote: > Hello, > > I have a couple of quick questions. When I execute this code on my > php page (I know that the .PSD image isn¹t web ready, but Safari does > what I need it to do :) ) it displays the entire source as one line. > Is there anyway to have it be broken. I have read places (internet > sites) that say that the following solutions might work: > echo OE¹;\n\n > echo OE¹\n\n ; > echo OE\n\n¹; > > None of them seem to work, am I doing something wrong? > > > echo ''; echo ''; > echo ''; > echo ''; > echo 'FilmCanister Desktops'; > echo ''; > echo ''; > echo ''; > echo ''; > echo ''; > echo ''; > echo 'Coming SoonDesktop Pictures (2.83 GB Worth)'; echo > ''; echo ''; > echo ''; The reason you have it all on one line is because you haven't echoed any newlines. You have a number of options to do this. As there is no variable interpolation anywhere in there, you could just break out of PHP and do it as straight HTML: ... ?> FilmCanister Desktops Coming SoonDesktop Pictures (2.83 GB Worth) ... '; If you plan to have variables in there at some point, you can either use segments, or use a heredoc: echo << ... END; or, again, you could use a multi-line string -- but this time double-quoted to give interpolation (but note that you now have to escape all your embedded double quotes): echo " ... "; Which route you choose is pretty much personal taste -- personally, if I have a page that's mostly straight HTML with not much PHP code, I write it as HTML with embedded PHP snippets, but I know some people think that looks weird or ugly...! Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] inserting dynamic drop down menu data into mysql
On 07 January 2004 15:12, Duane Barnes contributed these pearls of wisdom:
> I'm having a problem with a standard html form. I'm using a
> php function to
> populate a drop down menu on a standard form. I want the
> contents of the
> submitted form to insert into a mysql table. All of the
> variables are inserted correctly except for the data from the
> drop down
> menu. For some
> reason it will only insert the first word in the variable.
> It cuts off
> everything after the frist word.
This sounds like an unquoted multi-word attribute problem.
[snip]
> function build_dropdown() {
> $sql = "select category from categories ORDER BY category";
> $result = mysql_query($sql) or DIE(mysql_error()." -
> ".mysql_errno());
>
> while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
> extract($row); $output .= " value=$category>$category";
Yup, here it is -- quote the argument to the value= attribute, and everything should
be hunky dorey.
Cheers!
Mike
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RE: [PHP-DB] Search Query
On 18 December 2003 05:26, Ng Hwee Hwee wrote:
> Dear all,
>
> i need help with my search query statement.. what is wrong
> with my code?
Nothing obvious that I can see, except a little inefficiency. Where do
$keyword and $table come from? -- is this a register_globals issue?
>
> $word = split(" ", $keyword);
> $num_words = count($word);
> $word_str = "";
> $criteria = "";
>
> for ($i=0; $i<$num_words; $i++)
> {
> if ($i)
> $word_str .= "and colName like '%".$word[$i]."%' ";
> else $word_str .= "colName like '%".$word[$i]."%' ";
> }
> $word_str .= "and col2 = '$foo' ";
>
> $criteria .= "$word_str ";
I'd replace all of the above with:
$criteria = "colName like '%"
. str_replace(' '
, "%' and colName like '%"
, $keyword)
. "%'"
. " and col2 = '$foo' "
> $table .= "db_table";
>
> $query = "select * from ".$table." where ".$criteria;
>
> when i try to echo $query, i get --- select * from where
>
> and so of course MySQL gives me an error 1064 near ' where '
>
> what happened?
What's your error_reporting level? HAve you tried cranking it up to E_ALL
to see if any relevant warnings are being generated that you're not
currently seeing?
Cheers!
Mike
-
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JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] SQL question
On 11 December 2003 11:52, Constantin Brinzoi wrote: > I know it is possible to search a database like this: > > SELECT * FROM x_table WHERE name="%part_of_name%" > > but I don't know for sure the correct command. > > Could you tell me the right syntax? SELECT * FROM x_table WHERE name LIKE "%part_of_name%" Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] How do I get quotes around strings to display?
On 22 October 2003 00:41, [EMAIL PROTECTED] wrote:
> $fieldarray = array("one","Two", "three", "four");
> $line = "\"".implode("\",\"",$fieldarray) ."\"";
Eck, eck, eck!! Definitely a construct crying out for single quotes rather than
double:
$line = '"'.implode('","',$fieldarray) .'"';
Cheers!
Mike
-
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RE: [PHP-DB] Dynamic sites, to appear static...?
On 04 September 2003 11:18, [EMAIL PROTECTED] wrote: > I've been building web sites that use a database backend for > some time > now. > I typically use the format. > http://www.mysite.com/index.php?page=contact > http://www.mysite.com/index.php?page=home > http://www.mysite.com/index.php?page=aboutus > etc > > My most recent job wants to use differnt pages, so the search engines > will pick up the url's as clearly defined, and not dynamic, as I > normally do... > Is there a way I can still admin the pages, and allow my client to > add/delete pages, but use static links , without '?page=home' etc... > > I hope I've made sence... > I've discused this with my client, and he said a friend of > his claimed > 'that webserver software should have a module or plugin that > will do this' > I've never heard of that, have I been living under a rock? Not even a module (well, except for php!) or plugin. If you're using Apache as your Web server with mod_php, anything looking like path information following the script name is passed to your script in $_SERVER['PATH_INFO']. Take a look at, for example: http://www.lmu.ac.uk:8082/lco/php/support.php/visitors/welcome Note the position of support.php in that URL -- this URL is processed by running support.php with $_SERVER['PATH_INFO'] set to '/visitors/welcome', which the script decodes to decide what it actually needs to display. There's nothing particularly special in my httpd.conf file to make this work -- the relevant section is simply: AddType application/x-httpd-php .php Order allow,deny As a refinement, if you don't want people to see the .php on the script name, so that the URL could be (say): http://www.lmu.ac.uk:8082/lco/php/support/visitors/welcome you can tweak this to: AddType application/x-httpd-php .php DefaultType application/x-httpd-php # or ForceType if you prefer Then you either need a relevant AliasMatch or Rewrite so the above still gets to call support.php, or you simply upload all your scripts to the server with their bare name to match. I believe IIS is capable of passing PATH_INFO information, too, if you set it up right, but as I don't use it I can't be sure (or tell you how it might work!). Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] include_path problem
On 03 September 2003 14:10, Bruce Levick contributed these pearls of wisdom: > There is an include_path for unix and an include_path for > windows. They both > differ slightly but aren't of the same value that is being > returned in the > php info page or the error that I am receiving. > > This is the info displayed for my php.ini file. My OS is on G:. > > G:\WINDOWS\php.ini > > This is the Include_path directory shown in the phpinfo page. > .;c:\php4\pear > > Thanks very much for your help on this. Let me know if you > need me to post > anything else that might help. Well, I think I'm about out of ideas then -- so long as the ini file you're editing is G:\WINDOWS\php.ini, this all looks spot on. Just as a very last resort, can you post an extract from your G:\WINDOWS\php.ini that shows the lines which set include_path, plus a few lines either side -- just to check that there's nothing in their context that might be mucking things up. I suppose it might also be interesting to see the entire line from your phpinfo that shows the include_path settings (i.e. both master and local values). Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] "Consider upgrading MySQL client" .... how do I do this?
On 03 September 2003 10:51, Vinoaj Vijeyakumaar contributed these pearls of wisdom: > Hi, > > Just this morning I upgraded to MySQL 4.1.0 alpha and PHP > 4.3.3. I'm also > running Apache 2 on a WinXP machine. The main reason for the > upgrade was so that I could make use of 4.1.0's sub-select > feature rather than attempt learning JOINs. It is now 7 hours > later, and I keep getting the following error when trying to > connect to my database: > > Warning: mysql_connect(): Client does not support > authentication protocol > requested by server. Consider upgrading MySQL client > My question, therefore, is - is there a way to upgrade the > MySQL client in PHP 4.3.3? If not, what are the alternatives > (apart from reverting back to MySQL 4.0.x of course). I don't believe so, although I'm not absolutely certain as I don't use MySQL myself. My understanding, however, is that support for MySQL 4.1 will not be available until PHP 5.0. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] include_path problem
On 03 September 2003 01:32, Bruce Levick contributed these pearls of wisdom: > Well yes I have restarted my webserver, and the php.ini file > is under the > "windows directory" (shown in phpinfo page) and I am > definatelty editing it. > > The current value for my include_path is ".;c:\php\includes" > which is different to whats showing up on the phpinfo page and > also > the error that is > coming up. > > The wierd thing is I can change anything else in the php.ini > file and it > updates on the phpinfo page. Just not the include_path > attributes. Its as if > I am not changing the correct service as there is nothing in > the php.ini > file that relates to the directory ".;c:\php4\pear". Couple more stabs in the dark, then: - Check there is only one entry for include_path. - Make sure it's not commented out! (No ; at the start of the line.) Also, just to be absolutely sure, can you post exactly what your phpinfo shows for the php.ini setting? Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] To slash or not to slash....
On 02 September 2003 16:45, Craig Cameron wrote:
> Ok simple problem I hope.
>
>
> Have the following code, used to store the location and a few
> details about meeting minutes.
>
>
> $connection = mssql_connect("server","user","password");
> mssql_select_db("DocumentManager",$connection);
>
> $AlteredMinutesLocation =
> str_replace("\\","\",$MinutesLocation);
>
> $SQL_STRING = "INSERT INTO tblMeetingMinutes
> VALUES('$Date','$Type','$AlteredMinutesLocation','$Centre')";
>
> $Result = mssql_query($SQL_STRING,$connection);
> mssql_close($connection);
>
>
This script cannot possibly run -- it should have a parse error. Due to the
way PHP handles backslashes in literal strings, the function call
str_replace("\\","\",$MinutesLocation);
has a string containing 1 (one) backslash, and an unterminated string
containing
a double-quote and then everything up to the next double-quote (which is
actually part-way through the next line).
> Problem is the backslashes. When I collect the filepath
> ($Location) it puts \\ into the db. However, when I change
> this it stops dead. Basically due to the escape
> charateristics of the backslash. I can get around this with
> single quotes of course but can't put these in the SQL_STRING
> as it falls down there then!
I'm not sure I exactly follow what you're saying, but yes, there is
definitely a problem caused by the escape characteristics of the \.
However, I'm not sure it's where you think it is. The problem I can see in
your supplied script is that you haven't properly expressed in the replace()
call strings representing \\ and \. Since \ is the escape character, every
\ has to be escaped by itself, so the correct way of writing this is:
$AlteredMinutesLocation = str_replace("","\\",$MinutesLocation);
(Note that single-quotes make no difference here, as ' (and \ itself, of
course) are just about the only characters escaped by \ in a single-quoted
string!!)
None of this should be relevant to the interpolation of
$AlteredMinutesLocation into $SQL_STRING, since variable interpolation just
inserts whatever is in the variable, without any backslash escaping or other
fancy footwork.
Or another option might be stripslashes().
Cheers!
Mike
-
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JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] include_path problem
On 02 September 2003 08:00, Bruce Levick wrote: > Hi guys, > I am re-developing the look and feel of a site and trying to set it up > localy. Its all setup and ready to go but I am getting a > pear.php include > failure. > > Warning: main(/PEAR.php): failed to open stream: No such file > or directory > in G:\Inetpub\wwwroot\DB.php on line 25 > > Fatal error: main(): Failed opening required '/PEAR.php' > (include_path='.;c:\php4\pear') in G:\Inetpub\wwwroot\DB.php > on line 25 > > > The include path "c:\php4\pear" is incorrect. This is showing up in my > phpinfo file and I can't seem to get it to change in my > php.ini file. There > are include_path options in the php.ini file but nothing like > the directory > path in the error I am receiving. OK; '.;c:\php4\pear' is the default value for include_path, so PHP is not seeing your edited php.ini. Let's try a couple of basic questions (forgive me if these are obvious to you, but you haven't covered them in your message): 1) Did you restart your Web server after editing php.ini? 2) Where does the phpinfo() output say your php.ini file should be (look at the "Configuration File (php.ini) Path" entry right near the top)? And is your php.ini there? If the answer to both of these is yes, and you're still having problems, get back to the list with some more detail and maybe someone will have some other bright ides. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] weird php error
On 29 August 2003 06:39, OpenSource wrote:
> Hi guys,
>
> This is weird to me..
> I got this script
> ---
> if ($_GET[login] == 'forgot')
> {
> echo "Sorry I forgot my password";
> } else { echo "you are good to go"; }
>
> >
> -
> when ran, it gives me this error
>
>
> Notice: Use of undefined constant login - assumed 'login' in
> G:\Inetpub\wwwroot\test\index.php on line 3
This is because you haven't quoted the array subscript -- PHP thinks you're
trying to refer to a constant called login, but on not finding that assumes
that you meant the string 'login' instead. To suppress this notice, supply
the subscript correctly as a string:
if ($_GET['login'] == 'forgot')
>
> Notice: Undefined index: login in G:\Inetpub\wwwroot\test\index.php
> on line 3
This means that there was no login= parameter on the URL that called this
script. If this is a permissible condition, you need to allow for it in
your code. One way is simply to suppress the error message with the @
operator:
if (@$_GET['login'] == 'forgot')
Another is to do more explicit checking:
if (isset($_GET['login']) && $_GET['login'] == 'forgot')
Which you use is really down to personal preference.
Cheers!
Mike
-
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Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] Beta 2 of plPHP released.
On 29 August 2003 05:27, Joshua D. Drake wrote: > Hello, > > Beta 2 of plPHP has been released. This version contains many bug > fixes. For example, if you write bad plphp code and try to > execute it, > the code will no longer crash PostgreSQL ;). It would be nice if you told us what plPHP actually is as part of this message -- save those of us who have no interest in whatever it is having to make an unnecessary click through to your Web site. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Populating an array from mysql db
On 28 August 2003 17:25, mike karthauser wrote:
> on 28/8/03 5:00 pm, CPT John W. Holmes at
> [EMAIL PROTECTED] wrote:
>
> > > Thanks for this - I ended up rehashing my query to this:
> > >
> > > > > $result = mysql_query("SELECT * FROM dates WHERE bookcode =
> > > '$bookcode' ORDER BY date1",$db);
> > >
> > >
> > > // loop to populate array
> > >
> > > $myrow = mysql_fetch_array($result);
> > >
> > > $i = 1;
> > > while ($i <= '30') {
> > >
> > > if ($myrow['date'.$i] > '-00-00')
> >
> > You're making PHP do some extra work here. You're testing to see if
> > one string is greater than another... how can strings be greater
> > than or less than? Why don't you just check for $myrow['date'.$i]
> > != '-00-00' ??
>
> Thanks. I'll make your change.
While you're about it, remove the quotes from
while ($i <= '30') {
as well -- saves a conversion from string to integer each time round the loop (well,
unless PHP optimises it out of the loop, but why take the chance?!).
Cheers!
Mike
-
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Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] Maximum execution time of 30 seconds exceeded
On 11 August 2003 07:02, Michael Cortes wrote: > I am using the Konqueror browser and browing to > http://localhost/my.php > > Howerver, the script I wrote, doing various queries and lookups, > inserts, etc.. takes a while to complete. That is fine with > me. I'll wait. However, the server and/or browser will not wait. > > I believe the server is the one which will not wait because I have > one "echo" line at the beginning of the script which put a title > "Udate Students" athe the top center of the page and that writes then > there is a pause while the queries are run and then I get the > following error in my browser > > Fatal error: Maximum execution time of 30 seconds exceeded in > /var/www/html/student_info/ps2follett.php on line 139 That's your PHP script timing out. Take a look at http://www.php.net/set_time_limit Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Searching a file for text surrounded by brackets
> -Original Message-
> From: Jamie Saunders [mailto:[EMAIL PROTECTED]
> Sent: 16 July 2003 11:20
>
> Hi, I need a way of searching a file for text between two
> brackets, below
> is an example of a couple of lines from the file I'm searching:
>
> {L_LOGIN}
> {L_LOGOUT}
>
> So I'll need to search the above for text between the '{' and
> '}' brackets
> and read each into an array.
preg_match_all() (see http://www.php.net/preg_match_all) should do what you
want -- something like:
preg_match_all('/{([^}])+}/', $file_contents, $matches);
should give you an array of matched tags (excluding the braces) in
$matches[1].
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] problem with starting a session
> -Original Message- > From: Ahmed Abdelaliem [mailto:[EMAIL PROTECTED] > Sent: 15 July 2003 08:54 > > i have a problem with starting a session in the page that > validates the user > input and sends it tothe database, > when the user clicks register he gets this error > > Warning: session_start(): Cannot send session cookie - > headers already sent > by (output started at > c:\inetpub\wwwroot\ads4u\data_valid_fns.php:25) in > c:\inetpub\wwwroot\ads4u\register_new.php on line 89 > > Warning: session_start(): Cannot send session cache limiter - headers > already sent (output started at > c:\inetpub\wwwroot\ads4u\data_valid_fns.php:25) in > c:\inetpub\wwwroot\ads4u\register_new.php on line 89 > > > and here is the code i wrote : There must be approximately 73 lines before this, as the error message says the session_start() is on line 89. Your problem is that one of those lines is an include/require for data_valid_fns.php, and line 25 of that file outputs something that can't be output before the session_start(). Take a look there and work out how you can fix that. > $email=$HTTP_POST_VARS['email']; > $passwd=$HTTP_POST_VARS['passwd']; > $passwd2=$HTTP_POST_VARS['passwd2']; > $title=$HTTP_POST_VARS['title']; > $name1=$HTTP_POST_VARS['name1']; > $name2=$HTTP_POST_VARS['name2']; > $phone=$HTTP_POST_VARS['phone']; > $mobile=$HTTP_POST_VARS['mobile']; > $address1=$HTTP_POST_VARS['address1']; > $address2=$HTTP_POST_VARS['address2']; > $town=$HTTP_POST_VARS['town']; > $pb=$HTTP_POST_VARS['pb']; > $country=$HTTP_POST_VARS['country']; > $occupation=$HTTP_POST_VARS['occupation']; > > session_start(); Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] latest version of php only cgi?
> -Original Message- > From: Doug Finch [mailto:[EMAIL PROTECTED] > Sent: 26 June 2003 21:12 > > Is the newest version of php 4 only available as a cgi-based program? > DF No. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] error checking question
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> Sent: 26 June 2003 20:22
>
> What I would like to do is somehow have a redundant error
> check on the server
> side and then display an error message above the form on the
> main page should
> fields be left blank or forbidden characters entered. Since I
> have access to the
> $_POST['variables'] on the form processing page, I've already
> written some code
> to detect the presence of error characters, etc...and no
> query is performed if
> there is an error. But how do I pass a "flag" variable back
> to the main page to
> echo an appropriate message above the form?
One simple way:
header("Location: http:/your.server.name/path/to/main_page.php?err=$errcode");
exit();
And then emit an error in main_page.php if $_GET['err'] is set.
If you're using sessions, another way would be to set an error variable in the session.
Cheers!
Mike
-
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Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] moving though an array..SOLVED
> -Original Message-
> From: Aaron Wolski [mailto:[EMAIL PROTECTED]
> Sent: 26 June 2003 16:12
>
> Solved my problem!
>
> Here's the code in case anyone really cares :P
>
> $col = explode(",",$threadsColumn);
>
> $col_search = "(";
> for ($i=0;$i
> $col_search .= $col[$i]." LIKE
> '%$threadsName%'";
> if ($i != (count($col) - 1)) {
> $col_search .= " OR ";
>}
> }
>
> $col_search .= ")";
Yes, that's about how I'd do it -- you may, however, be interested in this variation
on the theme:
$col = explode(",",$threadsColumn);
$col_search = array();
foreach ($col as $col_name) {
$col_search[] = "$col_name LIKE '%$threadsName%'";
$col_search = "(" . implode(' OR ', $col_search) . ")";
A completely different approach might be to do it like this:
$col_search = "("
. str_replace(',',
" LIKE '%$threadsName%' OR ",
$threadsColumn)
. " LIKE '%$threadsName%'"
. ")";
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] setting session variables via a form
> -Original Message-
> From: Hutchins, Richard [mailto:[EMAIL PROTECTED]
> Sent: 16 June 2003 17:08
>
> session_start();
> session_register("isRegistering");
>
> $_SESSION["isRegistering"] = "true";
B't! If you're using the $_SESSION array, then you MUST NOT use
session_register() and friends.
(Well, ok, maybe that's overstating it a bit, but you still shouldn't do it!)
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
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RE: [PHP-DB] Help Please!! Oracle/PHP connection
> -Original Message- > From: Matthew Moldvan [mailto:[EMAIL PROTECTED] > Sent: 11 June 2003 01:03 > > Have you tried the built in Oracle functions in PHP? > > http://us3.php.net/oracle That's only for Oracle up to version 7. For Oracle 8 or 9, use the OCI extension http://www.php.net/oci8. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Is this query even possible?
> -Original Message- > From: Matthew Moldvan [mailto:[EMAIL PROTECTED] > Sent: 10 June 2003 16:50 > > As for the line breaks, I've used SQL formatted that way before and it > hasn't cause me any problems. It's a matter of preference, but I prefer to keep my query strings as lean as possible -- bear in mind that this version: > > > $sql = "UPDATE newdacs > > > SET emailfwd='$emailfwd', > > > mformat='$mformat', > > > filter_code='$filter_code'"; will include not only the linebreaks but also all the leading whitespace on every line. Personally, I like the technique of breaking my query up logically onto multiple lines, but I also prefer not to include unnecessary whitespace in the constructed query. In addition, it seems to me that the repetitive inclusion of "$sql .= " on every line is not only distracting but also slightly inefficient, as you perform a concatenation and assignment for every line -- by using the form I showed in my previous response, you can reduce this to just a concatenation per line, and a single assignment: $sql = "UPDATE newdacs" . "SET emailfwd='$emailfwd'," . "mformat='$mformat'," . "filter_code='$filter_code'"; Of course, this is all completely IMHO, and I wouldn't say that any of the other ways of doing it is absolutely wrong. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Count database-values
> -Original Message-
> From: Becoming Digital [mailto:[EMAIL PROTECTED]
> Sent: 10 June 2003 12:15
>
> I screwed up my own code. Silly me. It should read:
Surely your first attempt is the right one? There's only ever going to be 1 Total, so
why waste a while loop trying to read more than one result row?
> $query = "SELECT SUM(bedrag) AS Total FROM finance WHERE
> posneg = 'af'";
> $result = mysql_query( $query );
> while ( $total = mysql_fetch_array( $result ) )
> {
> $total = $total['Total'];
> }
>
> Edward Dudlik
> Becoming Digital
> www.becomingdigital.com
>
>
> - Original Message -
> From: "Becoming Digital" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, 10 June, 2003 06:43
> Subject: Re: [PHP-DB] Count database-values
>
>
> > So far no problems, but I want to count all these values.
> > I tried with SUM but with the following code it doesn't work:
> >
> > $squery = "SELECT SUM(bedrag) AS Total FROM finance WHERE
> posneg = 'af'";
> >
> > any suggestions how to do? I want to store it in a
> variabele ($total)
> > so I can echo it. (E.g.: $total = 93.63 in this case)
>
> If you want the total, you need to do something like the following:
>
> $query = "SELECT SUM(bedrag) AS Total FROM finance WHERE
> posneg = 'af'";
> $result = mysql_query( $query );
> $total = mysql_fetch_array( $result );
> $total = $total['Total'];
>
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Is this query even possible?
> -Original Message-
> From: Susan Ator [mailto:[EMAIL PROTECTED]
> Sent: 10 June 2003 16:18
>
> > This is what I am trying to do:
> >
> > if ($FUNC==("USERPOST") || $FUNC==("MODU")) {
> > $sql = "UPDATE newdacs
> > SET emailfwd='$emailfwd',
> > mformat='$mformat',
> > filter_code='$filter_code'
> > if ($FUNC=='USERPOST') {
> > ,unote='$unote'
> > }
> > WHERE user_id='$user_id'";
> > $set_newdacs_result = mysql_query($sql) or print
> > mysql_error();
> > }
Well, you're burying a PHP conditional inside what should be the SQL query,
which ain't gonna work very well. Try separating it out -- two possible
ways are to (i) use the ?: conditional operator, like this:
$sql = "UPDATE newdacs"
. " SET emailfwd='$emailfwd'"
. ",mformat='$mformat'"
. ",filter_code='$filter_code'"
. ($FUNC=='USERPOST' ? ",unote='$unote'" : '')
. " WHERE user_id='$user_id'";
or (ii) a fully-blown if(), like this:
$sql = "UPDATE newdacs"
. " SET emailfwd='$emailfwd'"
. ",mformat='$mformat'"
. ",filter_code='$filter_code'";
if ($FUNC=='USERPOST'):
$sql .= ",unote='$unote'"
endif;
$sql .= " WHERE user_id='$user_id'";
There are probably umpteen other ways of approaching this -- use whatever
floats your boat! ;)
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] PHP sort from .... best solution?
> -Original Message-
> From: A. Lyse [mailto:[EMAIL PROTECTED]
> Sent: 06 June 2003 11:34
This was sent privately to me, but I'm redirecting the response back to the list in
case it helps anyone else.
> Feeling kinda stupid. hehe. sorry I didnt label the lines.
Probably no more stupid than I did when I realised I'd got the usort() call wrong...!
> You are sure going to laught now for my stupidity, but the aricles are
> listing the wrong way (I'm a bit embarrassed now) Look here:
> http://www.amotor.no/artikler.php
> The last article: formel 1 art 4 (2003 04/06) is dated
> forth of june,
> 2003 and the first atricle formel 1 art 1 (2003 28/05) is dated
> twenty-eight of May, 2003. The articles in the between the
> first and last
> article are sorting from the oldest (the first) to the newest
> (the last). I
> guess it's not a problem to get this flipped?
No, dead simple -- simply put a - sign in the comparison function:
function obj_date_compare($a, $b) {
return -strcmp($a->publisertLang, $b->publisertLang);
}
> Sorry, for my bad English. I'm from Norway :(
Your English is fine -- if you hadn't mentioned it, I probably wouldn't have guessed
that you're not a native speaker!
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] PHP sort from .... best solution?
> -Original Message- > From: A. Lyse [mailto:[EMAIL PROTECTED] > Sent: 05 June 2003 21:21 > > Thanks! But I got a problem with the code: > > The PHP file as it is with the code pasted into it will i'll > past at the end > of this post. The problem is I get the error: > > Warning: Invalid argument supplied for foreach() in > /home/amotor/www/list_ingresser_artikler.php on line 43 > > If I put a // in front of line 32 the script feeds correct, > but not sorted. It would help if you labelled lines 32 and 43, so we don't have to count all up and down your posted script to work out which they are. However, having done the necessary counting, this is your problem line: > $ingresser = usort($ingresser, 'obj_date_compare'); ... in which case, apologies, my bad, because usort does an in-place sort and has no return value, so you just want: usort($ingresser, 'obj_date_compare'); Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] while - if - problem
> -Original Message-
> From: Earl [mailto:[EMAIL PROTECTED]
> Sent: 04 June 2003 22:04
> To: PHP-DB
>
> FYI
> this was beginning to bug me out... so I decided to try the
> trim function
> and walla... it worked.
>
> Thanks for ya'll assistance.
I was going to say this even before you added the trim() calls in , but this
really does look like an excellent situation for using the switch construct
(just look at all those trim() calls and array accesses you save!):
while($cols=ifx_fetch_row($eventQuery))
{
switch (trim($cols['out_type']))
{
case '0':
$r_away['linetype']='L';
$r_home['linetype']='L';
break;
case '1':
$r_away['linetype']='H';
$r_home['linetype']='H';
break;
}
switch (trim($cols["s_acro"]))
{
case 'CF':
case 'PF':
$r_away['sport']='1';
$r_home['sport']='1';
$s_lt='PS';
$t_lt='TP';
break;
case 'PB':
case 'CB':
$r_away['sport']='2';
$r_home['sport']='2';
$s_lt='PS';
$t_lt='TP';
break;
case 'B':
$r_away['sport']='3';
$r_home['sport']='3';
$s_lt='ML';
$t_lt='TM';
break;
case 'H':
$r_away['sport']='4';
$r_home['sport']='4';
$s_lt='ML';
$t_lt='TM';
break;
}
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] PHP sort from a database variable..?
> -Original Message-
> From: heilo [mailto:[EMAIL PROTECTED]
> Sent: 03 June 2003 23:35
>
> sorry, needed some time to hack this one ::)
>
> as your print_r shows that you have to sort an array which
> includes objects
> (in this case an ingress-class - whatever this is). i tried
> to simulate your
> environement and endet up with this:
This looks a bit like a sledgehammer to crack a nut -- why not just use
usort, like this:
function obj_date_compare($a, $b) {
return strcmp($a->publisertLang, $b->publisertLang);
}
...
if($ingresser = array_merge($i1 ,$i2))
{
$ingresser = usort($ingresser, 'obj_date_compare');
listIngresser($ingresser);
}
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Array Pointer
> -Original Message-
> From: Ian Fingold [mailto:[EMAIL PROTECTED]
> Sent: 03 June 2003 16:58
>
> Ok I'm trying to write this function to up date some fields
> in my database
> so i'm grabbing some info from a query and throwing it into
> an array (with
> mysql_fetch_array).
>
> one of the values i'm puting into that array is the table id. I'm then
> comparing the table id with the value of $i in my loop. Now
> my problem is
> when I loop through and the table id is not equal to $i I
> need to add 1 to
> $i but I need to move the array pointer back one.
>
> In the code below I used prev() but i'm getting warnings
> about the "Passed
> variable is not an array".
> http://55yardline.cflmain.com/55main/2003/fantasy/tests/update.php
>
> I'm thinking that prev() must not view an array fetch from a
> database the
> same or something. But what else can I use besides prev() to
> rewind the
> pointer by 1?
>
> Thanks,
>
>
>
> include "function.php";
> connect1();
>
> //query roster database and put results into an array.
> $num1 = mysql_query("SELECT * FROM roster");
> $num2 = mysql_fetch_array($num1);
> //set i to zero
> $i = 0;
>
> //start loop to determine if $i matches the current roster id
> do {
> $i = $i + 1;
> if ($num2["ros_id"] == $i) {
> //if a match is found, query the fan_roster database
> where the play_id =
> $i
> //and put the results into a array
> $upd = mysql_query("SELECT * FROM fan_roster WHERE play_id='$i'");
> $updr = mysql_fetch_array($upd);
> //loop through the passing field and add them up
> do {
> $passing = $passing + $updr["pass_yrd1"];
> } while($updr = mysql_fetch_array($upd));
>
> //Print feedback
> echo "Player:$i total Passing: $passing $updr[play_id]";
>
> //update the roster table with the total $passing where ros_id=$i
> $upd1 = mysql_query("UPDATE roster SET pass_yrd='$passing' WHERE
> ros_id='$i'");
> //reset passing for next loop
> $passing = 0;
> } else {
> //if there isn't a match, add 1 to $i
> $i = $i + 1;
>
> //print feedback
> echo "$i no player";
>
> //put the array pointer back one for next loop
> $num2 = prev($num2["ros_id"];
(1) prev() takes an array as its argument, not an individual element, so prev($num2)
would be syntactically correct (but I doubt it's what you really mean).
(2) anyway, this whole statement is pointless as you immediately do:
> }
> } while($num2 = mysql_fetch_array($num1));
Which promptly overwrites the value of $num2 you just put there!
What are you *really* trying to do?
> ?>
>
>
>
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